Explain how Newton’s cradle demonstrates the law of conservation of energy.

Answer:

OH NO

Explanation:

Just try you best to that's what I do!

Answer: i no rite i dont ether

Explanation:

Answer:

“GMOs have helped farmers reduce their environmental footprint by allowing them to use fewer inputs and enabling a shift to reduced tillage. These practices have led to less time spent on a tractor, less fuel used and fewer emissions.

Hope this helps!!!

Answer:

I think that the metric system is one of the easiest systems once you understand it (no hate)

In titration of an unknown weak monoprotic acid,  equivalence point is reached when the acid (analyte) is completely neutralized by  base (analyte).

One mole of  acid produce one mole of acetate; so,

0.025 L acid x 0.1 mol base = 0.0025 mol

1 L soln

0.0025 mol  x 1 mol = 0.0025 mol

1 mol acid

So, what volume is the acetate i will, Not 35 mL you added a solution

of acid

how much base did we add? 1 mol acid for the 1 mole of  base

0.0025 mol CH₃CO₂H x 1 mol NaOH = 0.0025 mol NaOH

1 mol CH₃COOH

where did the NaOH come from? a 0.1 M NaOH solution

0.0025 mol of the  NaOH x 1 L of solution = 0.025 L of the NaOH

0.1 mol NaOH

so, total volume is

total voumel = volume of acid + vol titrant

vol = 0.025 L + 0.025 L = 0.050 L

So, the concentration is

0.0025 mol of acid

= 0.050 M

0.050 L

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Answer:

HF(aq)+NaOH(aq)→NaF(aq)+H2O(l)

Explanation:

Complete question

Dissolved hydrofluoric acid reacts with dissolved sodium hydroxide to form water and aqueous sodium fluoride. What is the net ionic equation

Equilibrium equation between the undissociated acid and the dissociated ions

HF(aq)⇌H+(aq)+F−(aq)

Sodium hydroxide will dissociate aqueous solution to produce sodium cations, Na+, and hydroxide anions, OH−

NaOH(aq)→Na+(aq)+OH−(aq)

Hydroxide anions and the hydrogen cations will neutralize each other to produce water.

H+(aq)+OH−(aq)→H2O(l)

On combining both the equation, we get –  

HF(aq)+Na+(aq)+OH−(aq)→Na+(aq)+F−(aq)+H2O(l)

The Final equation is  

HF(aq)+NaOH(aq)→NaF(aq)+H2O(l)

Among the given options, the gas with the highest rate of effusion is NO2 (option D).

The rate of effusion is determined by Graham's law of effusion, which states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass. Therefore, the gas with the lowest molar mass will have the highest rate of effusion.

Let's compare the molar masses of the gases provided. N2O has a molar mass of 44 g/mol, N2O4 has a molar mass of 92 g/mol, NO3 has a molar mass of 62 g/mol, and NO2 has a molar mass of 46 g/mol.

Among these options, NO2 has the lowest molar mass, which means it will have the highest rate of effusion according to Graham's law. The other gases, N2O, N2O4, and NO3, have higher molar masses, and therefore, their rates of effusion will be slower compared to NO2.

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Neil Bohr used the fluorescent screen and an alpha particle detector to study the structure of an atom.

An atom is defined as the smallest unit of matter which forms an element. Every form of matter whether solid,liquid , gas consists of atoms . Each atom has a nucleus which is composed of protons and neutrons and shells in which the electrons revolve.

Atoms of the same element are similar as they have number of sub- atomic particles which on combination do not alter the chemical properties of the substances.

The atom as a whole is neutral and stable due to presence of oppositely charged particles.

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18.6 grams of chlorine gas are allowed to react with with 3.82 grams of hydrogen to form hydrochloric acid.

H2+Cl2 → 2HCl

At normal temperature and pressure, hydrogen chloride (HCl), a gas composed of the elements hydrogen and chlorine, is a gas. Hydrochloric acid is the name given to a gaseous solution in water. Chlorine (Cl2) gas and hydrogen (H2) gas can be combined directly to generate hydrogen chloride; the process is quick at temperatures above 250 °C (482 °F). Heat is released during the reaction, which is described by the equation H2 + Cl2 2HCl, and moisture seems to speed up the process. A chloride, often sodium (NaCl) chloride, is typically used to create hydrogen chloride both in laboratories and on an industrial scale by reacting with sulfuric acid (H2SO4). Additionally, it is created when certain chlorides (such as phosphorus trichloride, PCl3,

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Answer:

i belive the answer is A if it's not i am very sorry

The suitable metals for use as sacrificial anodes to protect against corrosion of underground iron pipes are magnesium, zinc, and aluminum.

These metals have a higher electrochemical potential than iron, which causes them to corrode instead of the iron pipe. This sacrificial corrosion helps protect the iron pipe from further damage. Other metals like copper, silver, and gold are not suitable as sacrificial anodes because they have a lower electrochemical potential than iron, meaning they will not corrode in preference to the iron pipe.

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INFORMATION:

We know that:

- pure water boils at 99.8 degrees celcius

And we must calculate the expected elevated boiling point of a solution of 2.50g of CaCl2, in 50.0mL (i.e., 50.0g) of H2O

STEP BY STEP EXPLANATION:

To calculate it, we need to use that:

Boiling point of solution = boiling point of pure solvent + boiling point elevation (ΔTb)

The elevation in boiling point (ΔTb) is proportional to the concentration of the solute in the solution. It can be calculated via the following equation.

Where,

- i is the Van’t Hoff factor

- Kb is the ebullioscopic constant

- m is the molality of the solute

From given information, we know that:

- i = 3

Now, the ebullioscopic constant (Kb) is often expressed in terms of °C * kg * mol^-1. The value of Kb for water is 0.512.

So, kb = 0.512 °C * kg * mol^-1

Then, we must calculate the molality

So, m = 0.45 mol/kg

Replacing the values in the formula for ΔTb

Finally, the expected elevated boiling point of the solution would be

ANSWER:

The expected elevated boiling point of the solution is 100.49 °C

Answer:

i think this is correct

Explanation:

For amplitude measurements, you count the number of vertical divisions occupied by the signal's vertical signal and then multiply by the vertical scale. The example below shows the process for measuring the peak-to-peak voltage of a signal.

Answer:

1. One atom pulls an electron from another atom.

2. Forming bonds releases energy and is exothermic.

3.pull electrons away from other elements.

4. Additional bonds require more energy to break, so the bond energy is higher.

5. −153

Explanation:

I just took it amor :) beijos good luck !

Answer:

1. One atom pulls an electron from another atom.

2. Forming bonds releases energy and is exothermic.

3. pull electrons away from other elements.

4. Additional bonds require more energy to break, so the bond energy is higher.

5. −153

Explanation:

i did the quick check i got 100%

Answer:

B

Explanation:

Answer:

B. Always add the acid to the water slowly, taking a moment to stir between drops

Answer:

The Dehydrohaogenation of 1-bromo propane with alcoholic KOH gives propene which on again hydrohalogenation with HBr gives 2-bromo propane due to Markonikove's rule for addition.

Explanation:

Here is a MATLAB code that calculates and plots the concentration profiles of NH ₃, NH₄+, NO₂-, and NO₃- as a function of time at T=298 K and neutral pH, given the rate constants and initial concentrations:

```matlab

% Rate constants (k) and initial concentrations ([C])

k1 = 0.1;   % Rate constant for NH₃ + H₂O₂ -> NH₂ + H₂O

k2 = 0.05;  % Rate constant for NH₂ + NO₃- -> NO₂- + H₂O

k3 = 0.08;  % Rate constant for NO₂- -> NO₃- + N₂

C_NH₃ = 1.0;    % Initial concentration of NH₃

C_H2₂O₂ = 0.5;   % Initial concentration of H₂O₂

C_NH₄ = 0.0;    % Initial concentration of NH₄+

C_NO₂ = 0.0;    % Initial concentration of NO₂-

C_NO₃ = 0.0;    % Initial concentration of NO₃-

% Time vector

t = 0:0.1:10;   % Time range from 0 to 10 with a step size of 0.1

% Calculation of concentrations at each time point

for i = 1:length(t)

   NH₃(i) = C_NH₃ * exp(-k1*t(i));

   NH₄(i) = C_NH₃ - NH₃(i);

   NO₂(i) = C_NO₂ + k₂ * (NH₄(i) - C_NH₄) * t(i);

   NO₃(i) = C_NO₃ + k₃ * NO₂(i) * t(i);

end

% Plotting concentration profiles

plot(t, NH₃, 'r-', t, NH₄, 'g-', t, NO₂, 'b-', t, NO₃, 'm-');

xlabel('Time');

ylabel('Concentration');

legend('NH₃', 'NH₄+', 'NO₂-', 'NO₃-');

```

The provided MATLAB code calculates and plots the concentration profiles of NH₃, NH₄+, NO₂-, and NO₃- as a function of time based on the given rate constants and initial concentrations. The code uses a time vector to define the time range for which the concentrations will be calculated.

Inside the for loop, the concentrations of NH₃, NH₄+, NO₂-, and NO₃- are calculated at each time point using the given rate constants and the previous concentrations. The concentration of NH₃ decreases exponentially over time due to the reaction NH₃ + H₂O₂ -> NH₂ + H₂O, where k1 is the rate constant. NH₄+ concentration is the difference between the initial NH₃ concentration and the current NH₃ concentration.

The concentration of NO₂- increases with time due to the reaction NH₂ + NO₃- -> NO₂- + H₂O, where k₂ is the rate constant. The change in NH₄+ concentration from its initial value is multiplied by k₂ and the time to calculate the increase in NO₂- concentration.

Finally, the concentration of NO₃- increases with time due to the reaction NO₂- -> NO₃- + N₂, where k₃ is the rate constant. The previous NO₂- concentration is multiplied by k₃ and the time to determine the increase in NO₃- concentration.

The resulting concentration profiles are then plotted using the plot function, with time on the x-axis and concentration on the y-axis. Each compound is represented by a different color line in the plot.

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Answer:

Photons of light from source X carry more energy than photons of light from source Y

Explanation:

According to Einstein's photoelectric equation, the kinetic energy of the emitted photoelectron depends on the energy of the incident photon and the work function of the metal.

For photoelectrons to be ejected from a metal surface, the energy of incident photon must be greater than the work function of the metal. If not, no electron is ejected.

The energy of photon X must be greater than the work function of the metal while the energy of photon Y is less than the work function of the metal. This brings us to the conclusion that the energy of photon X must be greater than that of photon Y.

Answer:

c

Explanation:

i got it right on edg2020

Answer:

It forms a barrier that prevents corrosive substances from reaching the underlying steel or iron. The zinc serves as a sacrificial anode so that even if the coating is scratched, the exposed steel will still be protected by the remaining zinc. The zinc protects its base metal by corroding before iron.

Explanation:

Answer:

It protects it from corrosion.

Explanation:

Zinc protects iron and steel from the relentless forces of corrosion. Galvanizing iron and steel by dipping them in molten zinc creates an alloy that can, in the right environmental conditions, protect the iron or steel beneath it for 100 years or more.

Measurement is the number or quantity that shows the size of the object. The measurements from longest to shortest are yards, km, inch, and nm.

Length is measured by various scales that include the distance and the range that can be stated in a unit. The unit yard is the longest and is followed by kilometers, inches, and the nanometer.

Therefore, the order is yards, km, inch, and nm.

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The given statement "Running water is the single most important erosional agent sculpting Earth's land surface" is false because it fails to acknowledge the significant role played by other erosional agents such as glaciers, wind, waves, and gravity.

Running water is indeed a significant erosional agent, but it is not the sole or primary agent responsible for shaping Earth's land surface. Erosion refers to the process of wearing away or removal of materials from the Earth's surface. While running water, particularly in the form of rivers and streams, plays a crucial role in erosion, other agents such as glaciers, wind, waves, and gravity also contribute significantly.

Glaciers, for example, have immense erosive power as they move across the land, carving out valleys and shaping mountains. The movement of ice and the grinding action of rocks embedded in the glacier can profoundly reshape the landscape.

Wind erosion occurs when wind transports and deposits sediment, resulting in the formation of sand dunes and the gradual weathering of rocks. Waves erode coastlines through processes like abrasion, hydraulic action, and corrosion. Gravity also plays a vital role in erosion, causing landslides, mass wasting, and the downward movement of materials on slopes.

While running water is important in shaping the Earth's surface, it is essential to acknowledge the significant role played by other erosional agents as well. The combined action of these forces contributes to the diverse and dynamic landforms we observe on our planet.

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In Step A, the reagent is NBS with benzoyl peroxide in CCl4 at 80°C.

In Step B, the reagent is NaOC2H5 in C2H5OH at 50°C.

Acne lesions can be effectively treated with benzoyl peroxide. It has no effect on antibiotic resistance.  It can be used with salicylic acid, sulfur, erythromycin, clindamycin, or adapalene (antibiotics) (a synthetic retinoid). Benzoyl peroxide/clindamycin and adapalene/benzoyl peroxide are two frequent combination medicines, with adapalene being a chemically stable retinoid that may be coupled with benzoyl peroxide, unlike Tazarotene and tretinoin.

For the treatment of acne lesions, combination treatments such as benzoyl peroxide/clindamycin and benzoyl peroxide/salicylic acid tend to be somewhat more effective than benzoyl peroxide alone.  In the United States, the combination tretinoin/benzoyl peroxide was authorized for medicinal use in 2021.

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Answer: A. troposphere :)

hope this helps

Explanation:

<3

83.3% yield

Explanation:

First, we need to convert 240 g of \(Fe_{2}O_{3}\) into moles:

\(240 \:g \:Fe_{2}O_{3} \:\times(\frac{1\:\text{mol}\:Fe_{2}O_{3}}{159.69\: \text {g}\:Fe_{2}O_{3}})\)

\(=1.50 \:\text{mol}\:Fe_{2}O_{3}\)

Next, find the theoretical Fe yield using molar ratios.

\(1.50 \: \text {mol} \: Fe_{2}O_{3}\: \times (\frac{2\: \text{mol} \: Fe}{1 \:\text{mol} \: Fe_{2}O_{3}})\)

\( = 3.00 \: \text{mol} \: Fe\)

Then convert this back into grams:

\(3.00 \: \text{mol} \:Fe \times (\frac{55.845 \: \text{g} \: Fe}{1 \: \text{mol} \: Fe}) = 168 \: \text{g} \: Fe\)

Note that actual yield is only 140 g Fe so percentage yield is

\(\dfrac{140\:\text{g}\:Fe}{168\:\text{g}\:Fe} \times 100\)%= 83.3%

83.3%

The answer is 83.3%

Answer:

0.96

Explanation:

Number of moles of Fe(III) = 3/1000 *  0.002 M = 6 * 10^-6 moles

Number of moles of SSA = 7/1000 * 0.02 = 1.4 * 10^-4 moles

Total number of moles =  6 * 10^-6 moles +  1.4 * 10^-4 moles

Mole fraction of SSA = number of moles of SSA/ total number of moles.

Mole fraction of SSA =  1.4 * 10^-4 moles/  6 * 10^-6 moles +  1.4 * 10^-4 moles

Mole fraction of SSA = 0.96

Answer:

41.03 %

Explanation:

Given that,

The actual length of a strip of aluminum is 2.12 m

Observed length of a strip of aluminum is 1.25 m

We need to find the student's percent error. The percentage error on any value is given by :

\(\%=\dfrac{\text{observed-actual}}{\text{actual}}\times 100\)

Putting all values, we get :

\(\%=\dfrac{2.12-1.25}{2.12}\times 100\\\\\%=41.03\ \%\)

So, the percent error of the student is 41.03 %.

Answer:  Assuming the question wants to know the mass of the same volumes of ice and water:  57.5 g for ice and 62.7 g for water/

Explanation:  The density of ice and water are 0.917 g/cm^3 and 1.99 g/cm^3, respectively.  1cm^3 = 1ml

(62.7 ml)*(0.917 g/cm^3) = 57.5 g for ice

(62.7 ml)*(1.99 g/cm^3) = 62.7 g for water

Answer:

when lit, the atoms of different chemical compounds inside the firework absorb energy, when the electrons fall back to lower energy levels, they give off colored light. Depending upon the chemical used, different colors are produced. neon lights or signs are glass tubes filled with neon gas. When the light is plugged in, the electrical energy causes the electrons of neon to jump to higher energy levels, when they go to lower levels, colored light is given off. The neat thing is that the neon never gets used up. The only thing that gets used up is the electricity. The electrons don't get destroyed and can be used over and over again jumping levels. Neon glows with an orange light, but you know that neon signs can be lots of different colors. The variations come when different gases other than neon are used such as argon, or krypton or when the tube is painted so that with the light produced it produces a certain color.

Explanation:

After being excited by high levels of electrical energy (as in neon signs) or heat energy, various elements and molecules will emit their own specific colors of light.

Metals burn in a variety of colors. When a copper compound is lit, for example, the flame is blue-green.

Calcium burns red, while potassium burns purple. Metals are combined to produce various colors in fireworks.

The appearance of each firework is determined by the type of stars it contains, as well as the size and quantity of these pellets.

Some stars contain metal salts, which produce brilliant colors, while others contain a variety of chemical compounds that produce dazzling light effects such as strobing, sparkling, and others.

Various elements and molecules will emit their own specific colors of light after being excited by high levels of electrical energy (as in neon signs) or heat energy (as in the fireworks).

Thus, the neon signs or fireworks provide different colors.

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According to the question, the pH of the solution after the addition of 50.0 mL of HNO₃ is 4.74.

pH is a measure of the acidity or alkalinity of a solution. It is measured on a logarithmic scale from 0 to 14, with 7 as the neutral point. Solutions with a pH lower than 7 are considered acidic, whereas solutions with a pH higher than 7 are considered basic or alkaline. Lower pH values indicate a higher concentration of hydrogen ions, while higher pH values indicate a higher concentration of hydroxide ions.

The pH of the solution after the addition of 50.0 mL of HNO₃ can be calculated using the Henderson-Hasselbalch equation.

pH = pKa + log (base/acid)

Where pKa is the -log of the acid dissociation constant (Kb) of NH₃ (1.8 x 10-5), base is the concentration of NH₃ in the solution (0.10 M), and acid is the concentration of HNO₃ in the solution (0.10 M).

pH = -log(1.8 x 10-5) + log(0.10/0.10)

pH = -log(1.8 x 10-5)

pH = 4.74

Therefore, the pH of the solution after the addition of 50.0 mL of HNO₃ is 4.74.

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