Helium-neon laser light of wavelength 776.4 nm is sent through a 0.454 mm wide single slit. What is the width of the central maximum on a screen 0.86 m from the slit

Superior forward visibility compared to radial or V-type engines is a benefit of horizontally opposed engines. For a variety of reasons, including fewer cylinders for equivalent power and smooth operation, opposed engines have today supplanted all previous forms of piston engines.

The American F4U-4 Corsair carrier-based fighter-bomber, created and manufactured by Chance Vought, was the most effective fighter of World War II. More than 12,500 aircraft were produced between 1942 and 1953. The fighter had an extremely lethal arsenal and outstanding mobility.

The requirement to gear the power from the two opposing pistons together was the biggest disadvantage. Compared to traditional piston engines, these extra weight and complexity

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Answer:

because the friction in the baloons and the magnetism make it like nuclear fision

Explanation:

The magnetic field and friction between the balloons when placing two very strong magnets in the middle of two separate balloons provide a good model for nuclear fusion.

Nuclear fusion is the process through which light elements interact to create heavier elements (up to iron). Significant amounts of energy are released when interacting nuclei are from elements with low atomic numbers, such as hydrogen (atomic number 1) or its isotopes deuterium and tritium.

Thermonuclear weapons, or hydrogen bombs, which were created in the decade immediately following World War II, were the first to utilize the tremendous energy potential of nuclear fusion.

There are two main categories of fusion reactions: those that maintain the ratio of protons to neutrons and those that convert protons to neutrons.

Therefore, the magnetic field and friction in the balloons when placing two very strong magnets in the middle of two separate balloons provide a good model for nuclear fusion.

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The force required in Jupiter is 80 N.

The strength of the gravitational field on Jupiter is determined by its mass and size, as well as the distance from its surface to the center of the planet. Because Jupiter is much larger and more massive than Earth, its gravitational field is much stronger, which results in a higher acceleration due to gravity.

In this case we need to know the value of the acceleration due to gravity on the Jupiter planet which is 8 m / s 2.

Thus we would need;

mg = 10 Kg * 8 m / s 2. = 80 N

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If an object is moving in a straight line, the change in velocity equals the final speed minus the initial speed.

The change in velocity of an object moving in a straight line is a measure of how much its speed has changed over time. The change in velocity is equal to the final speed minus the initial speed, and it is a vector quantity, meaning it has both magnitude and direction.

For example, if an object is moving at a speed of 10 m/s at time t1 and has a speed of 20 m/s at time t2, then its change in velocity would be;

20 m/s - 10 m/s = 10 m/s.

The direction of the change in velocity would depend on the direction of the speed change, which could be either positive (increasing speed) or negative (decreasing speed).

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Answer:

\( \green{ \sf \: \: 1.6 \: m {s}^{ - 2} \: \: \: is \: the \: correct \: answer}\)

Explanation:

\( \sf \: \huge{g } _{ \small{moon}} = \frac{ {\huge{g}}_{earth}}{6} \\ \\ \sf \implies \: \sf \: \huge{g } _{ \small{moon}} = \frac{ 9.8}{6} = 1.6 \: \: m {s}^{ - 2} \)

Explanation:

Given mass of the object is 1200kg and it's placed at a height of 45m above the ground. As we know that potential energy is ,

\(\longrightarrow PE = mgh \)

where,

Substituting the respective values ,

\(\longrightarrow P.E. = 1200kg * 10m/s^2* 45m\)

Multiply ,

\(\longrightarrow P.E. = 540000J \)

Hence the potential energy is 540000J .

I hope this helps.

Answer:

132

Explanation:

Answer:

I think its C

Explanation:

Answer:

1)  F = M a      accelerating forward would cause a seeming increase weight.

2) F = m v^2 / R    a person moving in a circular arc would have an apparent component of  weight towards the center of rotation (in addition to his normal vertical component of weight).

The required original velocity of the bowling ball is calculated to be 6 m/s.

The total momentum prior to and following a collision are identical in a closed system.

From the principle of conservation of momentum,

M × U + m × u = M × V + m × v ----(1)

Where,

M = Mass of the bowling ball (M = 8 kg)

m = Mass of the pin (m = 2 kg)

U = Initially, the bowling ball's speed

u = Initial velocity of the pin (u = 0 m/s)

V = Final velocity of the bowling ball (V = 2 m/s)

v = Final velocity of the pin (v = 8 m/s)

Substitute these values in (1) and to solve U:

8(U)+2(0) = 8(4)+2(8)

8U = 32 + 16

8U = 48

U = 6 m/s

Thus, the initial velocity of the bowling ball is calculated to be 6 m/s.

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Answer:theory

Explanation:

It should be noted that after the big bang occurred, the universe "Became Denser" (Option B)

According to the Big Bang Theory, after the explosion which triggered the transformation of radiation into matter, gravity pulled dark matter together which in turn attracted normal matter.

Hence, it is right given the above analogy that the Universe became denser.

It should be mentioned that the big-bang hypothesis is a widely accepted account of the universe's evolution. Its defining characteristic is the universe's birth from a condition of great heat and density—the so-called big bang, which occurred 13.8 billion years ago.

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At a point p on the ring's axis, the electric potential due to the ring is

V = \(\frac{kQ}{\sqrt{z^{2} +}R^{2} }\)

The amount of work required to move a unit of electric charge from a reference point to a specific place in an electric field is known as the electric potential.

dV =kdq/r

From the figure given below:

r = \(\sqrt{z^{2}+R^{2} }\)

By integrating the equation we got,

V = kQ/r

As E = -dV/dz,

Therefore, At a point p on the ring's axis, the electric potential due to the ring is:

V = \(\frac{kQ}{\sqrt{z^{2} +}R^{2} }\)

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The fast with which lava hot springs travelling in 15.01 m/s when it hit the surface of water.

When an object moves, it is said to be in motion under gravity since gravity has an impact on the object's vertical motion. Gravity is the force that pulls objects down. Known as acceleration owing to gravity, the earth's gravity pulls the object toward itself with an acceleration.

Height of platform =11.5 m = h

V^2 = U^2 -2gh

initial vlocity U = 0

V^2= - 2 x-9.8m/s x 11.5

    = > V= 15.01m/s

A body is said to be in freefall when it is only being moved by the gravity of the earth. The ball is encountering external push, thereby the motion will intensify. The term "gravitational acceleration" is also used to describe this rate of free fall.

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The  resistance increased in the circuit during experiment #3, the voltage decreased while the current decreased.

This is in accordance with Ohm's Law, which states that the voltage (V) across a conductor is directly proportional to the current (I) passing through it, but inversely proportional to the resistance (R) of the conductor. So, as the resistance increases, the voltage decreases in order to maintain a constant current flow. Similarly, as the resistance increases, the current also decreases, as there is less flow of electrons through the circuit.

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Answer:

The horizontal component of the force, \(F_x= 34.24 \ N\)

The  vertical component of the force, \(F_y=7.28 \ N\)

Explanation:

Given;

Force on the rope, F = 35 N

angle between the rope and the horizontal = 12 °

The horizontal component of the force is given by;

\(F_x = Fcos \theta\\\\F_x = 35cos(12^0)\\\\F_x = 34.24 \ N\)

The vertical component of the force is given by;

\(F_y = Fsin\theta\\\\F_y = 35sin(12^0)\\\\F_y = 7.28 \ N\)

a) To calculate the mass flow rate at point 3, we can use the continuity equation, which states that the mass flow rate through any pipe or channel must be constant, given that the fluid is incompressible. The equation is: m_dot = rho * A * v

Where m_dot is the mass flow rate, rho is the density of the fluid, A is the cross-sectional area of the pipe, and v is the velocity of the fluid. Since the water is coming out of the pipe at point 3, we can assume atmospheric pressure and neglect any changes in potential energy. Therefore, we can use the pressure at point 1 and the height difference between points 1 and 3 to calculate the velocity of the water at point 3 using Bernoulli's equation.

Using the given radius of the tank, we can calculate its cross-sectional area as A1 = pi*r^2 = 201.1 m^2. The height difference between point 1 and point 3 is 15 m - 3 m = 12 m. Using Bernoulli's equation, we can calculate the velocity of the water at point 3:

P1/rho + gh1 + 0.5*v1^2 = P3/rho + gh3 + 0.5*v3^2

Since P3 is atmospheric pressure, we can neglect it. Rearranging and solving for v3, we get:

v3 = sqrt(2*(P1-Patm)/rho + 2*g*(h1-h3))

where Patm is atmospheric pressure, g is the acceleration due to gravity, h1 is the height of point 1, and h3 is the height of point 3. Substituting the given values, we get:

v3 = sqrt(2*(2.8 x 10^5 Pa - 1.01 x 10^5 Pa)/(1000 kg/m^3) + 2*9.81 m/s^2*(15 m - 3 m)) = 17.81 m/s

Using the cross-sectional area of the pipe at point 3 (A3 = pi*r^2 = 0.046 m^2) and the density of water, we can calculate the mass flow rate:

m_dot = rho * A3 * v3 = 1000 kg/m^3 * 0.046 m^2 * 17.81 m/s = 8.19 kg/s

Therefore, the mass flow rate at point 3 is 8.19 kg/s.

b) To calculate the velocity of the water at point 2, we can use Bernoulli's equation again, assuming that the pressure at point 2 is atmospheric pressure and neglecting any changes in potential energy:

P1/rho + gh1 + 0.5*v1^2 = P atm/rho + gh2 + 0.5*v2^2

Rearranging and solving for v2, we get:

v2 = sqrt(2*(P1-Patm)/rho + 2*g*(h1-h2))

Substituting the given values, we get:

v2 = sqrt(2*(2.8 x 10^5 Pa - 1.01 x 10^5 Pa)/(1000 kg/m^3) + 2*9.81 m/s^2*(15 m - 1.8 m)) = 25.35 m/s

Therefore, the velocity of the water at point 2 is 25.35 m/s.

c) The rate that the water level in the tank is falling can be calculated using the equation of continuity and the principle of conservation of mass.

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The speed of the motorcycle is  9.02777m/s in 7.2 sec.

The rate at which an object's velocity with respect to time changes is referred to as acceleration in mechanics. They are vector quantities, accelerations. The direction of the net force acting on an object determines the direction of its acceleration.

v(0) = 5.8

s(0)=0

s(7.2) = 65

s(t) =at^2/2 + v(0)t

s(7.2) = a(7.2)^2 + 5.8(7.2) = 65

a = (65-41.76)/51.84

a= 23.24/51.84 = about 0.4483 m/s²

v(t) = s'(t) = at +v(0) = at +5.8

v(7.2) = 0.4483(7.2) + 5.8

= 9.02777

velocity in 7.2 seconds is about 9.03 meters per second

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Answer:

They form ions, or charged particles

Explanation:

Some atoms become more stable by gaining or losing an entire electron (or several electrons). When they do so, atoms form ions, or charged particles. Electron gain or loss can give an atom a filled outermost electron shell and make it energetically more stable.

hope it helped please tell me if im wrong.

The minimum and maximum braking distances needed to ensure that all vehicles traveling at the posted speed limit can stop before reaching the intersection are as follows:

- For small cars: Minimum ≈ 1773.028 m, Maximum ≈ 1568.850 m

- For large trucks: Minimum ≈ 3285.760 m, Maximum ≈ 2409.595 m

To calculate the minimum and maximum braking distances, we can use the equations of motion for a decelerating vehicle.

The equation for the braking distance of a vehicle is given by:

d = (v^2) / (2 * μ * g)

where d is the braking distance, v is the initial velocity of the vehicle, μ is the coefficient of friction between the tires and the road, and g is the acceleration due to gravity.

Let's calculate the minimum and maximum braking distances separately for small cars and large trucks.

For small cars with a mass of 563 kg:

- Minimum braking distance:

  v = 8989 km/h = (8989 * 1000) / 3600 m/s = 2496.944 m/s

  μ_min = 0.536

  d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.536 * 9.8) ≈ 1773.028 m

  Maximum braking distance:

  μ_max = 0.599

  \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.599 * 9.8) ≈ 1568.850 m\)

For large trucks with a mass of 3951395 kg:

- Minimum braking distance:

  v = 8989 km/h = 2496.944 m/s (same as for small cars)

  μ_min = 0.350

 \(d_min = (v^2) / (2 * μ_min * g) = (2496.944^2) / (2 * 0.350 * 9.8) ≈ 3285.760 m\)

  Maximum braking distance:

  μ_max = 0.480

 \(d_max = (v^2) / (2 * μ_max * g) = (2496.944^2) / (2 * 0.480 * 9.8) ≈ 2409.595 m\)

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Answer:

CL2+H2O----------->2HCL+[0]

Among H2S, KCl, and CO2, all three substances can dissolve in water to some extent, but they differ in their solubility levels. H2S (hydrogen sulfide) is a polar molecule that can dissolve in water, forming a weak acidic solution.

This is due to the partial negative charge on the sulfur atom and partial positive charges on the hydrogen atoms, which allow the formation of hydrogen bonds with water molecules. KCl (potassium chloride) is an ionic compound that dissolves readily in water. The positive potassium ions (K+) and negative chloride ions (Cl-) are attracted to the partial negative and positive charges of the water molecules, respectively. This strong interaction leads to the dissociation of KCl into its individual ions, resulting in a clear, aqueous solution.

CO2 (carbon dioxide) is a nonpolar molecule with limited solubility in water. When dissolved, it reacts with water to form a weak acid called carbonic acid (H2CO3). This reaction is reversible, meaning some CO2 molecules will remain dissolved without forming carbonic acid. In summary, all three substances, H2S, KCl, and CO2, can dissolve in water. However, KCl is the most soluble due to its ionic nature, while H2S and CO2 exhibit lower solubility as they form weak acids in aqueous solutions.

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The acceleration of an object with a mass of (m2-m1) is given by the force of F divided by the mass of the object, (m2-m1). This can be expressed as a = F/(m2-m1).


To solve this, first calculate the force F.

The force F acting on mass m1 is F1 = m1*a1 and the force F acting on mass m2 is F2 = m2*a2.

Since both masses are being acted upon by the same force, the equation F1 = F2 can be used.

Therefore, F = m1*a1 = m2*a2.

Now, substitute the known values for m1, m2 and a1, a2 into the equation to get F = m1*a1 = m2*a2.

F = m1*14.0 \(m/s^2\) = m2*3.8 \(m/s^2\).

Therefore, the acceleration of the object with a mass of (m2-m1) is given by a = F/(m2-m1). Substituting the value of F into the equation gives:

a = F/(m2-m1) = (m1*14.0 m/s2)/(m2-m1).

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The maximum instantaneous power dissipated by the 3.6-hp pump connected to a 240-vrms AC power source is 2704.8 watts.

To find the maximum instantaneous power dissipated by a 3.6-hp pump connected to a 240-vrms AC power source, we can use the formula:

P = Vrms^2 / R

where P is power, Vrms is the root-mean-square voltage, and R is the resistance.

First, we need to convert 3.6 hp to watts:

1 hp = 746 watts
3.6 hp = 3.6 x 746 = 2685.6 watts

Next, we can calculate the resistance of the pump using the formula:

P = Vrms^2 / R
R = Vrms^2 / P

Since the power source is AC, the resistance will be impedance, which is given by:

Z = Vrms / I

where Z is impedance and I is current.

Assuming the pump has a power factor of 1 (which means the voltage and current are in phase), we can use the formula:

Z = Vrms / I = R

to calculate the resistance.

So, the maximum instantaneous power dissipated by the pump can be calculated as follows:

R = Vrms^2 / P = (240)^2 / 2685.6 = 21.3 ohms
Z = R = 21.3 ohms
I = Vrms / Z = 240 / 21.3 = 11.27 A (amperes)

P = Vrms x I = 240 x 11.27 = 2704.8 watts

Therefore, the maximum instantaneous power dissipated by the 3.6-hp pump connected to a 240-vrms AC power source is 2704.8 watts.

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a) The thin-wall cylinder is subjected to internal pressure, which results in tensile stresses in the hoop and axial directions of the cylinder wall. The stresses in the hoop and axial directions, respectively, are as follows:sigmaH = pi * D / (2 * t) ; sigmaA = pi * D * t / (4 * r^2 - D^2)where pi = 100 MPa, D = 100 mm, and r = D/2 = 50 mm.

For sigma H, t is the thickness of the wall. Since the cylinder is thin-walled, we can assume that the stresses are uniformly distributed across the wall thickness, and we can apply the Tresca and von Mises criteria based on the stresses in the wall.

b) i) The minimum wall thickness based on the Tresca and von Mises failure theories is given below. Tresca theory: According to Tresca's theory, yielding occurs when the maximum shear stress in the wall exceeds the shear yield stress (dy/2).

The maximum shear stress in the wall is given by: tau = (sigmaH - sigmaA) / 2 For yielding to occur, tau >= dy/2, or sigmaH - sigmaA >= dy .

For the given internal pressure and dimensions, we have sigmaH = pi * D / (2 * t) = 50 * pi / t and sigmaA = pi * D * t / (4 * r^2 - D^2) = pi / (2 * t / D - 1) .

The minimum wall thickness that satisfies the Tresca criterion can be obtained by setting sigmaH - sigmaA = dy, and solving for t: tTresca = D * pi / (2 * (dy + pi)) = 0.610 mm. Von Mises theory:

According to von Mises's theory, yielding occurs when the equivalent von Mises stress in the wall exceeds the equivalent yield stress (dy/3).

The equivalent von Mises stress is given by: sigmaVM = sqrt(sigmaH^2 - sigmaH*sigmaA + sigmaA^2) For yielding to occur, sigmaVM >= dy/3 .

The minimum wall thickness that satisfies the von Mises criterion can be obtained by setting sigmaVM = dy/3, and solving for t: tVM = D * (9*dy^2 + 3*pi^2 - 6*dy*pi*sqrt(3))^(1/2) / (6 * (dy + pi)) = 0.684 mm

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Here, both the momentum and kinetic energy of he ball are conserved. There is no change in the magnitude of the speed thus, its kinetic energy is conserved.

The kinetic energy of an object is the energy generated by virtue  of its motion. It is related to its mass and velocity by the expression written below:

Ke = 1/2 mv²

The momentum of an object is the product of its mass and velocity. For an elastic collision both momentum and kinetic energy is conserved. But in the case of an inelastic collision, there is some energy loss and the kinetic energy is not conserved but momentum is conserved.

Here, the ball bounces by colliding with the floor, where its direction is changing but not the magnitude of speed. Hence, both the momentum and kinetic energy are conserved.

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Answer:

The cans should move towards each other. This is due to Bernoulli's principle

that the air pressure will be reduced in the area between the cans. This is similar to lift on an airplane wing due to the faster moving air over the top of

the wing or the curving of a pitched baseball due to the rotation of the ball

causing greater air pressure on one side of the ball as compared to the air pressure on the other side of the ball.

The movement of a body part around a central point or axis is known as rotation.

Rotation refers to the circular movement of a body part around its axis or a fixed point. It involves the turning or twisting motion of a body segment without changing its position in space.

Flexion (a) is the movement that decreases the angle between two body parts, typically bending or decreasing the joint angle. The extension (b) is the opposite movement, increasing the angle between two body parts, typically straightening or increasing the joint angle. Abduction (d) refers to the movement of a body part away from the midline of the body.

During rotation, the body part or segment moves around an imaginary line called the axis. This axis can be within the body itself or located externally. For example, when we rotate our head from side to side, the axis of rotation is an imaginary line passing through the neck.

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