Exactly equal amounts (in moles) of gas A and gas B are combined in a 1 L container at room temperature. Gas B has a molar mass that is twice that of gas A. Which of the following is true for the mixture of gases? Check all that apply.
a. The molecules of gas B have a greater average velocity than those of gas A.
b. Gas B has a greater partial pressure than gas A.
c. The molecules of gas B have greater kinetic energy than those of gas A.
d. Gas B makes a greater contribution to the average density of the mixture than gas A.

The concentration of all the species that are in the solution is 0.008 M.

We know that when we dissolve potassium fluoride in solution that it form the acid which is hydro fluoric acid and as such the solution would become acidic. We can now set up the ICE table as we see it below;

                    HF(aq)   +  \(H_{2} O\)(l)    ⇔   \(H_{3} O^+\)(aq)  + \(F^-\)(aq)

I                  0.11                                     x                 x

C                 -x                                       +x                +x

E               0.11 - x                                   x                  x

Ka = [ \(H_{3} O^+\)] [ \(F^-\)]/[HF]

6.3 * 10^-4 = x^2/0.11 - x

6.3 * 10^-4(0.11 - x) = x^2

6.93 * 10^-5 - 6.3 * 10^-4x = x^2

Using the quadratic method;

x^2 + 6.3 * 10^-4x - 6.93 * 10^-5 = 0

x=0.008 M

Hence;

[ \(H_{3} O^+\)] = [ \(F^-\)] = [\(K^+\)] = 0.008 M

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a. acceleration

----------------------

The flow of water in a pipe and the flow of electrons in a wire are both examples of fluid flow and are caused by different physical phenomena.

The flow of water in a pipe is caused by a pressure difference, also known as a pressure gradient, between two points. If the pressure at one end of the pipe is higher than the pressure at the other end, water will flow from the high-pressure end to the low-pressure end. The flow rate will depend on the pressure difference, the diameter of the pipe, and the viscosity of the fluid.

The flow of electrons in a wire, on the other hand, is caused by a difference in electrical potential, also known as a voltage difference, between two points. If the voltage at one end of the wire is higher than the voltage at the other end, electrons will flow from the high-voltage end to the low-voltage end. The flow rate will depend on the voltage difference, the resistance of the wire, and the number of electrons available to flow.

In summary, the cause of the flow of water in a pipe is a pressure difference, while the cause of the flow of electrons in a wire is a voltage difference.

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Answer: A and D

Explanation:

I hope this helps. Sorry if I’m wrong

Answer:

Region D

Explanation:

The region is on the tectonic plate boundaries.

Answer:

B. Alleles

Explanation:

Answer:

About 110 g.

Your tool of choice here will be the solubility graph for potassium nitrate, KNO3, in water.

Answer:

613

Explanation:

search up that question at coursehero.com...these questions were originally made there, with the answers

Answer:

An another result of climate change is the increasing in the frequency of high intensity rainfall events,which increase the regional water damage events.If the precipitation volume decreases in summer time and increases in winter time,then it will be lower infiltration and more runoffs.

Severe hydro-meteorological activities, including heavy precipitations or lack thereof, floods, and droughts, are becoming greater excessive and common because of weather exchange and can strongly affect water first-rate.

Hydrometeorological hazards, such as floods, droughts, landslides, and hurricane surges, can pose an instantaneous risk to lives and impact livelihoods by way of detrimental and destroying transport links, power components, agencies, and agricultural land.

Hydrometeorological dangers are a result of extreme meteorological and climate events, along with floods, droughts, hurricanes, tornadoes, landslides, or mudslides.

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Answer:

Heat = 7375J

Final temperature of the mixture = 27.35°C

Explanation:

In the reaction:

2HCl(aq) + Ba(OH)₂(aq) → BaCl₂(aq) + 2H₂O(l) ΔH = –118 kJ

When 2 moles of HCl reacts with excess of Ba(OH)₂ there are released 118kJ.

In the reaction, moles of HCl and Ba(OH)₂ that reacts are:

Moles HCl = 0.250L ₓ (0.500 moles / L) = 0.125 moles HCl

Moles Ba(OH)₂ = 0.500L ₓ (0.500 moles / L) = 0.250 moles Ba(OH)₂

For a complete reaction of 0.125 moles of HCl you need:

0.125 mol HCl ₓ (1 mole Ba(OH)₂ / 2 moles HCl) = 0.0625 moles Ba(OH)₂

As you have 0.250 moles of Ba(OH)₂, this reactant is in excess

2 moles of HCl that react release 118kJ, 0.125 moles of HCl release:

0.125 moles HCl ₓ (118kJ / 2 moles) = 7.375kJ =

The heat released can be obtained with the formula:

Q = C×m×ΔT

Where Q is heat, C specific heat of the solution, m its mass and ΔT change in temperature.

Replacing:

Q = C×m×ΔT

7375J = 4.18J/g°C×750.0g×ΔT

2.35°C = ΔT

As ΔT = Final T - Initial T:

2.35°C = Final T - 25.0°C

Answer:

ok so I don't really understand how you get 8 digits, but Q1 goes to Digit 1, Q2 goes to digit 3, Q3 goes to digit 4, and Q4 goes to digit 2

Explanation:

sorry!!!!!!

Answer:

\(8.9\textrm{ g/cm}^3\)

Explanation:

\(\frac{178}{20}=8.9\textrm{ g/cm}^3\)

Answer:

Density=178g÷20cm³

            =8.9g/cm³

The part of Dalton's atomic theory that was disproved by Thomson's experiment is toms cannot be created, destroyed, or divided into smaller particles. The correct option is A.

According to Dalton's atomic theory, atoms are tiny units of matter that make up all matter, including elements, compounds, and mixtures.

Following are some of the theory's postulates: All substance is made up of atoms, which are exceedingly tiny particles. Atoms belonging to the same element share the same mass and chemical composition.

Thomson presented the plum pudding model of the atom, which contained positively charged "soup" and negatively charged electrons inside.

Thus, the correct option is A. Atoms cannot be created, destroyed, or divided into smaller particles.

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Answer:

a) The empirical formula of the hydrocarbon is CH4.

b) The molecular formula of the hydrocarbon is (CH4) * 1.875 = C1.75H7

Explanation:

(a) To find the empirical formula of the hydrocarbon, we can follow these steps:

Convert the percentages of each element to grams: 80% C = 0.8 * 12 g/mol = 9.6 g C, and 20% H = 0.2 * 1 g/mol = 0.2 g H.

Calculate the number of moles of each element: 9.6 g C / 12 g/mol = 0.8 mol C, and 0.2 g H / 1 g/mol = 0.2 mol H.

Divide each number of moles by the smallest number of moles to find the ratio of the elements: 0.8 mol C / 0.2 mol H = 4, and 0.2 mol H / 0.2 mol H = 1.

(b) To find the molecular formula of the hydrocarbon, we need to know the relative molecular mass (RMM) of the compound, which is given as 30. The empirical formula of the compound is CH4, which has a RMM of 12 + 4 = 16. To find the molecular formula, we need to multiply the empirical formula by a factor that will give us the correct RMM. In this case, we can multiply the empirical formula by a factor of 30 / 16 = 1.875. Multiplying the empirical formula by this factor gives us a molecular formula of (CH4) * 1.875 = C1.75H7.

Answer:

The number of molecules of water us 1.50× 10²⁵ molecules

Explanation:

From N=nL

where L =avogadro number ( 6.02× 10^²³ entities)

The number of the molecules of water =1

n (amount of substance)=25 moles

hence (N) = 25×1×6.02×10^²³

=1.50×10²⁵ molecules of H2O

Answer:

Domain

Explanation:

This is because Linnaeus taxonomy is a system of classification which was invented by a swedish Botanist called Carl Linnaeus and it is refered to hierarchy of grouping organisms called taxa. It involve 7 system of classifications and they include Kingdom, Phylum, Class, Order, Family, Genus, and Species.

Answer:

\(Q=210.8kJ\)

Explanation:

Hello!

In this case, since the heat of vaporization is related with the energy required by a substance to undergo the phase transition from liquid to gas, we can compute such amount of energy as shown below:

\(Q=m\Delta H_{vap}\)

In such a way, since the enthalpy of vaporization is given as well as the mass, we compute the energy as shown below:

\(Q=155g*1360J/g\\\\Q=210.8kJ\)

Best regards!

Answer:

CuBr

Mn2O3

Hg2I2

Mg3(PO3)2

Explanation:

When writing the formula of an ionic compound, we use the exchange method.

The symbol of each element or ion is written with it's charge as a superscript. The charges are then interchanged, the signs are dropped and the figures are written as subscripts. This gives the formula of compound.

At equilibrium, the HI concentration is 2.92 mol/L.

For the process H2(g)+CO2(g)updownarrow H2O+CO. at 1660 °C, the equilibrium constant KP is 4. In a 5 liter flask, 0.8 moles each of H2 and CO2 are first injected. Reactions occur in the following order with relation to H2: 1. In experiments 1 and 2, the reaction rate doubles when the initial concentration of H2 is doubled while the initial concentration of Cl2 is held constant.

H2(g) + I2(g) ⇌ 2HI(g)

c = [HI]² / [H2][I2]

At the specified temperature, c = 53.3, hence the following can be written:

53.3 = [HI]^2 / (0.400 mol/L) × (0.400 mol/L)

or, [HI]² = 53.3 × 0.16

or, [HI]² = 8.528

or, [HI] = sqrt(8.528) mol/L

or, [HI] = 2.92 mol/L

As a result, 2.92 mol/L of HI are present at equilibrium.

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Answer:

From the Online Catalog to the Shelf

Libraries in the United States generally use either the Library of Congress Classification System (LC) or the Dewey Decimal Classification System to organize their books. Most academic libraries use LC, and most public libraries and K-12 school libraries use Dewey.

Explanation:

Answer:

From the Online Catalog to the Shelf

Libraries in the United States generally use either the Library of Congress Classification System (LC) or the Dewey Decimal Classification System to organize their books. Most academic libraries use LC, and most public libraries and K-12 school libraries use Dewey.

A light wave in a medium has a wavelength of 5107 m and a frequency of 41014 Hz.

Its frequencies range from 4 to 8 hertz (Hz), or cycles per second, and its wavelengths range from 380 nanometers (nm), or 1.5 nm, to 740 nm, or 2.9 to 105 inches.

The parts of the electromagnetic spectrum are designated as follows, from highest to lowest energy: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves. The radio wave region of the electromagnetic spectrum includes microwaves (such as those found in microwave ovens).

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The equation for the equilibrium constant (K) of the reaction studied in this exercise can be written as follows: K = ([\(CI_20\), 2-] * [\(H_20\)(1)]) / ([\(C0_4^ 2\)-] * [Ht])

In this equation, the concentrations of the species involved in the reaction are represented by the square brackets [ ]. The subscripts indicate the stoichiometric coefficients of each species in the balanced chemical equation.

The reaction being studied involves the following species:

\(C0_4^ 2\)- (ag) + 2Ht (ag) = \(CI_20\), 2- (ag) + \(H_20\)(1)

In the equilibrium constant expression, the concentration of \(CI_20\), 2- is multiplied by the concentration of \(H_20\)(1) and divided by the product of the concentrations of \(C0_4^ 2\)- and Ht. The stoichiometric coefficients in the balanced equation are used as exponents for the concentrations of the respective species.

It is important to note that the concentrations used in the equilibrium constant expression should be in molar units (mol/L) or expressed as partial pressures for gases.

Additionally, the equilibrium constant is specific to a given temperature, and its value provides information about the relative amounts of reactants and products at equilibrium.

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Answer:

Two positive aspects of using methane recapture systems are able to generate significant electricity. Another benefit is that the process of anaerobic digestion creates heat that can be used to warm buildings where animals are kept

Answer:  The correct answer is;

Two positive aspects of using methane recapture systems include lowering the impact on greenhouse gasses and the production of energy. Methane is a very potent greenhouse gas that is contributing to global warming. As a result, the recapturing process reduces the methane impacts of global warming by reclaiming and reusing the gas for other purposes. Recaptured methane can be stored and used to generate electricity or used as fuel to power updated vehicles and other engines on the farm. The overall benefits from this combination are reducing impacts causing global warming and lower the cost of electricity or fuel on the farm.

Explanation:  This answer has been confirmed correct.

Answer:

the heat energy is transformed to any kind of energy depending on what it's meant to be transformed to.

remember it cannot be destroyed so it's definitely transformed to some kinda energy

The volume in millilitres of 2.37M potassium hydroxide that contains 9.29g of solute is 70mL.

Volume of a solution can be calculated from the molarity, which is the concentration of a substance in solution, expressed as the number moles of solute per litre of solution.

Molarity = no of moles ÷ volume

no of moles = mass ÷ molar mass

Molar mass of pottasium hydroxide (KOH) = 56.1056 g/mol

moles = 9.29g ÷ 56.1056 g/mol = 0.166moles

2.37 = 0.166/V

V = 0.166 ÷ 2.37

V = 0.07L

Volume in millilitres = 70mL

Therefore, 70mL is the volume of the pottasium hydroxide solution.

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Answer:

it is a soft and very cold molocules but at the touch of a hand it will melt because of how compact the molocules are

Explanation:

gallium can only stay a solid under 85.59°F so is someone had is in there had is would end up like ice cream

Hello, this is Bing. I can help you with your question. Based on the information I found on the web, **H2** can be broken down into its two atoms of hydrogen (H) by supplying enough energy to overcome the bond that holds them together⁴. This process is called **dissociation** and requires an energy equal to or greater than the **dissociation energy** of H2, which is about 436 kJ/mol⁴.

One way to break down H2 is by using **electricity** to split water (H2O) into hydrogen (H2) and oxygen (O2) through a process called **electrolysis**¹. In this process, water is decomposed into its elements by passing an electric current through it. The electric current is provided by a battery or another source of electricity and the water needs to have an **electrolyte**, such as salt or acid, added to it to make it conductive¹. Two electrodes, usually made of metal or other conductive material, are inserted into the water and connected to the battery. The electrode connected to the positive terminal of the battery is called the **anode** and the one connected to the negative terminal is called the **cathode**¹. When the electric current flows through the water, hydrogen gas bubbles form at the cathode and oxygen gas bubbles form at the anode¹. The overall chemical reaction for electrolysis of water is:

2 H2O → 2 H2 + O2

Another way to break down H2 is by using **heat** to cause a reaction between hydrogen and oxygen that produces water and releases a large amount of energy. This reaction is called **combustion** or **oxidation** and can be ignited by a spark or a flame³. The reaction is very fast and explosive and can be dangerous if not controlled. The overall chemical reaction for combustion of hydrogen is:

2 H2 + O2 → 2 H2O

I hope this helps you understand how H2 can be broken down and what methods are used to do so.

Answer:

The person above me is correct  

Explanation:

It's D

Based on the given reactions, the compounds are as follows:

A: The specific product formed from the reaction between prop-1-yne and either 2HBr or H2O2.

B: The product formed when compound A reacts with 2H2O.

C: The product formed when compound B reacts with K2CO3(aq).

D: The product formed from the heat-induced reaction of compound C.

E: The product formed when compound D reacts with HBr.

Based on the given reactions, let's analyze the compounds involved:

Reaction 1: prop-1-yne + 2HBr/H2O2 = A

The reactant prop-1-yne reacts with either 2HBr or H2O2 to form compound A. The specific product formed will depend on the reaction conditions.

Reaction 2: A + 2H2O = B

Compound A reacts with 2H2O (water) to form compound B.

Reaction 3: B + K2CO3(aq) = C

Compound B reacts with K2CO3(aq) (potassium carbonate dissolved in water) to form compound C.

Reaction 4: C + heat = D

Compound C undergoes a heat-induced reaction to form compound D.

Reaction 5: D + HBr = E

Compound D reacts with HBr (hydrobromic acid) to form compound E.

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Answer:

किसी पदार्थ की ऊष्मीय चालकता को प्रति इकाई तापमान अंतर के प्रति इकाई क्षेत्र की सामग्री की एक इकाई मोटाई के माध्यम से गर्मी हस्तांतरण की दर के रूप में परिभाषित किया गया है। किसी पदार्थ की ऊष्मीय चालकता इस बात का माप है कि उस पदार्थ में कितनी तीव्र ऊष्मा प्रवाहित होगी। थर्मल चालकता के लिए एक बड़ा मूल्य इंगित करता है कि सामग्री एक अच्छा गर्मी कंडक्टर है, और एक कम मूल्य इंगित करता है कि सामग्री एक खराब गर्मी कंडक्टर या इन्सुलेटर है। कमरे के तापमान पर शुद्ध तांबे की तापीय चालकता 401 W / m है। K, जो इंगित करता है कि एक 1m मोटी तांबे की दीवार 401 W / m 2 की दर से गर्मी का संचालन करेगीप्रति दीवार के क्षेत्र का अंतर दीवार के पार तापमान अंतर। चित्रा 2.3 सामान्य तापमान और दबाव में पदार्थ के विभिन्न राज्यों के लिए तापीय चालकता की सीमा को दर्शाता है। एक ठोस की ऊष्मीय चालकता, गैस की तुलना में चार गुना अधिक परिमाण की हो सकती है। यह प्रवृत्ति काफी हद तक दोनों राज्यों के बीच अंतर-संबंधी अंतर के कारण है।

ठोस राज्य

सामग्रियों के आधुनिक दृष्टिकोण में, एक ठोस में मुक्त इलेक्ट्रॉनों और एक आवधिक व्यवस्था में बाध्य परमाणुओं का समावेश हो सकता है जिसे जाली कहा जाता है। तदनुसार, थर्मल ऊर्जा का परिवहन दो प्रभावों के कारण होता है: मुक्त इलेक्ट्रॉनों का पलायन और जाली कंपन तरंगें। ये प्रभाव योगात्मक हैं, जैसे कि तापीय चालकता k , इलेक्ट्रॉनिक घटक k e और समरूप घटक k l का योग है

k = k e + k l

(2.7)

सामान्य तापमान और दबाव में विभिन्न राज्यों के लिए थर्मल चालकता की 2.3 रेंज चित्रा

k e विद्युत प्रतिरोधकता के व्युत्क्रमानुपाती होता है । शुद्ध धातुओं के लिए, जो कम के हैं , k e , k l की तुलना में बहुत बड़ा है । इसके विपरीत, मिश्र धातुओं के लिए, जो कि काफी बड़े होते हैं , k l से k का योगदान अब नगण्य नहीं है। गैर-धात्विक ठोस के लिए, k को मुख्य रूप से k l द्वारा निर्धारित किया जाता है , जो कि जाली के परमाणुओं के बीच परस्पर क्रिया की आवृत्ति पर निर्भर करता है। जाली व्यवस्था की नियमितता का k l पर महत्वपूर्ण प्रभाव पड़ता है , क्रिस्टलीय (सुव्यवस्थित) सामग्री की तरह, क्वार्ट्ज जैसी सामग्री में कांच जैसी अनाकार सामग्री की तुलना में अधिक ऊष्मीय चालकता होती है। वास्तव में, क्रिस्टलीय के लिए, गैर-धात्विक ठोस जैसे कि हीरा और बेरिलियम ऑक्साइड, k l काफी बड़े हो सकते हैं, जो कि अच्छे कंडक्टरों से जुड़े k के मूल्यों से अधिक होते हैं , जैसे कि एल्यूमीनियम।

इन्सुलेशन सिस्टम

थर्मल इंसुलेशन में कम तापीय चालकता वाली सामग्री शामिल होती है, जो एक कम प्रणाली वाली तापीय चालकता को प्राप्त करने के लिए संयुक्त होती है। फाइबर-, पाउडर-, फ्लेक-टाइप इंसुलेशन में, ठोस पदार्थ को पूरी तरह से एक एयर स्पेस में फैलाया जाता है। ऐसी प्रणालियों को एक प्रभावी तापीय चालकता की विशेषता होती है , जो ठोस पदार्थ की तापीय चालकता और सतह विकिरणकारी गुणों पर निर्भर करती है, साथ ही साथ हवा या शून्य स्थान की प्रकृति और मात्रात्मक अंश। प्रणाली का एक विशेष पैरामीटर इसकी थोक घनत्व (ठोस द्रव्यमान / कुल मात्रा) है, जो उस तरीके पर दृढ़ता से निर्भर करता है जिसमें ठोस सामग्री परस्पर जुड़ी हुई है।

द्रवित अवस्था

चूंकि इंटरमॉलिक्युलर स्पेसिंग बहुत बड़ी होती है और अणु की गति ठोस अवस्था की तुलना में द्रव अवस्था के लिए अधिक यादृच्छिक होती है, इसलिए थर्मल एनर्जी ट्रांसपोर्ट कम प्रभावी होता है। इसलिए गैसों और तरल पदार्थों की तापीय चालकता ठोस पदार्थों की तुलना में छोटी होती है।

ऊष्मीय विसरणशीलता

गर्मी हस्तांतरण समस्याओं के हमारे विश्लेषण में, पदार्थ के कई गुणों का उपयोग करना आवश्यक होगा। इन गुणों को आम तौर पर थर्मोफिजिकल गुणों के रूप में संदर्भित किया जाता है और इसमें दो अलग-अलग श्रेणियां, परिवहन और थर्मोडायनामिक गुण शामिल होते हैं। परिवहन गुणों में प्रसार दर गुणांक जैसे कि के, थर्मल चालकता (गर्मी हस्तांतरण के लिए), और , गतिज चिपचिपापन (गति हस्तांतरण के लिए) शामिल हैं। दूसरी ओर, थर्मोडायनामिक गुण, एक प्रणाली के संतुलन की स्थिति से संबंधित हैं। घनत्व ( ) और विशिष्ट ऊष्मा ( C p ) दो ऐसे गुण हैं जिनका उपयोग थर्मोडायनामिक विश्लेषण में बड़े पैमाने पर किया जाता है। उत्पाद सी पीआम तौर पर वॉल्यूमेट्रिक ताप क्षमता को कहा जाता है , जो थर्मल ऊर्जा को स्टोर करने के लिए एक सामग्री की क्षमता को मापता है। क्योंकि बड़े घनत्व के पदार्थों को आमतौर पर छोटे विशिष्ट हीट्स, कई ठोस और तरल पदार्थों की विशेषता होती है, जो कि बहुत अच्छा ऊर्जा भंडारण मीडिया है, इसमें तुलनीय ताप क्षमता होती है। हालांकि उनकी बहुत छोटी घनत्व के कारण, गैसें थर्मल ऊर्जा भंडारण के लिए खराब अनुकूल हैं।

ऊष्मा अंतरण विश्लेषण में, ऊष्मा चालकता के लिए तापीय चालकता का अनुपात एक महत्वपूर्ण गुण है जिसे तापीय विवर्तनशीलता कहा जाता है , जिसमें m 2 / s की इकाइयाँ होती हैं ।

(2.8)

यह तापीय ऊर्जा को संग्रहीत करने की क्षमता के सापेक्ष तापीय ऊर्जा का संचालन करने के लिए एक सामग्री की क्षमता को मापता है। बड़ी की सामग्री उनके थर्मल वातावरण में बदलाव के लिए जल्दी से प्रतिक्रिया देगी, जबकि छोटे की सामग्री अधिक सुस्त प्रतिक्रिया देगी, एक नई संतुलन स्थिति तक पहुंचने में अधिक समय लेगी।

Answer:

Yes.

Explanation:

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In this according to the attached file, we infer that the aniline can be nitrated by the addition of nitric acid and in presence of sulfuric acid that provides an acidic media. It leads to the formation of o-nitroaniline, m-nitroaniline and p-nitroaniline whereas the major products are the last two due to the steric hindrance.

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