C is the element symbol for which element?
a. Carbon
b. Cadmium
c. Celenium
d. Chlorine​

Answer:

5.6 g

Explanation:

The computation of the number of grams of silicon is shown below:

But before that we dop the following calculations

Given that

actual yield = 17 g

Now

Percentage of yield = actual yield × 100 ÷ theoretical yield

50 = 17 g × 100 ÷ theoretical yield

So,

theoretical yield = 34 g

Now

The Molar mass of SiCl_4,

MM = 1 × MM(Si) + 4 × MM(Cl)

= 1 × 28.09 + 4 × 35.45

= 169.89 g/mol

And,  

mass of SiCl_4 = 34 g

Also,

mol of SiCl_4 = (mass) ÷ (molar mass)

= 34 ÷ 1.699*10^2

= 0.2001 mol

The Balanced chemical equation is:

S_i + 2 Cl_2 —> SiCl_4

As per the balanced equation

mol of Si formed = moles of SiCl_4

= 0.2001 mol

Molar mass of Si = 28.09 g/mol

mass of Si = number of mol × molar mass

= 0.2001 × 28.09

= 5.6 g

Answer:

The frequency would be 6.88*10^14Hz

\(v=\frac{c}{lambda} = \frac{3.00*10^8 m/s}{4.36*10^-7m}\)

We can solve the equation above to get the answer

The frequency of this radiation should be \(6.88\times 10^{14}\ Hz.\)

Since  A mercury lamp emits radiation with a wavelength of \(4.36 \times 10^{-7}\)m

So here the frequency should be

\(= c \div \lambda\\\\= 3.00 \times 10^{8} \div 4.36 \times 10^{-7} m.\\\\= 6.88\times 10^{14}\ Hz.\)

Hence, we can conclude that The frequency of this radiation should be \(6.88\times 10^{14}\ Hz.\)

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Answer:

a, b and c

Explanation:

To calculate molarity the number of moles and volume in dm3 is needed. So with the mass and molar mass the number of moles can be gotten and hence the molarity when dividing the number of moles by the volume in dm3.

Answer:

D

Explanation:

Answer:

D

Explanation:

Answer:

D. +3

Explanation:

You're Welcome

The electromagnetic spectrum shown in the diagram is describing radiant energy.

The electromagnetic spectrum shows the total range of frequencies or wavelengths that electromagnetic radiation covers or occurs.

The electromagnetic spectrum usually arranges all forms of electromagnetic radiation from that having the shortest wavelength or highest frequency to that having the longest wavelength or lowest frequency or vice versa.

The electromagnetic spectrum shown arranges electromagnetic radiation from gamma rays to radio waves.

All forms of electromagnetic radiation possess radiant energy.

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1. The constituent gases of air are:

2. The surrounding air is not seen with the eyes because it is transparent. Air molecules are not visible to the na-ked eye, and they do not scatter or absorb visible light significantly. Therefore, air appears colorless and transparent.

3. To prove that air supports burning, you can perform an experiment with a burning candle. Place a glass jar or bell jar over a lit candle, ensuring that the jar is airtight. As the candle burns, it consumes oxygen from the air inside the jar. Eventually, the candle flame will go out due to the lack of oxygen, proving that air (specifically oxygen) is necessary for burning.

4. To show that air occupies space, you can perform a simple experiment using a plastic bottle or syringe. Fill the bottle or syringe with water, ensuring there are no air bubbles. Then, cover the opening tightly and try to compress the air inside. You will find that it is not possible to compress the air significantly, indicating that air occupies space.

5. To prove that air has weight, you can use a sensitive balance or scale. Weigh an airtight container or balloon, and then fill it with air. The weight of the container or balloon with the added air will be greater than its initial weight, demonstrating that air has weight.

6. Air is useful to us in various ways. Three points highlighting the importance of air are:

7. Three properties of air include:

Air exerts force in various ways. For example, air pressure allows objects like airplanes to fly by providing lift. Air resistance or drag opposes the motion of objects moving through the air, creating a force that can affect their speed and trajectory.

8. Four effects of air pollution include:

9. Causes of pollution:

10. Two control measures for air pollution include:

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Answer:

I am so sorry to say this, but I can't see the image

(The boxes in the table)

Answer:

1.sea water 2.fresh water 3. Salt and ice

4.salted roads 5. Sugar solution used for making candy

Explanation:

Because Truck

Answer:

salted roads

sugar something

pure water

Explanation:

trust me bro

The precessional frequency of the compound's non-equivalent hydrogen atoms affects the signals in NMR. The non-equivalent hydrogens exist in an alternative chemical setting.

The (a) compound has three sets of non-equivalent hydrogens. The methyl hydrogens in (1) are in cis to chlorine. Methyl hydrogens, which are trans to chlorine, make up (2). Next to the chlorine atom are the (3) methyl hydrogens.  The compound in (b) contains one set of non-equivalent hydrogens. The environments of the (1) and (1') methyl hydrogens are identical. The (c) compound has one set of non-equivalent hydrogens. The environments of the (1) and (1') methyl hydrogens are identical. The compound (d) contains one set of non-equivalent hydrogens. The atmosphere contains both the (1) and (1') methyl hydrogens. The compound (e) contains two sets of non-equivalent hydrogens. The chlorine atom is located at the carbon next to the (1), which is trans to the methyl group. The (2) is cis to the methyl group, and a nearby carbon has a bromine atom.

Hence, frequency of the compound's non-equivalent hydrogen atoms affects the signals in NMR.

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For convenience, assume that we have 100 g of this unknown compound. Given the percent composition, we can then assume that we have 7.79 g C and 92.21 g Cl.

Next, convert these masses to moles.

For C: (7.79 g) ÷ (12.01 g/mol) = 0.6486 mol C.

For Cl: (92.21 g) ÷ (35.453 g/mol) 2.601 mol Cl.

Now, we divide each molar quantity by the smaller of the two (in this case, that'd be 0.6486 mol C) to obtain a whole-number subscript—what we're doing here is finding the ratio of the moles of each element.

0.6486 mol C/0.6486 = 1

2.601 mol Cl/0.6486 = 4.010 ≈ 4.

What we have now are the mole ratios that would comprise the subscripts of the empirical formula of our compound, which would be CCl₄. But the empirical formula and molecular formula are not necessarily the same; the empirical formula gives us the simplest ratios between the atoms, but the molecular formula (and the actual compound) may have a ratio that's larger. To figure out the factor by which our ratios differ, we divide the molar mass of the actual compound by the molar mass of the empirical compound. The molar mass of the actual compound is given to us as 152 g/mol (that's a typo in the question); the molar mass of the empirical compound is 153.82 g/mol.

Now, just from looking at it, we should be able to tell that the quotient is approximately equal to one. Precisely, it's 152/153.82 = 0.988 ≈ 1.

So, in this case, our empirical and molecular formulae are the same. Thus, the molecular formula of our compound is CCl₄.

Answer:

Molecular Formula: CCl4

Explanation:

First, in order to find the molecular formula, we have to find the empirical formula.

We need to convert the percentages of each element to grams, and then moles. Usually, for problems like these, since we don't already have the chemical formula, we assume that the percents are in grams...

7.79% C becomes 7.79 grams of Carbon, and

92.21% Cl becomes 92.21 grams of Chlorine.

Now that we have grams, we can convert to moles.

The amu of Carbon is 12.01 g, and the amu of Chlorine is 35.45 g.

Carbon in moles = \((7.79 g C)(\frac{1 mol C}{12.01 g C}) =0.6486261449 = 0.65 \\\)

Chlorine in moles = \((92.21 g Cl)(\frac{1 mol Cl}{35.45 g Cl}) = 2.60112835 = 2.6\)

Now that we have the moles, we want to keep these as subscripts and write them into an empirical formula.

Since these numbers are in decimal formula, we have to divide them by the smallest mole in order to get a whole-number for our subscripts.

0.65/0.65 = 1, so the subscript for carbon is 1 (which can just be written as C with nothing next to it)

2.6/0.65 = 4, so the subscript for chlorine is 4 (which can be written as Cl4)

Now we will write our empirical formula as \(C Cl_{4}\).

In order to find our molecular formula, we will take the molecular mass (aka the molecular formula's molar mass which is 152) and divide by the mass from the empirical formula. Then we will get another whole-number multiple that we will multiply our subscripts by in order the numbers for the subscripts for our molecular formula.

The total mass from the empirical formula is 153.81

[12.01 + 4(35.45) = 153.81]

152/153.81 = 0.9882322346 which can be rounded to 0.99 or just 1.0..

When we multiply our subscripts by 1.0, they equal 1 and 4 (the same numbers as before), which means that our empirical formula and molecular formulas are the same.

Empirical Formula: CCl4

Molecular Formula: CCl4

Answer:

a.In the garden

Explanation:

Because, inside from garden with big tub like a stock tank on your patio. They grow tubers planted in pots beneath the water and send up stems with rounded leaves and star-shaped blossoms that float on the surface.

I hope it helps to us. Always welcome my youngest sister:). keep learning and God bless.

Answer:

Germanium monoxide

hope this helps :)

A glass of wine costs about $12 at a pub. A 5-ounce glass of wine, or 147 mL, counts as one serving. This indicates that the typical bottle can accommodate five 5-ounce wine glasses. Ten wine glasses can fit within a magnum bottle. 20 glasses of wine fit inside a double-magnum bottle.

A case of 12 wine bottles contains 9 litres, or 2.378 gallons, as a typical wine bottle is 750 millilitres in size. A tonne of grapes yields 150 gallons every tonne, which translates to 150/2.378 gallons each case, or just over 63 cases, of wine. We have a total of 756 bottles, 12 bottles each case.

Since 1 ounce equals slightly under 30 ml, a glass has a volume of 120 ml. A 750 ml bottle of wine will therefore yield slightly more than 6 glasses.

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A heat capacity minus A temperature loss equals B heat capacity minus B temperature gain 9.56 °C

Object A is hotter than Object B, and since they are in direct contact, heat can be conducted between them. The conservation of energy principle states that energy cannot be created or destroyed. The energy that item A expends in this situation can only be transferred to object B.

To calculate the amount of energy transmitted, multiply the heat capacity by the degrees of temperature increase or drop, assuming that the mass of both items is the same. Below is the calculation:

Energy acquired by B = Energy lost by A

A heat capacity minus A temperature loss equals B heat capacity minus B temperature gain.

\(4.37J/degree C * 6.3 C= 2.88 J * TbTb= \frac{(4.37 J/ degree C * 6.3 C) }{ 2.88J}Tb= 9.56 degree C\)

Therefore ,A heat capacity minus A temperature loss equals B heat capacity minus B temperature gain 9.56 °C

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Answer:

Q = 10118.4 j

Explanation:

Given data:

Mass of ice = 30.0 g

Initial temperature of ice = -20°C

Final temperature = 140°C

Energy required = ?

Solution:

The specific heat of ice is 2.108 J/g*°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 140°C -  (-20°C)

ΔT = 160°C

Q = 30.0 g× 2.108 J/g°C ×160°C

Q = 10118.4 j

Answer:

Bohr's model of the hydrogen atom is based on three postulates:

1) An electron moves around the nucleus in a circular orbit,

2) An electron's angular momentum in the orbit is quantised,

3) The change in an electron's energy as it makes a quantum jump from one orbit to another is always accompanied by the emission or absorption of a photon. Bohr's model is semi-classical because it combines the classical concept of electron orbit (postulate 1) with the new concept of quantisation ( postulates 2 and ).

Answer:B. One that occurs on its own

Explanation:

Answer:

Increased

Explanation:

Answer:

One atom of sulfur has a mass of 32.07 AMU; one mole of S atoms has a mass of 32.07 g.

Explanation:

Therefore, the answer should be 32.07 g

Answer:

protein, carbs, and fats.

Explanation:

Those are the three main sources of macronutrients.

(this isn't a chemistry, it's health)

Answer:

fats, carbohydrates and proteins

Explanation:

I don't know, I answered that on my test and it was correct

The balanced chemical equation for the reaction is: H2SO4 + 2KOH → K2SO4 + 2H2O. It can be concluded that the basicity of tetraoxosulphate VI acid is 2.

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Answer:

It is important for us to be able to make hydrogen from seawater instead of pure water for several reasons:

   Abundance: Seawater is abundant and widely available, making it a more sustainable and renewable source of hydrogen compared to pure water, which is often in limited supply.

   Cost-effective: Seawater is a low-cost source of hydrogen, as it does not require the use of fresh water, which can be scarce and expensive in many regions.

   Energy efficient: Seawater contains dissolved salts and minerals, which can be used as catalysts to speed up the water splitting process and make it more energy efficient.

   Environmental impact: Using seawater as a source of hydrogen instead of pure water reduces the amount of freshwater that is used, conserving this precious resource and minimizing the environmental impact of water extraction and transportation.

   Versatility: Seawater can be used as feedstock for various hydrogen production methods such as electrolysis, thermolysis, photocatalysis, and biotechnology.

In summary, being able to make hydrogen from seawater is crucial to address the growing energy demand while also preserving fresh water resources, and also to make hydrogen production more sustainable and cost-effective.

Explanation:

hope this helps

Let us first consider the reaction of zinc and hydoxide ion :

• Zn^2+(s) + 2OH^-1(aq) ↔ Zn(OH)2 (aq)

ratio> 1 : 2 :1

From the above, we can see that the ratio of zinc ion to hydroxide ion is 1:2, the answer is True .

The equilibrium constant for the system at this temperature is\(1.17 × 10^-31 mol^2/L^2\).

For the chemical equation:

N2(g) + O2(g) ⇌ 2NO(g)

The equilibrium mixture at a temperature of 1500 K is determined to contain 6.4 × 10^-3 mol/L of N2,\(1.7 × 10^-3\)mol/L of O2 and 1.1 × 10^-5 mol/L of NO.  First, we need to calculate the concentration of N2 and O2 required to produce

1.1 × 10^-5 mol/L of NO:

2NO(g) = N2(g) + O2(g)

Given that there are 1.1 × 10^-5 mol/L of NO, the number of moles of N2 and O2 are equal since the stoichiometric ratio is 1:1. Therefore:

\(1.1 × 10^-5 mol/L\) = [N2][O2]Kc = \(([NO]^2)/([N2][O2])Kc\)= \((1.1 × 10^-5 mol/L)^2/(6.4 × 10^-3 mol/L)(1.7 × 10^-3 mol/L)Kc\) =

1.17 × 10^-31 mol^2/L^2.

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Answer:0.46

Explanation:

C) It contains the same number of electrons and protons.

She said that the exposure to the radiation in the microwave would have cooked the animal's internal organs. She said: 'It is a horrific case in the fact that the death of the cat would have been prolonged and it is unimaginable what it would have gone through taking some time to die.