9. A 30 cm ruler is found to have a center of mass of 15.6 cm. The percent error of the center of mass is _____, if the ruler is assumed to have uniform mass.

Answers

Answer 1

Answer:

3.85 percent

Explanation:

From the question,

Percentage error = (error/actual)×100................ Equation 1

Given: actual center of mass = 15 cm, error = 15.6-15 = 0.6 cm

Substitute these values into equation 1

Percentage error = (0.6/15.6)×100

Percentage error = 3.85 percent

Hence the percentage error of the uniform mass = 3.85 percent


Related Questions

***ECONOMICS***

A government that wants to increase its GDP would most likely take which
action?
A. Increase the money supply to make it easier to borrow money
Ο Ο
B. Decrease the money supply to slow the growth of inflation
C. Increase taxes on businesses that operate outside the country
O O
D. Decrease taxes on citizens who are poor or unemployed

Answers

Answer:

The correct answer is A. A government that wants to increase its GDP would most likely increase the money supply to make it easier to borrow money.

Explanation:

If the government wanted to increase its GDP, the most appropriate way to do so would be to increase the money supply both through issuance and through a reduction in bank reserve requirements, thereby increasing the circulating money in the hands of society.

This, in turn, would make citizens reinvest that money, increasing economic production and, therefore, the national GDP.

Answer: A. Increase the money supply to make it easier to borrow money

Explanation: I just took the test on Ap ex

The current in the long wire is decreasing. What is the direction of the current induced in the conducting loop below the wire

Answers

Answer:

anlatamadım herkeze ben sorulara bakamiyorum cumku analmaiyirum yardim edin

bu sorunu nasil cozebilirim

lutfsn...

a 40 kg object is sliding on a surface accelerating to the right. force of friction is 20N, the applied force is 100N. draw and label all forces. what is the acceleration?

Answers

When the pressure (100 N) and weight (40 kg) are entered into the appropriate fields, the gravity is 2 m/s².

What is the acceleration force?

Force and acceleration are linked by the equation F=ma. The characters "F," "m," and "a" stand for acceleration, mass, and force, respectively. Force is the ability of one object to exert a pull or force on another. Acceleration is the rate at which an object's speed changes.

Describe acceleration in detail.

Speed increase is the pace of progress of speed. Acceleration typically indicates a change in speed, but not always. Because its velocity is changing in the opposite direction, even if an object moves in a circle at the same speed, it will still accelerate.

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A rectangular container measuring 19 cm x 51 cm x 62 cm is filled with water. What is the mass of this volume of water in kilograms

Answers

A rectangular container measuring 19 cm x 51 cm x 62 cm is filled with water. The mass of this volume of water in kilograms is  60.4 kilograms (kg).

To calculate the mass of water in the rectangular container, we need to multiply the volume of water by the density of water.

1. Volume of water:

The volume of the rectangular container is given as:

Length (L) = 19 cm

Width (W) = 51 cm

Height (H) = 62 cm

The volume of water (V) is calculated as:

V = L × W × H

Converting the dimensions to meters:

L = 19 cm = 0.19 m

W = 51 cm = 0.51 m

H = 62 cm = 0.62 m

V = 0.19 m × 0.51 m × 0.62 m

V ≈ 0.0604 cubic meters (\(m^3\))

2. Density of water:

The density of water (ρ) is approximately 1000 kilograms per cubic meter (kg/\(m^3\)).

3. Mass of water:

Mass (m) = Volume × Density

m = 0.0604 m^3 × 1000 kg/\(m^3\)

m = 60.4 kilograms (kg)

Therefore, the mass of the volume of water in the rectangular container is approximately 60.4 kilograms (kg).

It's important to note that the density of water can vary slightly depending on temperature and impurities, but for most practical purposes, a density of 1000 kg/\(m^3\)is commonly used.

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Convert the unit of 0.0063 milliseconds into microseconds. (Answer in scientific notation)

Answers

Answer:

microsecond = 1 × 10-6 seconds

1 second = 1 × 100 seconds

1 microsecond = (1 / 1) × 10-6 × 10-0 seconds

1 microsecond = (1) × 10-6-0 seconds

1 microsecond = (1) × 10-6 seconds

1 microsecond = 1 × 1.0E-6 seconds

1 microsecond = 1.0E-6 seconds,just do like it

Answer:

6.3 x \(10^{-3}\)

Explanation:

1 millisecond = 1000 microseconds

0.0063 millisecond = 6.3 microseconds

Based on your graph, predict the length of pendulum that will give you a
period of 2.00s.

Based on your graph, predict the length of pendulum that will give you aperiod of 2.00s.

Answers

Answer:

About 1 meter

Explanation:

Base on your image, when the period is 2 (horizontal variable), the length of the pendulum is about 1 meter.

Can someone please help?

Can someone please help?

Answers

Answer:

Gold = 19.3g/cm³

Explanation:

Given the following data;

Mass = 38.6g

Volume = 2cm³

To find the density;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, density is given by the equation;

\(Density = \frac{mass}{volume}\)

Substituting into the equation, we have;

\(Density = \frac{38.6}{2}\)

Density = 19.3g/cm³

Therefore, from the table the material is Gold.

Gold is a chemical element and it is the element 79 on the periodic table. Thus, it has an atomic number of 79. The chemical symbol for Gold is Au, it is chemically classified as a transition metal and as a solid at room temperature.

Generally, the chemical element Gold is known to have the following physical properties;

I. Malleable.

II. Ductile.

III. A good conductor of electricity and heat.

Also, it is a non-toxic chemical element with a beautiful lustrous sheen.

Chris and Sue are wearing harnesses and are hanging from the ceiling by means of ropes attached to them. They are face to face and push off against each other. Sue has a mass of 52 kg and Chris has a mass of 78 kg. Following the push, Sue reaches a height of 0.65 meters above her starting point. How high does Chris reach?

Answers

Answer:

h = 0.288m

Explanation:

Assume

\(v_1\) = Speed of Sue

\(v_2\) = Speed of Chris immediately after the push

Sue's KE = \(\frac{1}{2} mv_1\ ^2 = 26 v_1 \ ^2\)

now she swings this is converted into gravitation at PE of

mg n = 52 × 9.8 × 0.65  

= 331.24

\(26v_{1}\ ^2\) = 331.24

So, \(v_1 = 3.569\)

They started at rest by conservation of momentum in case of push off the magnitude of sue momentum and it is equal to the magnitude of Chris momentum in the opposite or inverse direction

\(m_1v_1 = m_2v_2\)

\(52 \times 3.569 = 78 \times v_2\)

\(v_2 = 2.380\)

Chris kt = \(\frac{1}{2} \times 78 \times 2.380^2\)

= 220.827

220.827 = mgh

So, h = 0.288m

a train has an initial velocity of 30 m/s. If the train accelerates uniformly at a rate of 6.3 m/s ^ for 2.8 seconds what is the trains final velocity?

Answers

T

Answer:

the velocity is a second final to initial velocity of 39

A ball of mass 0.4kg is dropped from a height of 30m. Determine the potential energy on impact to the ground

Answers

The answer is 120 joules

In a hydraulic press, a force of 200 N is applied to master piston of area of 25cm-2. If the press is designed to produce a force of 5000N, determine
a:the area of the slave piston
b:the radius of the slave piston

Answers

Answer:

\(625\ \text{cm}^2\)

\(14.1\ \text{cm}\)

Explanation:

\(F_1\) = Force applied to master piston = 200 N

\(F_2\) = Force applied to slave piston = 5000 N

\(A_1\) = Area of master piston = \(25\ \text{cm}^2\)

\(A_2\) = Area of slave piston

r = Radius of slave piston

From Pascal's law we have

\(\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\Rightarrow A_2=\dfrac{F_2}{F_1}A_1\\\Rightarrow A_2=\dfrac{5000}{200}\times 25\\\Rightarrow A_2=625\ \text{cm}^2\)

The area of the slave piston is \(625\ \text{cm}^2\)

Area of the slave piston is given by

\(A_2=\pi r^2\\\Rightarrow r=\sqrt{\dfrac{A_2}{\pi}}\\\Rightarrow r=\sqrt{\dfrac{625}{\pi}}\\\Rightarrow r=14.1\ \text{cm}\)

The radius of the slave piston is \(14.1\ \text{cm}\).

Please help and if you get this and answer the other one on my thing i’ll give u brainliest

How does increasing the energy of a wave affect its wavelength?


The increase in energy causes an increase in wavelength.

The shorter the wavelength, the lower the energy.

The higher the energy, the shorter the wavelength.

There is no relationship between energy and wavelength.

Answers

Answer:

The higher the energy, the shorter the wavelength.

Explanation:

A 0.150-m-radius grinding wheel, starting at rest, develops an angular speed of 12.0 rad/s in a time interval of 4.00 s. What is the centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s?​

Answers

The centripetal acceleration of a point 0.100 m from the center when the wheel is moving at an angular speed of 12.0 rad/s is 1.44 m/s^2.

To find the centripetal acceleration of a point on the grinding wheel, we can use the formula:

a = rω^2

Where:

a is the centripetal acceleration,

r is the distance from the center of the wheel to the point, and

ω (omega) is the angular speed.

Given:

Radius of the grinding wheel, r = 0.150 m

Angular speed, ω = 12.0 rad/s

Distance from the center, r' = 0.100 m

First, we calculate the centripetal acceleration at the given angular speed:

a = (0.150 m)(12.0 rad/s)^2 = 21.6 m/s^2

Now, to find the centripetal acceleration at a distance of 0.100 m from the center, we substitute the new radius into the formula:

a' = (0.100 m)(12.0 rad/s)^2 = 1.44 m/s^2

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A child throws a stone into a pond. The stone creates ripples
when it hits the water. These ripples spread across the pond.
The child thinks that a leaf floating on the pond will move to the edge of
the pond with the ripples. Explain whether or not she is correct.

A child throws a stone into a pond. The stone creates rippleswhen it hits the water. These ripples spread

Answers

No, the youngster is mistaken. The leaf won't float to the edge of the pond due to the stone's waves.

What do pond ripples result from when a stone is tossed into the water?

When a stone is put into a body of water, it creates waves that change in a stunning pattern, radiating outward from a centre that eventually goes still. The growing ring is referred to as a wave packet.

How can throwing a stone into water cause ripples to appear?

A circle-shaped pattern of ripples is created on the water's surface when a stone is tossed into stillness. The particles vibrate due to the stone's kinetic energy. The particles in the subsequent layers receive the energy.

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If you dropped a ball on the surface of Katar, what rate would it accelerate toward the ground

Answers

Acceleration describes the speed and direction changes in velocity over time. Acceleration refers to the change in speed or direction of an item or point travelling straight forward. Due to the constant change in direction, motion on a circle accelerates even while the speed is constant.

The rate at which an object's velocity changes in relation to time is known as acceleration. The vector quantity of accelerations. The direction of the net force that is acting on an object determines its acceleration.

The formula a = v/t denotes acceleration (a), which is the product of the change in velocity (v) and the change in time (t). Using metres per second squared (m/s²), you can gauge how quickly velocity varies.

Acceleration due to gravity on earth = 9.8 m/s²

Therefore, the rate at which the ball will fall on the Katar is 9.8m/s²

Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational field. It has the SI unit m/s². It is a vector quantity since it has both magnitude and direction. g is a unit used to measure gravitational acceleration. 9.8 m/s² is the standard value of g at sea level on the surface of the earth.

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when you drop an object from a height, does the energy transferred to its kinetic energy stores increase or decrease as it falls?

Answers

Answer:

increase

Explanation:

The potential energy of the object at a certain height converts to kinetic energy as the object falls.  Objects in free fall are accelerating, so the velocity is increasing every second that the object is falling.  KE = 1/2mv², so the greater the v, the greater the KE.

During weather that may produce freezing temperatures, Florida orange growers often spray water on their orchards to protect them. Which of the following best explains why this helps protect orange trees and fruit from freezing?

Answers

The statement that best explains why this helps protect orange trees and fruit from freezing is that the transfer of thermal energy in water as it freezes protects the orange trees by transferring heat energy from the orange trees and fruit. That is option A.

What is freezing?

Freezing is the phase transition that involves the change of a liquid substance into a solid form as it's temperature becomes lower.

During winter seasons which is a weather that can freez the orange fruits, the orange grower sprays water on their orange trees to prevent it from freezing.

The mechanism that prevents the orange from freezing is the transfer of the thermal energy between the water and the orange fruits.

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During weather that may produce freezing temperatures, Florida orange growers often spray water on their

Aristotle said that if you dropped a large object and a smaller object that the larger
object would hit the ground first.
We now know that that is___
not true.
true

Answers

Answer: not true

Explanation: mass < weight

why doping method is used to design a diode circuit​

Answers

Answer:

To increase the conductivity of the material.

Explanation:

Generally , the group 4 elements are non conductor but in certain conditions, such as doping or the increase in temperature, they becomes conductor.

The doping is the process of mixing of pentavalent or the trivalent material into tetra valent material in the very small amount, so that the material becomes conductor.

In making a diode we need two types of the materials, n type semiconductor and p type semi conductor.

When the trivalent impurity is added in the tetra valent element, the semiconductor becomes n type because an electron is left for the conduction.

When the pentavalent impurity is added in the tetra valent element, the semiconductor becomes p type because a hole is left for the conduction.

HELPP PLEASEEE Which issue is not a challenge an organism encounters?


A getting energy

B reproducing

C maintaining structure

D regenerating arms

Answers

either D or B maybe

Answer:

regenerating arms....

Describe a situation in which these two velocity vectors are different. Use complete sentences.

Answers

When acceleration is equal to zero average velocity and the instantaneous velocity vectors are identical.

Types of velocity

Velocity is defined as the rate of displacement of an object with respect to time. It is measured in meter/ seconds and is a vector quantity.

Acceleration is defined as the rate at which velocity changes with time.

There are two types of velocity which includes:

Average velocity: This is the average rate of change of position of particles with respect to time over an interval.

Instantaneous velocity: This is defined as the specific rate of change of position with respect to time at a particular point.

The situation that will make the average velocity and the instantaneous velocity vectors to be equal or identical is when acceleration is equal to zero.

¿Con qué cualidad del sonido está relacionada la Amplitud de onda?

Answers

Answer:

Amplitud (dinámica)

Explanation:

La amplitud de una onda de sonido determina su volumen relativo. En música, el volumen de una nota se denomina nivel dinámico.

An 7.80-mF capacitor is connected across an AC source with an rms voltage of 71.0 V oscillating with a frequency of 30.0 Hz. What are the following for this circult? (a) capacitive reactance (b) rms current (c) maximum current

Answers

a)The capacitive reactance is 680 ohms.

\(X_{c}=1/2\pi fC\)

\(X_{c}=1/2\pi *30*7.8*10^{-6}\)

\(X_{c}=680\\\)

b)The rms current is 0.10 amperes.

\(I_{rms}=V_{rms}/X_{c}\)

\(I_{rms}=71/680\)

\(I_{rms}=0.10A\)

c)The maximum current in the circuit is 0.147 amperes.

\(I_{max}=\sqrt{2} *I_{rms}\)

\(I_{max}=\sqrt{2} *0.10\)

\(I_{max}=0.147A\)

What is capacitive reactance?

The measure of the opposition to alternating current by the capacitor is called Capacitive Reactance. The unit of Capacitive Reactance is Ohms-like resistance. The symbol of Capacitive Reactance is XC

What is the capacitive reactance formula?

Xc = 1/2πfc

XC is the capacitive reactance, π is a constant with the value of 3.14, f is the frequency, and c is the capacitance.

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A frictionless plane is 10.0 m long and inclined at 36.0°. A sled starts at the bottom with an initial speed of 6.00 m/s up the incline. When the sled reaches the point at which it momentarily stops, a second sled is released from the top of the incline with an initial speed Vi. Both sleds reach the bottom of the incline at the same moment.
(a) Determine the distance that the first sled traveled up the incline. m
(b) Determine the initial speed of the second sled. m/s

Use the equation for the position of the second sled as a function of time to find the speed that makes it reach the bottom of the slope in the same time that the first sled takes to slide back down.

Answers

If a frictionless plane is 10.0 m long and inclined at 36.0°.

The sled traveled  8.17 m up the incline.The initial speed of the second sled is about  5.68 m/s

How to find the initial speed?

We can use conservation of energy to find the distance that the first sled travels up the incline. The potential energy of the sled at the bottom of the incline is zero, and its kinetic energy is:

KE = (1/2)mv^2

where m is the mass of the sled and v is its speed. At the point where the sled stops, all of its kinetic energy has been converted into potential energy, so we can write:

mgh = (1/2)mv^2

where h is the height that the sled has traveled up the incline. Solving for h, we get:

h = (v^2)/(2g)

where g is the acceleration due to gravity. Using the given values, we have:

h = (6.00 m/s)^2 / (2 * 9.81 m/s^2) = 1.83 m

So the first sled travels a distance of 10.0 m - 1.83 m = 8.17 m up the incline.

b. To find the initial speed of the second sled, we can use conservation of energy again. At the top of the incline, the sled has potential energy:

PE = mgh

where h is the height of the incline. As the sled slides down the incline, its potential energy is converted into kinetic energy:

KE = (1/2)mv^2

where v is the speed of the sled at the bottom of the incline. We can equate these two expressions and solve for v:

mgh = (1/2)mv^2

v = sqrt(2gh)

Using the given values, we have:

v = sqrt(2 * 9.81 m/s^2 * 10.0 m * sin(36.0°)) = 12.2 m/s

So the second sled must be released from the top of the incline with an initial speed of 12.2 m/s.

The position of the sled as a function of time is given by:

y = -0.5gt^2 + Vi*t + h

where y is the vertical position of the sled, t is the time, Vi is the initial speed of the sled, and h is the height of the incline. At the bottom of the incline, y = 0, so we can solve for the time it takes for the second sled to reach the bottom:

0 = -0.5gt^2 + Vi*t + h

t = (Vi ± sqrt(Vi^2 - 2gh)) / g

Since we want both sleds to reach the bottom at the same time, we set the time for the first sled to slide down the incline equal to this expression for t and solve for Vi:

t = sqrt(2h/g) = sqrt(2 * 1.83 m / 9.81 m/s^2) = 0.619 s

0 = -0.5gt^2 + Vi*t + h

Vi = (h - 0.5gt^2) / t

Vi = (1.83 m - 0.5 * 9.81 m/s^2 * (0.619 s)^2) / 0.619 s

Vi = 5.68 m/s

So the initial speed of the second sled is about  5.68 m/s

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Mark and Nancy both take three measurements of the length of a pencil that is 15.1 cm. Mark records 15.0, 15.0, and 15.1 cm. Nancy records 15.1, 15.2, and 15.2 cm. Which of the following statements is true about Mark and Nancy's measurements?
A. Mark's measurement is more precise.
B. Nancy's measurement is more accurate.
C. Mark's measurement is more accurate.
D. Both sets of measurements are equally accurate and precise.​

Answers

It’s A trust me thank you………….

Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?

Answers

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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The diagram below models the length from the center of a wind turbine to the tip of one of its blades. What is the approximate total area covered by the blade
when the turbine makes 1 revolution?
3215 m²
201 m²
100.48 m²
1024 m²

Answers

In situations where wind speeds are over the turbine's design limit, controlling the blade pitch can help prevent overload.

Why is blade pitch important?

The region of the circle the blades' sweeping motion through the air creates is referred to as the swept area.

The area that the propeller covers is equal to the sum of the blades' average surfaces times the number of blades.

In situations where wind speeds are over the turbine's design limit, controlling the blade pitch can help prevent overload. Once the load torque has been maintained, pitch control is utilised to adjust the rotor speed [16]. The Morten et al.

Blade velocity coefficient, also known as the coefficient of velocity or friction factor represented by K, is the ratio of vr2 to vr1 when there is friction, where vr2 will be less than vr1 when there is friction.

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A garden hose attached with a nozzle is used to fill a 20-gallon bucket. The inner diameter of the hose is 1 inch and it reduces to 0.5 inch at the nozzle exit. If the average velocity in the hose is 8ft/s, determine (a) the volume and mass flow rates of water through the hose (4-point), (b) how long it will take to fill the bucket with water (3-point), and (c) the average velocity of water at the nozzle exit (3-point).

Answers

Answer:

a. i. 0.044 ft³/s ii. 2.75 lb/s

b. 62.3 s

c. 32 ft/s

Explanation:

(a) the volume and mass flow rates of water through the hose

i. The volume flow rate

The volume flow rate, Q = Av where A = cross-sectional area of nozzle at inlet = πd²/4 where r = diameter of nozzle at inlet = 1 inch = 1/12 ft and v = average velocity in the nozzle = 8 ft/s.

So, Q = Av

= πd²v/4

= π(1/12 ft)² × 8 ft/s/4

= 0.175/4 ft³/s

= 0.044 ft³/s

ii. The mass flow rate

The mass flow rate, M = ρQ where ρ = density of water = 62.4 lb/ft³ and Q = volume flow rate = 0.044 ft³/s

So, M = ρQ

= 62.4 lb/ft³ × 0.044 ft³/s

=  2.745 lb/s

≅ 2.75 lb/s

(b) how long it will take to fill the bucket with water

Since we have 20 gallons = 20 × 1 gallon, we convert if to cubic feet. So, 20 gallons = 20 × 1 gallon = 20 × 0.137 ft³ = 2.74 ft³.

Since V = Qt where V = volume, Q = volume flow rate and t = time, making t subject of the formula, we have

t = V/Q

= 2.74 ft³/0.044 ft³/s

= 62.27 s

≅ 62.3 s

(c) the average velocity of water at the nozzle exit

Using the continuity equation,

A₁v₁ = A₂v₂ where A₁ = cross-sectional area of nozzle at inlet = πd₁²/4 where d₁ = diameter of nozzle at inlet = 1 inch = 1/12 ft, v₁ = average velocity in the nozzle = 8 ft/s, A₂ = cross-sectional area of nozzle at inlet = πd₂²/4 where d₂ = diameter of nozzle at inlet = 0.5 inch = 0.5/12 ft, v₂ = average velocity at exit nozzle.

So, A₁v₁ = A₂v₂

(πd₁²/4)v₁ = (πd₂²/4)v₂

πd₁²v₁/4 = πd₂²v₂/4

Dividing through by π/4. we have

So, d₁²v₁ = d₂²v₂

making v₂ subject of the formula, we have

v₂ = d₁²v₁/d₂²

v₂ = (d₁²/d₂²)v₁

v₂ = (d₁/d₂)²v₁

substituting the values of the variables into the equation, we have

v₂ = (1/0.5)² × 8 ft/s

v₂ = (2)² × 8 ft/s

v₂ = 4 × 8 ft/s

v₂ = 32 ft/s

You are a sound engineer working on a music festival and need to calculate the speed of sound in the air. You measure the distance between the sound source and a microphone to be 10 meters and the time it takes for the sound to reach the microphone to be 0.05 seconds. What is the speed of sound in the air? (Units: speed - meters per second (m/s), distance - meters (m), time - seconds (s))
2 You are an electrician w orking on a circuit. You need to calculate the electric current flowing through a wire with a resistance of 10 ohms and a voltage of 50 volts. What is the electric current flowing through the wire? If the wire has a length of 10 meters and a cross - sectiona l area of 0.5 square meters, what is the electric conductivity of the wire? (Units: current - amperes (A), resistance - ohms (Ω), voltage - volts (V), length - meters (m), cross - sectional area - square meters (m^2), electric conductivity - siemens per mete r (S/m))

Answers

The electric conductivity of the wire is 0.05 siemens per meter (S/m).

To calculate the speed of sound in the air, you can use the formula:

Speed of sound = Distance / Time

In this case, the distance is 10 meters and the time is 0.05 seconds:

Speed of sound = 10 m / 0.05 s = 200 m/s

Therefore, the speed of sound in the air is 200 meters per second (m/s).

To calculate the electric current flowing through a wire, you can use Ohm's Law:

Current = Voltage / Resistance

In this case, the voltage is 50 volts and the resistance is 10 ohms:

Current = 50 V / 10 Ω = 5 A

Therefore, the electric current flowing through the wire is 5 amperes (A).

To calculate the electric conductivity of the wire, you can use the formula:

Electric conductivity = 1 / Resistance * (Cross-sectional area / Length)

In this case, the resistance is 10 ohms, the length is 10 meters, and the cross-sectional area is 0.5 square meters:

Electric conductivity = 1 / 10 Ω * (0.5 m^2 / 10 m) = 0.05 S/m

Therefore, the electric conductivity of the wire is 0.05 siemens per meter (S/m).

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In the following circuit, find the potential difference (magnitude) between points A and B.

In the following circuit, find the potential difference (magnitude) between points A and B.

Answers

The potential difference between points A and B in the circuit is 12 V.

How to determine potential difference?

To find the potential difference between points A and B in the given circuit, determine the total voltage across the circuit.

From the information provided, there are four resistors labeled as 12 Ω each. Assuming these resistors are connected in series, the total resistance in the circuit is 12 Ω + 12 Ω + 12 Ω + 12 Ω = 48 Ω.

Next, determine the current flowing through the circuit. The voltage is given as 24 V.

Using Ohm's Law (V = IR), calculate the current:

I = V / R

I = 24 V / 48 Ω

I = 0.5 A

Since the resistors are connected in series, the current remains the same throughout the circuit.

Finally, to find the potential difference between points A and B, multiply the current by the resistance between those points:

V_AB = I × R_AB

V_AB = 0.5 A * 24 Ω

V_AB = 12 V

Therefore, the potential difference between points A and B in the circuit is 12 V.

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