(26 pts) Let v(t) = 120 sinc(120t) - 80 sinc(80t). (a) (6 pts) Find V(f). Considering v as a passband signal, what is its 100% energy containment bandwidth? (b) (8 pts) Find û(t), the Hilbert transform of v. (c) (4 pts) Let u(t) = v(t) cos(250t). Sketch U(f). (d) (8 pts) Find env(t), the complex envelope of u(t).

When a storm hits while a vessel is underway, the operator should ensure that all those aboard are wearing a Personal Flotation Device.

During a storm at sea, safety precautions are crucial. The operator should prioritize the safety of all individuals aboard the vessel. One of the key measures is to ensure that everyone is wearing a Personal Flotation Device (PFD) or a life jacket. PFDs provide buoyancy and can potentially save lives in case of an emergency or if someone falls overboard.

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The continuity equation allows finding the results for the speed and flow of the outlet pipe are:

Fluid mechanics studies the movement and fluid dynamics, it is described  by two fundamental relationships:

          \(P_1 + \frac{1}{2} \rho v_1^2 + \rho g y_1 = P_2 + \frac{1}{2} \rho v_2^2 + \rho g y_2\)  

Where P is the pressure, v the velocity, y the height, the subscripts are two selected points of interest in the pipe.

            \(A_1v_1 = A_2 v_2\)

Where A₁ and A₂ is the area of ​​the inlet and outlet pipes and v₁ and v₂ are the velocities of the fluid at the inlet and outlet

They indicate the inlet and outlet diameters of the pipe are d₁ = 0.02 m and d₂ = 0.1 m, the inlet velocity v₁ = 10 m / s, with the continuity equation let's find the outlet velocity

         \(v_2 = ( \frac{A_1}{A_2} )^2 \ v_1\)  

the cross section of the tavern is

        A = \(\pi r^2 = \pi \ d^2/4\)  

Where r is the radius and d is the diameter

Let's substitutes

        \(v_2 = (\frac{d_1}{d_2} )^2 \ v_1\)  

        \(v_2 = (\frac{0.02}{0.1} )^2 \ 10\)  

        v₂ = 0.4 m / s

The flow  (Q) is defined as the amount of liquid that passes through the section of the pipe per unit of time, we can see that this is the same conservation of mass, therefore

        Q = A v

        Q = \(\pi \frac{d_2^2}{4} \ v_2\)π d2 ^ 2 v2

        Q = \(\pi \ \frac{0.1^2}{4} \ 0.4\)

        Q = 3.14 10⁻³ m ^ 3 / s

As the transported liquid is water

         1 liter water = 1 kg

Consequently

         1 m³ = 1000 liter = 1000 kg of water

Let's reduce the flow

         Q = 3.14 10⁻³ m³/s ( \(\frac{10^3 kg}{1 m^3}\) )

         Q = 3.14 kg / s

In conclusion using the continuity equation we can find the results for the speed and flow of the outlet pipe are:

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The bandwidth of a low-pass RL filter is the range of frequencies that can pass through the filter with minimal attenuation. It is defined as the difference between the upper and lower frequencies of the passband, where the attenuation is less than a certain threshold, usually -3 dB or half power point.

The cutoff frequency of a low-pass RL filter is the frequency at which the filter begins to attenuate the input signal. For a first-order low-pass RL filter, the cutoff frequency is given by the formulafc = R/(2πL)where R is the resistance of the series resistor and L is the inductance of the series inductor.If the cutoff frequency of a low-pass RL filter is 20 kHz, then we can calculate its bandwidth by determining the frequencies at which the filter's attenuation is -3 dB. Since the filter is a first-order low-pass filter, its attenuation at the cutoff frequency is -3 dB.

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Note that some of the attractive features of the shielded metal arc welding process are: "Electrodes are only changed out according to the workpiece and a filler metal is only optional."

Shielded metal arc welding, also referred as manual metal arc welding, flux shielded arc welding, or stick welding informally, is a manual arc welding procedure that employs a consumable electrode coated in flux to lay the weld.

To use this method correctly, maintain a 20° to 30° lead angle in the dragging direction during stick welding. Hold the rod or wire (regardless of weld procedure) at a 45° angle between the two pieces of metal when welding using a fillet (tee). Speed: Keep an eye out for welding puddles and ridges (where the molten metal solidifies).

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Answer:

false

Explanation:

it is not necessary to securitize its commerical paper

Answer:

Steady-state concentration of the pollutant in the effluent= 1.3245033 mg/L

Explanation:

Given Data:

Amount of sewage received=500 m^3/d

Surface Area= 10 hectares=10*10^4 m^2

Depth=1 m

Pollutant concentration=200 mg/L

Decay coefficient=0.75 d-1

Required:

Steady-state concentration of the pollutant in the effluent= ?

Solution:

Volume=Surface Area * Depth

\(Volume=10*10^4 *1\\Volume=10*10^4\ m^3\)

Time to fill the lagoon=\(\frac{Volume}{Amount\ received\ per\ day}\)

\(Time\ to\ fill\ the\ lagoon=\frac{10*10^4\ m^3}{500\ m^3}\\ Time\ to\ fill\ the\ lagoon= 200\ days\)

Formula for steady State:

\(A_t=\frac{A_0}{1+kt}\)

where:

A_t is the steady state concentration

A_0 is the initial concentration

k is the decay constant

t is the time

\(A_t=\frac{200\ mg/L}{1+0.75*200}\\ A_t=1.3245033\ mg/L\)

Steady-state concentration of the pollutant in the effluent= 1.3245033 mg/L

Answer:

Wireless

Explanation:

A wireless remote control can be an advantage to an operator who is welding close to the power source. Hence, option A is correct.

An electrical device used to wirelessly and remotely operate another device is a remote control, often known as a remote or clicker. Consumer gadgets, such as television sets, DVD players, and other home appliances, can be controlled by a remote control.

In the current electronic market, remote control systems fall into three primary categories: IR-based systems, RD-based systems, and BT-based systems. the receiver and the remote must be lined up exactly for infrared, also known as IR.

IR, on the other hand, is unable to pass through a number of materials but can operate over a much wider spectrum. This allows the user far greater freedom and control in environments with challenging terrain and obstacles.

Thus, option A is correct.

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I recently had a terrible experience with a database system when I tried to book a hotel room. The system was hosted by a company called Hotel.com, and I accessed it through their website. The interface was confusing and hard to navigate,

A database is a collection of data that is organized in a structured format, usually stored and accessed electronically from a computer system. It allows easy access and manipulation of data, and is used in a wide variety of applications, such as financial services, education, business, or government. Some of the most common types of databases include relational, object-oriented, and hierarchical. Relational databases use tables, columns, and rows to store data, while object-oriented databases use objects to store data. Hierarchical databases are structured like a tree, with nodes and branches representing the data. Databases can also be classified by the type of data they store, such as text, numerical, or graphical.

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Answer:

OBJECTLINE

HIDDEN LINE

SECTION LINE

CENTER LINE

Explanation:

False. Fire extinguishing equipment cannot be frozen according to Ref. 213/91.

According to Ref. 213/91, fire extinguishing equipment cannot be frozen. Fire extinguishers are essential safety devices designed to combat fires effectively. They contain pressurized agents that are specifically formulated to extinguish different types of fires. Freezing temperatures can significantly impair the functionality of fire extinguishers and render them ineffective in emergency situations.

When fire extinguishing equipment freezes, several issues can arise. First, the contents of the extinguisher may expand as they freeze, potentially leading to ruptures or leaks in the container. This can cause the extinguisher to malfunction or become hazardous when used. Second, freezing temperatures can affect the performance of the extinguishing agent itself. Certain agents, such as water-based solutions, can solidify or lose their effectiveness when exposed to extreme cold.

It is crucial to store fire extinguishers in suitable environments that are above freezing temperatures. This ensures that the equipment remains in optimal condition and is ready for immediate use during emergencies. Regular inspections and maintenance are also essential to identify any signs of damage or deterioration that may compromise the functionality of fire extinguishers.

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The center of gravity, also known as the balance point or point of rotation when an object is permitted to freely rotate, is the average location of an object's weight.

All objects with mass are attracted to one another by the gravitational attraction, which has a magnitude that is directly proportional to the masses of the two objects and inversely proportional to the square of their distance from one another.

By means of gravity, a planet or other body pulls items toward its core. All the planets are maintained in their orbits around the sun by the force of gravity.

Any particle of matter in the universe will gravitate toward any other with a force that varies directly as the product of the masses and inversely as the square of the distance between them, according to Newton's law of gravity.

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It is a kind of periodic motion bounded between two extreme points. For example, Oscillation of Simple Pendulum, Spring-Mass System. The object will keep on moving between two extreme points about a fixed point is called the mean position (or) equilibrium position along any path.

(a) The equation for the piston's position is given as x=(5.00 cm)cos(2t+ 6π )

At t=0,

 x=(5.00 cm)cos( 6π )= 4.33 cm

(b) Differentiating the equation for position with respect to time gives us the piston's velocity:

  v= dt/dx =−(10.0 cm/s)sin(2t+ 6π )

At t=0,v= −5.00 cm/s

​

(c) Differentiating again gives its acceleration:

 a= dv/ dt =−(20.0 cm/s 2 )cos(2t+ 6π )

At t=0,a= −17.3 cm/s 2

(d) The period of motion is

T= ω/2π − 22π = 3.14 s

​

(e) We read the amplitude directly from the equation for x:

                       A= 5.00 cm

​

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When an ordinarily elastic material cracks brittlely, there is little or no outward trace of material deformation prior to failure.

The plastic deformation that occurs before failure is minimal or nonexistent in brittle fractures. Glasses, ceramics, as well as various polymers and metals, frequently fracture in a brittle way.

When a material is exposed to forces below its yield limit, brittle fractures take place. A ductile material is typically the foundation for machine design, and the design criteria are intended to prevent plastic and, in some circumstances, elastic deformations.

Material that has undergone either no plastic deformation or very little plastic deformation prior to fracture is said to have fractured with brittleness. Since they all share this quality, brittle materials include rock, concrete, glass, and cast iron.

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Answer:

Invitational Workshop

An invitational workshop is what many of us know. It’s what Lucy Calkins has made famous through the Reading and Writing Workshop. In the invitational workshop, the instructor usually hosts a minilesson. This minilesson is intended to meet the needs of the majority of children in the classroom. Afterward, the children are “invited” to employ the skills or strategy for the minilesson during workshop time, where students work independently or in small groups

Explanation:

Answer:

Here are 5 examples:

Explanation:

I hope this helps!

The reason that makes it is difficult to accurately quantify the quantum of carbon released from terrestrial ecosystems  are linked with Sensitivity analysis as well as bias made by gap filling of satellite data.

In its ground state, the six electrons of carbon (atomic number 6) in the second row of the periodic table occupy two of its primary energy levels, giving the highest-energy electron a principal quantum number n of 2.

Therefore, note that the act of  carrying out Sensitivity analysis  is a factor that has hindered the knowledge about the amount of release of carbon in the atmosphere.

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The calculate value of Mass flow rate = 0.00414 kg/s while the rejected heat is 1.32 Kw

We have to use the properties of the enthalpies from the pressure table

At p4 = 100 kpa

hf = 17.28 kj / kg

hfg = 217.16 kj / kg

enthalpy at the state 1

= 17.28 + 2*217.16

= 60.712 kj / kg

T1 = - 26 degrees celsius

enthalpy of vapor = 234.44 kj / kg

a. The mass flow rate

Ql = 1.2 x 600

= 720 watts

convert to Kw

= 0.72 KW

We have to find the mass flow rate

This is given as the formula

Ql  / h1 - h4

we would have

0.72 / 2344 - 60.712

Mass flow rate = 0.00414 kg/s

b. We have to find the rejection of the heat through the use of the number 1 law of thermodynamics

Qh = Ql + W

= 0.72 + 0.6

= 1.32 Kw

Hence the mass flow rate is 0.00414 and the rejected heat rate is 1.32 kW

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The total length of the wood needed will be 27 inches.

From the information given, it was stated that each wood is about 4 1/2 inches and that 6 pieces will be needed.

The length of the total woods needed will be:

= 4 1/2 × 6

= 9/2 × 6

= 27 inches.

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Answer:

  C.  3325 Ω - 3675 Ω

Explanation:

5% of 3500 Ω is ...

  0.05 × 3500 = 175

The lower limit is this amount less than the nominal value:

  3500 -175 = 3325

The upper limit is the nominal value plus the tolerance:

  3500 +175 = 3675

The lower and upper limits are 3325 Ω and 3675 Ω, respectively.

To validate a multiple regression model for predicting a quantitative outcome variable, you would use techniques such as cross-validation, residual analysis, and hypothesis testing.

To ensure that the model is accurate and reliable, you can use cross-validation to test the model's performance on new data sets. Residual analysis can help you identify any patterns or trends in the model's errors, which can then be used to improve the model.

Hypothesis testing can be used to determine if the coefficients in the model are significant and whether they are contributing to the model's overall predictive power.

Additionally, you could evaluate the model's goodness-of-fit measures, such as the R-squared value, to assess how well the model fits the data. Overall, using a combination of these techniques can help you validate the multiple regression model and ensure that it is an effective predictor of the outcome variable.

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Answer:

60000 H

Explanation:

We are given;

Number of turns; N = 3000 turns

Change in flux = 900 - 860 = 40 Wb

Change in current = 9 - 7 = 2 A

Now, the formula for incremental inductance is given as:

L = N(Change in flux/Change in current) where;

N is Number of turns

Plugging in the relevant values, we have;

L = 3000(40/2)

L = 60000 H.

The value of the shear stress at the wall surface is 8.65 Pa.

The formula for shear stress is given by:

τ = µ (du/dy)

Where τ is the shear stress, µ is the dynamic viscosity of the fluid, du/dy is the velocity gradient perpendicular to the flow direction.

The fluid is air at 1 atm and a temperature of 20°C. Air is a compressible fluid and it is commonly assumed as an ideal gas at atmospheric conditions.

Therefore, the dynamic viscosity of air can be calculated as:

µ = (1.81 × 10⁻⁵ Pa.s) × [(T/273)^(3/2)] × [(273 + S)/273]^(1/2)

where T is the temperature in kelvin and S is the Sutherland's constant, which is 110.4 K for air.

So, substituting the given values we get,

µ = (1.81 × 10⁻⁵ Pa.s) × [(293/273)^(3/2)] × [(273 + 110.4)/273]^(1/2)= 1.81 × 10⁻⁵ Pa.s × 1.105 × 1.0135^(1/2)= 2.03 × 10⁻⁵ Pa.s

The shear stress at the wall surface can be calculated from the following equation:

τ = (0.04 × ρ × V^2) / d

where ρ is the density of air, V is the velocity of air, and d is the diameter of the pipe.

Substituting the given values we get,

ρ = 1.2041 kg/m³ (density of air at 1 atm and 20°C)V = 3 m/s (assuming fully developed flow)

d = 0.05 mτ = (0.04 × 1.2041 kg/m³ × (3 m/s)^2) / 0.05 m= 8.65 Pa

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Answer:

I think its A

Explanation:

Recent scholarship questions the derivation of the architectural orders from wood, proposing instead that the orders developed from a monumental decorative style using molded stone details.

Various scholars argue that architectural orders could not have evolved from wood designs due to the brittle and ephemeral nature of the wood; it cannot bear the weight of any significant structure or long-lasting framework without collapsing, therefore implying that the system had to be changed to develop a new system of permanent construction. Instead of woods, the orders might have originated from some other materials that could carry the weight of the building. The stone was an appropriate material that could stand up to the rigors of the environment and could be carved into the shapes required for structures such as columns.

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The radius of the second pipe in the concentric bend is 19 inches.

In a concentric bend, the pipes are arranged in a circular manner with the same center point. To find the radius of the second pipe, we need to consider the information provided.

Step 1: Calculate the radius of the first pipe.

Given that the radius of the first pipe is 16 inches and the outer diameter (OD) is 2 inches, we can use the formula: OD = 2 × radius.

2 inches = 2 × 16 inches

2 inches = 32 inches.

So, the outer diameter of the first pipe is 32 inches.

Step 2: Calculate the spacing between the pipes.

The spacing between the pipes is given as 3 inches. This means there is a gap of 3 inches between the outer diameter of the first pipe and the inner diameter of the second pipe.

Step 3: Calculate the radius of the second pipe.

To find the radius of the second pipe, we need to consider the outer diameter of the first pipe and the spacing between the pipes. The radius of the second pipe can be calculated using the formula: radius = (OD + spacing) / 2.

radius = (32 inches + 3 inches) / 2

radius = 35 inches / 2

radius = 17.5 inches.

Therefore, the radius of the second pipe in the concentric bend is 17.5 inches.

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The Heating Degree Day (HDD), considering an indoor setpoint as 19.5°C, is 0 degree day. Option (A) is correct.

Heating Degree Day (HDD) is defined as the number of degrees in which the mean temperature of the day is less than the reference temperature, which is the base temperature.

Here, we need to find the heating degree day (HDD), considering an indoor setpoint as 19.5°C.

Given minimum temperature for 24 hours = 17°C

Indoor setpoint = 19.5°C

Reference temperature = 19.5°C (since indoor setpoint is 19.5°C)

We know that if the mean temperature of the day is less than the reference temperature, then HDD can be calculated as follows:

HDD = Reference temperature - Mean temperature of the day

Since the minimum temperature for 24 hours is less than the indoor setpoint temperature, we will calculate HDD using the above formula.

So, Mean temperature of the day = (Minimum temperature for 24 hours + Maximum temperature for 24 hours) / 2= (17°C + 22°C) / 2= 19.5°C

HDD = Reference temperature - Mean temperature of the day= 19.5°C - 19.5°C= 0°C

Therefore, the Heating Degree Day (HDD), considering an indoor setpoint as 19.5°C, is 0 degree day.

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Answer:A

Explanation:

Those who want to save money and will use the product for only a few years

Answer:

THE ANSWER is A - those who want to save money and will use the product for only a few years

Explanation: Got it right on edg 2021

Anemometer

Explanation:

An anemometer is a device used for measuring wind speed and direction. It is also a common weather station instrument. The term is derived from the Greek word anemos, which means wind, and is used to describe any wind speed instrument used in meteorology.