12. Which of the following shows the domain and range of F(x) = 2 |x|?

Answer: 40%

Step-by-step explanation:

Answer:

x = 40

Step-by-step explanation:

x/(2 1/2) = 16/1

x/(5/2) = 16

Multiply both sides by 5/2.

x = 16 * 5/2

x = 80/2

x = 40

Answer: x = 40

The example that illustrates the difference between statistical significance and practial significance is

In a survey arranged by school-authority of a district on participation in sports by school-going boys and girls, it is found that 60% of boys and 57% of girls participate in outdoor sports. Thus the survey shows a 3% difference between school-going boy-participants and girl-participants in outdoor sports. Now the point is how much significance this 3% difference has statistically as well as practically. Statistical significance of this 3% depends upon the size of data used in determining the percentage of boys and girls participate in sports. If a sufficiently big sample size is used then the difference is statistically significant, and if a very small sample size is used then the difference is statistically insignificant. Thus bigger the sample size more is the statistical significance of a computed figure.

On the other hand practical significance of this 3% difference arises if decision is made or action is taken or needs to be taken on the basis of this 3% difference. If cost permits, the authority may consider promoting girl students participation in sports in order to bring about more gender parity in outdoor sports. In this case the 3% difference though small, may be practically significant.

Statistical significance is a measure of whether your research findings are meaningful. It is concerned with whether a research result is due to chance or sampling variability. Where, practical significance is concerened with wheteher the result is useful in the real world.

Therefore, the example that illustrates the difference between statistical significance and practial significance is

In a survey arranged by school-authority of a district on participation in sports by school-going boys and girls, it is found that 60% of boys and 57% of girls participate in outdoor sports. Thus the survey shows a 3% difference between school-going boy-participants and girl-participants in outdoor sports. Now the point is how much significance this 3% difference has statistically as well as practically. Statistical significance of this 3% depends upon the size of data used in determining the percentage of boys and girls participate in sports. If a sufficiently big sample size is used then the difference is statistically significant, and if a very small sample size is used then the difference is statistically insignificant. Thus bigger the sample size more is the statistical significance of a computed figure.

On the other hand practical significance of this 3% difference arises if decision is made or action is taken or needs to be taken on the basis of this 3% difference. If cost permits, the authority may consider promoting girl students participation in sports in order to bring about more gender parity in outdoor sports. In this case the 3% difference though small, may be practically significant.

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Answer:

ggddhi hhuoiss nndkdoy hsudhh jejdgbnk hehrjji

The marginal pdf of X is: f1(x) = 5x^3, for 0 < x < 1, and the conditional pdf of Y given X is: f2(y|x) = 3y^2 / x, for 0 < y < x < 1

We are given the joint pdf f(x,y) = 15xy^2, with 0 < y < x < 1. We need to find the marginal pdf f1(x) and the conditional pdf f2(y|x).

a) To find the marginal pdf f1(x), we need to integrate the joint pdf f(x,y) over the variable y:

f1(x) = ∫[0, x] 15xy^2 dy

Integrating with respect to y, we get:

f1(x) = 5x*y^3 | [0, x] = 5x^3

So the marginal pdf f1(x) = 5x^3.

b) To find the conditional pdf f2(y|x), we will use the following formula:

f2(y|x) = f(x, y) / f1(x)

We already found f1(x) = 5x^4. Now we'll substitute the values of f(x,y) and f1(x) in the formula:

f2(y|x) = (15xy^2) / (5x^4)

Simplifying the expression, we get:

f2(y|x) = 3y^2 / x^3

So the conditional pdf f2(y|x) = 3y^2 / x^3.

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Answer:

C

Step-by-step explanation:

\( \frac{1}{4} (2 - 5x + 6) \\ = \frac{1}{2} - \frac{5}{4} x + \frac{3}{2} \\ = - \frac{5}{4}x + 2\)

The measurement closest to the circumference of the coin in millimeters is 75.36 mm.

The circumference of a circle can be calculated using the formula C = πd, where C is the circumference and d is the diameter of the circle.

Given that the diameter of the coin is 24 mm, we can substitute this value into the formula to find the circumference: C = π(24) = 75.36 mm (rounded to two decimal places).

Therefore, the measurement closest to the circumference of the coin in millimeters is 75.36 mm.

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Since the polygons DEFG and SPQR are congruent

That means

DE = SP

EF = PQ

FG = QR

DG = SR

AND

mmmm

Since DE = x and SP = 3, then

x = 3

Since < S = 107 degrees and

In the polygon DEFG, the sum of the angles is 360 degrees, then

107 + (y + 3) + 83 + (y + 1) = 360

Add the like terms on the left side

(107 + 3 + 83 + 1) + (y + y) = 360

194 + 2y = 360

Subtract 194 from both sides

194 - 194 + 2y = 360 - 194

2y = 166

Divide both sides by 2

y = 83

The value of x is 3 and the value of y is 83

The required probability that the captain will be a senior is 0.3125.

Probability can be defined as the ratio of favorable outcomes to the total number of events.

Here,
Neil's soccer team consists of 8 sophomore members, 14 junior members, and 10 senior members.
Total number of person = 14 + 10 + 8 = 32
The probability that the captain will be a senior, then the number of favorable events = 10

The probability that the captain will be a senior is given as,
= 10 / 32
= 0.3125

Thus, the required probability that the captain will be a senior is 0.3125.

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Answer:

hope this helps you

Taylor series is \(f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }\)

To find the Taylor series for f(x) = ln(x) centering at 9, we need to observe the pattern for the first four derivatives of f(x). From there, we can create a general equation for f(n). Starting with f(x), we have

f(x) = ln(x)

\(f^{1}(x)= \frac{1}{x} \\f^{2}(x)= -\frac{1}{x^{2} }\\f^{3}(x)= -\frac{2}{x^{3} }\\f^{4}(x)= \frac{-6}{x^{4} }\)

.

.

.

Since we need to have it centered at 9, we must take the value of f(9), and so on.

f(9) = ln(9)

\(f^{1}(9)= \frac{1}{9} \\f^{2}(9)= -\frac{1}{9^{2} }\\f^{3}(x)= -\frac{1(2)}{9^{3} }\\f^{4}(x)= \frac{-1(2)(3)}{9^{4} }\)

.

.

.

Following the pattern, we can see that for \(f^{n}(x)\),

\(f^{n}(x)=(-1)^{n-1}\frac{1.2.3.4.5...........(n-1)}{9^{n} } \\f^{n}(x)=(-1)^{n-1}\frac{(n-1)!}{9^{n}}\)

This applies for n ≥ 1, Expressing f(x) in summation, we have

\(\sum_{n=0}^{\infinite} \frac{f^{n}(9) }{n!} (x-9)^{2}\)

Combining ln2 with the rest of series, we have

\(f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }\)

Taylor series is \(f(x) = ln2 + \sum_{n=1)^{\infty}(-1)^{n-1} \frac{(n-1)!}{n!(9)^{n}(x9)^{2} }\)

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To determine the number of smaller boxes that would contain the same amount of cereal as a larger box, we set the expressions representing the cereal content equal to each other. Solving the equation, we find that 15 smaller boxes are required to match the cereal quantity in the larger box.

To find the number of smaller boxes that equal the same amount of cereal in a larger box, we need to equate the two expressions and solve for n.

Setting the expressions equal to each other:

10 + 6.3n = 7 + 6.5n

Simplifying the equation:

6.3n - 6.5n = 7 - 10

-0.2n = -3

Dividing both sides by -0.2:

n = -3 / -0.2

n = 15

Therefore, 15 smaller boxes would equal the same amount of cereal as the larger box.

The problem states that the expressions 10 + 6.3n and 7 + 6.5n represent the amount of cereal in the new larger box. The variable n represents the number of smaller boxes.

To find how many smaller boxes are equivalent to the larger box, we need to set the two expressions equal to each other and solve for n. This equation represents the balance between the amount of cereal in the larger box and the combined amount of cereal in the smaller boxes.

By simplifying the equation and solving for n, we find that 15 smaller boxes are needed to equal the same amount of cereal as the larger box.

This means that if the cereal manufacturer wants to package the same amount of cereal as the larger box, they would need to use 15 smaller boxes instead. This calculation helps the manufacturer determine the number of smaller boxes needed to maintain the same quantity of cereal while changing the box size.

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On solving the provided question, we can say that  let the equation be  X =   4ª - 4(2) (-8) => X = -15

A mathematical equation is a formula that joins two statements and uses the equal symbol (=) to indicate equality. A mathematical statement that establishes the equality of two mathematical expressions is known as an equation in algebra. For instance, in the equation 3x + 5 = 14, the equal sign places the variables 3x + 5 and 14 apart. The relationship between the two sentences on either side of a letter is described by a mathematical formula. Often, there is only one variable, which also serves as the symbol. for instance, 2x – 4 = 2.

let the equation be

X =   4ª - 4(2) (-8)

here, a = 0

X = 1 - 8-8

X = -15

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Answer: The y intercept is wherever the line crossed the Y axis. I can't see all the graphs but for example graph A would have a Y intercept of -3. Because the line crosses the point (0,-3).

If you update the pic I can give the answer.

Therefore, the probability that by the seventh dishwasher sold, none of the defective ones remain is 7/60.

To solve this problem, we can use the concept of conditional probability.

Let's break it down step by step:

Step 1: Calculate the probability of selling a non-defective dishwasher on the first sale. Since there are 10 dishwashers in total and 3 of them are defective, there are 7 non-defective dishwashers. Therefore, the probability of selling a non-defective dishwasher on the first sale is 7/10.

Step 2: Calculate the probability of selling a non-defective dishwasher on the second sale. After selling one dishwasher, there are 9 dishwashers left in the showroom, with 6 of them being non-defective. Therefore, the probability of selling a non-defective dishwasher on the second sale is 6/9, which simplifies to 2/3.

Step 3: Repeat Step 2 for the third, fourth, fifth, sixth, and seventh sales. Since each time we sell a dishwasher, the total number of remaining dishwashers decreases by one, and the number of non-defective dishwashers also decreases by one, the probability remains the same each time. So, for each sale, the probability is 2/3.

Step 4: Multiply the probabilities together. Since the sales are independent events, we can multiply the probabilities of each sale together to find the overall probability. In this case, we need to calculate (7/10) * (2/3) * (2/3) * (2/3) * (2/3) * (2/3) * (2/3).

Calculating this expression gives us (7/10) * (2/3) * (2/3) * (2/3) * (2/3) * (2/3) * (2/3) = 196/1620 = 7/60.

None of the given answer choices match this result exactly. The closest answer is (a) 7/120, but it is not the exact probability calculated in this solution.

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Answer:

Step-by-step explanation:

You want two methods of choosing points on the line with slope 1/2 through A(-1, 2).

Writing the equation in standard form, we can find the x- and y-intercepts. To get there, we can start from point-slope form:

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

  y -2 = 1/2(x -(-1)) . . . . . using given slope and point

  2y -4 = x +1 . . . . . . . . . . multiply by 2

  x -2y =  -5 . . . . . . . . . . . . add -1 -2y

Setting x=0 tells us the y-intercept is ...

  0 -2y = -5

  y = -5/-2 = 5/2

So, the y-intercept is (0, 5/2).

Setting y=0 tells us the x-intercept is ...

  x -2(0) = -5

  x = -5

So, the x-intercept is (-5, 0).

It will be convenient to choose an arbitrary y-value to find another point on the line. We can pick y = 6, for example, Then the corresponding x-value is ...

  x -2y = -5

  x = -5 +2y = -5 +2(6) = 7

Another point on the line is (7, 6).

__

Additional comment

If we were to choose an arbitrary value for x, we would want it to be odd, so the corresponding y-value would be an integer. We chose to pick an arbitrary value of y so we didn't have to worry about how to make the x-value an integer.

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Answer:

10 popcorn orders

Step-by-step explanation:

\(10 + 4.55 x = 8 + 4.75x \\ 4.55x - 4.75x = 8 - 10 \\ - 0.2x = 8 - 10 \\ - 0.2x = - 2 \\ x = \frac{ - 2}{ - 0.2} \\ x = 10\)

Answer:

1/3x  +1/3

Step-by-step explanation:

2/3x + 1/3 - 1/3x

Combine like terms

2/3 x - 1/3x     +1/3

1/3x         +1/3

Answer:

1/3x + 1/3

Step-by-step explanation:

Solution: put all alphabets and numbers at one side.

2/3x + 1/3 - 1/3x =

2/3x - 1/3x + 1/3 =

1/3x + 1/3

The eccentricity of an infinitely long ellipse will be less than 1.

The ratio of the focus's distance from the ellipse's center and the ellipse's distance from one of its ends.

It is easy to comprehend how circular an ellipse is in relation to a circle when we consider its eccentricity. It also measures the ovalness of the ellipse and eccentricity close to one refers to the high degree of ovalness.

The eccentricity of an ellipse is always less than 1 i.e e < 1. The formula for the eccentricity of an ellipse is given by

Which can be written as

Where

e = Eccentricity of the ellipse

c = Distance of the focus from the center of the ellipse

a = Distance of the end of the ellipse from the center

As we know the eccentricity of an ellipse is always less than 1, So we can conclude that the eccentricity of an infinitely long ellipse is less than 1.

Therefore,

The eccentricity of an infinitely long ellipse will be less than 1.

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Answer:

x = −2 and y = 2

Step-by-step explanation:

Multiply the first equation by 2, and multiply the second equation by 1.

2(−3x + 2y = 10)

1(6x + 6y = 0)

Becomes:

−6x + 4y = 20

6x + 6y = 0

Add these equations to eliminate x:

10y = 20

Then solve 10y = 20 for y:

10y = 20

10y/10 = 20/10 (Divide both sides by 10)

y = 2

Now that we've found y let's plug it back in to solve for x.

Write down an original equation:

−3x + 2y = 10

Substitute 2 for y in −3x + 2y = 10:

−3x + (2)(2) = 10

−3x + 4 = 10(Simplify both sides of the equation)

−3x + 4 − 4 = 10 − 4(Subtract 4 to both sides)

−3x = 6

-3x/-3 = 6/-3 (Divide both sides by -3)

x = −2

If the three-phase end-of-line current is 645 Amps, the single-phase end-of-line current would be 645 / √3 ≈ 372.36 Amps.

To find the single-phase end-of-line current from a given three-phase end-of-line current, you can use the formula: Single-phase end-of-line current = Three-phase end-of-line current / √3.

In this case, the three-phase end-of-line current is 645 Amps. By dividing this value by the square root of three (√3), we can calculate the single-phase end-of-line current. Evaluating the formula, we have: 645 / √3 ≈ 372.36 Amps.

The square root of three (√3) is a constant value used in electrical calculations to convert between three-phase and single-phase systems. Dividing the three-phase current by √3 distributes the total current across a single phase, providing the equivalent single-phase end-of-line current.

By applying the formula, we determined that the single-phase end-of-line current is approximately 372.36 Amps for a given three-phase end-of-line current of 645 Amps.

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The probability of either event E or event F occurring, when E and F are mutually exclusive, is 0.85.

If E and F are mutually exclusive events, it means that they cannot occur simultaneously. In such cases, the probability of either event E or event F occurring is the sum of their individual probabilities.

Given that P(E) = 0.34 and P(F) = 0.51, we can calculate the probability of E or F, denoted as P(E or F), as:

P(E or F) = P(E) + P(F)

Substituting the given values, we have:

P(E or F) = 0.34 + 0.51

Calculating the sum, we find:

P(E or F) = 0.85

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Answer:

28m

Step-by-step explanation:

Formula of area

AREA = LENGTH (multiply) BREATH

Answer:

The area of a triangle can be calculated with the formula: 1/2(bh), where b is the base length, and h is the height.

In this case, 4 is the base, and 7 is the height.

So we have: Area = 1/2(4)(7)

Simplifying: Area = 2(7), Area = 14.

The area of the triangle is 14 meters squared.

Let me know if this helps!

The 'e' value of 6e12 means 6 x 10^12, which is equal to 6000000000000. It is a scientific notation used to represent a very large number.

The 'e' value of 6e12 is a scientific notation used to represent a very large number. 6e12 is shorthand for 6 x 10^12, which means 6 multiplied by 10 to the power of 12. To calculate the value of 6e12, first note that 10 to the power of 12 is equal to 1000000000000. Then, multiply 6 by 1000000000000 to get 6000000000000. Therefore, 6e12 is equal to 6000000000000. This notation is commonly used to represent very large numbers without having to write out all of the zeros. It is also useful when dealing with large numbers in scientific calculations.

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An irrational number is a real number that cannot be expressed as a ratio of integers. The decimal expansion of an irrational number is neither terminating nor recurring.

Let us check the options one at a time:

OPTION A: -√196

Answer:

addition +

Step-by-step explanation:

You always do what's in parenthesis first.

Answer:

Do addition first. It is because it is in the ()

Answer:

$35

Step-by-step explanation:

The number of different ways to select all of the items without replacement from a sample space with 48 elements is approximately 1.241391 × 10^61, which can be expressed in factorial notation as 48!.

When selecting items without replacement from a sample space, the number of different ways to select all of the items can be calculated using factorial notation.

In this case, the sample space has 48 elements. To find the number of ways to select all of the items without replacement, we need to calculate the factorial of 48, denoted as 48!.

Factorial notation represents the product of all positive integers less than or equal to a given number. So, 48! represents the product of all positive integers from 1 to 48.

Mathematically, we can calculate 48! as:

48! = 48 × 47 × 46 × ... × 3 × 2 × 1

This calculation can be time-consuming and challenging to do manually. However, using mathematical software or calculators with factorial capabilities, we can find the value of 48!.

By evaluating the expression, we find that 48! is an extremely large number:

48! ≈ 1.241391 × 10^61

Therefore, there are approximately 1.241391 × 10^61 different ways to select all of the items from the sample space without replacement.

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