Compound X has the formula C8H14.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane. Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?

Answers

Answer 1

Answer:

Compound X has the formula C8H14.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethyl cyclohexane. Treatment of X with ozone followed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O). What is the structure of X?

Explanation:

The degree of unsaturation in the given molecule C8H14 is:

DU=(Cn+1)-Hn/2-Xn/2+Nn/2

where,

Cn=number of carbon atoms

Hn=number of hydrogen atoms

Xn=number of halogen atoms

Nn=number of nitrogen atoms

C8H14:

DU=(8+1)-14/2

=>DU=9-7 =2

Hence, the given molecule will have either two double bonds or one double bond and one ring or two rings.

X reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form a mixture of cis- and trans-1,2-dimethylcyclohexane.

This indicates that the molecule X has one double bond and one ring that is cyclohexane ring.

Treatment of X with ozone follwed by zinc in aqueous acid gives a ketone plus formaldehyde (CH2=O).

So, the molecule has a ring and double bond CH2.

Based on the given data the structure of compound X is shown below:

The reaction sequence is shown below:

Compound X Has The Formula C8H14.X Reacts With One Molar Equivalent Of Hydrogen In The Presence Of A
Compound X Has The Formula C8H14.X Reacts With One Molar Equivalent Of Hydrogen In The Presence Of A

Related Questions

what type of energy is stored as sugars in plant leaves
a. elastic B. chemical C. mechanical D. electrical ​

Answers

Your mom

Explanation:

Calculate the mass of 9.96 times 10 to the power of 26 atoms of tellurium

Answers

Answer:

21121.58 grams

Explanation:

Given, 9.96 times 10 to the power of 26 atoms of tellurium

Convert atoms into moles of tellurium,

As we know, 1 mol= 6.02 *10 to the power of 23 atoms

Hence, 9.96 *10 to the power of 26/ 6.02 *10 to the power of 23= 1654 moles of tellurium

Now, mass= molar mass*moles

As we know, tellurium has a molar mass of 127.6000 g/mol

Mass= 1654 *1277 g/mol

       = 21121.58

The system at equilibrium below is heated.
How does the system adjust to reestablish
equilibrium?
2SO₂(g) + O₂(g) ⇒ 2SO3(g) + 198 kJ

Answers

When the system described above, which involves the reaction of sulfur dioxide (SO₂) and oxygen (O₂) to form sulfur trioxide (SO₃) with the release of 198 kJ of heat, is heated, it disrupts the equilibrium. In response to the increase in temperature, the system will adjust in order to reestablish equilibrium. Here's what happens:

According to Le Chatelier's principle, when a system at equilibrium is subjected to a stress, it will shift in a way that counteracts that stress. In this case, heating the system adds energy to it, which can be viewed as a stress. To counteract the increase in temperature, the system will shift in the endothermic direction, absorbing some of the added heat.

The forward reaction, in which SO₂ and O₂ combine to form SO₃, is an exothermic process since heat is released. By Le Chatelier's principle, increasing the temperature will shift the equilibrium to the left, favoring the reverse reaction (the endothermic direction). This means that some of the SO₃ molecules will decompose back into SO₂ and O₂.

As the system adjusts to reestablish equilibrium, the concentrations of SO₂, O₂, and SO₃ will change. The concentrations of SO₂ and O₂ will increase, while the concentration of SO₃ will decrease. This shift occurs in an attempt to consume some of the excess heat and reduce the temperature back towards the original equilibrium.

Overall, heating the system disrupts the equilibrium, causing a shift towards the reverse reaction. This shift helps absorb the added heat and restore the system to equilibrium by altering the concentrations of reactants and products.

Organic Molecules worksheet

Answers

Answer:

ok

Explanation:

What type of reaction is shown below?
2N₂ + 3H₂ <==>2NH3

A. A reversible reaction
B. A combustion reaction
C. A one way reaction

What type of reaction is shown below?2N + 3H &lt;==&gt;2NH3A. A reversible reactionB. A combustion reactionC.

Answers

The given chemical equation, 2N₂ + 3H₂ <==>2NH3, is an example of a reversible reaction.option A.

The double arrows between the reactants and products indicate that the reaction can proceed in both directions, forming both products and reactants.The reversible reaction, also known as a chemical equilibrium reaction, refers to a chemical reaction that can occur in both forward and reverse directions. It occurs when reactants are converted into products, and the products are also converted back into the original reactants.A reversible reaction can be identified by the symbol “<==>” or “⇌” that appears between the reactants and products in the chemical equation. It denotes that the reaction is in a state of chemical equilibrium. When the reactants and products have achieved equilibrium, the rate of the forward and reverse reactions is equal, and there is no further net change in the amounts of the reactants and products.A combustion reaction is a type of exothermic reaction in which a substance reacts with an oxidizing agent to produce heat and light. A one-way reaction is a type of reaction that occurs in only one direction and cannot be reversed without significant changes to the reaction conditions, such as changing the temperature or pressure.A reversible reaction, unlike a one-way reaction, can occur in both directions and reach equilibrium when the forward and reverse reaction rates are equal.option A.

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Carrie measured mass and another property, X, of three pure samples of the same compound. She recorded her data in the table.



Which of the following best describes property X?

Answers

The property X is an extrinsic property.

What is an extensive property?

The term extensive property refers to the type of property that depends on the amount of the substance present. We must recall that an intensive property does not in any way depend on the number or the amount of the substance present in the sample.

If we have a good look at the table that is being referred to here, we would see that the mass of the substance tends to increase as a certain un named property of the substance X is increasing. This implies that the property X is affected by the mass of the object which is the quantity of matter in the object. This gives us an idea that the property that we are referring to can not be an intrinsic  property since it varies with the mass of the substance that is under study as shown.

We can then conclude that the property X is an extrinsic property.

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Missing parts;

Carrie measured mass and another property, X, of three pure samples of the same compound. She recorded her data in the table. Which of the following best describes property X?

A. X  is an intensive property because it does not vary with the size of the sample.

B. X is an extensive property because it does not vary with the size of the sample.

C. X is an extensive property because it varies directly with the size of the sample.

D. X is an intensive property because it varies directly with the size of the sample.

Carrie measured mass and another property, X, of three pure samples of the same compound. She recorded

At 25 °C a solution has a pOH of 2.33. What is the [H3O + ] for the solution? Is this solution acidic or basic?

Answers

At 25 °C a solution having a pOH of 2.33. The [H₃O⁺] of the solution is 2.08 × 10⁻¹² M, and the solution is basic.

To find the [H₃O⁺] of the solution, we first need to use the relationship between pH and pOH;

pH + pOH = 14

Rearranging the equation, we get;

pH = 14 - pOH

Substituting the given value of pOH into equation, we have;

pH = 14 - 2.33 = 11.67

Next, we use the relationship between pH and [H₃O⁺];

pH = -log[H₃O⁺]

Substituting the value of pH we just calculated, we have;

11.67 = -log[H₃O⁺]

Taking the antilog of both sides, we get;

[H₃O⁺] = 2.08 × 10⁻¹² M

Therefore, the [H₃O⁺] is less than 1 × 10⁻⁷ M, the solution is basic.

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What is a combination of two or more substances that are all solids

Answers

Answer:

Solids cant react to each other because they are the same room temperature

Answer:

A is the correct answer.

Explanation:

A mixture of solids is the correct answer.

How many molecules are present in 3dm^3 of nitrogen dioxide at r.t.p?

Answers

Answer:

At RTP (room temperature and pressure), one mole of any ideal gas occupies a volume of 24.45 dm³. Therefore, we can use the following steps to calculate the number of molecules of nitrogen dioxide in 3 dm³ at RTP:

Calculate the number of moles of nitrogen dioxide in 3 dm³ using the ideal gas law:

PV = nRT

Where:

P = pressure = 1 atm (at standard pressure)

V = volume = 3 dm³

n = number of moles (unknown)

R = gas constant = 0.0821 L atm/(mol K)

T = temperature = 298 K (at standard temperature)

n = PV/RT

n = (1 atm)(3 dm³)/(0.0821 L atm/(mol K) x 298 K)

n = 0.122 mol

Calculate the number of molecules of nitrogen dioxide in 0.122 mol using Avogadro's number:

1 mol of any substance contains 6.022 x 10^23 molecules (Avogadro's number)

Therefore, the number of molecules in 0.122 mol of nitrogen dioxide is:

6.022 x 10^23 molecules/mol x 0.122 mol = 7.35 x 10^22 molecules

Therefore, there are 7.35 x 10^22 molecules of nitrogen dioxide in 3 dm³ at RTP.

Explanation:

Does anyone know Chemistry

Answers

Answer:

so so

Explanation:

this your question?? <_>

Use the balanced chemical equation shown below to complete parts A-D:

molar masses: H2SO4 = 98.09g/mol; Fe = 55.85g/mol; Fe2(SO4)3 = 399.9g/mol; H2 = 2.016g/mol



A. If 67.03g of H2SO4 are reacted with 37.84g of Fe, what is the maximum amount of Fe2(SO4)3 that can be produced? SHOW ALL OF YOUR WORK AND INCLUDE UNITS IN YOUR ANSWER.

B. What is the limiting reactant in this reaction?

C. What is the excess reactant in this reaction?

D. This reaction was conducted in the laboratory with the same starting amounts of both reactants and it produced 64.37g of Fe2(SO4)3. What is the percentage yield for this experiment? SHOW ALL OF YOUR WORK.

Answers

To determine the maximum \(Fe_2(SO_4)_3\) produced, we find the limiting reactant (Fe), calculate theoretical yield (0.3383 mol), and obtain a percentage yield of 47.56%.

A. To determine the maximum amount of \(Fe_2(SO_4)_3\)  that can be produced, we have to identify the limiting reactant and use it to calculate the theoretical yield. The balanced chemical equation for the reaction is: 2 Fe + 3 \(H_2SO_4\) → \(Fe_2(SO_4)_3\)  + 3  \(H_2\)Using the molar masses given in the problem, we can calculate the number of moles of each reactant:67.03 g \(H_2SO_4\) × (1 mol \(H_2SO_4\) / 98.09 g) = 0.6832 mol \(H_2SO_4\) 37.84 g Fe × (1 mol Fe / 55.85 g) = 0.6766 mol FeTo determine the limiting reactant, we need to calculate the number of moles of \(Fe_2(SO_4)_3\) that each reactant can produce if it reacts completely:From the balanced chemical equation, we can see that 3 moles of \(H_2SO_4\) can produce 1 mole of \(Fe_2(SO_4)_3\) , while 2 moles of Fe can produce 1 mole of \(Fe_2(SO_4)_3\) . Therefore: 0.6832 mol \(H_2SO_4\) × (1 mol \(Fe_2(SO_4)_3\) / 3 mol \(H_2SO_4\)) = 0.2277 mol \(Fe_2(SO_4)\) 30.6766 mol Fe × (1 mol \(Fe_2(SO_4)_3\) / 2 mol Fe) = 0.3383 mol \(Fe_2(SO_4)_3\)Based on these calculations, Fe is the limiting reactant because it can produce only 0.3383 mol of \(Fe_2(SO_4)_3\), while \(H_2SO_4\) can produce 0.2277 mol of \(Fe_2(SO_4)_3\).B. The limiting reactant is Fe.C. \(H_2SO_4\) is the excess reactant.D. To calculate the percentage yield, we need to divide the actual yield by the theoretical yield and multiply by 100%. The theoretical yield is the amount of \(Fe_2(SO_4)_3\)  that would be produced if the reaction went to completion based on the limiting reactant. We already calculated the theoretical yield in part A to be 0.3383 mol \(Fe_2(SO_4)_3\) .To calculate the actual yield, we can convert the given mass of \(Fe_2(SO_4)_3\)  to moles and then use the molar mass to convert back to grams:64.37 g \(Fe_2(SO_4)_3\) × (1 mol \(Fe_2(SO_4)_3\)  / 399.9 g) = 0.1609 mol \(Fe_2(SO_4)_3\) The percentage yield is then:Percentage yield = (actual yield / theoretical yield) × 100%Percentage yield = (0.1609 mol / 0.3383 mol) × 100%Percentage yield = 47.56%Therefore, the percentage yield for this experiment is 47.56%.Summary: The balanced chemical equation for the reaction between Fe and \(H_2SO_4\) is:2 Fe + 3 \(H_2SO_4\) → \(Fe_2(SO_4)_3\)  + 3 \(H_2\)To determine the maximum amount of \(Fe_2(SO_4)_3\) that can be produced, we need to identify the limiting reactant and use it to calculate the theoretical yield. Fe is the limiting reactant because it can produce only 0.3383 mol of \(Fe_2(SO_4)_3\) , while \(H_2SO_4\) can produce 0.2277 mol of \(Fe_2(SO_4)_3\) . \(H_2SO_4\) is the excess reactant. The percentage yield for this experiment is 47.56%.

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What is the chemical change that is occurring during the students investigation

Answers

Answer:

Some signs of a chemical change are a change in color and the formation of bubbles. The five conditions of chemical change: color change, formation of a precipitate, formation of a gas, odor change, temperature change.

Find the percent by mass of each element in C12H22O11

STEP 1:

C 12 x 12.01 =

H 22 x 1.00 =

O 11 x 15.99 =

Molar Mass =

Answers

The percent by mass of each element in C12H22O11 is 42.1 % for C, 6.4 % for H, and 51.43 % for O respectively.

The mass consistent with cent is defined as the grams of solute consistent with grams of solution, accelerated with the aid of one hundred to get the share. The Mass in keeping with cent components is expressed as fixing for the molar mass and also for the mass of each detail in 1 mole of the compound. Mass percent is one way of representing the attention of an element in a compound or a component in a mixture

Calculation:-

Molar Mass of C12H22O11 = 342

C 12 x 12.01 = 144.12 / 342 × 100

                   = 42.1 %

H 22 x 1.00 = 22/ 342 × 100 = 6.4 %

O 11 x 15.99 = 175.89/ 342 × 100 = 51.43 %

Mass percentage composition is likewise recognized percent via weight. it's miles abbreviated as w/w%. For a solution, mass percent equals the mass of an element in a single mole of the compound divided with the aid of the molar mass of the compound, increased with the aid of 100%.

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explain why d-block and transition metal should not be used interchangeably ?

Answers

Answer:

The d-block and transition metal are not interchangeable terms because the d-block elements are a subset of the transition metal elements. The transition metals are defined as the elements that have partially filled d orbitals, which includes the d-block elements as well as other elements that have partially filled d orbitals in other blocks, such as lanthanides and actinides. Therefore, while all d-block elements are transition metals, not all transition metals are d-block elements.

Giant planet atmospheres have layers of clouds and aerosols (tiny liquid droplets) made from different chemicals because:
A) convection does not occur on giant planets.
B) the Coriolis effect affects each chemical compound differently.
C) different chemicals condense at different temperatures.
D) the winds are in the outermost layer.

Answers

Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Thus option C is correct option.

What is matter?

Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.

Matter is anything that is made up of atoms. Anything around us that can be physically seen and touched are matter. Ice, water and water vapors are example of matter.

Giant planet atmospheres have layers of clouds and aerosols (tiny liquid droplets) made from different chemicals because different chemicals condense at different temperatures.

Therefore,  option C is correct option.

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The substances Na2CO3, MgSO4, and NH4Cl are all soluble ionic compounds. For each substance, indicate the ions present in an aqueous solution.

Answers

The substances sodium carbonate, magnesium sulphate and ammonium chloride are all ionizes in their solution. The ions of sodium carbonate is Na⁺and CO₃ ²⁻ and the ions of MgSO₄ is Mg²⁺ and SO₄²⁻ and that of NH₄Cl is NH4+ and Cl⁻.

What are ionic compounds ?

Ionic compounds are formed by between metals and non metals. The metals are all electropositive and they can donate their valence electrons to the electronegative nonmetals.

Sodium carbonate is formed by the donation of one electron from the sodium metal to the carbonate ion and the ions formed when it is dissolved in water are Na⁺and CO₃ ²⁻.

Similarly, magnesium sulphate is formed by losing two electrons from Mg and it gains two positive charge and sulphate ions accept those electrons to have two negative charges. Thus the ions are Mg²⁺ and SO₄²⁻.

In the same fashion ammonium chloride, NH₄Cl is ionised into NH4+ and Cl⁻.

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The Haber Process is performed: __N₂ + __H₂__NH,If I start with 35.0 grams of N₂ and 45.0 grams of H₂, how many grams of NH, are produced? HowMuch excess is left over?

Answers

We must first balance the equation, we have two atoms of nitrogen and hydrogen in the reactants, so we must put the coefficient 2 on the side of the products to balance the equation. The balanced equation of the reaction will be:

\(N_2+H_2\rightarrow2NH\)

Now, to find the grams of NH that will be produced, we will follow these steps:

1. We find the moles of N2 and H2 by dividing the grams by the molar mass of each element.

Molar Mass N2=28.0g/mol

Molar Mass H2=2.0g/mol

2. By stoichiometry we find out which is the limiting reactant, we see that for each mole of H2 one mole of N2 reacts, therefore, the limiting reactant will be the one with the least number of moles. The other reactant will be the excess reactant

3. We find the moles of NH using the limiting reactant.

4. We find the grams of NH by multiplying the moles by the molar mass of NH.

5. We find how much of the excess reactant is left by subtracting the initial moles minus the reacting moles.

Let's proceed with the calculations

1. Moles of N2 and H2

\(\begin{gathered} molH_2=givengH_2\times\frac{1molH_2}{MolarMassgH_2} \\ molH_2=45.0gH_2\times\frac{1molH_2}{2.0gH_2}=22.5molH_2 \end{gathered}\)\(\begin{gathered} molN_2=givengN_2\times\frac{1molN_2}{MolarMassgN_2} \\ molN_2=35.0gN_2\times\frac{1molN_2}{28.0gN_2}=1.25molN_2 \end{gathered}\)

2. Limiting reactant

We see that there are 22.5 moles of H2 and 1.25 moles of N2. The ratio N2 to H2 is 1/1, therefore, the limiting reactant will be the one with fewer moles, since it will be consumed faster. Therefore, the limiting reactant is nitrogen.

3. Moles of NH

The ratio NH to N2(Limiting reactant) is 2/1, therefore the moles of NH produced will be:

\(\begin{gathered} molNH=givenmolN_2\times\frac{2molNH}{1molN_2} \\ molNH=1.25molN_2\times\frac{2molNH}{1molN_{2}}=2.5molNH \end{gathered}\)

4. Mass of NH

\(\begin{gathered} MassNH=givenmolNH\times\frac{MolarMass,gNH}{1molNH} \\ MassNH=2.5molNH\times\frac{286gNH}{1molNH}=15.0gNH \end{gathered}\)

5. Excess of H2

\(\begin{gathered} molH_2(LeftOver)=molH_2initial-molH_2react \\ molH_2(LeftOver)=22.5H_2-1.25molhH_2=21.25molH_2 \end{gathered}\)

The mass of H2 left over will be:

\(\begin{gathered} MassH_2=21.25molH_2\times\frac{MolarMass,gH_2}{1mol} \\ MassH_2=21.25molH_2\times\frac{2.0gH_2}{1molH_2}=42.5gH_2 \end{gathered}\)

Answer: 15.0 grams of NH will be produced and the excess will be 42.5g of H2

Which of the following substances contains MOSTLY ionic bonding? A) LIF B) CO2 C) AICI: D) BeCl2 E) Cu​

Answers

Answer: \(LiF\) , \(AlCl_3\) and \(BeCl_2\)

Explanation:

An ionic bond is formed when an element completely transfers its valence electron to another element. The element which donates the electron is known as electropositive element or the metal and the element which accepts the electrons is known as electronegative element or non metal.

A covalent bond is formed when an element shares its valence electron with another element. This bond is formed between two non metals.

\(LiF\) , \(AlCl_3\) and \(BeCl_2\) contain ionic bonds as they aremade up of metals and non metals.

Calculate the density of an object that has the mass of 16 grams and takes up 7 cm3 of space.

Answers

Explanation:

\(density \: = \: mass \: over \: volume \\density \: 16grams \: over \: 7cm {}^{3} \\ density = 2.3g \cm {}^{3} \)

Please answer my question.

Please answer my question.

Answers

When chlorine react in ionic form, it gain one electron as its electronegativity is very high. chlorine form mostly ionic compound.

What is ion?

An atom or molecule is said to be an ion if a number of its electron pairs have been acquired or lost, giving it a net negative or positive electrical charge.

In other terms, a chemical species has an unbalanced ratio of proton (positively charged particles) to electrons (negatively charged particles). When chlorine react in ionic form, it gain one electron as its electronegativity is very high. chlorine form mostly ionic compound.

Therefore, when chlorine react in ionic form, it gain one electron as its electronegativity is very high.

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A recipe calls for 1/4 cup of butter. One ounce (oz) of butter is equivalent to 2 tablespoons (T), and there are 8 oz of butter in 1 cup. Which of the following statements correctly interpret the information provided?

a. The information provided gives the conversion factor 8oz/2T.
b. The information provided gives the conversion factor 8oz/1 cup.
c. The recipe requires 64 T of butter.
d. The recipe requires 4T of butter.

Answers

Answer:

D

Explanation:

8oz=1cup

Xoz=1/4cup

cross multiply

Xoz=8×1/4=2

2oz=1/4cup

1oz=2T

2oz=x

cross multiply

×=2×2=4T

The cup of butter, number of tablespoons and ounces of butter are all in direct proportion with one another. The interpretation of the information provided is:

(b). The information provided gives the conversion factor 8oz/1 cup.

Given that:

\(1\ recipe = \frac{1}{4}\ cup\)

\(1\ oz = 2T\)

\(8\ oz = 1\ cup\)

Multiply both sides of \(1\ oz = 2T\) by 8

\(8 \times 1oz = 8 \times 2T\)

\(8 oz = 16T\)

Substitute 8oz for 1 cup in: \(1\ recipe = \frac{1}{4}\ cup\)

\(1\ recipe = \frac{1}{4} \times 8oz\)

Substitute \(8 oz = 16T\)

\(1\ recipe = \frac{1}{4} \times 16T\)

\(1\ recipe = 4T\)

The interpretations are as follows:

\(1\ recipe = 4T\) means that 1 recipe requires 4T of butter \(8\ oz = 1\ cup\) means that the information provided gives a conversion of 8oz/1 cup

Hence, (b) is correct

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Consider the reaction
2NO(g) + O2(g) = 2NO2(g)
Suppose that at a particular moment during the reaction nitric oxide
(NO) is reacting at the rate of 0.066 M/s. (a) At what rate is NO2
being formed? (b) At what rate is molecular oxygen reacting?

Answers

Answer:

(a) Rate of formation of NO2 is also 0.066M/s

(b) Rate of reaction of O2 gas is 0.033M/s

Explanation:

(a) in one second, according to the equation,

2 moles of NO combines with 2moles of NO2.

Therefore 0.066M NO will still consume 0.066mole NO2.

(b) According to the equation,

2 moles NO consumes 1 mole O2, 0.0666M will consume 0.0333 mole O2

1. What will be the final concentration of the solution indicated that will result from the
following dilutions?
a. 14.0 ml of a 4.2 M Na2CO3 solution is diluted to 86.0 ml.

Answers

Taking into account the definition of dilution, the final concentration of the solution is 0.68 M.

Definition of dilution

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, and the volume of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentrationVi: initial volumeCf: final concentrationVf: final volume

Final concentration

In this case, you know:

Ci: 4.2 MVi: 14 mLCf: ?Vf: 86 mL

Replacing in the definition of dilution:

4.2 M× 14 mL= Cf× 86 mL

Solving:

(4.2 M× 14 mL)÷ 86 mL= Cf

0.68 M= Cf

In summary, the final concentration is 0.68 M.

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How much heat, in kilojoules, must be added to a 580 g aluminum pan to raise its temperature from 25∘C to 150∘C?
---The specific heat capacity for aluminum is 0.897 J/g∘C.
---Round the answer to two significant figures.

Answers

Answer:

Q = 65 kJ

Explanation:

Given that,

Mass, m = 580 g

Initial temperature, \(T_i=25^{\circ} C\)

Final temperature, \(T_f=150^{\circ} C\)

The specific heat capacity for aluminum is 0.897 J/g°C

We need to find the heat added to the aluminium pan so that its heat raised to a temperature from 25°C to 150°C. It is given by :

\(Q=mc\Delta T\\\\Q=580\ g\times 0.897\ J/g^{\circ} C\times (150-25)^{\circ} C\\\\Q=65032.5\ J\)

or

Q = 65.03 kJ

or

Q = 65 kJ

Hence, the heat added to the pan is 65 kJ.

The question is in the photo

The question is in the photo

Answers

The required moles of AgBr precipitate produced by given moles of silver nitrate is 0.0123.

How do we calculate moles from molarity?

Molarity of any solution is define as the moles of solute present in per liter of the solution and it will be represented as:
M = n/V

Given that, molarity of AgNO₃ = 0.250M

Volume of AgNO₃ = 49.5mL = 0.0495L

Moles of AgNO₃ = (0.25)(0.0495) = 0.0123mol

Given chemical reaction is:

2AgNO₃(aq) + CaBr(aq) → 2AgBr(s) + Ca(NO₃)₂(aq)

As it is mention that CaBr is present in excess quantity and AgNO₃ is the limiting reagent so the formation of precipitate will depend on the AgNO₃.

From the stoichiometry of the reaction, it is clear that:

2 moles of AgNO₃ = produces 2 moles of AgBr

0.0123 moles of AgNO₃ = produces 2/2×0.0123=0.0123 moles of AgBr

Hence 0.0123 is the required moles of precipitate.

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Help me answer this please
Are the electrons in the following redox reactions transferred completely from the atoms of one element to the atoms of another or are they only partially transferred?
a. Ca(s) + Cl2(g) → CaCl2(s)
b. 4Cu(s) + O2(g) → 2Cu2O(s)

Answers

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The electrons, in redox reaction get partially transferred by one to another element.

What is redox reaction?

A redox reaction occurs when the oxidation states of the substrate change. The loss of electrons or maybe an increase in the oxidation state of a chemical and its atoms is referred to as oxidation. The gain of electrons or a reduction in the oxidation state of either a chemical or its atoms is referred to as reduction. The oxidation as well as reduction process can be seen in same reaction which is introduced as redox reaction.

What is electrons?

Electron can be considered as sub atomic particle which carry negative charge on it.

The given reactions are:

a. Ca(s) + Cl2(g) → CaCl2(s)

b. 4Cu(s) + O2(g) → 2Cu2O(s)

After transferring two electron in both reaction Ca and Cu it will form  CaCl2 and 2Cu2O.

Therefore, after transferring partially electrons one elements get converted into another kind of molecule

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some uses of sodium bicarbonate​

Answers

Answer:

Sodium bicarbonate is an antacid used to relieve heartburn and acid indigestion. Your doctor also may prescribe sodium bicarbonate to make your blood or urine less acidic in certain conditions. This medication is sometimes prescribed for other uses; ask your doctor or pharmacist for more information.

What is the molality of a solution of naphthalene dissolved in chloroform if the solution has a boiling point of 63.2 °C?

What is the molality of a solution of naphthalene dissolved in chloroform if the solution has a boiling

Answers

Answer:

3.6

Explanation:that is right

How much of the 0.2M solution of NaCl did you dispense to measure out 3.0 grams of NaCl? Please give your answer in units of LITERS, however do not explicitly include any units in your answer.

Answers

The amount, in liters, of the 0.2M NaCl solution required to measure out 3.0 grams of NaCl is 0.25 Liter.

Stoichiometric problem

Recall that the molarity of a solution is the ratio of the number of moles of solutes in the solution to the volume of the solution.

Molarity = number of moles/volume in Liters

Thus, a 0.2M NaCl solution contains 0.2 moles of NaCl in 1 Liter of the solution.

But 3.0 grams of NaCl is needed. Recall that:

Number of moles = mass/ molar mass

3.0 grams of NaCl = 3.0 grams/58.88 g/mole = 0.051 moles

If 1 Liter of the solution contains 0.2 moles of NaCl, then the amount of the solution that will contain 0.051 moles (3.0 grams) will be:

               1 x 0.051/0.2 = 0.25 Liter

The volume of 0.2M NaCl solution required in order to measure out 3.0 grams of NaCl is 0.25 Liter.

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The equilibrium-constant expression is used to describe the concentration of reactants and products for a reaction in dynamic equilibrium. For ideal gases and ideal solutions in homogeneous equilibria, where all reactants and products are in the same phase, the extent to which a particular chemical reaction proceeds to products is given by the equilibrium equation.

aA+bB⇌cC+dD , K=[C]c[D]d[A]a[B]b

where K is the equilibrium constant and the right-hand side of the equation is known as the equilibrium-constant expression.

The concentration of each product raised to its coefficient is divided by the concentration of each reagent raised to its coefficient according the the balanced chemical equation. Therefore, the higher the concentration of products, the larger the value of K will be.

Required:
Identify the proper form of the equilibrium-constant expression for the equation.
N2(g)+O2(g)⇌2NO(g)

Answers

Answer: \(K=\frac{[NO]^2}{[N_2]^1[O_2]^1}\)

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as \(K\)

For the given chemical reaction:

\(N_2(g)+O_2(g)\rightleftharpoons 2NO(g)\)

The expression for \(K\) is written as:

\(K=\frac{[NO]^2}{[N_2]^1[O_2]^1}\)

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