an electron confined in a one-dimensional box is observed, at different times, to have energies of 12 ev , 27 ev , and 48 ev . part a what is the minimal length of the box? express your answer in nanometers.

Answer:

D=mass /volume

=60/0.002

=30000

A spring of force constant 120 N/m acted up by a constant force of 240N. Then, the elastic potential energy stored in the spring is 240 Nm.

The elastic potential energy stored in the spring is formulated as follows

                                                 PE = ½kx²

Where PE is the elastic potential energy, x is the displacement of the spring from its equilibrium position, and k is the spring force constant.

In this question, the spring force constant is 120 N/m, and the constant force acting on the spring is 240 N. To find the spring displacement, we can use the formula:

F = kx

Where F is the force acting on the spring, x is the displacement, and k is the force constant,

So that:

F = kx

240 N = 120 N/m . x

x = 240 N/120 N/m

x = 2 m

Once x is known, then we can calculate the potential energy of the spring:

PE = ½kx²

PE = ½ (120) (2²)

PE = 60 x 40

PE = 240 Nm

So, the elastic potential energy stored in the spring is 240 Nm.

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An element of atomic number 88 decays radioactively to an element of atomic number 82. The emissions that achieve this result is one alpha particle. The correct option is D. The emission that achieves this result is one alpha particle. The correct option is C.

To determine the emissions that achieve the radioactive decay from an element with atomic number 88 to an element with atomic number 82, we need to consider the changes in atomic number and mass number during the decay process.

In a radioactive decay, the atomic number decreases by the emission of a particle, and the mass number decreases by a specific amount as well.

Atomic number of initial element = 88

Atomic number of final element = 82

From this information, we can conclude that the decay process involves the emission of an alpha particle.

The emission of an alpha particle corresponds to the emission of a helium nucleus, which consists of two protons and two neutrons. This emission reduces the atomic number by 2 and the mass number by 4.

Therefore, the emission that achieves this result is C, one alpha particle.

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Answer:

The capacitor helps to store data even after the battery is removed

Explanation:

The cell phone is fitted with different types of capacitors, which come in all shapes and sizes. However they come, their main function is to store charges within them, and dissipate these charges when necessary.

This serves a great purpose in the printed circuit boards of phones as they provide the power needed for data to be stored even when the battery of the phone is removed.

A capacitor is a solid-state device because it has no moving part. It just stores charges within its parallel plates for the phone until the power is needed.

see

below

Explanation:

refractive index = speed of light in vacuum / speed of light in medium

light travels at a speed of 3.0 x 10^8 m/s in vacuum

refractive index = 3.0 x 10^8 / 2.0 x 10^8

refractive index = 1.5

hope this helps, please mark it

Answer:

\(a=\frac{v^2}{r}\)

\(v=\sqrt{a*r}\)

\(r=\frac{v^2}{a}\)

Explanation:

This is the formula for centripetal acceleration in terms of the tangential velocity (v) and the radius of the circular motion (r).  The expression for the acceleration is already given, so simply type it as shown:

\(a=\frac{v^2}{r}\)

For the velocity (v) multiply by "r" both sides and then use the square root to solve for v:

\(a*r=v^2\\v=\sqrt{a*r}\)

For the radius multiply both sides by r and then divide both sides by the acceleration (a) in order to isolate r completely:

\(a*r=v^2\\r=\frac{v^2}{a}\)

Answer:

Number of electron wavelength will Double

Explanation:

let the radius = r  and wavelength = λ

when R doubles and  λ ( wavelength ) remains the same

The number of electron electron wavelengths will double as well

Using Bohr's angular momentum quantization to show this

attached below

Answer:

Those quantities that can be measured are called physical quantity...hope this helps:)

The length of foil can be (L)= 8581.2 cm=8.581 m

To calculate the value of the length of foil, we are using the formula

d= \(\frac{m}{V}\)

Or, d= \(\frac{m}{L\times W\times h}\)

Or, L= \(\frac{m}{d\times W\times h}\)

Here we are given,

d= The density of foil

= 2.7 g/cm³

W=  width of the foil

= 0.015 mm = 0.0015 cm.

h= Hight of the foil

= 305 mm = 30.5 cm.

m= mass of the foil.

= 1.06 kg = 1060 g

We have to calculate the value of the length of the foil =L cm

Now we put the known values in the above equation, we get

L= \(\frac{m}{d\times W\times h}\)

Or, L= \(\frac{1060}{2.7\times 0.0015\times 30.5}\)

Or, L= 8581.2 cm=8.581 m

From the above calculation we can calculate that, The length of foil can be (L)= 8581.2 cm=8.581 m

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Answer:

When air expands adiabatically (without gaining or losing heat), its pressure P and volume V are related by the equation PV^1.4=C where C is a constant. Suppose that at a certain instant the volume is 630 cubic centimeters and the pressure is 89kPa and is decreasing at a rate of 12 kPa/minute. At what rate in cubic centimeters per minute is the volume increasing at this instant? cm^3/min

Explanation:

89 kPa * 630 cm^3 = C

C = 3.54885 x 10^9 cm^4 kPa^(-1.4)

Now that we know the value of C, we can differentiate the equation with respect to time. This gives us:

dP/dt = -12 kPa/min

dV/dt = (1.4)(C)(P^(-1.4))(dP/dt)

dV/dt = (1.4)(3.54885 x 10^9 cm^4 kPa^(-1.4))(89 kPa)^(-1.4)(-12 kPa/min)

Therefore, the rate of change of volume is 910.846 cm^3/min. This means that the volume is increasing at a rate of 910.846 cubic centimeters per minute

Answer:

Force = mass × acceleration

Acceleration:

\({ \tt{15 = (22 \times a)}} \\ { \tt{a = \frac{15}{22} \: {ms}^{ - 2} }}\)

From first Newton's equation of motion:

\({ \bf{v = u + at}} \)

Change = v - u:

\({ \tt{v - u = (a \times t)}} \\ { \tt{v - u = ( \frac{15}{22} \times 1.2) }} \\ { \tt{v - u = 0.82 \: {ms}^{ - 2} }}\)

Answer:

Statement 2 is wrong

Explanation:

To check the statements in this exercise, let's describe the main properties of electromagnetic waves. Let's describe the characteristics

* they are transverse waves

* formed by the oscillations of the electric and magnetic fields

* the speed of the wave is the speed of light

with these concepts let's review the final statements

1) True. Formed by the oscillation of the two fields

2) False. They are transverse waves

3) True. Can travel by vacuum as they are supported by oscillations of the electric and magnetic fields

4) True. They all have the same speed of light

Statement 2 is wrong

Magnetic fields and electric fields are similar on the basis of the forces and its application.

An electric field is an electric property that is connected with any location in space where a charge exists in any form. The electric force per unit charge is another term for an electric field.

Magnetic and electric fields have certain similarities, are as follows;

1. Both the electric force and magnetic forces are the non-contact forces.

2. Both acts between the two entity having certain mass.

3. Both have their respective ranges.

Hence, magnetic fields and electric fields are similar on the basis of the forces and its application.

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The magnifying power of an astronomical telescope will be:

"0.095".

Telescope: Focal length and Power

According to the question,

Radius of curvature, R = 5.5 mm

Focal length of eyepiece,  = 2.9 cm

We know that,

→ Focal length of mirror,

F₀ =

By substituting the values,

   = 2.75 mm or,

   = 0.278 cm

hence,

The telescope's magnification be:

= 0.095

Thus the above approach is correct.

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The magnifying power of the astronomical telescope using a reflecting mirror is approximately 108.62.

To determine the magnifying power of an astronomical telescope, we can use the formula:

Magnifying power (M) = Focal length of the objective / Focal length of the eyepiece

For a reflecting mirror, the focal length is half of the radius of curvature. In this case, the focal length of the objective (mirror) is:

Focal length of the objective = Radius of curvature / 2 = 6.3m / 2 = 3.15m

Now, convert the eyepiece's focal length to meters:

Focal length of the eyepiece = 2.9cm = 0.029m

Using the formula for magnifying power:

M = 3.15m / 0.029m = 108.62

Therefore, the magnifying power of the astronomical telescope is approximately 108.62.

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the ratio of the mass of the A string to that of the E string is  0.653.

the equation for the frequency of a vibrating string is given as :

f = (1/2L) * √(T/μ)

f_ = frequency of the string,

L=  length of the string,

T= tension in the string, and

μ=  linear mass density of the string

We know that  the strings are all the same length and under essentially the same tension,

f1/√μ1 = f2/√μ2

f1=  frequency of the A string,

μ1 = linear mass density of the A string,

f2=  frequency of the E string, and

μ2=  linear mass density of the E string.

440/√(m1/L) = 639/√(m2/L)

440/√m1 = 639/√m2

(440 * √m2)² = (639 * √m1)²

m2 = (639/440)² * m1

In conclusion, we have that  the ratio of the mass of the A string to that of the E string is:

m1/m2 = 1/[(639/440)²]

m1/m =  0.653

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Part A: The electric potential V at a point on the disk's axis a distance x from the center of the disk is given by:

V = σ/2ε₀ × \((R^{2}/(x^{2} +R^{2} )^{1/2})\)

Part B: After calculating for −∂V/∂x we get:

-∂V/∂x = σR²x/2ε₀\((x^{2}+R^{2})^{3/2}\)

Part A:

The disc can be split into a number of thin, concentric rings in order to compute the electric potential V at a point on its axis that is located x distance from the disk's centre.

Each ring's potential is determined by:

\(V_{ring}\) = 1/4πε₀ × (\(Q_{ring}\) /  \((x^{2} +R^{2} )^{1/2}\))

where

\(Q_{ring}\) is the charge of the ring and

ε₀ is the permittivity of free space.

Since

the disk has uniform surface charge density σ, the charge on each ring is given by:

\(Q_{ring}\) = σ × 2πr × dr

where

r is the radius of the ring and

dr is its thickness.

By substituting \(Q_{ring}\) into the expression for \(V_{ring}\), we get:

\(V_{ring}\) = 1/4πε₀ × (σ × 2πr × dr / \((x^{2} +R^{2} )^{1/2}\))

By integrating across all the rings, it is possible to get the total potential V at any point along the axis of the disc:

V = ∫V_ring

V = ∫(1/4πε₀ × (σ x 2πr × dr / \((x^{2} +R^{2} )^{1/2}\))

V = σ/2ε₀ × ∫(r / \((x^{2} +R^{2} )^{1/2}\)) dr from 0 to R

By evaluating the integral and simplifying, we get:

V = σ/2ε₀ × [\((R^{2}/(x^{2} +R^{2} )^{1/2})\) - \((0/(x^2+0^2)^{1/2})\)]

V = σ/2ε₀ × \((R^{2}/(x^{2} +R^{2} )^{1/2})\)

Therefore, the electric potential V at a point on the disk's axis a distance x from the center of the disk is given by:

V = σ/2ε₀ × \((R^{2}/(x^{2} +R^{2} )^{1/2})\)

Part B:

To find the value of −∂V/∂x,

The derivative of the equation for V with regard to x must be taken:

∂V/∂x = -σR²x/2ε₀\((x^{2}+R^{2})^{3/2}\)

Hence, the expression for −∂V/∂x is:

-∂V/∂x = σR²x/2ε₀\((x^{2}+R^{2})^{3/2}\)

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ANSWER:

C. light energy → electrical energy → heat energy

STEP-BY-STEP EXPLANATION:

Solar panels capture light energy from the sun, which must necessarily be converted into electrical energy to then generate heat to bake the cookies.

So, the correct order would be the following:

C. light energy → electrical energy → heat energy

Answer:yeah its C lol

Explanation:

Answer:

33 hours

Explanation:

7.5 + 6.5 = 13 + 1

14 + 10 = 24

9= 6+3

24 + 6 = 30

30+3= hours

The vernal or spring equinox occurs in the northern hemisphere on March 21 or 22.

The diagram that represents the position of a ball, at equal time intervals, as it falls freely is diagram B.

The acceleration of an item in free fall is -9.8 m/s/s. (The minus symbol represents a downward acceleration.) For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.

vf = g x t where g is the acceleration of gravity. The value for g on Earth is 9.8 m/s/s. This formula is used to determine the object's speed after being dropped from rest for any period of time.

Therefore, the correct option is B. diagram B.

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The question is incomplete. Your most probably complete question is given below:  the options are attached below.

Dalton's atomic theory is related to the characteristics of atom. The statement describes one of the main principles of Dalton's atomic theory is atoms of same element are identical.

The Dalton's theory states that All matter is composed of extremely small particles called atoms and Atoms of a given element are identical in size, mass, and other properties. Atoms of different element are different.

Hence, the statement describes one of the main principles of Dalton's atomic theory is atoms of same element are identical.

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Answer:

Below

Explanation:

If they are all in parallel, the quivalent resistance is given by

            1                     =    3.6 Ω

  1/R1   + 1/R2  + 1/R3

Answer:

Essential processes happen in a cell: Onion plant and Diatom

A cell is its basic unit of structure: Onion plant and Diatom

Made up of one cell: Diatom

Made up of many cells: Onion plant

Answer:

5 m/s²

Explanation:

Acceleration = change in speed/time taken

20-5=15

15/3= 5 m/s²

Answer:

H

Explanation:

Answer:

Pacific Ocean and Nazca plates is moving to west

Explanation:

beacause if they move to west they will move to the left

The hyphen notation for 11 electrons and 14 neutrons. isotope is written as Na-25.

To write the hyphen notation for 11 electrons and 14 neutrons isotope we will apply the following method.

First, the hyphen notation for an isotope indicates the number of protons and the number of neutrons present in a given atom.

So we can say that it indicates the sum of the atomic number.

To write the hyphen notation for an isotope with 11 electrons and 14 neutrons isotope, we will write it as follows;

an atom with 11 electrons and 14 neutrons is definitely sodium with mass number of 25

mass number = 11 + 14 = 25

The  hyphen notation = Na-25

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The vertical and horizontal parts of a projectile are perpendicular and independent of one another over a short distance.

Depending on the force imposed on it, horizontal motion is defined as a projectile motion in a horizontal plane. The vertical and horizontal parts of a projectile are perpendicular and independent of one another over a short distance.

Throughout the course of a projectile's flight, the horizontal component of its speed remains constant. This is because the projectile experiences no horizontal force after being launched. As a result, the projectile moves horizontally at a fixed speed.

The following equation is used to determine how far a bullet travels;

d = vt, where

t = Time

d = Distance

v = velocity

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The speed of sound in air at the temperature of 136°F (331 K) = 365.71 m/s

The speed of sound in air depends on temperature, so the higher the temperature, the greater the value of the speed of sound.

The equation for determining the speed of sound with a change in temperature is:

v = v₀ + 0.6(∆T)

where:

v = the final sound velocity (m/s)

v₀ = the initial sound velocity (m/s)

∆T = temperature change (°C)

Note: The speed of sound in air at 0°C is 331 m/s.

We have ∆T = 136°F ⇒ 57.85°C

So,

v = 331 + 0.6 (57.85)

= 365.71 m/s

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Answer:

C

Explanation:

Answer:

A

because volcano can produce sediment and

erodus rock