Answer:
5/6
Step-by-step explanation:
hello
in total there are 12 numbers
C has two items
so C' has 10 items
so the probability that this number is in set C' is 10/12=5/6
hope this helps
Consider Example 6-1 in the textbook; the one with uncertainty on pages 150-156. Then, make the following changes: (1) Trips Logistis receives revenue of 1.32 for each unit of demand. (2) For the Fixed Lease Option, the lease must be signed for 120,000 sq. ft. of warehouse space. (3) For the Flexible Lease Oprtion, Trips Logistics will have the flexibility of using between 120,000 sq. ft. to 144,000 sq. ft. What is the expected NPV of the Flexible Lease Option? $47,868 $27,868
$37,868
$57, 8686
The expected NPV of the Flexible Lease Option with the given changes is -$3,475,760.
Based on the information provided, let's assume the following:
- The demand for warehouse space can be low (L), medium (M), or high (H).
- The probabilities of each demand level are P(L) = 0.3, P(M) = 0.4, and P(H) = 0.3.
For the Flexible Lease Option:
- The lease cost for 120,000 sq. ft. is $3,500,000.
- The lease cost for 144,000 sq. ft. is $4,000,000.
- The revenue per unit of demand is $1.32.
Let's calculate the expected NPV:
1. Determine the cash flows for each demand level:
For Low demand (L):
- Revenue = 120,000 sq. ft. $1.32 = $158,400
- Lease cost = $3,500,000
For Medium demand (M):
- Revenue = 132,000 sq. ft. $1.32 = $174,240
- Lease cost = $3,500,000
For High demand (H):
- Revenue = 144,000 sq. ft. $1.32 = $190,080
- Lease cost = $4,000,000
2. Calculate the NPV for each demand level:
For Low demand (L):
NPV(L) = Revenue(L) - Lease cost = $158,400 - $3,500,000 = -$3,341,600
For Medium demand (M):
NPV(M) = Revenue(M) - Lease cost = $174,240 - $3,500,000 = -$3,325,760
For High demand (H):
NPV(H) = Revenue(H) - Lease cost = $190,080 - $4,000,000 = -$3,809,920
3. Calculate the expected NPV:
Expected NPV = P(L) NPV(L) + P(M) NPV(M) + P(H) NPV(H)
Expected NPV = 0.3 (-$3,341,600) + 0.4 (-$3,325,760) + 0.3 * (-$3,809,920)
Expected NPV = -$1,002,480 - $1,330,304 - $1,142,976
Expected NPV = -$3,475,760
Therefore, the expected NPV of the Flexible Lease Option with the given changes is -$3,475,760.
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Determine the Type I error if the null hypothesis, H0, is: the percentage of homes in the city that are not up to the current electric codes is no more than 10%. And, the alternative hypothesis, Ha, is: the percentage of homes in the city that are not up to the current electric codes is more than 10%.
Answer:
..
Step-by-step explanation:
.
In the example for “solving right triangles using trigonometric ratios”, students solved for a triangle given angle 0 = 48 and b = 10 using cosine and secant. Use the diagram below as a reference
using trigonometric ratios, following is the proof.
In what way may I locate trigonometric ratios?You can determine trigonometric ratios by either utilizing the provided acute angle or by figuring out the ratios of the right-angled triangle's sides. The formula for trigonometric ratios is sin = Perpendicular/Hypotenuse. base/hypotenuse = cos.
Its given that
θ = 48 , b = 10
Cos θ = b/c
Cos 48 = 10/c Equation (A)
Sec 48 = c/b
sec 48 c/10 Equation (B)
Equation (A) × Equation (B)
Cos 48 × Sec 48
10/c × c/10
1 =1
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pls eliminate this problem, i will give 50 brainliest points
Required solution of the given equations are x = 2 and y = -26
What is elimination method?
The elimination method is a technique used to solve systems of linear equations. The idea is to add or subtract the equations in order to eliminate one of the variables, which will allow us to solve for the other variable. In this case, we eliminated y by adding the two equations. The method can be used with any number of variables, but it can become more complex as the number of variables increases
To solve these equations by elimination method, we can eliminate one of the variables by adding or subtracting the two equations.
First, let's rearrange the second equation to put it in standard form:
y = -9x - 26
Now we can add the two equations:
-2x - y = 12.. ..(1)
y = -9x - 26
or, -9x-y = 26....(2)
We are subtracting equation (2) from equation (1) and get
-2x-y+9x+y = 26-12
So, 7x = 14
Simplifying, we get:
x = 2
Now, from equation (1),
-2×2-y = 12
So, y = -16
So the solution to the system of equations is (2,-16).
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The output values for y = x² and y = 15 + x show patterns. Describe in words how the patterns differ. Use the words increase and decrease in your description.
The pattern in y = x² exhibits a nonlinear increase in y as x increases, forming a U-shaped curve, while the pattern in y = 15 + x shows a linear increase in y as x increases at a constant rate.
The patterns in the equations y = x² and y = 15 + x differ in terms of the direction of change. In the equation y = x², the pattern shows an increase in y as x increases.
As x increases from negative to positive values, the corresponding y values also increase, forming a symmetric U-shaped curve. The rate of increase for y becomes steeper as x moves further away from zero.
On the other hand, in the equation y = 15 + x, the pattern shows a linear increase in y as x increases. As x increases, the corresponding y values increase in a straight line.
The rate of increase for y remains constant at one unit per increase in x. This linear pattern reflects a constant upward shift of the graph as x increases.
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I'm been doing this question about an hour still can't solve so I really need your help! Really appreciate if u do :D
Explanation:
1 hat = 45 dollars
6 hats = 6*45 = 270 dollars
1 phone = 40 dollars
4 phones = 4*40 = 160 dollars
total = $270 + $160 = $430
Felicia spent a total of $430. Since this amount of money leaves her account, this means we write a negative sign out front to end up with the final answer of -430
In other words, her account balance went down by $430 which is why we use a negative. If someone gave her $430, then the answer would be positive.
If we change the constraint quantity to a value outside the range of feasibility for that constraint quantity, the shadow price will change.
True or False
Yes, it is True. If we change the constraint quantity to a value outside the range of feasibility for that constraint quantity, the shadow price will change.
The shadow price is the marginal value of the constraint quantity, and it represents the increase in the objective function per unit increase in the constraint quantity. If the constraint quantity is changed to a value outside the range of feasibility, the shadow price will change because the relationship between the objective function and the constraint quantity has changed. The change in shadow price will depend on how the constraint affects the objective function, but it is typically that the shadow price will increase as the constraint becomes more binding.
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Solve 11 = 6 + a help pls
Answer:
Subtraction Property of Equality
Step-by-step explanation:
Subtract six from both sides
5=a
question 1 a data set containing 36 data points is divided into nine quantiles. what is the maximum number of data points that fall within the first quantile?
The maximum number of data points that can fall within the first quantile is 4 + 4 + 4 + 4 = 16.
To determine the maximum number of data points that can fall within the first quantile, we need to understand the concept of quantiles and how they are calculated.
Quantiles are values that divide a dataset into equal-sized subgroups. For example, the first quartile (Q1) divides the data into four equal parts, while the second quartile (Q2) is the median, dividing the data into two equal parts. In general, if we divide a dataset into "n" quantiles, each quantile will contain roughly an equal number of data points.
Given that we have 36 data points and we want to divide them into nine quantiles, we can calculate the maximum number of data points that can fall within the first quantile as follows:
Each quantile will contain approximately 36/9 = 4 data points because we have 36 data points divided into 9 quantiles.
Since we want to determine the maximum number of data points in the first quantile, we can assume that all the data points in the first four quantiles fall within the first quantile.
However, it's important to note that this assumes a perfect division of the data points into equal-sized quantiles. In practice, due to rounding and distribution characteristics, the actual number of data points in each quantile may vary slightly from the ideal.
Therefore, while 16 is the maximum number of data points that can fall within the first quantile, the actual number of data points may be slightly different in a real-world dataset.
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Two consecutive odd number have a product of 35. What are the numbers?
Please help me find the vertex of the following quadratic equation and explain how to find the vertex.
The Solution:
Given:
We are asked to find the vertex of the given equation.
The Vertex formula for a Quadratic Equation is:
From the given equation, we have:
\(y=7(x^2-8x+16)+14\)\(\begin{gathered} y=7x^2-56x+112+14 \\ \\ y=7x^2-56x+126 \end{gathered}\)In this case,
\(\begin{gathered} a=7 \\ b=-56 \\ c=126 \end{gathered}\)So, the vertex is:
\((h,k)=(\frac{-b}{2a},\frac{-(b^2-4ac)}{4a})=(\frac{-(-56)}{2(7)},\frac{-[(-56)^2-4(7)(126)}{4(7)})=(4,-14)\)Therefore, the correct answer is:
\((h,k)=(4,-14)\)In the triangle below,
y = [ ? ) cm. Round to the
nearest tenth.
Answer:
9.7
Step-by-step explanation:
using TOA (angle, opposite, adjacent)
t = 70 o = 12 a = ?
equation in calc = tan-1(12/70) = 9.727... rounded down = 9.7
PLEASE HELP QUICK!!!! WILL GIVE BRAINIEST!!!!!
Answer:
From top to bottom:
Slope intercept Equation: \(y = \frac{3}{4} x+2\) \(y=3x-2\)
Slope: 4 2
Y-int: (0,-2) (0,10)
Step-by-step explanation:
Please help will mark brainliest
Answer:
-4
Step-by-step explanation:
Answer:
y = 1/3x - 3
Step-by-step explanation:
the population of the city Martin was approximately 12,420 in the year 2005 and has been continuously growing at a rate of 1.6% each year
The function that describes the population of Martin is\(P(t) = 12,420 \times (1 + 0.016)^t\)
The predicted population of Martin in 2015 is 14557
The predicted population of Martin in 2002 is 10,658
The function that describes the population of Martin as a function of the number of years t, since 2005, can be written as:
\(P(t) = 12,420 \times (1 + 0.016)^t\)
where P(t) is the population of Martin t years since 2005.
To predict the population of Martin in 2015, we need to substitute t = 10 into the equation:
P(10) = 12,420 × (1 + 0.016)¹⁰
= 14556.5
Therefore, the predicted population of Martin in 2015 is approximately 14556.5 people.
To predict the population of Martin in 2002, we need to find the number of years between 2005 and 2002, which is 3 years.
We can substitute t = -3 into the equation:
P(-3) = 12,420 × (1 + 0.016)⁻³)
= 10,658
Therefore, the predicted population of Martin in 2002 is approximately 10,658 people.
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A factory inspector found flaws in 3 out of 18 wooden boxes. What is the experimental probability that the next wooden box will be flawed?
Write your answer as a fraction or whole number.
Hi there!
»»————- ★ ————-««
I believe your answer is:
\(\frac{1}{6}\)
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
\(\boxed{\text{Box Probability}}\\\\\rightarrow \frac{\text{# of boxed flawed}}{\text{# of boxes checked}} \\\\\rightarrow \frac{3}{18}\\\\\rightarrow \frac{3/3}{18/3}\\\\\rightarrow\boxed{\frac{1}{6}}\)
⸻⸻⸻⸻
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
1. biotech research center is working to develop a new vaccine for the west nile virus. the project is so important that the firm has created three teams of experts to work on the project from different perspectives. team 1 has an 86 percent chance of success, team 2 an 87 percent chance of success, and team 3 a 65 percent chance. what is the probability that biotech will develop the
Probability that the vaccine will be developed = \(\frac{99363}{100000}\)
What is probability?
Probability gives us the information about how likely an event is going to occur
Probability is calculated by Number of favourable outcomes divided by the total number of outcomes.
Probality of any event is greater than or equal to zero and less than or equal to 1.
Probability of sure event is 1 and probability of unsure event is 0.
Here,
Team 1 has an 86 % chance of success of developing a new vaccine
Team 1 has 100 - 86 = 14% chance of failure of developing a new vaccine
Team 2 has an 87 % chance of success of developing a new vaccine
Team 2 has 100 - 87 = 13% chance of failure of developing a new vaccine
Team 3 has an 65 % chance of success of developing a new vaccine
Team 3 has 100 - 65 = 35% chance of failure of developing a new vaccine
Probability that the vaccine will not be developed =
\(\frac{14}{100} \times \frac{13}{100}\times \frac{35}{100}\\\frac{637}{100000}\\\)
Probability that the vaccine will be developed =
\(1 - \frac{637}{100000}\\\\\frac{100000-637}{100000}\\\\\frac{99363}{100000}\)
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PLEASE ILL DO ANYTHING I ALREADY OFFERED AS MUCH POINTS AS POSSIBLE
Answer:
A, B, D, E
Step-by-step explanation:
Given expression:
(0.06) · (0.154)When multiplying decimals, multiply as if there are no decimal points:
\(\implies 6 \times 154 = 924\)
Count the number of digits after the decimal in each factor:
0.06 → 2 digits0.154 → 3 digitsTherefore, there is a total of 5 digits.
Put the same number of total digits after the decimal point in the product:
\(\implies (0.06) \cdot (0.154)=0.00924\)
-----------------------------------------------------------------------------------------------
Answer option A
\(\boxed{6 \cdot \dfrac{1}{100} \cdot 154 \cdot \dfrac{1}{1000}}\)
When dividing by multiples of 10 (e.g. 10, 100, 1000 etc.), move the decimal point to the left the same number of places as the number of zeros.
Therefore:
6 ÷ 100 = 0.06154 ÷ 1000 = 0.154\(\implies 6 \cdot \dfrac{1}{100} \cdot 154 \cdot \dfrac{1}{1000}=(0.06) \cdot (0.154)\)
Therefore, this is a valid answer option.
Answer option B
\(\boxed{6 \cdot 154 \cdot \dfrac{1}{100000}}\)
Multiply the numbers 6 and 154:
\(\implies 6 \times 154 = 924\)
Divide by 100,000 by moving the decimal point to the left 5 places (since 100,000 has 5 zeros).
\(\implies 6 \cdot 154 \cdot \dfrac{1}{100000}=0.00924\)
Therefore, this is a valid answer option.
Answer option C
\(\boxed{6 \cdot (0.1) \cdot 154 \cdot (0.01)}\)
Again, employ the technique of multiplying decimals by first multiplying the numbers 6 and 154:
\(\implies 6 \cdot 154 = 924\)
Count the number of digits after the decimal in each factor:
0.1 → 1 digit0.01 → 2 digitsTherefore, there is a total of 3 digits.
Put the same number of digits after the decimal point in the product:
\(\implies 0.924\)
Therefore, as (0.06) · (0.154) = 0.00924, this answer option does not equal the given expression.
Answer option D
\(\boxed{6 \cdot 154 \cdot (0.00001)}\)
Again, employing the technique of multiplying decimals.
As there are a total of 5 digits after the decimals:
\(\implies 6 \cdot 154 \cdot (0.00001)=0.00924\)
Therefore, this is a valid answer option.
Answer option E
\(\boxed{0.00924}\)
As we have already calculated, (0.06) · (0.154) = 0.00924.
Therefore, this is a valid answer option.
3+(5+4)(8-6) what is this please help
Answer:
21
Step-by-step explanation:
simplify the expression
:)
The table below represents which equation?
х
0
2.
-1
1
1
-5
2
-8
у
-2
A
y = -x
B
y = 3x + 6
y=-3x - 2
D
y = x + 2
Answer:
C
Step-by-step explanation:
The slope of the equation is
1- (-2)/-1-0 = 3/-1 = -3
the slope of y= -3x-2 is -3
50- select C
{ find the slope of the equation }
Can I please help me ?!
Answer:
14 ft
Step-by-step explanation:
area = length * width
140 sq ft = 10 ft * width
width = (140 sq ft)/(10 ft)
width = 14 ft
Find the volume of the solid generated by rotating the region bounded by y=e^−x,y=0,x=−1,x=0 about the line x=2. Volume =
The volume of the solid generated by rotating the given region about the line x = 2 is 13π/3.
The given region is bounded by
\(y = e^(-x),\)
y = 0,
x = -1 and
x = 0.
We are required to find the volume of the solid generated by rotating the region about the line x = 2.
The volume of the solid generated by rotating the given region about the line x = 2 is given by:
V = π ∫ \([R] [(f(x) + 2)^2 - 4^2] dx\)
where [R] denotes the region of integration and f(x) is the distance between the line of rotation and the function
(f(x) = 2 - x in this case).
Putting the given values into the formula, we get:
V = π ∫\([-1, 0] [(2 - x + 2)^2 - 4^2] dx\)
= π ∫\([-1, 0] [(4 - x)^2 - 16] dx\)
= π ∫\([-1, 0] [x^2 - 8x] dx\)
= π \([x^3/3 - 4x^2] [-1, 0]\)
= π [(0 - 0) - (-1/3 + 4)]
= π (13/3)
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Consider a one-way classification model
$$
y_{i j}=\mu+\tau_i+\varepsilon_{i j}
$$
for $i=1,2,3$ and $j=1,2, \ldots, n_i$. The following data is collected:
\begin{tabular}{l|ccc} Factor level: & $\mathrm{A}$ & $\mathrm{B}$ & $\mathrm{C}$ \\
\hline$n_i$ & 12 & 8 & 16 \\
Mean response: & 11.3 & 8.4 & 10.2
\end{tabular}
We are also given $s^2=4.9$.
For this question, you may not use the $1 \mathrm{~m}$ function in $\mathrm{R}$.
(a) Calculate a $95 \%$ confidence interval for $\tau_A-\tau_B$.
(b) Calculate the $F$-test statistic for the hypothesis $\tau_A=\tau_B=\tau_C$, and state the degrees of freedom for the test.
(c) Test the hypothesis $H_0: \tau_C-\tau_B \geq 2$ against $H_1: \tau_C-\tau_B<2$ at the $5 \%$ significance level.
(d) Suppose the above data is collected through a completely randomised design with total sample size $n=36$. Does this design minimise 2 var $\left(f_A-\hat{t}_C\right)+\operatorname{var}\left(\hat{\tau}_B-\hat{t}_C\right)$ ? If not, what is the optimal allocation for $n_A, n_B$, and $n_C$ ?
a) The confidence interval for τA - τB is:
CI = (τA - τB) ± t* * SE(τA - τB)
b) the sum of squares: SSE = (11.3 - μA)² + (11.3 - μA)²
What is the confidence interval?
A confidence interval is a range of values that is likely to contain the true value of an unknown population parameter, such as the population mean or population proportion. It is based on a sample from the population and the level of confidence chosen by the researcher.
(a) To calculate the 95% confidence interval for τA - τB, we can use the formula:
CI = (τA - τB) ± t(α/2, df) * SE(τA - τB)
where t(α/2, df) is the t-score for the desired confidence level and degrees of freedom, and SE(τA - τB) is the standard error of the difference in means.
The degrees of freedom for the test can be calculated using the formula:
df = ∑(ni - 1)
Given the data:
nA = 12, nB = 8, and mean responses: μA = 11.3, μB = 8.4, μC = 10.2
We can calculate the standard error using the formula:
SE(τA - τB) = √((s²/nA) + (s²/nB))
where s² is the sample variance.
Calculating the degrees of freedom:
df = (nA - 1) + (nB - 1) = 11 + 7 = 18
Plugging in the values, we have:
SE(τA - τB) = √((4.9/12) + (4.9/8)) ≈ 1.313
The t-score for a 95% confidence interval with 18 degrees of freedom can be found using a t-table or statistical software. Let's assume the t-score is t*.
The confidence interval for τA - τB is:
CI = (τA - τB) ± t* * SE(τA - τB)
You would need to consult a t-table or use statistical software to find the t* value. The interval would be calculated by substituting the appropriate values.
(b) To calculate the F-test statistic for the hypothesis τA = τB = τC, we can use the formula:
F = (MSA / MSE)
where MSA is the mean square due to treatments and MSE is the mean square error.
The mean square due to treatments can be calculated as:
MSA = SSA / (k - 1)
where SSA is the sum of squares due to treatments and k is the number of groups (in this case, k = 3).
The mean square error can be calculated as:
MSE = SSE / (N - k)
where SSE is the sum of squares error and N is the total sample size.
To calculate the sum of squares:
SSA = ∑(ni * (μi - μ)²)
SSE = ∑∑((yij - μi)²)
Given the data, we can calculate the sum of squares:
SSA = (12 * (11.3 - ((11.3 + 8.4 + 10.2) / 3))^2) + (8 * (8.4 - ((11.3 + 8.4 + 10.2) / 3))²) + (16 * (10.2 - ((11.3 + 8.4 + 10.2) / 3))²)
SSE = (11.3 - μA)² + (11.3 - μA)²
Hence, a) The confidence interval for τA - τB is:
CI = (τA - τB) ± t* * SE(τA - τB)
b) the sum of squares: SSE = (11.3 - μA)² + (11.3 - μA)²
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A six-foot person walks from the base of a streetlight directly toward the tip of the shadow cast by the streetlight... (more down below)When the person is 12 feet from the streetlight and 5 feet from the tip of the streetlight's shadow, the person's shadow starts to appear beyond the streetlight's shadow.(a) Draw a right triangle that gives a visual representation of the problem. Show the known quantities and use a variable to indicate the height of the streetlight. (b) Use a trigonometric function to write an equation involving the unknown quantity.
h =(c) What is the height of the streetlight?
______ ft
b) h = \(tan \theta\) x 17 is the required equation.
c) The height of the streetlight is 20.4 ft.
The height of the person is 6 ft.
The distance at which the person is standing from the streetlight = 12 ft.
The distance at which the person's shadow appears = 5ft.
a) Hence, we can make the following diagram.
The right triangle below gives a visual representation of the problem. It shows the known quantities and a variable 'h' to indicate the height of the streetlight.
b) Let's now find an equation trigonometric function involving the unknown quantity 'h'.
from the below diagram, we can say that,
\(tan \theta\) = h/base
base= 12+5=17
hence we have, \(tan \theta\) = h/17
h = \(tan \theta\) x 17 is the required equation.
c) Now we have to find the height of the streetlight.
firstly let's find the value of \(\theta\),
\(\theta\) = tan 6/5.
\(tan^{-1}\)(6/5) = 50.2°
hence, tan 50.2 = h/17
1.20 = h/17
h= 1.20 x 17
h= 20.4 ft.
Hence, the height of the streetlight is 20.4 ft.
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Let Σ be the alphabet {0,1}. For each of the following sets indicate if its cardinality is finite or infinite. If it is finite what is its cardinality and if it is not finite is it countable or uncountable? a.) Σ b.) 2^Σ’ c.) Σ' d.) 2^ Σ e.) {ɸ}
The answer to this question is 2, finite set, 1,4, singleton set.
Explanation: Partwise
a) Σ = {0, 1} is a finite set, and its cardinality is 2.
b) 2^Σ' is the power set of the complement of Σ, which is the set of all subsets of the complement of Σ. The complement of Σ is {ε}, where ε is the empty string. Therefore, 2^Σ' is the set of all subsets of {ε}, which has cardinality 2^1 = 2. So, 2^Σ' is a finite set with cardinality 2.
c) Σ' is the complement of Σ, which is {ε}. Therefore, Σ' is a finite set with cardinality 1.
d) 2^Σ is the power set of Σ, which is the set of all subsets of Σ. The cardinality of the power set of a finite set with n elements is 2^n. In this case, Σ has 2 elements, so 2^Σ has cardinality 2^2 = 4. So, 2^Σ is a finite set with cardinality 4.
e) {ɸ} is a singleton set, which is a finite set with cardinality 1.
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i need help with this please
Answer:212
Step-by-step explanation: 36 plus 36 40 plus 40 29 plus 29 19 plus ten then add the sums then u get 212
quick easy one to do!! 15pts
Answer:
34
Step-by-step explanation:
90-56=34
Answer:
Step-by-step explanation:
K=34
Hope it helps
And I’m only in 6th grade
And i smart ÙwÚ
Tim wants to buy several pairs of jeans. He compares the prices at a store in his neighborhood and at an online store. He finds that a pair of jeans costs $24 at the local store. If he buys online, each pair would cost $22, and he would have to pay a shipping fee of $6 per order.
Answer:
2 orders
Step-by-step explanation:
Step one:
given data
The local store sells at $24 per pair of jeans
Cost = $24
The online store sells at $22 per pair plus a shipping fee of $6 per order
let the number of orders be x
Cost= 22+6x
For 1 order
the online store will cost
Cost= 22+6*1
Cost= 22+6
Cost= $28
For 2 orders
The local shop cost
Cost= 24*2= $48
The online store will cost
Cost= 22+6*2
the online store will cost
Cost= 22+12
Cost= $34
Hence Tim should place at least 2 orders if he wants to buy online
Answer:
# of orders is 2 ORDERS!!!
Step-by-step explanation:
I hope this helps!!!
A castle has to be guarded 24 hours a day. Five knights are ordered to split each day's guard duty equally. how long will each knight spend on guard duty in one day???? Please help I am very stuck on this
Answer:
Step-by-step explanation:
If there are five knights and they need to divide the guard duty equally for the 24 hours in a day, each knight would spend 24/5 = 4.8 hours on guard duty in one day.
However, since it's not possible to guard for a fraction of an hour, they would need to round that number to the nearest whole number. In this case, each knight would spend 5 hours per day on guard duty.
How many strings of seven hexadecimal digits do not have any repeated digits? (b) How many strings of seven hexadecimal digits have at least one repeated digit? % Need Help? Read It
Number of strings of seven hexadecimal digits that do not have any repeated digits and at least one repeated are required. The hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Number of strings of seven hexadecimal digits that do not have any repeated digits. There are sixteen different digits.The first digit can be any one of the sixteen different digits. Hence, the first digit can be chosen in 16 ways. Once the first digit has been chosen, there are only fifteen remaining digits. Hence, the second digit can be chosen in 15 ways. Similarly, the third digit can be chosen in 14 ways, the fourth digit can be chosen in 13 ways, and so on. Thus, the number of ways that a string of seven hexadecimal digits can be formed without any repeated digits is given by 16×15×14×13×12×11×10 = 111, 767, 040
Number of strings of seven hexadecimal digits that have at least one repeated digit is required. There are two ways to approach the solution of this problem:By finding the number of strings that do not have any repeated digits and subtracting this from the total number of strings of seven hexadecimal digits.By counting the number of strings that have at least one repeated digit directly.
Method 1 : To find the number of strings that do not have any repeated digits, we have found in part (a) to be 111, 767, 040. The total number of strings of seven hexadecimal digits is 167, 772, 160. Hence, the number of strings of seven hexadecimal digits that have at least one repeated digit is given by:167, 772, 160 – 111, 767, 040 = 56, 005, 120
Method 2 :By counting the number of strings that have at least one repeated digit directly, we shall apply the principle of inclusion and exclusion. Let A1, A2, A3, A4, A5, A6, A7 denote the events that the first, second, third, fourth, fifth, sixth and seventh digits repeat, respectively. The number of strings in which only the first and second digits repeat is 16×15×14×13×12×11×1 = 24,883,200. Similarly, the number of strings in which only the first and third digits repeat is 24, 883, 200. There are fifteen possible pairs of distinct digits and for each such pair, there are 10 ways to place the two digits into the seven positions, i.e., ten different arrangements of the pair of digits. Hence, the number of strings in which exactly two digits repeat is given by 15×10×16×15×14×13×1 = 56,160,000. There are six different ways in which three distinct digits can be selected from sixteen. For each choice of three distinct digits, there are three possible ways that the digits can be arranged in the string. This gives a total of six×3×16×15×14×1×1×1 = 60,480. There are no strings with four or more distinct digits repeating. Thus, by the principle of inclusion and exclusion, the number of strings of seven hexadecimal digits with at least one repeated digit is given by24, 883, 200+24, 883, 200−56, 160, 000+60, 480=56,005,120
The number of strings of seven hexadecimal digits that do not have any repeated digits is 111, 767, 040. The number of strings of seven hexadecimal digits that have at least one repeated digit is 56, 005, 120.
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