The missile is flying at an altitude of approximately 124.22 ft above the ground.
The altitude at which the missile is flying, we need to calculate the distance between the ground and the Mach wave generated by the nose of the missile.
Let's assume that the speed of sound at the given altitude is 1116 ft/s (which is approximately the speed of sound at sea level).
The formula to calculate the distance between the ground and the Mach wave is:
\(\(d = \frac{M^2}{\sqrt{M^2 - 1}} \cdot h\)\)
Where:
\(\(d\)\) = Distance between the ground and the Mach wave
\(\(M\)\)= Mach number of the missile
\(\(h\)\) = Altitude of the missile above the ground
In this case, the Mach number of the missile is 1.5, and the distance between the ground and the Mach wave \(\(d\)\) is given as 559 ft. Let's substitute these values into the formula and solve for\(\(h\)\):
\(\(559 = \frac{1.5^2}{\sqrt{1.5^2 - 1}} \cdot h\)\)
\(\(559 = \frac{2.25}{\sqrt{2.25 - 1}} \cdot h\)\)
\(\(559 = \frac{2.25}{\sqrt{0.25}} \cdot h\)\)
\(\(559 = \frac{2.25}{0.5} \cdot h\)\)\(\(559 = \frac{2.25}{\sqrt{2.25 - 1}} \cdot h\)\)
\(\(559 = 4.5 \cdot h\)\)
Now, we can solve for \(\(h\)\):
\(\(h = \frac{559}{4.5}\)\)
\(\(h \approx 124.22\) ft\)
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Which of these is
considered "work"
according to
science?
A. pushing against a wall
B. babysitting
C. kicking a soccer ball
Answer:c
Explanation:work is force x distance. The wall doesn’t move any distance in A so that’s not work. B involves tasks that do work but I don’t think this is what they’re going for. For a short instance while kicking a ball, your foot is applying a force to the ball which moves a distance before following its own trajectory after contact with your foot. Because the contact has a short duration and isn’t instantaneous, this is work
What name carries the hypothetical artificial megastructure surrounding a star in order to capture its power?.
A light-rail train going from one station to the next on a straight section of track accelerates from rest at 1.1 m/s2 for 20 s. it then proceeds at constant speed for 1100 m before slowing down at 2.2 m/s2 until it stops at the station. what is the distance between the stations?
The distance between the stations is 1320 m
How to determine the distance travelled in the first 20 sWe'll begin by calculating the distance travelled by the train in the first 20 s. This can be obtained as follow:
Initial velocity (u) = 0 m/sAcceleration (a) = 1.1 m/s²Time (t) = 20 sDistance (s) =?s = ut + ½at²
s = (0 × 20) + (½ × 1.1 × 20²)
s = 0 + 220
s = 220 m
How to determine the distance between the stationsThe distance between the stations can be obtained as illustrated below:
Distance in the 1st 20 s = 220 mDistance in the remaining journey = 1100 mTotal distance =?Total distance = 220 + 110
Total distance = 1320
Thus, the distance between both stations is 1320 m
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what is the quantiti of component k that will be needed to assemble 30 units of p
Since we need to assemble 30 units of p, the total amount of component k required would be (x/2) * 30 units.
To determine the quantity of component k that will be needed to assemble 30 units of p, we need to have the required amount of component k for one unit of p.
The required amount of component k can be obtained from the given data.
A component k is required in a ratio of 2:1 with component j to produce one unit of p. This means that for every two units of component j, one unit of component k is required.
So, to find the required quantity of component k for one unit of p, we need to divide the amount of component k required for 2 units of component j by 2.
Let's assume that x units of component j are required for one unit of p. Then, the required amount of component k for one unit of p would be x/2 units.
Since component j is required in a ratio of 3:1 with component i, we can assume that y units of component i are required for one unit of p.
Then, the required amount of component j for one unit of p would be 3y units.
Therefore, the total amount of component k required for one unit of p can be expressed as (x/2) units. The total amount of component j required for one unit of p can be expressed as 3y units.
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Using a 675 nm wavelength laser, you form the diffraction pattern of a 1.11 mm wide slit on a screen. You measure on the screen that the 15th dark fringe is 8.99 cm away from the center of the central maximum. How far is the screen located from the slit
The screen is located approximately 271.1 cm away from the slit.
\(y_n\) = (nλL) / w
Solving for L, we get:
L = (\(y_n\) * w) / (n * λ)
Substituting the values given, we get:
L = (8.99 cm * 0.111 cm) / (15 * 675 nm)
L ≈ 271.1 cm
A screen refers to a flat, usually rectangular surface that displays visual information. Screens are commonly used in a wide range of electronic devices, such as televisions, computers, smartphones, tablets, and even wearable devices like smartwatches. Screens have become an integral part of modern life, used for everything from entertainment and communication to work and education.
Screens can be made from a variety of materials, such as glass, plastic, or metal, and can use different display technologies, such as LCD (Liquid Crystal Display), OLED (Organic Light Emitting Diode), or LED (Light Emitting Diode). The resolution of a screen refers to the number of pixels it can display, with higher resolutions allowing for more detailed and sharper images.
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A 8 kg cat is running 4 m/s. How much kinetic energy does it
have?
tin nergy and is rolling
Answer:
The formula for kinetic energy is,
where m is mass and v is velocity.
It's kinetic energy is 64 Joules.
Explanation:
(b) Sea level rise is widely acknowledged to be a key consequence of climate change. The Ministry for the Environment (2015) projections are for around 0.7 m to 1.9 m of sea level rise by 2050 under RCP2.6 to RCP8.5.
(i) Briefly explain the two main mechanisms involved in sea level rise, and which one will dominate under the RCP8.5 scenario.
(ii) Sea walls (also know as "hard defences") are an engineering option preferred by some coastal human communities. What are the potential impacts on neighbouring communities of sea walls?
The two main mechanisms involved in sea level rise are thermal expansion and the melting of land-based ice. Hard defenses can provide protection against rising sea levels and coastal erosion for the communities located directly behind them, they can have potential impacts on neighboring communities.
As the Earth's oceans absorb heat from the atmosphere, the water expands thermally, leading to an increase in sea level.
Melting of land-based ice refers to the melting of glaciers and ice sheets, such as those in Greenland and Antarctica.
Under the RCP8.5 scenario, which represents a high greenhouse gas emissions trajectory, the dominant mechanism of sea level rise is expected to be the melting of land-based ice.
The increased temperature and subsequent accelerated melting of ice sheets and glaciers would contribute significantly to rising sea levels.
Hard defenses can provide protection against rising sea levels and coastal erosion for the communities located directly behind them, they can have potential impacts on neighboring communities.
Some of these impacts include Increased erosion, altered wave patterns, loss of coastal access, coastal squeeze, and visual and aesthetic impact.
It is essential to consider these potential impacts on neighboring communities when evaluating the suitability and long-term effects of implementing sea walls as coastal protection measures.
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It took Lightning McGreen 2.5 hours to travel
600 kilometers.
How fast was he going in Kilometers an hour?
Answer:
240km/h
Explanation:
speed=distance/time
speed=600/2.5
=240km/h
Answer:
you know the answer
Explanation:
Two vehicles have a head-on collision. The vehicles essentially stick together and travel a certain distance for 20 seconds before coming to a complete stop. You are able to obtain the mass of both vehicles, the initial velocity for Vehicle A, and the final velocity for both vehicles immediately after the crash. Can you determine the momentum of both vehicles before the collision?
The answer is yes because of conservation of momentum. That is, the momentum before collision is equal to the momentum after collision.
What is Momentum ?Momentum is the product of mass and velocity. It is a vector quantity. And it is measured in Kgm/s
If two vehicles have a head-on collision, the vehicles essentially stick together and travel a certain distance for 20 seconds before coming to a complete stop. The final velocity for both vehicles immediately after the crash can be obtain by using the formula
v = u - at
Where
v = final velocityu = initial velocitya = accelerationt = timeIf you are able to obtain the mass of both vehicles, the initial velocity for Vehicle A, and the final velocity for both vehicles immediately after the crash, then you can determine the momentum of both vehicles before the collision by calculating the momentum of both after the collision because momentum is always conserved.
Or by first calculating the initial velocity for vehicle B by using the formula below
\(M_{1}U_{1} - M_{2}U_{2} = (M_{1} + M_{2} )V\)
where
M1 = mass of the first objectU1 = initial velocity of the first objectM2 = mass of the second objectU2 = initial velocity of the second objectV = common final velocityAfter we obtain initial velocity for vehicle B, we can calculate the momentum of both vehicles before the collision
Therefore, the momentum of both vehicles before the collision can be determined.
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Petroleum is a non -renewable resource. Therefore, its use needs
to be planned so that present and future use can be adequately met.
Explain how the optimal level of use of petroleum can be
achieved.
Petroleum is a non-renewable resource, which means that it cannot be replenished. Because of this, its usage needs to be planned properly to make sure that there is sufficient availability for present and future needs
The optimal level of use of petroleum can be achieved by several ways which are listed below:
1. Reduce wastage: The optimal level of petroleum use can be achieved by reducing wastage. We should aim to use petroleum products efficiently to minimize wastage and ensure that the resource is not used up too quickly.
2. Develop alternative energy sources: Another way to achieve the optimal level of petroleum use is to develop alternative energy sources. Renewable energy sources like solar, wind, and hydro can be developed to supplement petroleum.
3. Increase efficiency: The third way to achieve the optimal level of petroleum use is to increase efficiency. We can achieve this by improving the efficiency of vehicles and machinery that consume petroleum products.
4. Conservation: Conservation can also help achieve the optimal level of petroleum use. We can conserve petroleum by using it judiciously and avoiding unnecessary use. We can also reduce our reliance on petroleum products by using alternatives like public transport or bicycles.
5. Develop sustainable transportation: Developing sustainable transportation can also help achieve the optimal level of petroleum use. We can develop transportation systems that are more efficient, rely on alternative energy sources, and reduce the amount of petroleum consumed.
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A small grinding wheel has a moment of inertia of 4.0*10-5kgm2. What net torque must be applied to the wheel for its angular acceleration to be 150 rad/s2
Hi there!
We can use the rotational equivalent of Newton's Second Law:
\(\huge\boxed{\Sigma \tau = I \alpha}\)
Στ = Net Torque (Nm)
I = Moment of inertia (kgm²)
α = Angular acceleration (rad/sec²)
We can plug in the given values to solve.
\(\Sigma \tau = (4 * 10^{-5})(150) = \boxed{0.006 Nm}\)
The proposed mechanism for a reaction is 1. A(g) + B(g) ⇌ X(g) Fast 2. X(g) + C(g) → Y(g) Slow 3. Y(g) → D(g) Fast What is D? A. Reactant B. More than one of these C. Catalyst D. Product E. Intermediate 2. The proposed mechanism for the reaction below is a one-step mechanism. NO + O3 => NO2 + O2 Which of the following would be a rate law for the reaction? A. rate = k[NO][O3] B. rate = k[O3] C. rate = k[NO] D. rate = k[O][NO3] E. rate = k[NO2][O2]
NO + O3 => NO2 + O2 of the following would be a rate law for the reaction The correct response is (Option E) Rate = k is the rate rule. [NO] [O₃].
The rate law for this common reaction will be: rate = k[A]n[B] for the products: A + Bᵃ
The order of this reaction is n in A and an in B. The sum of the orders of each reactant, in this situation, produces the overall reaction.
The reaction's overall order is n + a.
We are aware that the reaction in our case is first order in O3 and second order generally. Then:
Order in NO plus Order in O3 represents the reaction's overall order.
2 = n + 1\s2 - 1 = n\sn = 1
The reaction is then of first order for NO and O3.
Rate = k[NO] [O₃]will be the rate law.
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The following questions concern a particular reaction where:ΔH = - 32 kJΔS = - 98 J/K1. Assuming that enthalpy and entropy do not vary with temperature, at what temperature will the reaction be at equilibrium?A. - 330 KB. 330 KC. 330 ∘CD. 0.33 KE. 0.30 ∘C
By assuming that enthalpy and entropy do not vary with temperature, the reaction will be at equilibrium at a temperature of approximately 330 K.
The temperature at which the reaction will be at equilibrium can be determined using the Gibbs free energy equation: ΔG = ΔH - TΔS.
At equilibrium, ΔG = 0. So, we can set up the equation as follows:
0 = -32,000 J/mol - T(-98 J/mol*K)
Now, we need to solve T:
32,000 J/mol = 98 J/mol*K * T
T = 32,000 J/mol / 98 J/mol*K
T = 326.53 K
Therefore, the temperature at which the reaction will be at equilibrium is approximately 326.53 K. The closest answer choice to 326.53 K is B. 330 K.
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A new way of "multiplying" two vectors is introduced in this chapter. What is it called? Select one: O a. The tensor product. O b. The angular product. Oc. The scalar product. O d. The dot product. O e. The cross product.
The correct option is option e) cross product
The cross-product is a new way of "multiplying" two vectors. It results in a new vector that is perpendicular to both the original vectors and its magnitude is given by the area of the parallelogram formed by the two original vectors.
In three-dimensional space, cross-product is a binary operation on two vectors. It yields a vector perpendicular to both vectors. a b represents the vector product of two vectors, a and b. Its resulting vector is parallel to a and b. Cross goods are another name for vector products.
The cross-product has four basic applications:
calculating the angle () between two vectorsdetermining a vector normal to a planecalculating the moment of a force about a pointcalculating the moment of a force about a line.Read more about Cross-Product from:
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A patient brings in a new prescription for tetracycline 500 mg, what is the best practice at data entry?
When a patient brings in a new prescription for tetracycline 500 mg
The best practice at data entry would be
Ask for her date of birth and phone numberAsk if she has any allergiesCheck if you have the medication in stockUses of tetracycline
Tetracycline is used to treat a wide variety of infections, including acne. It is an antibiotic that works by stopping the growth of bacteria. This antibiotic treats only bacterial infections. It will not work for viral infections (such as common cold, flu).
Using any antibiotic when it is not needed can cause it to not work for future infections. Tetracycline can also be used in combination with anti-ulcer medications to treat certain types of stomach ulcers.
Tetracycline works best when taken on an empty stomach 1 hour before or 2 hours after meals. If stomach upset occurs, ask your doctor if you can take this medication with food. Take each dose with a full glass of water (8 ounces or 240 millilitres) unless your doctor directs you otherwise. Do not lie down for at least 10 minutes after taking this medication. For this reason, do not take it right before bedtime.
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can you please help me with this
Answer:
1.76 seconds/cycle
Explanation:
Frequency is 10 cycles / 17.6 seconds
PERIOD is 1/frequency = 17.6 seconds/10 cycles = 1.76 s/c
cycle is a vibration , so the unit may be 1.76 second / vibration
Energy is the energy an object has because of its motion. True or False
That depends on what word you skipped at the beginning of the question.
If it's supposed to be "Potential" energy, then the statement is false.**
If It's supposed to be "Kinetic" energy, then the statement is true.
** It's also false if the missing word is "Chemical", "Mechanical", "Thermal", "Nuclear", "Electrical", "Electromagnetic", or "Nervous".)
a pole-vaulter runs down a track, plants one end of the pole into the ground, and then jumps in the air while bending the pole. As the pole unbends, it creates force that launches the pole-vaulter up and over the bar using your knowledge of potential and kinetic energy, describe how the pole is like a spring.
When the pole is lifted, it could be able to supply energy to the pole - vaulter much like that of a spring that launches the pole vaulter upwards.
How does the pole vault work?We know that the pole vault is one of the popular sports especially in the Unites States. It is a competition that takes place even at the Olympic level and has a lot of athletes that do compete in the competition.
We know that as the pole unbends, it creates force that launches the pole-vaulter up and over the bar using your knowledge of potential and kinetic energy.
This implies that there are a series of energy conversions that do take place in the pole vault as it is in operation as we can see here. Thus, it is the series of the energy conversions that takes place in the pole vaulting that enables the athlete to be able to launch high in the game as we see.
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Defects of vision and their correction drawing
No Spams ❌❌
Answer:
Vision Correction
You probably know people who need eyeglasses or contact lenses to see clearly. Maybe you need them yourself. Lenses are used to correct vision problems. Two of the most common vision problems are myopia and hyperopia.
Explanation:
hope this helps
A mass hanging on a spring is given a positive initial velocity V from equilibrium. The ensuing displacement x=x(t) from equilibrium (x=0) is governed by
mx
′′
x(0)
=−ax∣x
′
∣−kx
=0,x
′
(0)=V
where −ax∣x
′
∣ is a nonlinear damping force and −kx is a linear restoring force of the spring. First make a table of the quantities and their dimensions. What are possible time scales, and on what physical processes are they based. What are possible length scales? If the restoring force is small compared to the damping force, choose appropriate time and length scales and nondimensionalize the model so that the small term appears in the damping force.
The table of quantities and their dimensions for the given scenario is given below: Quantity Dimensions Displacement[x]L Velocity[V]LT−1 Mass[m]M L-3 Force[ax∣x′∣+kx]MLT−2
The possible time scales and their based physical processes for the given scenario are given below: Time Scales Physical ProcessesT1 = (m/a)^(1/2) Viscous damping timescale.T2 = (m/k)^(1/2)Natural frequency of the spring-mass system.T3 = (a/k)^(1/2)Critical damping timescale. The possible length scales are given below: Length Scales Description L1 = v0T1 Initial kinetic energy. L2 = x0 Initial displacement from equilibrium.L3 = cInitial position when the damping force becomes equal to the spring force. Now we need to nondimensionalize the given model, by choosing appropriate time and length scales. Let's select the natural frequency of the spring-mass system (T2) as the characteristic time and the equilibrium position of the mass (L2) as the characteristic length. From this, we can define the following dimensionless variables:t = t/T2x = x/L2. The dimensionless model is as follows:mL2x′′+aTkL2x′−k/mL2x = 0, x′(0) = V/L2T2x(0) = L2Let us assume that the damping force is small compared to the restoring force. Then the modified equation will be: mL2x′′+aTkL2x′ = 0, x′(0) = V/L2T2x(0) = L2For this model, the time scale is T2 and the length scale is L2.
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A ball starting from rest accelerates uniformly at 5.0 meters per second2 as it rolls 40. meters down an incline. How much time is required for the ball to roll the 40. meters
The time required for the ball to roll down the given distance is 4 seconds.
Given the data in the question;
Since the ball started from rest,
Initial velocity; \(u = 0\)Acceleration; \(a = 5.0m/s^2\)Distance traveled; \(s = 40m\)Time taken; \(t =\ ?\)To determine the time required for the ball to travel the given distance, we use the Second Equation of Motion:
\(s = ut + \frac{1}{2}at^2\)
Where s is distance traveled, u is initial velocity, a is acceleration and t is time taken.
We substitute our given values into the equation and solve for "t"
\(40m = [ 0*t ] + [ \frac{1}{2}\ *\ 5.0m/s^2\ *\ t^2 ]\\\\40m = 2.5m/s^2\ *\ t^2\\\\t^2 = \frac{40m}{2.5m/s^2}\\\\t^2 = 16s^2\\\\t = \sqrt{16s^2}\\\\t = 4s\)
Therefore, the time required for the ball to roll down the given distance is 4 seconds.
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How many of the alleles for blood type can be inherited from each parent?
Answer:
Two alleles can be inherited from each parent.
Answer:
Two alleles
Explanation:
Everyone gets one allele from each parent. Your two alleles determine your blood type.
What is all cells in a body that arent formed in a reproductive organ???
Explanation:
An organ is made of several types of tissue and therefore several types of cells. For example, the heart contains muscle tissue that contracts to pump blood, fibrous tissue that makes up the heart valves, and special cells that maintain the rate and rhythm of heartbeats.
Manipulate the mass of the puck by dragging the Mass bar to the right for increasing the mass and to the left for decreasing it. What changes do
you see in the speed of the puck? Which principle works behind this change?
Answer:
The positive charges point away from each other
Explanation:
Arrows point away from the positive charge and toward the negative charge.
Increasing the mass of the puck decreases its speed, while decreasing the mass increases its speed. This change is explained by the principle of conservation of momentum.
Explanation:When the mass of a puck is increased, its speed decreases, and when the mass is decreased, the speed increases. This is known as the principle of conservation of momentum, which states that the total momentum of a system remains constant when there is no external force acting on it. The momentum of an object is the product of its mass and velocity, so when the mass of the puck is increased, the momentum decreases, resulting in a decrease in speed. Similarly, when the mass is decreased, the momentum increases, leading to an increase in speed.
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What is the mass of a large ship that has a momentum of 1.60x10^9 kg*m/s and is moving at a velocity of 10m/s?
Answer:
160000000 kg.
Explanation:
p=mv
p=1.6x10^9
v=10m/s
rearrange and substitute:
(1.6x10^9)=m(10)
m=(1.6x10^9)/10
m= 1.6x10^8 kg.
suppose that requiring motorcycle riders to wear helmets reduces the probability of a motorcycle fatality from 0.3 percent to 0.2 percent over the lifetime of a motorcycle rider and that the cost of a lifetime supply of helmets is $500. it is efficient for the government to require riders to wear helmets if human life is valued at
The human life valuation based on the information is E. $500000 or more.
What is the human life valuation?It was illustrated that the motorcycle riders to wear helmets reduces the probability of a motorcycle fatality from 0.3 percent to 0.2 percent over the lifetime of a motorcycle rider.
Probability is the occurence of likely events. It is the area of mathematics that deals with numerical estimates of the likelihood that an event will occur or that a statement is true.
Since the cost of a lifetime supply of helmets is $500, the lifetime human life = = 500 / (0.3 - 0.2) × 100
= 500 / 0.1 × 100
= 5000 × 100
= 500000
The correct option is E.
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Complete question
Suppose that requiring motorcycle riders to wear helmets reduces the probability of a motorcycle fatality from 0.3 percent to 0.2 percent over the lifetime of a motorcycle rider and that the cost of a lifetime supply of helmets is $500. it is efficient for the government to require riders to wear helmets if human life is valued at:
A. $100 or more.
B. $150 or more
C. $500 or more.
D. $50000 or more.
E. $500000 or more.
A particle possessing 6.25 ?C of charge and mass 6.55 g is fired at a speed of 459 cm/s through two charged plates of length 34.6 cm, as shown in the figure. If the electric field is constant at 2060 N/C between the two plates* and directed upwards, calculate the distance y in which the charge falls below its intended path.
Which field strength will allow the particle to pass between the plates along a straight path.
Coulomb's law states that the force of attraction or repulsion between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Given, Charge
q = 6.25 × 10⁻⁶ C and mass
m = 6.55 g = 6.55 × 10⁻³ kg
Speed of the particle = v = 459 cm/s = 4.59 m/s
Length of the plates,
d = 34.6 cm = 0.346 m
Electric field strength,
E = 2060 N/C
Mathematically,
F ∝ Q₁Q₂/d²
The force on the charge q due to the electric field E is given by
F = Eq
Distance fallen by the particle is given
by = 1/2 gt²,
where g = acceleration due to gravity = 9.8 m/s²In the vertical direction, force on the charge F = mg
Since the charge falls below its intended path, the vertical component of the electric force is greater than the force due to gravity.
So,
we have
F = Eq = mg ⇒ qE = mg
⇒ y = 1/2 gt² = (qE/m) × (t²/2) = (qE/m) × [2y/g]²/2
⇒ y = [(qE/m) × (y/g)]²
⇒ y = (qE/mg)²/3 [∵ t = 2y/g]
Substituting the given values,
we gety = [(6.25 × 10⁻⁶ C × 2060 N/C) / (6.55 × 10⁻³ kg × 9.8 m/s²)]²/3= (1.233 × 10⁻²)²/3= 1.59 × 10⁻⁴ m = 1.59 × 10⁻² cm
Hence, the particle falls 1.59 × 10⁻² cm below its intended path.
Therefore, a field strength of 1.04 × 10⁴ N/C would allow the particle to pass through the plates along a straight path.
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Calculate the minimum height that 7.0 kg of water must fall to gain 1300 J of kinetic energy.
Explanation:
K=mgh\\1300=(7)(9.8)h\\h=19\ mK=mgh
1300=(7)(9.8)h
h=19 m
A wave that consists of a combination of electrical and magnetic energy is a(n):
a. magnoelectric wave
c. magnetolectric wave
b. electromagnetic wave
d. electrical-magnetic wave
miguel weighs 250 pounds and is trying to lose weight. he decides to start an exercise program and starts walking (2 mph) for 30 minutes, five days a week. this activity burns 0.044 kcal/kg body weight/minute. how many additional kilocalories will miguel burn each week with this exercise regime?
Miguel will burn an additional 750 kilocalories each week with this exercise regime. It's worth noting that in order to lose weight.
We first need to convert Miguel's weight from pounds to kilograms. One pound is equal to 0.453592 kilograms, so Miguel's weight is approximately 113.4 kilograms.
Next, we can calculate how many kilocalories Miguel will burn per minute by multiplying his weight in kilograms by the rate of calorie burn per minute:
0.044 kcal/kg body weight/minute * 113.4 kg = 5.0 kcal/minute
Miguel walks for 30 minutes, five days a week, so he will burn an additional:
5.0 kcal/minute * 30 minutes * 5 days = 750 kilocalories per week
Therefore, Miguel will burn an additional 750 kilocalories each week with this exercise regime. It's worth noting that in order to lose weight, Miguel will need to ensure that he is also consuming fewer kilocalories than he is burning overall, not just through exercise.
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