According to the general procedure of Experiment A2b, 213 mg of (E)-stilbene (180. 25 g/mol) was reacted with 435 mg of pyridinium bromide perbromide (319. 82 g/mol) to afford 342 mg of meso-stilbene dibromide (340. 05 g/mol) as a white solid. Calculate the percent yield for this reaction. Enter your answer as digits only (no units), using the proper number of significant figures

The molarity of the hydrochloric acid solution in the reaction between NaOH and HCl, 1 mole of NaOH reacts with 1 mole of HCl. 1 NaOH + 1 HCl → 1 NaCl + 1 H2O (Mole ratio of NaOH to HCl is 1:1) • The concentration of the NaOH was 0.1 M, or 0.1 moles/liter.

What is molarity?

Molarity (M) is the quantity of a substance in a given extent of solution. Molarity is described because the quantity of moles of solute consistent with liter of solution. Molarity is likewise known as the molarity of a solution.

Therefore, The molarity of the hydrochloric acid solution in the reaction between NaOH and HCl, 1 mole of NaOH reacts with 1 mole of HCl. 1 NaOH + 1 HCl → 1 NaCl + 1 H2O (Mole ratio of NaOH to HCl is 1:1) • The concentration of the NaOH was 0.1 M, or 0.1 moles/liter.

To learn more about molarity refer the given link:-
https://brainly.com/question/14591804
#SPJ4

The most appropriate research agenda for my community would be focusing on how to reduce poverty and increase economic opportunities.

This would involve researching the current economic conditions in my community, identifying areas where poverty is most prevalent, and exploring potential solutions to create more jobs and increase economic mobility.

Additionally, this may involve researching the effectiveness of government programs and initiatives in the area, as well as exploring potential partnerships with local businesses and organizations to create new economic opportunities.

For more question on research click on

https://brainly.com/question/3628862

#SPJ11

Increasing the starting pressure of NO2 in the reaction CO(g) + NO2(g) → CO2(g) + NO(g) with rate law rate = k[NO2] will result in a four-fold increase in the reaction rate.

If the rate law for the reaction CO(g) + NO2(g) → CO2(g) + NO(g) is given as rate = k[NO2], it indicates that the rate of the reaction is directly proportional to the concentration of NO2. Since the concentration of a gas is directly related to its partial pressure, an increase in the partial pressure of NO2 will result in an increase in the concentration of NO2 and, consequently, an increase in the reaction rate.

In this case, if the starting pressure of NO2 is increased from 0.25 atm to 1.0 atm, the rate of the reaction will increase by 4-fold. This is because the four-fold increase in the partial pressure of NO2 leads to a corresponding increase in the concentration of NO2, resulting in a proportional increase in the reaction rate.

It is important to note that the reaction rate is determined by the concentrations or partial pressures of the reactants, as described by the rate law. By manipulating the concentrations or pressures of the reactants, we can control the rate of the reaction. In this particular case, increasing the pressure of NO2 results in a proportional increase in the rate of the reaction.

To know more about partial pressure

https://brainly.com/question/13199169

#SPJ11

Answer:

a the concentration of hydrogen gas decreases

Explanation:

Zn +HCl ---) ZnCl +H evolves

Answer:

the fossils on some of the continents were in the same spots as fossils on other continents

Explanation:

tell me if i need to explain more. x

Answer:

Ionization energy : energy required to take out an electron from the valance orbital of an atom.

Electron affinity: electron affinity of an atom measures the amount of energy released when an electron is forcibly entered or pushed into the valence orbital of an atom.

Ionization energy is the energy required to make an atom into a positive ion. Electron affinity is the energy released when an atom becomes a negative ion.

ionization energy is what is required to remove one electron from a normal gaseous atom to produce a +1 anion of that atom.

electron affinity is the energy required to remove one electron from a gaseous -1 anion of an atom to produce a normal gaseous atom.

Answer:

true

Explanation:

It's true man..............true.........

The correct options are:1.

Conditional probability that the selected compound actually has an impurity is 0.74.2.

Conditional probability that the selected compound is actually free of an impurity is 0.0185.3.

Conditional probability that the selected roll is from Process I given that it is defective is 0.64.

Here, we need to find out the probability that a selected compound has an impurity given that the test indicates an impurity is present.

P(A) = probability that a compound has impurity = 0.15

P(B) = probability that the test indicates an impurity is present

= 0.15 x 0.9 + 0.85 x 0.05

= 0.14 + 0.0425

= 0.1825P

(B|A) = probability that the test indicates an impurity is present given that the compound has impurity = 0.9

Therefore, by Bayes' Theorem,

P(A|B) = P(B|A) * P(A) / P(B)

         = 0.9 * 0.15 / 0.1825

         = 0.7370

         ≈ 0.74

Conditional probability that the selected compound actually has an impurity is 0.74.10.

Here, we need to find out the probability that a selected compound is actually free of an impurity given that the test indicates an impurity is not present.

P(A) = probability that a compound has impurity = 0.15

P(B) = probability that the test indicates an impurity is not present = 0.85 x 0.95 + 0.15 x 0.1 = 0.8075

P(B|A) = probability that the test indicates an impurity is not present given that the compound has impurity

          = 0.1

Therefore, by Bayes' Theorem,

P(A|B) = P(B|A) * P(A) / P(B)

          = 0.1 * 0.15 / 0.8075

          = 0.0185

Conditional probability that the selected compound is actually free of an impurity is 0.0185.11.

Here, we need to find out the probability that the selected roll is from Process I given that it is defective.

Let A denote the event that a roll is from Process I and B denote the event that a roll is defective.

Then, we need to find out P(A|B).

P(A) = probability that a roll is from Process I = 0.6

P(B|A) = probability that a roll is defective given that it is from Process I = 0.03

P(B|A') = probability that a roll is defective given that it is from Process II = 0.01

P(A'|B) = probability that a roll is from Process II given that it is defective

Therefore, by Bayes' Theorem,

P(A|B) = P(B|A) * P(A) / [P(B|A) * P(A) + P(B|A') * P(A')]

= 0.03 * 0.6 / (0.03 * 0.6 + 0.01 * 0.4)

= 0.6429

≈ 0.64

Conditional probability that the selected roll is from Process I given that it is defective is 0.64.

Hence, the correct options are:1.

Conditional probability that the selected compound actually has an impurity is 0.74.2.

Conditional probability that the selected compound is actually free of an impurity is 0.0185.3.

Conditional probability that the selected roll is from Process I given that it is defective is 0.64.

Learn more about  impurity from this link:

https://brainly.com/question/14932983

#SPJ11

Answer:

A strong alkali is 100% ionised.eg÷sodium hydroxide.

A week alkali is not 100% ionised.eg÷ammonia

A concentrated acid contains a large amount of acid in a given volume.

Answer-1:

A strong alkali dissociates completely to form OH- ions. A weak alkali only partially dissociates to form OH- ions. An example of a strong alkali is is sodium hydroxide.

Answer-2

If the number of certain moles in per litre of a molecule is more then the acidic substance is known as concentrated acid. For example : In dilute solution of H2SO4 the concentration of acid is 2% and 98% water.

To achieve the highest yield in the conversion of (1S,3S)-3-methylcyclohexan-1-ol into (1R,3S)-1-chloro-3-methylcyclohexane, the reagent of choice would be thionyl chloride (SOCl2).

The conversion of (1S,3S)-3-methylcyclohexan-1-ol into (1R,3S)-1-chloro-3-methylcyclohexane involves the substitution of a hydroxyl group (OH) with a chlorine atom (Cl) while maintaining the stereochemistry at the 3-position.

Thionyl chloride (SOCl2) is a commonly used reagent for the conversion of alcohols to alkyl chlorides. It reacts with alcohols via an SN2 mechanism, where the hydroxyl group is replaced by a chlorine atom.

The reason why thionyl chloride is preferred in this conversion is that it generally provides high yields and is selective for the desired substitution. Thionyl chloride reacts readily with alcohols and the resulting alkyl chlorides are generally of high purity. This reagent is known for its efficiency and effectiveness in alcohol chlorination reactions.

Other reagents commonly used for alcohol chlorination, such as phosphorus trichloride (PCl3) or phosphorus pentachloride (PCl5), can also be used but may have different selectivity or require additional steps to achieve the desired stereochemistry.

Therefore, for the highest yield and selective conversion of (1S,3S)-3-methylcyclohexan-1-ol into (1R,3S)-1-chloro-3-methylcyclohexane, thionyl chloride (SOCl2) is the recommended reagent.

Learn more about Thionyl chloride (SOCl2): https://brainly.com/question/30029310

#SPJ11

The hydrogen and oxygen links in a single water molecule are known as covalent bonds.

An electron exchange that results in the creation of electron pairs between atoms is known as a covalent bond. Covalent bonding is a stable equilibrium of the attractive and repulsive forces between two atoms that occurs when they share electrons. Bonding pairs or sharing pairs are other names for these electron pairs. A covalent bond is established when one or more pairs of electrons are exchanged between two atoms. These electrons are simultaneously pulled to the two atomic nuclei. When the difference in electronegativities between two atoms is too tiny for an electron transfer to take place and make ions, covalent bonds are formed.

To learn more about covalent bonds please visit https://brainly.com/question/19382448

#SPJ4

Boiling point elevation is a colligative property, which means it depends on the number of solute particles in a solution, not the identity of the solute itself. The formula for boiling point elevation is:

ΔTb = Kbm
Where ΔTb is the change in boiling point, Kb is the molal boiling point elevation constant (0.52°C/m for water), and m is the molality of the solution, which is the number of moles of solute per kilogram of solvent. To calculate the molality, we need to first calculate the number of moles of ethylene glycol in the solution:

moles of ethylene glycol = mass of ethylene glycol / molecular weight of ethylene glycol

moles of ethylene glycol = 800 g / 62.01 g/mol

moles of ethylene glycol = 12.903 mol

Next, we need to calculate the mass of water in the solution:

mass of water = 3.5 kg - 0.8 kg

mass of water = 2.7 kg

Finally, we can calculate the molality:

molality = moles of solute / mass of solvent (in kg)

molality = 12.903 mol / 2.7 kg

molality = 4.78 mol/kg

Now we can plug in the values into the boiling point elevation formula:

ΔTb = Kbm

ΔTb = 0.52°C/m × 4.78 mol/kg

ΔTb = 2.49°C

The boiling point of pure water is 100°C, so the boiling point of the solution is:

boiling point = 100°C + ΔTb

boiling point = 100°C + 2.49°C

boiling point = 102.49°C

Therefore, the correct answer is (a) 2.92°C.

To know more about Boiling point elevation, visit:

https://brainly.com/question/30641033

#SPJ11

Answer:

2

Explanation:

The upper mantle. It contains the asthenosphere and is part of the lithosphere and begins just beneath the crust and ends at the lower mantle.

Electrophilic aromatic substitution reactions have various applications in organic chemistry. They are commonly used to introduce functional groups onto aromatic rings, synthesize pharmaceuticals, produce dyes, and create complex organic molecules.

In organic chemistry, electrophilic aromatic substitution reactions are crucial tools for attaching new functional groups to aromatic rings. In these reactions, an electrophile replaces a hydrogen atom on an aromatic molecule. The end output can be used in a variety of different sectors.

Pharmaceutical synthesis is one area in which electrophilic aromatic substitution is used. Chemists can change the solubility, reactivity, and bioavailability of medicinal compounds by selectively adding functional groups to aromatic rings. This enables the creation of fresh medication candidates or the advancement of current ones.

The manufacture of dyes is an additional use. Due to their conjugated systems, aromatic compounds with particular functional groups can display bright hues. Colorful dyes used in textiles, inks, and other industries are produced through the introduction of chromophores onto aromatic rings using electrophilic aromatic substitution processes.

Additionally, it is essential for the synthesis of complex organic compounds to undergo electrophilic aromatic substitution processes. Chemists can create complex chemical structures with particular functions by carefully swapping various locations on an aromatic ring. This makes it possible to synthesize natural substances, sophisticated compounds, and materials with specific qualities.

To know more about Electrophilic aromatic substitution here https://brainly.com/question/30761476

#SPJ4

In order to answer the question first we must write the atomic number of each element:

Zirconium (Zr): 40

Cadmium (Cd): 48

Iridium (Ir): 77

Iron (Fe): 26

Then, we have to complete the distribution of electrons in each orbital for each atom:

The first 4 levels have the following distribution:

Level1: 1s

Number of electrones: 2

Level 2: 2s, 2p

Number of electrones 8 (2 in the s orbital and 6 in the p orbitals).

Level3: 3s, 3p, 3d

Number of electrones 18 (2 in the s orbital, 6 in the p orbital and 10 in the d orbitals)

Level 4: 4s, 4p, 4d, 4f

Number of electrones 32 (2 in the s orbital, 6 in the p orbitals, 10 in the d orbitals and 14 in the f orbitals)

The order in which the orbitlas are completed depends on the energy of each level. For example the 4s orbitals will be completed before the 3d orbitals because their energy is lower.

The order is as follows:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p...

Now, knowing the atomic number we can answer the question:

For Zirconium (total 40 electrones):

2 electrones are predicted in the 4d orbital

For Cadmium (total 48 electrones):

10 electrones are predicted in the 4d orbital

For iridium, as it has an atomic number higher than Cadmium we can predict tha it also complets the 4d orbital, then it has also 10 electrones in it.

For iron (total 26 electrones)

Iron has no electrones in the 4d orbitals

Main Answer:

When the experiment is repeated with 2.00 M HCl(aq), the same amount of heat will be released as in the previous reaction.

Supporting Answer:

In this reaction, HCl(aq) and NaOH(aq) undergo a neutralization reaction, resulting in the formation of water (H2O) and the release of heat. The fact that equal volumes of 1.00 M HCl(aq) and 1.00 M NaOH(aq) produce 57.1 kJ of heat indicates that the reaction is exothermic and that the enthalpy change (ΔH) for the reaction is constant.

When the concentration of HCl(aq) is doubled to 2.00 M, the reaction still involves an equal number of HCl molecules, and therefore the same amount of heat will be released. Thus, in the case of 2.00 M HCl(aq) and 1.00 M NaOH(aq) reacting in equal volumes, 57.1 kJ of heat will also be released.

To Know more about 2.00 M HCl(aq) visit link

https://brainly.com/question/31019527

SPJ11

The formula of the hydrated salt  would be \(FeSO_4.7H_2O\)

The formula of the hydrated salt of iron (II) sulfate would be in the form, \(FeSO_4.xH_2O\). The number of moles of water of hydration can be determined using the empirical formula approach.

Mass of hydrated salt = 15.79 g

Mass of anhydrous salt = 8.63 g

Mass of water of hydration = 15.79 - 8.63

                                             = 7.16 g

Now, let's find the equivalent mole of each component of the hydrated salt.

Molar mass of iron (II) sulfate = 151.908 g/mol

Molar mass of water of hydration = 18.01 g/mol

Mole of iron (II) sulfate = 8.63/151.908

                                      = 0.0568

Mole of water of hydration = 7.16/18.01

                                            = 0.3976

Divide by the smallest mole:

Iron (II) sulfate = 0.0568/0.0568 = 1

Water of hydration = 0.3976/0.0568 = 7

In other words, x, which represents the number of moles of water of hydration, is 7.

Hence, the formula of the hydrated salt would be  \(FeSO_4.7H_2O\).

More on the formula of hydrated salts can be found here: https://brainly.com/question/18264811

#SPJ1

Answer:

HCl

Explanation:

Carbon monoxide is the byproduct of fuel combustion that may result in death if such combustion equipment is not properly vented and is denoted as option D.

This is a compound which is derived from the combustion of carbon in insufficient supply of oxygen. Carbon monoxide when inhaled replaces the oxygen content in the body which is dangerous because oxygen is needed for the survival of the cells of the body.

The carbon monoxide is usually formed when there is no properly vent thereby resulting in insufficient supply of air. This therefore results in its presence in the body results in the death of cells of the body system.

This is therefore the reason why carbon monoxide was chosen as the most appropriate choice.

Read more about Carbon monoxide here https://brainly.com/question/25350361

#SPJ1

Answer:

because if the internet or electronics would go boom boom, then that would be our lifeline to save our important things.

Explanation:

Answer:

..... yep

Explanation:

tep no yep no hyshshshss

motion results in the kinetic energy of an object

Answer:

c

Explanation:

The molar absorptivity of compound X is approximately 7.99 × 10^3 M^(-1) cm^(-1).

To calculate the molar absorptivity of compound X, we can use the Beer-Lambert Law, which states that the absorbance of a sample is directly proportional to its concentration and the molar absorptivity.

The Beer-Lambert Law equation is given by:

A = ɛ * c * l

Where:

A is the absorbance,

ɛ (epsilon) is the molar absorptivity,

c is the concentration of the compound in moles per liter (M), and

l is the path length in centimeters (cm).

Given:

Absorbance of compound X solution (A) = 0.331

Path length (l) = 1.000 cm

Concentration of compound X (c) = 4.14 × 10^(-5) M

We can rearrange the equation to solve for the molar absorptivity (ɛ):

ɛ = A / (c * l)

Substituting the given values:

ɛ = 0.331 / (4.14 × 10^(-5) M * 1.000 cm)

Calculating the result:

ɛ ≈ 7.99 × 10^3 M^(-1) cm^(-1)

Therefore, the molar absorptivity of compound X is approximately 7.99 × 10^3 M^(-1) cm^(-1).

To know more about Beer-Lambert Law refer to

https://brainly.com/question/30404288

#SPJ11

Rhe equation to solve for the molar mass of the unknown compound:
molar mass of unknown compound = mass of unknown compound / moles of unknown compound.

The freezing point depression equation is given by ΔT = Kf * m * i, where ΔT is the freezing point depression, Kf is the cryoscopic constant, m is the molality of the solute, and i is the van't Hoff factor.

In this case, we have ΔT = 2.1 °C, and the mass of camphor (solvent) is 5.640 g. The mass of the unknown compound (solute) is 0.10 g.

To find the molality, we need to convert the mass of the solute and solvent into moles. The molar mass of camphor is 152.23 g/mol.

Step 1: Convert the mass of camphor to moles:
moles of camphor = mass of camphor / molar mass of camphor
moles of camphor = 5.640 g / 152.23 g/mol

Step 2: Convert the mass of the unknown compound to moles:
moles of unknown compound = mass of unknown compound / molar mass of unknown compound
moles of unknown compound = 0.10 g / molar mass of unknown compound

Since the unknown compound is assumed to be a non-electrolyte, the van't Hoff factor (i) is 1.

Step 3: Calculate the molality (m):
m = moles of unknown compound / mass of camphor (in kg)
m = moles of unknown compound / (5.640 g / 1000) kg

Step 4: Plug the values into the freezing point depression equation:
2.1 °C = Kf * m * i

The cryoscopic constant (Kf) depends on the solvent, so you will need to look up the value for camphor.

Finally, rearrange the equation to solve for the molar mass of the unknown compound:
molar mass of unknown compound = mass of unknown compound / moles of unknown compound

Learn more about cryoscopic constant

brainly.com/question/30582187

#SPJ11

Answer:

A diffraction.

Explanation:

Diffraction takes place with sound; with electromagnetic radiation, such as light, X-rays, and gamma rays; and with very small moving particles such as atoms, neutrons, and electrons, which show wavelike properties.

Tenacity refers to a mineral's toughness or resistance to breaking or being deformed.

We need the concentrations of hydrogen gas, water vapour, and oxygen gas to proceed further. If these concentrations are provided, we can substitute them into the equations and solve for δG° and Kp.

To calculate δG°, we need to use the equation δG° = -RT ln(Kp), where R is the gas constant and T is the temperature in Kelvin. To calculate Kp, we use the equation Kp = [H2]²/[H2O]²[O2]. By substituting the given values and solving the equations, we can find δG° and Kp.

To calculate δG° for the given equilibrium reaction at 25.00°C, we can use the equation δG° = -RT ln(Kp), where δG° is the standard Gibbs free energy change, R is the gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin. In this case, we need to convert the temperature from Celsius to Kelvin by adding 273.15 (25.00°C + 273.15 = 298.15 K).

To calculate Kp for the equilibrium reaction 2H2O(g) ⇌ 2H2(g) + O2(g), we can use the equation Kp = [H2]²/[H2O]²[O2]. Here, [H2] represents the concentration of hydrogen gas, [H2O] represents the concentration of water vapour, and [O2] represents the concentration of oxygen gas.

Now, let's substitute the given values into the equations and solve:

δG° = -RT ln(Kp)
= -(8.314 J/(mol·K)) * 298.15 K * ln(Kp)

Kp = [H2]²/[H2O]²[O2]
= ([H2]²) / ([H2O]²[O2])

To know more about Gibbs free refer to this:

https://brainly.com/question/13795204

#SPJ11

Answer:

it's false

Explanation:

cause oil is lighter than water

False!

Oil is less denser than water and thus will float