Help me pls thanks so much

Answer:

1.25

5/4

1 1/4

Step-by-step explanation:

The dimensions of rectangle A are L=12 and W=8. The dimensions of rectangle B are L=15 and W=10.

We are told rectangle B is a copy of rectangle A, thus we must find the scale factor by dividing both dimensions:

15/12=5/4

10/8 =5/4

Dividing 5/4 we get 1.25.

Converting 5/4 to mixed fraction: 5/4= 1 1/4

There are three valid selections:

1.25

5/4

1 1/4

Answer:

2pi

Step-by-step explanation:

Answer:

Flip the triangle around at the point Z

Step-by-step explanation:

The reason you need to flip the triangle at point Z is because, when reflecting, you need to reflect it over the line given. since the reflective line is x = 1, you reflect it off the line x of 1 or point (1,0). Also, when reflecting, the line of reflection will actually be perpendicular with the point given because, when reflecting, x = 1 means that all of the x coordinates on the line will equal 1. For example, your line would have to pass through the points (1,-4), (1,-2), (1,0), (1,2), so on so forth so in this statement, all of your points will be reflected over that line and since z is on that line, the triangle is just fliped at point z.

Mike Sullivan recently retired as Professor of Mathematics at Chicago State University, having taught there for more than 30 years. He received his PhD in mathematics from Illinois Institute of Technology.

He is a native of Chicago’s South Side and currently resides in Oak Lawn, Illinois. Mike has 4 children; the 2 oldest have degrees in mathematics and assisted in proofing, checking examples and exercises, and writing solutions manuals for this project. His son Mike Sullivan, III co-authored the Sullivan Graphing with Data Analysis series as well as this series. Mike has authored or co-authored more than 10 books. He owns a travel agency and splits his time between a condo in Naples, Florida and a home in Oak Lawn, where he enjoys gardening.

Michael Sullivan, III has training in mathematics, statistics and economics, with a varied teaching background that includes 27 years of instruction in both high school and college-level mathematics. He is currently a full-time professor of mathematics at Joliet Junior College. Michael has numerous textbooks in publication, including an Introductory Statistics series and a Precalculus series which he writes with his father, Michael Sullivan.

Michael believes that his experiences writing texts for college-level math and statistics courses give him a unique perspective as to where students are headed once they leave the developmental mathematics tract. This experience is reflected in the philosophy and presentation of his developmental text series. When not in the classroom or writing, Michael enjoys spending time with his 3 children, Michael, Kevin and Marissa, and playing golf. Now that his 2 sons are getting older, he has the opportunity to do both at the same time!

Product details

Publisher ‏ : ‎ Pearson; 4th edition (8 January 2018)

Language ‏ : ‎ English

Hardcover ‏ : ‎ 1224 pages

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The expressions that equal 36 is:

E) 53 − (2. 5 × 30) − 20

Evaluated the mathematical expressions in each response to see if they equal 36.

A. (14⋅32)2−28 = (448)² - 28 = 14⁴ - 28 = 2016 - 28 = 1988, not equal to 36.

B. 23 + (58−54)2 + 122 = 23 + (4)² + 12 = 23 + 16 + 12 = 51, not equal to 36.

C. 92 − (43 + 32) + 30050 = 9² - (7 + 3) + 30050 = 81 - 10 + 30050 = 30021, not equal to 36.

D. 124 + (82 − 42) − 99 = 124 + (64 - 16) - 99 = 124 + 48 - 99 = 73, not equal to 36.

Thus, only the expressions listed in my previous answer equal 36.

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Answer: 88

Step-by-step explanation:

First use the distributive property.

4(15 + 7) can turn into 4(15) + 4(7)

Then we simplify until we get the answer.

4(15) = 60

4(7) = 28

Then it is...

60 + 28

Just add them together...

60 + 28 = 88

So the answer is 88. I hope this helps, and I hope it's not wrong, but I do not think it is.

Answer:

Step-by-step explanation:

okay so what I would do is multiply the denominator of 3 from 2/3 by 4 to get 12. So what you do to the bottom you have to do to the top so that fraction 2/3 will turn to 8/12.

Then I would multiply the denominator of 4 from 1/4 by 3 to get also get 12. And again what you do to the bottom you have to do to the top. So that fraction will be 3/12.

Ten you add them 8/12 + 3/12 = 11/12

Answer = 11/12

To determine the maximum amount Jaxson can borrow for a 20-year mortgage with a monthly payment of $1,125 and an annual interest rate of 4.8% (compounded monthly)

We can use the formula for the present value of an annuity:

P = M * (1 - (1 + r)^(-n)) / r

Where:

P = Amount borrowed (to be determined)

M = Monthly payment = $1,125

r = Monthly interest rate = Annual interest rate / 12 = 4.8% / 12 = 0.004

n = Total number of payments = 20 years * 12 months/year = 240

Substituting the given values into the formula:

P = $1,125 * (1 - (1 + 0.004)^(-240)) / 0.004

Calculating the expression inside the parentheses:

(1 + 0.004)^(-240) ≈ 0.354296

Substituting this value into the formula:

P = $1,125 * (1 - 0.354296) / 0.004

P ≈ $1,125 * 0.645704 / 0.004

P ≈ $177,824.75

Therefore, to the nearest dollar, the maximum amount Jaxson can borrow is $177,825.

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Answer:

20.8333333333

Step-by-step explanation:

7 + 5 = 12. 250 divided by 12 equals 20.8333333333 or 20.833... You will have more than 20 and a half batches but you can just say about 21, however needed.

Answer:

x=−4

Step-by-step explanation:

Rearrange terms

20−2=−7

−2+20=−7

Subtract 20 from both sides of the equation

−2+20=−7

−2+20−20=−7−20

Subtract the numbers

−2=−7−20

Add 7 to both sides of the equation

−2=−7−20

−2+7=−7−20+7

Simplify

5=−20

Divide both sides of the equation by the same term

5x=-20

5x/5=-20/5

Simplify

x=-4

Answer:

Step-by-step explanation:History(H),Economics(E),Literature(L)

1a).To find History(H) only is

H only =H-HE-HL+HEL

H only =60-30-16+10=24

b).E only=50-30-22+10=8

c). L only=48-22-16+10=20

2).no of candidates who sat for the exam is 24+8+20=52

"In an examination of final year students of a school, 60 offered history, 50 offered economics, and 48 literature." The Vein diagram is attached below.

A Venn diagram is a diagram that utilizes circles to demonstrate the similarities and contrasts between two or more items.

Generally, the equation for History students only is mathematically given as

HisO=His-His Eco-His Lie+HisEcoLie

Therefore

HisO=60-30-16+10

HisO=24

EcoO=50-30-22+10

EcoO=8

LieO=48-22-16+10

LieO=20

In conclusion, candidates that sat for at least one subject

At least HEL= 24+8+20

At least HEL=52

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Using a t-distribution table or calculator, we get the t-score and are 98% positive that the interval (32.126, 53.874) includes the genuine population mean amount the medicine would drop a typical patient's systolic blood pressure to.

We must create a confidence interval for the population mean decrease in systolic blood pressure in order to calculate how much the medicine will reduce a typical patient's systolic blood pressure with a 98% confidence level.

CI = x t /2 * (s / n)

where x is the sample mean, s is the sample standard deviation, n is the sample size, t /2 is the t-score for the desired degree of confidence, and is the significance level (1 - confidence level).

With the supplied variables plugged in, we obtain:

CI = 43 t0.01/2 * (11 / 10)

The t-score at a 98% confidence level and 9 degrees of freedom (n-1) are roughly 2.821, according to a t-distribution table or calculator.

We obtain the following number by substituting it:

CI = 43 2.821 * (11 / 10) = (32.126, 53.874)

As a result, we have a 98% confidence that the interval (32.126, 53.874) contains the actual population mean amount that the medication would reduce the systolic blood pressure of an average patient.

The following requirements must be met for the interval to be valid:

1. The sample is a straightforward random sample taken from the population.

2. For the Central Limit Theorem to be applicable, either the population is normally distributed or the sample size is sufficient (n > 30).

3. A fair estimate of the population standard deviation is the sample standard deviation (which is assumed to be unknown).

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Answer:

Step-by-step explanation:

(a) To find the probability that it is raining when you arrive in Oneirabad on a random day, we need to use the law of total probability.

Let A be the event that it is raining, and B be the event that it is the Wet season.

P(A) = P(A|B)P(B) + P(A|B')P(B')

Given that the Wet season lasts for 1/3 of the year, we have P(B) = 1/3. The probability that it is raining during the Wet season is 3/4, so P(A|B) = 3/4.

The Dry season lasts for 2/3 of the year, so P(B') = 2/3. The probability that it is raining during the Dry season is 1/6, so P(A|B') = 1/6.

Now we can calculate the probability that it is raining when you arrive:

P(A) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it is raining when you arrive in Oneirabad on a random day is 13/36.

(b) Given that it is raining when you arrive, we can use Bayes' theorem to calculate the probability that your visit is during the Wet season.

Let C be the event that your visit is during the Wet season.

P(C|A) = (P(A|C)P(C)) / P(A)

We already know that P(A) = 13/36. The probability that it is raining during the Wet season is 3/4, so P(A|C) = 3/4. The Wet season lasts for 1/3 of the year, so P(C) = 1/3.

Now we can calculate the probability that your visit is during the Wet season:

P(C|A) = (3/4)(1/3) / (13/36)

= 1/4 / (13/36)

= 9/52

Therefore, given that it is raining when you arrive, the probability that your visit is during the Wet season is 9/52.

(c) Given that it is raining when you arrive, the probability that it will be raining when you return to Oneirabad in a year's time depends on the season. If you arrived during the Wet season, the probability of rain will be different from if you arrived during the Dry season.

Let D be the event that it is raining when you return.

If you arrived during the Wet season, the probability of rain when you return is the same as the probability of rain during the Wet season, which is 3/4.

If you arrived during the Dry season, the probability of rain when you return is the same as the probability of rain during the Dry season, which is 1/6.

Since the season you arrived in is independent of the weather when you return, we need to consider the probabilities based on the season you arrived.

Let C' be the event that your visit is during the Dry season.

P(D) = P(D|C)P(C) + P(D|C')P(C')

Since P(C) = 1/3 and P(C') = 2/3, we can calculate:

P(D) = (3/4)(1/3) + (1/6)(2/3)

= 1/4 + 1/9

= 9/36 + 4/36

= 13/36

Therefore, the probability that it will be raining when you return to Oneirabad in a year's time, given that it is raining when you arrive, is 13/36.

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The Law of Large Numbers is a fundamental concept in probability theory and statistics stating the number of trials of a random event increases, the average of the outcomes approaches the expected value of the event. It's better to use 500 trials.

In other words, as we repeat an experiment a large number of times, the proportion of times that a certain outcome occurs will converge to its probability of occurrence. This is an important concept in statistical inference, as it helps to ensure that the results of a sample are representative of the population from which it was drawn.

Now, if you were using the relative frequency of an event to estimate the probability of the event, it would be better to use 500 trials rather than 100 trials. The reason is that the larger the number of trials, the more accurate the estimate of the probability is likely to be.

Using a larger sample size reduces the impact of random variation and provides a more precise estimate of the true probability. The Law of Large Numbers tells us that as the sample size increases, the relative frequency of the event should converge to the true probability, so a larger sample size will generally give a more reliable estimate

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The correct option H0: µD ≥ 0,HA: µD < 0, is used to determine whether the first population's mean is lower than the second population's mean, a set of hypotheses.

Paired testing, commonly referred to as auditing, is a practical and easy technique to determine whether and how discrimination is present.

Thus, µD ≥ 0,HA: µD < 0, is used to determine whether the first population's mean is lower than the second population's mean, a set of hypotheses.

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C. Safe, reliable childcare for a single parent so they can go to work

Answer

967.1  squared cm, multiply area of base by two, and perimeter by 15.

Answer:

x = 12

Step-by-step explanation:

72° and (7x + 24)° are same- side interior angles and sum to 180° , that is

72 + 7x + 24 = 180

7x + 96 = 180 ( subtract 96 from both sides )

7x = 84 ( divide both sides by 7 )

x = 12

The solution of each expression is

(1) (-2×-5-3)+(2×-2)  = - 10

(2) (3/4 x-1)-(1/3 x +4) = -13/12 x -5

(3) -6.5b+11 + 3.3 b - 2 = - 3.2b + 9

(4) (-3.6x+9.4)-(1.9x +3.6) = -5.5 x + 5.8

When two expressions are connected with the equals sign (=) in a mathematical formula, it expresses the equality of the two expressions. An equation is an algebraic statement that demonstrates two mathematical expressions are equivalent in algebra, and this is how it is most usually used. In the equation 3x + 5 = 14, for instance, the two expressions 3x + 5 and 14 are separated by the symbol "equal." When two expressions are joined by an equal sign, a mathematical statement is called an equation. An equation is something like 3x - 5 = 16. By solving for x, we discover that x equals 7, which is the value for the variable.

(1) The sum of the given expressions is given as
(-2×-5-3)+(2×-2)

= -2x - 8 + 2x - 2

= -8 - 2

= - 10

(2) (3/4 x-1)-(1/3 x +4)

(-3/4) x- (1/3) x - 1 - 4

= -13/12 x -5

(3) -6.5b+11 + 3.3 b - 2

= (-6.5+ 3.3) +11 -2

= - 3.2b + 9

(4) (-3.6x+9.4)-(1.9x +3.6)

= (-3.6x-1.9x)+9.4 - 3.6

= -5.5 x + 5.8

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Tom will pay a total of $13,424.20 in interest over the term of the loan.

The formula to calculate the monthly payment for an amortized loan is given by:  `P = r(PV) / [1 - (1 + r)^(-n)]`Where P is the monthly payment, r is the interest rate per month, PV is the present value of the loan, and n is the number of payments or the total number of months.

Substituting the given values, we get:P = 0.0052083333 × 44,000 / [1 - (1 + 0.0052083333)^(-7×12)]P = 632.32Therefore, Tom's monthly payment is $632.32 (rounded to the nearest cent).b. Since Tom pays the monthly payment each month for the full term, his total amount to repay the loan is equal to the present value of the loan.

Therefore, the total amount to repay the loan is $44,000 (rounded to the nearest cent).c. The total amount of interest paid over the term of the loan can be calculated as the difference between the total amount repaid and the principal amount of the loan.

Therefore, the total interest paid is: Total interest paid = Total amount repaid - Principal amount of the loan Total interest paid = $57,424.20 - $44,000Total interest paid = $13,424.20

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The value of the given triple integral is (3π)/8.

To evaluate the given triple integral using cylindrical coordinates, we first need to express the integrand in terms of cylindrical coordinates. The cylindrical coordinates are given by (ρ, θ, z), where ρ is the distance from the z-axis, θ is the angle made with the x-axis (0 ≤ θ ≤ 2π), and z is the height.

Converting the Cartesian coordinates to cylindrical coordinates, we have:

We also have the limits of integration:

Substituting the cylindrical coordinates and limits of integration, we have:

∫∫∫3sin(x² y)d²xdydz = ∫₀²π ∫₀¹ ∫₀¹ 3sin(ρ² cos²θ sin²θ) ρ dz dρ dθ

Evaluating the z-integral, we get:

∫₀²π ∫₀¹ 3/ρ sin(ρ² cos²θ sin²θ) dρ dθ

Simplifying the integrand, we get:

∫₀²π ∫₀¹ 3/ρ sin(ρ²(1-ρ² sin²θ)) dρ dθ

Let u = ρ²(1-ρ² sin²θ). Then, du/dρ = 2ρ(1-3ρ² sin²θ). Solving for ρ in terms of u, we have:

ρ² = u/(1+u sin²θ)

Substituting for ρ² and du/dρ, we get:

∫₀²π ∫₀¹ 3/2 ∫₀¹ sin(u)/(1+u sin²θ) du dθ

Evaluating the u-integral using u-substitution, we get:

∫₀²π ∫₀¹ 3/2 ∫₀¹ sin(u)/(1+u sin²θ) du dθ = ∫₀²π ∫₀¹ 3/2 (1/2) ln(1+u sin²θ)∣₀¹ dθ

= ∫₀²π ∫₀¹ 3/4 ln(1+sin²θ) dθ

Solving the inner integral, we get:

∫₀¹ ln(1+sin²θ) dθ = θ - tan⁻¹(sinθ)∣₀¹ = π/2

Substituting back into the original integral, we get:

∫₀²π ∫₀¹ 3/4 ln(1+sin²θ) dθ = (3/4) π/2 = (3π)/8

Therefore, the value of the given triple integral is (3π)/8.

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The cylinder with maximum volume has a radius of 6.5 feet and a height of 2.5 feet.

Let the radius and height of the cylinder be r and h, respectively. Since the cylinder is inscribed in the cone, its height and radius must satisfy the following conditions:

The height of the cylinder must be equal to the height of the cone, i.e. h = 2.5 feet.

The radius of the cylinder must be less than or equal to the radius of the base of the cone, i.e. r ≤ 6.5 feet.

To maximize the volume of the cylinder, we can use the formula for the volume of a cylinder:

V = πr^2h

Substituting h = 2.5, we get:

V = 2.5πr^2

Now, we can express the volume of the cylinder in terms of a single variable, r. To do this, we use the fact that the cylinder is inscribed in the cone, so the cross-sectional area of the cylinder is a fraction of the cross-sectional area of the cone. Specifically, the ratio of the areas is equal to the square of the ratio of the radii:

r/6.5 = h/2.5

Solving for h, we get:

h = 2.5r/6.5

Substituting into the formula for the volume of the cylinder, we get:

V = 2.5πr^2 = 2.5πr^2(h/2.5) = πr^2(2r/6.5)

Simplifying, we get:

V = (4π/13)r^3

To find the value of r that maximizes V, we can take the derivative of V with respect to r and set it equal to zero:

dV/dr = (4π/13)3r^2 = 0

Solving for r, we get:

r = 0

This is not a valid solution since r must be greater than zero. Therefore, we must look for a maximum value of V on the interval 0 < r ≤ 6.5.

To do this, we can evaluate V at the endpoints of the interval and at any critical points in the interior. Since we already know that there are no critical points, we just need to evaluate V at the endpoints:

V(0) = 0

V(6.5) = (4π/13)(6.5)^3 ≈ 724.06

Therefore, the cylinder with maximum volume has a radius of 6.5 feet and a height of 2.5(6.5/6.5) = 2.5 feet.

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The formula to calculate the area of the parallelogram with the adjacent sides u and y is given by; A = u × y × sinθwhere u and y are adjacent sides and θ is the angle between them.

Let's calculate the area of the parallelogram for each problem one by one.29. u = 3i - j, v = 3j + 2kWe have,u = 3i - j and v = 3j + 2kNow, calculate the cross product of u and v;u × v = (-3k) i + (9k) j + (3i) k - (9j) k = 3i - 12j - 3k

We can calculate the magnitude of the cross product as;|u × v| = √(3² + (-12)² + (-3)²) = √(9 + 144 + 9) = √(162) = 9√2Now, we can calculate the area of the parallelogram as;A = |u × v| × sinθSince sinθ = 1,

we haveA = 9√2 × 1 = 9√2 sq.units.30. u = -3i + 2k, v = i + j + k

We have,u = -3i + 2k and v = i + j + kNow, calculate the cross product of u and v;u × v = (-2i + 3j + 5k) i - (5i + 3j - 3k) j + (i - 3j + 3k) k = (-2i - 5j + i) + (3i - 3j - 3k) + (5k + 3j + 3k)= -i - 6j + 8k

We can calculate the magnitude of the cross product as;|u × v| = √((-1)² + (-6)² + 8²) = √(1 + 36 + 64) = √(101)Now, we can calculate the area of the parallelogram as;A = |u × v| × sinθSince sinθ = 1,

we have A = √(101) × 1 ≈ 10.0499 sq.units.32. u = 8i + 20j - 3k, v = 2i + 43j - 4kWe have,u = 8i + 20j - 3k and v = 2i + 43j - 4kNow, calculate the cross product of u and v;u × v = (-80k + 12j) i - (-32k + 24i) j + (-86j - 16i) k= 12i + 512k6j + 1

We can calculate the magnitude of the cross product as;|u × v| = √(12² + 56² + 112²) = √(144 + 3136 + 12544) = √(15724) ≈

we can calculate the area of the parallelogram as;A = |u × v| × sinθSince sinθ = 1,

we haveA = 125.3713 × 1 ≈ 125.3713 sq.units.

Hence, the area of the parallelogram for the given values of u and v is;29. 9√2 sq.units30. ≈ 10.0499 sq.units32. ≈ 125.3713 sq.units.

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The expected value of the envelope is less than 100,000, Margaret should reject the offer and keep her envelope.

To determine whether Margaret should accept the offer of $X for her envelope, we need to compare the expected value of the envelope to the amount offered. Given that the envelope contains either $81,000 or $40 with equal probability, the expected value of the envelope is calculated as follows:
Expected value = (probability of $81,000) * $81,000 + (probability of $40) * $40
Expected value = (1/2) * $81,000 + (1/2) * $40
Expected value = $40,520 + $20
Expected value = $40,540

According to Margaret's utility function, v(m) = m, she values money linearly. Therefore, for her to accept the offer of $X for her envelope, X should be at least equal to the expected value of the envelope. In this case, X should be at least $40,540.

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Rounding this to two decimal places, the equivalent nominal interest rate compounded monthly is approximately 2.53%.

To determine the equivalent nominal interest rate compounded monthly for a given nominal interest rate compounded quarterly, we can use the formula for nominal interest rate conversion.

The formula is:

r = (1 + i/n)^n - 1

Where:

r is the nominal interest rate compounded annually (we're looking for this),

i is the nominal interest rate compounded quarterly (2.50% in this case),

n is the number of compounding periods per year (4 for quarterly compounding).

Plugging in the values, we have:

r = (1 + 0.025/4)^4 - 1

Calculating this expression, we find:

r ≈ 0.025335

Rounding this to two decimal places, the equivalent nominal interest rate compounded monthly is approximately 2.53%.

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1 - In order to solve this problem we have to solve the following equation

20 = 25t - 5t²

2 - In order to solve that equation we have to options

1 - Use the quadratic equation

2 - Factor the expression

For this probem we will facor the expression. The first thing that we will do is divide everything by 5, so we get

20/5 = ( 25/5 ) t - (5 / 5 ) t²

which would give us

4 = 5t - t²

Now we subtract 4 and we get

t² - 5t +4 = 0

then

t² - 5t +4 = (t - 4 ) (t - 1 ) = 0

Therefore there are two answers

t = 4

t = 1

Notice that the answer is correct because

h = 25(1) - 5*(1)² = 20

Answer:

B & D because someone had the same exact question but with a picture

Step-by-step explanation:

Here every player gets 2 bottles of water and 1 bottle of lemonade. Then each player should get a total of 4 fluid ounces of water and 2 fluid ounces of lemonade.

Here we have to apply the principles of algebraic expressions to derive the answer
To evaluate the total fluid ounces each player gets, we can apply summation of the total fluid ounces from Sachi's bottles and Olivia's bottles then divide it by the number of players.
Total fluid ounces from Sachi's bottles = (22 × x) + (15 × y)
where
x = number of fluid ounces in each bottle of water
y = number of fluid ounces in each bottle of lemonade.
Total fluid ounces from Olivia's bottles = (28 × x) + (10 × y)
Total fluid ounces = Total fluid ounces from Sachi's bottles + Total fluid ounces from Olivia's bottles
Total fluid ounces = (22 × x) + (15 × y) + (28 × x) + (10 × y)
Total fluid ounces = 50x + 25y
Total number of players = Number of players on Sachi's team + Number of players on Olivia's team
Total number of players = 2(Number of players on Sachi's team)
Total number of players = Number of players on Sachi's team + Number of players on Olivia's team
Number of players on Sachi's team = Total number of players / 2
Number of players on Olivia's team = Total number of players / 2
Staging the values we get,
50x + 25y = Total fluid ounces = (22 × x) + (15 × y) + (28 × x) + (10 × y)
50x + 25y = 564 + 536
50x + 25y = 1100
Dividing both sides by 25,
2x + y = 44
Each player gets 4 fluid ounces of water and 2 fluid ounces of lemonade.
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