consider the given result of a chromatography experiment. developed chromatography plate with three spots. spot a has travelled about half of the distance between the starting line and the solvent front. spot b has travelled about one third of the distance between the starting line and the solvent front. spot c has travelled about three quarters of the distance between the starting line and the solvent front. identify which spot corresponds to the compound in each description. has a retention factor of about 0.60 choose... corresponds to the compound with the highest affinity for the solvent choose... corresponds to the compound with the lowest affinity for the solvent choose...

The amount of work done on the toboggan by the tension force of 105 N with a rope directed 32° above the snow is 3.12 KJ

W = F d cos θ

W = Work done

F = Force

d = Distance

θ = Angle between force and displacement vector

d = 35 m

F = 105 N

θ = 32°

W = 105 * 35 * cos 35°

W = 105 * 35 * 0.85

W = 3123.75 N m

W = 3.12 KJ

Work done is energy transferred to make an object move to a distance. Its unit is Joules which is denoted as J. It is the amount of work done by a force of 1 Newton to move a distance of 1 meter.

Therefore, the amount of work done on the toboggan by the tension force is 3.12 KJ

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Answer:

B. add more loops of wire between the magnets

Explanation:

this would increase the magnetic force acting on the rod therefore increasing

By adding more loops of wire between the magnets the motor is changed to be able to lift a heavier box.

An electric motor is a mechanism that turns electricity into mechanical energy.

The interaction between the motor's magnetic field and electric current in a wire winding generates force in the form of torque imparted to the motor's shaft in most electric motors.

An electric generator is physically equivalent to an electric motor, but it converts mechanical energy into electrical energy using a reversed flow of power.

The load capacity in the motor can be increased by increasing the no of loops. So by adding more loops of wire between the magnets the motor is changed to be able to lift a heavier box.

Hence option B is correct.

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The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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The force of 8800 N cannot lift boxes of weight 8800 N due to similar of both forces i.e. weight and lifting force.

The force of 8800 N cannot lift boxes of weight 8800 N because the downward force which is weight equals to upward force i.e. lifting force. When more than 8800 N force is applied in order to lift the weight of 8800 N. If there is equal amount of lifting force and weight then the weight can not be lifted upward but when the force is increased then the weight can be lifted. So that's why the force can not lifted the weight of boxes.

So we can conclude that the force of 8800 N cannot lift boxes of weight 8800 N due to similar of both forces i.e. weight and lifting force.

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Answer:

the f is 1.3 m

Explanation:

Given that

An object 2.0m is from the concave mirror

And, the image is 4.0m from the mirror

We need to find out the f

So,

u = -2 m

v = -4 m

1 ÷ f = 1 ÷ v + 1 ÷ u

= (-1 ÷ 4) + (-1 ÷ 2)

= -3 ÷4

f = -4 ÷ 3

= |1.3| m

Hence, the f is 1.3 m

Answer: 0.2 u

Explanation:

The atomic mass of nuclide is written as a superscript. On the left (reactants) aide of the nuclear equation shown, the total atomic mass is 235.0 + 1.0 u = 236 u. On the right (products) side reaction, the total atomic mass is 137.9u + 94.9u + 3 x 1.0u = 235.8 u. Therefore, 0.2 mass units must have been converted into energy.

Answer:

like fixing are car engine would be an example of a mechanical wave

(1) The tension in cable 2 is 34.83 N.

(2) The coefficient of friction between the block and the floor is 0.45.

The tension in the cable 2 is determined by resolving the forces into various component as shown below.

The vertical component of the forces on the picture is given as;

∑Fy = T₁ sin (65) + T₂ sin (32) - 20 N = 0

T₁ sin (65) + T₂ sin (32) - 20 N = 0

1.7 x sin (65) + 0.53T₂ - 20 = 0

1.54 + 0.53T₂ = 20

0.53T₂ = 18.46

T₂ = 18.46 / 0.53

T₂ = 34.83 N

The value of coefficient of friction is calculated by applying Newton's second law of motion as follows;

F (net) = ma

(F₁ + F₂) - Ff = ma

where;

Ff is the force friction

a is the acceleration of the block

m is the mass of the block

(F₁ + F₂) - μmg = ma

where;

When block moves at a constant velocity, the acceleration a = 0

(F₁ + F₂) - μmg = 0

μmg  = (F₁ + F₂)

μ = (F₁ + F₂) / mg

μ = ( 195 + 222 ) / ( 95 x 9.8 )

μ = 0.45

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Answer: C.

Correct me if I'm wrong.

Answer:

An electromagnet is a type of magnet that is created by an electric current flowing through a coil of wire wrapped around a magnetic core. The core is usually made of a ferromagnetic or ferrimagnetic material, such as iron, that can increase the magnetic field strength by hundreds or thousands of times.

The effects on an electromagnet of removing or replacing the core depend on the properties of the core material. Here are some possible effects:

i) Removing the core: This will reduce the magnetic field strength of the electromagnet, as the core material is no longer concentrating the magnetic field lines. The electromagnet will become an air-core coil, which has a much lower magnetic permeability than a ferromagnetic or ferrimagnetic core. The electromagnet will also lose its ability to retain some magnetism when the current is switched off, as the core material is no longer magnetized.

ii) Replacing the iron core with a steel core: This will change the magnetic field strength and the magnetic behavior of the electromagnet, depending on the type and quality of steel used. Steel is an alloy of iron and other elements, such as carbon, manganese, nickel, chromium, etc. Some types of steel have higher magnetic permeability than iron, which means they can increase the magnetic field strength more than iron. However, some types of steel have lower magnetic permeability than iron, which means they can decrease the magnetic field strength. Steel also has higher coercivity and hysteresis than iron, which means it can retain more magnetism when the current is switched off, but it also requires more energy to magnetize and demagnetize. Steel can also be affected by temperature changes, corrosion, and mechanical stress, which can alter its magnetic properties over time.

Answer:

just trace a picture of it.

Answer:

Approximately \(0.10\), assuming that \(g = 9.81\; {\rm N\cdot kg^{-1}}\) and a level surface.

Explanation:

Under the assumption, the normal force between the ice and the hockey puck is equal to the weight of the puck:

\(\begin{aligned}m\, g &= (0.16\; {\rm kg})\, (9.81\; {\rm N\cdot kg^{-1}}) \\ &\approx 1.57\; {\rm N}\end{aligned}\).

The friction on the puck is considered "static" when as long as the puck is not moving relative to that surface. In this question, the maximum value of this static friction is \(0.157\; {\rm N}\). When the external horizontal force exceeds \(0.157\; {\rm N}\!\), the puck would start moving relative to the ice.

Divide maximum static friction by the normal force to find the coefficient of static friction:

\(\begin{aligned}\mu_{s} &= \frac{(\text{maximum static friction})}{(\text{normal force})} \\ &\approx \frac{0.157\; {\rm N}}{1.57\; {\rm N}} \\ &\approx 0.10\end{aligned}\).

Answer:

The wavelength of a wave with the frequency of 330hz and a speed of 343m/s would be 1.04m

Explanation:

You can get the wavelength of a wave by dividing the speed of the wave by its frequency, which in this case would be:

343/300, which as a decimal number, it'd be 1.04.

I hope I helped you, and a "Brainliest" is always appreciated! ☺

Work required to stop an electron which is moving with a speed of 1.10x10^6m/s is \(-\frac{3.971}{5^{19}\cdot \:1048576}\)

There are three main types of particles in an atom: protons, neutrons, and an electron that is bonded to an atom. For a variety of reasons, electrons are different from other particles. They possess both wave-like and particle-like properties, exist outside of the nucleus, have a substantially lower mass than protons. A particle that is not composed of smaller parts is an electron, which is also an elementary particle. They are not elementary particles because quarks are assumed to make up protons and neutrons.

We can solve the problem by using the work-energy theorem: in fact, the work done on the electron must be equal to its change in kinetic energy, therefore

\(W=K_{f}-K_{i}\)

\(W=\frac{1}{2} mv^{2} - \frac{1}{2} mu^{2}\)

where,

m=9.11 × 10⁻³¹kg  is the mass of the electron

v  is the final velocity of the electron

u is the initial velocity of the electron

In the problem, we are told that the electron is initially moving at,

v = 1.90×10⁶ m/s

Therefore, the work required to stop it as

W = -1/2 mv²

W = -1/2 (1.10×10⁻³¹)(1.90×10⁶)²

\(W= -\frac{3.971}{5^{19}\cdot \:1048576}\\\)

and the work is negative since it is in the opposite direction to the motion of the electron.

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This question involves the concepts of the rectangular components of the vector and the resultant of the vectors.

The magnitude of the resultant force is "72.11 N", and it makes an angle of "33.7°" from one of the vectors.

The rectangular components of a vector are those components that have a right angle between them. The resultant of two rectangular components of a vector can be found using the following formula:

\(F = \sqrt{F_1^2+F_2^2}\)

where,

F = resultant force = ?

F₁ = First component of force = 40 N

F₂ = Second component of force = 60 N

Correction: The unit in question is given as m/s, while the unit of force is N. Hence, N is taken here.

Therefore,

\(F = \sqrt{(40\ N)^2+(60\ N)^2}\)

F = 72.11 N

The following formula can be used to find the angle of resultant from 60N vector:

\(\theta = tan^{-1}(\frac{40\ N}{60\ N})\\\\\)

θ = 33.7°

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The attached picture shows the resultant calculation for the rectangular components of a vector.

Answer:

D. X-rays have more energy than ultraviolet waves.

At room temperature,300 K, will a miscibility limit emerge. At the temperature less than, the miscibility will fall below 1%.

Temperature directs the hotness or coldness of a body. In clear terms, it is the method of finding the kinetic energy of particles within an entity. Faster the motion of particles, more the temperature.

Hence, at room temperature,300 K, will a miscibility limit emerge. At the temperature less than, the miscibility will fall below 1%.

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Answer: Distance traveled in time t is s

Explanation: Self Explanatory

Answer:

3.6×10⁻⁶  Nm

Explanation:

From the question,

The expression for maximum torque is given as

τ = BANI.................Equation 1

where τ = maximum torque, B = magnetic field, A = Area of the coil, N = number of turns, I = current carried by the coil.

Given: B = 0.1 T, A = (5×12) = 60 cm² = 0.006 m², N = 600 turns, I = 10⁻⁵ A.

Substitute these values into equation 1

τ = 0.1(0.006)(600)(10⁻⁵)

τ = 3.6×10⁻⁶  Nm

Answer: A literature review consists of an overview, a summary, and an evaluation (“critique”) of the current state of knowledge about a specific area of research.

Explanation:

Answer: Here you go, i hope this kinda helps.

Explanation:Disambiguation is just a fancy way of saying "asking clarifying questions".

Watson Assistant replies to user's questions based on a confidence score.

Sometimes the customer's question could be interpreted in two or three different ways.

For example, if you say you'd like to "book a table for 8", the assistant is able to ask a clarifying question:

Did you mean booking a table for 8PM, 8AM, or booking a table for 8 guests?

Watson Assistant will ask the question when its confidence score is divided between a few options to ensure that your customers get exactly the right service they need.

The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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The dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

Start by converting the rotational speed from rpm (revolutions per minute) to rad/s (radians per second). Since 1 revolution is equal to 2π radians, we can use the conversion factor:

Angular speed (ω) = (1100 rpm) × (2π rad/1 min) × (1 min/60 s)

ω ≈ 115.28 rad/s

The moment of inertia (I) is given as 2.0 × 10^-7 kg⋅m².

Use the formula for rotational kinetic energy:

Rotational Kinetic Energy (KE_rot) = (1/2) I ω²

Substituting the given values:

KE_rot = (1/2) × (2.0 × 10^-7 kg⋅m²) × (115.28 rad/s)²

Calculate the value inside the parentheses:

KE_rot ≈ (1/2) × (2.0 × 10^-7 kg⋅m²) × (13274.28 rad²/s²)

KE_rot ≈ 1.331 × 10^-3 J

Round the result to the proper number of significant figures, which in this case is three, as indicated by the given moment of inertia.

KE_rot ≈ 4.8 × 10^-4 J

Therefore, the dragonfly must generate approximately 4.8 × 10^-4 Joules of energy to spin itself at a rate of 1100 rpm.

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Answer:

Energy in carriage (Potential energy) = 4,116 J

Explanation:

Given:

Mass of baby = 20 kg

Height = 21 m

Find:

Energy in carriage (Potential energy)

Computation:

The energy accumulated in an object as a result of its location relative to a neutral level is known as potential energy.

In carriage accumulated energy is potential energy.

Energy in carriage (Potential energy) = mgh

Energy in carriage (Potential energy) = (20)(9.8)(21)

Energy in carriage (Potential energy) = 4,116 J

ANSWER:

Sound waves are faster in water

STEP-BY-STEP EXPLANATION:

Sound travels differently in water than it does in air.

Sound waves travel faster in denser substances because neighboring particles will more easily collide with each other.

Water is denser than air, which means that sound waves travel much faster in water than in air.

Although they travel faster in water, we must keep in mind that the human ear evolved to hear sounds in the air and is not as useful when submerged in water.

The pendulum loses energy through these

When you forces it to oscillation then the amplitude increases friction decreases but later on they comes back to their places so energy is lost in terms of heat .

#Part B

There is energy loss so this part is of no use

The government can encourage the production of goods that create positive externalities by implementing policies and mechanisms such as subsidies, tax incentives, and regulations.

Positive externalities occur when the production or consumption of a good or service benefits society beyond the direct parties involved. These benefits can include improved public health, environmental sustainability, or increased social welfare. To encourage the production of goods with positive externalities, the government can take the following steps:

Subsidies: The government can provide financial support to producers of goods with positive externalities. Subsidies can offset production costs, making it more attractive for producers to supply these goods. By reducing the costs of production, subsidies can encourage higher output and more widespread availability of goods that benefit society.

Tax incentives: The government can offer tax incentives or tax breaks to businesses that produce goods with positive externalities. By reducing the tax burden on producers, it becomes economically advantageous for businesses to engage in activities that generate positive externalities. Tax incentives can stimulate investment, innovation, and production in areas that have positive spillover effects.

Regulations: The government can implement regulations and standards that require or promote the production of goods with positive externalities. For example, environmental regulations can encourage industries to adopt cleaner technologies and reduce pollution. By setting standards and enforcing regulations, the government can steer production towards goods that have positive impacts on society.

Public-Private Partnerships: The government can collaborate with private entities to promote the production of goods with positive externalities. Through partnerships, the government can provide resources, expertise, and incentives to businesses that are willing to produce goods that generate social benefits. This collaboration can help overcome barriers and create a conducive environment for the production of socially beneficial goods.

By employing these measures, the government can provide the necessary incentives and support for the production of goods that create positive externalities. These actions align the private interests of producers with the broader goals of societal welfare, fostering a more sustainable and socially responsible economy.

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The letter that represents the various descriptions is as follows:

5.) Angle of incidence: B

6.) Object: D

7.) Plain mirror:A

8.) Reflection: E

9.) Angle of reflection: C

10.) Normal: F

The law of reflection in a plain mirror states that the angle of reflection is equal to the angle of incidence.

The diagram explains the law of reflection on a plain mirror because it shows the reflection of the object D as E after creating an angle of incidence B on the plane mirror surface A which is equal to the angle of reflection C.

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