2. The price of licorice is proportional to its length. It costs
$0.50 to buy 5 in. How much licorice can you get for $1.80?

Answer: there is no picture I will help if you repost it ? Brainliest if you can I need 4 more to rank up

Step-by-step explanation:

\(~~~~~~ \stackrel{\textit{\Large Anna}}{\textit{Simple Interest Earned Amount}} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$100\\ r=rate\to 4.5\%\to \frac{4.5}{100}\dotfill &0.045\\ t=years\dotfill &3 \end{cases} \\\\\\ A=100[1+(0.045)(3)]\implies A=100(1.135)\implies A=113.5 \\\\[-0.35em] ~\dotfill\)

\(~~~~~~ \stackrel{\textit{\Large Matt}}{\textit{Simple Interest Earned Amount}} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$100\\ r=rate\to 3\%\to \frac{3}{100}\dotfill &0.03\\ t=years\dotfill &3 \end{cases} \\\\\\ A=100[1+(0.03)(3)]\implies A=100(1.09)\implies A=109 \\\\[-0.35em] ~\dotfill\\\\ \stackrel{Anna}{113.5} - \stackrel{Matt}{109}\implies 4.5\)

The equation that requires the multiplication property of equality to be solved is:

\(\boxed{\sf \dfrac{a}{6}=420}\)

Multiplication property of equality states that if both the sides of an equation are multiplied by the same number, the expressions on the both sides of the equation remain equal to each other.

The multiplication property states that:

Out of the given options, \({\sf \dfrac{a}{6}=420}\) requires the multiplication property of equality to be solved.

That is:

\(\text{If} \ {\sf \dfrac{a}{6}=420}\)

\({\sf \dfrac{a}{6}\times6=420\times6\)

\(\sf a=2520\)

Hence, the equation that requires the multiplication property of equality to be solved is:

\({\sf \dfrac{a}{6}=420}\)

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Using the four-step process,  f'(1) = 10, f'(2) = 12, and f'(3) = 14.

To identify f'(x), the derivative of f(x), using the four-step process, we can follow these steps:

1: Identify the function.
The given function is f(x) = x^2 + 8x - 6.

2: Apply the power rule.
Differentiate each term of the function separately.
The derivative of x^2 is 2x.
The derivative of 8x is 8.
The derivative of -6 is 0 (constant term).

3: Simplify.
Combine the derivatives obtained in step 2.
So, f'(x) = 2x + 8.

4: Evaluate f'(1), f'(2), and f'(3).
Substitute x = 1, 2, and 3 into the derived equation to identify the respective values.
f'(1) = 2(1) + 8 = 10.
f'(2) = 2(2) + 8 = 12.
f'(3) = 2(3) + 8 = 14.

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The value of LM in parallelogram LMNQ in this question is 13.

A parallelogram is a four-sided shape that is a part of the quadrilateral spectrum. As the name suggests, two pairs of the sides of a parallelogram are parallel to each other. In simpler words, the opposite sides of a parallelogram are equal and parallel.

As shown in the image attached, in parallelogram LMNQ, the sides LM and NQ are parallel. This means that these sides are equal as well. We have been told that the value of NQ is 13. This means that the value of LM is 13 as well.

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Answer:

a. I'm not sure if there's more to the question but I can't answer without knowing how many is the whole class

B. 12 boys

False. The complement of an event A, denoted by A', is the event consisting of all outcomes in the sample space S that are not in A.

In probability theory, a sample space S represents the set of all possible outcomes of an experiment or random phenomenon. An event A is a subset of the sample space S, representing a specific outcome or a combination of outcomes of interest.

The complement of event A, denoted by A', includes all the outcomes in the sample space S that are not part of event A. In other words, A' consists of all outcomes that do not satisfy the conditions for event A to occur.

For example, let's consider rolling a fair six-sided die. The sample space S consists of the numbers {1, 2, 3, 4, 5, 6}. Now, let event A be the event of rolling an odd number. In this case, A = {1, 3, 5}, and the complement of A, denoted by A', would be A' = {2, 4, 6}. A' includes all the outcomes that are not odd numbers.

It's important to note that the complement of an event A and the event itself together cover the entire sample space S. In other words, A and A' are mutually exclusive and exhaustive, meaning that any outcome must either be in A or in A'.

So, in summary, the complement of an event A is the set of all outcomes in the sample space S that do not belong to A.

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The one that has the most circles in a group :D

Answer:

don't really know

Step-by-step explanation:

you should use socratic and Microsoft Math

Answer:

This sh't confusing but I think the answer is bank B

Step-by-step explanation:

Answer:

12 miles

Step-by-step explanation:

Answer:

12 miles

Step-by-step explanation:

20 * 3 = 60 minutes

4 * 3 = 12 miles

Hope this is helpful:)

Answer:

3 batches

Step-by-step explanation:

First simplify 1/2 into 3/6

which into 1/6 makes three which means Mark can make 3 batches of cookies.

(If Mark had a full pound he could make 6 batches of cookies)*

Have a good day. :)

Hope this helps!

(brainliest would be appreciated)

Answer:

3 batches

Step-by-step explanation:

By writing all the numbers as decimals, we can see that the correct option is D, the correct inequality is:

23% < 0.85 < four and one fourth

Here we have 3 numbers, which are:

0.85

23%

4 + 1/4.

So we have a decimal number, a percentage number, and a mixed number, let's write all of them as decimal numbers.

For the percentage, to get the decimal form we just need to divide it by 100%, so we will get:

23%/100% = 0.23

For the mixed number we have:

4 + 1/4 = 4 + 0.25 = 4.25

Then our 3 numbers are:

0.85

23% = 0.23

4 + 1/4 = 4.25

Then the correct order is:

23% < 0.85 < 4 and 1/4.

So the correct inequality is the one in option D.

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Answer:

d

Step-by-step explanation:

Answer:

470.1

Step-by-step explanation:

Since this is a parabola that opens down, the maximum height is where the graph has a horizontal tangent line.

This is where the derivative=0

Since it is a parabola that opens down, we do not need to test the sides of the point where the derivative=0 as the vertex is a local maximum and the only point with a horizontal tangent.

y=\(-16x^2+146x+137\)

y'=\(-32x+146\)=0

-32x+146=0

x=\(\frac{146}{32}\)=\(\frac{73}{16}\) This is the x-coordinate of the vertex

Now plug this back into the original equation to find the maximum height.

f(73/16)=\(-16(\frac{73}{16})^2+146(\frac{73}{16} )\)+137

=\(\frac{-73^2}{16} +666.125+137\)

=-333.0625+666.125+137

=470.0625

To the nearest tenth this is 470.1

Answer:

x=15/2

Hope it helps :)

Answer:

x = 7.5

Step-by-step explanation:

4 = 2/3 (2x - 9)

4 = 4/3x - 6

4 + 6 = 4/3x - 6 + 6

10 = 4/3x

10 x 3/4 = x

x = 7.5

Answer:

Step-by-step explanation:

of is *

20% is 1/5

1/5 *2000= 2000/5= 400

572000 or 5.72×10^5

Step-by-step explanation:

depends on what format ur teacher prefers but both show 3 sig figs correctly so either is correct

Answer:

square is the answer...

Answer:

1. b  2. b  3. c  4. a  5. c

Step-by-step explanation:

hope this helps! i can give an explanation if needed

Answer:

What he said

Step-by-step explanation:

Answer:

135 seconds = 54 yards

1sec = 54/135 yards

60 sec = 54/135 * 60

1 minute = 24 yards

hope it helps you jamie

Answer:

yes

Step-by-step explanation:

0(zero) crates weigh more than 99. 5 pounds.

The distance between the median and the third quartile on the plot is equal to the interquartile range,

IQR.IQR = Q3 − Q1

Using the values given in the plot:

Q1 = 99.5Q3

     = 143IQR

     = 143 − 99.5

     = 43.5

The upper bound of the plot can be determined by adding 1.5 times the interquartile range to the third quartile.

UPPER = Q3 + 1.5(IQR)

UPPER = 143 + 1.5(43.5)

UPPER = 209.25

Since the upper bound of the plot is 209.25, any crate weighing more than 209.25 pounds is an outlier, which means that all crates on the plot are within the reasonable range.

To determine the number of crates weighing more than 99.5 pounds, we need to look at the box-and-whisker plot again.

We can see that the crate's weight starts at 84 and ends at 170.

So, we need to determine how many crates weigh more than 99.5 pounds, which is the third value on the plot.

From the plot, we can see that 170 is the largest weight and the next-largest weight is 143, which is less than 170.

Thus, there are no crates weighing more than 170 pounds.

Therefore, the number of crates weighing more than 99.5 pounds is the same as the number of crates weighing more than 143 pounds.

This means that no crate weighs more than 99.5 pounds. So the answer is 0.

There are zero crates weighing more than 99.5 pounds, and this can be written as 0 in numerals. This answer can be verified by looking at the plot.

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180|                               |                                              |                                            |                             |

     |                               |                                              |                                            |                             |

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     |                               |_____________________|                                            |                              |

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     |                               |                                              |                                            |                              |

     |                               |                                              |                                            |                              |

     |                               |                                              |                                            |                              |

     |                               |                                              |____________________|                              |

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     |                               |                                              |                                            |                              |

140|                               |                                              |                                            |                              |

     |                               |                                              |                                            |                              |

120|                               |                                              |                                            |                              |

     |                               |                                              |                                            |                              |

     |______________|_____________________|____________________|______________|

  80            100                                                      120                                       140                        160

Therefore, the number of crates is 0.

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Given:

The polynomial \(x^3-1\) is divided by (x+2).

To find:

The remainder.

Solution:

Remainder theorem: If a polynomial p(x) is divided by (x-c), then the remainder is p(c).

Consider the polynomial:

\(p(x)=x^3-1\)

It is divided by (x+2). So, by the remainder theorem the remainder is p(-2).

Substituting x=-2 in the above polynomial, we get

\(p(-2)=(-2)^3-1\)

\(p(-2)=-8-1\)

\(p(-2)=-9\)

Therefore, the remainder is -9.

The remainder when x³ - 1 is divided  by (x + 2) is -9

Polynomial is an expression consisting of only the operations of addition, subtraction, multiplication of variables.

The remainder theorem states that when a polynomial f(x), is divided by a linear polynomial x - a, the remainder of that division will be equivalent to f(a).

Given the polynomial f(x) = x³ - 1.

The linear equation is x + 2, hence; x = -2

f(-2) = (-2)³ - 1 = -8 - 1 = -9

The remainder when x³ - 1 is divided  by (x + 2) is -9

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Answer:

392

Step-by-step explanation:

20• 4 + 13•24

80+ 312

Answer:

I believe it is, $80 for adults and $312 for students.

Answer:

y=-1/5x+9

Step-by-step explanation:

-1/5x is the slope and 9 is y intercept