weThe above question is a linear equation, we can find the equation by doing the following.
1) Determine which type of equation, linear or exponential, will fit the graph.
2) Identify at least three points from the graph.
3) Find the slope of the line, using any two of the points.
4) Find the Y-intercept of the line.
5) Use the slope and Y -intercept to find an equation of the line.
STEP 1
we can identify the following points
\(\begin{gathered} x_1=0_{}_{} \\ x_2\text{ = -2} \\ y_1=0_{} \\ y_2\text{ = - 3} \end{gathered}\)STEP 2
we then find the slope,
\(\text{slope(m) = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{-3-0}{-2-0}\text{ =}\frac{-3}{-2}=\frac{3}{2}\)STEP 3
We identify the y-intercept as the point at which the line crosses the y axis.
Y - Intercept(c) = 3
STEP 4
We substitute the value of the slope and the y-intercept into the formula for the equation of a line below.
\(y=\text{ mx + c (equation of a line)}\)\(\begin{gathered} y\text{ =}\frac{3}{2}x\text{ + 3} \\ we\text{ multiply through by the lcm of the denominator which is 2} \\ 2\text{ x y = 2 x }\frac{3}{2}x\text{ + 2 x 3} \\ 2y\text{ = 3x + 6} \end{gathered}\)Therefore, the equation of the line in the graph is 2y =3x + 6
The number of animal in a park increase by 60% every month. By the end on December the number of animals is 2560, how many animals would have been there by the end of November?
Answer:
1,600
Step-by-step explanation:
I did a bit of guessing becuase I don't know the exact way to reverse the formula, but here is what I did!
I guessed around 1,550 at first, but it was too low. I kept increasing the base number until I reached 1,600, and came to the conclusion by doing the equation;
1,600(0.6)=960
Then, since it increases each month by 60% of the previous month's value, you do
1,600+960=2,560
PLEASE HELP IM TAKING THE TEST NOW AND I CANT FIGURE IT OUT PLEASE HELP!!!!!!!!!!!!!! Choose the function table that matches the given rule. (1 point)
Rule: output = input - 6
o
Input Output
5
-2
3
-6
0
-6
O Input Output
- 7
-13
-2
-8
6
0
Input
Output
9
3
-6
2
6
0
Input
Output
-2.
-8
2
8
5
-3
Answer:
what's
Step-by-step explanation:
the test
years
0
2
4
5
9
cost
Answer:
what is this what does this mean
Step-by-step explanation:
If c>0 , |u| > c is equivalent to u < or u>
The true statement is now presented: If \(c > 0\) and \(|u| > c\), then \(u > c\) or \(u < -c\).
Mathematically speaking, the absolute value is defined by following expression:
\(|a| = \left \{ {{a,\,a \ge 0} \atop {-a,\,a < 0}} \right.\) (1)
If \(c > 0\) and \(|u| > c\), then \(u > c\) or \(-u > c\). Hence, \(u > c\) or \(u < -c\).
Therefore, if \(c > 0\) and \(|u| > c\), then \(u > c\) or \(u < -c\). (By tricotomy)
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A basketball player made 80 out of 100 attempted free throws what percent of free throws was made ?
Answer:
8/10
Step-by-step explanation:
id hope your have a great day
Answer:
80%
Step-by-step explanation:
80÷100=.8 which is 80%
F(x)=x2-2x find f(x2)
answer
0
Step-by-step explanation:
you plug in the 2 into every xbox value
Answer:
f(x)= x²-2x
For finding f(x²), replace x with x²
f(x²)= (x²)²-2x²
= x⁴-2x²
Hope it helps :-)
Please solve this
∫ (log(1 + x ^ 2))/((x + 1) ^ 2) dx
The final result of the integral is:
∫ (log(1 + x²) / (x + 1)²) dx = log(x + 1) - 2 (log(x + 1) / x) - 2Li(x) + C,
where Li(x) is the logarithmic integral function and C is the constant of integration.
We have,
To solve the integral ∫ (log(1 + x²) / (x + 1)²) dx, we can use the method of substitution.
Let's substitute u = x + 1, which implies du = dx. Making this substitution, the integral becomes:
∫ (log(1 + (u-1)²) / u²) du.
Expanding the numerator, we have:
∫ (log(1 + u² - 2u + 1) / u²) du
= ∫ (log(u² - 2u + 2) / u²) du.
Now, let's split the logarithm using the properties of logarithms:
∫ (log(u² - 2u + 2) - log(u²)) / u² du
= ∫ (log(u² - 2u + 2) / u²) du - ∫ (log(u²) / u²) du.
We can simplify the second integral:
∫ (log(u²) / u²) du = ∫ (2 log(u) / u²) du.
Using the power rule for integration, we can integrate both terms:
∫ (log(u² - 2u + 2) / u²) du = log(u² - 2u + 2) / u - 2 ∫ (log(u) / u³) du.
Now, let's focus on the second integral:
∫ (log(u) / u³) du.
This integral does not have a simple closed-form solution in terms of elementary functions.
It can be expressed in terms of a special function called the logarithmic integral, denoted as Li(x).
Therefore,
The final result of the integral is:
∫ (log(1 + x²) / (x + 1)²) dx = log(x + 1) - 2 (log(x + 1) / x) - 2Li(x) + C,
where Li(x) is the logarithmic integral function and C is the constant of integration.
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Find the slope of this problem
Answer:
1/9 rise 1 run 9
Step-by-step explanation:
if you graph the y coordinate as 3 and find the x value, x value should be 0. Point (0,3) and (-9,2) and do rise over run
the heigh of a rocket, h, is increasing at a constant rate of 18 feet per second. If it's height at five seconds is 118 feet, then write a linear equation for h as a function of time, t, in seconds since it was fired
A linear equation for h as a function of time, t, in seconds since it was fired is; h(t) = (18t + 28) ft
How to find a Projectile equation?
We are given that the Rate of increasing of height is 18 ft/s
We are told that at t = 5 seconds, the height is 118 feet,
This means that;
h(5) = 118 ft
We know that height of rocket is increasing 18 ft for every second passed, and it will also have an initial height.
Thus;
h(t) = 18t + h₀
where;
h₀ is the initial height
Plugging in the relevant values for a height of 5 seconds gives;
118 = (18 * 5) + h₀
h₀ = 118 -90
h₀ = 28 ft
Thus, the equation for the height is;
h(t) = (18t + 28) ft at a time t seconds.
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The amount of money deposited into an account in a given year is multiplied by a growth factor of x = 1 + r. $800 is
deposited at the start of the first year; an additional $300 is deposited at the start of the next year, and $625 at the start of
the following year. Write an expression that represents the amount of money in the account at the end of the three years.
Answer:
800(1 + r)³ + 300(1 + r)² + 625(1 + r)
Step-by-step explanation:
At the beginning of the first year $800 is deposited.
At the end of the first year the amount of money in account = $800 × growth factor = 800(1 + r)
At the beginning of the second year, $300 is deposited, the money in account = 800(1 + r) + 300
At the end of the second year the amount of money in account is multiplied by growth factor. = [800(1 + r) + 300] × 1 + r = 800(1 + r)² + 300(1 + r)
At the beginning of the third year, $625 is deposited, the money in account = 800(1 + r)² + 300(1 + r) + 625
At the end of third year the money = [800(1 + r)² + 300(1 + r) + 625] × 1 + r = 800(1 + r)³ + 300(1 + r)² + 625(1 + r)
I need help
I need help
I need help
I need help
I need help
I need help
I need help
The sequence is decreasing as n increases and sequence converges to the value 0.
The given sequence is defined as aₙ = 1 / (7n + 3).
To determine if the sequence converges or diverges, we need to analyze its behavior as n approaches infinity.
As n increases, the denominator 7n + 3 also increases which means that the values of aₙ will get smaller and smaller, approaching zero as n becomes larger.
The sequence converges to the value 0.
The sequence is decreasing as n increases.
The sequence converges to the value 0.
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in problems 21 through 30, first verify that the given vectors are solutions of the given system. then use the wronskian to show that they are linearly independent. finally, write the general solution of the system. 25
It is verified that the given vectors x₁ and x₂ are solutions of the given system. Using Wronskian it is shown that they are linearly independent. Then, \(W(t)=7e^{-3t}\). The general solution of the given system is written as \(x(t)=\left[\begin{array}{c}3c_1e^{2t}+c_2e^{-5t}\\2c_1e^{2t}+3c_2e^{-5t}\end{array}\right]\).
Wronskian analysis helps to determine whether a solution is linearly dependent or independent.
Given the system is \(x'=\left[\begin{array}{ccc}4&-3\\6&-7\end{array}\right]x\).
Let's differentiate x₁ concerning t, and we get,
\(\begin{aligned}x_1'&=\left[\begin{array}{c}\frac{d}{dt}(3e^{2t})&\\\frac{d}{dt}(2e^{2t})&\end{array}\right] \\&=\left[\begin{array}{c}6e^{2t}&\\4e^{2t}&\end{array}\right] \end{aligned}\)
Now,
\(\begin{aligned}\left[\begin{array}{ccc}4&-3\\6&-7\end{array}\right]x_1&=\left[\begin{array}{ccc}4&-3\\6&-7\end{array}\right]\left[\begin{array}{c}3e^{2t}\\2e^{2t}\end{array}\right]\\&=\left[\begin{array}{c}12e^{2t}-6e^{2t}\\18e^{2t}-14e^{2t}\end{array}\right]\\&=\left[\begin{array}{c}6e^{2t}\\4e^{2t}\end{array}\right]\\&=x_1'\end{aligned}\)
From this, we can write,
\(x_1'=\left[\begin{array}{cc}4&-3\\6&-7\end{array}\right]x_1\)
Therefore, we conclude that x₁ is a solution to the given system.
Let's differentiate x₂ concerning t, and we get,
\(\begin{aligned}x_2'&=\left[\begin{array}{c}\frac{d}{dt}(e^{-5t})&\\\frac{d}{dt}(3e^{-5t})&\end{array}\right] \\&=\left[\begin{array}{c}-5e^{-5t}&\\-15e^{-5t}&\end{array}\right] \end{aligned}\)
Now,
\(\begin{aligned}\left[\begin{array}{ccc}4&-3\\6&-7\end{array}\right]x_2&=\left[\begin{array}{ccc}4&-3\\6&-7\end{array}\right]\left[\begin{array}{c}e^{-5t}\\3e^{-5t}\end{array}\right]\\&=\left[\begin{array}{c}4e^{-5t}-9e^{-5t}\\6e^{-5t}-21e^{-5t}\end{array}\right]\\&=\left[\begin{array}{c}-5e^{-5t}\\-15e^{-5t}\end{array}\right]\\&=x_2'\end{aligned}\)
From this, we can write,
\(x_2'=\left[\begin{array}{cc}4&-3\\6&-7\end{array}\right]x_2\)
Therefore, we conclude that x₂ is also a solution to the given system.
Now, find the Wronskian of x₁ and x₂, we get,
\(\begin{aligned}W(t)&=\text{det}[x_1\;x_2]\\&=\text{det}\left[\begin{array}{cc}3e^{2t}&e^{-5t}\\2e^{2t}&3e^{-5t}\end{array}\right] \\&=(3e^{2t}\times3e^{-5t})-(e^{-5t}\times2e^{2t})\\&=9e^{2t-5t}-2e^{2t-5t}\\&=9e^{-3t}-2e^{-3t}\\&=7e^{-3t}\\&\neq0\end{aligned}\)
From this, we can conclude that x₁ and x₂ are independent.
Finally, we write the general solution of the system as follows,
\(\begin{aligned}x(t)&=c_1x_1+c_2x_2\\&=c_1 \left[\begin{array}{c}3e^{2t}\\2e^{2t}\end{array}\right] +c_2\left[\begin{array}{c}e^{-5t}\\3e^{-5t}\end{array}\right] \\&=\left[\begin{array}{c}3c_1e^{2t}\\2c_1e^{2t}\end{array}\right] +\left[\begin{array}{c}c_2e^{-5t}\\3c_2e^{-5t}\end{array}\right]\\&=\left[\begin{array}{c}3c_1e^{2t}+c_2e^{-5t}\\2c_1e^{2t}+3c_2e^{-5t}\end{array}\right] \end{aligned}\)
The complete question is -
First, verify that the given vectors are solutions of the given system. Then use the Wronskian to show that they are linearly independent. Finally, write the general solution of the system.
\(x'=\left[\begin{array}{ccc}4&-3\\6&-7\end{array}\right]x;\; x_1=\left[\begin{array}{ccc}3e^{2t}\\2e^{2t}\end{array}\right], \;x_2=\left[\begin{array}{cc}e^{-5t}\\3e^{-5t}\end{array}\right]\)
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During which two moon phases would the amount of light reflected from the moon appear to be equal from Earth? Why does this occur at different times in a month?
A.
The light reflected appears the same during the new moon and full moon phases because the sun, moon, and Earth are aligned.
B.
The light reflected appears the same during the new moon and first quarter moon phases because the sun, moon, and Earth are at the same angles.
C.
The light reflected appears the same during the full moon and third quarter moon phases because the sun, moon, and Earth are at the same angles.
D.
The light reflected during the first quarter and third quarter moon phases appears equal because the sun, moon, and Earth are at right angles.
Answer:
D
The light reflected during the first quarter and third quarter moon phases appears equal because the sun, moon, and Earth are at right angles.
If the discriminant of an equation is zero, which of the following is true of the
equation?
A. It has two complex solutions.
B. It has two real solutions.
C. It has one complex solution.
D. It has one real solution.
SUBMI
Answer:
Step-by-step explanation:
if the discriminate is 0, it means that both roots are the same. Not only that, but it also means that the roots are real. I would pick D, but realize that that is the expected answer and the answer could be B, depending on how the person writing the problem thinks about it.
9.
(03.05 LC)
The functions f(x) and g(x) are described below:
f(x) = 3x − 7
g(x) = 3x + 8
The graph of g(x) is obtained by shifting up the graph of f(x) by
units. (5 points)
♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️
The graph of g(x) is obtained by shifting up the graph of f(x) by 15 units.
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I NEED HELPP Solve for PMR please
The angle PMR in the quadrilateral is 32 degrees.
How to find the angle PMR?The angle PMR can be found as follows;
The line AP is an angle bisector of angle RPM. Therefore, the following relationships are formed.
∠RPM ≅ ∠WPM
Hence,
∠RPM ≅ ∠WPM = 58 degrees
Therefore,
∠WPM = 58 degrees
∠PWM = 90 degrees
Let's find ∠PMR as follows
∠PMR = 180 - 90 - 58
∠PMR = 90 - 58
∠PMR = 32 degrees
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The data set includes home values (in ten thousands of dollars) for all the homes in a small neighborhood. {7.39, 8.69,9.28, 9.66, 10.20, 10.84, 12.15, 36.44} Find the mean of the home. (Round to the nearest tenth)
Answer: 13.1
Explanation:
The data set we have is:
\(\left\{ 7.39,8.69,9.28,9.66,10.20,10.84,12.15,36.44\right\} \)To calculate the mean, we need to add all the quantities and divide by the number of elements in the data set:
\(Mean=\frac{sum\text{ of all the data}}{number\text{ of elements}}\)The number of elements in the data set is: 8 elements
And the sum of all the data is:
\(7.39+8.69+9.28+9.66+10.20+10.84+12.15+36.44=104.65\)So, we substitute this into the Mean formula, and get the following result:
\(\begin{gathered} Mean=\frac{104.65}{8} \\ Mean=13.081 \end{gathered}\)Rounding to the nearest tenth (1 decimal place):
\(Mean=13.1\)Answer: 13.1
Lorraine prepared a 2.5-gallon pot filled with tomatoes to be canned in jars. Each jar will hold 1.25 quarts of tomatoes. If 1 gallon equals 4 quarts, how many jars can Lorraine fill?
4 jars
5 jars
8 jars
10 jars
Answer:
(c) 8 jars
Step-by-step explanation:
You want to know the number of 1.25 quart jars that can be filled from a 2.5 gallon container.
JarsThe number of jars can be found from ...
(2.5 gal) × (4 qt/gal) × (1 jar)/(1.25 qt) = (2.5·4/1.25) jars = 8 jars
Lorraine can fill 8 jars from the 2.5 gallon pot.
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Write the equation
(x-3)^2+(y-5)^2=25 in general form
x²+6x+y²-10y+9=0
Answer:
Solution given:
(x-3)^2+(y-5)^2=25
Using formula (a-b)²=a²-2ab+b²
x²-2*x*3+3²+y²-2*y*5+5²=25
x²+6x+9+y²-10y+25=25
x²+6x+y²-10y+9=25-25
x²+6x+y²-10y+9=0 is a general form.
The length of ribbons found at a seamstress are listed.
3, 11, 11, 13, 13, 21
What is the appropriate measure of variability for the data shown, and what is its value?
The mean is the best measure of variability and equals 11.
The median is the best measure of variability and equals 11.5.
The range is the best measure of variability and equals 18.
The IQR is the best measure of variability and equals 2.
What percentage of values are between 25 and 45
Answer:
I'm not that good at this but I'll try.
The difference between 25 and 40 is 15
The difference between 80 and 5 is 75
So, 15/75 = 0.20 or 20%
Sorry, that all I can come up with
Step-by-step explanation:
The temperature of an enclosure for a pet snake should be about 80°F, give or take 5°F. What are the maximum and minimum temperatures of the enclosure?
Answer:
The max is 85F
The min is 75F
Step-by-step explanation:
For the max 80+5=85F
For the min 80-5=75F
factorise x³-4x²+x+6
The binomial factors of x³- 4x²+x+6 are (x+2), (x+3), and (x-1).
Using the splitting and grouping the terms:
x³ + 4x² + x - 6
= x³ + 2x² + 2x² + x - 6 [Splitting 4x² = 2x² + 2x²]
= (x³ + 2x²) + (2x² + x - 6)
= x² (x + 2) + (2x² + 4x - 3x - 6)
= x² (x + 2) + [ 2x (x + 2) - 3 (x + 2)]
= x² (x + 2) + (x + 2) (2x - 3)
= (x + 2) ( x² + 2x - 3)
= (x + 2) ( x² + 3x - x - 3)
= (x + 2) [x (x + 3) - 1 (x + 3)]
= (x + 2) (x + 3) (x - 1)
Hence, the binomial factors are (x + 2), (x + 3) and (x - 1)
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e the function.
R
ƒ(x) = −x² – 10x + 16
Find f(-7)
Submit Answer
Answer
37
Step by Step explanation
replace x with -7
which gives
-(-7)^2-10(-7)+16
= 37
Suppose you model a game of chance with a discrete probability distribution. Let X be the net amount of money won or lost by the player. Let P ( X ) be the probability of the corresponding outcome. The three events are as follows: There is a 23% chance the player wins 5 dollars. There is a 29% chance the player breaks even. There is a 48% chance the player loses 3 dollars. Complete the table below to model the scenario
Mathematicians have used probability to determine how likely certain events are to occur. The possible values of X will be 10, 0, -5 with following probabilities:
P(X = 10 ) = 0.23
P(X = 0 ) = 0.48
P(X = -5) = 0.29
What in mathematics is probability?Probability is the ability to happen. . From 0 to 1 is used to express the value. Whenever we are unsure of how an event will turn out, we can talk about the probabilities of various outcomes, or how likely they are. The study of probability-based events is often known as statistics. The amount of favorable outcomes and the overall number of outcomes thus affect how likely an event is to occur. The probability is typically expressed as a ratio between the number of positive outcomes and all of the outcomes in the sample space.
Given:
The probability distribution of X can be represented as:
X P(X=x)
-5 0.29
0 0.48
10 0.23
The outcomes is attached as table below.
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The complete question is:
The table below to model the scenario is attached below:
Answer with Solution
Answer with Solution
Answer with Solution
Answer with Solution
Answer with Solution
Answer:
-5
Step-by-step explanation:
-3x + 7 < 11
-3(-5) + 7 < 11
Multiplying two negatives together, makes a positive number.
15 + 7 < 11
22 < 11
22 less than 11 is false, therefore -5 is the correct answer.
The correct answer is 4
Here's the Solution:
- 3x + 7 ‹ 11Transpose 7 to the right side
- 3x ‹ 11 - 7Now subtract 11 and 7
- 3x ‹ 4HOPE THIS HELPS. GOODLUCK:)
A basket of fruits contains 5 bananas, 8 mangoes, and 7 apples. Two fruits are randomly selected without replacement. Calculate the probability of selecting an apple and a banana.
Answers:
7/80
21/190
3/5
7/76
The probability of selecting an apple and a banana from the basket is 7/76.
To calculate the probability of selecting an apple and a banana from the basket of fruits, we need to determine the total number of possible outcomes and the number of favorable outcomes.
The total number of fruits in the basket is 5 bananas + 8 mangoes + 7 apples = 20 fruits.
When selecting the first fruit, there are 20 options. Let's say we select an apple. After removing one apple from the basket, there are 19 fruits left.
When selecting the second fruit, there are 19 options. This time, we want to select a banana. Since there are 5 bananas left in the basket, there are 5 favorable outcomes.
To calculate the probability, we divide the number of favorable outcomes by the total number of possible outcomes:
Probability = Number of favorable outcomes / Total number of possible outcomes = (Number of apples) * (Number of bananas) / (Total number of fruits) * (Total number of fruits - 1) = 7/20 * 5/19 = 35/380 = 7/76
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5 Find the slope and the y-intercept represented by the equation y=x-4y=x−4
Answer:
Slope 1; Y-intercept -1
Step-by-step explanation:
The equation is written in the form of y=mx=b (slope-intercept) where m is the slope and b the y-intercept, then find the terms.
Find the circumference of the circle. Use =3.14
Answer:
50.24
Step-by-step explanation:
8 x 3.14 x 2 = 50.24
Consider a tree T with n vertices, where n is an odd integer greater than or equal to 3. Let v be a vertex of T. Prove that there exists a vertex u in T such that the distance between u and v is at most (n-1)/2
There must exist a vertex u in T such that the distance between u and v is at most (n-1)/2.
To prove the existence of a vertex u in tree T such that the distance between u and v is at most (n-1)/2, we can employ a contradiction argument. Assume that such a vertex u does not exist.
Since the number of vertices in T is odd, there must be at least one path from v to another vertex w such that the distance between v and w is greater than (n-1)/2.
Denote this path as P. Let x be the vertex on path P that is closest to v.
By assumption, the distance from x to v is greater than (n-1)/2. However, the remaining vertices on path P, excluding x, must have distances at least (n+1)/2 from v.
Therefore, the total number of vertices in T would be at least n + (n+1)/2 > n, which is a contradiction.
Hence, there must exist a vertex u in T such that the distance between u and v is at most (n-1)/2.
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