The exit velocity of the carbon dioxide is approximately 0.63 m/s.
To determine the exit velocity of carbon dioxide, we can use the generalized enthalpy departure chart.
First, we need to find the enthalpy departure at the inlet and the outlet of the nozzle. From the given information, we know that the inlet conditions are 8 MPa and 450 K. Using the chart, we can find the enthalpy departure at the inlet to be around 1.8. Similarly, the outlet conditions are 2 MPa and 350 K, and the enthalpy departure at the outlet is around 2.8.
Next, we can use the conservation of energy equation to find the exit velocity. Since the nozzle is adiabatic, there is no heat transfer and thus, the change in enthalpy is equal to the work done. Therefore, the change in enthalpy between the inlet and outlet is equal to the kinetic energy of the fluid at the outlet.
Δh = (V2^2 - V1^2)/2
where Δh is the enthalpy departure and V1 and V2 are the velocities at the inlet and outlet, respectively.
Rearranging the equation, we get:
V2 = sqrt(2Δh + V1^2)
Plugging in the values, we get:
V2 = sqrt(2(2.8-1.8) + 0) = 0.63 m/s
Therefore, the exit velocity of the carbon dioxide is approximately 0.63 m/s.
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Each of the two drums and connected hubs of 250 mm radius has a mass of 105 kg and a radius of
gyration about its center of 370 mm. Calculate the angular acceleration of each drum. Friction in each
bearing is negligible.
Answer:
the angular acceleration of each drum depends on the applied force F. If the force is known, then the angular acceleration can be calculated. If the force is not known, then the angular acceleration cannot be calculated.
Explanation:
To find the angular acceleration of each drum, we can use the equation for rotational dynamics:
\(I * alpha = F * r\)
where I is the moment of inertia of the drum, alpha is the angular acceleration, F is the applied force, and r is the distance from the center of rotation to the point where the force is applied.
In this case, the moment of inertia of each drum is given by:
\(I = mr^2\)
where m is the mass of the drum and r is the radius of gyration. Substituting this expression into the equation above, we get:
\((m * r^2) * alpha = F * r\)
Solving for alpha, we find that:
\(alpha = F * r / (m * r^2)\)
Substituting the given values, we find that the angular acceleration of each drum is:
\(alpha = F * 250 mm / (105 kg * (370 mm)^2)\)
This equation can be simplified to:
\(alpha = F / (7.29 * 105 kg)\)
So the angular acceleration of each drum depends on the applied force F. If the force is known, then the angular acceleration can be calculated. If the force is not known, then the angular acceleration cannot be calculated.
what is the impact of colloidal particles in water
Answer:
Colloids are very low diameter particles which are responsible for the turbidity or the color of surface water. Because of their very low sedimentation speed the best way to eliminate them is the coagulation-flocculation processes.
V'r(rms) = Xc √R² + X² ×Vr(rms) Make Xc the subject of the formula..
To make Xc the subject of the formula is Xc = √(Vr(rms)² / (R² + X²))
How to make Xc the subject of the formulaTo make Xc the subject of the formula, we can rearrange the equation step by step:
Vr(rms) = Xc √(R² + X²)
Square both sides of the equation to eliminate the square root:
Vr(rms)² = Xc² (R² + X²)
Divide both sides of the equation by (R² + X²) to isolate Xc:
Xc² = Vr(rms)² / (R² + X²)
Take the square root of both sides to solve for Xc:
Xc = √(Vr(rms)² / (R² + X²))
Therefore, Xc is the subject of the formula.
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What is the difference between a.c and d.c
Answer:
Alternating Current (a.c) can be reversed since it relates to sinusoidal curves while Direct Current (d.c) can not be reversed.
Explanation:
\(.\)
Difference between AC and DC
Electric current flows in two ways as an alternating current (AC) or direct current (DC). In alternating current, current keeps switching directions periodically – forward and backward. While in the direct current it flows in a single direction steadily. The main difference between AC and DC lies in the direction in which the electrons flow. In DC, the electrons flow steadily in a single direction while electrons keep switching directions, going forward and then backwards in AC. Let us learn more differences between them in the next few sections.
Someone answer this please
which indoor pollutant is commonly used in building materials, carpet backing, furniture, foam insulation, plywood, and particle board?
Formaldehyde is a indoor pollutant is commonly used in building materials, carpet backing, furniture, foam insulation, plywood, and particle board.
Pesticides are made comprised of both the active ingredient and chemicals that are used to transport the active agent. These carrier agents are referred to as "inerts" in pesticides because they are not poisonous to the insect that is being targeted, yet some inerts have the potential to harm human health. These substances, referred to as mutagens, work by directly changing the DNA sequence of a cell. Due to their size or structural characteristics, many mutagens are able to pass through nuclear and cellular membranes and interact directly with DNA, usually causing damage. A mixture of tiny liquid and solid particles that are in the air we breathe is referred to as particle pollution.
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The two most important operations that the heap can support are O insert O insert and extract-min/extract-max O heapify O extract-min and extract-max
The two most important operations that the heap data structure can support are O(1) insert and O(log n) extract-min/extract-max.
These operations are critical for maintaining the heap property, which is that the parent node is always greater than or equal to its children (for a max heap) or less than or equal to its children (for a min heap). The insert operation involves adding a new element to the heap, while the extract-min/extract-max operation involves removing the root element (which is either the smallest or largest element in the heap, depending on whether it's a min heap or max heap).
Additionally, the operation of heapify is also important, as it allows us to efficiently convert an unsorted array into a heap in O(n) time complexity. This operation involves reorganizing the elements in the array so that they satisfy the heap property.
Overall, the efficiency of these heap operations makes the heap data structure an important tool in a wide range of applications, such as sorting algorithms, priority queues, and graph algorithms.
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In an international film festival, a penal of 11 judges is formed to judge the best film. At
last two films FA and FB were considered to be the best where the opinion of judges got
divided. Six judges where in favor of FA whereas five in favor of FB. A random sample
of five judges was drawn from the panel. Find the probability that out of five judges,
three are in favor of film FA.Enunciate demerits of classical probability.
Answer:
International Film Festival
Judging the best best film:
a. The probability that out of five judges (random sample), three are in favor of film FA is:
= 33%.
b. The demerits of classical probability are:
1. Classical probability can only be used with events that have definite numbers of possible outcomes.
2. Classical probability can only handle events where each outcome is equally likely.
3. Classical probability is based on the assumption of linear relationship (which is not always true in real life) between the latent variable and observed scores.
Explanation:
a) Number of judges = 11
Number of judges in favor of FA film = 6
Number of judges in favor of FB film = 5
Probability of judges in favor of FA film = 6/11
Probability of judges in favor of FB film = 5/11
Random sample of judges = 5
Probability that out of five judges, three are in favor of film FA = 3/5 * 6/11
= 18/55
= 33%
b) Classical probability is the simple probability showing that each event has equal chance of happening. It can be contrasted with empirical probability that is obtained from experiments.
__________ is an example of an electrical device.
Plug
Cord
Cable
All of the above
Explanation:
is an example of an electrical device.
Cable
10. Consider the following state diagram of control unit, that has four states and two inputs \( x \) and \( y \). Design the control with multiplexer.
To design a control unit with a multiplexer, you need to determine the control signals required for each state transition based on the inputy. Here's a general step-by-step process:
Understand the State Diagram: Study the given state diagram and identify the four states and the transitions between them. Determine the conditions for each transition based on the inputs
Identify Control Signals: Determine the control signals needed for each state transition. These signals control various components or operations in the system.
Define the Inputs to the Multiplexer: Assign the inputs
y to the appropriate select lines of the multiplexer. The number of select lines depends on the number of states or transitions.
Determine the Control Signal Inputs: Assign the control signals to the inputs of the multiplexer. The number of control signal inputs depends on the number of control signals required for the transitions.
Connect the Outputs: Connect the outputs of the multiplexer to the corresponding components or operations that need to be controlled.
Implement the Multiplexer: Use the truth table or Boolean expressions derived from the state diagram to configure the multiplexer. This will determine the appropriate connections between the inputs and outputs.
It is important to note that the actual design of the control unit using a multiplexer requires a detailed understanding of the specific state diagram, inputs, and control signals involved. The above steps provide a general approach, but the implementation details may vary depending on the specific requirements of your system.
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The pilot of a jet transport brings the engines to full takeoff power before releasing the brakes as the aircraft is standing on the runway. The jet thrust remains constant, and the aircraft has a near-constant acceleration of 0.4g. If the takeoff speed is 200 km/h, calculate the distance s and time t from rest to takeoff.
Answer:
The distance from rest to takeoff is 6116 meters, and the time from rest to takeoff is 138.9 seconds.
Explanation:
To calculate the distance and time from rest to takeoff for a jet transport with a constant acceleration of 0.4g, we can use the equations of motion for constant acceleration. The equations for distance and time are:
Distance: s = v0t + 0.5at^2
Time: t = (v - v0)/a
Where s is the distance, v0 is the initial velocity, t is the time, a is the acceleration, and v is the final velocity. In this case, we are given that the initial velocity is 0 (since the aircraft is at rest), the acceleration is 0.4g, and the final velocity is 200 km/h.
To convert the final velocity to meters per second, we need to first convert the velocity from kilometers per hour to meters per second. One kilometer is equal to 1000 meters, and one hour is equal to 3600 seconds, so 200 km/h is equal to 200 * 1000 / 3600 = 55.56 m/s.
We can then plug these values into the equations of motion to calculate the distance and time from rest to takeoff:
Distance: s = 0 * t + 0.5 * 0.4g * t^2
s = 0.2g * t^2
Time: t = (v - v0)/a
t = (55.56 - 0) / 0.4g
t = 138.9 seconds
Therefore, the distance from rest to takeoff is 0.2g * 138.9^2 = 6116 meters, and the time from rest to takeoff is 138.9 seconds.
Question 14 The specific internal energy and enthalpy of an ideal gas are each functions of temperature alone, but its specific entropy depends on two independent intensive properties. Not yet answered Select one: Marked out of 2.00 O True O False P Flag question
The specific internal energy and enthalpy of an ideal gas are each functions of temperature alone, but its specific entropy depends on two independent intensive properties.
True. The specific internal energy and enthalpy of an ideal gas are both functions of temperature alone because they only depend on the molecular motion and interactions of the gas particles. However, the specific entropy of an ideal gas depends on two independent intensive properties, such as temperature and pressure or temperature and volume. This is because entropy is a measure of the energy dispersal or randomness of a system, which can be influenced by multiple factors.
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Why are manhole covers round in most of the cases?
Answer:
Explanation:
Because there are no angles for alignment, the round shape makes these heavy covers easier to put back on once they're taken off. Round covers are also easier to manufacture. But the main reason manhole covers are round is so they won't accidentally fall into the manhole itself.
Nec ________ covers selection of time-delay fuses for motor- overload protection.
Nec Article 430 covers selection of time-delay fuses for motor- overload protection.
What article in the NEC covers motor overloads?Article 430 that is found in National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .
Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.
Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.
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Five bolts are used in the connection between the axial member and the support. The ultimate shear strength of the bolts is 320 MPa, and a factor of safety of 4.2 is required with respect to fracture. Determine the minimum allowable bolt diameter required to support an applied load of P
Answer:
The minimum allowable bolt diameter required to support an applied load of P = 450 kN is 45.7 milimeters.
Explanation:
The complete statement of this question is "Five bolts are used in the connection between the axial member and the support. The ultimate shear strength of the bolts is 320 MPa, and a factor of safety of 4.2 is required with respect to fracture. Determine the minimum allowable bolt diameter required to support an applied load of P = 450 kN"
Each bolt is subjected to shear forces. In this case, safety factor is the ratio of the ultimate shear strength to maximum allowable shear stress. That is to say:
\(n = \frac{S_{uts}}{\tau_{max}}\)
Where:
\(n\) - Safety factor, dimensionless.
\(S_{uts}\) - Ultimate shear strength, measured in pascals.
\(\tau_{max}\) - Maximum allowable shear stress, measured in pascals.
The maximum allowable shear stress is consequently cleared and computed: (\(n = 4.2\), \(S_{uts} = 320\times 10^{6}\,Pa\))
\(\tau_{max} = \frac{S_{uts}}{n}\)
\(\tau_{max} = \frac{320\times 10^{6}\,Pa}{4.2}\)
\(\tau_{max} = 76.190\times 10^{6}\,Pa\)
Since each bolt has a circular cross section area and assuming the shear stress is not distributed uniformly, shear stress is calculated by:
\(\tau_{max} = \frac{4}{3} \cdot \frac{V}{A}\)
Where:
\(\tau_{max}\) - Maximum allowable shear stress, measured in pascals.
\(V\) - Shear force, measured in kilonewtons.
\(A\) - Cross section area, measured in square meters.
As connection consist on five bolts, shear force is equal to a fifth of the applied load. That is:
\(V = \frac{P}{5}\)
\(V = \frac{450\,kN}{5}\)
\(V = 90\,kN\)
The minimum allowable cross section area is cleared in the shearing stress equation:
\(A = \frac{4}{3}\cdot \frac{V}{\tau_{max}}\)
If \(V = 90\,kN\) and \(\tau_{max} = 76.190\times 10^{3}\,kPa\), the minimum allowable cross section area is:
\(A = \frac{4}{3} \cdot \frac{90\,kN}{76.190\times 10^{3}\,kPa}\)
\(A = 1.640\times 10^{-3}\,m^{2}\)
The minimum allowable cross section area can be determined in terms of minimum allowable bolt diameter by means of this expression:
\(A = \frac{\pi}{4}\cdot D^{2}\)
The diameter is now cleared and computed:
\(D = \sqrt{\frac{4}{\pi}\cdot A}\)
\(D =\sqrt{\frac{4}{\pi}\cdot (1.640\times 10^{-3}\,m^{2})\)
\(D = 0.0457\,m\)
\(D = 45.7\,mm\)
The minimum allowable bolt diameter required to support an applied load of P = 450 kN is 45.7 milimeters.
We have that the minimum allowable bolt diameter is mathematically given as
d = 26.65mmFrom the question we are told
Five bolts are used in the connection between the axial member and the support. The ultimate shear strength of the bolts is 320 MPa, and a factor of safety of 4.2 is required with respect to fracture. Determine the minimum allowable bolt diameter required to support an applied load of Assuming P to be P = 425 kN.DiameterGenerally the equation for the stress is mathematically given as
\(\mu= 320/4.2 \\\\\mu= 76.190 N/mm^2\)
Therefore
Force = Stress * area
Force = P/2
F= 425,000 N / 2 = 212,500 N
Hence area of each bolt is given as
212,500 = 76.190*( 5* area of each bolt)
area of each bolt = 557.815
Since
area of each bolt=\pi*d^2/4
\pi*d^2/4 = 557.815
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Which of the following are consequences of burning coal for energy? (mark all that apply) Check All That Apply A. increased levels of CO2 in the atmosphere B. increased heavy metals (lead and mercury) released into the air C. acidified rain D. increased radicals that deplete ozone in the stratosphere:
The following are consequences of burning coal for energy increased levels of CO2 in the atmosphere, increased heavy metals (lead and mercury) released into the air and Acidified rain. The correct options are a, b and c.
Burning coal produces a number of main emissions: Sulphur dioxide (SO2), which causes respiratory conditions and acid rain, Nitrogen oxides (NOx), which cause respiratory diseases and smog, Particulates that cause lung sickness, respiratory diseases, fog, and haze, The main greenhouse gas produced by burning fossil fuels (coal, oil, and natural gas) is carbon dioxide (CO2).
Mercury and other heavy metals have been associated with developmental and neurological harm in both humans and other animals. Power stations produce bottom ash and fly ash as byproducts of burning coal.
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What should a company do to develop a better data culture?
Answer:
Some good ways and popular ways are:
1. Investing in data literacy.
2. Think about cybersecurity.
3. Choosing good and the right tools.
4. Establish metrics that matter.
Explanation:
These all are helpful.
(Hope this helped! Have a great day.)
Two Liquids, A and B, are mixed. A is 5% solids, the rest is water. B is 11% solids; the rest is water. To the mixture is added 18.5 kg of bone-dry solids resulting in a mixture of 2,150 Kg containing 8.25% solids. What were the original amounts of the liquids A and B? Show all work
The original amounts of the liquids A and B based on the information will be 1260kg and 872kg.
What is an equation?An equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario. It is vital to note that an equation is a mathematical statement which is made up of two expressions that are connected by an equal sign.
Based on the information given, let us call the liquids illustrated as A and B, while the weight is in kg.
The first equation is the amount of solids and this will be represented thus:
0.05A + 0.11B + 18.5 = 0.0825(2150) = 177.375
0.05A + 0.11B = 158.875
5A + 11B = 15887.5
The second equation will be represented thus:
A + B + 18.5 = 2150
Collect like terms
A + B = 2150 - 18.5
A + B = 2131.5
Multiplying the equation will be:
6B = 5230
Divide through by 6
6B / 6 = 5230 / 6
B = 872 kg
Therefore, A will be 1260 kg.
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Eugene runs a company that manufactures bricks. The manufacturing process consumes a lot of energy and causes pollution, which type of
bricks is his company manufacturing?
Answer:
D. Fire clay bricks
Explanation:
Just like in the steel mills with the big furnaces that's what causes all the smoke to come out of the stacks
Answer:
d is correct
Explanation:
when flow is fully-develped, the pressure gradient in the axial direction along the center of the pipe is
Answer:
Zero
Explanation:
For this, it is necessary to use the the Hagen-Poiseuille equation, which is a law of physics that describes an incompressible fluid of low viscosity through a tube of constant circular cross-section.
By derivating the Pressure over x it becomes zero
\(\frac{dP}{dx} = 0\)
3. If nothing can ever be at absolute zero, why does the concept exist?
The absolute zero in temperature refers to the minimal possible temperature. It is the temperature at which the molecules of a system stop moving, so it is a really useful reference point.
Why absolute zero can't be reached?It would mean that we need to remove all the energy from a system, but to do this we need to interact with the system in some way, and by interacting with it we give it "some" energy.
Actually, from a quantum mechanical point of view, the absolute zero has a residual energy (so it is not actually zero) and it is called the "zero point". This happens because it must meet Heisenberg's uncertainty principle.
So yes, the absolute zero can't be reached, but there are really good approximations (At the moment there is a difference of about 150 nanokelvins between the absolute zero and the smallest temperature reached). Also, there are a lot of investigations near the absolute zero, like people that try to reach it or people that just need to work with really low temperatures, like in type I superconductors.
So, concluding, why does the concept exist?
Because it is a reference point.It is the theoretical temperature at which the molecules stop moving, defining this as the minimum possible temperature.If you want to learn more about the absolute zero, you can read:
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2
A spring balance pulls with 5 N on a beam of 0.5 m.
What is the torque at the end of the beam?
Answer:
The torque at the end of the beam is 2.5 Nm
Explanation:
Given;
length of beam, r = 0.5 m
applied force, F = 5 N
The torque at the end of the beam is given by;
τ = F x r
where;
τ is the torque
F is applied force
r is length of the beam
τ = 5 x 0.5
τ = 2.5 Nm
Therefore, the torque at the end of the beam is 2.5 Nm
if you can see a copper conductor in a cable what should you do with the cable
If you can see a copper conductor in a cable then Turn off power, Assess damage, Repair or replace with the cable this is what we need to do.
If you can see a copper conductor in a cable, it's important to take the following steps:
1. Turn off power: Disconnect any power sources to ensure safety before handling the cable.
2. Assess damage: Check for any exposed or damaged conductor, which may pose a risk of electrical shock or short circuit.
3. Repair or replace: If the damage is minor, consider repairing the cable by insulating the exposed area with electrical tape. However, if the damage is extensive, it's best to replace the cable entirely to ensure safety and proper functionality.
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air enters a nozzle steadily at 200 kpa and 65°c with a velocity of 35 m/s and exits at 95 kpa and 240 m/s. the heat loss from the nozzle to the surrounding medium at 24°c is estimated to be 3 kj/kg. determine the exit temperature. the gas constant of air is r
Exit temperature ≈ 724.85 K when air enters a nozzle at 200 kPa, 65°C, and exits at 95 kPa, 240 m/s.
To determine the exit temperature of the air in the given scenario, we can use the steady flow energy equation. The equation can be written as:
h1 + (V1^2/2) + (P1/rho1) + Q = h2 + (V2^2/2) + (P2/rho2)
where h1 and h2 are the specific enthalpies at the inlet and outlet respectively, V1 and V2 are the velocities at the inlet and outlet, P1 and P2 are the pressures at the inlet and outlet, rho1 and rho2 are the densities at the inlet and outlet, and Q is the heat loss.
Given:
P1 = 200 kPa
T1 = 65°C = 338 K
V1 = 35 m/s
P2 = 95 kPa
V2 = 240 m/s
Q = 3 kJ/kg
Tsurrounding = 24°C = 297 K
By using the gas constant of air (r = 287 J/(kg·K)), we can solve for T2, the exit temperature.
Simplifying the equation, we have:
h1 + (V1^2/2) + (P1/rho1) + Q = h2 + (V2^2/2) + (P2/rho2)
Using the ideal gas equation, P1/rho1 = r * T1 and P2/rho2 = r * T2, we can rewrite the equation as:
h1 + (V1^2/2) + r * T1 + Q = h2 + (V2^2/2) + r * T2
Since the air is entering and exiting the nozzle steadily (adiabatic process), we can assume that h1 = h2.
Therefore, the equation becomes:
(V1^2/2) + r * T1 + Q = (V2^2/2) + r * T2
Now, we can substitute the given values and solve for T2:
(35^2/2) + (287 * 338) + 3 = (240^2/2) + (287 * T2)
T2 = [(35^2/2) + (287 * 338) + 3 - (240^2/2)] / 287
T2 ≈ 724.85 K
Therefore, the estimated exit temperature of the air is approximately 724.85 K.
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potential difference is the work done in moving a unit positive charge from one point to another in an electric field. State True/False.
Answer:
True
Explanation:
Because the Electric Magnetic Field is the work done per unit charge where other forms of energy is tranferred to electrical energy
1–14 Determinations of the ultimate tensile strength Sut of stainless-steel sheet (17-7PH, condition
TH 1050), in sizes from 0.016 to 0.062 in, in 197 tests combined into seven classes were
Sut (kpsi) 174 182 190 198 206 214 222
f 6 9 44 67 53 12 6
where Sut is the class midpoint and f is the class frequency. Estimate the mean and standard
deviation.
The mean of the ultimate tensile strength (Sut) is 198.61 kpsi
The standard deviation is 9.67 kpsi.
What are the centre of measures?To get mean, we need to calculate the weighted average of the class midpoints using the class frequencies:
Mean = (∑(Sut * f)) / (∑f)
Mean = ((174 * 6) + (182 * 9) + (190 * 44) + (198 * 67) + (206 * 53) + (214 * 12) + (222 * 6)) / (6 + 9 + 44 + 67 + 53 + 12 + 6)
Mean = (1044 + 1638 + 8360 + 13266 + 10918 + 2568 + 1332) / 197
Mean = 42,126 / 197
Mean = 198.609137056
Variance = (∑((Sut - Mean)^2 * f)) / (∑f)
Variance = ((174 - 198.609)^2 * 6 + (182 - 198.609)^2 * 9 + (190 - 198.609)^2 * 44 + (198 - 198.609)^2 * 67 + (206 - 198.609)^2 * 53 + (214 - 198.609)^2 * 12 + (222 - 198.609)^2 * 6) / 197
Variance = 93.5172769391
Variance = 93.52 (approx)
Standard Deviation = √Variance
Standard Deviation = √93.52
Standard Deviation = 9.67057392299
Standard Deviation = 9.67.
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qué es una nube informática
If chestnut hair (E) is dominant over black hair (e), can two horses with black hair produce an offspring with chestnut hair? Explain your answer.
Answer:
No, the offspring of two black horses cannot have chestnut hair. Since the black hair allele is recessive, both parents have to be hz recessive and do not carry the dominant chestnut hair allele. The only allele the parents can pass back to their offspring is the black allele.
Explanation:
Edg. 2022
Answer: The offspring of two black horses cannot have chestnut hair. Since the black hair allele is recessive, both parents have to be his recessive and do not carry the dominant chestnut hair allele. The only allele the parents can pass back to their offspring is the black allele.
Explanation:
a power miter saw combines a miter box with a
Note that a power miter saw combines a miter box with a Circular Saw.
What is a Power Miter Saw?A miter saw, also known as a miter saw, is a saw that is used to produce precise crosscuts and miters in a workpiece by placing a mounted blade on a board.
Power miter saws are intended for angled cuts in moldings, trim work, rafters, and other common carpentry applications. The saws also create straight crosscuts, and when equipped with the correct blade, the flexibility of a miter saw is a vital aspect of a professional carpenter's tool arsenal as well as a DIYer's tool arsenal.
Note:
When the saw is on the ground, do not use it.Cut no smaller than 20 cm (8 in.) pieces...Stock with loose knots, cracks, flaws, or foreign items (e.g., metal stone) should not be cut.Learn more about Power Miter Saw:
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what is crop production definition