a. Explain the different components of a water supply system Also, draw the sequential diagram of components.

Answer:

B

Step-by-step explanation:

I took the assignmen.

The reflection of point that will produce the image at same coordinate (0, k) is across the y - axis

We have a Point with coordinates  (0, k).

We have to find the reflection that will produce the image at the same coordinate (0, k).

For a Point P \((x,y)\) the image across -

We can use the above laws to find the reflection of point

For Point P(0,k) , the -

Hence, the reflection of point that will produce the image at same coordinate \((0,k)\) is across the y - axis.

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Peter doesn't get wet on solving the simultaneous

equations.

A system of simultaneous linear equations is any set of two or more linear equations that share the same unknown variables. To solve such a system, finding values for the unknown variables that simultaneously satisfy all of the equations is required.

We can utilize the following parameters in our calculation based on the question:

y = 2x - 1/4x²

y = 1/4x - 1

Through substitution, we now.

2x - 1/4x² = 1/4x - 1

By multiplying by 4,

This results,

8x - x² = x - 4

Analyze similar terms,

x² - 7x - 4 = 0

We have developed a graphical tool to

x = -0.531 and x = 7.531

In y = 2x - 1/4x2, replace x = -0.531 and x = 7.531.

y = 2(-0.531) - 1/4(-0.531) (-0.531) ²

y = -1.13

y = 2(7.531) - 1/4(7.531) ²

y = 0.88

Thus, we have

(-0.531, -1.13) and (7.531, 0.88) (7.531, 0.88)

(-0.531, -1.13) and (7.531, 0.88) do not meet the standards (8, 1)

So, Peter avoids getting wet.

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Answer:

7x < 60

Step-by-step explanation:

Answer:

Yes but I do not get what we are going to do here

Step-by-step explanation:

Answer:

$8,580,000 (rounded) = $9,000,000

Step-by-step explanation:

Keep in mind, 2007 is four years after 2003.

So, 8(%) • 4 = 32(%)

Over the course of 4 years, the companies profits increased by a total of 32 percent.

(*Write 6.5m in standard form)

6,500,000 + 32% = $8,580,000

8,580,000 (rounded up) = 9,000,000

Answer:

area = 432 ft²

Step-by-step explanation:

area = 1/2(B1 + B2)(H)

area = 1/2(20 + 16)(24) = 432 ft²

The probability of success is 1/5. The solution has been obtained by using probability.

What is probability?

In order to calculate the chance of an event, the mathematical notion of probability is used. It only enables us to estimate the likelihood that an event will take place. On a scale of 0 to 1, with 0 representing impossibility and 1 representing a specific occurrence.

We are given that a d10 dice is rolled.

The sample space will be

S = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

It is given that a player succeeds at an action if a 9 or 10 is rolled.

Probability of getting 9 or 10 = 2/10

Probability of getting 9 or 10 = 1/5

Hence, the probability of success is 1/5.

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1.35 is the point estimate for mean value of thickness of paint when the sample observation is taken into consideration.

The Mean Value Theorem is a crucial concept in calculus. The original form of the mean value theorem was developed in the 14th century by Parmeshwara, a mathematician from Kerela, India. Furthermore, Rolle provided a simpler model of this back in the 17th century: Rolle's Theorem, which was proved solely for polynomial observation and did not part of the calculus. The current iteration of the Mean Value Theorem was first presented in 1823 by Augustin Louis Cauchy.

The mean value theorem asserts that for a curve passing through two given points, there is one point on the curve where the tangent is parallel to the secant running through the two provided locations.

How to solve?

We are given the following sample for thickness for low-viscosity paint.

0.81 0.87 0.90 1.05 1.11 1.14 1.30 1.30 1.48 1.48 1.59 1.60 1.66 1.69 1.78 1.84.

a) Point estimate of the mean value of coating thickness.

We use the sample mean to estimate the mean value of the coating thickness.

mean= sum of all observations/total number of observations

mean=21.6/16

mean=1.35 which is the point estimate for mean value of thickness of paint.

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Answer:B (-4.5,9]

That’s the answer I think, honestly we all just trying to pass

The measures of the angles are ∠1 = 127°, ∠2 = 53°, ∠3 = 127°, ∠4 = 37°, ∠5 = 53°, ∠6 = 90°, ∠7 = 37°, ∠8 = 143°, ∠9 = 37° and ∠10 = 143°

From the question, we have the following parameters that can be used in our computation:

The transversal lines and the other lines

So, we have

∠1 = 180 - 53

Evaluate

∠1 = 127°

Also, we have

∠5 = 53°

By vertical angles, we have

∠2 = 53°

∠3 = 127°

Next, we have

∠4 = 127 - 90°

∠4 = 37°

Solving further, we have

∠6 = 90°

By corresponding angles, we have

∠7 = 37°

∠9 = 180 - 90 - 53°

∠9 = 37°

∠10 = 90 + 53°

∠10 = 143°

∠8 = 143°

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Answer:

C, A, C

Step-by-step explanation:

1) Angle D corresponds to angle A, so since corresponding angles of similar triangles are congruent, it measures 64 degrees.

2) Angle E corresponds to angle B. To find the measure of angle B, we can start by using the fact that angles F and C correspond. This means that in triangle ABC, we have angles with measures of 64 degrees, 73 degrees, and angle B. It follows that angle B, and thus angle E, measures 43 degrees.

3) By the exterior angle theorem, the measure of angle G is equal to the measure of angles D and F combined. The measure of angle D is 64 degrees, and the measure of angle F is 73 degrees, so angle G measures 137 degrees.

The number of cans required to paint an area of 2000 square units is equal to 5 cans.

As given in the question,

Total area to be painted is equal to 2000 square units.

Area covered by one can of paint is equal to 400 square units

400 square units = 1 can of paint

⇒ 1 square units = ( 1 / 400 ) cans of paint

⇒ 2000 square units =  ( 2000 / 400 ) cans of paint

⇒ 2000 square units = 5 cans of paint

Therefore, the number of cans required to paint an area of 2000 square units using given can is equal to 5 cans.

The above question is incomplete, the complete question is:

How many cans of paint are needed to cover an area of 2000 square units if one can of paint covers in area 400 square units?

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649 divided by 2 is equal to 347

To determine the normal and shearing stresses at point h located at the top of the outer surface of the pipe assembly, additional information about the forces applied to the assembly is required. Without this information, a specific calculation cannot be provided. However, I can explain the concept of normal and shearing stresses in a general context.

In engineering mechanics, normal stress refers to the force per unit area acting perpendicular to a surface. It is calculated by dividing the applied force by the cross-sectional area. Normal stress can be tensile (pulling apart) or compressive (pushing together) depending on the direction of the force.

Shearing stress, on the other hand, refers to the force per unit area acting parallel to a surface. It arises when two adjacent layers of a material slide or deform relative to each other. Shearing stress is calculated by dividing the applied shearing force by the cross-sectional area.

To determine the normal and shearing stresses at point h, the magnitude and direction of the applied forces, as well as the geometry of the assembly, need to be provided.

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The normal stress at point h located at the top of the outer surface of the pipe can be determined using the formula σ = P/A, where P is the applied force and A is the cross-sectional area. The shearing stress can be calculated using the formula τ = V/Q, where V is the applied shear force and Q is the first moment of area.

To calculate the normal stress at point h, we need to consider the applied forces acting on the pipe assembly. If we have the axial force P applied at point h, the normal stress can be calculated using the formula σ = P/A, where A is the cross-sectional area of the pipe. Since the pipe has an inner diameter of 36 mm and an outer diameter of 44 mm, the cross-sectional area can be calculated as A = π/4 * (D_outer^2 - D_inner^2), where D_outer and D_inner are the outer and inner diameters, respectively.

To calculate the shearing stress at point h, we need to consider the applied shear force V. The shearing stress can be calculated using the formula τ = V/Q, where Q is the first moment of area. The first moment of area can be calculated as Q = π/4 * (D_outer^4 - D_inner^4), considering the same pipe dimensions as before.

By substituting the values of P, A, V, and Q into the respective formulas, you can determine the normal stress and shearing stress at point h, located at the top of the outer surface of the pipe assembly.

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Answer:

17th term

Step-by-step explanation:

For some nth term, both series have same term. So,

6n - 21 = 4n + 13

Subtract 4n from both sides

6n - 4n - 21 = 13

  2n - 21 = 13

Add 21 to both sides

2n = 13+21

2n = 34

Divide both sides by 2

n = 34/2

n = 17

Check:

6n - 21 = 6*17 - 21 = 102 - 21 = 81

4n + 13 = 4*17 + 13 = 68 + 13 = 81

17th term both the series is 81

Answer:

The answer is n = 17

Step-by-step explanation:

You first have to substitute a number for n. You put in a number and calculate. If the 2 are not equal, then it is not correct. When you substitute 17,

4(17) + 13 = 81. 6(17) - 21 = 81.

Because of this, 17 would be the correct term for n.

Answer:

5.85

Step-by-step explanation:

Jusy use the calculator

Answer:

x

Step-by-step explanation:

Answer:

1 1/4 pounds

Step-by-step explanation:

1/2 ÷ 2/5 = 5/4

is good answer the x value and y value

Answer:

No, the inverse function does not pass the horizontal line test.

Step-by-step explanation:

Answer:

Step-by-step explanation:

You want the zeros of f(x) = x³ -5x² -22x -16, given that a factor is x+2.

Using synthetic division (see attachment), we find the quadratic factor to be (x² -7x -8), so we have ...

  f(x) = (x +2)(x² -7x -8)

The quadratic can be factored using our knowledge of the divisors of -8 to give ...

  f(x) = (x +2)(x +1)(x -8)

The zeros of f(x) are the values of x that make these factors zero:

  x = -2, -1, 8 . . . . . zeros of f(x)

__

Additional comment

We know the product of binomial factors is ...

  (x -a)(x +b) = x² -(a-b)x -ab

This means we can factor the quadratic by looking for factors of 8 that have a difference of 7. We know that 8 = 8·1 and that 8-1=7, so the values of 'a' and 'b' we're looking for are a=8, b=1.

The "zero product rule" tells you a product is zero only if one of the factors is zero. That is how we know to look for the zeros of the binomial factors of f(x). For example, x+2=0 ⇒ x=-2 is a zero of f(x). (The remainder of 0 in the synthetic division also tells us f(-2)=0.)

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Answer:

-10

Step-by-step explanation:

= -X - XY

= -2 - 2×4

= -2 - 8

= -10

therefore, -X - XY = -10

Answer:

-10

Step-by-step explanation:

Answer:

-1/2

Step-by-step explanation:

First:

Flip 2/3 so it is 3/2

Second:

Multiply -1/3 by 3/2

Third:

Simplify.

-3/6 = -1/2

Hope I helped :)

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Answer:

To calculate the relative frequency, first we need to know what exactly is and how to calculate it.

Relative frequency is the ratio between the absolute frequency (how many repetitions have a specific outcome) and the total outcomes. Also, this type of frequency is used to show the representation that some data have over the whole distribution.

So, in this case, we need to just divide 13, which belongs to red marble's results, to 60 which is the total outcomes, as it's presented:

         13redmarble                                                                                                                       Fr = -------------------------

       60 totalmarbles  

Normally, relative frequency is shown as a percentage multiplying this result by 100. Therefore, 22% is the approximate percentage of the relative frequency, which means that 22% is the representation of red marbles outcomes of the whole distribution, or we can say it as a probability: there's 22% of chances when someone extract a marble, it will be red.

Answer:

40000

400

Step-by-step explanation:

40000 because 4000 * 10 = 40000

400 because 1 / 10 of 4000 = 400

Answer:

ok so 1/2 is your answer 1/4 divide = 1//2 !

Step-by-step explanation:

The given expression is sec cot csc tan.

To find the simplest form of this expression, let's break down each trigonometric function:

1. sec(theta) is equal to 1/cos(theta).
2. cot(theta) is equal to 1/tan(theta), which is the same as cos(theta)/sin(theta).
3. csc(theta) is equal to 1/sin(theta).
4. tan(theta) is equal to sin(theta)/cos(theta).

Now, substituting these values into the original expression, we get:

sec cot csc tan = (1/cos(theta)) * (cos(theta)/sin(theta)) * (1/sin(theta)) * (sin(theta)/cos(theta))

We can simplify this expression by canceling out common factors. The cos(theta) in the numerator of the second term and the denominator of the fourth term cancel out, as do the sin(theta) in the denominator of the second term and the numerator of the third term.

After canceling out these common factors, we are left with:

sec cot csc tan = 1/sin(theta)

So, the simplest form of the expression sec cot csc tan is 1/sin(theta).

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What is the simplest form of the expression below? cot(theta) cos(theta)/sin(theta)*tan(theta) divided by sin(theta)/cos(theta) tan(theta)

The given cost function is C(x)1 C(x) = 1,000 + ax + x?/ 4 and if the marginal cost at x is 400 units is -$100, then the value of a is - 150.

Given information is as follows:

Cost function C(x)1 C(x) = 1,000 + ax + x?/ 4

For x = 400, the marginal cost is $100.

Hence, we can write the following equation

marginal cost at x = 400

= C’(400) = a + 1/8 * 400

= a + 50

So, a + 50 = - 100

a = - 150

Conclusion: The given cost function is C(x)1 C(x) = 1,000 + ax + x?/ 4 and if the marginal cost at x is 400 units is -$100, then the value of a is - 150.

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Carol's bank reconciliation has cash balance of  $1,535.15 and bank balance of  $1,535.15.

Checkbook balance $ 954.25

Add  Interest $2.75

Add IRS refund $630.15

[$ 954.25 + ($ 2.75 + $630.15 ) = $1,587.15]

Less  ATM card fee $ 25.00

Less NSF fee $27.00

Book balance $1,535.15

[$1,587.15 - ($25.00 + $27.00)]

Bank balance: $ 859.75

Add Deposit in transit $1,402.05

[$ 859.75 + $1,402.05 = $2,261.80]

Less Outstanding checks:

No. 115: $521.15

No. 116: $205.50

Bank balance: $1,535.15

[$2,261.80 - ($521.15 + $205.50)]

Therefore  Carol's bank reconciliation has cash balance of  $1,535.15 and bank balance of  $1,535.15.

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