When light travels from less dense air to denser glass or water, it slows down. Slowing down of a ray of light changes the direction of the ray of light.
What is Ray of light?Light that travels in a straight line in one direction is called a ray of light. When a group of light emanates from a source, it is called a beam of light. A beam of light is defined as the path of a photon or a group of photons traveling through a space appearing as a column of light.
There are three types of light rays. They are
Incident raysReflected raysRefracted raysExample of a beam is a beam of light with a pass from a laser or laser pointer. A beam of light is made up of particles called photons that carry specific amounts of energy. We cannot measure the length of a beam.
Thus, when light travels from less dense air to denser glass or water, it slows down. Slowing down of a ray of light changes the direction of the ray of light.
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When a small amount of 12 M HNO3(aq) is added to a buffer solution made by mixing CH3NH2(aq) and CH3NH3Cl(aq) , the pH of the buffer solution changes from 10.64 to 10.62. Which of the following equations represents the reaction that accounts for the fact that the pH does not change significantly when the HNO3(aq) is added?
a. CH3NH2(aq) + H+(aq) â CH3NH3+(aq)
b. CH3NH3+(aq) + H+(aq) â CH3NH42+(aq)
c. NO3- (aq) + H+(aq) â HNO3(aq)
d. OH- (aq) + H+(aq) â H2O(l)
Answer:
a. CH3NH2(aq) + H⁺ → CH3NH3⁺
Explanation:
The mixture of a weak base as CH3NH2 with its conjugate acid CH3NH3Cl produce a buffer. As the weak acid is in equilibrium with water, the mixture of the weak base and its conjugate base produce that the acid or base released react avoiding the change in pH.
For example, when a strong acid as HNO3 reacts, the weak base will react producing the conjugate base, that is:
CH3NH2(aq) + H⁺ → CH3NH3⁺
Right answer is:
a. CH3NH2(aq) + H⁺ → CH3NH3⁺A 2 .4 liter container of hydrogen gas has a pressure of 0.5 atm, what volume would be necessary to decrease the pressure to 1.7 atm?
Answer:
0.7 L
Explanation:
Step 1: Given data
Initial volume of the container (V₁): 2.4 LInitial pressure of hydrogen gas (P₁): 0.5 atmFinal volume of the container (V₂): ?Final pressure of hydrogen gas (P₂): 1.7 atmStep 2: Calculate the final volume of the container
If we assume ideal behavior and constant temperature, we can calculate the final volume of the container using Boyle's law.
P₁ × V₁ = P₂ × V₂
V₂ = P₁ × V₁/P₂
V₂ = 0.5 atm × 2.4 L/1.7 atm = 0.7 L
Please answer my question.
Using standard thermodynamic data at 298K, the entropy changes of the environment when 1.59 mol of P₄O₁₀ (s) is irritated at standard conditions is - 45339.5 J/K
∆H°f product is the total enthalpy of standard formation based on the product substances. ∆H°f reactants is the total enthalpy of the standard formation based on the reactants.
We know:
∆H⁰f (P₄O₁₀) = - 2984 KJ/mol
∆H⁰f (H₂O) = - 285.8 KJ/mol
∆H⁰f (4H₃PO₄) = - 1288.3 KJ/mol
The e reaction is:
P₄O₁₀ (s) + 6H₂O (l) → 4H₃PO₄ (aq)
∆H⁰rxn = ∆H⁰f products - ∆H⁰f (reactants)
∆H⁰rxn = [4∆H⁰f (P₄O₁₀)] - [1 ∆H⁰f (P₄O₁₀) + 6 ∆H⁰f (H₂O)]
∆H⁰rxn = [4(- 1288.3)] - [ 1(- 2984) + 6(- 285.8)]
∆H⁰rxn = [ - 5153.2] - [ -11936 - 1714.8]
∆H⁰rxn = [- 5153.2] - [-13650.8]
∆H⁰rxn = - 5153.2 + 13650.8
∆H⁰rxn = 8497.6 KJ
Therefore, ∆H⁰rxn for this reaction is + 8497.6 KJ.
From the above-balanced chemical equation, we can write,
For the reaction of 1 mol of P₄O₁₀,
∆H⁰rxn value = + 8497.6 KJ
Then, for the reaction of 1.59 mol of P₄O₁₀, ∆H0rxn value
= + 8497.6 KJ/1 mol x 1.59 mol
= + 13511.184 KJ
We know,
∆S⁰surroundings = - ∆H⁰rxn/ T
Where,
∆S⁰surroundings = standard entropy changes of the surroundings
∆H⁰rxn = standard enthalpy changes of the reaction
T = temperature in Kelvin
Here,
∆H0rxn = 13511.184 KJ = 13511.184 x 10³ J = 13511184 J
T = 298 K
Now,
∆S⁰surroundings = - ∆H⁰rxn/ T
∆S⁰surroundings = - 13511184J/298 K
∆S⁰surroundings = - 45339.5 J/K
Therefore, the entropy changes for the surroundings when 1.59 mol of P₄O₁₀ reacts at standard conditions is - 45339.5 J/K
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"What is the % TDS Coffee if the refractive index, np, is 1.3384 and the
equation that relates refractive index to % TDS Coffee is
np = 0.00175 (% TDS Coffee) + 1.3342"
The relation between %TDS coffee and refractive index is given by the formula:
np = 0.00175 (% TDS Coffee) + 1.3342
In the given case
np = 1.3384
So, substituting the value of np in the equation above, we get:
1.3384 = 0.00174 (%TDS Coffee) + 1.3342
⇒ 1.3384 - 1.3342 = 0.00174 (%TDS Coffee)
⇒ 0.0042 = 0.00174 (%TDS Coffee)
⇒ (%TDS Coffee) = 0.0042/0.00174
⇒ %TDS Coffee = 2.4137
Hence the value of %TDS Coffee is 2.4137
What is Refractive Index?How much light is twisted or refracted when it enters a material depends on the material's refractive index. The intensity of the reflected light (determined by Fresnel's equations), the critical angle for total internal reflection, and Brewster's angle are all influenced by the refractive indices.The refractive index can be thought of as the parameter that reduces the speed and wavelength of the radiation relative to their vacuum values: the speed of light in a medium is v = c/n and the wavelength in that medium is = 0/n, where 0 is the wavelength of that light in vacuum.This assumes that the refractive index of vacuum is 1, and it also assumes that the refractive index has no impact on the wave's frequency (f = v/).To learn more about Refractive Index, refer to:
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HELP!⚠️ I’ll mark you as brainlist.
Caffeine is a bitter stimulate drug and is found in vary quantities. It’s formula is C8H10N4O2. Match the number of moles of each element found
• numbers are 1.2, 2.0, 4.0, 5.0, 8.0, 10, 16, 27
• There are ___ mol of nitrogen in 0.30 mol
• There are ___ mol of hydrogen in 2.7 mol caffeine
• There are ___ mol of carbon in 2.0 mol caffeine
• There are __ mol of oxygen in 2.5 mol of caffeine
Answer:
• There are 1.8 mol of nitrogen in 0.30 mol of caffeine.
• There are 21.6 mol of hydrogen in 2.7 mol of caffeine.
• There are 16.0 mol of carbon in 2.0 mol of caffeine.
• There are 5.0 mol of oxygen in 2.5 mol of caffeine.
Explanation:
CHEM FINAL TOMORROW, NEED IMMEDIATE HELP!!! There are a few topics I don't understand, if someone could give a short explanation of how to do these kinds of problems, it would help so much. I'll be posting a few more of these on my page, so feel free to check those out if you would like. Thanks!
The mass of \(O_2\) needed to produce 8.65 x \(10^{23\) atoms of silver is 22.96 grams.
Stoichiometric calculationIn the given balanced equation, it is stated that 2 moles of \(Ag_2O\) produce 4 moles of Ag and 1 mole of \(O_2\).
First, let's calculate the number of moles of Ag:
8.65 x \(10^{23\) atoms of Ag / (6.022 x \(10^{23\) atoms/mol) = 1.435 moles of Ag
Since 2 moles of \(Ag_2O\) produce 1 mole of \(O_2\), the number of moles of \(O_2\) needed is half of the moles of \(Ag_2O\).
Number of moles of \(O_2\)= 1.435 moles of \(Ag_2O\) / 2 = 0.7175 moles
Now, we'll use the molar mass of \(O_2\) to find the mass:
Molar mass = 32.00 g/mol
Mass of \(O_2\) = number of moles × molar mass
= 0.7175 moles × 32.00 g/mol = 22.96 g
Therefore, the mass of \(O_2\) needed to produce 8.65 x \(10^{23\) atoms of silver is 22.96 grams.
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Write the balanced molecular equation for the aqueous reaction of hydroiodic acid (HI) and zinc metal.
The balanced chemical equation is for the aqueous reaction of hydroiodic acid (HI) and zinc metal is Zn + 2HI → ZnI₂ + H₂.
What is Balanced Chemical Equation ?The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now write the balanced chemical equation
Zn + 2HI → ZnI₂ + H₂
Here Zn is a reducing agent, HI is an oxidizing agent.
Thus from the above conclusion we can say that The balanced chemical equation is for the aqueous reaction of hydroiodic acid (HI) and zinc metal is Zn + 2HI → ZnI₂ + H₂.
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What mass of copper would be deposited at the cathode if a current of 2.5 A flows through copper(II) sulfate solution for 51 minutes and 28 seconds?
1.28 g
2.56 g
5.12 g
10.24 g
a chemist mixed 3.2 h2 and 8.2n2, which one is the limiting reactant equation
The limiting reactant equation after the chemist's mixture is H₂.
How to determine limiting reactant?To determine the limiting reactant, we need to compare the moles of each reactant to their stoichiometric coefficients in the balanced chemical equation.
The balanced equation for the reaction between H₂ and N₂ is:
N₂+ 3H₂ → 2NH₃
From the problem, we have 3.2 moles of H₂ and 8.2 moles of N₂. We can use the coefficients from the balanced equation to calculate how many moles of NH₃ each reactant would produce if it completely reacted:
H₂: (3.2 mol H₂) × (2 mol NHH₃ / 3 mol H₂) = 2.13 mol NH₃
N₂: (8.2 mol N₂) × (2 mol NHH₃ / 1 mol N₂) = 16.4 mol NHH₃
The reactant that produces the smaller amount of product is the limiting reactant. In this case, H₂ produces 2.13 mol of NH₃, while N₂ produces 16.4 mol of NHH₃. Therefore, H₂ is the limiting reactant.
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a pharmaceutical company wants to extract an ingredient from pomace supplied by a certain food processing plant. which process is the most efficient with the lowest environmental impact
A. Catalyst extraction
B. High pressure, high temperature water extraction
C. Organic solvent extraction
D. Enzyme extraction
Answer: high pressure, high temperature water extraction
Explanation:
Answer:
C). high pressure, high temperature water extraction
Explanation:
HEY GUYS what has been the highlight of your day
Answer:
Earlier today, my friend got a call from the company where she had recently applied for a job. They informed her that she had been selected for an interview, which was scheduled for later this week. She was overjoyed and relieved to hear the news, as she had been searching for a job for several months and this was one of the positions she was most excited about. The call was definitely the highlight of her day, and it put her in a great mood for the rest of the afternoon! :) She immediately called her parents and friends to share the good news and celebrate!!
Some landforms you might see while traveling across the country could be
mountains
forests
hills
rivers
glaciers
Answer:
Mountains, Hills and Rivers
Explanation:
Because I read it and I already know that
Hope that helps!
Answer:
Mountains, Hills and Rivers
Explanation:
-. How many moles of Pb are contained in 2.49 x 1025 atoms Pb?
Answer: There are \(4.13 \times 10^{-3}\) moles of Pb are contained in \(2.49 \times 10^{25}\) atoms Pb.
Explanation:
According to the mole concept, 1 mole of every substance contains \(6.023 \times 10^{23}\) atoms.
Hence, number of moles present in \(2.49 \times 10^{25}\) atoms of Pb are as follows.
\(No. of moles = \frac{2.49 \times 10^{25}}{6.023 \times 10^{23}}\\= 4.13 \times 10^{-3} mol\)
Thus, we can conclude that there are \(4.13 \times 10^{-3}\) moles of Pb are contained in \(2.49 \times 10^{25}\) atoms Pb.
Part A
How many moles of water are needed to react with 1.7 moles of Li, O?
Given: Li2O + H202LiOH
1.7
0.85
3.4
1.5
none of the above
Answer:1.7
Explanation:
What is the pH of a solution that is 0.21 M sodium fluoride and 0.57 M hydrofluoric acid?
The pH of a solution that is 0.21 M sodium fluoride and 0.57 M hydrofluoric acid is 3.36.
given the data as follows :
sodium fluoride ( base ) = 0.21 M
hydrofluoric acid ( acid )= 0.57 M
using the Henderson - Hassel Balch equation we get:
pH = pKa + log (base / acid)
pKa of hydrofluoric acid = 3.8
∴ pH = 3.8 + log ( 0.21 / 0.57 )
pH = 3.8 + ( - 0.4341)
pH = 3.36
Thus, The pH of a solution that is 0.21 M sodium fluoride and 0.57 M hydrofluoric acid is 3.36.
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Step 1: She pours a colorless solution into a beaker that contains another colorless liquid. Yellow particles appear in the liquid.
Step 2: She lets the yellow particles settle in the beaker and then separates the colorless liquid by decantation.
What has most likely occurred in the beaker?
a chemical change in step 1 and a physical change in step 2
a physical change in step 1 and a chemical change in step 2
chemical changes in both step 1 and step 2
physical changes in both step 1 and step 2
It is most likely Option A: that a chemical change occurred in step 1 and a physical change occurred in step 2.
What is the chemical change?In step 1, the yellow particles appeared in the liquid, indicating a chemical change. This could be a result of a chemical reaction between the two colorless liquids, or the addition of a reagent that caused a reaction. This change is characterized by the formation of new substances, which are the yellow particles.
In step 2, the colorless liquid was separated from the yellow particles by decantation. Decantation is a physical process that separates immiscible liquids or solid particles from a liquid by allowing them to settle and then carefully pouring off the liquid.
Therefore, This change is characterized by the separation of components of a mixture, no new substances are formed.
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Sulfur has 6 valence electrons.
Which element could pair with it
in a 1 atom : 1 sulfur ratio?
Answer:
Any Group 2A element (Be, Mg, Ca, Sr, Ba, Ra)
Explanation:
According to the Octet Rule, Sulfur would want to gain two electrons in its outermost shell to achieve an octet (8 total electrons). The elements that could accomplish this in a one-to-one ratio would be Group 2A on the periodic table (alkaline earth metals).
There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, alkaline earth metals are the suitable elements.
What is chemical Compound?Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.
An ionic compound is a metal and nonmetal combined compound. Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.
The compound that is ionic in nature can be dissociated very easily in water. Since ionic compounds are polar in nature, they readily dissolve in water. The elements that could accomplish this in a one-to-one ratio would be alkaline earth metals
Therefore, alkaline earth metals are the suitable elements.
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Dwight made this model using a golfball, a baseball, and a basketball
How could Dwight improve his model?
Group of answer choices
Make the moon smaller than the earth
Place the sun between the Earth and the moon
Place Earth between the moon and the sun
Use a flat object, such as a coin, to represent the objects
He could improve the model if he place Earth between the moon and the sun.
What is the model?We know that the solar system is composed of the sun and the planets and we can have a model of the solar system when we get together the sun and the other parts of the solar system as has been done in the model that was put together by Dwight .
Since the model was intended to show the eclipse of the moon then the model can be improved if he place Earth between the moon and the sun in the image of the model
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aluminum + sulfur aluminum sulfide
10.8 g 19.2 g (REACTANT/PRODUCT)??
Answer:
Al + S -> Al2S3
Al and S are the reactants, Al2S3 is the product
Explanation:
Mg metal was burned in a inverted beaker of air suspended over a tank of water. There was originally 300ml of air and after burning there was only 254ml of air remaining. If oxygen makes up 20.95% of air then how much Mg was reacted with oxygen?
The mass of magnesium that reacted with oxygen as determined from the moles of reactants is is 0.01 g.
How many moles of oxygen took part in the reaction with magnesium metal?
The number of moles of oxygen that took part in the reaction with magnesium metal is determined from the volume of oxygen that reacted with the magnesium metal.
The volume of oxygen that reacted with magnesium metal is determined as follows:
The volume of air that reacted with magnesium metal = initial volume - final volume
The volume of air that reacted with magnesium metal = 300 mL - 254 mL
Volume of air = 46 ml
Volume of oxygen in the air = 46 * 20.95%
Volume of oxygen in the air = 9.64 mL
Moles of oxygen = 9.64 * 1 mol/22400 mL
Moles of oxygen = 0.00043 moles
Moles of oxygen = moles of Mg
Moles of Mg = 0.00043
Mass of Mg = 0.00043 moles * 24 g/mol
Mass of Mg = 0.01 g
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Match the term with the example that shows its definition.
Match Term Definition
Compressibility A) Gas is squeezed into a small container
Flammability B) Sodium easily combines with chlorine to make salt
Heat of combustion C) The burning of coal releases a lot of heat
Reactivity D) Gasoline catches fire
Compressibility --- A) Gas is squeezed into a small container
Reactivity --- B) Sodium easily combines with chlorine to make salt
Heat of combustion --- C) The burning of coal releases a lot of heat
Reactivity --- D) Gasoline catches fire.
What is compressibility?Compressibility is the measure of how much a volume changes when pressure is applied on the gas or liquid substance. In other words we can say that Compressibility is defined as a measure of the volume change of a fluid or solid in response to change in pressure.
So we can conclude that Compressibility --- A) Gas is squeezed into a small container
Reactivity --- B) Sodium easily combines with chlorine to make salt
Heat of combustion --- C) The burning of coal releases a lot of heat
Reactivity --- D) Gasoline catches fire.
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List the color of the stars from hottest to lowest:
Answer:
Blue 25,000 K
White 10,000 K
Yellow 6000 K
Orange 4000 K
Red 3000 K
Explanation:
k = kelvin
8. A rock dropped in a graduated cylinder raises the level of water from 20 mL to 35 mL.
The rock has a mass of 45 g. What is the density of the rock?
Answer:
3.0 g/cm\(3\)
Explanation:
وزن الملي مكافئ لحامض الخليك
Answer:
hshssytdtctdyeheb
Explanation:
yye6d66d6d6dududyydydydyehwj2
what mass of glucose c6h12o6 would be required to prepare 5000 mL of a 0.215 M solution
Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.
To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, let's convert the volume of the solution from milliliters (mL) to liters (L):
5000 mL = 5000/1000 = 5 L
Now, we can rearrange the formula to solve for moles of solute:
moles of solute = Molarity (M) x volume of solution (L)
moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol
Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:
mass of solute = moles of solute x molar mass of solute
mass of glucose = 1.075 mol x 180.16 g/mol
mass of glucose = 194.0 g (rounded to three significant figures)
Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.
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Animal fats and vegetable oils are triacylglycerols, or triesters, formed from the reaction
of glycerol (1, 2, 3-propanetriol) with three long-chain fatty acids. One of the methods
used to characterize a fat or an oil is a determination of its saponification number. When
treated with boiling aqueous KOH, an ester is saponified into the parent alcohol and fatty
acids (as carboxylate ions). The saponification number is the number of milligrams of
KOH required to saponify 1.000 g of the fat or oil. In a typical analysis, a 2.085-g sample
of butter is added to 25.00 mL of 0.5131 M KOH. After saponification is complete, the
excess KOH is back titrated with 10.26 mL of 0.5000 M HCl. What is the saponification
number for this sample of butter?
Saponification number = (V × M × F × 56.1) / W
Where:
V = volume of HCl used in the back titration
M = molarity of HCl
F = factor of KOH (which is 1 for pure KOH)
W = weight of the butter sample used in grams
First, we need to calculate the amount of KOH used in the saponification reaction:
0.5131 M KOH = 0.5131 moles KOH / liter
25.00 mL KOH = 0.02500 L KOH
moles KOH used = 0.5131 moles/L × 0.02500 L = 0.0128 moles KOH
Since the saponification reaction is a 1:1 reaction between KOH and the triacylglycerol in the butter sample, the amount of butter used is also 0.0128 moles.
Next, we need to calculate the amount of HCl that reacted with the excess KOH:
0.5000 M HCl = 0.5000 moles HCl / liter
10.26 mL HCl = 0.01026 L HCl
moles HCl used = 0.5000 moles/L × 0.01026 L = 0.00513 moles HCl
Since the reaction between HCl and KOH is also a 1:1 reaction, the moles of KOH that were not used in the saponification reaction is equal to the moles of HCl used in the back titration:
moles KOH not used = moles HCl used = 0.00513 moles HCl
To find the saponification number,
Saponification number = (V × M × F × 56.1) / W
Saponification number = (0.01026 L × 0.5000 moles/L × 1 × 56.1) / 2.085 g
Saponification number = 6.50
Therefore, the saponification number for this sample of butter is 6.50.
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Asphalt, like the desert, ___ the sun's energy, causing higher temperatures
A.absorbs
B.reflects
Answer: A. absorbs
Explanation:
Select all answer choices that would result in units of moles.
a) RT/PV
b) PV/RT
c) mass ÷ molar mass
d) molar mass ÷ mass
e) molar mass × mass
f) molarity ÷ volume
g) volume ÷ molarity
h) molarity × volume
The correct options that will result in mole are option B, C, and H
How do i know which options will result in mole?To know the options that will result in mole, do the following:
Ideal gas law states as follow:
PV = nRT
Where
P is the pressure V is the volumen is the number of moleR is the gas constantT is the temperaturePV = nRT
Make n the subject by dividing both sides by RT
n = PV / RT (option B)
Mole, mass and molar mass are related according to the following formula:
Mole = mass / molar mass (option C)
Molarity is defined as mole per unit volume as shown below:
Molarity = mole / volume
Make mole the subject by cross multiplying.
Mole = Molarity × volume (option H)
Thus, from the above illustrations, we can conclude that the correct options which will result in mole are option B, C, and H
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the number of valence electrons present in metal are
Answer: Valency
Explanation:
Who has course hero?I really need the “lion king…Ecology science.” Answer key so I can print it.It wont let me print mines.
Note that the above prompt on Ecology draws it's analysis form a well known story which have been told visually called "The Lion King".
The answers are:
1) Biotic Factors, simply put are living things
2 examples of things from Lion King Introduction are:
3) Abiotic factors are Non -living things.
4) Examples from the introduction are:
MountainWaterDirt5) the symbiotic relationship is called: commensalism.
What is commensalism?Long-term biological interactions known as commensalism occur when individuals of one species benefit while those of the other species suffer neither advantages nor harm.
Ecology which is the study of the environment, allows a person to comprehend how different types of creatures coexist in various kinds of physical settings.
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Full Question:
Although part of your question is missing, you might be referring to this full question:
1) What is Biotic Factors
2) List three biotic factors from the Lion King introduction
3) What is Abiotic factors?
4) List three Abiotic factors from the Lion King introduction
5) The bird riding on the tusks of the elephant feed on insects the elephant stirs up. What kind of symbiotic relationship exists between the two?