1. Car traveling at 34.6m/s has an acceleration of -3.4m/s². What is the car'svelocity after 3s?#1

Answer:

Chemical weathering

Explanation:

This changes the molecular structure of rocks and soil. For instance, carbon dioxide from the air or soil sometimes combines with water in a process called carbonation. This produces a weak acid, called carbonic acid, that can dissolve rock.

Answer:

Democritus and Dalton has similar ideas about the atom, but Democritus based his theory more on reason than science. ... His ideas were similar to those of Democrites in that he believed that atoms were indivisible and that atoms of one substance are all alike but are different from atoms of another substance.

Explanation:

PLS MAKE ME AS BRAINLIST

Answer:

Democritus and Dalton has similar ideas about the atom, but Democritus based his theory more on reason than science. ... His ideas were similar to those of Democrites in that he believed that atoms were indivisible and that atoms of one substance are all alike but are different from atoms of another substance.

Explanation:

The go-kart will travel approximately 444.3 meters during the given time period.

To determine the distance traveled by the go-kart during the given time period, we can use the equation:

\(\[ \text{{distance}} = \frac{1}{2} \cdot \text{{acceleration}} \cdot \text{{time}}^2 \]\)

Given:

Mass of the go-kart, \(\( m = 73.9 \)\) kg

Net force acting on the go-kart, \(\rm \( F = 90.2 \)\) N

Time period, \(\rm \( t = 38.0 \)\) s

First, we need to calculate the acceleration experienced by the go-kart using Newton's second law of motion: \(\rm \[ F = m \cdot a \]\)

Solving for acceleration:

\(\[ a = \frac{F}{m} \]\)

Substituting the given values:

\(\[ a = \frac{90.2 \, \text{N}}{73.9 \, \text{kg}} \]\)

Now, we can calculate the distance traveled:

\(\[ \text{{distance}} = \frac{1}{2} \cdot a \cdot t^2 \]\)

Substituting the values of \(\( a \)\) and \(\( t \)\):

\(\[ \text{{distance}} = \frac{1}{2} \cdot \left(\frac{90.2 \, \text{N}}{73.9 \, \text{kg}}\right) \cdot (38.0 \, \text{s})^2 \]\)

Calculating the result:

\(\[ \text{{distance}} \approx 444.3 \, \text{m} \]\)

Therefore, the go-kart will travel approximately 444.3 meters during the given time period.

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Answer:

Seasons happen because Earth's axis is tilted at an angle of about 23.4 degrees and different parts of Earth receive more solar energy than others.

Explanation:

One cyclist is cycling at a speed of 17 km/hr while the other is cycling at a speed of 23 km/hr.

Let's denote the rate of the slower cyclist as "r" km/h. Then the rate of the faster cyclist is "r+6" km/h.

When they are cycling toward each other, their relative speed is the sum of their speeds. Therefore, we can set up the equation:

\(120 \ km = (r + r+6) \ km/h \times 3\) hours  (since together they both travel a total distance of 120 km)

Simplifying this equation:

\(120 \ km = (2r + 6)\  km/h \times 3 \ hours\)

\(40 \ km = (2r + 6) \ km/h\)

\(2r + 6 = 40 \ km/h\)

\(2r = 34 \ km/h\)

\(r = 17 \ km/h\)

So the slower cyclist is cycling at 17 km/h and the faster cyclist is cycling at 17+6=23 km/h.

Therefore, the speeds of cyclists are 17 km/h and 23 km/h.

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Answer:

Either C or D.

Explanation:

Either one of them.

The inductance of the inductor is 169Ω and the energy in the inductor is 1.48 x 10⁻³ J.

The resistance of the resistor is 13.7K and the ideal battery has EMF 73.0 V. So, the initial current in the circuit will be,

I = 73/13700

I = 5.3 mA.

The current reaches 2.95 mA after 5.46 mA.

(a). The inductance in the coil can be given by,

E = LΔI/Δt

L is the inductance and E is the EMF, So, Putting values,

73 = L(2.35)/5.46

L = 169Ω.

(b) The energy in the inductor when current is 2.95 mA,

E = 1/2LI²

Putting values,

E = 1/2 x 169 x 2.95 x 2.95 x 10⁻⁶

E = 1.48 x 10⁻³ J.

So, energy in the inductor is 1.48 x 10⁻³ J.

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For a single-phase ideal transformer

Load current, I₂ = 7.2 - j9.6 A

source current I₁ = I₂ / N =  3.6 - j4.8 A

and the impedance seen by the source is 60 + j80 Ω.

Power (P) = 3 kVA,

Primary voltage (V₁) = 480 V

Secondary voltage (V₂) = 240 V

Frequency (f) = 60 Hz

Load impedance (ZL) = 15 + j20 Ω

The primary current is equal to the secondary current multiplied by the turn's ratio of an ideal transformer.

Therefore, Load current, I₂ = V₂ / ZL = 240 / (15 + j20) = 7.2 - j9.6 A

The turns ratio, N = V₁ / V₂ = 480 / 240 = 2

The source current is given by,I₁ = I₂ / N = (7.2 - j9.6) / 2 = 3.6 - j4.8 A

The impedance seen by the source can be calculated by multiplying the impedance of the load by the square of the turns ratio,

Zin = ZL (N²) = (15 + j20) x (2²) = 60 + j80 Ω

Therefore, the load current is 7.2 - j9.6 A, the source current is 3.6 - j4.8 A, and the impedance seen by the source is 60 + j80 Ω.

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Answer:

Gravitational Energy

Answer:

Work input = 1620

Explanation:

Given the following data;

Work output = 810

Efficiency = 50%

To find the work input;

Mathematically, efficiency is given by the formula;

\( Efficiency = \frac {Out-put \; work}{In-put \; work} * 100 \)

Substituting into the formula, we have;

\( 50 = \frac {810}{WI} * 100 \)

Cross-multiplying, we have;

\( 50I = 810 * 100 \)

\( 50I = 81000 \)

\( WI = \frac {81000}{50} \)

Work input = 1620

Answer:

5.61 seconds

Explanation:

The baseball moves as a projectile. Its angle is 45° and its velocity is 95 miles per hour.

Let us convert this to metres per second:

1 mile per hour = 0.45 m/s

95 miles per hour = 95 * 0.45 = 42.75 m/s

We need to find the time of flight of the baseball. Time of flight is given as:

\(T = \frac{2u sin\alpha }{g}\)

where u = initial velocity

α = angle

g = acceleration due to gravity (9.8 m/s)

Therefore:

\(T = \frac{2 * 42.75 * sin40}{9.8}\\ \\T = 5.61 secs\)

The baseball was in the air for 5.61 seconds.

Molecular clouds are made up gas and dust, it obscure a light from background sources. at longer wavelengths, such as infrared and radio wavelengths, dust becomes more transparent.

This is because the dust particles are small compared to the wavelength of the light, so they scatter the light less effectively. As a result, longer wavelength observations can penetrate deeper into molecular clouds, allowing us to study the processes that are taking place within them. This is particularly important for studying the early stages of star formation, which often occur within molecular clouds.

By using longer wavelength observations, astronomers can see through the dusty outer layers of the cloud and observe the protostars that are forming within. Overall, observing molecular clouds at longer wavelengths provides a valuable tool for studying the processes that shape our universe.

According to the theory of molecular orbitals, molecular orbitals are created by joining the atomic orbitals of a molecule's constituent atoms. Atomic orbitals can be combined to form either bonding or antibonding molecular orbitals. A bonding molecular orbital is created when two atomic orbitals come together in phase. As a result, the resulting molecule orbital has a lower energy and greater stability than its atomic component orbitals. The stability of the molecule as a whole is influenced by electrons in orbitals that form bonds.

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Therefore, the current in the wire is 1.09 A.

We can use Ohm's law to solve for the current:

V = IR

where V is the potential difference, I is the current, and R is the resistance. The resistance of the wire can be found using the formula:

R = ρL/A

where ρ is the resistivity of the material (in this case, nichrome), L is the length of the wire, and A is the cross-sectional area of the wire.

The resistivity of nichrome is 1.0 x 10⁻⁶ Ωm. The cross-sectional area of the wire can be found using the formula for the area of a circle:

A = πr²

where r is the radius of the wire (half the diameter). Substituting in the given values, we get:

A = π(0.40 x 10⁻³ m)²

= 5.03 x 10⁻⁷ m²

The resistance of the wire is therefore:

R = (1.0 x 10⁻⁶ Ωm)(0.30 m) / 5.03 x 10⁻⁷ m²

= 5.98 Ω

Now we can solve for the current:

I = V/R

= 6.5 V / 5.98 Ω

= 1.09 A

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Answer:

because of the idea that like charges get repulsion as a force.

Explanation:

because you wrap the ball with foil, the negative charges will leave the foil and go into the ball by induction. This leaves the foil as a positively charged particle since its electrons left it for the ball, making the ball a negatively charged particle. but if you bring the negative charge near the foil, the electrons will transfer from that and go into the foil, making it negatively charged. Now, because the ball and the foil have the same charge, they repel. the foil flies off.

Answer:

uh,Free fall is the motion of a body where its weight is the only force acting on an object.

Answer:

4..... the answer is 4

Explanation:

Answer:

Electric field intensity is not conservative vector

Explanation:

Only electrostatic fields i.e. fields generated by a static charge distribution, are conservative in nature

Answer:

Maybe A.... I'm not sure

Explanation:

Given,

The length is r=5.70 m

The tangential speed is r=9.10 m/s

The centripetal acceleration is:

The acceleration is:

Answer:

6. Paula is correct. Think about buildings, buildings are constantly pushed by different forces like wind or gravity. The buildings aren’t moving but this doesn’t mean that they aren’t under force

Explanation:

Answer:

(a) The train took 100 seconds (1.667 minutes) to reach its top speed.

(b) The train travelled a distance of 270000 meters (270 kilometers) at top speed.

(c) The train decelerates at a rate of 2.5 meters per square second.

Explanation:

Statement is incomplete. Complete description is presented below:

A train started from a station and accelerated at \(0.5\,\frac{m}{s^{2}}\) to reach its top speed of \(50\,\frac{m}{s}\) and maintained this speed for 90 minutes.

When the train approached the next station the driver applied the brakes uniformly to bring the train to a stop in a distance of 500 meters.

(a) Calculate how long it took the train to reach its top speed.

(b) Calculate how far it travelled at its top speed.

(c) Calculate the acceleration experienced by the train when the brakes were applied.

(a) Let suppose that train accelerates uniformly. Then, the time needed by the vehicle (\(t\)), measured in seconds, is described by the following equation of motion:

\(t = \frac{v-v_{o}}{a}\) (1)

Where:

\(a\) - Acceleration, measured in meters per square second.

\(v_{o}\), \(v\) - Initial and final speed, measured in meters per second.

If we know that \(a = 0.5\,\frac{m}{s^{2}}\), \(v_{o} = 0\,\frac{m}{s}\) and \(v = 50\,\frac{m}{s}\), then the time needed by the train is:

\(t = \frac{50\,\frac{m}{s}-0\,\frac{m}{s}}{0.5\,\frac{m}{s^{2}} }\)

\(t = 100\,s\)

The train took 100 seconds (1.667 minutes) to reach its top speed.

(b) Let suppose that train travels at constant speed, the distance travelled by the train (\(s\)), measured in meters, is:

\(s = v\cdot t\) (2)

Where:

\(v\) - Top speed, measured in meters per second.

\(t\) - Time, measured in seconds.

If we know that \(v = 50\,\frac{m}{s}\) and \(t = 5400\,s\), then the distance travelled by the train at top speed is:

\(s = \left(50\,\frac{m}{s} \right)\cdot (5400\,s)\)

\(s = 270000\,m\)

The train travelled a distance of 270000 meters (270 kilometers) at top speed.

(c) Let suppose that train decelerates at constant rate. We can calculate the acceleration from the following expression:

\(a = \frac{v^{2}-v_{o}^{2}}{2\cdot s}\) (3)

Where:

\(v_{o}\), \(v\) - Initial and final speed, measured in meters per second.

\(s\) - Travelled distance, measured in meters.

If we know that \(v_{o} = 50\,\frac{m}{s}\), \(v = 0\,\frac{m}{s}\) and \(s = 500\,m\), then the acceleration of the train is:

\(a = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(50\,\frac{m}{s} \right)^{2}}{2\cdot (500\,m)}\)

\(a = -2.5\,\frac{m}{s^{2}}\)

The train decelerates at a rate of 2.5 meters per square second.

water does form a hydrogen but oil on the other hand does not

Answer:

The median lead level in the water is 7 ppm.

Explanation:

C. 25 grams

Explanation:

100g l 0 half-lives

50g l 1 half-life

25g l 2 half-lives

The acceleration force factor, fa, needed for this application is 0.086 ft-lb/in. Option A is the correct answer.

The acceleration force factor, fa, is a measure of the force required to accelerate a load over a given distance. It can be calculated using the formula:

fa = (v²) / (2 × d)

where v is the final velocity of the load and d is the distance over which the load is accelerated.

Substituting the given values of v = 35 ft/min and d = 0.5 inches, we get:

fa = (35 ft/min)² / (2 × 0.5 in) = 0.086 ft-lb/in

Therefore, the acceleration force factor needed for this application is 0.086 ft-lb/in, which corresponds to option (a). This means that a force of 0.086 ft-lb is required to accelerate the load from 0 to 35 ft/min over a distance of 0.5 inches.

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The question is -

We want a load at the end of a cylinder to be accelerated from 0 to 35 ft/min in 0.5 inches. what is the acceleration force factor, fa, needed for this application?

group of answer choices,

a. 0.086

b. 0.04

c. 0.255

d. 0.13

The moment of inertia about the rotation axis for the given playground toy, with two children sitting opposite each other, is approximately 145.35 kg·m².

To determine the moment of inertia about the rotation axis for the given playground toy, we need to consider the contributions from the seats and the two children.

Given:

Mass of each seat = 6.4 kg

Length of the rods (r) = 1.5 m

Mass of the first child (m₁)= 16 kg

Mass of the second child (m₂) = 23 kg

The moment of inertia of each seat can be calculated using the formula for the moment of inertia of a point mass about an axis:

\(I_{seat} = m_{seat times} r^2\)

For each seat, the moment of inertia is:

\(I_{seat} = 6.4 kg times (1.5 m)^2= 14.4 kg\cdot m^2\)

Now, to calculate the moment of inertia contributed by the children, we need to consider that the children are located opposite each other. Assuming the axis of rotation passes through the center of mass of the children-seats system, the moment of inertia for each child is:

\(I_{child} = m_{child times} r^2\)

For the first child (m₁):

\(I_1 = 16 kg times (1.5 m)^2 = 36 kgm^2\)

For the second child (m₂):

\(I_2 = 23 kg times (1.5 m)^2 = 51.75 kgm^2\)

Finally, we can calculate the total moment of inertia by summing the contributions from the seats and the children:

Total moment of inertia =\(4 times I_{seat} + I_1 + I_2\)

= \(4 times (14.4 kgm^2) + 36 kgm^2 + 51.75 kgm^2\)

= \(57.6 kgm^2 + 36 kgm^2 + 51.75 kgm^2\)

= \(145.35 kgm^2\)

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Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

\(\hrulefill\)

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

The torque required to give an object an angular acceleration of 1.40 rad/s2 if it is rotated about the x axis is 1.4 N*m.

The torque is given by the formula:

T = I * α

where T is the torque, I is the moment of inertia, and α is the angular acceleration.

In this case, the moment of inertia is equal to the mass of the object * the radius of the object squared.

\(I = m * r^2\)

If the mass of the object is 1.0 kg and the radius of the object is 1.0 m, then the moment of inertia is 1.0 kg*m^2.

Plugging in the values for T, I, and α, we get the following:

T =\(1.0 kg*m^2 * 1.40 rad/s^2 = 1.4 N*m\)

Therefore, the torque required to give an object an angular acceleration of 1.40 rad/s2 if it is rotated about the x axis is 1.4 N*m.

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