\(6 \log q + \log 2\\\\= \log q^6 + \log 2\\\\= \log(2 q^6)\)
Write the following phrase as an algebraic expression. Use n for a number." three increased by the quotient of a number and two a. 3 + 2 b. 3 + C! 312+ 2) d. 3 + 212
Answer:
Write the following phrase as an algebraic expression. Use n for a number." three increased by the quotient of a number and two a. 3 + 2 b. 3 + C! 312+ 2) d. 3 + 212
Step-by-step explanation:
Write the following phrase as an algebraic expression. Use n for a number." three increased by the quotient of a number and two a. 3 + 2 b. 3 + C! 312+ 2) d. 3 + 212
Answer:
The answer is b. 3 + n / 2
Step-by-step explanation:
Find X (x=4, need work)
Based on the angle of two-tangent theorem, the value of x in the image is: x ≈ 4.
What is the Angle of Two-tangent Theorem?The angle of two-tangent theorem states that when two tangent lines intersect outside of a circle, the angle that they form has a measure equal to half the positive difference between the measures of the arcs intercepted by the angle.
Applying the theorem, we have:
70 = 1/2[(360 - 27x + 2) - (27x + 2)]
140 = 360 - 27x + 2 - 27x - 2
140 = 360 - 54x
140 - 360 = -54x
-220 = -54x
-220/-54 = x
x ≈ 4
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1. Randy paid $3,450 for shares of a corporation that manufactured cell phones. He sold it for
$6,100. Express his capital gain as a percent of the original purchase price. Round to the
nearest tenth of a percent.
well, the capital gain was hmmm 6100 - 3450 = 2650 bucks.
if we take $3450 as the 100%, what's $2650 off of it in percentage?
\(\begin{array}{ccll} amount&\%\\ \cline{1-2} 3450 & 100\\ 2650& x \end{array} \implies \cfrac{3450}{2650}~~=~~\cfrac{100}{x} \\\\\\ \cfrac{69}{53}=\cfrac{100}{x}\implies 69x=5300\implies x=\cfrac{5300}{69}\implies x\approx 76.8\)
Question 5(Multiple Choice Worth 2 points)
(Sample Spaces MC)
Julia had a bag filled with gumballs. There were 2 watermelon, 3 lemon-lime, and 5 grape gumballs. What is the correct sample space for the gumballs in her bag?
A) Sample space = watermelon, watermelon, lemon-lime, lemon-lime, lemon-lime, grape, grape, grape, grape, grape
B) Sample space = watermelon, lemon-lime, grape
C) Sample space = 2, 3, 5
D) Sample space = 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
The sample space is (a) watermelon, watermelon, lemon-lime, lemon-lime, lemon-lime, grape gumballs, grape gumballs, grape gumballs, grape gumballs, grape gumballs
How to determine the sample spaceFrom the question, we have the following parameters that can be used in our computation:
2 watermelon, 3 lemon-lime, and 5 grape gumballs
Rewrite the items according to their frequencies
So, we have the following representation
watermelon, watermelon, lemon-lime, lemon-lime, lemon-lime, grape gumballs, grape gumballs, grape gumballs, grape gumballs, grape gumballs
The above represents the sample space
Hence, the sample space is (a)
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HELP PLEASE I NEED HELPPPP!!!!!!!!!!
two triangles is equal to 12 ft squared
the area of rectangles is equal to 8 ft x 6 ft which will give you 48 feet squared
you add them together to get the total area and you will get 84 feet sqaured
I need help with this ! Anything helps.
which table of values would you use to graph y = 3X^2?
Answer:
y because its y i really dont no
The electric field in the xy-plane due to an infinite line of charge along the z-axis is a gradient field with a potential function
V(x,y)equals=c ln (ro/√ x²+y²)
where c > 0 is a constant and r0 is a reference distance at which the potential is assumed to be 0.
Required:
Find the components of the electric field in the x- and y-directions, where E(x,y) =∇V (x,y )
Answer:
c(x,y)/(x²+y²)
Step-by-step explanation:
Since E(x,y) = -∇V (x,y ) and V(x,y) =c ln (ro/√ x²+y²)
Let ro/√(x²+y²) = u and √(x²+y²) = v
dV/du = c/u = c√(x²+y²)/ro,
du/dv = -ro/(x²+y²) = -ro/² and dv/dx = x/√(x²+y²)
Using the chain rule,
So dV/dx = dV/du × du/dv × dv/dx
= c√(x²+y²)/ro × -ro/(x²+y²) × x/√(x²+y²)
dV/dx = -cx/(x²+y²)
- dV/dx = -(-cx/(x²+y²)) = cx/(x²+y²)
Also, dv/dy = y/√(x²+y²)
Using the chain rule
dV/dy = dV/du × du/dv × dv/dy
= c√(x²+y²)/ro × -ro/(x²+y²) × y/√(x²+y²)
dV/dy = -cy/(x²+y²)
- dV/dy = -(-cy/(x²+y²)) = cy/(x²+y²)
E(x,y) = -∇V (x,y )
= -(dV/dx)i + [-(dV/dy)]j
= [cx/(x²+y²)]i +[ cy/(x²+y²)]j
= c(x,y)/(x²+y²)
The function f(x) = -2(4)²+1 +140 represents the number of tokens a child has x hours after arriving at an arcade.
What is the practical domain and range of the function?
Enter your answer by filling in the boxes to correctly complete the statements. If necessary, round to the nearest hundredth.
The practical domain of the situation is ?
The practical range of the situation is ?
PLEASE HELP ASAP ITS PRETTY EASY I JUST DONT UNDERSTAND (PRE ALGEBRA)
Answer:
Well I think the answe is
1. (1,3) (1,7)
2. (2,-3) (6,-5)
Evaluate the expression when x = 3/4 and y= - 1/2: 2x +y
Answer:
1
Step-by-step explanation:
2(3/4)-1/2=
The 2 cancels out the 4 making it 3/2.
3/2-1/2=2/2
=1
Which graph represents a proportional relationship?
Answer:
the first one
Step-by-step explanation:
.....................................................................................
Answer:
the second graph. Good luck!
Step-by-step explanation:
Which equation is correct?
427 × 3 = 400 × 3 + 20 × 3 + 7 × 3
427 × 3 = 400 + 20 × 3 + 7 × 3
427 × 3 = 400 × 3 + 20 × 3 + 7
427 × 3 = 4,000 × 3 + 200 × 3 + 70 × 3
Answer:
A) 427 × 3 = 400 × 3 + 20 × 3 + 7 × 3
Step-by-step explanation:
\(427*3=(400+20+7)*3=(400*3)+(20*3)+(7*3)\)
Therefore, the first option is correct
A bank wants to estimate the difference in the proportion of its "big" customers who have a second account with a different bank and the proportion of its "small" customers who also have an account with another bank. Of the 200 “big” customers who were randomly selected, 160 claimed to also bank with other banks. Of the 300 “small” customers who were randomly selected, 120 claimed to also bank with other banks.
Based on the 99% confidence interval (0.297, 0.503), is there convincing evidence of a difference in the proportion of “big” bank customers who bank with more than one bank as compared with the “small” customers who bank with more than one bank?
Because
contained in the interval, there is
to believe there
a difference in the proportion of “big” bank customers who bank with more than one bank as compared to the “small” customers who bank with more than one bank.
Yes, based on the 99% confidence interval (0.297, 0.503), there is convincing evidence of a difference in the proportion of "big" bank customers who bank with more than one bank compared to the "small" customers who bank with more than one bank.
The confidence interval (0.297, 0.503) represents the range of values within which the true difference in proportions between the two customer groups is likely to fall with 99% confidence. Since the interval does not include zero (0), we can conclude that there is a statistically significant difference between the proportions.
To further explain, the confidence interval was constructed using the sample proportions and the standard error. The sample proportion for the "big" customers who bank with other banks is 160/200 = 0.8, and for the "small" customers, it is 120/300 = 0.4. The standard error takes into account the sample sizes and proportions, and it measures the uncertainty in the estimation.
Since the confidence interval does not include zero, it indicates that the true difference in proportions is unlikely to be zero. In other words, there is strong evidence that the proportion of "big" bank customers who bank with more than one bank is higher than the proportion of "small" customers who do the same.
Therefore, based on the provided data and the confidence interval, we can conclude that there is convincing evidence of a difference in the proportion of "big" bank customers who bank with more than one bank compared to the "small" customers who bank with more than one bank.
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so confused
DUE SOON PLEASE HELP IM SO CONFUSED
Answer:
1) Mean = $75812.50
Median = $74000
Mode = $73100
2) Mean = 24.5
Median = 24.33333...
Modal class = 29 - 33
Step-by-step explanation:
Definitions
The mode is the most frequently occurring data value.The median is the middle value when all data values are placed in order of size.The mean is the sum of all data values divided by the total number of data values.Question 1Given data:
71500, 74900, 69700, 82300, 78500, 73100, 73100, 83400Mean
\(\begin{aligned}\textsf{Mean}&=\dfrac{71500+74900+69700+82300+78500+73100+73100+83400}{8}\\ &= \dfrac{606500}{8}\\&=75812.50\end{aligned}\)
Median
Place the data values in order of size (smallest to largest):
69700, 71500, 73100, 73100, 74900, 78500, 82300, 83400As there is an even number of data values, the median is the mean of the middle two values:
\(\implies \sf Median=\dfrac{73100+74900}{2}=74000\)
Mode
The most frequently occurring data value is $73100. Therefore:
\(\implies \textsf{Mode} = 73100\)
Question 2With grouped data, we can only estimate the mean and median.
Mean
To find an estimate of the mean, assume that every reading in a class takes the value of the class midpoint.
The number of days is the frequency (f).
Add a class midpoint (x) and an fx column to the table:
\(\begin{array}{|c|c|c|c|}\cline{1-4}\vphantom{\dfrac12} \sf Number\;of\;sales&\textsf{Number of days, $f$}&\textsf{Class midpoint, $x$}&fx\\\cline{1-4}\vphantom{\dfrac12}14-18&5&16&80\\\cline{1-4}\vphantom{\dfrac12}19-23&9&21&189\\\cline{1-4}\vphantom{\dfrac12}24-28&6&26&156\\\cline{1-4}\vphantom{\dfrac12}29-33&10&31&310\\\cline{1-4}\vphantom{\dfrac12}\sf Totals&\sum f=30&&\sum fx=735\\\cline{1-4}\end{array}\)
\(\textsf{Mean}=\dfrac{\sum fx}{\sum f}=\dfrac{735}{30}=24.5\)
Median
To find an estimate for the median, use linear interpolation.
Add a cumulative frequency column to the table:
\(\begin{array}{|c|c|c|}\cline{1-3}\vphantom{\dfrac12} \sf Number\;of\;sales&\textsf{Number of days}&\textsf{Culmulative frequency}\\\cline{1-3}\vphantom{\dfrac12}14-18&5&5\\\cline{1-3}\vphantom{\dfrac12}19-23&9&14\\\cline{1-3}\vphantom{\dfrac12}24-28&6&20\\\cline{1-3}\vphantom{\dfrac12}29-33&10&30\\\cline{1-3}\end{array}\)
Find which class the median is in.
Since n/2 = 30/2 = 15, there are 15 values less than or equal to the median. This means the median must be in the 24-28 class.
Therefore:
\(a_1=m-23.5\)\(b_1=28.5-23.5=5\)\(a_2=15-14=1\)\(b_2=20-14=6\)To find the median, m:
\(\begin{aligned}\dfrac{a_1}{b_1}=\dfrac{a_2}{b_2} \implies \dfrac{m-23.5}{5}&=\dfrac{1}{6}\\\\ 6(m-23.5)&=5\\\\6m-141&=5\\\\6m&=146\\\\m&=24.3333...\end{aligned}\)
Therefore, the median is 24.3333...
Mode
The modal class is the class with the highest frequency density.
As all the classes are the same width, this is the class with the highest frequency.
Modal class = 29 - 33A bag contains 70 pencils out of which 15 are green and 30 blue.how many pencils of other colours are in the bag
Answer:
25 pencils.
Step-by-step explanation:
You have 30 blue pencils and 15 green ones. To find how many pencils of other colors are in the bag, we can solve: 70-15-30=25
So, there are 25 pencils of other colors in the bag.
Given f(x) = 5 - x?, find f(3).
Answer:
the answer is 2
Step-by-step explanation:
just plug in the 3 for x and perform the neccessary calculation.
Answer:
2
Step-by-step explanation:
if x is 2 that means 2 + 3 = 5
Give me brainllest Plz
To prepare for his mountain biking trip, Rhyan bought four tire patches. Rhyan paid using a gift card that had $22.20 on it. After the sale, Rhyan’s gift card had $1.90 remaining. Which equations could you use to find the price of one tire patch? Select all that apply. 4x – 1.9 = 22.2 4x – 22.2 = 1.9 4x + 1.9 = 22.2 4x + 22.2 = –1.9 22.2 – 4x = 1.9
Answer:
Step-by-step explanation:
4x-22.2=1.90
22.20-4x=1.90
4x + 1.90 = 22.20
Click to show whether each equation represents a linear or nonlinear function
Linear Nonlinear
С
ооооо
С
у 5 (х + 2) 0
Answer: y = x ( x )= non linear
y = x = linear
y = x ^2 + 1 =non linear
y= 5 (x+2) = linear
y = x^1 + 2= linear
Step-by-step explanation: I calculated all in a website
there’s the graph so yeah
Answer:
what
Step-by-step explanation:
Express the function graphed on the axes below as a piecewise function.
The function graphed on the axes below as a piecewise function is,
⇒ f (x) = 2x - 1 ; x > 2
= 3 ; x ≥ - 3
What is mean by Function?A relation between a set of inputs having one output each is called a function. and an expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).
Now, By the graph;
For upper line,
The equation of line is passing though points (4, 7) and (5, 9).
Hence, The equation of line is,
⇒ y - 7 = (9 - 7) / (5 - 4) (x - 4)
⇒ y - 7 = 2 (x - 4)
⇒ y - 7 = 2x - 8
⇒ y = 2x - 1
For x > 2
And, For lower line,
The equation of line is passing though points (-4, 3) and (-5, 3).
Hence, The equation of line is,
⇒ y - 3 = (3 - 3) / (-5 + 4) (x - (-4))
⇒ y - 3 = 0 (x + 4)
⇒ y - 3 = 0
⇒ y = 3
For x ≥ - 3
Hence, The piecewise function is,
⇒ f (x) = 2x - 1 ; x > 2
= 3 ; x ≥ - 3
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Solve for X.
8e^x=16
x= ln(2).
Step-by-step explanation:1. Write the expression.\(8e^{x} =16\)
2. Divide both sides of the equation by 8.\(\frac{8e^{x}}{8} =\frac{16}{8} \\ \\e^{x} =2\)
3. Apply the natural logarithm on both sides.\(ln(e^{x} )=ln(2)\\ \\x=ln(2)\)
4. Verify the result.If the result is correct, if variable "x" is substituted by the calculated value (ln(2)) in the original equation, it should return the same value in both sides of the equal (=) sign.
Substituting "x" by the value:
\(8e^{ln(2)} =16\\\\16=16\)
That's correct! Therefore, the correct answer is "x= ln(2)".
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Please help will mark Brainly
Answer:
f(x) = - 2x + 4
Step-by-step explanation:
Since we are only trying to move the graph up 3 units, the slope does not change. So, it would be -2.
We also know that the 1 in f(x)= -2x + 1 is the y-intercept (y=mx+b). But again, we are moving the graph 3 units up, so we have to add 3. That makes it 4 (3+1=4).
So, the new equation would be f(x) = -2x + 4
Step-by-step explanation:
it simply means that g(x) is f(x) just shifted 3 units upwards.
that means nothing else changes, only whatever y result f(x) produces is increased by 3.
so,
g(x) = f(x) + 3 = -2x + 1 + 3 = -2x + 4
therefore, as domain and range were the whole set of real numbers, the addition of 3 does not make any difference in relation to infinity. so, they remain unchanged.
the slope stays the same (g(x) is simply a parallel line to f(x)).
the y-intercept (the y-value when x = 0) also increases by 3, and is 4.
the x-intercept (the x-value when y = 0) changes :
0 = -2x + 4
2x = 4
x = 2
the x-intercept is 2.
PLEASE ANSWER NEED QUICK ILL GIVE BRAINLISET
Answer:
A) y = 3x -2 is the answer
Step-by-step explanation:
The y-intercept is -2
The slope is going up 3 and right 1 which is 3/1 and 3 divide by 1 is 3.
Hope this helps and pls do mark me brainliest:)
you mix 1/2 quart of blue paint for every 1/3 quart of red paint to make 5 quart of purple paint. How much blue paint and how much red paint do you use?
The amount of blue paint and red paint that you use will be 3 quarts and 2 quarts, respectively.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
You mix 1/2 quart of blue paint for every 1/3 quart of red paint to make 5 quarts of purple paint.
Let 'x' be the amount of blue paint and 'y' be the amount of red paint. Then the equations are given as,
x / y = (1/2) / (1/3)
x / y = 3/2 ...1
x + y = 5 ...2
From equations 1 and 2, then we have
(3/2) y + y = 5
(5/2) y = 5
y = 2 quart
Then the value of 'x' is given as
x + 2 = 5
x = 3 quart
The amount of blue paint and red paint that you use will be 3 quarts and 2 quarts, respectively.
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solve for x×-8112x-8
You have that the distance of the segment CA is the sum of the segment CB and BA, as you can notice in the given figure.
In order to solve for x, you simply take into account the previous situation, segements CB and BA are equal to CA. You put this in an algebraic way, and solve for x. You proceed as follow:
x - 8 + 11 = 2x - 8 add 8 both sides
x + 11 = 2x subtract x both sides
11 = x
Hence, x is equal to 11
1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 QUESTION 1 [24] Gavin Pillay is employed at Maritzburg Engineering, a Steel manufacturing company in Pietermaritzburg. Below is a copy of his Payslip. 1. 3201 Company Maritzburg Engineering cc 21 Halsted Road Pietermaritzburg Employment No 105 Id Number Income Basic Salary Overtime M Gross Salary Maritzburg Engineering cc Employee Name Gavin Pillay Period 31/05/2023 Sex Male 790128514088 R8700 R1200 A Status Married Deductions PAYE UIF Total Deductions Net Pay 1200 87 B C Name the Employee? What does UIF stand for? Show by calculation that the UIF paid by Gavin is calculated correctly Which month is this Payslip for? Calculate the missing values A to C How old is Gavin this year? Give the address of Gavin's work place. Gavin would like to contribute towards a Pension fund (7,5% of his Basic Salary). H would this affect his net salary?
If Gavin contributes towards a Pension fund (7,5% of his Basic Salary), then his net salary will be reduced by the amount he contributed towards pension fund i.e. R652.5.
1.1 Name of employee is Gavin Pillay. 1.2 UIF stands for Unemployment Insurance Fund. UIF is a benefit to provide short-term relief to workers who lose their jobs, or can't work due to illness, maternity or adoption leave. 1.3 The UIF paid by Gavin is calculated correctly.
Firstly, we need to calculate Gross Salary of Gavin, which is given as: Basic Salary + Overtime + M = R8700 + R1200 + R3201 = R13101Then, calculate total deductions from gross salary.
Total Deductions = PAYE + UIF = R1200 + 87 = R1287Hence, Gavin's net salary = Gross salary - Total Deductions = R13101 - R1287 = R11814Therefore, UIF paid by Gavin is calculated correctly as R87.1.4 This payslip is for the month of May i.e.
31/05/2023.1.5 Basic salary of Gavin = R8700. Deduct 7.5% of his basic salary to calculate his pension fund contribution. Pension Fund Contribution = 7.5/100 x R8700 = R652.5.1.6
Total deductions of Gavin includes PAYE, UIF and pension fund contribution.
Therefore, Total Deductions = PAYE + UIF + Pension Fund Contribution = R1200 + R87 + R652.5 = R1939.5.1.7
Gavin's age can not be determined as his date of birth is not provided.1.8 Address of Gavin's workplace is 21 Halsted Road, Pietermaritzburg?
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what is the answer pls Question 29 of 45
In the triangle below, what is the length of MN?
OA. 50
OB. 100
OC. 20
OD. 40
50
20
M
50
The calculated length of the segment MN in the triangle is 20
How to find the length of the segment MN in the triangleFrom the question, we have the following parameters that can be used in our computation:
The triangle
The third angle in the triangle is calculated as
Third angle = 180 - 50 - 50
Evaluate
Third angle = 80
The length of the segment MN is then calculated as
MN/sin(50) = 20/sin(50)
This gives
MN = sin(50) * 20/sin(50)
Evaluate
MN = 20
Hence, the length of the segment MN in the triangle is 20
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The chart below represents the steps in the process of a bill becoming a law. Use the chart to answer the following question.
The image represents the process of a bill becoming a law. It shows a set of parallel lines that merge, then split into two, and then merge again. Moving left to right, the top line has boxes labeled: A, C, E, G, and H. The bottom line has boxes labeled: B, D, F, and I. Boxes A and B, C and D, E and F, H and I, are paired. G is the only box on the top line without a corresponding box on the bottom line. Continuing to move from left to right, the two lines merge into one and have one box labeled J. Then the lines separate into two parallel lines again. The top line is labeled with box K and the bottom line is labeled with box L. The two parallel lines continue to the right where they again merge into one line, with an arrow pointing to a final box labeled M.
© 2011 FLVS
Which section of this chart represents the point where a bill is first debated in subcommittees?
A and B
H and I
C and D
K and L
Based on the description provided, the section of the chart that represents the point where a bill is first debated in subcommittees is: C and D
How to explain the informationIn the given chart, the parallel lines represent the progression of a bill through various stages in the legislative process. The boxes on the top line represent one set of actions or steps, while the boxes on the bottom line represent another set of actions or steps.
Moving from left to right on the chart, the boxes A and B are paired, representing a particular stage in the process. Similarly, the boxes C and D are paired, indicating another stage in the process.
In the context of the question, the stage where a bill is first debated in subcommittees is represented by the boxes C and D.
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How does the graph of g(x) = - 1/x compare to the graph of f(x) = 1/x?
Answer:
The answer is B) g(x) is shift 5 units to the right and 2 units up from f(x).
Step-by-step explanation:
The equation that is given in this item can be written for clarity as follows:
g(x) = 1/(x - 5) + 2
It can be seen that the x-component is subtracted with 5 and the g(x) which would lie in the y-axis is added with two. This suggests that the graph of this equation is shifted to the right by 5 units and upwards by 2 units compared to the graph of the parent function.
The Graph for both function is attached below.
What is Translation?A translation in mathematics does not turn a shape; instead, it moves it left, right, up, or down. They are congruent if the translated shapes (or the image) seem to be the same size as the original shapes. They have only changed their direction or directions.
Given:
g(x) = - 1/x
and, f(x) = 1/x
The Graph shown below.
From the Graph we can see that the graph of g(x)= -1/x and f(x)= 1/x
shows the same graph but the position is changed in opposite of each other.
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