Anna just found out she is pregnant and has
recently been experiencing some hair loss. She
seeks medical advice, and her doctor tells her not
to worry, that it is most likely a result of
O hirsutism.
Ohair infection.
O pregnancy.
O a genetic disorder.
DONE

Answer:

The acceleration of the crate is \(0.3356\,\frac{m}{s^2}\)

Explanation:

Recall the formula that relates force,mass and acceleration from newton's second law;

\(F=m\,a\)

Then in our case, we know the force applied and we know the mass of the crate, so we can solve for the acceleration as shown below:

\(F=m\,a\\75.5\,N=225\,\,kg\,\,a\\a=\frac{75.5}{225} \,\frac{m}{s^2} \\a=0.3356\,\,\frac{m}{s^2}\)

The acceleration of both points A and B can be determined from the given velocities and accelerations of the gear racks.

Point A:

x-component of acceleration = 0 m/s^2

y-component of acceleration = 6 m/s^2

Point B:

x-component of acceleration = 0 m/s^2

y-component of acceleration = -6 m/s^2

The acceleration of both points A and B can be determined from the given velocities and accelerations of the gear racks. The x-component of the acceleration of both points is equal to 0 m/s^2 since the gear racks are not moving horizontally. The y-component of the acceleration of both points is equal to 6 m/s^2 in the upward direction for point A, and -6 m/s^2 in the downward direction for point B. Therefore, the acceleration of point A is (0, 6) m/s^2 and the acceleration of point B is (0, -6) m/s^2.

The complete question is:

At a given instant, the gear racks have the velocities and accelerations shown.

Determine the acceleration of points A and B.

Enter the x and y components of the acceleration

the complete question is :

At a given instant, the gear racks have the velocities and accelerations shown ( attached below ).

Determine the acceleration of point A.

Enter the x and y components of the acceleration

Determine the acceleration of point B.

Enter the x and y components of the acceleration

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Potential energy is a form of accumulated energy that an item or set of objects may have depending on their size, shape, location, or even substance.

Potential energy is the energy retained by an object as a result of its location relative to other objects, internal stresses, electric charge, or other variables. Although it has ties to the old Greek philosopher Aristotle's idea of potentiality, the word potential energy was coined by the 19th-century Scottish engineer and physicist William Rankine.

The gravitational potential energy of an object, the elastic potential energy of a stretched spring, and the electric potential energy of an electric charge in an electric field are all examples of common kinds of potential energy.

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The magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹ (Option E).

The electric flux through a surface is given by the product of the electric field strength and the area of the surface projected perpendicular to the electric field.

In this case, the electric field strength is 18 N C⁻¹, and the area of the sheet projected perpendicular to the electric field is 0.450 m²

(since the normal to the sheet makes an angle of 60° with the electric field). Multiplying these values gives the electric flux:

Electric flux = Electric field strength × Area

Electric flux = 18 N C⁻¹ × 0.450 m²

Electric flux = 8.1 N m² C⁻¹

In summary, the magnitude of the electric flux through the sheet is 4.05 N m² C⁻¹. This value is obtained by multiplying the given electric field strength by the projected area of the sheet perpendicular to the electric field.

The angle of 60° is taken into account to determine the effective area for calculating the flux.(Option E).

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When acceleration is equal to zero average velocity and the instantaneous velocity vectors are identical.

Types of velocity

Velocity is defined as the rate of displacement of an object with respect to time. It is measured in meter/ seconds and is a vector quantity.

Acceleration is defined as the rate at which velocity changes with time.

There are two types of velocity which includes:

Average velocity: This is the average rate of change of position of particles with respect to time over an interval.

Instantaneous velocity: This is defined as the specific rate of change of position with respect to time at a particular point.

The situation that will make the average velocity and the instantaneous velocity vectors to be equal or identical is when acceleration is equal to zero.

The work required to stretch a string is given by the following equation:

Where:

If the string is stretched 2 cm then we substitute the value of "x = 2" in the formula, we get:

Solving the square and simplifying:

Now, if the string is stretched 1 cm we get:

Solving the operations:

Now, we determine the quotient between W2 and W1:

Simplifying we get:

Now, we multiply both sides by W2:

Therefore, the work required to stretch the string 2 cm is 4 times the work to stretch it 1 cm.

(A) The water will shrink when is heated above 4°C. (B).water at an initial temperature of 33.3°C will be expand by twice as much when it is raised by 1°C compared to water at 30°C.

The anomalous expansion of water refers to the fact that its volume increases upon cooling from 4°C to 0°C, and then contracts upon further cooling to 0°C, and continues to contract upon further cooling. Similarly, when water is heated, its volume first contracts until it reaches 4°C, and then expands upon further heating.

To determine at what temperature water shrinks when heated, we need to find the point at which the coefficient of volume expansion, β, becomes negative. The coefficient of volume expansion is defined as the fractional change in volume per degree Celsius change in temperature, i.e.,

β = (1/V)  (dV/dT)

where V is the volume of the water and dV/dT is the rate of change of volume with respect to temperature.

At temperatures below 4°C, the coefficient of volume expansion is positive, indicating that water expands upon heating. However, at temperatures above 4°C, the coefficient of volume expansion becomes negative, indicating that water contracts upon heating.

Therefore, water will shrink when heated above 4°C.

To determine the initial temperature at which water will expand by twice as much when raised by 1°C, we can use the formula for the coefficient of volume expansion:

β = (1/V)  (dV/dT)

We want to find the initial temperature T such that

(dV/dT)T = 2 (dV/dT)30

where (dV/dT)T is the rate of change of volume with respect to temperature at temperature T, and (dV/dT)30 is the rate of change of volume with respect to temperature at 30°C.

Using the coefficient of volume expansion for water, we have

β = 3α

where α is the coefficient of linear expansion, which is approximately constant for small temperature changes. Therefore, we can write

(dV/dT) = V × 3α

Substituting this into the equation above and simplifying, we get

T = 30 + 10/3 = 33.3°C

Therefore, water at an initial temperature of 33.3°C will expand by twice as much when raised by 1°C compared to water at 30°C.

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Answer:

3 m/s

Explanation:

A= F/m

12,000/ 4000 = 3

Answer:

3 m/s^2

Explanation:

The equation you have to use is F=ma because the problem is a Newton's 2nd law problem.

Our known values are:

F ( Force ) = 12,000 N

m ( mass ) = 4,000 kg

a ( acceleration ) = ?

Now we plug in the known values into the equation and solve

F=ma

12,000=4,000a

We have to divide 4,000 by both sides to isolate the a value

12,000/4,000=4,000/4,000a

The 4,000s on the right of the equation cancel.

And 12,000 divided by 4,000 equals 3

The acceleration (a) is 3 meters per second squared (m/s^2)

Next, check to make sure 3 does work by plugging it back into the equation.

12,000=4,000*3

12,000=12,000 ✔

As you can see, the acceleration will be 3 m/s^2

The potential of the two aluminum spheres will be equal when they come into contact. identical radius, therefore equal potential results in  charges. Hence, sphere C will have a final charge of q c = +1.125q.

All charges in a circular conductor are at suitable intervals from one another because the energy in a sphere conductor will travel about until it is evenly distributed across its surface. As a result, there's an equal and opposite charge for every charge. Electric fields produced by these charges cancel each other out.

This is just Qr40r if the charge is evenly dispersed throughout the sphere. The charge contained inside radius r in this instance is Qr, and if the charge is Q(r3/a3) is uniformly distributed around the sphere. Hence, Qr240a3 represents that portion of the potential.

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Answer:

a spark

Explanation:

a spark would be the most smartest

(a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.

Acceleration owing to gravity is the term used to describe the rate at which a body's velocity changes as a result of the earth's gravitational pull. In general, it is assumed that the acceleration caused by gravity is in the downward direction.

The acceleration caused by gravity has been calculated as, however as it changes from location to location, it may have an impact on the estimation.

You may have thought that the wind has no impact, but it can actually generate drag and even cause the ball to shift course.

Therefore, (a) The ball goes up to the height of 31.89 m. (b) The ball stays for 5.1 s in the air. (c) The acceleration due to gravity and wind resistance can affect the estimation.

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The current in the circuit when the voltage across the resistor is equal to the voltage across the inductor is given by:

i(t) = [V_B / R] (1 - e^(-Rt/L)) where t is the time after the switch is closed.

The series circuit in the figure contains an ideal battery with a constant terminal voltage V_B=52 V, an ideal inductor L=42 H, a R=20-ohm resistor, and a switch S. Initially, the switch is open, and there is no current in the inductor. At time t=0 s, the switch is suddenly closed. What is the current in the circuit when the voltage across the resistor is equal to the voltage across the inductor-If the voltage across the resistor and the voltage across the inductor are equal, then the voltage across the inductor is V = IR, where I is the current in the circuit.

According to Kirchhoff's law, the voltage across the resistor is equal to the voltage of the battery minus the voltage across the inductor, i.e., V = V_B - L (di / dt), where di/dt is the rate of change of current, and L is the inductance of the inductor. Equating these two expressions for V, we have: IR = V_B - L (di / dt). Rearranging this equation gives us the following differential equation:di / dt + (R/L) i = (V_B / L)The solution of this differential equation is given by: i(t) = [V_B / R] (1 - e^(-Rt/L)).

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The medium in which electromagnetic waves and mechanical waves travel is one of their primary distinctions. Light and other electromagnetic waves, including radio waves, can move through void space without the aid of a physical medium.

They may move through vacuum, air, or other materials and are made up of oscillating electric and magnetic fields. The propagation of mechanical waves, such as sound or water waves, on the other hand, depends on a physical medium.

To transport energy, they rely on particle interactions and displacements in the medium. Since mechanical waves need a physical medium to carry their energy, they cannot move through a vacuum.

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Answer:

weight, acceleration

Explanation:

weight = mass x gravity(meaning the direction of the mass)

acceleration = v-u/t

v-u is the change in velocity

* **Step 1: Identify the relevant information.**

We are given the following information:

 * The initial velocity of the puck is 28.0 m/s horizontally.

 * The height of the platform above the ground is 2.00 m.

 * We can neglect air resistance.

* **Step 2: Set up the equations.**

We can use the following equations to solve for the direction of the velocity of the puck just before it hits the ground:

 * $v_y = v_0y + at$

 * $y = y_0 + v_0yt + \frac{1}{2}at^2$

Where:

 * $v_y$ is the final velocity in the vertical direction

 * $v_0y$ is the initial velocity in the vertical direction

 * $a$ is the acceleration due to gravity (9.8 m/s^2)

 * $t$ is the time

 * $y$ is the vertical position

 * $y_0$ is the initial vertical position

* **Step 3: Solve for the unknowns.**

We can solve for the final velocity in the vertical direction using the following equation:

```

v_y = v_0y + at

```

Plugging in the known values, we get:

```

v_y = 0 + (-9.8) t

```

```

v_y = -9.8t

```

We can solve for the time using the following equation:

```

y = y_0 + v_0yt + \frac{1}{2}at^2

```

Plugging in the known values, we get:

```

2 = 0 + (0) t + \frac{1}{2}(-9.8)t^2

```

```

4 = -4.9t^2

```

```

t^2 = -0.816

```

```

t = -0.90

```

We can now solve for the final velocity of the puck using the following equation:

```

v_y = -9.8t

```

Plugging in the known value for $t$, we get:

```

v_y = -9.8(-0.90)

```

```

v_y = 8.82 m/s

```

The final velocity of the puck in the vertical direction is 8.82 m/s downward.

* **Step 4: Find the angle.**

The angle of the velocity of the puck can be found using the following equation:

```

\theta = \tan^{-1} \left ( \frac{v_y}{v_x} \right )

```

Plugging in the known values for $v_y$ and $v_x$, we get:

```

\theta = \tan^{-1} \left ( \frac{8.82}{28.0} \right )

```

```

\theta = 12.6^\circ

```

Therefore, the direction of the velocity of the puck just before it hits the ground is 12.6 degrees below the horizontal.

Answer:

Gironde Ecosystem is an important biological and cultural area.

Explanation:

Answer:

C.  3.0 s

Explanation:

Well, I've taken this question before, so I went back and this was the answer I put, which was correct.

Hope this helps! <3 May I have brainliest if it helps you enough?

It will take 3 s for the stone to get to the surface of the water.

We'll begin by listing out what was given from the question. This includes:

Height (h) = 45 m

NOTE: Acceleration due to gravity (g) is 10 m/s²

From the data above, we can obtain the time taken for the stone to get to the surface of the water as follow:

45 = ½ × 10 × t²

45 = 5 × t²

\(t^{2} = \frac{45}{5} \\\\t^{2} = 9\)

\(t = \sqrt{9}\)

Therefore, it will take 3 s for the stone to get to the surface of the water.

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A VfL (Vertical Field LED) backlighting system is commonly used in LCD (Liquid Crystal Display) televisions.

LCD TVs rely on a backlight to illuminate the liquid crystal layer, which controls the passage of light to create the visual image. The VfL technology is a specific type of LED backlighting arrangement used in certain LCD TV models. In a VfL backlighting system, the LEDs (Light-Emitting Diodes) are positioned vertically along the edges of the LCD panel.

The light emitted by these LEDs is directed across the panel using light guides or optical films, illuminating the liquid crystal layer uniformly. One advantage of VfL backlighting is its ability to provide consistent illumination across the LCD panel, reducing any potential inconsistencies in brightness or color uniformity. The vertical orientation of the LEDs allows for more precise control over light distribution, improving overall image quality.

Additionally, VfL backlighting offers potential advantages in terms of power efficiency. By selectively dimming or turning off specific zones of LEDs, local dimming techniques can be employed to enhance contrast and black levels, resulting in improved picture quality while conserving energy. It's important to note that VfL backlighting is just one of several backlighting technologies available for LCD TVs.

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If airflow lifts a 3.6 kg bird 50 m up, then the work done by the airflow is 1764 joules.

Given,

Work done against the friction (W) =?

We know that :

Work done against the friction (W) = force × displacement

W = F × d

W = m × g x d        [ Force = mass × acceleration due to gravity ]

W = 3.6 × 9.8 × 50      [ g = 10 m/s2 ]

W = 1764 joules

Hence,  the work done by the airflow is 1764 joules.

A force is an influence that has the power to alter an object's motion. A force can cause an object with mass to accelerate when it changes its velocity, for as when it moves away from rest.

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The approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

To approximate the heat transfer through the air layer in the double-paned window, we can assume that the glass layers have a negligible impact on the heat flow. The heat transfer can be calculated using Fourier's Law of Heat Conduction, which states that the heat flow (Q) is proportional to the temperature difference (ΔT) and inversely proportional to the thickness (L) and thermal conductivity (k) of the material.

First, we need to calculate the effective thermal conductivity of the air layer due to its thickness and the thermal conductivity ratio between air and glass. Let's denote the thermal conductivity of air as k_air and the thermal conductivity of glass as k_glass. Since glass has a thermal conductivity roughly 36 times greater than air, we have k_glass = 36 * k_air.

Next, we calculate the effective thermal conductivity of the air layer as:

k_eff = (k_air * L_air) / (L_air + k_glass)

Substituting the given values, we have:

k_eff = (k_air * 0.0165 m) / (0.0165 m + 0.005 m) = 0.01309 * k_air

Now, we can calculate the heat flow per second through the air layer using the formula:

Q = (k_eff * A * ΔT) / L_air

Substituting the given values, we get:

Q = (0.01309 * k_air * 0.760 m^2 * 23.0 K) / 0.0165 m = 24.4 J/s

Therefore, the approximate heat transfer through 1.65 cm of air with a temperature difference of 23.0 °C is approximately 24.4 J/s.

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The final velocity of the car can be calculated using the formula: final velocity = initial velocity + acceleration * time. Plugging in the values you provided, we get: final velocity = 5.82 m/s + 2.35 m/s² * 3.25 s = 13.44 m/s.

convex lenses.

eyeglasses with convex lenses increase refraction, and accordingly reduce the focal lenght

(a)

A = (75.0 cm) (cos(30°) i + sin(30°) j)

A = (75.0 cm) (√3/2 i + 1/2 j)

A ≈ (64.95 i + 37.5 j) cm

The x component is the coefficient of the i unit vector, while the y component is the coefficient of the j unit vector.

(b) "points along the negative axis" in other words means that B makes an angle of 180° with the positive x-axis in the counterclockwise direction. In particular this tells you that B is parallel to the x-axis, so its y component would be zero.

B = (25.0 cm) (cos(180°) i + sin(180°) j)

B = (25.0 cm) (-1 i + 0 j)

B = (-25.0 i) cm

(c) If the negative x-axis corresponds to 180°, then 45° below this would make an angle of 180° + 45° = 225° with the positive x-axis.

C = (40.0 cm) (cos(225°) i + sin(225°) j)

C = (40.0 cm) (-1/√2 i - 1/√2 j)

C ≈ (-28.28 i - 28.28 j) cm

(d) The sum A + B + C has components that are the sums of the components of each of A, B, and C.

A + B + C ≈ (11.67 i + 9.22 j) cm

(e) The magnitude of the vector sum is

||A + B + C|| = √((11.67 cm)² + (9.22 cm)²) ≈ 14.87 cm

(f) Since both components of the vector sum are positive, you know that it's a vector that terminates in the first quadrant of the x,y-plane, so it makes an angle with the positive x-axis of

arctan(9.22/11.67) ≈ 38.3°

Answer:

they are related because..

Explanation:

Physical properties can be observed or measured without changing the composition of matter. Physical properties include: appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many others

The relation is ; Reflectivity and solubility are both physical properties of substances and are measured in relation to given variable ( i.e. incident ray for reflectivity and solvent for solubility )

Reflectivity ( aka optical property ) and solubility are both physical properties of any substance. while reflectivity of an object is measured as the amount of light an object reflects in relation to the light incident on it ( incident ray ), solubility is the amount of a substance that will dissolve in a given solvent at a given temperature.   a

Hence we can conclude that the relation between reflectivity and solubility is that they are both physical properties of substances and are measured in relation to given variable ( i.e. incident ray for reflectivity and solvent for solubility ).

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Given :

Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1.

To Find :

The ratio of the magnetic field in the interior of 2 to that in the interior of 1.

Solution :

We know, magnetic field in the interior of a solenoid is given by :

\(B = \dfrac{\mu ni}{L}\)

Let, length of solenoid 2 is L.

Therefore, length of solenoid 1 is 6L.

\(B_a=\dfrac{\mu (6n)i}{L}\\\\B_b = \dfrac{\mu n i}{L}\)

Dividing \(B_a\) by \(B_b\) :

\(\dfrac{B_a}{B_b}=\dfrac{\dfrac{\mu (6n)i}{L}}{\dfrac{\mu n i}{L}}\\\\\dfrac{B_a}{B_b}=6\)

Therefore, the correct answer is C. 6.

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

The observation that electromagnetic radiation with energy above a certain value can eject electrons out of a metal is a piece of evidence that they have particle-like properties.

This observation that electromagnetic radiation behaves like particles is known as the photoelectric effect.

It provides evidence that electromagnetic radiation exhibits particle-like properties. When EMR with sufficient energy (above a certain threshold) interacts with a metal surface, it can cause the ejection of electrons from the metal.

This behavior indicates that EMR behaves as discrete packets of energy called photons, which transfer their energy to the electrons and cause their release. The photoelectric effect supports the particle nature of EMR and is a fundamental concept in the field of quantum mechanics.

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U = mgh is result of the expression calculating gravitational potential energy elevation (h). R + h = R + g = GM/R2 follow when hR.  should be noted as g no value near the earth's centre, a body's weight is also zero .

But in a wider sense, gravity is a force since it explains the interaction of two masses. Fundamentally, the stretching of space and the motion of things through the deformed spacetime are what create gravitational effects. But the outcome appears to be the effect of applying force.

– Derive ΔU = mgh. When, h<<R, then, R + h = R and g = GM/R2. ⇒

There will be only one kind of gravity. In nature, there are only two types of gravity. This indicates that there is just one kind of gravitational pull that draws the two bodies closer based on their.

U = – GMm / r

U = – GMm/r

U = mgh

Fdx = dw

 dW = (GMm/x2)dx

W=SC.Mm ) dx00

W = - (GMm)- (-00• GMm

W=-GMm/r

U = - GMm(1/r1 - 1/r2)

if r1 >r2 so U is negative

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The correct question is

Define gravitational potential energy. Derive expression for gravitational potential in the gravitational field of earth at distance r from the centre of the earth.