Answer:
32
Step-by-step explanation:
Because in one cup there are 4 fourths, so 8*4=32
A doctor wants to estimate the mean HDL cholesterol of all 20- to 29-year-old females. How many subjects are needed to estimate the mean HDL cholesterol within 2 points with 99% confidence assuming s = 17.7 based on earlier studies? Suppose the doctor would be content with 95% confidence. How does the decrease in confidence affect the sample size required?
Click the picture to view a partial table of critical values.
A.) 99% confidence level requires _____ subjects. (Round up to the nearest subject.)
B.) 95% confidence level requires _____ subjects. (Round up to the nearest subject.)
C. How does the decrease in confidence affect the sample size required?
A. The sample size is the same for all levels or confidence .
B. Decreasing the confidence level decreases the sample size needed*
C. Decreasing the confidence level increases the sample size needed
a. 99% confidence level requires 452 subjects.
b. 95% confidence level requires 246 subjects.
c. Decreasing the confidence level decreases the sample size needed
How to solve for the sample size nWe are to solve for using the data that is gitten in the question
a. The z value using the 99 percent confidence level is given as (2.576
We have to put the value in the formula
n = (Z * s / E)^2
n = (2.576 * 17.7 / 2)^2
n ≈ 451.24
B For 95 percent, the critical value of Z is given as 1.96
when we out the value in the formula we would have
n = (1.96 * 17.7 / 2)^2
n ≈ 245.24
C. The decrease in the confidence level leads to a fall in the sample size. From the results, the sample size fell from 452 to 246 when the confidence was reduced from 99 to 95 percent
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Solve y = ax² + c for x.
O x
x= ± √ay-c
O
O
x = ±₁
X=
X=
у-с
a
y
y + c
a
In the quadratic equation y = a\(x^{2}\) + c ,the value of x = ± \(\sqrt \frac{y-c}{a}\)
A quadratic equation is any equation containing one term wherein the unknown is squared and no term wherein it's far raised to a higher power.
A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is ax2 + bx + c = 0, in which a and b are the coefficients, x is the variable, and c is the constant term.
To find the value of x
Assuming \(a\neq o\)
First, subtract c from both the sides to get:
\(y-c=ax^{2}\)
then, divide both sides by \(a\) and transpose to get:
\(x^{2} =\frac{y-c}{a}\)
So, \(x\) must be a square root of \(\frac{y-c}{a}\) and we can deduce:
\(x=\) ± \(\sqrt \frac{y-c}{a}\)
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Points X, Y, and Z are collinear, and Y is the midpoint of XZ . Find
the value of b.
The measure of the variable 'b' from the line is 11
Collinear points on a lineCollinear points are points that lies on the same straight line. From the given diagram:
XY = YZ (since Y is the midpoint of XZ)
where:
XY = 2b + 7
YZ = 3b - 4
Substitute the given parameters to have:
2b + 7 = 3b - 4
2b - 3b = -4 - 7
-b = -11
b = 11
Hence the measure of the value of b from the line is 11
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Find the measure of angle A.
60x
O 60°
O 30°
O 23°
O 37°
30x
A
Answer:
Step-by-step explanation:
sum of angles in a triangle=180º
90+60x+30x=180
90+90x=180
90(1+x)=180
1+x=2
x=1
angle A=30º
One number exceeds another by 6 and their sum is 16. Find the two numbers.
Answer:
answer is 11 or 5
Step-by-step explanation:
x+y=16 ------ 1
x-y= 6 ------ 2
______
2x = 22
x =22/2 =11
put the value of x on equation 1
x+y =16
11+y =16
y =16-11 =5
if m <4 = 61°, find m <6
Answer:
m<6 = 119
Step-by-step explanation:
m<4 + m<6 = 180 (Linear Pair)
61 + m<6 = 180
=> m<6 = 180 - 61
=> m<6 = 119
50 points pls help
Assume that the parcel starts its journey at 20ºC (lower left blank, 0 meters). Use the DAR (5C/500 meters) to calculate the decreasing temperature of the parcel up to and including the 1000-meter elevation.
The decreasing temperature of the parcel as it travels up the mountain, from 0–m to 1,000–m are;
20 °C, 25 °C, 30 °C
What is the Dry Adiabatic Lapse rate?The Dry Adiabatic Lapse Rate is the rate of change in temperature air which is unsaturated as it moves towards or away from a surface.
The given temperature of the parcel at an elevation of 0 meters = 20 °C
The Dry Adiabatic lapse Rate, DAR = (5°C/ 500–m)
The temperature, T, of the parcel at 1000–m is found as follows;
Using the DAR of 5°C/500–m, we have;
At 0–m, T = 20°CAt 500–m, T = 20°C - 500–m × (5°C/500–m) = 15°At 1000–m, T = 20°C - 1000–m × (5°C/500–m) = 10°Learn more about types of lapse rate here:
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An equation is shown below: 5(3x − 15) + 16 = 5x + 11 Part A: Write the steps you will use to solve the equation, and explain each step. (8 points) Part B: What value of x makes the equation true? (2 points)
The result of the unknown variable x is equivalent to 7
Solving linear equationsLinear equations are equation that has a leading degree of 1. Given the expression below:
5(3x − 15) + 16 = 5x + 11
Expand the expression
5(3x) - 5(15) + 16 = 5x + 11
15x - 75 + 16 = 5x + 11
15x - 5x - 59 - 11 = 0
10x - 70 = 0
10x = 70
Divide both sides by 10
10x/10 = 70/10
x = 7
Hence the value of x makes the equation true is 7
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Question 2
No calculations are necessary to answer this question.
3/01
3/02
$1.7420 $1.7360
Date
July GBP Futures
Contract Price
O long; long
Based on the closing prices of July GBP Futures Contract over the 3-day period in March 20XX as shown above, you shou
position on 3/01 and a position on 3/02.
O long; short
O short; short
3/03
short; long
$1.7390
The given information does not provide any clear indication for determining the position that should be taken on 3/01 and 3/02. Without additional information, it is not possible to make a decision. The table only displays the closing prices of the July GBP Futures Contract on different days, and it is unclear what trading strategy or what scenario is being considered. Additional information about the goals and objectives, the market conditions, and other relevant factors would be necessary to make a decision about trading positions.
Find the value of x.
|(4x - 10) (x)
Answer:
the answer is -40
Step-by-step explanation:
You want to install a 1 1 yd wide walk around a circular swimming pool. The diameter of the pool is 23 yd. What is the area of the walk? Use 3.14 for pi π.
Complete Question:
You want to install a 1 yd wide walk around a circular swimming pool. The diameter of the pool is 23 yd. What is the area of the walk? Use 3.14 for pi π.
Answer:
75.36 square yard
Step-by-step explanation:
From the question,
The diameter of this circular pool inside is 23 yd.
This means that the radius = Diameter/2 = 23yd/2 = 11.5 yd.
The formula for the area of a circle =
A = πr²
A = π(11.5)²
A =3.14 × 11.5²
A = 415.265 yd²
This is the Area of the inner circle.
We were told in the question also that he wants to install a walk of 1 yard
Hence, the radius of outer circle =
radius of inner circle +length of the walk
11.5yard + 1 yard
= 12.5 yard
A = πr²
A = 3.14 × (12.5)²
A = 490.625yd²
Area of the walk = Area of the Outer circle - Area of the inner circle
= (490.625 - 415.265)yd = 75.36 yd²
Therefore, the area of the walk is 75.36 square yards.
Mary, Margaret, Ron, and Nick are to share a scholarship. Ron receives 1/3 of the scholarship; Nick gets 1/4 of the scholarship; Mary receives the same as Nick, and Margaret receives $72,000.
Find each person's share in the scholarship as well as the original scholarship amount
Thus, Ron's share is $24,000, Nick's share is $18,000, Mary's share is $18,000, and Margaret's share is $72,000.
Let's denote the original scholarship amount as "P."
According to the given information, Margaret receives $72,000, which means the remaining scholarship amount for the other three individuals is P - $72,000.
Ron receives 1/3 of the scholarship, which can be represented as (1/3)(P - $72,000). Nick receives 1/4 of the scholarship, which can be represented as (1/4)(P - $72,000). Mary receives the same as Nick, so Mary's share is also (1/4)(P - $72,000).
Now, we can sum up all the shares to equal the original scholarship amount:
Ron's share + Nick's share + Mary's share + Margaret's share = P
(1/3)(P - $72,000) + (1/4)(P - $72,000) + (1/4)(P - $72,000) + $72,000 = P
To simplify the equation, we can combine like terms:
(P/3 - $24,000) + (P/4 - $18,000) + (P/4 - $18,000) + $72,000 = P
Combining the fractions and constants:
(4P + 3P - 3P + 12P)/12 - $24,000 - $18,000 - $18,000 + $72,000 = P
16P/12 - $48,000 = P
Multiplying both sides of the equation by 12 to eliminate the denominator:
16P - $576,000 = 12P
Subtracting 12P from both sides of the equation:
4P = $576,000
Dividing both sides of the equation by 4:
P = $144,000
Therefore, the original scholarship amount is $144,000.
Ron's share: (1/3)($144,000 - $72,000) = $24,000
Nick's share: (1/4)($144,000 - $72,000) = $18,000
Mary's share: (1/4)($144,000 - $72,000) = $18,000
Margaret's share: $72,000
Thus, Ron's share is $24,000, Nick's share is $18,000, Mary's share is $18,000, and Margaret's share is $72,000.
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Help me answer this please
The area of the sector in terms of π is 35.6π inches squared.
The area of the sector is approximately 111.6 inches square
How to find the area of a sector?The area of sector of a circle is the amount of space enclosed within the boundary of the sector.
Therefore,
area of a sector = ∅ / 360 × πr²
where
r = radius∅ = central angleTherefore,
∅ = 200 degrees
r = 8 inches
area of the sector = 200 / 360 × 8²π
area of the sector = 200 / 360 × 64π
area of the sector =12800π/ 360
area of a sector = 35.6π inches squared
Let's find the area of the sector with π = 3.14
area of a sector = 35.6 × 3.14 = 111.6 inches square
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A rancher has 200 feet of fencing to enclose two adjacent rectangular corrals. What dimensions should
be used so that the enclosed area will be a maximum?
Length is 33.33 feet and width is 25 feet are dimensions should
be used so that the enclosed area will be a maximum.
What is Area of Rectangle?The area of Rectangle is length times of width
Given that, a rancher has 200 feet of fencing to enclose two adjacent rectangular corrals of the same dimensions.
Here, the dimensions of the rectangles are the same.
The width of the two rectangles is W=2W+2W=4W
The length of the two rectangles is L=L+L+L=3L
Because the adjacent side has a common length.
3L+4W=200
3L=200-4W
Divide both sides by 3
L=(200-4W)/3
Let us form an equation using the area of rectangle formula:
A=2LW
=2(200-4W)/3.W
A=400-8W²/3
Let us differentiate to get the area to be maximized dA/dW=0
1/3×(400-8W²)=0
1/3(400-16W)=0
400-16W=0
400=16W
Divide both sides by 16
W=25
The width is 25 feet.
Substitute W value in equation to get L value:
L=200-4×25/3
=200-100/3
=100/3
=33.33
The length is 33.33 feet.
Now let us find the maximum area
A=2LW
=2×33.33×25
=1666.66
Hence, length is 33.33 feet and width is 25 feet are dimensions should
be used so that the enclosed area will be a maximum.
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I need help please pleaseeeeee
Answer:
19.64 ft
Step-by-step explanation:
7/25 = 5.5/x
7x = 137.5
x = 19.64
Are the points H and L collinear?
E
S
H
Ms. Robinson gave her class 12 minutes to read. Carrie read 5 ½ pages in that time. At what rate, in pages per hour, did Carrie read?
Answer:
27.5 pages read per hour
Step-by-step explanation:
Sean l(x) y C(x) el ingreso y costo total de una fábrica
al producir y vender x productos respectivamente,
con precio unitario de venta de S/(2x-2) y costo
unitario de S/(x+4). Si los costos fijos suman S/160,
halle el mínimo número de unidades que se debe
vender para que la fábrica obtenga utilidades.
The minimum quantity that the factory must sell in order to obtain benefits is x is 3.
What is the minimum quantity that the factory?Assuming that the unit price and unit cost are known, in addition to the fixed costs, the following formulas are proposed to determine the minimum quantity number of units that the factory must sell in order to obtain benefits: Input, cost, total cost, benefit, and utility. This example illustrates these formulas.
Unities sold = x =?
Unitary selling price = \(S.(2x-2)\)
Unit cost is \(\frac{S}{(x+4)}\)
Fixed costs = \(\frac{S}{160}\)
Assumption: I(x) = p*x= x*
\((2x-2)\)
Total cost: C(x)=\(x*(x+4)+160\)
U(x) = \(x*(2x-2)-x*(x+4)+160\)
U(x) = \(2x^{2} -2x-x(4)+160\)
U(x)= \(x^{2} -6x+160\)
derived from and equal to zero:
U'(x)= \(2x-6=0\)
x = 3.
Therefore, the minimum quantity that the factory must sell in order to obtain benefits is x is 3.
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• 10%
5) An experiment consists of spinning the spinner shown below 200 times and recording the
results in a frequency table. Based on theoretical probability, how many times would you
expect the color blue or green to be spun?
BLUE
GREEN
YELLOW
REd
Based on their given probabilities, e would expect the color blue or green to be spun approximately 75 times in this experiment.
How many times can the blue or green color be obtained?To find the expected number of times the color blue or green will be spun, we first need to add their probabilities:
0.25 + 0.125 = 0.375
This means that, on average, we would expect to see blue or green spun 0.375 times for every spin. To find the expected number of times this will happen over 200 spins, we can multiply the probability by the number of spins:
0.375 x 200 = 75
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Classify the function. y=2x^3 - 4x^2 - 160x
a party rental company has chairs and tables for rent. the total cost to rent three chairs and five tables is $52. The total cost to rent 9 chairs and 7 tables is$86. what is the cost to rent each chair and each table?
Answer:
The cost for 1 chair is $2.75 and the cost for 1 table is $8.75.
Step-by-step explanation:
Use the elimination method of linear equations to find your answer.
Our equations for this problem are:
3c+5t=52 and 9c+7t=86
Multiply the entire first equation by -3.
-3(3c+5t=52)
Simplify the equation from above:
-9c-15t=-156
Stack the two equations on top of each other and add/subtract:
-9c-15t=-156
9c+7t=86
You should be left with -8t=-70. Simplify this to find the value of t:
t=8.75
Plug the value of t into any of the original equations and solve for c.
3c+5(8.75)=52
Simplify the equation above:
3c+43.75=52
Subtract 43.75 from both sides of the equation:
3c=8.25
Divide both sides by 3 to get your c value:
c=2.75
Factor the expression completely.
63x – 9
Answer:
The answer is 9(7x – 1).
Step-by-step explanation:
63x – 9
3 × 3 × 7 × x – 3 × 3
9(7x – 1)
Thus, The answer is 9(7x – 1).
-TheUnknownScientist 72
Evaluate: 4+8÷2× (6-3)
Answer:
12/6 but if you simplify it's 2
Step-by-step explanation:
4+8 = 12
6-3 = 3
2 x 3 = 6
12/6 = 2
Determine the value of h such that the matrix is the augmented matrix of a consistent linear system.[1 h 43 6 8]
The value of h such that the matrix is the augmented matrix of a consistent linear system is 2
For the given matrix to be the augmented matrix of a consistent linear system, we need to check whether the matrix is in row echelon form or not. If the matrix is in row echelon form and the last row is not all zeros, then the linear system is consistent.
We can use elementary row operations to transform the matrix into row echelon form.
\(\left[\begin{array}{ccc}1&h&4\\3&6&8\end{array}\right]\)
R2 <- R2 - 3R1
\(\left[\begin{array}{ccc}1&h&4\\0&6-3h&-4\end{array}\right]\)
The matrix is in row echelon form. Now, we need to check whether the last row is all zeros or not.
If 6-3h = 0, then the last row will be all zeros, which implies that the linear system is inconsistent.
If 6-3h ≠ 0, then the last row will not be all zeros, which implies that the linear system is consistent.
Therefore, we need to solve the equation 6-3h = 0 to determine the value of h that makes the linear system consistent.
6-3h = 0
3h = 6
h = 2
So, the value of h that makes the matrix the augmented matrix of a consistent linear system is h = 2.
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Find the arc length of the curve on the given interval. (Round your answer to three decimal places.) Parametric Equations Interval x = 6t + 5, y = 7 − 5t −1 ≤ t ≤ 3
The arc length of the curve on the given interval is 31.241.
Explain the term Parametric Equations?Equation of this type is known as a parametric equation; it uses an independent variable known as a parameter (commonly represented by t) and dependent variables that are characterized as continuous functions of a parameter and independent of other variables.Parametric Equations
x = 6t + 5, y = 7 − 5tInterval: −1 ≤ t ≤ 3
dx/dt = d/dx(6t + 5)
dx/dt = 6
And, dy/dt = d/dt(7 − 5t )
dy/dt = -5
The arc length of curve is estimated as;
L = ∫√(dx/dt)² + (dy/dt)²).dt
L = ∫√(36 + 25t) Interval: [−1 ≤ t ≤ 3]
L = √61 x (3 + 1)
L = 31.241
Thus, the arc length of the curve on the given interval is 31.241.
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What are the relative minimum and relative maximum values over the interval [1, 5] for the function shown in the graph?
Responses
a. relative minimum = −3, relative maximum = −14
b. relative minimum = 1.5, relative maximum = 4.5
c. relative minimum = 1.5, relative maximum = −3
d. relative minimum = −14, relative maximum = −3
Answer:
d
Step-by-step explanation:
As you can tell by the graphs the relative minimum is -14 since that is where the curve ends and -3 is the maximum due to the top curve being at -3
Answer:
d) relative minimum = −14, relative maximum = −3
Step-by-step explanation:
The relative minimum and maximum values are the minimum and maximum y-values of the points in the domain of the function.
From inspection of the given graph, the minimum y-value in the interval [1, 5] is -14 and the maximum y-value in the interval [1, 5] is -3.
Therefore:
Relative minimum = -14Relative maximum = -33 to 6 = 7 to help plz.
the answer is 10
3 to 6 and 7 to 10
it adds three both times
A model rocket is launched with an initial upward velocity of 183 ft/s. The rocket's height h (in feet) after t seconds is given by the following.
h=183t-16t^2
Find all values of t for which the rocket's height is 95 feet.
Answer:
0.55 seconds and 10.89 seconds
Step-by-step explanation:
h = 183t − 16t²
95 = 183t − 16t²
16t² − 183t + 95 = 0
Solve with quadratic formula:
t = [ -(-183) ± √((-183)² − 4(16)(95)) ] / 2(16)
t = (183 ± √27409) / 32
t = (183 ± √27409) / 32
t ≈ 0.55 or 10.89
3 6 9 12 15 18 21 24 27 30 is odd or even numbers?
Answer: Half of them are even and half of them are odd.
Step-by-step explanation:
The even numbers are 6, 12, 18, 24, and 30. An even number is defined as a number that is divisible by 2, meaning it has no remainder when divided by 2. For example, 6 divided by 2 equals 3 with no remainder, so 6 is even.
The odd numbers are 3, 9, 15, 21, and 27. An odd number is defined as a number that is not divisible by 2, meaning it has a remainder of 1 when divided by 2. For example, 9 divided by 2 equals 4 with a remainder of 1, so 9 is odd.
Therefore, out of the given numbers, half of them are even and half of them are odd.
________________________________________________________
Find the measure of ∠S in △STU.