Balance: _Al + _S2 → __AI2S3
A.) 4,3,1
B.) 4,3,2
C.) 2,3,2
D.) 2,3,1

To produce one molecule of glucose, 6 molecules of carbon dioxide (\(CO_{2}\)), 18 molecules of adenosine triphosphate (ATP), and 12 molecules of nicotinamide adenine dinucleotide phosphate (NADPH) are required.

Glucose, a six-carbon sugar, is synthesized through the process of photosynthesis in plants. It involves the Calvin cycle, which incorporates carbon dioxide, ATP, and NADPH to produce glucose. For each molecule of glucose formed, 6 molecules of carbon dioxide are required.

The energy needed for glucose synthesis is provided by ATP, which is an energy-rich molecule. In the Calvin cycle, the synthesis of one glucose molecule requires 18 molecules of ATP.

NADPH, a coenzyme involved in energy transfer reactions, is required for the reduction of carbon dioxide during the Calvin cycle. In the process, 12 molecules of NADPH are utilized to produce one molecule of glucose. These components play crucial roles in capturing and storing energy, as well as providing carbon atoms for the formation of glucose, which serves as a vital energy source for organisms.

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Answer:

Here's what I get  

Explanation:

Assume the initial concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.

We must calculate the initial concentration of HI.

1. We will need a chemical equation with concentrations, so let's gather all the information in one place.

                   H₂ +    I₂    ⇌ 2HI

I/mol·L⁻¹:    0.30   0.15         x

2. Calculate the concentration of HI

\(Q_{\text{c}} = \dfrac{\text{[HI]}^{2}} {\text{[H$_{2}$][I$_{2}$]}} =\dfrac{x^{2}}{0.30 \times 0.15} = 5.56\\\\x^{2} = 0.30 \times 0.15 \times 5.56 = 0.250\\x = \sqrt{0.250} = \textbf{0.50 mol/L}\\\text{The initial concentration of HI is $\large \boxed{\textbf{0.50 mol/L}}$}\)

3. Plot the initial points

The graph below shows the initial concentrations plotted on the vertical axis.

The initial concentration of the HI at the time 0 sec, has been 0.05 mol/L.

The balanced chemical equation for the reaction has been:

\(\rm H_2\;+\;I_2\;\rightarrow\;2\;HI\)

The given initial concentration of hydrogen has been 0.030M, and the given concentration of iodine has been 0.015 M.

The reaction quotient for the following reaction has been:

Reaction quotient = \(\rm \dfrac{[HI]^2}{[H_2]\;[I_2]}\)

The concentration of HI for the reaction quotient 5.56 has been:

5.56 = \(\rm \dfrac{[HI]^2}{[0.030]\;[0.015]}\)

\(\rm [HI]^2\) = 0.0025 M

HI = 0.05 mol/L or 0.05 M.

The concentration of the HI at the initial concentration has been 0.05 mol/L.

The graph attached has been plotted as the concentration as the function of time.

The initial concentration of hydrogen, iodine, and hydrogen iodide have been plotted as the function of time.

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[H+][OH-]=10-¹⁴

We are using this formula because we need to find the H+

substitute the value given for hydronium ion for OH-

[H+][4.19×10⁵]=10-¹⁴

[H+]=10-¹⁴÷4.19×10⁵

[H+]=2.387×10-¹⁹

Then the pH of the solution will be

pH= –log¹⁰ [H+]

pH = –log¹⁰ [2.387×10-¹⁹]

pH= –log¹⁰2.387+19log¹⁰

= –0.378+19

pH =18.622

Carbon dioxide is produced when 5 mL of methane gas interacts.

Methane, a hydrocarbon, is the primary component of natural gas. Methane has an effect on the climate and temperature of the earth because it is a greenhouse gas (GHG). Methane is released into the atmosphere through a variety of natural and anthropogenic (caused by humans) sources.

Methane is non-toxic and safe to breathe in small amounts, but if it is allowed to replace air in large quantities, the absence of oxygen could result in suffocation.

\(CH_{4}(g) + 2O_{2} \rightarrow CO_{2} + 2H_{2}O(g)\)

1 volume of \(CH_{4}\) = 1 volume of \(CO_{2}\)

5 ml of \(CH_{4}\) = 1 × 5 mL CO2

                    = 5 mL CO2

So, volume of methane = 5mL

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Answer:

Analytical Chemist.

Chemical Engineer.

Chemistry Teacher.

Forensic Scientist.

Geochemist.

Hazardous Waste Chemist.

Materials Scientist.

Pharmacologist.

Explanation:

Dow Chemical would be best described as a multinational corporation in this scenario.

This is the type of corporation which are involved in controlling production of goods and services in at least one country different from that of residence.

Dow chemical is known to have a plant in Germany and Russia thereby making it a multinational corporation.

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Ideal gas law is valid only for ideal gas not for vanderwaal gas. Combined Boyle's and Charles' gas law is used here. The  new temperature of gas is 79.3°C.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature.

Mathematically,

PV=nRT

where,

P = pressure of gas

V= volume of gas

n =number of moles of gas

T =temperature of gas

R = Gas constant = 0.0821 L.atm/K.mol

Combining Boyle's and Charles' gas law

P₁V₁/T₁ = P₂V₂/T₂

{ (752 mmHg) (8.29 L )} ÷296K ={ ( 358 mmHg) (11.39 L)} ÷T₂

T₂ = 79.3°C

Therefore the new temperature of  gas is79.3°C.

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Answer: D. Investigation 4

Answer:

Investigation D

Explanation:

Answer:

A. 35Cl1-

Explanation:

Chlorine needs 1 more electron to have full octet thus will take 1 electron and possess a -1 charge.

Density is intensive because it is the ratio of two extensive properties that is mass to volume.

Density is defined as mass per unit volume. S.I unit if density is kg/m³.

It is expressed as

Density = \(\frac{\text{Mass}}{\text{Volume}}\)  or \(d = \frac{m}{V}\)

Intensive property is the property which does not depend on the size of the system. Intensive property can be easily identified. Intensive property is the independent property. The size does not change in this.

Example of intensive property are Density, Freezing point, melting point, colour, Lustre, etc.  

Extensive property is the property which depend on the substance. Extensive property cannot be easily identified.

Example of extensive property length, weight, volume, mass etc.

Thus from the above conclusion we can say that Density is intensive because it is the ratio of two extensive properties that is mass to volume.

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Disclaimer: The given question is incomplete on the portal. Here is the complete question.

Question: The density (d) of a substance is an intensive property that is defined as the ratio of its mass (m) to its volume (v)

density = \(\frac{\text{Mass}}{\text{Volume}}\)  or \(d = \frac{m}{V}\)

Considering that mass and volume are both extensive properties, explain why their ratio, density is intensive.

Answer:

NaOH

Explanation:

NaOH is among the water soluble bases

Answer:

40.02 calories

Explanation:

V = 10 mL = 10g

we know t went up by 4°C, this is our ∆t as it is a change.

Formula that ties it together: Q = mc∆t

where,

Q = energy absorbed by water

m = mass of water

c = specific heat of water (constant)

∆t = temperature change

Q = (10 g) x (4.186 J/g•°C) x (4°C)

Q = 167.44 J

Joules to Calories:

167.44 J x 1 cal/4.184 J = 40.02 calories

(makes sense as in image it is close to the value).

Answer:

Ionic bonds are a class of chemical bonds that result from the exchange of one or more valence electrons from one atom, typically a metal, to another, typically a nonmetal. This electron exchange results in an electrostatic attraction between the two atoms called an ionic bond.

Explanation:

Answer:

The electrons are transferred from one atom to another. The atom that loses electrons becomes positive.

Explanation:

I don't really understand what form of an answer you need but I hope this helps?

Answer:

Ka = 9.2x10⁻⁷

Explanation:

The equilibrium of carbonic acid in water is:

H₂CO₃ ⇄ HCO₃⁻ + H⁺

Where Ka is defined as:

Ka = [HCO₃⁻] [H⁺] / [H₂CO₃]

The equilibrium concentration of the species is:

[H₂CO₃] = 1.9x10⁻² - X

[HCO₃⁻] = X

[H⁺] = X

As pH is -log[H⁺]

3.88 = -log[H⁺]

1.318x10⁻⁴ = [H⁺] = X

Replacing:

[H₂CO₃] = 1.9x10⁻² - 1.318x10⁻⁴ = 1.8868x10⁻²

[HCO₃⁻] = 1.318x10⁻⁴

[H⁺] = 1.318x10⁻⁴

Replacing in ka equation:

Ka = [1.318x10⁻⁴] [1.318x10⁻⁴] / [1.8868x10⁻²]

Answer: 9.2 x 10^-7

Explanation:

Answer:

According to the law of conservation of mass, the mass of the reactants must be equal to the mass of the products

Explanation:

law of conservation of mass

Answer:

3.39e+20

Explanation:

Answer:

144 N

Explanation:

Newton's 3rd Law: "For every action, there is an equal and opposite reaction."

Answer:

thermal shock

Explanation:

the temperatures inside the glass jar should have continued to increase over time. Internal stresses due to uneven heating. This is also known as “thermal shock”.

In general, the thicker the glass, the more prone it will be to breaking due to the immediate differences in temperature across the thickness of glass.

Borosilicate glass is more tolerant of this, as it has a higher elasticity than standard silicon glass.

You may also note that laboratory test tubes and flasks are made with thinner walls, and of borosilicate glass, when designated for heating.

Answer: 18

Explanation:

i think  so

Answer:

A

Explanation:

Answer:

A

Explanation:

Not D or B

The mole is a unit used to measure the amount of a substance. One mole of any substance is defined as the amount of that substance that contains the same number of particles (such as atoms, molecules, or ions) as there are in 12 grams of carbon-12. This number of particles is known as Avogadro's number, which is approximately 6.022 x 10^23 particles per mole.

The molar mass of a substance is the mass of one mole of that substance and is expressed in grams per mole. To determine the number of grams in a mole of a substance, you simply need to calculate the molar mass of the substance by adding up the atomic masses of each atom in its chemical formula.

For example, for carbon monoxide (CO), the atomic mass of carbon is 12.01 g/mol, and the atomic mass of oxygen is 16.00 g/mol. Adding these together gives a molar mass of 28.01 g/mol, which means that one mole of CO has a mass of 28.01 grams.

For helium (He), the atomic mass is 4.00 g/mol, so one mole of helium has a mass of 4.00 grams.

For nitrogen (N2), the atomic mass of nitrogen is 14.01 g/mol, and since there are two nitrogen atoms in each molecule, the molar mass of nitrogen gas is 28.02 g/mol. Therefore, one mole of nitrogen gas has a mass of 28.02 grams.

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The solvent that would be used for extracting the compound from an aqueous solution will be chloroform as it has maximum solubility.

What is solubility?

Solubility is a degree to which the a substance dissolves in a solvent to make a solution. Solubility is expressed as grams of solute per litre of solvent.

Solvent requires 2 grams of compound to dissolve.

Finding solubility

For water, 2g/90ml= 2.22

For chloroform, 2g/7.50= 26.6

For diethyl ether, 2g/32= 6.25

For benzene, 2g/85= 2.35

Partition Coefficients -

For chloroform = 11.98

For Diethyl Ether = 2.81

For Benzene = 1.05

Hence, Chloroform would be chosen to extract compound from an aqueous solution as it has maximum solubility.

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Since chloroform has the greatest solubility, it would be the solvent of choice for removing the compound from an aqueous solution.

What is solubility?

A homogeneous mixture of one or even more solutes in a solvent is referred to as a solution. A typical illustration of a solution is the addition of sugar cubes to a cup of tea or coffee. Solubility is a quality that aids in the dissolution of sugar molecules. Thus, the ability of a substance (solute) to dissolve in a specific solvent can be defined as solubility. Any substance that is dissolved in a solvent and is either solid, liquid, or gas is referred to as a solute.

Compound needs 2 grammes of solvent to dissolve it.
Finding solubility
For water, 2g/90ml= 2.22
For chloroform, 2g/7.50= 26.6
For diethyl ether, 2g/32= 6.25
For benzene, 2g/85= 2.35
Partition Coefficients -
For chloroform = 11.98
For Diethyl Ether = 2.81
For Benzene = 1.05

As a result of its high solubility, chloroform would be used to extract a compound from an aqueous solution.

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The mass of the solid of density 1.75 g/ mole is 116.77g. This is calculated using the expression for density.

Density is defined as the mass per unit of volume of the substance. The symbol used for density is ρ. Basically density is defined as mass divided by volume.

Density = mass/ volume

mass of the liquid = 21.0 g

density of the liquid = 0.865 g/ mole

volume of liquid = mass / density

                            = 21.0 g / 0.865g/ mole

                            = 24.27 ml

The total volume of the solid and liquid together is 91.0 ml.

Total volume = volume of solid + volume of liquid

volume of solid =  total volume - volume of liquid

                           = 91.0ml - 24.27 ml

                           = 66.73 ml

density of the solid= 1.75 g/ mole.

mass = density * volume

         = 1.75 g /mole * 66.73 ml

         = 116.77 g

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No, it does not pass the "fat pencil" test. Therefore, a normal distribution is not a reasonable model. Option B is the correct answer.

The "fat pencil" test is a quick visual check to determine if a dataset can be reasonably approximated by a normal distribution. In this case, the pH readings of wastewater show a significant deviation from a normal distribution. The presence of several low pH values (1.0) and a few high pH values (10.0, 10.5, 11.4) indicate a non-normal distribution with skewness and potential outliers. Therefore, it is not reasonable to model these data using a normal distribution.

Option B is the correct answer.

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The concentration of A decreases and then levels out. Option A

In many chemical reactions, a reactant is consumed as the reaction progresses, leading to a decrease in its concentration over time. The reactant molecules are transformed into products, and as the reaction proceeds, the concentration of the reactant gradually diminishes.

At equilibrium, the concentrations of both reactants and products remain relatively constant over time, although they can coexist.

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Good scientific design involves a. replication and repetition, which is fundamental to gaining understanding by using the scientific method.

Replication and repetition are fundamental in scientific design because they allow for obtaining results that can be tested by using the scientific method and thus validated or refute in the light of new scientific evidence.

Therefore, with this data, we can see that replication and repetition are critical for a good scientific design in order to obtain reproducible results that can be used to develop theories.

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An argumentative, plausible view of the literary work being evaluated is the claim in a literary analysis.

The claim in a literary analysis, which is an interpretation of a literary work, is the author's argument or viewpoint regarding the relevance or meaning of the work.

The assertion needs to be clear, debatable and backed up by textual evidence.

The claim in literary analysis is the main viewpoint or argument that the author is advancing regarding the relevance or meaning of the literary work under consideration.

The assertion should be a reasonable, disputed opinion that can be backed up by textual evidence, and it should be sufficiently detailed to be convincing and understandable to the reader.

For instance, in an interpretation of William Shakespeare's play "Hamlet," a writer can contend that, rather than a lack of courage, Hamlet's hesitation to exact revenge on his father's murderer stems from his desire for justice and his battle with indecision.

This assertion is both plausible and problematic because different readers or critics may interpret Hamlet's actions differently.

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the basic unit of structure and function in all living things.

Answer:

all living things.

Explanation:

The best choice of ketone to use for a crossed aldol reaction with butanal would be ketone B.

The best choice of ketone to use for a crossed aldol reaction with butanal would be ketone B. This is because ketone B has a good leaving group and is capable of undergoing the aldol reaction. The aldol reaction involves the condensation of an aldehyde or ketone with an enolate to form a β-hydroxy carbonyl compound. In this case, the enolate is derived from butanal, and the ketone is the other reactant. Ketones A and C have a poor leaving group and are not suitable for the aldol reaction. Ketones B and C have similar structures, but ketone B is more reactive due to the presence of a methyl group, which stabilizes the enolate intermediate. Therefore, ketone B is the best choice for the crossed aldol reaction with butanal.

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