Answer:
1) θ = 130°
2) θ = 310°
Step-by-step explanation:
We want to find a value of θ such that:
sin(θ) = sin(50°)
We know that sin(90°) = 1
We will have a symmetry around 90°.
Then if we define a constant k
sin(90° + k) = sin(90° - k)
we can define k such that:
90° - k = 50°
90° - 50° = k
40° = k
Then:
sin(90° + 40°) = sin(90° - 40°)
sin(130°) = sin(50°)
then θ = 130°
Now we want to find:
cos(θ) = cos(50°)
We know that cos(0°) = 1
Then we have symmetry around 0°
With the same reasoning than before, we can write:
cos( 0° + k) = cos(0° - k)
We can define:
0° + k = 50°
k = 50°
Then:
cos(50°) = cos(-50°)
But we want 0° < θ < 360°
Knowing that the peridisity of the trigonometric functions is of 360° then:
cos(50°) = cos(-50°) = cos( - 50° + 360°)
cos(50°) = cos(310°)
in this case θ = 310°
write an equivalent expression.
if N is 1/8 as much as 16, what does N equal?
Background:
"As much as" means that two quantities are being compared and is a keyword for division.
Procedure:
\(N=\frac{16}{8}=2\)Answer: 2
The low temperature on Monday was 16°F. On Tuesday, the low was 18°F cooler. On Wednesday, the low temperature was –4 times Tuesday’s low.
Which of the following expressions can be used to describe the low temperature on Wednesday? Select all that apply.
16 + (–18)(–4)
16(4) + (–8)
(16 – 18)(–4)
[16 + (–18)](–4)
Answer:
\(-4(16-18)\), \([16 + (-18)](-4)\)
Step-by-step explanation:
Given: The low temperature on Monday was 16°F. The low temperature on Tuesday was 18°F cooler. The low temperature on Wednesday was –4 times Tuesday’s temperature.
To find: expression that can be used to describe the low temperature on Wednesday
Solution:
Temperature on Monday = 16°F
So,
Temperature on Tuesday = \((16-18)\°F\)
Temperature on Wednesday = \(-4(16-18)\°F\)
So, expression \(-4(16-18)=(16-18)(-4)\) can be used to describe the low temperature on Wednesday.
Also,
\((16-18)(-4)=[16 + (-18)](-4)\,\,\left \{\because (a-b)=\left [ a+(-b) \right ] \right \}\)
So, expression \([16 + (-18)](-4)\) also represent temperature on Wednesday.
Answer:
(16 – 18)(–4)
[16 + (–18)](–4)
Step-by-step explanation: Answers for Edge
If you had $120 and earned $20 each week, how long would take to get $340? and an equation
A square garden has sides of length 10 ft. If topsoil costs $5 / cubic foot, how much will it cost to put a 0. 5 ft layer of topsoil on the entire garden?
Cost to put a 0. 5 ft layer of topsoil on the entire garden is $1000.
The quantity of square units required to completely fill a square is known as the area of a square. The region that lies inside the confines of a flat item or a two-dimensional figure is generally referred to as the area. Measurements are made in square units, with square meters serving as the reference unit
Area of a Square = Side × Side.
Therefore, the area of square = Side square units.
Side of a square garden= 10 ft.
Area of a square garden= Side × Side= 10 × 10 =100 square ft.
Cost of the whole garden = 100×$5 =$500
Cost to put a 0. 5 ft layer of topsoil on the entire garden =$500/0.5
=$1000
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The cost need to put a 0. 5 ft layer of topsoil on the entire garden is $1000
According to the given statement
we have given that the
side length of the square garden is 10ft.
topsoil cost per foot is $5
And we have to find the cost which required to put a 0. 5 ft layer of topsoil on the entire garden.
So,
The side length of the square garden is 10ft.
Now, the volume of the cube is (a)^2
And
Total volume of cube = 10*10
Total volume of cube = 100 per square foot.
Now, we find the cost required for a topsoil.
Cost required to put a topsoil of 1 foot in the total volume of cube = volume*cost
So,
Cost required to put a topsoil of 1 foot in the total volume of cube = 1000*5
Cost required to put a topsoil of 1 foot in the total volume of cube = $5000
if we put a topsoil of 0.5 feet then
The cost required = $5000/0.5
The cost required = $1000.
So, The cost need to put a 0. 5 ft layer of topsoil on the entire garden is $1000
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Carson invested $850 in an account paying an interest rate of 5.7% compounded
daily. Assuming no deposits or withdrawals are made, how much money, to the
nearest dollar, would be in the account after 6 years?
Answer:
A = $ 1,195.63
A = P + I where
P (principal) = $ 850.00
I (interest) = $ 345.63
Step-by-step explanation:
First, convert R percent to r a decimal
r = R/100
r = 5.7%/100
r = 0.057 per year,
Then, solve our equation for A
A = P(1 + r/n)nt
A = 850.00(1 + 0.00475/12)(12)(6)
A = $ 1,195.63
Summary:
The total amount accrued, principal plus interest,
from compound interest on an original principal of
$ 850.00 at a rate of 5.7% per year
compounded 12 times per year
over 6 years is $ 1,195.63.
A. 24
B. 48
C. 32
D. 12
Answer:
A, 24
Step-by-step explanation:
Answer:
A. 24
Step-by-step explanation:
This is because on the cube numbered 1-6, there are only three numbers greater than 3. On the wheel, there are four outcomes and on the coin, there are two outcomes. Now, I simply multiply the possible outcomes.
\(3*4*2=24.\)
I, therefore, believe the answer to this word problem is 24.
I NEED HELP WITH 2 QUESTIONS WILL MARK THE MOST BRAINLIEST IF CORRECT!
Answer:
-1, 6
0, -3
1, -3.9
2, -3.99
f(x) = 5^2x+1
Step-by-step explanation:
for the first question, after plugging in the values of x, we get our answer to be the 2nd table
-1, 6
0, -3
1, -3.9
2, -3.99
for the second question
f(x) = 5^2x+1
after graphing, we can see it never passes x = 2
Select ALL the correct answers. Identify each true statement. Remember the answer should always be positive. Question 2 options: 9 = |9| 4.1 = |-4.1| -3 = |3| |-2.6| = -2.6 |7| = -7 |-8.5| = 8.5
Answer:
The answer is:
Step-by-step explanation:
9, 4.1, 2.6, 7, 8.5
In a class of 25 students, some students play a sport, some play a musical
instrument, some do both, some do neither. Complete the two-way table to show
data that might come from this class.
Answer:
Step-by-step explanation:
#2 Q is between P and R. Find PR.
6x + 4
3x
3x tc
P
R
Q
14x - 6 6-
Answer:
PR=22
Step-by-step explanation:
3x+6x+4=14x-6
9x+4=14x-6
10=5x
x=2
Plug in
3(2)
6
6(2)+4
12+4
16
16+6
22
So the bottom should equal 22
14(2)-6
28-6
22
Hope this helps
Brainliest would be appreciated
6. A pizza's original price is $11. It is on sale for $9.25. What percent off is it?
Solution:
We know that:
\(Original \ price = \$11\)
\(Sale \ price = \$9.25\)
\(\frac{9.25}{11} + \frac{1.75}{11} =100\%\)
Simplify the equation to find the percent off:
\(\frac{9.25}{11} + \frac{1.75}{11} =100\%\)
\(84\% + \bold{16\%} = 100\% \space\ \space\ \space\ \ \ \ \ [Rounded]\)
This means that the original price has decreased about 16%.
pls help :(
y= _x +_
Find the equation of the line
hi, I'm no bot just in case...
the grapgh of the line shows y intercept of -9 and rate of change by 4
SoThe equation of the lline will be: \(y=4x-9\)
(-11, 12),(-4,-9) slope
Answer:
slope = -3
Step-by-step explanation:
Hope this helps! Have a great day!
What are the solutions to the system of equations?
y=x^2 – 5x + 6
y = -4x + 6
A. (0, 6) and (1, 2)
B. (-1,0) and (6, 0)
C. (0, -1) and (6, 0)
D. (-1,0) and (0, 6)
The answer is definitely C
applicants for graduate school take a test that has scores which are normally distributed with a mean of 560 and a standard deviation of 90. what is the probability that a randomly chosen applicant will score between 550 and 650?
There is a 38.51% probability that a randomly chosen applicant will score between 550 and 650 which is derived through standard normal distribution method.
It is given to us that the scores of the applicants for graduate school are normally distributed with -
Mean(μ) = 560
and, Standard deviation (σ) = 90
We have to find out the probability of a randomly chosen applicant will score between 550 and 650.
We have to use the standard normal distribution method in order to find out the required probability.
According to standard normal distribution curve method,
Z = (X-μ)/σ
=> Z = (550-560)/90 and, Z = (650-560)/90
=> Z = -0.11 and Z = 1.00
The probability will be with respect to the corresponding z-tables which is equal to = (0.3413+0.0438)
= 0.3851
Thus, the probability of a randomly chosen applicant will score between 550 and 650 is 0.3851 or 38.51%.
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How could you use a set of coin flips to simulate this situation?
Answer:
Let heads represent a person who exercises the given amount, and let tails represent a person who doesn’t. Because there are three people, flip the coin three times (once for each person) and note the results of each set of three flips. If all three flips land on tails, it would mean that all three randomly selected people do not exercise as much as 50% of Americans do.
Step-by-step explanation:
Write the quadratic equation in general form. (x-5)2
Answer:
x^2 - 10x + 25
Step-by-step explanation:
I'm hoping that the 2 means squared.
x^2 - 10x + 25
Answer:
x^2 -10x+25
Step-by-step explanation:
(x-5)^2
(x-5)(x-5)
FOIL
first = x*x = x^2
outer:-5x
inner: -5x
last: -5*-5 = 25
Add them together
x^2 -5x-5x+25
Combine like terms
x^2 -10x+25
Standard form is ax^2 +bx +c so this is standard form
Which table represents exponential growth?
:))))
Answer: x: 1,2,3,4 y: 2,4,8,16
Step-by-step explanation:
Exponential growth means that the rate of the line of a graph or chart is rapidly growing in size or number.
1 | 2
2 | 4
3 | 8
4 | 16
5 | 32
6 | 64
etc.
Answer:
option B edg 2021
Step-by-step explanation:
im too lazy to explain but its option B
Select all ratios equivalent to 5:3.
1
35:21
7:5
15:4
Complete the following tables by filling in the missing values and determine the rule for each table:
An object is moving along the x x -axis. At t t = 0 it is at x x = 0. Its x x -component of velocity vx v x as a function of time is given by vx(t)=αt−βt3 v x ( t ) = α t − β t 3 , where α= α = 7.2 m/s2 m / s 2 and β= β = 4.8 m/s4 m / s 4 .
(a) At what nonzero time t t is the object again at x x = 0? Express your answer with the appropriate units.
An object is moving along the x x -axis. At t t = 0 it is at x x = 0. Its x x -component of velocity vx v x as a function of time is given by vx(t)=αt−βt3 v x ( t ) = α t − β t 3 , where α= α = 7.2 m/s2 m / s 2 and β= β = 4.8 m/s4 m / s 4 the nonzero time at which x = 0 is 1.22 seconds.
To find the time at which the object is again at x=0, we need to solve the equation vx(t) = 0, which gives us:
αt - βt^3 = 0
t(α - βt^2) = 0
The solutions to this equation are t = 0 (which corresponds to the initial position) and t = ±√(α/β). Since we're looking for a nonzero time, we can discard the t = 0 solution and take t = √(α/β):
t = √(α/β) = √(7.2 m/s^2 / 4.8 m/s^4) = √(1.5 s^2) = 1.22 s
Therefore, the object is again at x=0 after a time of 1.22 seconds.
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How much inches go into 5ft?
The graph of y=√x is shifted 2 units down and 3 units left. Which equation represents the new graph?
A. y=√x-2-3
B. y=√x+2-3
C. y=√x+2+3
D. y=√x+3+2
the equation that represents the new graph is:
g(x) = √(x - 3) - 2
Which equation represents the new graph?
Here we start with the function:
y = f(x) = √x
First, we shift it 2 units down, then the new equation will be:
g(x) = f(x) - 2
Now we apply a horizontal shift, this time we shift the graph 3 units to the left, then the new equation is:
g(x) = f(x - 3) - 2
Now we replace f(x) = √x to get:
g(x) = √(x - 3) - 2
That is the equation that represents the new graph.
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determine the sequence
Answer:
Add 3 each time. (for question #8)
Step-by-step explanation:
9+3=12
12+3=15
15+3=18
18+3=21
21+3=24
24+3=27
.
.
.
The formula for evaluating the area of a sector with the given measure of the arc in degrees and radius is,
Choose the correct option:
A
m180∘×πr2\frac{m}{180^{\circ}}\times \mathrm{\pi r}^{2}
180
∘
m
×πr
2
B
m360∘×2πr\frac{m}{360^{\circ}}\times 2\mathrm{\pi r}
360
∘
m
×2πr
C
m360∘×πr2\frac{m}{360^{\circ}}\times \mathrm{\pi r}^{2}
360
∘
m
×πr
2
D
m360∘×πd\frac{m}{360^{\circ}}\times \mathrm{\pi d}
360
∘
m
×πd
Answer:
It's B,
Step-by-step explanation:
It looks so messy
How many solutions does the equation a+b+c+d+e+f=2006. They are positive integers. Your FINAL answer should be in the form x!/x!•x!, where x is a placeholder
The number of solutions of a+b+c+d+e+f = 2006 is 9.12 * 10^16
How to determine the number of solutions?The equation is given as:
a+b+c+d+e+f = 2006
In the above equation, we have:
Result = 2006
Variables = 6
This means that
n = 2006
r = 6
The number of solutions is then calculated as:
(n + r - 1)Cr
This gives
(2006 + 6 - 1)C6
Evaluate the sum and difference
2011C6
Apply the combination formula:
2011C6 = 2011!/((2011-6)! * 6!)
Evaluate the difference
2011C6 = 2011!/(2005! * 6!)
Expand the expression
2011C6 = 2011 * 2010 * 2009 * 2008 * 2007 * 2006 * 2005!/(2005! * 6!)
Cancel out the common factors
2011C6 = 2011 * 2010 * 2009 * 2008 * 2007 * 2006/6!
Expand the denominator
2011C6 = 2011 * 2010 * 2009 * 2008 * 2007 * 2006/720
Evaluate the quotient
2011C6 = 9.12 * 10^16
Hence, the number of solutions of a+b+c+d+e+f = 2006 is 9.12 * 10^16
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Answer:
210 = 6!/1!•1!•1!•1!•1!•1!
Step-by-step explanation:
We can use the stars and bars method to solve this problem. Imagine we have 2006 stars and we want to distribute them among 6 bins (a, b, c, d, e, and f). We can represent the stars as follows:
... * (a stars)
| * * * ... * (b stars)
| | * * * ... * (c stars)
| | | * * * ... * (d stars)
| | | | * * * ... * (e stars)
| | | | | * * * ... * (f stars)
The bars divide the stars into 6 bins, and the number of stars in each bin represents the value of the corresponding variable (a, b, c, d, e, or f).
To ensure that each variable is a positive integer, we can add 1 to each variable and distribute the remaining stars. For example, if we add 1 to a, b, c, d, e, and f, the equation becomes:
(a+1) + (b+1) + (c+1) + (d+1) + (e+1) + (f+1) = 2012
Now we have 6 stars and 5 bars, and we can use the stars and bars formula to find the number of solutions:
Number of solutions = (6+5-1) choose (5-1) = 10 choose 4 = 210
Therefore, the equation a+b+c+d+e+f=2006 has 210 positive integer solutions.
Expressing the answer in the form x!/x!•x!, we have:
210 = 6!/1!•1!•1!•1!•1!•1!
The stars and bars formula:The stars and bars formula is a combinatorial formula that allows us to count the number of ways to distribute identical objects into distinct groups.
Suppose we have n identical objects and k distinct groups. We can represent the objects as stars and the groups as bars. For example, if we have 7 objects and 3 groups, we can represent them as:
| | |
The bars divide the 7 stars into 3 groups, and the number of stars in each group represents the number of objects in that group.
The stars and bars formula tells us that the number of ways to distribute n identical objects into k distinct groups is:
(n+k-1) choose (k-1)
where "choose" is the binomial coefficient. This formula can be derived using a technique called "balls in urns" or by using generating functions.
In the example above, we have n = 7 objects and k = 3 groups, so the number of ways to distribute the objects is:
(7+3-1) choose (3-1) = 9 choose 2 = 36/2 = 18
Therefore, there are 18 ways to distribute 7 identical objects into 3 distinct groups.
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There is a cell phone manufacturer whose cost to manufacture x number of phones is 2000x + 750000, and the revenue generated from manufacturing x number of cell phones is -0.09x squared + 700x
The profit function made by the cell phone manufacturer is given by -0.09x² -1300x - 750000
What is an equation?An equation is an expression that shows the relationship between two or more numbers and variables.
An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.
The profit function is given as:
Profit = Revenue - Cost
Cost = 2000x + 750000, Revenue = -0.09x² + 700x, hence:
Profit = -0.09x² + 700x - (2000x + 750000) = -0.09x² -1300x - 750000
The profit function made by the cell phone manufacturer is given by -0.09x² -1300x - 750000
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clint's cowboy shop buys horse feed for $\$10$ per cubic meter ($\text{m}^3$). clint's customers don't like the metric system, so they'll only buy horse feed by the cubic foot. how many cents should clint charge for a cubic foot ($\text{ft}^3$), if he wants to sell the horse feed for twice the price he bought it at?
In linear equation, 57 cents per cubic foot should clint charge for a cubic foot .
What are a definition and an example of a linear equation?
An equation with only one variable is referred to as a linear equation in one variable. It has the mathematical formula Ax + B = 0, where A and B can be any two real numbers, and x is an unknowable variable with just one possible value. A linear equation in one variable would be 9x + 78 = 18.cubic meter = [3.28 ft ]^3 ≈ 35.29 cubic feet
So,
price [ in cents] / 35.29 cubic feet = 2000 / 35.29 ≈ 57 cents per cubic foot
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Loretta is rolling an unfair 6 sided die with a single number between 1 and 6 on each face. She has a 70% chance of rolling a four. She is playing a game with a friend and knows that if she rolls a four on three of her next five rolls she will lose the game. She wants to determine the probability that she rolls a four on three of her next five rolls.
Which simulation design has an appropriate device and a correct trial?
Complete question is;
Loretta is rolling an unfair 6 sided die with a single number between 1 and 6 on each face. She has a 70% chance of rolling a four. She is playing a game with a friend and knows that if she rolls a four on three of her next five rolls she will lose the game. She wants to determine the probability that she rolls a four on three of her next five rolls.
Which simulation design has an appropriate device and a correct trial?
A) Using a fair coin let heads represent rolling a four and tails represent not rolling a four. Flip the coin five times.
B) Using a table of random digits select a digit between 0 and 9. Let 0-6 represent rolling a four and 7-9 represent not rolling a four. Select five digits.
C) Roll a fair die with a single digit between 1 and 6 on each face. Let four represent rolling a four and 1-3 and 5 and 6 represent not rolling a four. Roll the die five times.
D) Using a table of random digits select a digit between 1 and 6, ignoring digits 0, 7, 8, and 9. Let 4 represent rolling a four and 1-3 and 5 and 6 represent not rolling a four Select five digits.
Answer:
B) Using a table of random digits, select a digit between 0 and 9. Let 0-6 represent rolling a four and 7-9 represent not rolling a four. Select five digits.
Step-by-step explanation:
Since she knows that if she rolls a four on three of her next five rolls she will lose the game, then the best simulation that she will roll a four on three of the next five rolls will be option B because it uses a table of random digits and doesn't ignore any number but is well ordered with 0-6 representing a four and 7-9 not rolling a four.