A brass rod with a mass of 0.300 kg slides on parallel horizontal iron rails, 0.440 m apart, and carries a current of 15.0 A. The coefficient of friction between the rod and rails is 0.300. What vertical, uniform magnetic field is needed to keep the rod moving at a constant speed

The difference in force = 67500N

The mass, m = 75 kg

The change in velocity, △v = 30 m/s

The force is calculated using the formula:

For the crash test without a seatbelt:

Time elapsed, △t = 0.03 seconds

Substitute m = 75, △v = 30, and △t = 0.03 into the formula above

For the crash test with a seatbelt:

Time elapsed, △t = 0.3 seconds

Substitute m = 75, △v = 30, and △t = 0.3 into the formula given

The difference in force = 75000 - 7500

The difference in force = 67500N

Answer: a + b = (-2,5)

Explanation: I'm assuming that these are 1-dimensional matrices or vectors.

So,

a + b = [ a(x) + b(x), a(y) + b(y) ]

        = [ (3) + (-5) , (2) + (3) ]

        = [ (-2) , (5) ]

a +b = (-2,5)

Answer:

The answer is Less.

Explanation:

The further you are away from a light source, the less intense the light appears.

Answer:

?

Explanation:

Answer:analize a afirmacao a seguir e tudo que envolve o gerenciamento da marca e que ultrapassa as acoes com objetivos economicos e refere se a cultura principios e valores

Explanation:

Answer: 22 hours 15 minutes

Explanation: The calculated flying distance from New York City to Dallas is equal to 1371 miles which is equal to 2206 km. If you want to go by car, the driving distance between New York City and Dallas is 2492.32 km. If you ride your car with an average speed of 112 kilometers/hour (70 miles/h), travel time will be 22 hours 15 minutes.

The mass of Car B is -6000 kg.

To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

Therefore, we can write the equation for the conservation of momentum as:

(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision

Let's substitute the given values into the equation:

(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)

Simplifying the equation:

20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)

Dividing both sides by -5 m/s:

-4000 kg = 2000 kg + mass of Car B

Subtracting 2000 kg from both sides:

mass of Car B = -4000 kg - 2000 kg

mass of Car B = -6000 kg

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The terminal velocity of the sphere is approximately 22.68 mph.

The terminal velocity of a sphere is the constant speed at which the gravitational force pulling the sphere down is balanced by the drag force pushing the sphere up. The drag force is proportional to the velocity of the sphere, and can be calculated using the following formula:

Fd = (1/2) * rho * Cd * A * v²

where Fd is the drag force, rho is the density of the fluid (air in this case), Cd is the drag coefficient (which depends on the shape of the object), A is the cross-sectional area of the object perpendicular to the direction of motion, and v is the velocity of the object.

The gravitational force pulling the sphere down is given by:

Fg = m * g

where m is the mass of the sphere and g is the acceleration due to gravity.

At terminal velocity, the drag force is equal in magnitude to the gravitational force, so:

Fd = Fg

Substituting the expressions for Fd and Fg and solving for v, we get:

v = √((2 * m * g) / (rho * Cd * A))

where A = pi * r² is the cross-sectional area of the sphere, and r is the radius of the sphere.

Plugging in the given values, we get:

v = sqrt((2 * 0.6 * 9.81) / (1.2 * 0.47 * pi * 0.3²)) ≈ 10.13 m/s

To convert this to mph, we multiply by 2.23694:

v ≈ 22.68 mph

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The net force on q1 is 9.94 N.

From Coulomb's Law, the force between two point charges is given by:

where;

All the charges have the same charge and magnitude and are separated by the same distance.

The force between q1 and q2 is:

F12 = (9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²

F12 = 4.97 N

The positive sign indicates that the force is repulsive

Similarly, the force between q2 and q3 is:

(9 * 10⁹ N * m²/C²) * (-2.35 x 10⁻⁶ C)² / (0.100 m)²

F12 = 4.97 N

The positive sign indicates that the force is repulsive

The net force on q1 will be:

Fnet = F12 + F23

Fnet = 4.97 N + (4.97)

Fnet = 9.94 N

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Answer:

Explanation:

Please post if there is a graph showing the data.

Without a graph, in general the trend can be described as:

"positive" when the dependent variable increases with an increase in independent variable

"negative" when the dependent variable decreases with an increase in independent variable

"neutral" when the dependent variable remains the same with an increase or decrease in independent variable

Answer:

I hope this helps and I'm not to late

A way the balls behave the same way is by bouncing about 1 time after throwing the balls up. A way the balls act differently is the blue ball is bouncier than all the balls, the red ball bounces about 2 times before stopping, and the green ball doesn’t really bounce except for one time.

Explanation:

you also can use paraphrase to help you reword bye bye!!

My Answer:

Starting with how they acted the same. All three balls fell at the same rate since they are of the same mass; gravity has equal force on all three. Next to the differences, all three balls bounce differently. The blue ball had an average of four bounces before it stopped. The red ball bounced twice before stopping, and lastly, the green ball didn't bounce.

My Explanation:

This is how I answered the question, and I'm on edmentem aswell.  

The gauge pressure at point 2 is 98100 Pa or 9.81 x\(10^4\) Pa, which is equivalent to 6.97 x\(10^4\) Pa when rounded to two significant figures.

Step 1: Identification of the given data:

- Elevation at point 1 (h1) = 10.0 m

- Elevation at points 2 and 3 (h2 = h3) = 2.00 m

- Cross-sectional area at point 2 (A2) = 0.0480 \(m^2\)

- Cross-sectional area at point 3 (A3) = 0.0160 \(m^2\)

Step 2: Determination of the discharge rate:

As mentioned earlier, the discharge rate (Q) is given by Q = A2 * v2, and since the velocity at point 2 (v2) is negligible, the discharge rate will be 0.

Therefore, the discharge rate is 0 cubic meters per second.

Step 3: Determination of the gauge pressure at point 2:

To find the gauge pressure at point 2, we'll use Bernoulli's equation:

P1 + (1/2)ρ\(v1^2\) + ρgh1 = P2 + (1/2)ρ\(v2^2\) + ρgh2

Since the velocity at point 2 (v2) is negligible, the term (1/2)ρ\(v2^2\) can be ignored.

The equation simplifies to:

Patm + ρgh1 = P2 + ρgh2

We want to find the gauge pressure at point 2, so we'll subtract the atmospheric pressure (Patm) from P2:

\(P_g_a_u_g_e\) = P2 - Patm

Now let's substitute the given values into the equation:

\(P_g_a_u_g_e\) = (Patm + ρgh1) - Patm

\(P_g_a_u_g_e\) = ρgh1

Plugging in the values:

\(P_g_a_u_g_e\) = (1000 kg/m^3) * (9.81 \(m/s^2\)) * (10.0 m)

\(P_g_a_u_g_e\) = 98100 Pa

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Answer:

Natae Si Jordan Kaya Sya Napaihe

Explanation:

haha

Answer:

D

Explanation:

A water cycle is constantly going on there is no definitive starting or stopping point

Answer:

h = 2755102 m = 2755.102 km

Explanation:

According to the given condition:

Potential Energy = Energy Consumed by Bulb

\(mgh = Pt\\\\h = \frac{Pt}{mg}\)

where,

h = height = ?

P = Power of bulb = 75 W

t = time = (2 h)(3600 s/1 h) = 7200 s

m = mass of bulb = 20 g = 0.02 kg

g = acceleration due to gravity = 9.8 m/s²

Therefore,

\(h = \frac{(75\ W)(7200\ s)}{(0.02\ kg)(9.8\ m/s^2)}\)

h = 2755102 m = 2755.102 km

Explanation:

the answer is D because of inertia aka the force that pulls obejects downs

For a spacecraft is traveling with a velocity of Vox-5690 m/s:

To solve this problem, use the equations of motion to calculate the final velocity and the vertical component of the velocity. Assume that the initial velocity in the y-direction is zero.

Given:

Initial velocity in the x-direction (V₀ₓ) = -5690 m/s

Time of engine firing (t) = 865 s

Acceleration in the x-direction (ax) = 1.45 m/s²

Acceleration in the y-direction (ay) = -8.66 m/s²

(a) To calculate the final velocity (v), use the equation:

v = V₀ₓ + ax × t

Substituting the values:

v = -5690 m/s + 1.45 m/s² × 865 s

v = -5690 m/s + 1254.25 m/s

v ≈ 685.25 m/s

Therefore, the final velocity (v) is approximately 685.25 m/s.

(b) To calculate the vertical component of the velocity (vy), use the equation:

vy = ay × t

Substituting the values:

vy = -8.66 m/s² * 865 s

vy = -7484.9 m/s

Therefore, the vertical component of the velocity (vy) is -7484.9 m/s.

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Answer:

2 because I did this on before

Answer:

sbdjhdjrjrjrjrjrbdhhrhejejejejejejejejdndndjsj

Answer: My hypothesis was that the future results of the experiment would show a correlation. According to my data, my hypothesis was correct. The file uploaded to this assignment shows that the graph is a correlation but not a 100% positive correlation because if you imagined there was a straight line there, the points would be completely aligned. The correlation is simply a “positive correlation”. Some of the difficulties I had when performing the experiment was distinguishing which type of luster was for each mineral because the light almost looked the same with other minerals. You might change the procedure to avoid this problem in the way of getting all the rest of the results for that specific mineral and then look at which of the graph with the answers was most alike and then you can see why the luster is that certain result in that data which is the correct one. A graphical analysis can be used to explore the relationship between any two scientific variables by changing the numerical data of the experiment into a graph, which is a much more effective and easier way of interpreting the gathered results. It's easier to visualize a graph data than read all the tables with numbers.

The graph is in the attachment below and the 6 minerals also with their names, their density, and their hardness

Lower frequencies (red) move faster in a glass prism than higher frequencies.

Light of all colors moves at the same speed in a vacuum. However, light travels at different speeds in many media, including water.

Red light moves through glass at the fastest speed, whereas violet light moves at the slowest speed.

Red light bends the least of all the colors because it moves at the fastest speed, whereas violet light moves at the slowest speed and bends the most.

Wavelength and speed are directly proportional. Speed also rises with increasing wavelength. Light that has a maximal wavelength therefore moves at its fastest.

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A 50.0-kg wagon is pulled with a constant force of 380 N. Neglecting friction, the wagon's acceleration will be 7.6 m/s².

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The resultant of the displacement is 336.5m

The process of splitting a vector into its components is called resolution of the vector. The vectors are splitted into vertical and horizontal component.

For the first displacement;

The vertical component = - 150 sin45 = -106.1 m

The horizontal component = - 150 cos 45° = -106.1 m

For the second displacement;

The vertical displacement = - 85sin90 = -85

The horizontal component = 0

For the third displacement;

The vertical displacement = 550 sin55 = 450.5

The horizontal displacement = 550 cos 55 = 315.5

Sum of vertical component = 450.5-85-106.1 = 263.4

sum of horizontal component = 315.5 -106.1 = 209.4

Using Pythagorean theorem

R = √ 263.4² + 209.4²

R = √113227.92

R = 336.5m

The resultant angle = tan^-1( 263.4/209.4)

= tan^-1(1.26)

= 51.56°

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SeaWorld is a chain of theme parks and oceanariums that showcase marine life through educational exhibits, live shows, and thrilling rides. While it has faced criticism for its treatment of animals, SeaWorld has made changes to prioritize conservation and phased out its orca breeding program.

SeaWorld is a chain of theme parks and oceanariums that primarily focuses on marine life and entertainment. The company operates various parks across the United States, including SeaWorld parks in Orlando, San Diego, and San Antonio, as well as Busch Gardens parks in Tampa and Williamsburg. SeaWorld offers a combination of educational exhibits, live shows, and thrilling rides, with a special emphasis on marine animals such as dolphins, whales, sea lions, penguins, and sharks.

SeaWorld parks provide visitors with opportunities to observe and interact with marine creatures up close, while also offering educational programs that aim to raise awareness about marine conservation and preservation. The parks feature captivating shows featuring trained animals, where they perform impressive behaviors and stunts, showcasing their intelligence and natural abilities.

Over the years, SeaWorld has faced criticism from animal rights activists and environmentalists, who argue that the captivity and use of marine animals for entertainment purposes is unethical and harmful to the animals' well-being. These concerns have led to significant changes in the company's practices, including the phasing out of its orca breeding program and the introduction of more educational and conservation-focused initiatives.

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The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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Explanation:

F = ma

m = 90 kg    

           a = change in v / change in time = (40-5)m/s  / 3 s =  11.67 m/s^2

F = ma = 90 kg ( 11.67 m/s^2 ) = 1050 N

Since the winner's average speed was about 318 km/h and the kinetic energy of the winning car was 3.80 MJ. So, the mass of the car and its driver is 974 kg.

The kinetic energy of the car is given by K = 1/2mv² where

Making m subject of the formula, we have

m = 2K/v²

Since K = 3.80 MJ = 3.80 × 10⁶ J, substituting the values of the variables into the equation, we have

m = 2K/v²

m = 2 × 3.80 × 10⁶ J/(88.33 m/s)²

m = 7.6 × 10⁶ J ÷ (7802.78 m²/s²)

m = 7600000 J ÷ 7802.78 m²/s²

m = 974.01 kg

m ≅ 974 kg

So, the mass of the car and its driver is 974 kg

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