Answer:
100 mL of Na2CO3
Explanation:
We'll begin by calculating the number of mole in 1 g of CaCO3. This can be obtained as follow:
Mass of CaCO3 = 1 g
Molar mass of CaCO3 = 100.09 g/mol
Mole of CaCO3 =?
Mole = mass /Molar mass
Mole of CaCO3 = 1/100.09
Mole of CaCO3 = 0.01 mole
Next, we shall determine the number of mole of Na2CO3 needed to produce 0.01 mole of CaCO3.
This is illustrated below:
Na2CO3 + CaCl2 —> 2NaCl + CaCO3
From the balanced equation above,
1 mole of Na2CO3 reacted to produce 1 mole of CaCO3.
Therefore, 0.01 mole of Na2CO3 will also react to produce 0.01 mole of CaCO3.
Next, we shall determine the volume of Na2CO3 needed for the reaction as illustrated below:
Mole of Na2CO3 = 0.01 mole
Molarity of Na2CO3 = 0.1 M
Volume of Na2CO3 solution needed =?
Molarity = mole /Volume
0.1 = 0.01 / volume of Na2CO3
Cross multiply
0.1 × volume of Na2CO3 = 0.01
Divide both side by 0.1
Volume of Na2CO3 = 0.01 / 0.1
Volume of Na2CO3 = 0.1 L
Finally, we shall convert 0.1 L to millilitres (mL). This can be obtained as follow:
1 L = 1000 mL
Therefore,
0.1 L = 0.1 L × 1000 mL / 1 L
0.1 L = 100 mL
Thus, 0.1 L is equivalent to 100 mL.
Therefore, 100 mL of Na2CO3 is needed for the reaction.
The volume of sodium carbonate used in the given reaction is 0.1 liter or 100mL.
How we calculate the volume from molarity?Volume of the solution will be calculated by using the molarity as:
M = n/V, where
n is the moles of solute and this can be calculated as:
n = W/M , where
W = given or required mass
M = molar mass
Given chemical reaction is:
Na₂CO₃ + CaCl₂ → CaCO₃ + 2NaCl
Moles of 1g of CaCO₃ = 1g/100g/mole = 0.01 moles
From the stoichiometry of the reaction, it is clear that same moles of CaCO₃ produced by same moles of used Na₂CO₃.
0.01 moles of CaCO₃ = produced by 0.01 moles of Na₂CO₃
Now we calculate the volume of 0.01 moles and 0.100M of Na₂CO₃ as:
V = n/M
V= 0.01/0.100 = 0.1L or 100mL
Hence 0.1 L is the required volume.
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Select the structure that corresponds
to the molecule name:
aniline
B.
A.
-NH₂
C. both
-NH₂
Enter
Answer:
B- \(C_{6} H_{5} NH_{2}\)Explanation:
Aniline is an organic compound with the formula C6H5NH2. Consisting of a phenyl group attached to an amino group, aniline is the simplest aromatic amine.
Read each situation carefully. Write how energy transformation occurs in each situation. Write your answer on a separate sheet of paper.
1. Gerald just finish his work out at the gym. He ran at the park for 30 minutes and got very sweaty. What energy transformation took place while he was running?
2. Joshua was very hungry when he got home from the school. He decided to make some popcorn in the microwave. What energy transformation allowed Joshua's popcorn to pop?
3. Jeremy shaves every week using a battery powered shaver. What energy transformation shows how the shaver works?
4. Rica studies her lesson before going to bed at night. She makes use of a lampshade in studying her lessons. What energy transformation occurs when she plugged in the lamp shade and turned it on?
5. Dennis used to watch his favorite cartoon character every saturday using the smart television. What energy transformation occurs on the television?
\(tysm \: in \: advance\)
Answer:
1. Mechanical energy
2. Thermal energy
3. electric energy to mechanical energy
4. electrical energy to light
5. electric energy into sound energy and radiant energy
Explanation:
burning 12g of urea raise temp of water by 30C what is the enthalpy of combustion for 1kg urea
The enthalpy of combustion for 1kg of urea is -1223525.84 J/mol.
Urea is a compound that is used in fertilizers and in some plastics.The enthalpy of combustion for urea is the amount of energy that is released when urea is burned. In order to calculate the enthalpy of combustion for 1kg of urea, we need to use the information that is provided to us in the question. Let us start by writing down the balanced equation for the combustion of urea: CO(NH2)2 + 3/2 O2 → CO2 + 2H2O + N2
The balanced equation shows that 1 mole of urea reacts with 1.5 moles of oxygen gas to produce 1 mole of carbon dioxide, 2 moles of water, and 1 mole of nitrogen gas. The enthalpy change for this reaction is equal to the amount of energy that is released when 1 mole of urea is burned.
The heat of combustion (ΔHc) of urea is -632.6 kJ/mol. This means that 632.6 kJ of energy is released when 1 mole of urea is burned. We know that 12g of urea raised the temperature of water by 30°C. We can use this information to calculate the amount of energy that was released when 12g of urea was burned.
The specific heat capacity of water is 4.18 J/g°C. This means that it takes 4.18 J of energy to raise the temperature of 1 gram of water by 1°C. Therefore, it takes 4.18 x 1000 = 4180 J of energy to raise the temperature of 1 kg of water by 1°C.
We know that 12g of urea raised the temperature of water by 30°C. Therefore, the amount of energy that was released when 12g of urea was burned is:
Energy = mass x specific heat capacity x temperature change
Energy = 0.012 kg x 4180 J/kg°C x 30°C
Energy = 1497.6 J
We can now use this information to calculate the enthalpy of combustion for 1kg of urea:
Enthalpy of combustion = energy released / moles of urea burned
Enthalpy of combustion = 1497.6 J / (0.012 kg / 60.06 g/mol)
Enthalpy of combustion = - 1223525.84 J/mol
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What are the products of a chemical reaction?
Answer: Chemical reactions occur when chemical bonds between atoms are formed or broken. The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.
which of the following statements about the combustion of glucose with oxygen to form water and carbon dioxide (c6h12o6 6 o2 → 6 co2 6 h2o) is correct?
a. The entropy of the products is greater than the entropy of the reactants.
b. The reverse reaction, making glucose from water and carbon dioxide, must be an exergonic reaction.
c. This is the process of cellular respiration, an anabolic pathway that releases free energy.
d. The entropy of the universe decreases as the result of this reaction.
e. The free energy lost in this combustion is less than the energy that appears as heat.
The correct statement about the combustion of glucose with oxygen to form water and carbon dioxide is The entropy of the products is greater than the entropy of the reactants.
A combustion reaction is a reaction in which a substance reacts with oxygen gas, releasing energy in the form of light and heat. Combustion reactions must involve O2 as one reactant.
A familiar example of a combustion reaction is a lighted match. When a match is struck along the match box, friction heats the head of the match to a temperature at which the chemicals react and then generate more heat which can escape into the air, and they burn with a flame after reacting with the oxygen.
In the above given question we can see that when combustion reaction of glucose takes place we can see that it produces water and along with that we can also see that carbon dioxide gas is also been released. In the reactant side we can see that there are no gaseous molecules present but we can see that in the product side there are gaseous molecules present, which suggests that randomness of the system is increased.
Hence the entropy of the products would be greater than the reactants.
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The following statements about the combustion of glucose with oxygen to form water and carbon dioxide is the entropy of the product is greater than the entropy of the the reactants.
The combustion reaction is given as :
C₆H₁₂O₆ + 6O₂ ----> 6CO₂ + 6H₂O
The large molecule that is glucose is converted into the small small molecules water and the carbon dioxide. this is the reason the entropy of the product side is greater than the entropy ( the disorder )of the reactants .
Thus, The following statements about the combustion of glucose with oxygen to form water and carbon dioxide is the entropy of the product is greater than the entropy of the the reactants.
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58.2 kg of sand (C = .742 J/g°C) was heated by the sun to raise its temperature from 14°C
to 31°C. How much energy did the sand absorb?
The sand absorbed869,034.8 Joules of energy from the sun to raise its temperature from 14°C to 31°C.
How much energy did the sand absorb?To calculate the energy absorbed by the sand, we can use the formula:
Q = m * C * ΔT
where:
Q = energy absorbed (in Joules)m = mass of the sand (in grams)C = specific heat capacity of the sand (in J/g°C)ΔT = change in temperature of the sand (in °C)Given:
Mass of the sand (m) = 58.2 kg = 58,200 g (since 1 kg = 1000 g)
Specific heat capacity of the sand (C) = 0.742 J/g°C
Change in temperature of the sand (ΔT) = 31°C - 14°C = 17°C
Plugging in the values into the formula:
Q = 58,200 g * 0.742 J/g°C * 17°C
Q = 869,034.8 J
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We know that water is purified before it is supplied to our houses. Then why do we have filters installed in our houses? What do they serve?
Answer:
Water filters remove elements that cause drinking water to have an unpleasant taste and smell, such as lead, chlorine and bacteria. Home water filtration system will improve the overall purity, taste and smell of your drinking water. It also lowers the pH level of the water that you drink.
write the structural formula for 2-bromo-3-chloro-4,4-dimethylpentanal
Answer:
Br-CH2-CH(CH3)2-C(Cl)H-CH(CH3)2-CHO
Explanation:
The molecule has a total of 14 carbon atoms, 13 hydrogen atoms, and 1 bromine atom. The carbon atoms are arranged in a chain with a methyl group attached to the second carbon atom, a chlorine atom attached to the third carbon atom, and two methyl groups attached to the fourth carbon atom. The fifth carbon atom has a carbonyl group attached to it.
The molecule is an aldehyde, which means that it has a carbonyl group (C=O) at the end of the chain. The carbonyl group is polar, and the oxygen atom has a partial negative charge. The hydrogen atom has a partial positive charge. This polarity makes the aldehyde group susceptible to nucleophilic attack.
The bromine and chlorine atoms are both electrophilic, which means that they have a partial positive charge. This makes them susceptible to nucleophilic attack.
The methyl groups are non-polar and do not have any significant reactivity.
The molecule is a chiral molecule, which means that it has a mirror image that is not superimposable on itself. This is because the carbon atom with the carbonyl group is attached to four different groups.
The molecule is a liquid at room temperature and has a strong odor. It is used in a variety of products, including perfumes, flavorings, and plastics.
Which of the following are examples of QUALITATIVE data? (seiect all that apply)
None these is qualitative data
The sound of a person's voice
The weight of person
The hair color of a person
The body temperature of a person
Answer:
The hair color of a person
Explanation:
The correct answer would be the hair color of a person.
Qualitative data are data that cannot be measured with any instrument but can only be used to characterize. Unlike quantitative data, these kinds of data can only be observed and recorded but cannot be assigned numerical values, except if coded.
The sound of a person's voice can be quantitative on one hand and qualitative on the other. The intensity of a sound can be measured using a decibel meter and quantitatively assigned a figure, whereas, the quality of the sound can only be characterized and not measured.
Both the weight and the body temperature of a person can be measured using a weighing balance and a thermometer respectively and hence, are considered to be quantitative data when collected.
The color of the hair of a person cannot be measured but can only be observed and characterized. Hence, hair color data constitute qualitative data.
Answer:
hair color
Explanation:
propose explanations for the trends you have described for ionic radii within groups and across periods
Ionic radii are a measure of the size of ions, which are atoms or molecules that have gained or lost electrons and therefore have a net electric charge. The ionic radii of elements within a group or a period can show certain trends due to the properties of the elements and the way in which their electron configurations change.
Within a group:
Within a group, ionic radii tend to increase as you go down the group. This is because elements in the same group have the same number of valence electrons (the electrons in the outermost energy level of an atom), but as you go down the group, the number of energy levels (shells) increases. This means that the outermost electrons are farther away from the nucleus, which leads to a larger atomic radius. When an atom loses or gains an electron to become an ion, the ionic radius will be similar to the atomic radius, so the ionic radii of elements within a group will also increase as you go down the group.
Across a period:
Across a period, ionic radii tend to decrease as you go from left to right. This is because elements in the same period have the same number of shells, but as you go from left to right, the number of protons (and therefore the atomic number) increases. This increases the positive charge of the nucleus, which attracts the electrons more strongly. As a result, the electrons are held closer to the nucleus, leading to a smaller atomic radius. When an atom loses or gains an electron to become an ion, the ionic radius will be similar to the atomic radius, so the ionic radii of elements across a period will also decrease as you go from left to right.
It is important to note that these trends are not always absolute and there can be some exceptions due to other factors such as electron shielding and the electron configurations of the elements.
There are several explanations for the trends in ionic radii within groups and across periods in the periodic table:
Within groups: Ionic radii generally increase as you move down a group. This is because the atomic radii of the elements in a group generally increase as you move down the group. This is due to the increasing number of energy levels and valence electrons as you move down the group. As the atomic size increases, the ionic size also increases.Across periods: Ionic radii generally decrease as you move from left to right across a period. This is because the atomic size generally decreases as you move from left to right across a period due to the increasing effective nuclear charge (the number of protons in the nucleus) and the decreasing number of energy levels. As the atomic size decreases, the ionic size also decreases.Charge: The ionic charge also plays a role in determining the ionic radius. For a given element, the ionic radius will generally be larger for a lower charge and smaller for a higher charge. This is because a higher charge leads to a stronger attractive force between the positive nucleus and the negative electrons, leading to a smaller size.Structure: The type of crystal structure can also affect the ionic radius. For example, cations in a cubic crystal structure generally have a smaller ionic radius than those in a hexagonal crystal structure.Overall, these trends in ionic radii can be explained by the interplay between the atomic size, effective nuclear charge, and the number of valence electrons of the elements.
_HNO3+ Fe+2
2+ H+ +_NO+ Fe+3+ H2O
What is the coefficient for water after the equation is balanced?
Answer: The coefficient for water after the equation is balanced is 2.
Explanation:
The balanced chemical equation must have same charge and same number of atoms on both sides of the equation.
As the given reaction is a redox recation occuring in acidic medium.
\(HNO_3+3Fe^{2+}+3H^+\rightarrow NO+3Fe^{3+}+2H_2O\)
The coefficient for water will be 2 after the equation is balanced.
Why does it mean by methane molecule is symmetrical?
A methane molecule (CH4) is considered symmetrical because it possesses a symmetric structure and exhibits symmetry operations.
Symmetry refers to a balanced arrangement of elements that can be divided into equal parts by a plane, axis, or center. In the case of methane, it exhibits several symmetrical characteristics.
Firstly, methane has a tetrahedral molecular geometry, with the carbon atom at the center and four hydrogen atoms positioned around it. This geometry ensures that the molecule is symmetrical in terms of its spatial arrangement.
Each hydrogen atom is located at one of the vertices of the tetrahedron, forming equal angles and distances with respect to the central carbon atom. This symmetry is maintained regardless of the orientation of the molecule.
Additionally, methane possesses rotational symmetry. It can be rotated around any of the carbon-hydrogen bonds, and the molecule will retain its overall appearance.
The symmetry of methane arises from its molecular structure and the equal distribution of electron density around the central carbon atom. The four hydrogen atoms are bonded to the carbon through sigma bonds, which have a cylindrical symmetry. This balanced arrangement of the atoms contributes to the overall symmetry of the molecule.
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conver 100 g Al to mol
To go from moles to grams, we must divide the given grams by the molar mass of the element. The molar mass of aluminum Al is 26.98g/mol. So the moles of Al will be:
\(molAl=givengAl\times\frac{1molAl}{MolarMass,gAl}\)\(molAl=100gAl\times\frac{1molAl}{26.98gAl}=3.71molAl\)Answer: 100 grams Al are equal to 3.71 moles of Al
HELPPPPP
54.5 g of Ca(NO3)2 was used to create a 1.5 M solution. What is the volume of the solution in ml?
We have already been introduced to solutions. Several chapters ago molarity (M) was introduced. Molarity is measured in moles per liter, or mol/L. A 0.30 M NaCl solution means that there is 0.30 mol NaCl in every liter of solution.
Often chemists have to make solutions; so, doing the calculations necessary to make a certain amount of solution become second nature.
For example:
Make 250 mL of a 0.30 M NaCl solution.
To make the solution we need to calculate the amount of NaCl to dissolve to make 250 mL of solution.
start with 250 mL
The solution is made by adding 4.38 g NaCl to a 250-mL volumetric flask. About 100 mL of water are added and when all the NaCl dissolves water is added up to the line on the volumetric flask.
But molarity is not the only unit we use; so, we need to be able to convert between different units...
Common units of concentration include
<==> <==><==>
% wt.
% vol
molarity (M)
molality (m)
mol fraction
That is, the mol fraction of "a" is the number of moles of "a" present divided by the total number of moles of material in the solution (including the solvent).
There is no simple formula for converting from one concentration unit to the next. In general the first step is to pick a convenient sample size. Then work to change each part of the concentration unit to the new unit. Do not try to do the conversion all at once.
For example,
HCl comes in bottles marked 37 % HCl by weight. The density of the solution is 1.200 g/cm-1. What is the molarity of the solution?
A conveneint sample size is 100 g of solution; convenient because 100 g x 37% = 37 g HCl.
This is the key...you must know the definitions for all the concentration terms
First, convert number of grams of HCl in your sample to number of moles in your sample (the 100 g of solution).
Second, convert g of solution to L of solution.
Third, divide moles by liters and you have molarity.
What is the molality of this solution?
Going from M to m. Since the concentration is in M a convenient sample size is 1 L.
OK, so the first conversion is not a conversion...there are 12 mol HCl present in 1 L of solution.
The second conversion is not as easy as it first appears. Let's use the density of the solution to perform a conversion from volume to mass.
This is NOT the mass that is used in molality. We just determined the mass of the solution; molality uses the mass of the SOLVENT!
The solution is made of a solvent and a solute. So, the mass of solvent can be found by subtracting the mass of the solute from the mass of the solution.
Drag each phrase to show weather it causes water pollution or is an effect of water pollution. (2 points)
Choices:
Algal blooms
Overgrazing
Use of chemical fertilizers to enhance production
High concentration of nitrogen in water
Algal blooms and high concentrations of nitrogen in water are effects of water pollution. Overgrazing and the use of chemical fertilizers cause water pollution.
Water pollutionAlgal blooms are an effect of water pollution. They occur when there is an excessive amount of nutrients, particularly nitrogen and phosphorus, in the water due to pollution. The overgrowth of algae depletes the oxygen levels in the water, which can harm fish and other aquatic animals.
Overgrazing can cause water pollution by increasing the sedimentation rate of waterways. This sedimentation can carry nutrients, bacteria, and other pollutants into the water, which can degrade water quality and cause harm to aquatic life.
The use of chemical fertilizers to enhance production is a cause of water pollution. When fertilizer is overused, it can leach into waterways and cause nutrient pollution, which can lead to algal blooms and other forms of water pollution.
High concentrations of nitrogen in water are often an effect of water pollution. This can be caused by the overuse of fertilizers or the discharge of untreated sewage into waterways. High nitrogen levels can cause algal blooms, which can lead to oxygen depletion and harm aquatic life.
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Answer:
Cause:
: : use of chemical fertilizers to enhance production
: : overgrazing
Effect:
: : high concentration of nitrogen in water
: : algal blooms
Hope this helps ;)
Glucose, C6H12O6, is used to prepare intravenous feeding solutions. What volume of 5.0 % W/V glucose solution can be prepared using 125 g of glucose? Show your working.
Please if the answer is correct, ill give brainliest
250 L of 5.0% w/v glucose solution can be prepared using 125 g of glucose.
We use the below formula to solve our problem,w/v = [ mass of solute (g) / volume of solution (mL) ] × 100
Substitute the values from our problem,5.0 % w/v = [ 125 g / volume of solution (mL) ] × 100
Rearranging the formula, we havevolume of solution (mL) = [ 125 g / 5.0 % w/v ] x 100
Substitute further for w/v,volume of solution (mL) = [ 125 g / (5.0 / 100) ] x 100
Simplify the expression,volume of solution (mL) = [ 125 g / 0.05 ] x 100
Hence, the volume of solution (mL) = 250,000 mL or 250 LA patient provides a urine sample. The density of the patient's urine is 1.0192 g/mL. What is the specific gravity of the urine?
Answer:
1.092
Explanation:
Density = 1.0192 g/mL
oecific gravity = ?
Specific gravity is the ratio of a material's density with that of water.
The density of water at 4 degrees Celsius = 1 g/mL
Specific gravity = 1.0192 / 1 = 1.0192
Because specific gravity is a ratio, it has no dimension.
HỌ5,42
Homework Answered Due Today, 11:59 PM
.
A 5.60E1 g sample of water at 9.910E1 °C is placed in a constant pressure calorimeter. Then, 2.40E1 g of zinc metal at 2.10E1 °C is
added to the water and the temperature drops to 9.70E1 °C. What is the specific heat capacity of the zinc metal measured in this
experiment?
The specific heat capacity of the zinc metal, given that 2.40×10¹ g of zinc metal at 2.10×10¹ °C is added to the water is 0.27 J/gºC
How do i determine the specific heat capacity of the zinc?First, we shall obtain the heat absorbed by the water when the zinc metal was added. This is shown below:
Mass of water (M) = 5.60×10¹ gInitial temperature (T₁) = 9.910×10¹ °CFinal temperature (T₂) = 9.70×10¹ °CChange in temperature (ΔT) = 9.70×10¹ - 9.910×10¹ = -2.1 °CSpecific heat capacity of water (C) = 4.184 J/gºC Heat absorbed by water (Q) =?Q = MCΔT
= 5.60×10¹ × 4.184 × -2.1
= -492.0384 J
Now, we shall determine the specific heat capacity of the zinc metal. Details below:
Heat absorbed by water (Q) = -492.0384 JHeat released by metal (Q) = 492.0384 JMass of zinc metal (M) = 2.40×10¹ gInitial temperature (T₁) = 2.10×10¹ °CFinal temperature (T₂) = 9.70×10¹ °CChange in temperature (ΔT) = 9.70×10¹ - 2.10×10¹ = 76 °CSpecific heat capacity (C) = ?Q = MCΔT
492.0384 = 2.40×10¹ × C × 76
492.0384 = 1824 × C
Divide both sides by 1824
C = 492.0384 / 1824
= 0.27 J/gºC
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When sulfur dioxide forms from two non-metals, a covalent bond results when the electrons are
Answer:
heres your answer
To determine whether a bond is Covalent or Ionic, you must know the difference in electronegativity (a fancy word for describing how good a job a particular element does at attracting new electrons).
Explanation:
What is an example of two organelles that both animal an plant cells share?
(A) nucleus and chloroplasts
(B) mitochondria and cell wall
(C) ribosomes and mitochondria
(D) cell wall and chloroplasts
what is the mass if the density is 2.7 g/ml and the volume is 11mL
Answer:
The answer is 29.7 gExplanation:
The mass of a substance when given the density and volume can be found by using the formula
mass = Density × volumeFrom the question
density = 2.7 g/mL
volume = 11 mL
The mass is
mass = 2.7 × 11
We have the final answer as
29.7 gHope this helps you
2.75 mol of KClO3 decomposes. How many grams of O2 will be produced?
As a result, 2.75 moles of KCLO3 are needed.
How do you locate the KClO3 moles?Divide the mass by the molar mass (122.6g/mole) of KClO3 to get the moles, which is 0.626. To determine the amount of O2 produced, multiply that by the molar ratio: (0.062) x (3/2) = 0.939 moles of oxygen.
The balanced chemical equation for KClO3's breakdown is:
2 KClO3(s) → 2 KCl(s) + 3 O2(g)
The equation states that 3 moles of O2 are created for every 2 moles of KClO3 that break down. Thus, we can apply a ratio to determine how much O2 is generated from 2.75 moles of KClO3:
(3 mol O2 / 2 mol KClO3) x 2.75 mol KClO3
= 4.125 mol O2
Now, we may convert moles to grammes using the molar mass of oxygen:
4.125 mol O2 x 32.00 g/mol
= 132 g O2
Therefore, 2.75 moles of KClO3 will produce 132 grams of O2.
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Calculate the Molar Mass Please select either A,B,C, or D at the end.
To calculate the molar mass of a compound, we first need to get the molar masses of the elements on the compond.
We can check thouse on a periodic table. In this case, we have the atoms Ca, N and O, so:
\(\begin{gathered} M_{Ca}=40.08g\/mol \\ M_N=14.01g\/mol \\ M_O=16.00g\/mol \end{gathered}\)The molar mass of the compound will be the sum of the molar mass of the elements multiplied by the amount of thouse elements are in the compound.
The parenthesis in the formula of Ca(NO₃)₂ means that there are two groups of NO₃, so there are 1 atom of Ca, 2 atoms of N and 6 atoms of O, thus, the molar mass is:
\(\begin{gathered} M_{Ca\mleft(NO_3\mright)_2}=1\cdot M_{Ca}+2\cdot M_N+6\cdot M_O \\ M_{Ca(NO_3)_2}=(1\cdot40.08+2\cdot14.01+6\cdot16.00)g\/mol \\ M_{Ca(NO_3)_2}=(40.08+28.02+96.00)g\/mol \\ M_{Ca(NO_3)_2}=164.10g\/mol\approx164.1g\/mol \end{gathered}\)As we can see, this corresponds to alternative C.
The density of lead is 11.4 g/cm3. Convert the density to lb/ft3. 1 lb = 454.55 g 1 ft = 12 in 1 in = 2.54 cm
When we convert 11.4 g/cm³ to lb/ft³, the result obtained is 707.92 lb/ft³
How to convert 11.4 g/cm³ to lb/cm³454.55 g/cm³ = lb/cm³
Therefore,
11.4 g/cm³ = 11.4 / 454.55
11.4 g/cm³ = 0.025 lb/cm³
How to convert 0.025 lb/cm³ to lb/ft³cm1 ft = 12 in
1 in = 2.54 cm
Thus,
12 in = 12 × 2.54
12 in = 30.48 cm
We can say
1 ft = 30.48 cm
Therefore,
1 ft³ = 30.48³ = 28316.84 cm³
Now, we can convert 0.025 lb/cm³ to lb/ft³ as follow:
(1/28316.85) lb/cm³ = 1 lb/ft³
0.025 lb/cm³ = 0.025 ÷ (1/28316.85) = 0.025 × 28316.85
0.025 lb/cm³ = 707.92 lb/ft³
Thus,
11.4 g/cm³ = 707.92 lb/ft³
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The equation below shows the acid hydrolysis of the ester ethyl ethanoate using an excess of dilute hydrochloric (or sulfuric) acid.
CH3COOCH2CH3 + H2O ⇌ CH3COOH + CH3CH2OH
a. Why is an excess of the acid used?
b. Write the formulae for the products if your hydrolysed methyl propanoate in the same way.
a. To ensure that the acid hydrolysis of an ester proceeds to completion, an excess of dilute hydrochloric (or sulfuric) acid is utilized.
Esters require an acid catalyst to hydrolyze since they are typically less reactive than carboxylic acids.
To ensure that there are enough acid molecules to interact with every ester molecule and cause complete hydrolysis, there is an excess of acid.
b. The equation for the acid hydrolysis of methyl propanoate is:
CH3CH2COOCH3 + H2O ⇌ CH3CH2COOH + CH3OH
The products are propanoic acid and methanol.
What is acid-hydrolysis?When water is added to an acidic chemical reaction, a molecule is broken down. This process is known as acid hydrolysis. Acid hydrolysis is frequently employed in organic chemistry to convert esters into the appropriate carboxylic acids and alcohols. An acid catalyst, such as diluted hydrochloric acid or sulfuric acid, is usually used to catalyze the process. A carboxylic acid and an alcohol are produced as a result of the ester bond being broken during acid hydrolysis by the addition of a hydroxyl group (OH) from water to one of the carbonyl carbon atoms. This reaction is frequently used to create many compounds, including medicines, perfumes, and tastes.learn more about acid hydrolysis here
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Which of the following is true about the two atoms?
The table compares the number of subatomic particles in two atoms.
Atom Q- 3 protons, 3 electrons, 4 neutrons
Atom R- 3 protons, 3 electrons, 3 neutrons
Which of the following is true about the two atoms?
A)They have the same charge and same mass.
B)They have different charges but the same mass
C)They have different charges and different masses.
D)They have the same charge but different masses.
Thanks!
Answer:
The answer is D)They have the same charge but different masses.
The number of neutrons in a nucleus affects the mass of the atom but not its chemical properties. Thus, a nucleus with six protons and six neutrons will have the ...
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Answer: D
Explanation:just did it
A mixture of argon and carbon dioxide gases, in a 9.04L flask at 13C, contains 6.77 g of argon and 12.2 g of carbon dioxide. The partial pressure of carbon dioxide in the flask is atm; and the total pressure in flask is atm
Answer
Explanation
The partial pressure (P) of can be calculated using ideal gas equation: PV = nRT.
Convert 9 gram of h2o into molecules
Helpme
Answer:
3.01×10²³ molecules.
Explanation:
From the question given above, the following data were obtained:
Mass of water, H₂O = 9 g
Molecules of water, H₂O =?
From Avogadro's hypothesis,
1 mole = 6.02×10²³ molecules
Next, we shall determine the mass of 1 mole of water, H₂O.
1 mole of water, H₂O = (1×2) + 16 = 18 g
Thus,
18 g of water, H₂O = 6.02×10²³ molecules
Finally, we shall determine the number of molecules in 9 g of water, H₂O. This can be obtained as follow:
18 g = 6.02×10²³ molecules
Therefore,
9 g = 9 g × 6.02×10²³ molecules / 18 g
9 g = 3.01×10²³ molecules
Thus, 9 g of water, H₂O contains 3.01×10²³ molecules.
If 110. grams of potassium carbonate (K2CO3) is dissolved into 300. mL of solution, what is the molarity of the solution?
Answer:
2.65 M
Explanation:
Convert grams of K₂CO₃ to moles. The molar mass is 138.205 g/mol.
(110 g)/(138.205 g/mol) = 0.796 mol
Convert milliliters of solution to liters.
300 mL = 0.300 L
Divide moles of K₂CO₃ by liters of solution.
0.796 mol/0.300 L = 2.65 mol/L = 0.265 M
Answer:
2.7 M
Explanation:
M=moles of solute/volume of solution (L)
First, you need to calculate the number of moles using the given mass and the molar mass.
110 g138.205 g/mol=0.80 mol
Then, you can solve for molarity using the molarity equation.
M=0.80 mol0.300 L=2.7 M
Remember, you need to convert mL to L before you can calculate molarity.
Let's do this!
Balance each equation so there are the same number of each type of atom on both sides of the
equation There is a chart above each problem to help you count the atoms
First-Count up the
number of atoms you
currently have Write
that number in the
chart for both sides of
the equation
Second-If the
numbers don't match,
try adjusting the
coefficients one at at
time Make sure to
change the number in
the chart
Remember- you can't
change the formulas!
2
Reactants
Mg
M
Mg
LI
Reactants
H
LO +
Products
Mg
N
L
O
H
но →
_Math
Products
LIOH
You should
do this in
pencil
The balanced chemical equations of the reactions are given below:
1. Mg (s) + 2 H₂O (l) ----> Mg(OH)₂ (s) + H₂ (g)
2. 2 Li (s) + 2 H₂O (l) ----> LiOH (aq) + H₂ (g)
What is a balanced equation?A balanced chemical equation is an equation in which the number of moles of atoms of elements in a given reaction is equal to the sum of the number of moles of atoms of each element that is produced.
A balanced chemical equation is in accordance with the law of conservation of mass which states that matter can neither be created nor destroyed.
When balancing chemical equations, numerical coefficients are added in front of moles of atoms of an element or moles of a given compound taking part in the reaction.
The balanced chemical equation of the reaction of magnesium and water as well as the reaction of lithium and water is given below:
Magnesium and water:
Mg (s) + 2 H₂O (l) ----> Mg(OH)₂ (s) + H₂ (g)
Lithium and water:
2 Li (s) + 2 H₂O (l) ----> LiOH (aq) + H₂ (g)
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