A manganese ion (Mn5+) differs from a neutral manganese atom in that the manganese ion has

Answer:

8

Explanation:

Answer:

0

Explanation:

pure elements will always possess an oxidation number of 0, regardless of their charge.

Answer:

D.) 0

Explanation:

I got it correct on founders edtell

A leather jacket and printer paper are examples of items that can be made from renewable resources, while plastic forks, metal cans, and electronics are not considered renewable due to their reliance on non-renewable materials and processes. Option  C, E

The two correct answers that are made from renewable resources are:

C) Leather jacket: Leather is derived from animal hides, which are a byproduct of the meat industry. As long as there is a sustainable and responsible approach to animal farming, the production of leather can be considered renewable. The hides are obtained from animals that are raised for meat consumption, and their use in leather production helps reduce waste.

E) Printer paper: Printer paper can be made from various sources, including trees, bamboo, and recycled paper fibers. If the paper is sourced from sustainably managed forests or from fast-growing plants like bamboo, it can be considered renewable. Additionally, the use of recycled paper fibers reduces the demand for materials and promotes a more circular economy.

The other options, A) plastic fork, B) metal can, and D) electronics, are not made from renewable resources:

A) Plastic fork: Plastics are typically derived from fossil fuels, which are non-renewable resources. The production of plastic involves the extraction and processing of petroleum or natural gas, both of which are finite resources.

B) Metal can: Metal cans are predominantly made from aluminum or steel. While these metals can be recycled, their initial production requires the extraction of raw materials from the Earth, which is not a renewable process.

D) Electronics: Electronics are made from a wide range of materials, including metals, plastics, and various chemical compounds. The production of electronics involves the extraction of raw materials, many of which are non-renewable resources.

Option C and E.

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Answer:

55/350

Explanation:

because the answer is in the middle of 50and 400

Answer:

(i) of protons

(ii) total number of both protons and neutrons

(b)they are neutral or have no overall charge because there are equal numbers of negative electrons to positive protons

Explanation:

Since both charges are equal, the number of positive protons cancels the number of negative electrons, thereby making the atom neutral

Answer:

D. fusing 5 kg of hydrogen.

Explanation:

Answer:

a. 0.2355052g

Explanation:

a)

1000ml of NaOH contain 0.241moles

24.43ml of NaOH contain (24.43*0.241)/1000 moles

= 0.00588763moles

Relative Molecular Mass of NaOH

= 1*23 + 1*16 + 1*1

= 40

1mole of NaOH weighs 40g

0.00588763moles weigh (0.00588763*40) g

= 0.2355052g

B)

NaOH -> Na+ + -OH

1 mole of NaOH dissociates to form 1 mole of -OH ions

1 mole of a substance contains 6.02*10^23 particles(atoms)

= 0.00588763 * 6.02 *10^23

= ______ions

Sally is wrong because copper is less electropositive than hydrogen, thus, can not displace hydrogen from dilute acids.

The reactions to prepare copper (ii) chloride are:

the chlo­ri­na­tion of cop­per sul­fide at a high tem­per­a­ture

reaction of copper (ii) oxide with dilute hydrochloric acid

The equations of the given reactions are as follows:CuS + Cl₂ ---> CuCl₂ + SCuO + 2HCl ----> CuCl₂ + H₂O

Reactive metals are metals that readily give up their electrons to form positive ions.

Reactive metals displace hydrogen from dilute acids. They are found in group 1A and 2A of the periodic table. Copper is not a reactive metal and will not displace hydrogen from acids.

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Sally is wrong because copper chloride is not made from the reaction of copper and dilute hydrochloric acid.

2. Copper (ii) chloride can be prepared as follows:

3. the equations of the reaction are:

Single replacement reactions are reactions in which a more reactive atom replaces another atom in a compound.

An example of a single replacement reaction is the reaction of chlorine gas with copper sulfide at high temperatures to form copper chloride.

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The hilltops and the steepest point of a slope are found in the highest and most closely-spaced contour lines on the map.

Contour lines are lines on a map that connect points of equal elevation. Each contour line represents a specific elevation, and the spacing between contour lines represents the slope of the terrain.

The closer the contour lines are to each other, the steeper the slope. The hilltops are found where the contour lines form a closed circle or oval shape. The steepest point of a slope is found where the contour lines are closest together, indicating the highest rate of change in elevation.

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Isopropyl alcohol (C3H8O) is a polar molecule due to the presence of an OH group. The types of intermolecular forces that would occur between the solute (isopropyl alcohol) and the solvent depend on the nature of the solvent. In general, polar solutes dissolve in polar solvents, and the intermolecular forces that occur are:

Hydrogen bonding: Isopropyl alcohol can form hydrogen bonds with other polar molecules, including water or other alcohols. Hydrogen bonds occur between the hydrogen atom of the OH group in isopropyl alcohol and the lone pair of electrons on the oxygen atom of the other molecule.

Dipole-dipole interactions: Isopropyl alcohol can also experience dipole-dipole interactions with other polar molecules. Dipole-dipole interactions occur when the positive end of one polar molecule is attracted to the negative end of another polar molecule due to their partial charges.

In summary, the intermolecular forces that would occur between isopropyl alcohol and a polar solvent, such as water or another alcohol, are hydrogen bonding and dipole-dipole interactions.

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The correct answer according to the law of conservation of energy is option E: "In a closed system, the total energy always remains constant."

The law of conservation of energy states that energy cannot be created or destroyed in an isolated system. Energy can only be transformed from one form to another or transferred between objects within the system. The total amount of energy within a closed system, which does not exchange energy with its surroundings, remains constant over time.

This principle is based on the understanding that energy is a fundamental quantity in nature and is conserved throughout physical processes. While energy can be converted between different forms, such as potential energy to kinetic energy or thermal energy to mechanical energy, the total amount of energy in a closed system remains unchanged.

Option A is not entirely accurate because the supply of energy is not necessarily limited; rather, it is the conservation of energy that is emphasized. Option B is incorrect as it contradicts the law of conservation of energy by suggesting that energy can be created and destroyed. Option C is also incorrect because it implies that energy can be created within a closed system. Option D is not entirely accurate as it does not account for the possibility of energy being transferred or transformed within a closed system.

Therefore, option E is the correct statement that aligns with the law of conservation of energy.

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We will utilise the water belongings tables from every state. Tables A-three, A-2, and A-five are used.

outline temperature ?

Temperature is a bodily amount that expresses quantitatively the

of hotness and coldness.

Part a

T = 179.nine and P = 10 br

Tables display that the T saturated is in addition 179.nine; hence, H20 exists as a two-segment liquid-vapor combination. Tsat-P = Tsat-P

See attachment 1 for similarly statistics on p-v and T-v.

Part b

T = one hundred fifty and P = 10 br

Tables display that the saturated T is 179.nine, implying that H20 exists withinside the sub-cooled liquid area. T. Tsat-P

Attachment 2 carries statistics on p-v and T-v.

Part c

P = 0.five br and T = one hundred ranges Celsius

According to temperature tables, the P saturated is 1.014 bar; hence, H20 exists withinside the super-heated area. Psat-T. Table A-2

Attachment three carries statistics on p-v and T-v.

Part d

P = 50 br and T = 20 ranges Celsius

According to temperature tables, the P saturated is 0.02339 bar; hence, H20 exists withinside the sub-cooled liquid area. Psat-T > Psat. A-2, Table

Attachment four carries statistics on p-v and T-v.

Part e

T = -6 C and P = 1 bar

According to temperature tables, the P saturated is 0.003689 br; hence, the H20 P > Psat-T strong due to the fact T is much less than the triple factor temperature. A5 Table

See

five for similarly statistics on p-v and T-v.

We will utilise the water property tables from each state. Tables A-3, A-2, and A-5 are used.

define temperature ?

Temperature is a physical quantity that expresses quantitatively the perceptions of hotness and coldness.

Part a

T = 179.9 and P = 10 br

Tables show that the T saturated is similarly 179.9; hence, H20 exists as a two-phase liquid-vapor combination. Tsat-P = Tsat-P

See attachment 1 for further information on p-v and T-v.

Part b

T = 150 and P = 10 br

Tables show that the saturated T is 179.9, implying that H20 exists in the sub-cooled liquid area. T. Tsat-P

Attachment 2 contains information on p-v and T-v.

Part c

P = 0.5 br and T = 100 degrees Celsius

According to temperature tables, the P saturated is 1.014 bar; hence, H20 exists in the super-heated area. Psat-T. Table A-2

Attachment 3 contains information on p-v and T-v.

Part d

P = 50 br and T = 20 degrees Celsius

According to temperature tables, the P saturated is 0.02339 bar; hence, H20 exists in the sub-cooled liquid area. Psat-T > Psat. A-2, Table

Attachment 4 contains information on p-v and T-v.

Part e

T = -6 C and P = 1 bar

According to temperature tables, the P saturated is 0.003689 br; hence, the H20 P > Psat-T solid because T is less than the triple point temperature. A5 Table

See  5 for further information on p-v and T-v.

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Answer:

Zero with the subscripts, +2 without them.

Explanation:

Hello!

In this case, since we consider that two silicon are bonded with four oxygen atoms to form silicon oxide according to the following chemical equation:

\(Si^{4+}+O^{2-}\rightarrow Si_2O_4\)

It is also possible to realize it can be simplified to obtain:

\(SiO_2\)

Which means that the total charge with the subscripts is zero, and without the subscripts +2 (+4-2).

Best regards!

Answer:

An increase in the concentration of the reactant in solution causes the reaction rate to increase exponentially - first order

The reaction rate increases in direct proportion to the concentration of the reactant in solution -second order

The reaction rate is constant regardless of the amount of reactant in solution - zero order

Explanation:

The Order of Reaction refers to the power dependence of the rate on the concentration of each reactant. The order of reaction is determined experimentally and not necessarily by inspection.

Typically, in a second order reaction, the rate of reaction increases in proportion to increase in concentration.

For a first order reaction, the rate of reaction increases exponentially as the increase in concentration.

For a zero order reaction, the rate of reaction is independent of the concentration of the reactant.

Answer:

X(HCO3)2 is X2(C2H2O6), so the total number of atoms for each element can be calculated:

2 X atoms

4 H atoms

6 C atoms

12 O atoms

Calculate the total atomic mass of the elements:

2 X atoms * atomic mass of X = 2X * atomic mass of X

4 H atoms * 1.0 amu = 4.0 amu

6 C atoms * 12.0 amu = 72.0 amu

12 O atoms * 16.0 amu = 192.0 amu

The molar mass of X(HCO3)2 is 162 g/mol, so the total atomic mass of the elements should add up to 162 g/mol:

2X * atomic mass of X + 4.0 amu + 72.0 amu + 192.0 amu = 162 g/mol

Solve for X by rearranging the equation:

2X * atomic mass of X = 162 g/mol - 4.0 amu - 72.0 amu - 192.0 amu = -12.0 amu

2X = -12.0 amu / atomic mass of X

Divide both sides by 2:

X = -6.0 amu / atomic mass of X

So the relative atomic mass of X is 6.0 amu.

The new volume of a weather balloon initially calibrated at 0.00 °C to have a volume of 12.0 L is 10.15L.

The volume of a given gas at a constant pressure can be calculated using the Charles's law equation as follows:

V₁/T₁ = V₂/T₂

Where;

According to this question, a weather balloon is calibrated at 0.00 °C to have a volume of 12.0 L. The new volume at -42.0 °C assuming pressure is held constant can be calculated as follows;

12/273 = V/231

V = 10.15L

Therefore, 10.15L is the volume of the weather balloon.

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Answer:

5.024 × 10⁻⁹ m

Explanation:

You need to use de Broglie's equation.

λ = h/mv

You have the velocity of the electron (1.43 × 10⁵ m/s), the mass of an electron (9.1 × 10⁻³¹ kg), and Planck's constant (6.626 × 10⁻³⁴ J·s).  You now need to solve for wavelength (λ).

λ = (6.626 × 10⁻³⁴ J·s)/(9.1 × 10⁻³¹ kg)(1.43 × 10⁵ m/s)

λ = 5.024 × 10⁻⁹ m

The de Broglie wavelength is 5.024 × 10⁻⁹ m.

Answer:

Absorbed

Released

Released

Explanation:

The formation of a cation is an endothermic process because energy must be absorbed in order to remove an electron from an atom.

Similarly, energy is evolved when an electron is added to an atom to form a negative ion.

The formation of an ionic compound is an exothermic process. Since ionic compounds are more stable than the individual ions separated by a distance, the excess energy of the isolated ions is evolved when the ionic compound is formed.

Statement 1: False

Statement 2: True

Statement 3: True

Statement 4: False

Statement 5: False

Statement 6: True

The partial pressure of nitrogen on Venus is approximately 321.914 kPa.

To find the partial pressure of nitrogen on Venus, we need to calculate the partial pressure using the mole fraction of nitrogen and the total atmospheric pressure. First, we convert the total atmospheric pressure from psi to kilopascals (kPa) since the mole fraction is given in terms of kPa.

1 psi = 6.89476 kPa

Therefore, the total atmospheric pressure on Venus is:

1334 psi × 6.89476 kPa/psi = 9197.53 kPa

Next, we can calculate the partial pressure of nitrogen using the mole fraction. The mole fraction of nitrogen is given as 0.035, which means that nitrogen makes up 3.5% of the total moles of gas in the atmosphere.

The partial pressure of nitrogen is given by:

Partial pressure of nitrogen = Mole fraction of nitrogen × Total atmospheric pressure

Partial pressure of nitrogen = 0.035 × 9197.53 kPa

Partial pressure of nitrogen = 321.914 kPa

Therefore, the partial pressure of nitrogen on Venus is approximately 321.914 kPa.

It's important to note that the given atmospheric composition of Venus's atmosphere and the total atmospheric pressure are approximate values and can vary depending on specific conditions and measurements.

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Answer:

There are 3.011 × 10^23 oxygen atoms

The element that helps the heart and is found in nuts and legumes is magnesium.

In this case, we are being asked about the element that promotes normal heart rhythm and muscle function and can be found in nuts, legumes, whole-grain products, and dark green vegetables. We have to know that this element is one of the key elements that are important to the health of a person.

Now we have to look at the options tat we have and see that magnesium is the element that is abundant in the nuts and the legumes and have been linked to the effective function of the heart.

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Answer :

(1) \(Cl_2+2LiI\rightarrow 2LiCl+I_2\)

(2) \(N_2+3H_2\rightarrow 2NH_3\)

(3) \(Ca(OH)_2+2HCl\rightarrow CaCl_2+H_2O\)

(4) \(2Al(NO_3)_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+6HNO_3\)

(5) \(C_4H_8+6O_2\rightarrow 4CO_2+4H_2O\)

(6) \((NH_4)_2SO_4+2KOH\rightarrow K_2SO_4+2NH_3+2H_2O\)

(7) \(2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O\)

(8) \(2H_3PO_4+3Mg(OH)_2\rightarrow Mg_3(PO_4)_2+6H_2O\)

(9) \(Al(NO_3)_3+3NaOH\rightarrow 3NaNO_3+Al(OH)_3\)

(10) \(BaCl_2+Na_2SO_4\rightarrow BaSO_4+2NaCl\)

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

Part 1 :

The unbalanced chemical reaction is,

\(Cl_2+LiI\rightarrow LiCl+I_2\)

In order to balance the chemical equation, the coefficient '2' put before the \(LiI\) and \(LiCl\) then we get the balanced chemical equation.

The balanced chemical reaction will be,

\(Cl_2+2LiI\rightarrow 2LiCl+I_2\)

Part 2 :

The unbalanced chemical reaction is,

\(N_2+H_2\rightarrow NH_3\)

In order to balance the chemical equation, the coefficient '3' put before the \(H_2\) and the coefficient '2' put before the \(NH_3\) then we get the balanced chemical equation.

The balanced chemical reaction will be,

\(N_2+3H_2\rightarrow 2NH_3\)

Part 3 :

The unbalanced chemical reaction is,

\(Ca(OH)_2+HCl\rightarrow CaCl_2+H_2O\)

In order to balance the chemical equation, the coefficient '2' put before the \(HCl\) then we get the balanced chemical equation.

The balanced chemical reaction will be,

\(Ca(OH)_2+2HCl\rightarrow CaCl_2+H_2O\)

Part 4 :

The unbalanced chemical reaction is,

\(Al(NO_3)_3+H_2SO_4\rightarrow Al_2(SO_4)_3+HNO_3\)

In order to balance the chemical equation, the coefficient '2' put before the \(Al(NO_3)_3\), the coefficient '3' put before the \(H_2SO_4\)  and the coefficient '6' put before the \(HNO_3\) then we get the balanced chemical equation.

The balanced chemical reaction will be,

\(2Al(NO_3)_3+3H_2SO_4\rightarrow Al_2(SO_4)_3+6HNO_3\)

Part 5 :

The unbalanced chemical reaction is,

\(C_4H_8+O_2\rightarrow CO_2+H_2O\)

In order to balance the chemical equation, the coefficient '6' put before the \(O_2\), the coefficient '4' put before the \(CO_2\) and the coefficient '4' put before the \(H_2O\) then we get the balanced chemical equation.

The balanced chemical reaction will be,

\(C_4H_8+6O_2\rightarrow 4CO_2+4H_2O\)

Part 6 :

The unbalanced chemical reaction is,

\((NH_4)_2SO_4+KOH\rightarrow K_2SO_4+NH_3+H_2O\)

In order to balance the chemical equation, the coefficient '2' put before the \(KOH,NH_3\) and \(H_2O\) then we get the balanced chemical equation.

The balanced chemical reaction will be,

\((NH_4)_2SO_4+2KOH\rightarrow K_2SO_4+2NH_3+2H_2O\)

Part 7 :

The unbalanced chemical reaction is,

\(C_2H_2+O_2\rightarrow CO_2+H_2O\)

In order to balance the chemical equation,the coefficient '2' put before the \(C_2H_2\), the coefficient '5' put before the \(O_2\), the coefficient '4' put before the \(CO_2\) and the coefficient '2' put before the \(H_2O\) then we get the balanced chemical equation.

The balanced chemical reaction will be,

\(2C_2H_2+5O_2\rightarrow 4CO_2+2H_2O\)

Part 8 :

The unbalanced chemical reaction is,

\(H_3PO_4+Mg(OH)_2\rightarrow Mg_3(PO_4)_2+H_2O\)

In order to balance the chemical equation,the coefficient '2' put before the \(H_3PO_4\), the coefficient '3' put before the \(Mg(OH)_2\) and the coefficient '6' put before the \(H_2O\) then we get the balanced chemical equation.

The balanced chemical reaction will be,

\(2H_3PO_4+3Mg(OH)_2\rightarrow Mg_3(PO_4)_2+6H_2O\)

Part 9 :

The unbalanced chemical reaction is,

\(Al(NO_3)_3+NaOH\rightarrow NaNO_3+Al(OH)_3\)

In order to balance the chemical equation,the coefficient '3' put before the \(NaOH\) and the coefficient '3' put before the \(NaNO_3\) then we get the balanced chemical equation.

The balanced chemical reaction will be,

\(Al(NO_3)_3+3NaOH\rightarrow 3NaNO_3+Al(OH)_3\)

Part 10 :

The unbalanced chemical reaction is,

\(BaCl_2+Na_2SO_4\rightarrow BaSO_4+NaCl\)

In order to balance the chemical equation,the coefficient '2' put before the \(NaCl\) then we get the balanced chemical equation.

The balanced chemical reaction will be,

\(BaCl_2+Na_2SO_4\rightarrow BaSO_4+2NaCl\)

Answer: C

Explanation:

In endothermic reactions, enthalpy is positive, and in exothermic reactions, enthalpy is negative, So, if enthalpy is positive, then it is an endothermic reaction, and hence is required for the reaction to occur.

Sedimentation, filtration, and coagulation are the treatments that will help remove contaminants from minerals or from the pipes carrying water from a source.

Sedimentation is a process in which suspended particles settle out of water. It is one of the most basic techniques for removing particles from water. As particles settle, they become trapped in the bottom of a container or settle to the ground in an outdoor setting

Filtration is a method of removing particles from a fluid. It is a physical or chemical separation method that separates solids from fluids (liquids or gases) by adding a medium through which only the fluid can pass.

Coagulation is the process of using chemicals to remove contaminants from water. By creating a chemical reaction, coagulation destabilizes particles and causes them to clump together. This helps to remove the contaminants from the water.

Disinfection is the process of eliminating or destroying pathogens that cause infection. Disinfection eliminates harmful microorganisms by destroying or inactivating them. The disinfectant is a chemical or physical agent that is used to destroy or inactivate harmful microorganisms.

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We may utilize the balanced chemical equation for the reaction between KOH and H3PO4 to address this issue. Consequently, 0.0591 mM of H3PO4 can be fully neutralized by 30.2 mL of 0.177 M KOH.

H3PO4 + 3KOH → K3PO4 + 3H2O

First, let's calculate the number of moles of KOH used:

moles of KOH = Molarity x Volume (in liters)

moles of KOH = 0.177 M x 0.0302 L

moles of KOH = 0.005352 moles

moles of H3PO4 = 0.005352 moles / 3 = 0.001784 moles

Using the volume of the H3PO4 solution, we can get the initial concentration of H3PO4 in millimoles per millilitre (mM):

mM of H3PO4 = moles of H3PO4 / volume of H3PO4 (in mL)

mM of H3PO4 = 0.001784 moles / 30.2 mL = 0.0591 mM

One molecule of the chemical H3PO4 has four oxygen atoms, three hydrogen atoms, and one phosphorus atom. The average atomic masses of these elements are added to determine the molar mass: H3PO4 has a molar mass of 3 (1.008 g), 1 (30.97 g), 4, and 16 (totaling 97.99 g).

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