Course INFORMATION SYSTEM AUDIT AND CONTROL
2. Discuss the role of Audit Committee
Answers
The Audit Committee is responsible for the examination of the accounting procedures and financial reports of an organization.
It is established by a company's board of directors to review and oversee the organization's financial reporting processes. This article explains the role of the Audit Committee.An Audit Committee's primary responsibility is to oversee and ensure the integrity and quality of the organization's financial reporting. This is accomplished through a variety of means, such as ensuring that the organization has an effective system of internal controls and ensuring that the organization's financial statements are accurate and reliable.
Furthermore, the Audit Committee ensures that the organization is in compliance with regulatory and legal requirements, such as those set forth by the Sarbanes-Oxley Act.The Audit Committee is responsible for selecting the external auditors who will conduct the audit of the organization's financial statements. It oversees the auditor's work, ensuring that it meets the organization's needs and is performed in accordance with auditing standards. The Audit Committee is also responsible for assessing the auditor's independence and objectivity, as well as the appropriateness of the auditor's fees.
Finally, the Audit Committee ensures that any issues or concerns identified during the audit are resolved promptly and effectively.In summary, the Audit Committee plays a crucial role in maintaining the integrity and quality of an organization's financial reporting processes. It oversees the organization's accounting procedures and financial reports, ensuring that they are accurate, reliable, and in compliance with regulatory and legal requirements. It also selects the external auditors and oversees their work, ensuring that it meets the organization's needs and is performed in accordance with auditing standards.
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Related Questions
What signal propagation phenomena causes the diffusion, or the reflection in multiple different directions, of a signal?
Answers
In the radio communication system, multipath is the propagation phenomenon that causes diffusion or reflection in multiple different directions of a signal.
Multipath is a propagation mechanism that impacts the propagation of signals in radio communication. Multipath results in the transmission of data to the receiving antenna by two or more paths. Diffusion and reflection are the causes that create multiple paths for the signal to be delivered.
Diffraction occurs when a signal bends around sharp corners; while reflection occurs when a signal impinges on a smooth object. When a signal is received through more than one path because of the diffraction or reflection, it creates phase shifting and interference of the signal.
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Tech a says that mass airflow sensors determine mass airflow based on engine speed and manifold pressure. tech b says that some airflow sensors use a hot wire to determine mass airflow. who is correct
Answers
Since Tech B says that some airflow sensors use a hot wire to determine mass airflow he is the only one that is correct.
How does a mass airflow sensor work?An MAF is one that consist of two sensing wires. One is known to be heated by the use of electrical current, while the other is not.
There are different kinds of wires for different kinds of purposes.
Tech A saying that mass airflow sensors determine mass airflow based on engine speed and manifold pressure is incorrect because that is not the role of the mass airflow sensors.
l
As air flows across the heated wire, it cools down. Hence, Since Tech B says that some airflow sensors use a hot wire to determine mass airflow he is the only one that is correct.
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Tensile Strength (MPa) Number-Average Molecular Weight (g/mol)
82 12,700
156 28,500
The tensile strength and number-average molecular weight for two polyethylene materials given above. Estimate the number-average molecular weight that is required to give a tensile strength required above. Using the data given find TS (infinity) in MPa.
Answers
Answer:
\(\mathbf{T_{S \infty } \ \approx 215.481 \ MPa}\)
\(\mathbf{M_n = 49163.56431 \ g/mol }\)
Explanation:
The question can be well structured in a table format as illustrated below:
Tensile Strength (MPa) Number- Average Molecular Weight (g/mol)
82 12,700
156 28,500
The tensile strength and number-average molecular weight for two polyethylene materials given above.
Estimate the number-average molecular weight that is required to give a tensile strength required above. Using the data given find TS (infinity) in MPa.
SOLUTION:
We know that :
\(T_S = T_{S \infty} - \dfrac{A}{M_n}\)
where;
\(T_S\) = Tensile Strength
\(T_{S \infty}\) = Tensile Strength (Infinity)
\(M_n\) = Number- Average Molecular Weight (g/mol)
SO;
\(82= T_{S \infty} - \dfrac{A}{12700} ---- (1)\)
\(156= T_{S \infty} - \dfrac{A}{28500} ---- (2)\)
From equation (1) ; collecting the like terms; we have :
\(T_{S \infty} =82+ \dfrac{A}{12700}\)
From equation (2) ; we have:
\(T_{S \infty} =156+ \dfrac{A}{28500}\)
So; \(T_{S \infty} = T_{S \infty}\)
Then;
\(T_{S \infty} =82+ \dfrac{A}{12700} =156+ \dfrac{A}{28500}\)
Solving by L.C.M
\(\dfrac{82(12700) + A}{12700} =\dfrac{156(28500) + A}{28500}\)
\(\dfrac{1041400 + A}{12700} =\dfrac{4446000 + A}{28500}\)
By cross multiplying ; we have:
\(({4446000 + A})* {12700} ={28500} *({1041400 + A})\)
\((5.64642*10^{10} + 12700A) =(2.96799*10^{10}+ 28500A)\)
Collecting like terms ; we have
\((5.64642*10^{10} - 2.96799*10^{10} ) =( 28500A- 12700A)\)
\(2.67843*10^{10} = 15800 \ A\)
Dividing both sides by 15800:
\(\dfrac{ 2.67843*10^{10} }{15800} =\dfrac{15800 \ A}{15800}\)
A = 1695208.861
From equation (1);
\(82= T_{S \infty} - \dfrac{A}{12700} ---- (1)\)
Replacing A = 1695208.861 in the above equation; we have:
\(82= T_{S \infty} - \dfrac{1695208.861}{12700}\)
\(T_{S \infty}= 82 + \dfrac{1695208.861}{12700}\)
\(T_{S \infty}= \dfrac{82(12700) +1695208.861 }{12700}\)
\(T_{S \infty}= \dfrac{1041400 +1695208.861 }{12700}\)
\(T_{S \infty}= \dfrac{2736608.861 }{12700}\)
\(\mathbf{T_{S \infty } \ \approx 215.481 \ MPa}\)
From equation(2);
\(156= T_{S \infty} - \dfrac{A}{28500} ---- (2)\)
Replacing A = 1695208.861 in the above equation; we have:
\(156= T_{S \infty} - \dfrac{1695208.861}{28500}\)
\(T_{S \infty}= 156 + \dfrac{1695208.861}{28500}\)
\(T_{S \infty}= \dfrac{156(28500) +1695208.861 }{28500}\)
\(T_{S \infty}= \dfrac{4446000 +1695208.861 }{28500}\)
\(T_{S \infty}= \dfrac{6141208.861}{28500}\)
\(\mathbf{T_{S \infty } \ \approx 215.481 \ MPa}\)
We are to also estimate the number- average molecular weight that is required to give a tensile strength required above.
If the Tensile Strength (MPa) is 82 MPa
Definitely the average molecular weight will be = 12,700 g/mol
If the Tensile Strength (MPa) is 156 MPa
Definitely the average molecular weight will be = 28,500 g/mol
But;
Let us assume that the Tensile Strength (MPa) = 181 MPa for example.
Using the same formula:
\(T_S = T_{S \infty} - \dfrac{A}{M_n}\)
Then:
\(181 = 215.481- \dfrac{1695208.861 }{M_n}\)
Collecting like terms ; we have:
\(\dfrac{1695208.861 }{M_n} = 215.481- 181\)
\(\dfrac{1695208.861 }{M_n} =34.481\)
1695208.861= 34.481 \(M_n\)
Dividing both sides by 34.481; we have:
\(M_n\) = \(\dfrac{1695208.861}{34.481}\)
\(\mathbf{M_n = 49163.56431 \ g/mol }\)
Which of the following is NOT used to stabilize a vehicle involved in a collision?
A. Strut
B. Cribbing
C. Nader pin
D. Step chock
Answers
Among the options provided, the Nader pin is NOT used for stabilization.
So, the correct answer is C.
Instead, it is a component of the vehicle door latch system that helps secure the door.
In a vehicle collision scenario, various tools and techniques are employed to stabilize the vehicle and ensure safety.
On the other hand, a strut (A) is a support device that holds the vehicle in place, cribbing (B) consists of wooden or plastic blocks placed beneath the vehicle to prevent movement, and step chocks (D) are wedge-shaped supports placed under the tires to prevent rolling.
These three tools contribute to vehicle stabilization, while the Nader pin does not.
Hence, the answer is C.
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technician a says that map sensors use a 5-volt reference voltage from the pcm. technician b says the map sensor voltage will be higher at idle at high altitudes compared to when the engine is operating at near sea level. which technician is correct?
Answers
Technician A is correct in stating that MAP (manifold absolute pressure) sensors use a 5-volt reference voltage from the PCM (powertrain control module) to measure engine load.
This voltage is used to determine the amount of air entering the engine and adjust the fuel injection accordingly. Technician B is also correct in stating that the MAP sensor voltage will be higher at idle at high altitudes compared to when the engine is operating at near sea level. This is because at higher altitudes, there is less air pressure, which affects the pressure in the engine. This change in pressure affects the voltage output of the MAP sensor. In summary, both technicians are correct in their statements.
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A coil having a resistance of 10 ohms and an inductance of 4 H is switched across a 20W dc source. Calculate (a) time required by the current to reach 50% of its final steady value, (b) value of the current after 0. 5 second
Answers
(a) The time constant of the circuit can be calculated as:
τ = L/R = 4/10 = 0.4 seconds
At t = τln(2), the current will have reached 50% of its final steady value. Therefore:
t = τln(2) = 0.4ln(2) ≈ 0.277 seconds
(b) The current in the circuit can be calculated using the formula:
i(t) = (V/R)(1 - e^(-t/τ))
At t = 0.5 seconds, we have:
i(0.5) = (20/10)(1 - e^(-0.5/0.4))
≈ 1.98 amps
Therefore, the value of the current after 0.5 seconds is approximately 1.98 amps.
An AC sine wave has an RMS value of 100 V. What's the average of the waveform?
A. 90 V
B. 80 V
C. 102 V
D. 92.6 V
Answers
Just took the test and it ISN'T 92.6 V, my guess is 80 V but I dont know because it only says if I got it wrong.
R-134a at 320 kPa and 40 C undergoes an isothermal process in a closed system until its quality is 45 percent. determine how much work and heat transfer are required per mass.
Answers
The system's temperature is maintained constant using an isothermal process, which is a type of thermodynamic process. Thermal equilibrium is maintained because heat is introduced or removed from the system so gradually.
What heat transfer required per mass in isothermal process?Any isothermal process must have zero change in internal energy since the change in internal energy depends on the change in temperature, which is zero for all isothermal processes.
Since the temperature is kept constant, the energy change is zero (U=0). Thus, the work that the ideal gas does on its surroundings is equal to the heat that the gas absorbs.
Therefore, In a closed system, refrigerant-134a undergoes an isothermal procedure at 320 kPa and 40 °C until its quality reaches 45%. Determine the effort and heat transfer needed on a per-unit-mass basis. 2: 40.6 kJ/kg and 130 kJ/kg.
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DNA can be represented as strings constructed from an alphabet of four characters: {A,C,G,T}. We can thus construct 4? = 16,384 possible different DNA strings of length 7. If we were to construct a well-balanced Binary Search Tree containing all 16,384 possible DNA strings of length 7, what would be the height of our BST? Measure "height" as the number of edges, not nodes, from the root to a leaf.
Answers
In order to answer this question, we first need to understand what a Binary Search Tree (BST) is and how it works. A BST is a binary tree data structure in which each node has at most two children, commonly referred to as the left and right child.
Additionally, in a BST, the left child of a node must have a value less than the value of the node, while the right child must have a value greater than the node. Given that we have 16,384 possible DNA strings of length 7, we can construct a well-balanced BST by taking the middle string as the root of the tree and recursively inserting the strings on the left or right of the root based on their alphabetical order.
In a well-balanced BST, the height of the tree is proportional to the logarithm of the number of nodes in the tree. Specifically, the height of a BST containing N nodes is approximately log2N, where log2 denotes the logarithm to base 2. In our case, we have 16,384 possible DNA strings of length 7. Taking the logarithm base 2 of this number gives us: log2(16384) = 14 Therefore, the height of our well-balanced BST would be approximately 14 edges from the root to a leaf.
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The following problem refers to triangle ABC, find all missing parts. Round degrees to 1 decimal places and
sides to the nearest whole number.
A = 36.5°C = 67.5°, c = 224 inches
A=
В.
C
O
O
490 do
a =
inches
inches
inches
C-
Answers
Answer:
A =41 .....
......
......
....C=21
Use the power property to rewrite the expression. log3 ³√y
The Richter scale measures the intensity, or magnitude, of an earthquake. The formula for the magnitude R of an earthquake is R=log(a/T)+B, where a is the amplitude in micrometers of the vertical motion of the ground at the recording station, T is the number of seconds between successive seismic waves, and B is an adjustment factor that takes into account the weakening of the seismic wave as the distance increases from the epicenter of the earthquake. Use the Richter scale formula to find the magnitude R of the earthquake given that the amplitude is 460 micrometers, the time between waves is 3.7 seconds, and B is 2.7.
Answers
The power property states that loga a^x = x loga a = x.
Rewrite the expression log3 ³√y using the power property below:log3 ³√y = log3 (y^(1/3))= (1/3) log3 yNow, we need to use the given Richter scale formula to find the magnitude R of the earthquake.R = log(a/T) + BWhere,a = 460 micrometersT = 3.7 secondsB = 2.7Magnitude, R = log(a/T) + B= log(460/3.7) + 2.7= log(124.3243) + 2.7= 2.0948 + 2.7= 4.7948Therefore, the magnitude of the earthquake is 4.7948, rounded to four decimal places.Note: The Richter scale ranges from 0 to 10. The magnitude increases by a factor of 10 for each unit increase on the scale. So, a magnitude 5 earthquake is 10 times more powerful than a magnitude 4 earthquake, and a magnitude 6 earthquake is 100 times more powerful than a magnitude 4 earthquake.
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30. at which displacement from the localizer and glideslope at the 1.9 miles indicated?
Answers
The displacement from the localizer and glideslope at the 1.9 miles indicated is not specified in the question. Further information is needed to provide a specific answer.
To determine the displacement from the localizer and glideslope at a specific point, such as 1.9 miles, additional information about the navigation system and approach procedure is required. The localizer and glideslope are part of an Instrument Landing System (ILS) used in aviation to guide aircraft during approach and landing. The localizer provides lateral guidance, while the glideslope provides vertical guidance to the aircraft.
The displacement from the localizer and glideslope is typically measured using the deviation indicators on the aircraft's navigation display. These indicators provide information on the aircraft's position relative to the desired course and glide path. The displacement can be indicated in terms of left/right deviation from the localizer or above/below deviation from the glideslope.
Without specific information regarding the navigation system and approach procedure, it is not possible to determine the displacement from the localizer and glideslope at the 1.9 miles indicated
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Answer every question of this quiz
Please note: you can answer each question only once.
Which number shows the intake valve?
OK
Answers
I'd say number 4, number 3 looks like an exhaust valve
What is land administration and cadastral survey
Answers
Cadastral surveying is the sub-field of cadastre and surveying that specialises in the establishment and re-establishment of real property boundaries. ... A cadastral surveyor must apply both the spatial-measurement principles of general surveying and legal principles such as respect of neighboring titles.
FILL IN THE BLANK the term ____ describes the ratio of data size in bits or bytes before and after compression.
Answers
The term compression ratio describes the ratio of data size in bits or bytes before and after compression.
Compression ratio is a measure used to quantify the effectiveness of a compression algorithm in reducing the size of data. It represents the ratio of the original data size to the compressed data size. A higher compression ratio indicates that more data has been compressed and the resulting file size is smaller.
Compression techniques are commonly used to reduce file sizes for storage or transmission purposes. Various compression algorithms, such as ZIP, gzip, and JPEG, employ different methods to eliminate redundant or unnecessary data, resulting in a compressed version of the original file.
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True/False. if a table is in 1nf and its primary key is not a composite key, then the table is also in 2nf.
Answers
The statement is true. In order for a table to be in 2nf, it must first be in 1nf, which means that each column must contain atomic values and there should be no repeating groups of data.
Additionally, the primary key of the table should be able to uniquely identify each row. If the primary key is not a composite key, which means that it is made up of only one column, then the table is also automatically in 2nf.
However, it is important to note that just because a table is in 2nf does not necessarily mean that it is in higher normal forms such as 3nf or BCNF. In order to achieve those higher normal forms, additional steps may need to be taken to ensure that there are no transitive dependencies or partial dependencies in the table.
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why was solving the gauge problem the key to creating an efficient rail network
Answers
Solving the gauge problem was crucial for creating an efficient rail network because it standardized the width of railway tracks. This standardization allowed for interoperability between different rail systems, enabling seamless transportation of goods and passengers across multiple regions and countries.
The gauge problem refers to the issue of different railway networks using varying track widths. In the early days of rail transportation, different regions and countries adopted their own track gauges based on local requirements and engineering decisions. As a result, incompatible track widths hindered the efficient movement of trains between different networks, necessitating costly and time-consuming transshipment of goods and passengers.
By solving the gauge problem through standardization, the rail industry achieved significant benefits. First and foremost, a standardized gauge allowed for the direct movement of trains from one rail system to another, without the need for transshipment or the time-consuming process of transferring goods and passengers between different trains. This streamlined the logistics of rail transportation, reducing costs and increasing operational efficiency.
Moreover, a standardized gauge facilitated the development of through-routing, where trains could travel continuously over long distances, crossing multiple regions and countries without interruption. This seamless connectivity enabled the creation of extensive rail networks that could efficiently transport goods and passengers across vast areas. It promoted economic growth by facilitating trade, connecting markets, and providing reliable transportation options for industries and individuals.
Additionally, standardization of the gauge encouraged the adoption of standardized rolling stock and infrastructure. Rail vehicles, such as locomotives and carriages, could be designed and manufactured to fit the standardized track gauge, allowing for greater interchangeability and cost-effectiveness. Infrastructure, such as tracks, switches, and signaling systems, could also be built uniformly, reducing complexity and improving maintenance and operational efficiency.
In conclusion, solving the gauge problem was a key factor in creating an efficient rail network. By standardizing the track gauge, rail systems achieved interoperability, enabling seamless transportation of goods and passengers across different networks. This led to cost reductions, increased operational efficiency, and the development of extensive rail networks that fostered economic growth and connectivity on a regional and global scale.
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When the third color band is silver it represents
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A steel wire is suspended vertically from its upper end. The wire is 400 ft long and has a diameter of 3/16 in. The unit weight of steel is 490 pcf. Compute:
a. the maximum tensile stress due to the weight of the wire
b. the maximum load P that could be supported at the lower end of the wire. Allowable tensile stress is 24,000 psi.
Answers
Answer:
a) the maximum tensile stress due to the weight of the wire is 1361.23 psi
b) the maximum load P that could be supported at the lower end of the wire is 624.83 lb
Explanation:
Given the data in the question;
Length of wire L = 400 ft = ( 400 × 12 )in = 4800 in
Diameter d = 3/16 in
Unit weight w = 490 pcf
First we determine the area of the wire;
A = π/4 × d²
we substitute
A = π/4 × (3/16)²
A = 0.0276 in²
Next we get the Volume
V = Area × Length of wire
we substitute
V = 0.0276 × 4800
V = 132.48 in³
Weight of the steel wire will be;
W = Unit weight × Volume
we substitute
W = 490 × ( 132.48 / 12³ )
W = 490 × 0.076666
W = 37.57 lb
a) the maximum tensile stress due to the weight of the wire;
σ\(_w\) = W / A
we substitute
σ\(_w\) = 37.57 / 0.0276
= 1361.23 psi
Therefore, the maximum tensile stress due to the weight of the wire is 1361.23 psi
b) the maximum load P that could be supported at the lower end of the wire. Allowable tensile stress is 24,000 psi
Maximum load P that the wire can safely support its lower end will be;
P = ( σ\(_{all\) - σ\(_w\) )A
we substitute
P = ( 24000 - 1361.23 )0.0276
P = 22638.77 × 0.0276
P = 624.83 lb
Therefore, the maximum load P that could be supported at the lower end of the wire is 624.83 lb
Which of the following is NOT true about the Internet of Things (IoT) devices?
Millions of IoT devices connected to the Internet can be harnessed as part of a botnet.
Device manufacturers focus on the device functionality and not security.
Attackers may inject bad data into an IoT network through an IoT device like a sensor.
These small devices are easily patched by the user, whether consumer or industrial.
Answers
Answer:
These small devices are easily patched by the user, whether consumer or industrial.
One of the main challenges with IoT devices is that they are often difficult or impossible to update or patch. Unlike traditional computers or smartphones, which can be easily updated with security patches and other software updates, many IoT devices are not designed to be easily updated by the user. This is because they may have limited processing power, memory, or storage, and may not have the capability to download and install software updates. As a result, many IoT devices are vulnerable to security threats, and attackers may be able to exploit vulnerabilities in these devices to gain access to an IoT network. In order to protect against these threats, it is important for device manufacturers to focus on security when designing IoT devices, and for users to carefully consider the security of the devices they purchase and use.
(Please mark as brainliest!)
Explanation:
How do I draw this from the side?
Answers
Answer:
draw it 3D
Explanation:
because it's a 3D picture
What types of materials are best for preventing heat transfer through convection?.
Answers
The types of materials are best for preventing heat transfer through convection include the following:
FiberglassWoolCottonPaper (wood cellulose)StrawFoamsWhat are the types of energy transmission?In Science, there are three (3) main types of heat energy transmission and these include the following:
ConvectionRadiationConductionWhat is convection?Convection can be defined as a heat energy transfer process which typically involves the transfer of heat, as a result of the movement of mass.
Based on scientific research and experiments, convection is generally considered to be a more effective and efficient means of heat transport on planet Earth when compared to conduction.
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Expert Review is done by end users.
Answers
Answer:nononononono
Explanation:
Which of the following is NOT a line used on blueprints?
Answers
Answer: Photo lines
Explanation: made more sense
what is tcp in network?
Answers
pls mark me as the brainliest
How Monopolies and Collusions Affect the Economy
Describe the concepts of monopoly and collusion in a market economy. Give five examples of monopolies and collusion among sellers and their effects on the market economy.
Answers
Answer:
Image result for How Monopolies and Collusion Affect the Economy Describe the concepts of monopoly and collusion in a market economy. Give five examples of monopolies and collusion among sellers and their effects on the market economy.
Collusion can lead to: High prices for consumers. This leads to a decline in consumer surplus and allocative inefficiency (Price pushed up above marginal cost) New firms can be discouraged from entering the market by types of collusion which act as a barrier to entry.
Explanation:
i hope this helped
Segments ab and cd of the assembly are solid circular rods, and segment bc is a tube. If the assembly is made of 6061-t6 aluminum, determine the displacement of end d with respect to end a.
Answers
The displacement of end D with respect to end A is \(-0.488 \times 10^{-3}\;m\)
Given the following data:
Length = 435 mm to m = 0.435 meter.Modulus of elasticity = 68.9 GPa.Radius A = 20 mm to m = 0.03 meter.Inner radius BC = 30 mm to m = 0.03 meter.Outer radius BC = 40 mm to m = 0.04 meter.Force A = 10 kN.Force B = 15 kN.To determine the displacement of end D with respect to end A:
How to calculate the displacement.First of all, we would do a sectional cut of the circular rods at point A and then determine the sum of forces acting on it:
\(\sum F=0\\\\ 10000+N_1=0\\\\N_1 = -10000\;N\)
Mathematically, the displacement of a circular rod is given by this formula:
\(d = \frac{NL}{AE}\)
Where:
N is the normal force.L is the length.A is the area.E is the modulus of elasticity.Substituting the given parameters into the formula, we have;
\(d_1 = \frac{-10000 \times 0.435}{\frac{3.142 \times 0.02^2}{4} \times 68.9 \times 10^9} \\\\d_1 = \frac{-4350}{0.0003142 \times 68.9 \times 10^9}\\\\d_1 =-0.201 \times 10^{-3}\;meter\)
For section cut BC:
\(\sum F=0\\\\ 10000-20000+N_2=0\\\\N_2 = 10000\;N\)
\(radius = outer\;radius^2 - inner\;radius^2\\\\radius = 0.04^2 -0.03^2=0.0007\;m\)
\(d_2 = \frac{10000 \times 0.435}{\frac{3.142 \times 0.0007^2}{4} \times 68.9 \times 10^9} \\\\d_2 = \frac{4350}{0.00054985 \times 68.9 \times 10^9}\\\\d_2 =0.115 \times 10^{-3}\;meter\)
For section cut D:
\(\sum F=0\\\\ -20000-N_3=0\\\\N_3 =- 20000\;N\)
\(d_3 = \frac{-20000 \times 0.435}{\frac{3.142 \times 0.02^2}{4} \times 68.9 \times 10^9} \\\\d_3 = \frac{-8700}{0.0003142 \times 68.9 \times 10^9}\\\\d_3 =-0.402 \times 10^{-3}\;meter\)
For the total displacement:
The total displacement is equal to the displacement of end D with respect to end A.
\(d_T = d_1 +d_2+d_3\\\\d_T = -0.201 \times 10^{-3} + 0.115 \times 10^{-3}-0.402 \times 10^{-3}\\\\d_T = -0.488 \times 10^{-3}\;m\)
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Which of the following is NOT part of a car's drive train?
A axle
B rotor
C differential
D transmission
Answers
Answer:
B. rotor
Explanation:
The correct answer Is rotor because the others are part of a cars drivetrain
The drive train system exists as a critical element of a vehicle and the transmission exists as an integral part of the drive train. B rotors NOT part of a car's drive train.
Which is not part of the drive train?A drive train exists not really a single part of your car – it's a set of drive train components that interact with the engine to drive the wheels and different regions of the vehicle to thrust it into motion. These components often contain the transmission, differential, driveshaft, axles, CV joints, and wheels.
Therefore, the correct answer is option B rotors.
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A site is underlain by a soil that has a unit weight of 118 lb/ft3. From laboratory shear strength tests that closely simulated the field conditions, the total stress parameters were measured to be C total = 250 lb/ft2 and φ total = 29°. Estimate the shear strength on a horizontal plane at a depth of 12 ft below the ground surface at this site in lbs/ sq ft
Answers
Answer: the shear strength at a depth of 12 ft is 1034.9015 lb/ft²
Explanation:
Given that;
Weight of soil r = 118 lb/ft³
stress parameter C = 250 lb/ft²
φ total = 29°
depth Z = 12 ft
The shear strength on a horizontal plane at a depth of 12ft
ζ = C + δtanφ
where δ = normal stress
normal stress δ = r × z = 118 × 12 = 1416
so
ζ = C + δtanφ
ζ = 250 + 1416(tan29°)
ζ = 250 + 1416(tan29°)
ζ = 250 + 784.9016
ζ = 1034.9015 lb/ft²
Therefore the shear strength at a depth of 12 ft is 1034.9015 lb/ft²
When checking the resistance of a dual voltage wye motor, there should be ____ resistance readings. 1) twelve 2) six 3) three
Answers
Answer:
1) twelve
Explanation:
The dual voltage motors are used in day to day operations. The wye is connected with 9 lead motors. Maximum resistance can be obtained if the resistance are connected in series. To check resistance of dual voltage wye motor there must be twelve resistance readings of 1 ohm each.