You're carrying a 3.0-m-long, 20kg pole to a construction site when you decide to stop for a rest. You place one end of the pole on a fence post and hold the other end of the pole 35cm from its tip.
A) How much force must you exert to keep the pole motionless in a horizontal position?
Express your answer using two significant figures. answer must be "N"
Answers
You need to provide 132 N of force to maintain the pole horizontally.
The criteria are as follows: 3.2 m for the pole's length and 24 kg for its weight.
The pole's weight is determined as follows:
W = 24 x 9.8 = 235.2 N
The total force applied to maintain the pole's horizontality,
∑F = F1 + F2 = 235.2
F1 = 235.2 - F2
Consider the pole's core for a minute.
F1 × 1.6 = F2(1.6 - 0.35)
1.6(235.2 - F2) = 1.25 F2
376.2 - 1.6F2 = 1.25 F2
376.2 = 2.85 F2
F2 = 376.32 ÷ 2.85
F2 = 132.04
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Related Questions
a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direct with a speed of 1.3 m/s whats the mass of the cannon.
Answers
The mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.
What is velocity?When anything is moving, its velocity tells us how rapidly that something's location is changing from a certain vantage point and as measured by a particular unit of time.
If a point moves along a path and covers a certain distance in a predetermined amount of time, its average speed over that period of time is equal to the distance covered divided by the travel time. A train traveling 100 kilometers in two hours, for instance, is doing it at an average speed of 50 km/h.
Given:
The mass of the cannonball, m = 5 kg,
The velocity of the cannon, v = 550 m/s,
The recoil speed of the cannon, vₐ = 1.3 m / s,
Then by using momentum conservation calculate the mass of the cannon,
\(m \times v = m_{a} \times v_{a}\)
Here mₐ is the mass of the cannon,
Substitute the values,
5 × 550 = mₐ × 1.3
mₐ = 2115.4 kg
Therefore, the mass of a cannon if a 5.0 kg cannonball is fired from a stationary cannon with a horizontal velocity of 550 m/s if the cannon recoil in the opposite direction with a speed of 1.3 m/s is 2115.4 kg.
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A helicopter (mass = 5000 kg) lifts 1475 kg of stuff (two people and packages). Let’s say initially the helicopter is hovering (v = 0 m/s). What thrust (force) is necessary for the helicopter to hover?
Answers
While it's carrying the passengers and packages, its total mass is 5000 kg + 1475 kg = 6475 kg, so that its weight is
(6475 kg) g = 63,455 N
In order to hover, the helicopter's thrust should match this weight.
What does the phrase “constant velocity” indicate?
a. zero distance
b. zero acceleration
c. constant acceleration
d. deceleration
Answers
Calculate the current if 10 coulombs of charge passes a point in 10 seconds.
Answers
Answer:
1A
Explanation:
=> Current (I) = q/t
Here charge (q) = 10C and time = 10sec
=> I = 10/10 = 1A
Helpppp pleaseeeee!!!!
Answers
I think it is the 2nd option, angle of incidence varies from point to point
Answer:
2nd option for me.
Mark me as brainliest please
An ant is following a circular pheromone trail. The ant takes 14 s to complete one ‘lap’ and is moving at a speed of 8.5 cm s−1.
What is the radius of the pheromone trail?
What is the angular velocity of the ant?
Answers
Explanation:
hold I will tell u the answer 1 sec
1/2
I, the student, verify that I have read the lab safety document and will comply with the rules as stated.
Yes
No
Answers
A Ford F150 can slow to a stop from 60 m/s in 2.44 seconds with an acceleration of -0.207 m/s2. What is the braking distance of the car?
Answers
The braking distance of the car, given the data from the question is 145.784 m
How to determine the braking distanceFrom the question given above, the following data were obtained:
Initial velocity (u) = 60 m/sTime (t) = 2.44 sAcceleration (a) = -0.207 m/s²Final velocity (v) = 0 m/Breaking distance (s) =?The breaking distance of the car can be obtained as illustrated below:
s = ut + ½at²
s = (60 × 2.44) + (½ × -0.207 × 2.44²)
s = 146.4 + (-0.616)
s = 146.4 - 0.616
s = 145.784 m
From the calculation made above, we can conclude that the breaking distance of the car is 145.784 m
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If dx denotes the change in position of an object and dt denotes the corresponding time interval, then instantaneous velocity is given by:
Answers
Answer:
\(Velocity=\frac{dx}{dt}\)
Explanation:
Remember that instantaneous velocity is just a measure to know the velocity that any object has at any point given in time, so we just need to know the distance it has travel, which would be the change in position, and the time it took that change in position to occurr, this means distance by time, so we just divide dx by dt and we have the solution for instantaneous velocity.
If a change in position as denoted by \(dx\) and \(dt\) change in time, the instantaneous velocity will be given by,
\(v = \dfrac {dx}{dt}\)
What is Velocity?It can be defined by the change in position of the object over time. This is a vector quantity. Vector quantity is a quantity that has both magnitude and direction.Instantaneous velocity:The velocity of the object at a point of time is known as instantaneous velocity. Instantaneous velocity can be calculated by the ratio of change in position to the elapsed point of time.
\(v = \dfrac {dx}{dt}\)
Where,
\(v\) - instantaneous velocity
\(dt\) - change in distance (position)
\(dt\)- change in time
Therefore, if a change in position as denoted by \(dx\) and \(dt\)change in time, the instantaneous velocity will be given by,
\(v = \dfrac {dx}{dt}\)
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if a sample known to be about 10,740 years old has 400 carbon-14 atoms. how many atoms were in the sample when the organism dies
Answers
Answer:
Carbon 14 has a half-life of about 5740 years
Since this is about 2 half-lives then 1/4 of the atoms would remain
meaning 1600 atoms were initially present , I assume that they mean the sample died 10,740 years ago
More accurately (T / 5740) = n = number of elapsed half-lives
(10740 / 5740) = 1.87 half lives
(1/2)^1.87 = .273 of original amount left
400 / .273 = 1463 atoms originally present
Which of the following objects
transforms chemical energy into
mechanical energy?
A. Battery powered clock
B. Cell phone
C. Washing machine
D. Windmill
Answers
Battery-powered clocks and Washing machines are objects that transform chemical energy into mechanical energy.
What are chemical energy and mechanical energy?Chemical energy is a type of energy that is stored in the bonds of a chemical. It is converted into thermal energy when people burn wood or burn gasoline in the engine of a car. Mechanical energy is a type of energy that is stored in objects by tension. Compressed springs and stretched bands are examples of mechanical energy.
Mechanical energy i.e. kinetic energy or potential energy is the energy that is present in an object in motion or the energy that is stored in objects due to their position. Mechanical energy is a type of renewable energy.
So we can conclude that options A and C are the correct answers.
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A parallel circuit has four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. How much current is supplied by the source?
Answers
A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.
The sum of the branch currents in a parallel circuit can be calculated by adding up the values of the individual branch currents. In this case, we have four branch currents: 120 mA, 380 mA, 250 mA, and 2.1 A. Thus, the sum of the branch currents is:120 mA + 380 mA + 250 mA + 2.1 A= 2.85 ATherefore, the current supplied by the source in this parallel circuit is 2.85 A. This is because, in a parallel circuit, the current from the source is split between the different branches of the circuit. Each branch will have a different current, but the sum of all the branch currents will always equal the current supplied by the sourceFor such more question on parallel circuit
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Mario places 10 mL of water in a test tube and heats the liquid over a Bunsen burner for 2 minutes. After removing the test tube from the Bunsen burner, there are 6 mL of water left in the test tube. This experiment is a good example of a
Answers
Answer:
water cycle your welcome
Answer:
This experiment is a good example of a water cycle
Explanation:
what is true and what is false
Answers
Answer:
1 . t
2 . f
3 . f
4 . t
5 . t
6 . f
Explanation:
Who exhibits more power?A) Bob transfer 2000 J in 3 minutes.B) Carl transfers 2 J in 0.1 s.C) Alan transfers 20 J in 0.5 s.
Answers
Given that:
A) Energy,
\(E_B=\text{ 2000 J}\)The time is
\(\begin{gathered} t_B=3\text{ min} \\ =3\times60\text{ s} \\ =180\text{ s} \end{gathered}\)B) Energy,
\(E_C=2\text{ J}\)and time
\(t_C=0.1\text{ s}\)C) Energy
\(E_A=20\text{ J}\)and time
\(t_A=0.5\text{ s}\)
We have to find the power for all three cases.
The formula to calculate power is
\(P=\frac{E}{t}\)The power transferred by Bob will be
\(\begin{gathered} P_B=\frac{E_B}{t_B} \\ =\frac{2000}{180} \\ =11.11\text{ W} \end{gathered}\)The power transferred by Carl will be
\(\begin{gathered} P_C=\frac{E_C}{t_C} \\ =\frac{2}{0.1} \\ =20\text{ W} \end{gathered}\)The power transferred by Alan will be
\(\begin{gathered} P_A=\frac{E_A}{t_A} \\ =\frac{20}{0.5} \\ =40\text{ W} \end{gathered}\)Thus, Alan exhibits more power.
Equipotential lines are lines with equal electric potential (for example, all the points with an electric potential of 5.0 V). Using the plot tool that comes with voltmeter (pencil icon) make two equipotential lines at r = 0.5 m and r = 1.5 m. Enable electric field vectors in the simulation. Put an electric field sensor at different points on the equipotential line and note the direction of the electric field vector. What can you conclude about the direction of the electric field vector in relation to the equipotential lines?
The direction for each field vector is perpendicular to equipotential lines.
Take a snapshot of the simulation showing equipotential lines and paste to a word document.
Answers
....................
17. Calculate the amount of gravitational potential energy at the top of one 4 points hill. The mass of the coaster is 500 kg. The height from the hill to the valley is 59.6 m. Use 9.81 m/s^2 as the acceleration due to gravity. Record your calculations in joules. (Hint: Gravitational PE = mgh)
A. 292.338 m/s^2
B. 3037 J
C. 82.3 kg
D. 292,338 J
Answers
Answer: D. 292,338 J
This is the correct answer :)
On average, both arms and hands together account for 13% of a person's mass, while the head is 7.0% and the trunk and legs account for 80%. We can model a spinning skater with her arms outstretched as a vertical cylinder (head, trunk, and legs) with two solid uniform rods (arms and hands) extended horizontally.
Suppose a 65.0 kg skater is 1.60 m tall, has arms that are each 74.0 cm long (including the hands) and a trunk that can be modeled as being 37.0 cm in diameter. The skater is initially spinning at 62.0 rpm with her arms outstretched.
What will her angular velocity 2 be (in rpm) after she pulls in her arms and holds them tightly against her trunk? Assume negligible friction between the skater and the ice.
Answers
The skater's angular velocity after pulling in her arms and holding them tightly against her trunk will be approximately 89.5 rpm or 1.492 rps (revolutions per second).
To solve this problem, we need to apply the principle of conservation of angular momentum. Initially, the skater is spinning with her arms outstretched, and then she pulls her arms in and holds them tightly against her trunk. The total angular momentum before and after the change should remain the same.
Calculate the initial moment of inertia:
The moment of inertia of the skater with her arms outstretched can be calculated as the sum of the individual moments of inertia for each body part.
For the vertical cylinder (head, trunk, and legs):
Mass = 0.07 × 65.0 kg = 4.55 kg
Height = 1.60 m
Radius = (37.0 cm / 2) = 0.185 m
Moment of inertia for the cylinder = (1/12) × Mass × Height^2 + (1/4) × Mass × Radius^2
For the horizontal rods (arms and hands):
Each arm length = 74.0 cm = 0.74 m
Mass of each arm = 0.13 × 65.0 kg = 8.45 kg
Moment of inertia for each rod = (1/3) × Mass × Length^2
Total initial moment of inertia = Moment of inertia for the cylinder + 2 × Moment of inertia for each rod
Calculate the initial angular momentum:
The initial angular momentum is given by L = Iω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity.
Convert the given initial angular velocity from rpm to rad/s:
Initial angular velocity = 62.0 rpm = (62.0 rpm) × (2π rad/rev) / (60 s/min) = 6.493 rad/s
Initial angular momentum = Total initial moment of inertia × Initial angular velocity
Calculate the final moment of inertia:
When the skater pulls her arms in and holds them tightly against her trunk, the moment of inertia changes. The arms and hands contribute no moment of inertia since they are now tightly held against the trunk.
The new moment of inertia will be that of the vertical cylinder alone.
Conservation of angular momentum:
According to the principle of conservation of angular momentum, the initial angular momentum should be equal to the final angular momentum.
Final angular momentum = Final moment of inertia × Final angular velocity
Since the total angular momentum remains constant:
Initial angular momentum = Final angular momentum
Calculate the final angular velocity:
Rearrange the equation to solve for the final angular velocity:
Final angular velocity = Initial angular momentum / Final moment of inertia
Substitute the known values and solve for the final angular velocity.
Convert the final angular velocity to rpm:
Final angular velocity (in rpm) = Final angular velocity × (60 s/min) / (2π rad/rev)
Therefore, the skater's angular velocity after pulling in her arms and holding them tightly against her trunk will be approximately 89.5 rpm or 1.492 rps (revolutions per second).
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if chilled coke and hot tea are
kept together tea cools down but ko gets warm why
Answers
Heat transfers from a area of hot region to cold.
The tea is hot in this case, due to taht factor the heat will move towards teh cooler region which is coke and will make the coke warm
Hope this helped!
Mention two ways in which the effects of friction can be minimised
Answers
Answer:
Polishing the rough surface.
Oiling or lubricating with graphite or grease the moving parts of a machine.
Providing all bearings or wheels between the moving parts of a machine or vehicles reduce friction and allow smooth movement as rolling friction is less than sliding friction.
Explanation:
A piece of wood 350 mm × 350 mm and 15 mm thick conducts heat through its thickness under steady state conditions. The rate of heat flow is measured to be 14.0 watts when the temperature difference is 28 C°. Determine the coefficient of thermal conductivity for this wood
Answers
The coefficient of thermal conductivity (k) is related to the rate of heat flow (Q), the cross-sectional area (A), the length (L), the temperature difference (ΔT), and the thermal resistance (Rth) by the following equation:
k = Q / (A * ΔT * L) = Rth * (A * ΔT)
Reorganizing this equation gives:
Rth = k / (A * ΔT)
The given information in the problem is:
Rate of heat flow (Q) = 14.0 watts
Thermal resistance (Rth) = (350 mm × 350 mm × 15 mm) / (14.0 watts) = 31.5 mm⁴/C
Temperature difference (ΔT) = 28°C
Substituting these values into the equation, we have:
k = Q / (A * ΔT) = 14.0 W / (0.35 m² * 28°C) = 1.94 W/mK
So the coefficient of thermal conductivity (k) for this wood is approximately 1.94 W/mK.
An electric heater plugged into a 120-V outlet draws a steady 15.0 A of current:
b. If you operate the heater 3 hours per day and the electric company charges 9.2
cents per kWh, how much does it cost to operate the heater for one month (30
days)
Answers
The amount required to operate the electric heater for one month is 1490.4 cents.
What is electrci heater?Electric heating is a process in which electrical energy is converted directly to heat energy at around 100% efficiency, using rather cheap devices.
To calculate the amount needed to operate the electric heater in 30 days, we use the formula below.
Formula:
A = R×30VIt/1000...........Equation 1Where:
A = Amount needed to operate the heater for 30 daysV = VoltageI = Currentt = TimeR = Electric company chargeFrom the question,
Given:
R = 9.2 cents per kWhV = 120 VI = 15 At = 3 hoursFrom the question,
Given:
A = 3×30×120×15×9.2/1000A = 1490.4 centsHence, The amount required to operate the electric heater is 1490.4 cents.
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"n 25 kg object is moving at a velocity or 10 ml. the obec has energy. Calculate it.
Answers
The energy of 25 kg object is moving at a velocity or 10 ml is 1250J.
What does a 25 kilogram object travelling at 10 m/s kinetic energy look like?KE = 1/2mv²
The mass is m = 25kg
The velocity is v = 10ms⁻¹
KE = 1/2 × 25 × 10²
⇒ KE = 1250J
Hence, Kinetic energy is 1250J
What is Kinetic energy?The energy an object has as a result of motion is known as kinetic energy. A force must be applied to an object in order to accelerate it. We must put in effort in order to apply a force. After the work is finished, energy is transferred to the item, which then moves at a new, constant speed.
What is velocity?The direction of a body or object's movement is defined by its velocity. In its basic form, speed is a scalar quantity. In essence, velocity is a vector quantity. It is the speed at which distance changes. It is the displacement change rate.
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Why does strenuous activities make the heart beat faster?
Answers
Explanation:
When you exercise the muscles in your body must contract, in order to do that they need oxygen, glucose, a molecule called ATP, and amino acids. As your muscles use these compounds and contract themselves, they will create waste products like carbon dioxide, and lactic acid that must be carried away from the muscles. When exercising many muscles will all require nutrients and elimination of waste products constantly at the same time. To meet this demand the heart must rapidly increase the rate at which it beats and pushes blood through the body. This is why the heart beats significantly faster during exercise.
Find out the three methods of energy transfer (conduction, convection and radiation). think about
2 situations of daily life where you know or think you know that each one applies
Answers
Explanation:
conduction- putting a metal spoon in fire
convection- boiling water. In ventilation
Radiation- suns heat reaches us by radiation. heat from fire place reaches us by radiation.
A motorcycle stoop is at a traffic light, when the light turns green, the motorcycle accelerates to a speed of 78 km/h over a distance of 50 m. What is the average acceleration of the motorcycle over this distance?
Answers
The average acceleration of the motorcycle over the given distance is approximately 9.39 m/s².
To calculate the average acceleration of the motorcycle, we can use the formula:
Average acceleration = (final velocity - initial velocity) / time
First, let's convert the final velocity from km/h to m/s since the distance is given in meters. We know that 1 km/h is equal to 0.2778 m/s.
Converting the final velocity:
Final velocity = 78 km/h * 0.2778 m/s = 21.67 m/s
Since the motorcycle starts from rest (initial velocity is zero), the formula becomes:
Average acceleration = (21.67 m/s - 0 m/s) / time
To find the time taken to reach this velocity, we need to use the formula for average speed:
Average speed = total distance/time
Rearranging the formula:
time = total distance / average speed
Plugging in the values:
time = 50 m / 21.67 m/s ≈ 2.31 seconds
Now we can calculate the average acceleration:
Average acceleration = (21.67 m/s - 0 m/s) / 2.31 s ≈ 9.39 m/s²
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If the mass of a basketball is 18 times that of a tennis mass, can they ever have the same momentum? Explain your answer
Answers
Answer:
Yes
Explanation:
Yes. The momentum is the same when the speed of the tennis ball is 18 times greater than the speed of the basketball and the velocities of both objects are in the same direction.
Which would not describe a physical property of
a substance?
how it reacts with another substance
B how shiny it is
C what color it is
D its mass
Answers
Answer:
Explanation:
Out of the given options, A would not describe a physical property of a substance. How a substance reacts with another substance is a chemical property, whereas physical properties are intrinsic characteristics that can be observed or measured without changing the substance's identity. B, C, and D are examples of physical properties - shininess, color, and mass respectively.
a force of 17 acts on a block of mass 4kg the forces of friction opposing the motion is 5n . the acceleration of the block is
Answers
N = m a
N = 4 × a
N = 4a
Fk = μK N
17 = 5 × 4a
17 = 20 a
a = ¹⁷/₂₀ = 0.85 m/s²
The force applied on the block of mass 4 kg is 17 N and a frictional force of 5 N is opposing this force. Hence, the net force is 8N and the acceleration is 2 m/s².
What is net force?Force is a vector quantity thus, characterized by a magnitude and direction. If two same or different forces are acting on a body from the same direction, the net force will be the sum of the magnitude of the two forces.
If two forces are acting from opposite directions, they will cancel each other and the net force is the substracted value of their magnitudes.
Given that, mass of the block = 4 kg
force applied on the block = 17 N
frictional force = 5 N
Net force = 17 - 5 = 8 N.
Force = mass × acceleration. (by Newton's second law of motion)
acceleration = force/ mass
= 8 N / 4 Kg = 2 m/s²
Therefore, the acceleration of the block is 2 m/s².
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O Object A: -2
Object B: -2
Object A: +3
Object B: +4
O Object A: -6
Object B: -4
O Object A: -3
Object B: 0
When the objects interact, which option indicates a possible net charge for each object?
