1/3x= -2/5 solve for x

Answer:

- sinu

Step-by-step explanation:

using the difference identity for sine

sin(a - b) = sinacosb - cosasinb

then

sin(u - π )

= sinucosπ - cosusinπ

= sinu(- 1) - cosu(0)

= - sinu - 0

= - sinu

If a rectangular prism has a length of 2 meters, a width of 4 meters, and a height of 2 meters. The volume of the prism is 16 cubic meters.

The volume of a rectangular prism is given by the formula:

Volume = length x width x height

Substituting the given values, we get:

Volume = 2 meters x 4 meters x 2 meters

Simplifying this expression, we get:

Volume = 16 cubic meters

Therefore, the volume of the prism is 16 cubic meters.

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Answer:

A

Step-by-step explanation:

For a right triangle

\(A=\frac{ab}{2} \\\frac{(10.4)(15.3)}{2} =79.56\)

This is the same as the other triangle because they are the same size because of congruency

Area of the rectangle

\(a^2+b^2=c^2\\\)

\(\sqrt{(10.4^2+15.3^2} =c\)

\(c= 18.5\)

18.5 x 7 = 129.5

Add them all up

129.5+79.56+79.56= 288.62

Answer:

4

Step-by-step explanation:

The slope for the given equation is 4.

Answer:

4

Step-by-step explanation:

Since the equation is written in y=mx+b form, we know that M is the value of the slope.

Since y=4x+5 is in slope intercept form, 5 would be (0,5) for y-Intercept

Consequently, y=90/x serves as the equation illustrating the connection between the two variables.

An equation is a mathematical formula that joins two statements and uses the equal symbol (=) to indicate equivalence. A mathematical statement that proves the equality of two mathematical expressions is known as an equation in algebra. For instance, in the equation 3x + 5 = 14, the equal sign divides the variables 3x + 5 and 14. The relationship between the two sentences on either side of a letter is explained by a mathematical formula. There is frequently only one variable, which also serves as the symbol. for instance, 2x - 4 = 2.

given

We can express this relationship as y1x if the variable y varies inversely as the variable x.

Y=k/x is the result of taking away the proportionality sign and adding a proportionality constant.

If y is equal to 18 when x is equal to 5, then 18=k/5 k=185=90.

Consequently, y=90/x serves as the equation illustrating the connection between the two variables.

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The simplification of the expressions in the question using the rules of indices are as follows;

1.) 6·e⁰ + (11·f)⁰ - 5/g⁰ = 2

2. (3⁻⁴ + 5⁻³)⁻¹ = \(49\frac{31}{206}\)

3. (3⁻⁴ + 5⁻³)⁻² = \(2415\frac{32685}{42436}\)

4.) \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{10\cdot c^{-5} \cdot d^6 \cdot e^{-8}}\) = \(\dfrac{c^5\cdot e^8}{2\cdot d^5}\)

5.)  \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5}\right)^{-3 }}{7\cdot \left(p^{-6} \cdot q^8\right)^{-4}} =\dfrac{-5\cdot m^{12}\cdot n^{15}\cdot q^{32}}{7\cdot p^{24}}\)

An index or indices is the power by which a number or variable or expression raised.

1.) 6·e⁰ + (11·f)⁰ - 5/g⁰

6·e⁰ + (11·f)⁰ - 5/g⁰ = 6 × 1 + 1 - 5/1

6 × 1 + 1 - 5/1 = 6 + 1 - 5 = 2

Therefore;

6·e⁰ + (11·f)⁰ - 5/g⁰ = 2

2.) (3⁻⁴ + 5⁻³)⁻¹

(3⁻⁴ + 5⁻³)⁻¹ = (1/(3⁴) + 1/(5³))⁻¹ = 1/(1/(3⁴) + 1/(5³))

1/(1/(3⁴) + 1/(5³)) = 1/(1/81 + 1/125) = 1/((125 + 81)/(81×125))

1/((125 + 81)/(81×125)) = (81 × 125)/(125+81) = 10125/209

10125/206 = 49 + 31/206

(3⁻⁴ + 5⁻³)⁻¹ = \(49 \frac{31}{206}\)

3.) (3⁻⁴ + 5⁻³)⁻²

(3⁻⁴ + 5⁻³)⁻² = 1/((1/3⁴ + 1/5³)²)

1/((1/3⁴ + 1/5³)²) = 1/((1/81 + 1/125)²)

1/((1/81 + 1/125)²) = 1/(((125 + 81)/(81 × 125))²)

1/(((125 + 81)/(81 × 125))²) = 1/((206/10125)²)

1/((206/10125)²) = (10125)²/(206)² = 102515625/42436

102515625/42436 = 2415 32685/42436

(3⁻⁴ + 5⁻³)⁻² = \(2415\frac{32685}{42436}\)

4.)  \(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}}\)

\(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}} = \dfrac{5\times 1}{10\times \left(\frac{1}{c^5}\times d^6 \times \frac{1}{e^8} \right) }\)

\(\dfrac{5\times 1}{10\times \left(\frac{1}{c^5}\times d^6 \times \frac{1}{e^8} \right) } = \dfrac{5}{10\times \left(\frac{d^6}{c^5\times e^8} \right) }\)

\(\dfrac{5}{10\times \left(\frac{d^6}{c^5\times e^8} \right) } = \dfrac{1}{2\times \left(\frac{d^6}{c^5\times e^8} \right) }\)

\(\dfrac{1}{2\times \left(\frac{d^6}{c^5\times e^8} \right) } = \dfrac{c^5\times e^8}{2\cdot d^6}\)

\(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}}= \dfrac{c^5\times e^8}{2\cdot d^6}\)

5.) \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\rright)^{-4}}\)

\(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\right)^{-4}} =\dfrac{-5\cdot \dfrac{1}{\left(\frac{1}{m^{4}}\times \frac{1}{n^{5}} \right)^{3}} }{7\cdot \dfrac{1}{\left(\frac{1}{p^{6}}\times q^8\right)^{4}} }\)

\(\dfrac{-5\cdot \dfrac{1}{\left(\frac{1}{m^{4}}\times \frac{1}{n^{5}} \right)^{3}} }{7\cdot \dfrac{1}{\left(\frac{1}{p^{6}}\times q^8\right)^{4}} } = \dfrac{-5\cdot {\left(m^4\times n^5\right)^3} }{7\cdot \left( \dfrac{p^6}{q^8\right)^{4}} }\)

\(\dfrac{-5\cdot {\left(m^4\times n^5\right)^3} }{7\cdot \left( \dfrac{p^6}{q^8\right)^{4}} } = \dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^8}{p^6}\right)^4 }\)

\(\dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^8}{p^6}\right)^4 } = \dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^{32}}{p^{24}}\right) }\)

\(\dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^{32}}{p^{24}}\right) } = \dfrac{-5\times {m^{12}\times n^{15}\times q^{32}} }{7\times p^{24}}\)

\(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\right)^{-4}} = \dfrac{-5\times {m^{12}\times n^{15}\times q^{32}} }{7\times p^{24}}\)

6.) (3·x⁻⁴·y⁻⁵·z⁻²)⁻²

(3·x⁻⁴·y⁻⁵·z⁻²)⁻² = \(3\cdot \left(\dfrac{1}{\left(\dfrac{1}{x^4} \cdot \dfrac{1}{y^5} \cdot \dfrac{1}{z^2} } \right)^2\right)\)

\(3\cdot \left(\dfrac{1}{\left(\dfrac{1}{x^4} \cdot \dfrac{1}{y^5} \cdot \dfrac{1}{z^2} } \right)^2\right) = 3\cdot \left(x^4\cdot y^5\cdot x^2\right)^2\)

3·(x⁴·y⁵·x²)² = 3·x⁸·y¹⁰·x⁴

Therefore;

(3·x⁻⁴·y⁻⁵·z⁻²)⁻² = 3·x⁸·y¹⁰·x⁴

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Ryan began the race ahead.

Here , Ryan is represented in red lines,

Initially he started the race ahead later at 20 min the race became a tie.

Therefore from the graph it is clear that Ryan started the race ahead.

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Answer:

2·2·2·2 = 16

Step-by-step explanation:

everytime a number is raised by another, that means you are going to multiply the base number  times itself as many times as the exponents tells you. this is a little but tricky to explain, so let me give you some examples:

2² → in this case the base number is 2 and the exponent is 2 as well, so you will multiply 2 times itself, 2 times:

2² = 2 · 2 = 4

2³ → in this case the base number is 2 and the exponent is 3, so you will multiply 2 times itself, 3 times:

2³ = 2 · 2 · 2 = 8

In the question asked, 2 is being raised by 4, so you will multiply 2 times itself, 4 times:

2^4 = 2·2·2·2 = 16

the same format will be used regardless of the base number and the exponent

i hope this helps! :)

The ratio of the sides EF/LM after the transformation is 1/8

Transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, reflection and dilation.

Dilation is the increase or decrease in size of a figure by a factor while translation is the movement of a point up, down, left or right.

Given the tansformation:

Hence:

LM = 8 * EF

EF/LM = 1/8

The ratio of the sides EF/LM after the transformation is 1/8

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The following phrases are used in place of supply chain:

Supply network ; Demand chain ; Extended enterprise ; Supply web.

The supply chain is a networked system of businesses, people, information, and assets created to locate, produce, and transport items from their point of origin to their final destination, which is often from the a supplier to a customer.

Modern supply chains sometimes span several nations and involve numerous processes, making them exceedingly complicated.

The fundamental steps in such a supply chain are as follows:

Thus, the following phrases are used in place of supply chain:

Supply network ; Demand chain ; Extended enterprise ; Supply web.

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Answer:

4

Step-by-step explanation:

5+3=8 and 5-3=2 which is 8/2=4

Answer:(6,2),(6,2)

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

I took the test it was right

The two-column proves that ΔMNP ≅ ΔNPQ by the ASA Congruence Theorem is shown in the image attached below (see attachment).

The ASA congruence theorem states that two triangles that have two pairs of congruent angles and a pair of included congruent sides are considered congruent triangles.

We are given that both triangles have two pairs of congruent angles, by the reflexive property, we can state that QP ≅ QP in each triangle.

By this, it means both triangles have two pairs of congruent angles and a pair of congruent included sides. Therefore, ΔMNP ≅ ΔNPQ by the ASA Congruence Theorem.

Thus, the two-column proves that ΔMNP ≅ ΔNPQ by the ASA Congruence Theorem is shown in the image attached below (see attachment).

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The value of q is 0.35.

The value of p is 0.16.

The value of r is 0.27.

The value of P(A given NOT B) is approximately 0.4211.

To calculate the values of p, q, and r, we can use the information provided in the Venn diagram and the probabilities of events A and B.

Given:

P(A) = 0.43

P(B) = 0.62

P(A∩B) = 0.27

Calculating the value of p:

The value of p represents the probability of event A occurring without event B. In the Venn diagram, p corresponds to the region inside A but outside B.

We can calculate p by subtracting the probability of the intersection of A and B from the probability of A:

p = P(A) - P(A∩B)

= 0.43 - 0.27

= 0.16

Therefore, the value of p is 0.16.

Calculating the value of q:

The value of q represents the probability of event B occurring without event A. In the Venn diagram, q corresponds to the region inside B but outside A.

We can calculate q by subtracting the probability of the intersection of A and B from the probability of B:

q = P(B) - P(A∩B)

= 0.62 - 0.27

= 0.35

Therefore, the value of q is 0.35.

Calculating the value of r:

The value of r represents the probability of both event A and event B occurring. In the Venn diagram, r corresponds to the intersection of A and B.

We are given that P(A∩B) = 0.27, so the value of r is 0.27.

Therefore, the value of r is 0.27.

Finding the value of P(A given NOT B):

P(A given NOT B) represents the probability of event A occurring given that event B does not occur. In other words, it represents the probability of A happening when B is not happening.

To calculate this, we need to find the probability of A without B and divide it by the probability of NOT B.

P(A given NOT B) = P(A∩(NOT B)) / P(NOT B)

We can calculate the value of P(A given NOT B) using the provided probabilities:

P(A given NOT B) = P(A) - P(A∩B) / (1 - P(B))

= 0.43 - 0.27 / (1 - 0.62)

= 0.16 / 0.38

≈ 0.4211

Therefore, the value of P(A given NOT B) is approximately 0.4211.

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Answer:

9a-2=7

Step-by-step explanation:

4a+ 5a-2=5+3-1

To simplify each side, combine like terms.

4a+5a = 9a

5+3-1 = 7

The equation becomes:

9a-2=7

The probability that a randomly selected student has a typing speed of less than 51 words per minute if the mean (u) is 47 words per minute and the standard deviation (o) is 4 words per minute is; 68%

The empirical rule in statistics states that for normal distributions, 68% of observed data points will lie inside one standard deviation of the mean, 95% will fall within two standard deviations, and 99.7% will occur within three standard deviations.

The formula for z-score is;

z = (x' - μ)/σ

where;

x' is sample mean

μ is population mean

σ is standard deviation

We are given;

x' = 51

μ = 47

σ = 4

Thus;

z = (51 - 47)/4

z = 1

From empirical formula at 1 standard deviation above the means, the probability is 68%.

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Answer: 7.9

Step-by-step explanation:

\(P=2000, r=0.09, n=2\\\\4000=2000\left(1+\frac{0.09}{2} \right)^{2t}\\\\4000=2000(1.045)^{2t}\\\\2=1.045^{2t}\\\\\log_{1.045} 2=2t\\\\t=\frac{\log_{1.045} 2}{2}\\\\t \approx 7.9\)

Answer:B) . 75°

Step-by-step explanation:dfghjkjhgfdfgty

Answer:

its 80

Step-by-step explanation:

i did it on usa test prep

Answer:

its the 3rd answer

Step-by-step explanation:

Answer:

A d= 3t

Step-by-step explanation:

(6)= 3(2)

(9)= 3(3)

(12)= 3(4)

(15)= 3(5)

(18)= 3(6)

Answer:

A) x = -3

Step-by-step explanation:

|3(-3) + 9| = 0

|-9 + 9| = 0

|0| = 0

0 = 0

Answer:

A)x=−3

Step-by-step explanation:

Step 1: Add -6 to both sides.

|3x+9|+6+−6=6+−6

|3x+9|=0

Step 2: Solve Absolute Value.

|3x+9|=0

We know 3x+9=0

3x+9=0(Possibility 1)

3x+9−9=0−9(Subtract 9 from both sides)

3x=−9

3x /3 = −9 /3

(Divide both sides by 3)

x=−3

Answer:

$95.00 = $3.99s + $15.20

Answer:

300 I think

Step-by-step explanation:

V=1/3 Bh

B=10*9=90

90*10=900         1/3 of 900= 300

Answer:

The probability that a skid of 50 DVD players will contain at least 3 defective units is 0.9487.

Step-by-step explanation:

We are given that Avery and Bradly work at a large electronics manufacturer that produces DVD players. The defective rate on the assembly line has gone up 12% and a skid of 50 DVD players has been selected by the manager.

Let X = Number of defective units of DVD players

The above situation can be represented through the binomial distribution;

\(P(X = r) = \binom{n}{r}\times p^{2} \times (1-p)^{n-r}; x= 0,1,2,3,....\)

where, n = number of samples (trials) taken = 50 DVD players

            r = number of success = at least 3 defective units

           p = probability of success which in our question is the probability

                 of defective rate, i.e; p = 12%

So, X ~ Binom(n = 50, p = 0.12)

Now, the probability that a skid of 50 DVD players will contain at least 3 defective units is given by = P(X \(\geq\) 3)

P(X \(\geq\) 3) = 1 - P(X = 0) - P(X = 1) - P(X = 2)

= \(1 - [ \binom{50}{0}\times 0.12^{0} \times (1-0.12)^{50-0}]-[ \binom{50}{1}\times 0.12^{1} \times (1-0.12)^{50-1}]-[ \binom{50}{2}\times 0.12^{2} \times (1-0.12)^{50-2}]\)

= \(1 - [ 1 \times 1 \times 0.88^{50}]-[50 \times 0.12^{1} \times 0.88^{49}]-[ 1225 \times 0.12^{2} \times 0.88^{48}]\)

= 0.9487

Hence, the probability that a skid of 50 DVD players will contain at least 3 defective units is 0.9487.

Answer:

the answer is 12

Step-by-step explanation:

the answer is 12

Answer:

∠ ABC = 49°

Step-by-step explanation:

the chord- tangent angle ABC is half the measure of the intercepted arc AB

∠ ABC = \(\frac{1}{2}\) AB = \(\frac{1}{2}\) × 98° = 49°