A 3-phase, 4 wire system has the following unbalanced loads. ZAN= 5∟35, ZBN= 8∟-70 and ZCN= 15.32∟-63.5 and having a 254V line to neutral. Assuming negative phase sequence, find the following.
a.) Find the three line currents
b.) Find the current in the neutral wire.
c.) Find the total power of the system.

Given,Four standard concrete cylinders of 6-inch diameter cross-section were tested under uniformly increasing axial compressive loads 28 days after casting concrete.

The maximum measured loads were 121,000 lbs, 116,700 lbs, 128,800 lbs, and 119,100 lbs.So, the average compressive strength of this concrete in ksi is as follows:The cross-sectional area of the cylinders, A= π r²where r= 6/2= 3 inches= 0.25 feetA = π × (0.25)²= 0.0491 ft²The maximum load on the concrete cylinders can be calculated by using the formula:σ = P/Awhere P = load on the cylinder,

and A = cross-sectional area of the cylinderσ = 121000/0.0491 = 2462631.4 lb/ft²σ = 2462631.4/144 = 17096.5 psi= 17096.5/1000 ksi= 17.1 ksiSimilarly,σ = 116700/0.0491 = 2373864.7 lb/ft²σ = 2373864.7/144 = 16486 psi= 16.5 ksiσ = 128800/0.0491 = 2623481.9 lb/ft²σ = 2623481.9/144 = 18209 psi= 18.2 ksiσ = 119100/0.0491 = 2425757.9 lb/ft²σ = 2425757.9/144 = 16847.7 psi= 16.8 ksiTherefore, the average compressive strength of this concrete in ksi is given by:Average compressive strength = (17.1 + 16.5 + 18.2 + 16.8)/4= 68.6/4= 17.15 ksi (approx)Hence, the average compressive strength of this concrete in ksi is 17.15.

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Answer:

Adjective. time-dependent (not comparable) (mathematics, physics) Determined by the value of a variable representing time.

Explanation:

Plz mark brainliest thanks

Answer: Adjective. time-dependent (not comparable) (mathematics, physics) Determined by the value of a variable representing time

Answer:

frejfru8758u37

Explanation:

i need points

Answer:

a) ZT = [ 38.786 ∠-4.28° ] ohms

b) ZT = [ 8.673 ∠4.06° ] ohms

Explanation:

Given that;

Voltage V = 480V

three loads of 1) 10Kw, 8 kVAR

2) 5 kVA, 0.9 power factor lagging

3) 12kW, 0.95 pf leading

Now for load1

Active power P = V^2 / R

Resistance R1 = V^2 / P

= (480 * 480) / 10*1000 = 23.04 OHMS

Reactive power Q = 8kVAR

let x be reactance

Q = V^2 / x

8 * 1000 = (480 * 480) / x

x1 = j28.8 ohms (inductive)

Load 2

Active power = kVA * nf = 5 * 9 = 4.5 Kw

Reactive power = sqrt(S^2 - P^2)

= Sqrt (5^2 - 4.5^2)

= 2.179 kVAR

now Resistance R2 = V^2 / P2 = (480 * 480) / 4.5*10^3

= 51.2 ohms

Reactance X2 = V^2 / Q2 = (480 * 480) / 2.178*10^3

X2 = 105.75 ohms

x2 = -j105.75 ohms (capacitive)

Load 3

Active power = 12kW AND PF = 0.95

so

kVA rating = 12/0.95 = 12.63 kVA

reactive power Q3 = sqrt (12.63^2 - 12^2 )

= 3.94 kVAR

Resistance R3 = V^2/P3 = (480*480) / 12*10^3

= 19.2 ohms

Reactance x3 = V2 / Q3 = (480 * 480) / 3.94*10^3

x3 = 58.47 ohms

x3 = -j58.47 ohms (capacitive)

NOW

a)

series combination of R and X

1/ZT = [1/(R1 + jx1)] + [1/(R2-jx2)] + [1/(R3-jx3)]

we substitute

1/ZT = [1/(23.04 + j28.8)] + [1/(51.2 - j105.74)] + [1/(19.2-58.48)]

1/ZT = 0.02571 + j1.92688*10^-3

ZT = 38.67 -j2.897 (total impedance)

so ZT = [ 38.786 ∠-4.28° ] ohms

b)

parallel combination of R AND X

1/ZT = 1/R1 + 1/jx1 + 1/R2 + 1/(-jx2) + 1/R3 + 1/(-jX3)

1/ZT = 1/23.04 + 1/j28.8 + 1/51.2 + 1/(-j105.74) + 1/19.2 + 1/(-58.48)

1/ZT = 0.1150 - j0.008164

ZT = 8.65 +j0.6141

so ZT = [ 8.673 ∠4.06° ] ohms

The queue operation that can be implemented as list.get(0) is peek(). The peek() operation retrieves the element at the front of the queue without removing it.

By accessing the element at index 0 in the list, we can effectively retrieve the element at the front of the queue without modifying the underlying list.

On the other hand, isEmpty() checks whether the queue is empty or not. This operation cannot be directly implemented as list.get(0) because it only checks the presence of elements in the list but doesn't specifically retrieve any element.

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Answer:

The Dependent Variable is the Effect, Its value depends on changes from the Independent Variable

Hope this Helps

The difference between magnetic north and true north is called magnetic declination. The magnetic declination varies depending on the location and changes over time. In Cleveland, Ohio, as of 2023, the magnetic declination is about 5.4 degrees west.

This means that if a compass points to magnetic north in Cleveland, Ohio, it is pointing about 5.4 degrees west of the true north-south line. To find the true north-south line, one can use a map or a GPS device that provides the true north reference.

The magnetic declination (also known as magnetic variation) is the angle formed by magnetic north and true north. When this angle is east of true north, it is positive; when it is west, it is negative. Magnetic declination varies with time and location.

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Answer:

B.

Explanation:

I think not sure hehe

The magnitude of the electric field due to a point source charge decreases as the distance from the source charge increases.

As the distance from a point source charge increases, the magnitude of the electric field it produces decreases. This is a result of the inverse-square law, which states that the intensity of the electric field diminishes as the square of the distance from the source. As the distance increases, the electric field spreads out over a larger area, resulting in a decrease in its strength. This behavior is consistent with the concept that electric field lines emanate radially outward from a point charge and become less concentrated as they move farther away.

In summary, the magnitude of the electric field due to a point source charge diminishes as the distance from the charge increases, following the inverse-square law.

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Answer:

C

Explanation:

The alternator generates electricity to power headlights/radio/windows etc and charge the battery.

The philosopher and sociologist Max Weber argued that property was an expression of one’s personality, a means of self-actualization.

Max Weber, individuals acquire property as a way to manifest their unique personality and to exercise control over their environment. Property allows individuals to express themselves and to assert their autonomy, which in turn contributes to their sense of self-worth and identity.

Moreover, Weber believed that property ownership could confer social status and prestige, particularly in capitalist societies. The acquisition of wealth and property was often seen as a sign of success and achievement, and those who possessed it were admired and respected. However, Weber also recognized the potential dangers of excessive materialism and the ways in which property ownership could lead to social inequality and conflict.

Overall, Weber's perspective on property emphasized its psychological and social significance, as well as its role in shaping individual identity and social relationships.

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Answer:

The inductance of the inductor is 0.051H

Explanation:

From Ohm's law;

  V = IR .................. 1

The inductor has its internal resistance referred to as the inductive reactance, X\(_{L}\), which is the resistance to the flow of current through the inductor.

From equation 1;

V = IX\(_{L}\)

X\(_{L}\) = \(\frac{V}{I}\) ................ 2

Given that; V = 240V, f = 50Hz, \(\pi\) = \(\frac{22}{7}\), I = 15A, so that;

From equation 2,

X\(_{L}\)= \(\frac{240}{15}\)

    = 16Ω

To determine the inductance of the inductor,

X\(_{L}\) = 2\(\pi\)fL

L = \(\frac{X_{L} }{2 \pi f}\)

  = \(\frac{16}{2*\frac{22}{7}*50 }\)

 = 0.05091

The inductance of the inductor is 0.051H.

The range of the aircraft when burning the same volume of liquid hydrogen is, 76.728km.

The range of the aircraft when burning the same volume of gaseous hydrogen is, 0.0885km

The range of the aircraft when burning the same volume of liquid hydrogen is:

= 0.82868 × 43000 × (In 613.0597/600)

= 76.728km

Also, the range of the aircraft when burning the same volume of gaseous hydrogen is, 0.0885km

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AASHTO assumes a deceleration value in calculating stopping sight distance (SSD) of B. 11.2 ft/s^2. This doesn't take any road defects into account.

Complete question:

A steel component with a tensile strength of 800 MPa and fracture toughness Kic=20 MPa Nm is known to contain internal cracks (also called tunnel cracks) with the maximum length of 1.4 mm. This steel is being considered for use in a cyclic loading application for which the designed stresses vary from 0 to 420 MPa. Would you recommend using this steel in this application?

a. Not sure. Because cyclic loading is applied. Fatigue test is needed in order to make the recommendation.

b. Yes, this because the tensile strength of steel is much higher than the applied highest stress of 420 MPa.

c. Yes, this because the calculated critical stress to fracture for the cracks is higher than the highest applied stress of 420 MPa and the steel can withstand the stress of 420 MPa.

d. No. Although the calculated critical stress to fracture for the cracks is slightly higher than the highest applied stress of 420 MPa and the steel may withstand the static stress of 420 MPa, the cyclic loading may cause rapid fatigue fracture.

Answer:

A. Not sure. Because cyclic loading is applied. Fatigue test is needed in order to make the recommendation.

Explanation:

we are not sure if to recommend this alloy for this application given that this material has already been left to experience fatigue degradation. the cyclic load application brings about a growth in the crack. We know that cyclic loading is continuous loading that is useful for the testing of fatigue. Therefore the answer to this question is option a. We cannot make recommendations except fatigue testing has been carried out.

thank you!

Answer:

a c 1 museum is a patient who by think and pay the the price

Answer:

He can take the job at the fast food restaurant to make money in order to pursue his career in robotics it doesnt mean he cant pursue it just he needs to make money for it first.

Shale and other types of "tight" rock, or impermeable rock formations that lock in oil and gas and complicate the production of fossil fuels, can be extracted of their natural gas or oil using the modern high-volume hydraulic fracturing process. Thus, option B is correct.

Shale gas is extracted through a procedure called hydraulic fracturing, also referred to as “fracking.” Due to the fact that shale reserves are often dispersed horizontally rather than vertically, deep holes are first drilled into the shale rock, then horizontal drilling is used to reach more of the gas.

A mixture of sand, chemicals, and water is pushed at high pressure down a borehole during hydraulic fracturing. The released gas can flow out of the rocks and back up the borehole because the water pressure causes cracks in the rock to widen, and the sand particles settle into the openings to keep them open.

Therefore, a way of extracting natural gas shale formations.

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The tool that is designed specifically to remove a lock cylinder is called a lock cylinder removal tool.

A lock cylinder removal tool is a specialized tool that is used to remove a lock cylinder from a door lock. It is designed to fit into the small hole or slot on the face of the lock cylinder, and then expands or grips onto the inside of the lock cylinder, allowing it to be pulled out of the lock mechanism. Lock cylinder removal tools are typically used by locksmiths or other professionals who need to remove a lock cylinder for repair or replacement, but they can also be used by homeowners or DIY enthusiasts who are comfortable working with locks and have the appropriate tools and knowledge. It is important to use the correct tool and follow proper safety procedures when working with locks to avoid damage to the lock or injury to yourself.

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Answer:

5318.346

Explanation:

From the question we have

M = 6kg/s

P = 15kpa

h1 = 3248.4kj

x = 0.9

H2 is unknown

From the steam table

hf = 225.85

hg = 2599.36

H2 = HF + x(hg -hf)

h2= 225.85+0.9(2599.36 - 225.85)

= 225.85 + 0.9(2373.51)

= 225.85 + 2136.159

= 2362.009

To find The power generated by this turbine:

We insert all the parameters into the equation below:

m(h1 - h2)

= 6(3248.4 - 2362.009)

= 6 x 886.391

= 5318.346KW

Answer:

torque to raise the load = 16.411 Nm

torque to lower the load = 8.40 Nm

overall efficiency = 0.24

Explanation:

Given:

max load on vertical direction of the screw = Force = F = 5kN

frictional  diameter of the collar = 45 mm

Diameter = 25 mm

length of pitch = 5 mm

coefficient of friction for thread µ  = 0.09

coefficient of friction for collar µ\(_{c}\) = 0.06

To find:

torque to "raise" the load

torque to and "lower"

overall efficiency

Solution:

Compute torque to raise the load:

\(T_{R} = \frac{ Fd_{m}}{2} (\frac{L+(\pi ud_{m}) }{\pi d_{m}-uL }) +\frac{Fu_{c} d_{c} }{2}\)

where

\(T_{R}\) is the torque

F is the load

\(d_{m}\) is diameter of thread

\(d_{c}\) is diameter of collar

L is the thread pitch distance

µ is coefficient of friction for thread

µ\(_{c}\)  is coefficient of friction for collar

Putting the values in above formula:

\(T_{R}\) = 5(25) / 2 [5+ (π(0.09)(25) / π(25)-0.09(5)] + 5(0.06)(45) / 2

    = 125/2 [5 + (3.14)(0.09)(25)/ 3.14(25)-0.45] + 13.5/2

    = 62.5 [(5 + 7.065) / 78.5 - 0.45] + 6.75

    = 62.5 [12.065 / 78.05 ] + 6.75

    = 62.5 (0.15458) + 6.75

    = 9.66125 + 6.75

    = 16.41125

\(T_{R}\) = 16.411 Nm

Compute torque to lower the load:

\(T_{L} = \frac{ Fd_{m}}{2} (\frac{(\pi ud_{m}) - L }{\pi d_{m}-uL }) +\frac{Fu_{c} d_{c} }{2}\)

     = 5(25) / 2 [ (π(0.09)(25) - L / π(25)-0.09(5) ] + 5(0.06)(45) / 2

     = 125/2 [ ((3.14)(0.09)(25) - 5) / 3.14(25)-0.45 ] + 13.5/2

     = 62.5 [ (7.065 - 5) / 78.5 - 0.45 ] + 6.75

    = 62.5 [ 2.065 / 78.05 ] + 6.75

     = 62.5 (0.026457) + 6.75

     = 1.6535625 + 6.75

     = 8.40 Nm

Since the torque required to lower the the load is positive indicating that an effort is applied to lower the load, Hence the thread is self locking.

Compute overall efficiency:

overall efficiency = F(L) / 2π \(T_{R}\)

                             = 5(5) / 2(3.14)( 16.411)

                             = 25/ 103.06108

overall efficiency = 0.24

Elevation drawings depict how a structure will seem from the outside. Most often, there will be a need for two distinct sets of elevation drawings: "existing" elevations, which depict the building as it is right now.

What does an interior design elevation drawing represent?

An elevation sketch is a two-dimensional orthographic projection of a three-dimensional space. It is a two-dimensional sketch with varied levels of detail of a wall (or sequence of walls) used in interior design.

What do plan and elevation mean in a drawing?

A plan is essentially an aerial picture of a space. The roof would be removed to reveal the internal area while creating a floor plan. An elevation view is shown here. When drawing internal elevations, this would represent one of the walls because an elevation is a view from the side of an item.

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Answer:

2.5=1500/Whp=> Whp=600 kWh

delWgain=1500-600=900 kWh

Money saved= 900* 6tk*=5400 tk

The tensile reinforcement is required at midspan is 3.103 in^2 and the total depth h is required is 17 in.

organizing the information given in the statement:

With that infromation we can say, total moment to be caried out in the bean is:

M=5780 in kips

Characteristics strength of concreete is 4ksi

Characteristics strength of steel is 60ksi

Find the depht of stress block:

\(a=\frac{A_s*f_y}{0.85*fc}\)

Substitute 4ksi in fc, 60 ksi in fy we have:

\(a= 17.65 A_s\)

Find the area of tensile reinforcement:

\(\phi M= \phi A_sf_y(d-a/2)\\5780=A_s*60(20-17.65A_s/2)\\A_s=3.103 in^2\)

Provide 3 stirrups of 9 inches bar (wich has a diameter of 1.128 inches)

Provide 3 inch as cover fot T-beam, therefore the effective depth is:

h=20-3=17 in

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The classification of the working surfaces are as follows;

A working surface is a flat surface on which various activities can be carried out.

In a construction system, the duty carried on a particular working surface varies from another. They can be categorized into heavy-duty, medium-duty, light-duty, and very light-duty.

The classification of the working surfaces are as follows;

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