The percent composition of carbon in C₆H₁₈ is 80 percent. It can be calculated by using the following formula:
percent composition = (mass of element ÷ mass of compound) × 100Read about another example of how to calculate the percentage composition
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a gas mixture composed of helium and argon has a density of 0.660 g/l at a 755 mmhg and 298 k. part a what is the composition of the mixture by volume?
The composition of the mixture by volume 62.1% He and 37.9% Ar.
PV = nRT
n = mass / mw
substitute and rearrange...
PV = (mass / mw) RT
mw = (mass / V) RT/P
and since density = mass / V
mw = (0.660g /L) x (0.08206 Latm/moleK) x (298K) / (755mmHg x 1atm/760mmHg)
mw = 17.61 g/mole
mole fraction He x molar mass He + mole fraction Ar x molar mass Ar = 17.61
and if we let χHe = mole fraction He.. then (1-χHe) = mole fraction Ar.. ie.
χHe x 4.003 + (1-χHe) x 39.95 = 17.61
-35.95 χHe = - 22.34
χHe = 0.621
χAr = 1-0.621 = 0.379
now.. what about volume well... if both gases are ideal, then PV= nRT ---> V/n = RT/P.. so at the constant T and P.. V/n = a constant.. ie.. V1/n1 = V2/n2.. ie.. V1/V2 = n1/n2..meaning this...
"volume ratio = mole ratio"
so. VHe / VAr = m0les H2 / m0les Ar.
and since mole fraction He = moles He / moles total and mole fraction Ar = moles Ar / moles total...
therefore..
mole fraction He / mole fraction Ar = [moles He / (moles total)] / [ moles Ar / (moles total)] = nHe / nAr
VHe / VAr = χHe / χAr = 0.621 / 0.379...
or if you prefer...
62.1% He and 37.9% Ar
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Which of the following best describes the relationship between the speed of sound and the type of medium?
A.
Sound travels slower in air because of the large distance between air particles
B.
Sound travels slower in solids because of the small distance between solid particles
C.
Sound travels slower in air because of the small distance between air particles
D.
Sound travels slower in solids because of the large distance between solid particles
Answer:
A. Sound travels slower in air because of the large distance between air particles
Explanation:
Sound is a mechanical wave that requires a medium for its propagation. Without a medium, sound cannot go through easily or readily. This implies that sound cannot be propagated through a vacuum.
A vacuum is an empty space without any particles in side. Sound waves travel fastest the most in solids because the particles are dense and close to one another. The speed of sound in air is the least because of the large distance between air particles. Therefore, the speed of sound is medium dependentHow much energy is required to raise the temperature of 2kg of iron from 20 c to 23 c?
20.7 kJ energy is required to raise the temperature of 2kg of iron from 20 c to 23 c.
Specific heat capacity refers to the amount of heat required to raise the temperature of a substance. Specific heat capacity is denoted by c.
The formula is Q = mcΔT
Given:
Mass = 2.00kgc = 449 J/ kg°CΔT = 23°CSolution:
Put the values in the formula given below
Q = mcΔT
Q = (2.00 kg) (449 J/ kg°C) ( 23°C)
Q = 20654 J or Q = 20.7 KJ
Approximately 20.7 kJ heat is required to raise the temperature of 2kg of iron from 20°C to 23°C.
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100 cm³ of a gas at 27°C is cooled to 20°C at constant pressure .Calculate the volume of gas at 20°C.
According to Charle's law, the volume of the given mass of a gas is directly proportional to its absolute temperature provided that the pressure is constant. Mathemically;
\(\begin{gathered} V\alpha T \\ V=kT \\ k=\frac{V}{T} \\ k=\frac{V_1}{T_1}=\frac{V_2}{T_2} \end{gathered}\)where;
V1 and V2 are the initial and final volume of the gas
T1 and T2 are the initial and final temperatures of the gas (in Kelvin)
Given the following parameters:
\(\begin{gathered} V_1=100\operatorname{cm}^3 \\ T_1=27^0C=27+273=300K \\ T_2=20^0C=20+273=293K \\ V_2=\text{?} \end{gathered}\)Substitute the given parameters into the formula;
\(\begin{gathered} V_2=\frac{V_1T_2}{T_1}^{} \\ V_2=\frac{100\times293}{300} \\ V_2=\frac{29300}{300} \\ V_2=\frac{293}{3} \\ V_2=97.67\operatorname{cm}^3 \end{gathered}\)Therefore the volume of the gas at 20°C is approximately 97.67cm³
51 kJ heat is transferred to a pistoncylinder system that loses 12 kJ and the piston produces work. Calculate the amount of work in kJ produced by the system.
In the given scenario, a piston-cylinder system receives 51 kJ of heat and loses 12 kJ. The system produces work, and To calculate work we can use W = Q - ΔU formula
The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system. Mathematically, this can be represented as:
ΔU = Q - W
Where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.
In this case, the system receives 51 kJ of heat (Q = 51 kJ) and loses 12 kJ (Q = -12 kJ). We need to calculate the work done by the system (W).
Using the first law of thermodynamics equation, we can rearrange it to solve for W:
W = Q - ΔU
Since the change in internal energy (ΔU) is not given, we cannot directly calculate the work done. Additional information about the change in internal energy or any other relevant parameters would be required to determine the amount of work produced by the system.
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what is the energy (in joules) of the photon emitted when the electron of a he cation relaxes from the 3s orbital to the 2s orbital? enter the numerical answer only; do not enter a unit.
the energy emitted by photon was 0.300564×10-18 J
what is photon?
The term photon, which means "light" in Ancient Greek, refers to a basic particle that is a quantum of the electromagnetic field, which includes electromagnetic radiation like light and radio waves. It also serves as the force carrier for the electromagnetic force. Considering that photons have no mass, they always travel at the speed of light in a vacuum, which is 299792458 m/s (or 186,282 mi/s).
formula was
ΔE=R(1n2f−1n2i)
R=the Rydberg constant, 2.178×10-18 J
For a transition from n=3 to n=2, we get
ΔE=2.178×10-18 J(1/22−1/32)
=2.178×10-18 J(1/4−1/9)
=2.178×10-18 J× 9 – 4/9×4
=2.178×10-18 J× 5/36
=0.300564×10-18 J
hence the energy emitted by the photon was 0.00564x10-18J
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5 grams of iron react with 5 grams of oxygen to produce iron 3 oxide. If I produce 5 grams of product what is my percent yield?
Answer:
5 grams of iron react with 5 grams of oxygen to produce iron 3 oxide.
The actual yield of the reaction is--- 5 grams.
What is the percent yield?
Explanation:
The balanced chemical equation of the reaction is:
\(4Fe(s)+3O_{2} (g)->2Fe_{2} O_3(s)\)
1)Identify the limiting reagent.
2)Using the limiting reagent calculate the amount of theoretical yield formed.
Identification of limiting reagent:
4 mol of Fe reacts with 3mol. of O2
that is:
4mol(55.84g/mol) of Fe reacts with ---- 3mol (32.0g/mol)
=223.36g of Fe reacts with ---- 96g. of O2
then,
5g of Fe requires how many grams of O2?
\(=>5g. of Fe * \frac{96g O2}{223.36g Fe} \\=2.14g. of O_{2} .\\\)
But provided 5g of O2.
So, O2 is present more than required.
Hence, O2 is the excess reagent and the limiting reagent is Fe.
The amount of product formed depends only on the amount of Fe only.
Theoretical yield:
From the balanced chemical equation:
4mol. of Fe forms ----- 2mol. of Fe2O3.
that is
223.36g of Fe forms --- 2(159.68g)of Fe2O3.
=>223.36g of Fe forms --- 319.36g of Fe2O3.
then,
5g of Fe forms ----? grams of Fe2O3
\(=>5g of Fe * \frac{319.36g Fe2O3}{223.36g of Fe} \\=7.14g. of Fe2O3\\\)
\(%Error =\frac{actual yield}{theoretical yield} * 100\\\\ %error=\frac{5g}{7.14g} * 100\\ %error =70.0\)% error=actual yield/ theoretical yield x 100
%error=5g./7.14g x100
=>%error=70.0
Hence, the answer is 70.0%.
the half-life of iodine-131 is 8.1 days. how much of a 75.0 mg sample will remain after 24.3 days? group of answer choices 75.0 mg 9.38 mg 4.68 mg 18.8 mg 37.5 mg
After 24.3 days, 3 half-lives of iodine-131 have passed. Therefore, the amount remaining can be found by multiplying the original amount of 75.0 mg by \((1/2)^3\), which equals 9.38 mg. Option B is correct.
The decay of radioactive isotopes can be modeled using the concept of half-life. Half-life is the amount of time it takes for half of the original sample of the isotope to decay.
In this problem, we are given that the half-life of iodine-131 is 8.1 days. This means that after 8.1 days, half of the original sample will remain, and after another 8.1 days, half of that remaining sample will decay, and so on.
We can use this information to find how much of a 75.0 mg sample of iodine-131 will remain after 24.3 days.
First, we need to determine the number of half-lives that have elapsed. To do this, we divide the elapsed time by the half-life:
24.3 days / 8.1 days per half-life = 3 half-lives
So, after 3 half-lives, the amount of iodine-131 remaining can be found by multiplying the original amount (75.0 mg) by \((1/2)^3\) (since 3 half-lives have passed):
Amount remaining = 75.0 mg * \((1/2)^3\)
= 75.0 mg * 0.125
= 9.38 mg
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Complete question:
The half-life of iodine-131 is 8.1 days. how much of a 75.0 mg sample will remain after 24.3 days? group of answer choices
A - 75.0 mg
B - 9.38 mg
C - 4.68 mg
D - 18.8 mg
E - 37.5 mg
The population size of panda
bears increases dramatically
The
population will decrease because
Answer:
it will decrease because there will not be food for all of them and there is very little space for them now so if there is more they will start to fight
Explanation:
there is very little habitat left for panda bears so if there population increases the food and space with be filed
Hello! jamilialves888
I'm glad you asked my name is ✰Tobie✰
And I will help you understand why the population of ⚝pandas ⚝
is decreasing .
-Your answer :βy Tobie
≛So why are pandas going extinct?
One of the main cause is due to the destruction of their own habitat
Since china is a country that is constantly growing their own homes are slowly being destroyed Since their habitats are becoming destroyed it forces them to live in small unhabitable area .
≛This leads to another problem.....
If they are forced to live in a small area there will be less food...
Since there is a shortage of food that will leave the panda's to slowly starve to death since pandas only eat bamboo they could never be able to live anywhere else....Another reason panda's are going extinct is because they are being hunted for their fur.
ex·tinct
/ikˈstiNG(k)t/
_____________
It means that the species does not exist anymore and
are no longer in existence
Hope this helps!
-Tobie <3
ʕ •ᴥ•ʔ
What is the molarity of a solution prepared by dissolving 12.0 g of sodium hydrogen carbonate, NaHCO3, in
water to make 250.0 mL of solution?
Answer:
- 0.57138096 M
- 0.571mol
- 0.571 M NaHCO3
- 0.571 mol/NaHCO3
(these are just different ways to identify the units but they all work and mean the same thing)
Explanation:
- molarity is measured by the ratio of the moles of a solute per liters of a solution
- the formula for molarity is: \(M = \frac{mol (s) solute}{L solution}\)__________________________________________________________
- first, you need to convert 250mL to L so, \(250/1000=0.25\)
- when it comes to converting g to mol you can do it in a separate equation but i prefer to do it all in one equation
__________________________________________________________
- so the equation for this specific problem would be set up like this:\(\frac{12.0g}{.25L} x \frac{1mol}{84.007 g} = x\)
12.0g of NaHCO3.25 L of solution1 mol: 84.007g (the molar mass of NAHCO3)__________________________________________________________
- now to actually solve it:
\(\frac{12.0g}{.25L} x \frac{1mol}{84.007 g} = \frac{12.0}{21.00175} = 0.57138096(or)/0.571mol/0.571 M NaHCO3/(0.571 mol/NaHCO3)\)
you just multiply across so \(12x1=12\) and \(.25x84.007 = 21.00175\) then divide so \(12.0/21.00175 = 0.57138096\)hope this helps :)
How was the work of Newlands similar to that of Mendeleev on the periodic table?
They both arranged the elements in order of increasing atomic mass.
They both arranged elements that had similar properties into groups.
They both predicted the positions of undiscovered elements on the table.
They both placed the relative atomic mass of each element on the table.
Answer:
A. They both arranged the elements in order of increasing atomic mass.
Explanation:
Hope this helps! :)
The work of Newlands similar to that of Mendeleev on the periodic table was that they both arranged the elements in order of increasing atomic mass.
Hence, Option (A) is correct answer.
What is Newland's Law of Octaves ?Newland's Law of Octaves states that if the chemical elements are arranged in increasing order of atomic mass, every eighth element's properties are similar to that of the first element.
What is Mendeleev's Periodic Law ?Mendeleev's Periodic Law states that the chemical and physical properties of elements are a periodic function of their atomic masses.
Now, lets check all options one by one
Option (A): They both arranged the elements in order of increasing atomic mass.
Mendeleev arranged the elements in rows and column of a table in order of their increasing atomic mass. Newland arranged the elements in order of their increasing atomic mass that every eighth element's properties are similar to that of the first element.
So, it is correct option.
Option (B): They both arranged elements that had similar properties into groups.
Newlands arranged the elements that every eighth element's properties are similar to that of the first element. Mendeleev arranged the elements with similar properties in vertical column (group).
So, it is incorrect option.
Option (C): They both predicted the positions of undiscovered elements on the table.
Only Mendeleev predicted the position of undiscovered elements that is Gallium (eka-Aluminium) and Scandium (eka-Boron).
So, it is incorrect option.
Option (D): They both placed the relative atomic mass of each element on the table.
Only Mendeleev placed the relative atomic mass of each element on the table.
So, it is incorrect option.
Thus, we can say that The work of Newlands similar to that of Mendeleev on the periodic table was that they both arranged the elements in order of increasing atomic mass.
Hence, Option (A) is correct answer.
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Acellus Chem HELP Question in picturee I WILL GIVE BRAINLIEST
You can solve this problem using stoichiometry:
The tables is already set for you, so let's solve this using it:
Starting at the 75.0 g, divide it by 44.96:
you are left with 1.668 mol because the g cancel each other out.
Now multiply 1.668 mol with 6.02 × 10²³ atom to be left with
1.0041 mol · atom Sc
1 mol Sc
The mol cancel each other out, so your final rounded answer will be
Answer: 1 × 10²³ atoms Sc
Define the following Physical Properties of Mineral and provide examples:
Transparency
Luster
Color
Luminescence
Fluorescence
Phosphorescence
Specific Gravity
Hardness
Tenacity
Cleavage
Fracture
Magnetic Property
Diamagnetic
Paramagnetic
Ferromagnetic
Electrical Property
Radioactive Property
Optical Property
Friction
Mineral Aggregation
Surface Properties
Transparency - the degree to which light can pass through a mineral. Examples: quartz, calcite.
Luster - the appearance or quality of light reflected from the surface of a mineral. Examples: metallic (galena, pyrite), non-metallic (quartz, calcite).
Color - the color of a mineral when viewed in reflected light. Examples: emerald (green), ruby (red).
Luminescence - the ability of a mineral to emit visible light when stimulated by energy. Examples: fluorite, calcite.
Fluorescence - the ability of a mineral to emit visible light when exposed to ultraviolet light. Examples: fluorite, calcite.
Phosphorescence - the ability of a mineral to emit visible light for a period of time after exposure to energy. Examples: willemite, calcite.
Specific Gravity - the ratio of the weight of a mineral to the weight of an equal volume of water. Examples: galena, hematite.
Hardness - the resistance of a mineral to scratching or abrasion. Examples: quartz (hardness of 7), talc (hardness of 1).
Tenacity - the resistance of a mineral to breaking or deformation. Examples: malleable (gold), sectile (gypsum).
Cleavage - the tendency of a mineral to break along planes of weakness. Examples: mica (perfect cleavage), calcite (good cleavage).
Fracture - the way in which a mineral breaks that is not related to planes of weakness. Examples: conchoidal (obsidian), uneven (halite).
Magnetic Property - the ability of a mineral to attract or repel other magnetic materials. Examples: magnetite, pyrrhotite.
Diamagnetic - minerals that are not attracted to a magnetic field. Examples: quartz, calcite.
Paramagnetic - minerals that are weakly attracted to a magnetic field. Examples: garnet, biotite.
Ferromagnetic - minerals that are strongly attracted to a magnetic field. Examples: magnetite, pyrrhotite.
Electrical Property - the ability of a mineral to conduct electricity. Examples: copper, graphite.
Radioactive Property - the ability of a mineral to emit radiation. Examples: uranium, thorium.
Optical Property - the way in which light interacts with a mineral. Examples: double refraction (calcite), isotropic (garnet).
Friction - the resistance of a mineral to sliding along a surface. Examples: talc (low friction), garnet (high friction).
Mineral Aggregation - the way in which mineral crystals are arranged in a rock. Examples: granular (granite), fibrous (asbestos).
Surface Properties - the way in which the surface of a mineral feels or looks. Examples: smooth (quartz), rough (pyrite).
Physical properties of minerals, transparency: It refers to the ability of a mineral to transmit light through it, luster: It is the appearance of the mineral's surface when light reflects off it.
I can define the following physical properties of minerals and provide examples for each:
Transparency: It refers to the ability of a mineral to transmit light through it. Some minerals are completely transparent, while others may be translucent or opaque. Examples of transparent minerals are diamond, quartz, and calcite.
Luster: It is the appearance of the mineral's surface when light reflects off it. Minerals can have a metallic or non-metallic luster. Metallic luster minerals include pyrite and galena, while non-metallic luster minerals include calcite and feldspar.
Color: It is one of the most noticeable physical properties of minerals, but not always a reliable indicator of a mineral's identity. For example, quartz can come in a variety of colors, including clear, white, purple, pink, and yellow.
Luminescence: It is the ability of a mineral to emit light when exposed to certain types of radiation. Some minerals exhibit fluorescence, which is the emission of light when exposed to ultraviolet radiation. Examples of fluorescent minerals are fluorite and scheelite.
Specific Gravity: It is the ratio of the weight of a mineral to the weight of an equal volume of water. This property helps to identify minerals that have similar appearances but different densities. For example, gold has a high specific gravity of 19.3, while pyrite has a specific gravity of 5.
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Which Statement describes what happens when ice melts,according to The kinetic theory?
Answer: As ice melts into water, kinetic energy is being added to the particles. This causes them to be 'excited' and they break the bonds that hold them together as a solid, resulting in a change of state: solid -> liquid.
Explanation:
Se hacen reaccionar 100 g del agente oxidante con 25 g del agente reductor, según la reacción REDOX LaTeX: N_2\left(g\right)+H_2\left(g\right)\longrightarrow NH_3\left(g\right)N 2 ( g ) + H 2 ( g ) ⟶ N H 3 ( g ) Indique el reactivo en exceso y los gramos de amoniaco formado, si la eficiencia del proceso es del 80 %
Answer:
El reactivo en exceso es hidrógeno
97.12g NH₃ son formados
Explanation:
Basados en la reacción:
N₂(g) + 3 H₂(g) → 2 NH₃(g)
El hidrógeno pasa de estado de oxidación 0 a estado de oxidación +1. Al perder un electrón se oxida y es el agente reductor.
El nitrógeno pasa de estado 0 estado -3. Al ganar 3 electrones se reduce y es el agente oxidante.
100g de N₂ son (Peso molecular: 28g/mol):
100g × (1mol / 28g) = 3.57 moles de N₂
Y 25g de H₂ son (Peso molecular: 2g/mol):
25g × (1mol / 2g) = 12.5 moles de H₂
Como 3 moles de hidrógeno reaccionan por mol de nitrógeno, las moles de nitrógeno que se necesitan para hacer reaccionar completamente 12.5 moles de hidrógeno son:
12.5 moles H₂× (1 mol N₂ / 3 moles H₂) = 4.17 moles de nitrógeno.
Como hay 3.57 moles de nitrógeno, el reactivo en exceso es hidrógeno.
Como el reactivo limitante es el nitrógeno y 1 mol de nitrógeno produce 2 moles de amoniaco, las moles de amoniaco son:
3.57 moles de N₂ × (2 moles NH₃ / 1 mol N₂) = 7.14 moles de NH₃
La masa producida idealmente es:
7.14 mol NH₃ ₓ (17g/mol) = 121.4 g de NH₃. Como la eficiencia del proceso es del 80%:
121.4 g NH₃ × 80% = 97.12g NH₃ son formados
Answer:
Excess reactant: H₂
Mass of produced ammonia, 97.1 g
Explanation:
Identify the reaction:
N₂ + 3H₂ → 2NH₃
We identify the reducing agent and the oxidizing agent:
N₂ changed the oxidation state from 0 to -3. This is the reduction, so it is the oxidizing agent. By the way the H₂ is the reducing agent.
We convert the mass to moles:
100 g / 28 g/mol = 3.57 moles of N₂
25 g / 2 g/mol = 12.5 moles of H₂
Ratio is 1:3. For 1 mol of nitrogen, we need 3 moles of hydrogen
Then, 3.57 moles of N₂ would need (3.57 . 3) / 1 = 10.7 moles
We have 12.5 moles of H₂, so the hydrogen is the excess reactant and the nitrogen is the limiting.
To produce ammonia, the reaction needs 1 mol of N₂, that can produce 2 moles of product
3.57 moles of N₂ will produce (3.57 . 2) / 1 = 7.14 moles of NH₃
As yield reaction is 80%, we will produce 7.14 mol . 0.80 = 5.71 moles
We convert the moles to mass: 5.71 mol . 17 g / 1mol = 97.1 g
Which feature causes a gap in the geologic record?
extrusion
fault
o intrusion
erosion
Answer:
Hi, there the answer is
A)extrusion
Explanation:
The feature that causes a gap in the geologic record is called extrusion.
What is extrusion in geologic record?Sometimes magma can force itself through a crack or fault in the rock at the Earth's surface. It pours out over the Earth's surface in a volcanic eruption. This process is called extrusion. The rocks that form from extruded magma are called extrusive igneous rocks.
Direct Extrusion, Indirect Extrusion, Hydrostatic Extrusion and Lateral or Vertical Extrusion are some types of extrusion.
Lava that hardens on the surface is called an extrusion. The rock layers below an extrusion are always older than the extrusion. Beneath the surface, magma may push into bodies of rock. There, the magma cools and hardens into a mass of igneous rock called an intrusion.
Therefore, The feature that causes a gap in the geologic record is called extrusion.
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Evaluate the integral. (Remember to use absolute values where appropriate. Use C for the constant of integration 17 tan*(x) x? dx Need Help? Read It Submit Answer 11. [0/1 Points] DETAILS PREVIOUS ANSWERS SCALCET9 7.5.052. Evaluate the integral. (Use C for the constant of integration.) /2/697 64 + e* dx X
Answer:
integral of 17 tan*(x) x dx = uv - integral of v du
= (17 tan*(x))(1/2)x^2 - integral of (1/2)x^2 (17 sec^2(x) dx)
= (17/2) tan*(x) x^2 - (17/4) integral of sec^2(x) dx
= (17/2) tan*(x) x^2 - (17/4) tan(x) + C
where C is the constant of integration.
For the second integral, the integral of (64 + e^x)dx, we can integrate each term separately. The integral of 64 dx is simply 64x, and the integral of e^x dx is e^x. Therefore,
integral of (64 + e^x) dx = 64x
Explanation:
Answer has the explaination.
To evaluate the integral of 17 tan(x) x dx, we can use integration by substitution.
Let u = tan(x), then du/dx = sec^2(x) and dx = du/sec^2(x). Substituting these into the integral gives 17∫u du. Integrating u with respect to itself gives (17/2)u^2 + C. Substituting u = tan(x) back in gives the final answer of (17/2)tan^2(x) + C. Don't forget to include the absolute value of tan(x) when necessary. To evaluate the integral, first note the given function: 17tan(x) x^2 dx. We can apply integration by parts, using the formula ∫u dv = uv - ∫v du. Let u = x^2, so du = 2x dx, and let dv = 17tan(x) dx, so v = 17∫tan(x) dx = -17ln|cos(x)|.
Now, uv - ∫v du = -17x^2ln|cos(x)| - ∫(-17ln|cos(x)|)(2x dx). Next, apply integration by parts again on ∫(-17ln|cos(x)|)(2x dx), with u = 2x and dv = -17ln|cos(x)| dx.
Simplify and combine terms, then add C for the constant of integration to obtain the final answer.
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When animals breathe, which of Earth's sphere's are interacting?
What is the electron configuration of chlorine?
Explanation:
[Ne] 3s² 3p⁵
Image result for What is the electron configuration of chlorine?
Atomic number: 17
Symbol: Cl
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Argon
What does an organism's phenotype describe?
Answer:
The term "phenotype" refers to the observable physical properties of an organism; these include the organism's appearance, development, and behavior
An organism's phenotype describe appearance, development, behavior, maybe even levels of hormones or blood cells.
Can someone please help me with this question
Answer:
the second one I think...
Answer:
The answer is the first one.
Acceleration is the change of velocity
Velocity is another term for speed with direction.
Click the game tab at the bottom of the simulation and select level 1. (there is no seesaw balance for this part of the activity.) balance the first equation, and click check to see if you got it right. if you can't balance it in the first try, you can try again. work through the five equations for level 1. click continue to go on to level 2, and later level 3. each level is more difficult than the one before. keep trying until all the equations are balanced. in one or two sentences, describe how you did in the balancing game. in a few more sentences, explain one strategy you learned for balancing more complex equations.
The strategy for balancing the equations is by looking at the number of atoms on each side of the equation and adding coefficients to the molecules.
What is a balanced equation?A balanced equation is an equation for a chemical reaction where the number of atoms for each element in the reaction and the total charge is the same for the reactants and the products,
A strategy that will help balance equations more quickly is balancing by inspection. Here, you look at how many atoms you have on each side of the equation and add coefficients to the molecules to balance out the number of atoms.
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PLEASE HELP ME, CHEMISTRY THANKS! :)
The density of water at 4.00°C is 0.967 g/mL. How many molecules of water are present in a 499.8 mL bottle of water? Express your answer to the correct number of significant figures. Be sure to show all steps completed to arrive at the answer.
Answer:
161.69×10²³ molecules
Explanation:
Given data:
Volume of water = 499.8 mL
Density of water = 0.967 g/mL
Number of molecules of water = ?
Solution:
First of all we will calculate the mass of water.
Density = mass/volume
0.967 g/mL = mass/499.8 mL
Mass = 0.967 g/mL × 499.8 mL
Mass = 483.3 g
Number of moles of water:
Number of moles = mass/molar mass
Number of moles = 483.30 g / 18 g/mol
Number of moles = 26.85 mol
1 mole contain 6.022×10²³ molecules
26.85 mol ×6.022×10²³ molecules / 1mol
161.69×10²³ molecules
Answer:
density of water at 4.00c is 0.967 g/mL. Volume of water=499.8mL
Mass of water=density x volume= 0.967 x 499.8=483.3066g
Number of moles of water molecules in given of water = givenmass/molarmass=483.3066/18=26.85
we know that 1 mole has 6.022 x 1023 molecules of water
so the number of water=6.022 x 1023 x 26.85=161.69 x 1023 =1.62 x 1025 molecules of water is its upto 3 significant figure.
Explanation:
bismuth-211 is a radioisotope. it decays by alpha emission to another radioisotope which emits a beta particle as it decays to a stable isotope. write the equations for the nuclear reactions that occur. first reaction: (f is the isotope and i is the decay particle) a is answer b is answer c is answer d is answer e is answer f is answer g is answer h is answer i is answer second reaction: (w is the isotope and z is the decay particle)
First reaction: Bi-211 (f) → Tl-207 (a) + α (i), where α is an alpha particle. Second reaction: Tl-207 (w) → Pb-207 (stable isotope) + β (z), where β is a beta particle.
In the first reaction, bismuth-211 (Bi-211) decays through alpha emission, producing thallium-207 (Tl-207) and an alpha particle (α). The equation is:
Bi-211 (f) → Tl-207 (a) + α (i)
In the second reaction, thallium-207 (Tl-207), which was produced in the first reaction, decays through beta emission to form a stable isotope, lead-207 (Pb-207), and a beta particle (β). The equation is:
Tl-207 (w) → Pb-207 (stable isotope) + β (z)
These two equations represent the nuclear reactions that occur as bismuth-211 decays to a stable isotope through both alpha and beta emissions.
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in which one of the following pairs will the first system have a higher entropy than the second? assume p and t are the same for each pair, unless stated otherwise. group of answer choices 1 mole he(g); 1 mole kr(g) 1 mole xe(g) at 1 atmosphere; 1 mole xe(g) at 0.5 atmosphere 1 mole ch4(g); 1 mole c2h6(g) 1 mole o2(g); 2 mole o(g) 2 mole o(g); 1 mole o2(g) flag question: question 2
20 one-dollar dollars were randomly distributed among 20 people, or 20 one-dollar bills were randomly divided among 10 entropy .
Which reaction has a higher entropy?Compared to solids or liquids, gases possess higher entropies because of their chaotic mobility.This implies that entropy will alter during a process in which the quantity of gas molecules present changes.
How can you tell if entropy is rising or falling?Entropy increases as a substance transitions from a solid to a liquid to a gas, and by observing the phases of a reactants and products, you can determine if an entropy change was positive or negative.Entropy rises whenever the number of gas moles rises.
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Which ion is formed when an atom of fluorine (f) gains one electron? f–1 f–2 f 1 f 2
Answer:
If a fluorine atom gains an electron, it becomes a fluoride ion with an electric charge of -1.
Explanation:
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In a short paragraph, explain one thing you've learned from the course this year.
Answer:
ive learned about the chart , ive learned about the coolest chemicle reactions and how. the can change colors , ive also learned that chenistrey is all around us since the beginning of life ,and how liquid can turn solid
Explanation:
What is the wavelength (in nm) of an electron with the following kinetic energies? (a) 20.0 ev (no response) nm (b) 200 ev (no response) nm (c) 2.00 kev (no response) nm (d) 20.0 kev (no response) nm (e) 0.200 mev (no response) nm (f) 2.00 mev (no response) nm which of these energies are most suited for study of the nacl crystal structure? (select all that apply.) 20.0 ev 200 ev 2.00 kev 20.0 kev 0.200 mev 2.00 mev none of these
The wavelength of an electron can be calculated using the formula: wavelength = h / (mass of electron * velocity). Since kinetic energy is equal to the mass of the electron multiplied by the velocity squared, we can also calculate wavelength by using the formula: wavelength = h / sqrt(2mass of electron kinetic energy).
To convert the kinetic energies given in electron volts (eV) to Joules (J), you can use the formula: 1 eV = 1.6 x 10^-19 J
(a) 20.0 eV = 3.2 x 10^-18 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-18 J) = 2.4 x 10^-12 m or 2.4 pm (picometers)
(b) 200 eV = 3.2 x 10^-17 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-17 J) = 2.4 x 10^-11 m or 24 pm
(c) 2.00 keV = 3.2 x 10^-14 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-14 J) = 2.4 x 10^-8 m or 2.4 nm
(d) 20.0 keV = 3.2 x 10^-13 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-13 J) = 2.4 x 10^-7 m or 24 nm
(e) 0.200 MeV = 3.2 x 10^-11 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-11 J) = 2.4 x 10^-5 m or 0.24 nm
(f) 2.00 MeV = 3.2 x 10^-10 J, wavelength = h / sqrt(2mass of electron3.2 x 10^-10 J) = 2.4 x 10^-4 m or 2.4 nm
A lower energy electron will have a longer wavelength, while a higher energy electron will have a shorter wavelength. To study the crystal structure of NaCl, you would need to use a technique such as X-ray diffraction, which typically uses X-rays with energies in the range of a few keV to a few tens of keV. Based on this, 2.00 keV and 20.0 keV energies are most suited for study of the NaCl crystal structure.
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What is a example of a colloid you can see threw?
Answer:
Mayonnaise and blood
Explanation:
Mayonnaise and blood are both examples of colloids.
what type of land use can result in nutrient depletion