A rabbit is moving in the positive x-direction at 1.10 m/s when it spots a predator and accelerates to a velocity of 10.9 m/s along the negative y-axis, all in 1.60 s. Determine the x-component and the y-component of the rabbit's acceleration. (Enter your answers in m/s2. Indicate the direction with the signs of your answers.)

The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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Answer:1. The masses Of The objects 2.the distance between the objects

Explanation:

newton's law of universal gravitation states that the force of attraction between two masses is directly proportional to the product Of The masses, and inversely proportional to thermal square Of The distance between them.therefore we can conclude that the two factors affecting the force between masses are:(1)the masses of the objects (2)the distance between the objects

The two factors that affect the force between two masses, according to the universal law of gravitation are

Newton's Universal law of gravitation states that the force of attraction that exists between particle or objects is directly proportion to the product of their masses and inversely proportional to the distances between them .

Therefore, The two factors that affect the force between two masses, according to the universal law of gravitation are

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Answer:

Option A

Explanation:

In this experiment, when balloon is rubbed on the chair electrons are transferred from the hair to the surface of the balloon thereby making balloon negatively charged and hair positively charged. When two negatively charged balloon are brought close to each other, they repel while when balloon is brought closer to the hair, they attract each other

Hence, option A is correct

Answer:

max

Explanation:

because its right 90/7

Answer:

Sound is produced when an object vibrates, creating a pressure wave. This pressure wave causes particles in the surrounding medium (air, water, or solid) to have vibrational motion. As the particles vibrate, they move nearby particles, transmitting the sound further through the medium.

Answer:

D

Explanation:

The wavelength of wave B (green) is half of the wavelength of wave A (black). Therefore, option (d) is correct.

The wavelength of a wave can be defined as the distance between the two adjacent points which are in phase with respect to each other. The separation between the two adjacent crests or adjacent troughs on a wave is also known as wavelength.

The relationship between the wavelength (λ) of the wave, frequency (ν), and speed of the wave (V) is:

V = νλ

Transverse waves oscillate along routes that are perpendicular to the direction in which the wave is propagating forward. In a transverse wave, particles of matter are oscillated up and down about their mean position instead of following the path of the wave.

Therefore, the wavelength of the transverse wave halved from black wave A to green wave B.

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Given:

• Amount of fat stored = 3500 Cal

• Rate = 340 Cal/h

• Speed of brisk walk = 3.5 mi/h

Let's find the distance a person will have to walk to burn off 1 lb of body fat.

Since the person burns fat at a rate of 340 Cal/h, the number of hours it will take to burn 1 lb will be:

It will take the person 10.29 hours to burn 1 lb.

Now, since the speed of the walk is 3.5 mi/h and the time it will take to burn 1 lb is 10.29 hours, the distance the person will cover to burn 1 lb will be:

Therefore, the person will have to will have to walk 36.03 miles

ANSWER:

36.03 mi

Answer:

It isn't moving

Explanation:

Solution :

c). \($\vec{F}_A = $\) force applied by Abe

   \($\vec{F}_B = $\) force applied by Barry

   \($\vec{F}_E = $\) force applied by Eric

   \($\vec{F}_R = $\) Resultant force

\($\vec{F}_A $\)  in the vector form can be written as :

         \($\vec{F}_A = 0 \hat{i} + 60 \hat{j}$\)

\($\vec{F}_B $\)  in the vector form can be written as :

         \($\vec{F}_B = 60 \hat{i} + 0 \hat{j}$\)

The resultant,

\($\vec{F}_R= \vec{F}_A+\vec{F}_B $\)

     \($=(0 \hat i + 60 \hat j)+(60 \hat i + 0\hat j)$\)

    \($=60 \hat i + 60 \hat j$\)

\($|\vec{F}_R| = \sqrt{60^2+60^2}$\)

        = 84.853 N

d). As the three forces are in equilibrium, therefore,

\($|\vec F_E| = |\vec F_R|$\)

\($|\vec F_E| =84.853 \ N$\)

e). The direction of the force exerted by Eric is exactly opposite to the direction of the resultant force.

The direction of the resultant force is :

\($\theta = \tan ^{-1}\left(\frac{F_y}{F_x}\right)$\)

   \($ = \tan ^{-1}\left(\frac{60}{60}\right)$\)

  = 45°  north east

The direction of the force E is  45° west or  45° south west.

A heat engine is a device that uses to produce useful work.

Definition - a device for producing motive power from heat, such as a gasoline engine or steam engine.

So..

If this is a true or false question.. Your answer is:

TRUE

Answer:

HEAT

Explanation:

Answer: -0.10m/s

Explanation:

khan academy

Using what has been learned about research methods, some of the limitations of Freud’s theory of personality are

This is further explained below.

Generally, Id, ego, and superego, according to Freud, make up the three parts of the mind, and interactions and conflicts between these parts are what provide personality (Freud, 1923/1949).

The id, according to Freudian thought, is the psychological trait that serves as the foundation for our most primal instincts.

In conclusion,

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Answer:

2g cube of Aluminum

Explanation:

Answer:

Shorter

Explanation:

i got the same question lol

When a train approaches the observer, the observer hears the sound with high frequency and the wavelenght observed by the observer is shorter.

Doppler effect is defined as the phenomenon observed when the a wave from the source is moving towards or moving away from the observer. It gives the relation between the frequency change with respect to the observer.

When a light or sound wave from the source is moving towards the observer, it get compressed. When a light or sound wave is moving away from the observer, it gets stretched.

When the sound wave move towards the observer, the frequency received by the observer is greater. This is called the blue shift. When the sound waves move away from the observer, the frequency received by the observer is lesser. This is called red shift.

Frequency is inversely proportional to the wavelength. In red shift, frequency is lesser and wavelegth is higher. In blue shift, the wavelength is shorter due to higher frequency.

Hence, the train approach the observer, have high frequency and shorter wavelength.

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The hiker made it to a safe landing on the other side of the gap after travelling horizontally at 2.49 m.

The time taken for the hiker to fall from the given height is calculated as follows;

h = vt + ¹/₂gt²

where;

h = ¹/₂gt²

t = √(2h/g)

t = √[(2 x 0.6) / (9.8)]

t = 0.35 seconds

The horizontal velocity of the hiker during the period of acceleration is calculated as follows;

Vₓ = at

Vₓ = (5.92 m/s²) x (1.2 s)

Vₓ = 7.104 m/s

The horizontal distance travelled during the time period of 0.35 seconds;

X = Vₓt

X = 7.104 x 0.35

X = 2.49 m

Thus, the hiker made it to a safe landing on the other side of the gap which is 2.3 m wide and smaller to his horizontal displacement of 2.49 m.

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1. The electron experiences acceleration and moves independently in the y-direction.

2. The y-component of the electron's displacement after 2.40 μs in the electric field is -8.11 μm.

3.  The x-component of displacement remains zero.

To calculate the y-component and x-component of the electron's displacement, we need to consider the motion of the electron in the electric field. Let's break it down step by step:

1. Acceleration of the Electron:

The electric field causes a force on the electron given by the equation: F = qE, where F is the force, q is the charge of the electron, and E is the electric field.

Since the charge of an electron is -1.6 × \(10^-^1^9\) C, and the electric field is 201 N/C, we can calculate the force:

F = (-1.6 × \(10^-^1^9\)C) * (201 N/C)

  = -3.216 × \(10^-^1^7\) N

Using Newton's second law, F = ma, we can find the acceleration (a) of the electron:

a = F / m

  = (-3.216 × \(10^-^1^7\) N) / (9.109 ×\(10^-^3^1\) kg)

  = -3.530 × \(10^1^3 m/s^2\)

2. Displacement in the y-direction:

Since no other forces act on the electron, its motion in the y-direction is independent of the electric field. The equation for displacement (y) under constant acceleration is:

y = (1/2) * a *\(t^2\)

Substituting the values, where the time (t) is 2.40 μs (2.40 ×\(10^-^6\) s), we can calculate the y-component of displacement:

y = (1/2) * (-3.530 ×\(10^1^3 m/s^2\)) * (2.40 ×\(10^-^6 s)^2\)

  = -8.11 μm

Therefore, the y-component of the electron's displacement 2.40 μs after entering the electric-field region is -8.11 μm.

3. Displacement in the x-direction:

Since the electron's velocity is only in the y-direction initially, the x-component of the displacement remains zero. Without any forces acting in the x-direction, the electron continues to move in the y-direction without changing its x-position.

Hence, the x-component of the electron's displacement 2.40 μs after entering the electric-field region is 0 meters.

Please note that the calculations provided are based on the given values and the provided formulas for displacement and acceleration.

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Answer:

Parents pass on traits or characteristics, such as eye colour and blood type, to their children through their genes

Explanation:

Answer:

125J

Explanation:

\(work \: = force \: \times distance \\ = 25 \times 5 \\ = 125joules\)

Answer and Explaination:

To solve this problem, we can analyze the forces acting on the mass as it travels up the inclined plane. We'll consider the gravitational force and the force exerted by the spring.

1. Gravitational force:

The force due to gravity can be broken down into two components: one perpendicular to the inclined plane (mg * cosθ) and one parallel to the inclined plane (mg * sinθ), where m is the mass and θ is the angle of the inclined plane.

2. Force exerted by the spring:

The force exerted by the spring can be calculated using Hooke's Law, which states that the force exerted by a spring is directly proportional to the displacement from its equilibrium position. The force can be written as F = -kx, where F is the force exerted by the spring, k is the spring constant, and x is the displacement from the equilibrium position.

Given:

Mass (m) = 5.0 kg

Compression of the spring (x) = 20.0 cm = 0.20 m

Angle of the inclined plane (θ) = 30°

First, let's find the force exerted by the spring (F_spring):

F_spring = -kx

To find k, we need the spring constant. Let's assume that the spring is ideal and obeys Hooke's Law linearly.

Next, let's calculate the gravitational force components:

Gravitational force parallel to the inclined plane (F_parallel) = mg * sinθ

Gravitational force perpendicular to the inclined plane (F_perpendicular) = mg * cosθ

Since the inclined plane is frictionless, the force parallel to the inclined plane (F_parallel) will be canceled out by the force exerted by the spring (F_spring) when the mass reaches its highest point.

At the highest point, the gravitational force perpendicular to the inclined plane (F_perpendicular) will be equal to the force exerted by the spring (F_spring).

Therefore, we have:

F_perpendicular = F_spring

mg * cosθ = -kx

Now, let's substitute the known values and solve for k:

(5.0 kg * 9.8 m/s^2) * cos(30°) = -k * 0.20 m

49.0 N * 0.866 = -k * 0.20 m

42.426 N = -0.20 k

k = -42.426 N / (-0.20 m)

k = 212.13 N/m

Now that we know the spring constant, we can calculate the maximum potential energy stored in the spring (PE_spring) when the mass reaches its highest point:

PE_spring = (1/2) * k * x^2

PE_spring = (1/2) * 212.13 N/m * (0.20 m)^2

PE_spring = 4.243 J

The maximum potential energy (PE_spring) is equal to the maximum kinetic energy (KE_max) at the highest point, which is also the energy the mass has gained from the spring.

KE_max = PE_spring = 4.243 J

Next, we can calculate the height (h) the mass reaches on the inclined plane:

KE_max = m * g * h

4.243 J = 5.0 kg * 9.8 m/s^2 * h

h = 4.243 J / (5.0 kg * 9.8 m/s^2)

h = 0.086 m

The height the mass reaches on the inclined plane is 0.086 m.

Now, we can calculate the distance traveled.

A 5.0 kg object compresses a spring by 0.20 m with a spring constant of 25 N/m. It climbs an incline, reaching a maximum height of 0.0102 m before coming back down, traveling a total distance of 0.0428 m.

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Answer:

The characteristics that determine how easily two substances change temperature are:

The volume and density of the substances and the amount of time they are in contact do not directly affect how easily they change temperature.

Explanation:

Answer:

1.92 Watt lost

Explanation:

Power rating of each toaster = 600 Watts

Current that flows = 5 Amperes

Wasted power = 1 Watt

Voltage of toaster can be gotten from P = \(I^{2}\)R

where I = current

and R = Resistance

600 = \(5^{2}\) x R

R = 600/25 = 24 Ohms.

According to joules loss due to heating of wire

Power loss P ∝ \(I^{2}\)R

imputing values,

1 ∝ \(5^{2}\) x 24

1 ∝ 600

to remove the proportionality sign, we introduce a constant k

1 = 600k

k = 1/600 = 0.00167

For the case where the current is doubled to 10 ampere, as the power doubles to 1200 W.

The resistance across the wire becomes

1200 = \(10^{2}\)R

R = 1200/100 = 12 Ohms

power loss P = k x \(I^{2}\)R

P = 0.0016 x \(10^{2}\) x 12

P = 1.92 Watt lost

This question involves the concepts of power, current, and resistance.

The power wasted by the wires in the home for two units will be "4 watt".

The power wasted by the wires can be given in terms of current and resistance by the following formula:

\(P=I^2R\\\\\frac{P}{I^2}=R=Constant\\\\\frac{P_1}{I_1^2}=\frac{P_2}{I_2^2}\)

where,

Therefore,

\(\frac{1\ watt}{(5\ A)^2}=\frac{P_2}{(10\ A)^2}\\\\P_2=\frac{(1\ watt)(100\ A^2)}{25\ A^2}\)

P₂ = 4 watt

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For the two animals involved (bird and its prey), the momentum of both animals is conserved.

The principle of conservation of momentum states that if two objects collide, then the total momentum before and after the collision will be the same if there is no external force acting on the colliding objects.

Initial momentum = final momentum

Thus, for the two animals involved (bird and its prey), the momentum of both animals is conserved.

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1a) Energy is absorbed, and the reaction is endothermic.

1b) The products have higher potential energy, the enthalpy change is positive, indicating an endothermic reaction.

1c) The peak of the potential energy diagram.

2a) The activation energy labeled as the difference between the reactants and the peak

2b) The activation energy can be determined by calculating the difference between the reactants.

2c) The enthalpy change can be calculated by finding the difference between the energy of the reactants and the energy of the products.

2d) The reaction is exothermic. In terms of the graph's shape.

3a) A decrease in potential energy as the products form.

3b)This indicates that a small amount of energy from the spark is needed to overcome the activation energy barrier

Part 1:

1a. To determine if the reaction is endothermic or exothermic, we need to analyze the potential energy diagram. If the products have lower potential energy than the reactants, it indicates that energy is released, and the reaction is exothermic. Conversely, if the products have higher potential energy than the reactants, it suggests that energy is absorbed, and the reaction is endothermic.

1b. The enthalpy change (ΔH) for the reaction can be calculated by comparing the potential energy of the products and the reactants. If the products have lower potential energy, the enthalpy change is negative, indicating an exothermic reaction. If the products have higher potential energy, the enthalpy change is positive, indicating an endothermic reaction.

1c. The activation energy (Ea) can be determined by examining the energy difference between the reactants' potential energy and the peak of the potential energy diagram.

Part 2:

2a. Since the energy of the reactants is 30 kJ, the energy of the products is 5 kJ, and the maximum energy of the system is 40 kJ, we can sketch a potential energy diagram with the reactants at 30 kJ, the products at 5 kJ, the activation energy labeled as the difference between the reactants and the peak, and the enthalpy change as the difference between the reactants and products.

2b. The activation energy can be determined by calculating the difference between the reactants' energy and the peak of the potential energy diagram.

2c. The enthalpy change can be calculated by finding the difference between the energy of the reactants and the energy of the products.

2d. Based on the energy values, if the energy of the products is lower than the energy of the reactants, the reaction is exothermic. In terms of the graph's shape, if the potential energy decreases from reactants to products, it indicates an exothermic reaction.

Part 3:

3a. The potential energy diagram for the striking and burning of a match can be sketched to show the initial potential energy of the reactants, a peak representing the activation energy, and a decrease in potential energy as the products form.

3b. The potential energy diagram would show an initial higher potential energy for the reactants, a peak representing the activation energy required for the reaction to occur, and a decrease in potential energy as the products form. This indicates that a small amount of energy from the spark is needed to overcome the activation energy barrier, leading to the release of a greater amount of energy during the burning process.

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Answer:

If 99.995 A  pass thru a shunt and 5 mA pass thru the meter, the meter will have full scale deflection for a current of 100 A.

By Ohm's Law  

99.995 Rs = .005 Rm

Rs = .005 / 99.995 * 120

Rs = .006 ohms

Using a shunt resistance of .006 Ω will produce the required result.

The value of the shunt resistor should be very low to divert most of the current, use a shunt resistor with a value of 0.0012 ohms.

The value of the shunt resistor (Rs) is:

Rs = (Rm × Im) ÷ (If - Im)

where:

Rs = Shunt resistor value

Rm = Resistance of the milliammeter

Im = Full-scale current of the milliammeter

If = Maximum current we want to measure

The shunt resistor value:

Rs = (120 × 5 ) ÷ (100  - 5)

Rs = (0.12 ) ÷ (100 - 0.005)

Rs = 0.12 ÷ 99.995

Rs = 0.00120018 ohms

Since the value of the shunt resistor should be very low to divert most of the current, use a shunt resistor with a value of  0.0012 ohms.

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Answer:

The magnitude of the work done by the worker is 303 J.

Explanation:

The work done by the worker can be found as follows:

\( W = |F|\cdot |d| cos(\alpha) \)                              

Where:

F: is the force applied by the worker

d: is the displacement = 5.0 m

α: is the angle between the force applied and the displacement = 180°

We need to find the force applied by the worker:

\(\Sigma F = ma\)

Taking as positive the movement direction of the crate we have:

\( -F - F_{\mu} + P_{x} = 0 \)  

Where:              

m: is the crate's mass

a: is the acceleration = 0 (It is moving at constant speed)

F: is the force applied by the worker

Pₓ: is the weight in the horizontal direction    

\(F_{\mu}\): is the frictional force  

Hence, the force applied by the worker is:            

\(F = P_{x} - F_{\mu} = mgsin(\theta) - \mu mgcos(\theta)\)

\( F = 50 kg*9.81 m/s^{2}*(sin(25) - 0.33cos(25)) = 60.6 N \)  

Then, the work done by the worker is:                        

\( W = |F|\cdot |d| cos(\alpha) = 60.6 N*5.0 m*cos(180) = -303 J \)                              

Therefore, the magnitude of the work done by the worker is 303 J.

I hope it helps you!                                            

The work is done by the worker will be 303 J. Work done is described as the multiplication of applied force and the amount of displacement.

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative.it depends on the direction of the body displaced. if the body is displaced in the same direction of the force it will be positive.

The given data in the problem is;

F is the force applied by the worker

d is the displacement = 5.0 m

α is the angle between the force applied and the displacement = 180°

m is the crate's mass=  50 kg

a is the acceleration = 0

Pₓ: is the weight in the horizontal direction    

The net force on the crate is found as;

\(\rm F_{net}= P_X - F_{\mu} \\\\ \rm F_{net}= mg sin \theta - \mu mg cos \theta \\\\ \rm F_{net}=50 \times \times 9.81 (sin 25^0 -0.33 cos(25) \\\\ \rm F_{net}= 60.6 N \\\\\)

The work done  by the worker will be;

\(\rm W= Fd cos \alpha \\\\ \rm W= 60.6 \times 5.0 cos 180^0 \\\\\rm W=-303 \ J\)

Hence the work is done by the worker will be 303 J.

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Answer:

0.15 m

Explanation:

First calculating the center of mass from the saw horse

\(\frac{3.15}{2} -1=0.575 m\)

from the free body diagram we can write

Taking moment about the saw horse

55.9×9.81×y=14.5×0.575×9.81

y= 0.15 m

So, the painter walk from the saw horse on the right until the board begins to tip is 0.15 m far.

The projectile launch relations allow finding the results for the different questions are:

     1. Rise time is 2.35 s

    2. The maximum height is 27 m

    3. The initial velocity is 26 m / s

    4. The launch angle is 62.3º

The launch of projectiles is an application of kinematics to the movement of objects near the earth's surface, in this case there is no acceleration on the x-axis and the acceleration is the gravity acceleration on the y-axis.

In the attachment we have a movement diagram of the football ball

1.  As the acceleration is constant, the time it takes the body to go up is equal to the time it takes to go down, therefore, as the total time affects, the time it takes to go up is half.

         \(t_u =\frac{t_{total} }{ 2}\)  

          t_u = 4.70 / 2

          t_u = 2.35 s

2. How high does the ball reach?

At the point of maximum height the vertical velocity is zero

        \(v_y = v_{oy} - g t\\0= v_{oy} - gt\\v_{oy} = gt\)

       \(v_{oy}\) = 9.8 2.35

        \(v_{oy}\) = 23 m / s

Now we can use the equation.

         \(v_y^2 = v_{oy}^2 - 2 g y\\0 = v_{oy}^2 - 2 g y\\\\y = \frac{v_{oy}^2}{2g}\)

        y = \(\frac{23^2}{2 \ 9.8}\)

        y = 27 m

2. What is the initial velocity?

The initial vertical velocity is 23 m / s

We look for the horizontal speed.

            \(v_x = \frac{x}{t}\)

They indicate the throw range is 57 m in the time of 4.70 s

            vₓ = 57.0 / 4.70

            vₓ = 12.1 m / s

To calculate the magnitude we use the Pythagorean Theorem

            v₀ = \(\sqrt{v_{ox}^2 + v_{oy}^2}\)  

            v₀ = \(\sqrt{12.1^2 + 23^2}\)  

            v₀ = 26 m / s

3. The launch angle

Let's use trigonometry

          tan θ = \(\frac{v_{oy}}{v_{ox}}\)  

          θ = tan⁻¹ \(\frac{v_{oy}}{ v_{ox}}\)

          θ = tan⁻¹  \(\frac{23}{12.1}\)

          θ = 62.3º

In conclusion, using the projectile launch relatios we can find the results for the different questions are:

     1. The rise time is 2.35 s

    2. The maximum height is 27 m

    3. The initial velocity is 26 m / s

    4. The launch angle is 62.3º

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The girl in the picture is using an ore to push the water backwards. At the same time the canoe is moving forward with the same amount of force. Newton's Third Law would explain why for every action there is an opposite and equal reaction. Hence correct  option A, (Newton's Third Law.)

Every action has an equal and opposite response, according to Newton's Third Law of Motion. In the example, the girl applies an action force to the water when she pushes it backward with the ore. Newton's Third Law states that the girl and the canoe are both subject to an equal and opposite reaction force from the water.

The girl and the canoe thus encounter a backward reaction force from the water, which causes the canoe to advance. The action force is what the girl with the ore is doing, and the reaction force is what the water is doing to the girl and the canoe. The Third Law of Newton applies to this occurrence.

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Answer: If you meant 5 miles in 20 minutes than it’s 1 mile in 5 minutes

Explanation:

The car's average speed is

0.1875 • (the number of miles it covered)