a student performed the following steps to find the solution to the equation . where did the student go wrong? step 1. factor the polynomial into (x 8) and (x – 6) step 2. x 8

a. Percentage of overweight girls = 7.29%

b. Percentage of overweight boys = 12.60%

c. Percentage of overweight students = 9.8% .

The percentage is depicted as a ratio represented as a fraction of a hundred.

a) To calculate the percentage of girls that are overweight, we need to divide the number of overweight girls (31) by the total number of girls (425) and then multiply by 100 to get the percentage:

Percentage of overweight girls = (31/425) x 100% = 7.29%

b) To calculate the percentage of boys that are overweight, we need to divide the number of overweight boys (48) by the total number of boys (381) and then multiply by 100 to get the percentage:

Percentage of overweight boys = (48/381) x 100% = 12.60%

c) To calculate the percentage of all students that are overweight, we need to add up the number of overweight girls and boys (31+48 = 79) and divide by the total number of students (425+381 = 806) and then multiply by 100 to get the percentage:

Percentage of overweight students = (79/806) x 100% = 9.8% (rounded to one decimal place)

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Answer:

9 +/- 13 or

22 or -4

Step-by-step explanation:

5x^2 - 90x - 475 = -35

5x^2 - 90x - 440 = 0

plug into quadratic formula

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

The piecewise function for this problem is defined as follows:

A piece-wise function is a function that has different definitions, depending on the input of the function.

Between x = -3 and x = -1, the linear function has a slope of 1, with a x-intercept of -3, meaning that the parent function y = x was shifted left 3 units, hence it is given as follows:

f(x) = x + 3, -3 ≤ x < -1

Between x = -1 and x = 1, the function is constant at y = 5, hence it is given as follows:

f(x) = 5, -1 ≤ x ≤ 1.

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Answer:

\(Length = Width = 6\ units\)

Step-by-step explanation:

Given

\(Area=36\)

Required

The least possible material

Sandboxes usually, are rectangles or squares.

Using the above assumption, the area is calculated as:

\(Area= Length * Width\)

\(Area= L* W\)

\(L * W = 36\)

Make L the subject

\(L = \frac{36}{W}\)

The material of the outer edge is calculated by the perimeter.

\(Perimeter = 2 * (L +W)\)

\(P = 2 * (L + W)\)

Substitute \(L = \frac{36}{W}\)

\(P = 2 * (\frac{36}{W} + W)\)

Open bracket

\(P = \frac{72}{W} + 2W\)

\(P = 72W^{-1} +2W\)

To get the minimum material needed, we differentiate P

\(P' = -72W^{-2} + 2\)

Set: \(P' = 0\)

\(-72W^{-2} + 2 = 0\)

Collect like terms

\(72W^{-2} = 2\)

Divide both sides by 72

\(W^{-2} = \frac{2}{72}\)

\(W^{-2} = \frac{1}{36}\)

Rewrite as:

\(\frac{1}{W^2} = \frac{1}{36}\)

Take positive square roots of both sides

\(\frac{1}{W} = \frac{1}{6}\)

Cross multiply

\(W = 6\)

Recall that: \(L = \frac{36}{W}\)

So, we have:

\(L =\frac{36}{6}\)

\(L = 6\)

Hence, the dimension with the littlest material as possible is:

\(Length = Width = 6\ units\)

Answer:

THEY ARE NOT LIKE  TERMS－O－

\(\boxed{Average\:speed=\frac{Total\:distance}{Total\:time\:taken}}\)

\(\bold{\underline{\underline{As\:we\:know\:all\:the\:units\:are\:in\:hr}}}\)

\(\rm{So,40\:minutes=\frac{40}{60}=\frac{2}{3}}\)

\(\sf{\underline{\underline{Now,putting\:values\:in\:the\:given\:formula:}}}\)

\(\rm{21km/h=\frac{Distance}{\frac{2}{3}}}\)

\(\rm→{21×\frac{2}{3}=Distance}\)

\(\rm{→14=Distance}\)

\( \large{ \underline{ \overline{ \mid{ \rm{ \red{Answer→Distance=14\:\:km}} \mid}}}}\)

Answer:

\(we \: have \: avarage \: speed= \frac{distance}{time \: } \\ here \: time \: is \: in \: \: minute \: convert \: \\ it \: in \: to \: hour \\ so \: \frac{40}{60} \: hour \\ = \frac{2}{3} hour \\ distance = avarage \: speed \times time \\ = 21 \times \frac{2}{3} = 7 ×2 = 14km\\ thank \: you\)

Answer:

See picture for explanation.

Step-by-step explanation:

Answer:

1)36

2)1/36

Step-by-step explanation:

Hope it can help you lovelots

Here are the values of f(1), f(2), f(3), f(4), and f(5) for each recursive definition:

a) \(\[f(1) = -6, \quad f(2) = 12, \quad f(3) = -24, \quad f(4) = 48, \quad f(5) = -96\]\)

b) \(\[f(1) = 16, \quad f(2) = 55, \quad f(3) = 172, \quad f(4) = 523, \quad f(5) = 1576\]\)

c) \(\[f(1) = 1, \quad f(2) = -3, \quad f(3) = 11, \quad f(4) = 107, \quad f(5) = 11365\]\)

d) \(\[f(1) = 3, \quad f(2) = 3, \quad f(3) = 3, \quad f(4) = 3, \quad f(5) = 3\]\)

a) Recursive definition: \(\(f(n + 1) = -2f(n)\)\)

To find \(\(f(1)\)\), we use the initial condition \(\(f(0) = 3\)\) and apply the recursive definition:

\(\[f(1) = -2f(0) = -2 \cdot 3 = -6\]\)

To find \(\(f(2)\)\):

\(\[f(2) = -2f(1) = -2 \cdot (-6) = 12\]\)

Similarly, we can continue applying the recursive definition to find \(\(f(3)\), \(f(4)\), and \(f(5)\)\):

\(\[f(3) = -2f(2) = -2 \cdot 12 = -24\]\)

\(\[f(4) = -2f(3) = -2 \cdot (-24) = 48\]\)

\(\[f(5) = -2f(4) = -2 \cdot 48 = -96\]\)

b) Recursive definition: \(\(f(n + 1) = 3f(n) + 7\)\)

Using the initial condition \(\(f(0) = 3\):\)

\(\[f(1) = 3f(0) + 7 = 3 \cdot 3 + 7 = 16\]\)

To find \(\(f(2)\)\):

\(\[f(2) = 3f(1) + 7 = 3 \cdot 16 + 7 = 55\]\)

Continuing in the same manner:

\(\[f(3) = 3f(2) + 7 = 3 \cdot 55 + 7 = 172\]\)

\(\[f(4) = 3f(3) + 7 = 3 \cdot 172 + 7 = 523\]\)

\(\[f(5) = 3f(4) + 7 = 3 \cdot 523 + 7 = 1576\]\)

c) Recursive definition: \(\(f(n + 1) = f(n)^2 - 2f(n) - 2\)\)

Using the initial condition \(\(f(0) = 3\)\)

\(\[f(1) = f(0)^2 - 2f(0) - 2 = 3^2 - 2 \cdot 3 - 2 = 1\]\)

To find \(\(f(2)\):\)

\(\[f(2) = f(1)^2 - 2f(1) - 2 = 1^2 - 2 \cdot 1 - 2 = -3\]\)

Continuing in the same manner:

\(\[f(3) = f(2)^2 - 2f(2) - 2 = (-3)^2 - 2 \cdot (-3) - 2 = 11\]\)

\(\[f(4) = f(3)^2 - 2f(3) - 2 = 11^2 - 2 \cdot 11 - 2 = 107\]\)

\(\[f(5) = f(4)^2 - 2f(4) - 2 = 107^2 - 2 \cdot 107 - 2 = 11365\]\)

d) Recursive definition: \(\(f(n + 1) = \frac{{3f(n)}}{3}\)\)

Using the initial condition \(\(f(0) = 3\):\)

\(\[f(1) = \frac{{3f(0)}}{3} = \frac{{3 \cdot 3}}{3} = 3\]\)

Since the recursive definition is \(\(f(n + 1) = \frac{{3f(n)}}{3}\)\), the value of \(\(f(n)\)\) remains constant as 3 for all values of \(\(n\)\). Hence,  \(\(f(2)\), \(f(3)\), \(f(4)\),\)  \(\(f(5)\),\) the value will be 3.

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The equations are equal at x = -0.25

An equation is a statement of two expressions, where the expressions are connected by an equal sign.

Given are two equations, y = x³ + 5x + 1 and y = x. we have to find that at which value of x do the equations are equal.

y = x³ + 5x + 1.......(i)

y = x......(ii)

Using eq(ii) in eq(i), we get,

x³ + 5x + 1 = x

x³ + 4x + 1 = 0

x(x²+2) + 1 = 0

Here, we have to find a value of x which satisfy the above equation, (plotting the graph we get x = -0.25)

Therefore, put x = -0.25, we get,

-0.25[(-0.25)²+2]+1

= -0.25×2.0625+1

≈ 0

Hence, the value of x where the equation are equal is x = -0.25

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Answer:

B. the greatest common factor of 10 and 15 is 5.

Step-by-step explanation:

A. is worg 14 cannot be divided by 5

C. is wrong 13 cannot be divided by 3

D. is wroing 14 cannot be divided by 3

I mean they all can but you won't get the whole numbers only fractions.

Option B

Let's check each option one by one.

A) The greatest common factor of 10 and 14 is 5.

Write down the factors of 10 and 14.

⇒ Factors of 10: 1, 2, 5, 10

⇒ Factors of 14: 1, 2, 7, 14

We can see here that the GCF is "1" as it is the greatest factor of 10 and 14.

Hence, option A is incorrect.

B) The greatest common factor of 10 and 15 is 5.

Write down the factors of 10 and 15.

⇒ Factors of 10: 1, 2, 5, 10

⇒ Factors of 15: 1, 3, 5, 15

We can see here that the GCF is "5" as it is the greatest factor of 10 and 15.

Hence, option B is correct.

C) The greatest common factor of 13 and 21 is 3.

Write down the factors of 13 and 21.

⇒ Factors of 13: 1 and 13

⇒ Factors of 21: 1, 3, 7, 21

We can see here that the GCF is "1" as it is the greatest factor of 13 and 21.

Hence, option C is incorrect.

D) The greatest common factor of 14 and 21 is 3.

Write down the factors of 14 and 21.

⇒ Factors of 14: 1, 2, 7, 14

⇒ Factors of 21: 1, 3, 7, 21

We can see here that the GCF is "7" as it is the greatest factor of 14 and 21.

Hence, option D is incorrect.

Thus, Option B is correct.

The term "income" refers to the money that an individual earns or receives in exchange for their work or services.

In this case, the panhandler is making $15 to $20 per day on the streets, which can be considered his income. The terms "prestige," "status," and "wealth" are not relevant in this context.
                                             A panhandler who makes $15 to $20 per day on the streets and you want to know whether this is his A) wealth, B) income, C) status, or D) prestige.

The answer is B) income. The money a panhandler makes per day can be considered his daily income.

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The length of the rectangle is, 12 miles and the width is, 6 miles.

What is the dimensions of rectangle?

Two dimensions make up a rectangle: the length and, perpendicular to that, the breadth (width). A triangle's or an oval's interior likewise has two dimensions.

Given: The width of the rectangle is 6 miles less than the length.

Suppose the length of the rectangle is x.

Then width is x - 6.

Also given that the area of the rectangle is 72 miles.

Since,

Area of rectangle = length x width

72 = x(x - 6)

72 = x^2 - 6x

x^2 - 6x - 72 = 0

x^2 - 12x + 6x - 72 = 0

x(x - 12) + 6(x - 12) = 0

(x + 6)(x - 12) = 0

x + 6 = 0,    x - 12 = 0

So, x = -6,  x = 12.

Since the length will not be negative.

Therefore, x = 12.

Hence length = 12 miles

width = 12 - 6 = 6 miles.

Therefore, the length of the rectangle is 12 miles and the width is 6 miles.

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Answer:

A

Step-by-step explanation:

w has to be lower so we would use

<

since 2000 has to be higher

W < 2000

Answer: 2 red balloons and 4 white balloons in each bunch

Step-by-step explanation:

divide 16/8 = 2 balloons in each bunch

divide 32/8 = 4 balloons in each bunch

Answer:

technically speaking true bc you didn't say if it was a right triangle but I'm going with false intuition speaking

If a fair coin is flipped several times until it lands on heads and the likelihood of such outcome is 50%, the probability of the coin landing on heads for the first time is 1/8.

There are four primary categories of probability: classical, empirical, subjective, and axiomatic. Since possibility and probability are equivalent, you may define probability as the likelihood that a specific event will occur.

given

A fair coin is repeatedly flipped until it comes up heads.

The coin is impartial.

On the third try, we need to calculate the likelihood of the first landing being on heads.

We are aware that each flip of a fair coin is independent of the others, and that each effort results in P(H) = P(T) = 0.5.

Required probability is the likelihood that the third attempt's first landing will be on heads.

= Chance of (I two trials result in tail and third result in head)

=P(I head) P(II head) P(III tail) (since each trial is independent)

= ( 1 /2 ) (1/2)(1/2) = (1/8 )

If a fair coin is flipped several times until it lands on heads and the likelihood of such outcome is 50%, the probability of the coin landing on heads for the first time is 1/8.

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Answer:

16.76 ft³

----------------------------------------------------------------------------------------------------------

Set up the system of equations for volume. We'll use V for volume, and h for height.

\(V = \pi r^2 \frac{h}{3}\)

Now, turn the equations into a multiplication problem, use 2 for radius, and 4 for height.

\(\pi * 2 * \frac{4}{3}\)

Next, calculate.

\(\pi *2^2 = 12.5663706144...\\\frac{4}{3} = 1.3333333...\\\\12.566 * 1.333 = 16.75048(rough~estimate)\)

----------------------------------------------------------------------------------------------------------

Ask in comments.

Answer: 100

Step-by-step explanation:

Answer:

  C.  142°

Step-by-step explanation:

You want the angle between vectors u=3i+√3j and v=-2i-5j.

There are a number of ways the angle between the vectors can be found. For example, the dot-product relation can give you the cosine of the angle:

  u•v = |u|·|v|·cos(θ) . . . . . . where θ is the angle of interest

You can find the angles of the vectors individually, and subtract those:

  u = |u|∠α

  v = |v|∠β

  θ = α - β

When the vectors are expressed as complex numbers, the angle between them is the angle of their quotient:

  \(\dfrac{\vec{u}}{\vec{v}}=\dfrac{|\vec{u}|\angle\alpha}{|\vec{v}|\angle\beta}=\dfrac{|\vec{u}|}{|\vec{v}|}\angle(\alpha-\beta)=\dfrac{|\vec{u}|}{|\vec{v}|}\angle\theta\)

This method is used in the calculation shown in the first attachment. The angle between u and v is about 142°.

A graphing program can draw the vectors and measure the angle between them. This is shown in the second attachment.

__

Additional comment

The approach using the quotient of the vectors written as complex numbers is simply computed using a calculator with appropriate complex number functions. There doesn't seem to be any 3D equivalent.

The dot-product relation will work with 3D vectors as well as 2D vectors.

<95141404393>

The measurements are represented by lengths of a triangle's sides by -

The triangle's three sides must satisfy the following condition:

"The total of any two triangle sides must be larger than or equal here to third side of the triangle."

We have four options in this question, so we'll go through them one at a time.

Since (1+3)<7  in this case, a triangle cannot be formed.

Since (3+3)<7 in this case, a triangle cannot be formed.

In this instance, (3+7)>8, (3+8)>7, and ((7+8)>3

Thus, a triangle will be formed by these.

In this instance, (3+5)>7, (3+7)>5, and (5+7)>3

Thus, a triangle will be formed by these.

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The options for the question are attached.

Solve for u using the equation -7u - 5 = 2

Now that we know the value of u, substitute it to the expression 2u + 7.

The uncertainties ⟨Δx^2⟩ and ⟨Δp^2⟩ are given by the expressions ⟨Δx^2⟩ = a^2/2 and ⟨Δp^2⟩ = (ℏ^2)/(8a^2).

To calculate the uncertainties ⟨Δx^2⟩ and ⟨Δp^2⟩ for the given wave packet, we need to find the expectation values of the observables (x^ - ⟨x⟩)^2 and (p^ - ⟨p⟩)^2, respectively.

The wave packet is represented by the function ψ(x) = [2πa^2]^(1/2) exp[-4a^2(x - ⟨x⟩)^2 + iℏpx]. Here, a is a constant, ⟨x⟩ represents the expectation value of x, and p is the momentum operator.

To find ⟨Δx^2⟩, we calculate the expectation value of (x^ - ⟨x⟩)^2 with respect to ψ(x). By integrating (x - ⟨x⟩)^2 multiplied by the squared magnitude of the wave packet over all x values, we obtain the result ⟨Δx^2⟩ = a^2/2.

Similarly, to find ⟨Δp^2⟩, we calculate the expectation value of (p^ - ⟨p⟩)^2 with respect to ψ(x). Since p is the momentum operator, its expectation value is ⟨p⟩ = 0 for the given wave packet. By integrating (p^ - 0)^2 multiplied by the squared magnitude of the wave packet over all x values, we obtain the result ⟨Δp^2⟩ = (ℏ^2)/(8a^2).

Therefore, the uncertainties ⟨Δx^2⟩ and ⟨Δp^2⟩ are given by the expressions ⟨Δx^2⟩ = a^2/2 and ⟨Δp^2⟩ = (ℏ^2)/(8a^2).

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The distance of the given point P from the plane would be \(\frac{-1}{\sqrt{6}}, \frac{-5}{\sqrt{6}},and, \frac{2}{\sqrt{6}}.\)

What is a plane?

A plane is a two-dimensional Euclidean surface that extends indefinitely in mathematics. A plane is a two-dimensional equivalent of a point, a line, and a three-dimensional space.

The given point P is P(-2, -1, 1) and the plane coordinates are [4, -1, 6].

Then the distance will be

                                \(= \frac{-2.4+(-1*-1)+1.6}{\sqrt{(-2)^2+(-1)^2+1^2}}\\\\ =\frac{-1}{\sqrt{6} }\)

Now the distance of a point P from the plane t[1, 6, 3]

                                  \(= \frac{-2.1+(-1*6)+1.3}{\sqrt{(-2)^2+(-1)^2+1^2}}\\\\ =\frac{-5}{\sqrt{6} }\)

Now the distance of a point P from the plane [-2, 3, 1]

                                   \(= \frac{-2.-2+(-1*3)+1.1}{\sqrt{(-2)^2+(-1)^2+1^2}}\\\\ =\frac{2}{\sqrt{6} }\)

hence, the distance would be \(\frac{-1}{\sqrt{6}}, \frac{-5}{\sqrt{6}},and, \frac{2}{\sqrt{6}}.\)

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for brainliest

Answer:

h=(3v)/(pi r^2)

Step-by-step explanation:

you simply have to move everything to one side.

Answer:

h = \(\frac{3V}{\pi r^2}\)

Step-by-step explanation:

Given

V = \(\frac{1}{3}\)πr²h ( multiply both sides by 3 to clear the fraction )

3V = πr²h ( isolate h by dividing both sides by πr² )

\(\frac{3V}{\pi r^2}\) = h

Numbers of ways to distribute 10 identical cards into 3 boxes is 36

Combination is is a way of selecting items from a collection where the order of selection does not matter.

Formula of combination:

Let a x-combination of a set is a subset of x distinct elements of S. If the set has n elements, the number of x-combinations is equal to the binomial coefficient.

ⁿCₓ = n(n-1)(n-2)(n-3). . . (n-x+1) / (x-1)(x-2)(x-3) . . . .(1)

which can be written as ⁿCₓ = n! / (n-x)! x!   , when n > x

ⁿCₓ = 0 , when n < x

Where n = distinct object to choose from

C = Combination

x = spaces to fill

According to the question,

Number of identical cards : n =10

Number of box cards are being distributed : x = 3

Number of ways to distribute when no condition is given : ⁿ⁺ˣ⁻¹Cₓ₋₁

If we place one one card in each box then

Number of cards left with us = 10 - 3

= 7

Now, condition of at least one cards in each box is satisfied ,

Then total number of ways to distribute 7 cards into 3 =  ⁷⁺³⁻¹C₃₋₁

=> ⁹C₂ = 9! / (9 - 2)! 2!

=>  9×8×7! / 7!2!

=> 9×8/2

=> 9×4

=>36 ways

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