Answer:
53.1 mL NaOH
Explanation:
The equivalence point of a titration is the point at which an equal amount of moles exists in each solution.
Let's start by writing a chemical equation for this reaction. Using the compounds in the reaction, HCl and NaOH, we can create the following equation:
\(\text{NaOH}_\text{(aq)} + \text{HCl}_\text{(aq)} \rightarrow \text{NaCl}_\text{(aq)} + \text{H}_2 \text{O}_\text{(l)}\)We have one very important formula that we want to use when dealing with titrations:
\(${V=\frac{n}{M}}\) where V = volume (L)n = number of moles M = molarityLet's start by finding the number of moles of HCl that is in this reaction using this formula. We have the molarity of HCl and volume of HCl.
Plug in 0.340 for M and 0.0250 L for V. Note that we are given the volume of HCl in mL, but we want to convert to L before using the formula.
\($V=\frac{n}{M}\)\(.0250 =\frac{n}{.340}\) \($n=.0250 * .340 = .0085\)Let's convert this number of moles to scientific notation for better readability.
\(n=8.5*10^-^3\ \text{mol HCl}\)Now that we've found the number of moles of HCl, let's use the coefficients of the compounds in the chemical equation in order to determine the molar ratio between compounds.
We want to determine the moles of NaOH; we can determine this value by using the molar ratio between HCl and NaOH. The coefficients of these substances in the chemical equation are both 1, so we can multiply the moles of HCl by:
\(8.5*10^-^3\ \text{mol HCl} * \frac{\text{1 mol NaOH}}{\text{1 mol HCl}} = 8.5*10^-^3\ \text{mol NaOH}\)Now, we have two variables for NaOH in the formula: \($V=\frac{n}{M}\)
We have the variables n (which we solved for) and M (which we were given). We are trying to solve for V, the volume of NaOH required to reach the equivalence point in the titration:
\(V=\frac{8.5*10^-^3\ \text{mol NaOH}}{0.160\ \text{M NaOH}} = 0.053125 \ \text{L}\)The last step is to convert 0.053125 L to mL:
\(53.1\ \text{mL NaOH}\)I kept the answer to 3 significant figures since the question contains calculations involving 3 significant figures.
ellus
What is the pH of a 3.5 x 10-11 M
H+ solution?
pH = [?]
Answer:
\(pH=10.5\)
Explanation:
Hello,
In this case, since we define the pH as:
\(pH=-log([H^+])\)
We can directly compute it by using the given concentration of H⁺:
\(pH=-log(3.5x10^{-11})\\\\pH=10.5\)
For which we conclude it is a basic solution as the pH is greater than 7.
Best regards.
Claims • Evidence • Reasoning Make
a claim about ways people can stay safe
during storms with high wind and heavy
rains. Summarize evidence to support the
claim and explain your reasoning.
Answer:
the claim is that when people avoid storms they hide in any secret place in there house
Explanation:
when people do that they don't even have to worry about a single thing that will happen to them
A balance was tested against a standard calibration mass with a certified value of 200.002 g and produced the following readings in grams: 195.587, 195.586, 195.588, 195.587, 195.589. The performance of this balance is best described as:
Answer:
Precise but not accurate.
Explanation:
We can tell the performance of the balance is precise, because the repeated measurements give values close to one another.
However, the performance of the balance is not accurate, as the mean value of the repeated measurements (195.587) is not close to the value considered as true (in this case the standard calibration mass with a certified value of 200.002 g).
Using the following equation, determine whether the changes listed below will cause a shift in equilibrium to shift forward, reverse, or no shift at all.
A open parentheses a q close parentheses italic space plus space B open parentheses s close parentheses italic space rightwards harpoon over leftwards harpoon space straight C open parentheses straight s close parentheses space plus space straight D open parentheses aq close parentheses space plus space straight E open parentheses aq close parenthesesA(aq) + B (s) → D(aq) + E(aq)
Addition of A?
Addition of B?
Removal of C?
Removal of D?
Addition of E?
Removal of A?
The number of moles of A will decrease. This causes a decrease in pressure which will lead to a shift in equilibrium towards reactants.
Addition of A: The addition of A will cause the equilibrium to shift forward. This is because A is added to the reactants side, so the number of moles of A will increase. This causes an increase in pressure which will lead to a shift in equilibrium toward products. Addition of B: The addition of B will cause the equilibrium to reverse. This is because B is added to the product side, so the number of moles of B will increase. This causes an increase in pressure which will lead to a shift in equilibrium towards reactants. Removal of C: The removal of C will cause no shift in equilibrium. This is because C is removed from the reactants side, but the number of moles of C will remain unchanged. Removal of D: The removal of D will cause no shift in equilibrium. This is because D is removed from the product side, but the number of moles of D will remain unchanged.
Addition of E: The addition of E will cause the equilibrium to shift forward. This is because E is added to the product side, so the number of moles of E will increase. This causes an increase in pressure which will lead to a shift in equilibrium toward products. Removal of A: The removal of A will cause the equilibrium to reverse. This is because A is removed from the reactant's side.
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which of the following molecules has a shape is trigonal pyramid?
ccl4
ch2o
Nh2o
h2o
Nh2o has a trigonal pyramid
Which of the following is an incorrect representation for a neutral atom?
36Li
613C
3063Cu
1530P
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97. The incorrect representation for a neutral atom is 36Li
To determine the correct representation for a neutral atom, we need to consider the atomic number (Z) and mass number (A) of the element. The atomic number represents the number of protons in the nucleus, while the mass number represents the sum of protons and neutrons.
Let's analyze the given representations:
36Li:
This representation suggests that the element is lithium (Li) with a mass number of 36, which is incorrect. The correct mass number for lithium is approximately 6.94.
613C:
This representation suggests that the element is carbon (C) with a mass number of 13, which is correct. Carbon has different isotopes, and 13C represents one of its stable isotopes.
3063Cu:
This representation suggests that the element is copper (Cu) with a mass number of 63, which is correct. Copper has different isotopes, and 63Cu represents one of its stable isotopes.
1530P:
This representation suggests that the element is phosphorus (P) with a mass number of 30, which is incorrect. The correct mass number for phosphorus is approximately 30.97.
Therefore, the incorrect representation for a neutral atom is 36Li, as it does not match the known properties of lithium.
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True or Fasle: Kinetic-molecular theory assumes that attractive and repulsive forces between gas
particles are stronger than those between gas particles and container walls.
The statement that Kinetic-molecular theory assumes that attractive and repulsive forces between gas particles are stronger than those between gas particles and container walls is false.
Kinetic-molecular theory simply explains that gas particles are typically in constant motion and that they also have perfectly elastic collisions.
Kinetic-molecular theory doesn't assume that attractive and repulsive forces between gas particles are stronger than those between gas particles and container walls.
Lastly, in kinetic-molecular theory, the particles exert no force on each other.
In conclusion, the correct option is false.
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What is chemistry?
A. The scientific study of matter
B. The study of living things
C. The study of how matter and energy interact
D. The study of changing ideas
Answer:
the scientific study of matter i believe
Explanation:
because the definition says the branch of science that deals with the identification of the substances of which matter is composed
List 3 properties of the hair’s cuticle.
Polar air masses bring warm temperature and have lower air temperature? T or F
Answer:
t? im pretty sure have a good day
What is the name of the compound N2O3?Trinitrogen dioxideTrinitrogen dioxygenDinitrogen trioxideDinitrogen trioxygen
Dinitrogen trioxide
Explanations;From the given question, we are to name the compound N2O3. From the given compound, you can see that there are 3 atoms of oxygen and 2 atoms of hydrogen.
Hence the name of the given compound is Dinitrogen trioxide
3. Would you expect your experimental results would change if a different gas, such as CO2, were used instead of air? Explain your answer.
The experimental results would change if a different gas, such as CO₂, were used instead of air.
What is Air?This comprises of gases that form the atmosphere and they include:
78.08% nitrogen20.95% oxygen0.93% argon0.04% carbon dioxide, and small amounts of other gases.Due to the presence of other gases in air, there would be a change in experimental results.
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A weak acid is titrated with 0.1236 M NaOH. From the titration curve you determine that the equivalence point occurs after exactly 12.42 mL of NaOH have been added. What is the volume of NaOH at the half-equivalence point (a.k.a. the midpoint)
Answer: The volume of NaOH required at the half-equivalence point is 6.21 mL
Explanation:
The chemical equation for the reaction of a weak acid with NaOH follows:
\(HA+ NaOH\rightarrow NaA+H_2O\)
From the equation, we can say that NaOH and weak acid is present in a 1 : 1 ratio.
We are given:
Volume of NaOH required at equivalence point = 12.42 mL
The volume of NaOH required at half-equivalence point will be = \(\frac{12.42mL}{2}=6.21mL\)
Hence, the volume of NaOH required at the half-equivalence point is 6.21 mL
The volume of NaOH at the half-equivalence point is 6.21 mL
What is equivalence point?The equivalence point is the point at which equal amount of the acid and base have reacted.
How to determine the half-equivalence pointVolume at equivalence point = 12.42 mLVolume at half-equivalence point =?Half equivalence point = Equivalence point / 2
Half equivalence point = 12.42 / 2
Half equivalence point = 6.21 mL
Therefore, we can conclude that the volume of NaOH at the half-equivalence point is 6.21 mL.
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Suppose a scientist proposes a plan to destroy all bacteria on Earth in order to get rid of diseases caused by bacteria. Explain why it would be a good idea to approve this plan or not.
The partial pressures of gases A, B, and C in a mixture are
0.75 atmosphere, 0.25 atmosphere, and 1.25 atmospheres,
respectively. What is the total pressure of the gas mixture
in millimeters of Hg?
A. 1710 mm of Hg
B.
1140 mm of Hg
C. 760.0 mm of Hg
D. 570.0 mm of Hg
Answer:
A
Explanation:
.75 + .25 + 1.25 = 2.25 atm
1 atm is 760 mm hg
2.25 * 760 = 1710 mm HG
Answer:
\(\huge\boxed{\sf 2.25\ atm = 1710\ mm\ of\ Hg}\)
Explanation:
Partial pressure of gas A = 0.75 atm
Partial pressure of gas B = 0.25 atm
Partial pressure of gas C = 1.25 atm
Total partial pressure = 0.75 atm + 0.25 atm + 1.25 atm
= 2.25 atm
We know that:
1 atm = 760 mm of Hg
Multiply 2.25 to both sides
2.25 atm = 760 × 2.25 mm of Hg
2.25 atm = 1710 mm of Hg
\(\rule[225]{225}{2}\)
6. Which describes particles or electromagnetic radiation emitted from the nucleus during
radioactive decay ?
a) harmless nuclear fallout
b) nuclear radiation
c) transmutation
d) daughter nuclides
Answer:
A harmless nuclear fallout
Explanation:
just did this
Does you have more momentun when you are running 3 km/hr or when you are walking 1 km/hr? Explain your answer
Baking soda is a critical component of chemical
spill kits. Why would a chemist need baking soda to
help clean up spills?
HELPPPPP NOWWW
0.276 g of Na2CO3.xH20 was weighed out accurately and dissolved in water. Titration with
0.050 mol cm sulphuric acid required 20.00 cm for neutralisation. Calculate the value of x.
x in Na₂CO₃.xH₂0 is the number of water molecule that is attached to sodium carbonate called water of crystallization. Therefore the value of x is 10
What is titration?Titration is a technique by which we know the concentration of unknown solution using titration of this solution with solution whose concentration is known. To know the end point we use phenolphthalein as indicator. End point is a point where completion of reaction happen
The balanced equation is
Na₂CO₃ + H₂SO₄ → Na₂SO₄ + H₂O + CO₂
Concentration of H₂SO₄= 0.05 mol/L
Volume of H₂SO₄ = 20 ml = 0.02 L
number of moles of H₂SO₄= 0.05× 0.02 = 0.001mol
number of moles of H₂SO₄ = n(Na2CO3) = 0.001 mol
Molar mass of Na₂CO₃= 106 g/mol
mass of Na₂CO₃ = n× M = 0.001 × 106 = 0.106g
change in mass =∆m = 0.276 – 0.106 = 0.17 g
Molar mass of (H₂O = 18 g/mol
n umber of moles of water = mass÷ Molar mass=0.17 g÷18=0.0094mol
x= number of moles of H₂O÷ number of moles of sodium carbonate
= 0.0094mol÷0.001
=10
Therefore the value of x is 10
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Magnesium nitride, Mg3N, undergoes a thermo decomposition reaction to form magnesium metal and nitrogen gas.
a. True
b. False
Answer:
a. True
Explanation:
Magnesium nitride, Mg₃N, is a binary salt. Upon heating, it decomposes into magnesium metal and nitrogen gas. The unbalanced equation is:
Mg₃N(s) ⇒ Mg(s) + N₂(g)
We can balance it with the trial and error method. First, we will balance N atoms by multiplying Mg₃N by 2.
2 Mg₃N(s) ⇒ Mg(s) + N₂(g)
Then, we get the balanced equation by multiplying Mg by 6.
2 Mg₃N(s) ⇒ 6 Mg(s) + N₂(g)
At STP, exactly 1 mole of any gas occupies 22.4 L. What size container (in Liters) do you need to hold 2.66 mol O2 gas at STP?(Show all work)59.647.763.870.3
Answer: A container with 59.6 L would be necessary to hold 2.66 moles of O2 (letter A)
Explanation:
The question requires us to determine the volume of 2.66 moles of O2 at STP.
At standard temperature and pressure conditions (STP), 1 mol of any gas corresponds to 22.4 L of the gas. Thus, we can calculate the volume of 2.66 moles of O2 at STP as:
1 mol O2 --------------------- 22.4 L O2
2.66 mol O2 ---------------- x
Solving for x, we'll have:
\(x=2.66mol\text{ O}_2\times\frac{22.4L\text{ O}_2}{1mol\text{ O}_2}=59.6L\text{ O}_2\)Therefore, 2.66 moles of O2 at STP corresponds to 59.6 L of O2.
How many kilojoules of heat are needed to raise the temperature of 10g of aluminum from 22 degrees C to 55 degrees C, if the specific heat of aluminum is .901 j/gc?
Answer:
name four agricultural inputs are subsidized by the government
0.297 kJ of heat is needed to raise the temperature of 10g of aluminum from 22 degrees Celsius to 55 degrees Celsius.
The specific heat is the amount of heat per unit mass required to raise the temperature by one degree Celsius.
It is a measure of how much energy it takes to raise the temperature of a substance. It is the amount of heat necessary to raise one mass unit of that substance by one temperature unit.
It is given by the formula -
Q = mcΔT
where, Q = amount of heat
m = mass
c = specific heat
ΔT = Change in temperature
Given,
mass = 10g
c = 0.901J/g⁰C
Initial temperature (T₁) = 22⁰C
Final Temperature (T₂) = 55⁰C
Q = mcΔT
= 10 × 0.901 × (55 -22)
= 297.33 J = 0.297 kJ
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Translate each number into standard notation
4.52 x 10 power3
Answer:
4.52×1000=4520
Explanation:
4.52*1000=4520
16.4 A cylinder of water contains oxygen in solution. The cross- sectional area of the cylinder is 2 cm2 and the length of the cylin- der is 5 cm. At one end of the cylinder the concentration of oxygern is maintained at 0.2 mol m-3, this concentration falls linearly to 0.05 mol m-3 at the other end of the cylinder. The diffusion con- stant of oxygen in water is 8 × 10-10 m2 s-1. How many moles of oxygen pass down this cylinder every second? What mass of oxy- gen passes down the cylinder each second?
Answer:
A) oxygen moles/sec = 48 * 10 ^-14 mol/sec
B) mass of oxygen = 1536*10^-14 grams
Explanation:
cross sectional area of cylinder = 2cm^2 = 2 * 10^-4 m^2
length of cylinder = 5 cm = 0.05 m
concentration at one end = 0.2 mol m^-3
concentration falls linearly at other end = 0.05 mol m^-3
Diffusion constant of oxygen = 8 * 10^-10 m^2 s^-1
A ) Number of moles of oxygen passing every second
N = A * D * \(\frac{dc}{dt}\) ------- ( 1 )
A = area , D = diffusion constant, \(\frac{dc}{dt}\) = rate of change of diffusion
dc /dt = ( 0.2 - 0.05 ) / 0.05 = 3 mol m^-4
back to the equation
N = ( 2 * 10^-4 ) * ( 8 * 10^-10 ) * ( 3 ) = 48 * 10 ^-14 mol/sec
B) Mass of oxygen passing down the cylinder each second
This can be obtained by converting : 48 * 10^-14 moles to grams
1 mole of oxygen = 32 grams of oxygen
therefore : 48 * 10^-14 moles of oxygen = ( 32 * (48*10^-14) = 1536*10^-14 grams
Identify the type of reaction. Complete the equations with the correct reactants then balance each equation.
The balanced equations are Cd (g) + S\(_8\) (g) → CdS (g), K\(_2\)CO\(_3\) → K\(_2\)O + CO\(_2\). and a Na + HOH → NaOH + H\(_2\). Cd (g) + S\(_8\) (g) → CdS (g) is combination reaction.
An equation per a chemical reaction is said to be balanced if both the reactants plus the products have the same number of atoms and total charge for each component of the reaction. In other words, both sides between the reaction have an equal balance of mass and charge. The balanced equations are Cd (g) + S\(_8\) (g) → CdS (g), K\(_2\)CO\(_3\) → K\(_2\)O + CO\(_2\). and a Na + HOH → NaOH + H\(_2\).
Cd (g) + S\(_8\) (g) → CdS (g) = combination reaction
K\(_2\)CO\(_3\) → K\(_2\)O + CO\(_2\) = decomposition reaction
Na + HOH → NaOH + H\(_2\) = Hydration reaction
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Magnesium hydroxide reacts with chlorine to form magnesium chloride,
magnesium chlorate and water. How many grams of magnesium hydroxide is
needed to yield 8.00 moles of magnesium chlorate?
77.8 g Mg(OH)2
9178.1 g Mg(OH)2
2799.6 g Mg(OH)2
.823 g Mg(OH)2
How many grams of sodium sulfato pro
The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.
To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.
The balanced equation is as follows:
2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O
From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.
Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.
To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.
Given:
Moles of Mg(ClO3)2 = 8.00 moles
Using the stoichiometric ratio, we have:
8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2
To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.
The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol
Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g
Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.
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(d) Other
sugar molecules become
_____ and are carried away from the crystal.
the force of attraction is
Answer:
liquid
Explanation:
defiantly
Suppose That 75 ML Of 4.25 M Iron (III) Hydroxide Is Combined With 81 ML Of 3.50 M Calcium Hydroxide. What Is The Concentration of OH ion in the resulting solution
The equation for the reaction between iron (III) hydroxide and calcium hydroxide is:
Fe(OH)3 + Ca(OH)2 → Fe(OH)2 + Ca(OH)4
To calculate the concentration of OH ions in the resulting solution, we can use the following formula:
cOH = [OH-] = √(M1V1 + M2V2)
Where M1 is the molarity of Fe(OH)3 (4.25M) and V1 is the volume of Fe(OH)3 (75 mL). M2 is the molarity of Ca(OH)2 (3.5M) and V2 is the volume of Ca(OH)2 (81 mL).
Substituting the values into the formula, we get:
cOH = [OH-] = √(4.25 x 75 + 3.5 x 81) = 5.64 M
Therefore, the concentration of OH ions in the resulting solution is 5.64 M.
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Similar Question: https://brainly.com/question/4154626
How would a small bar magnet be oriented when placed at position x?
Answer:
d
Explanation:
Answer:C is the answer
Explanation:
If you have 50 grams of H2SO4 and excess
Al, how many grams of Al2(SO4)3 are
produced during the following reaction?
2 Al + 3 H2SO4 → Al2(SO4)3 + 3 H2
0.65mol \(Alx_{2} (So_{4} )_{3}\) are produced during the reaction.
What is the molar mass?The mass in grams of one mole of a chemical is its molar mass. A mole is the measurement of the number of things, such as atoms, molecules, and ions, that are present in a substance. Any substance's mole is. Molecules, 6.022 10 23.Divide each element's atomic weight (found in the periodic table) by the number of that element's atoms in the compound. 3. Add up the totals, and then follow the number with the units of grams/mole.The mass of every atom in a molecule, expressed in grams per mole, is known as the molar mass. We first obtain the atomic weights of the different elements in a periodic table to compute a molecule's molar mass. Then, we multiply the total number of atoms by each one's atomic mass.How many grams of Al2(SO4)3 are produced during the following reaction?
2 Al + 3 H2SO4 → Al2(SO4)3 + 3 H2
Molar mas:26.98 →341.15g/mol
All take 35g.
Moles of aluminum=35/26.98=1.29mol.
2mole of aluminum will give=1/2*1.29=0.65
Therefore, 0.65mol \(Alx_{2} (So_{4} )_{3}\).
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