How many faces, edges and vertices does the shape below have?

Answer:

Step-by-step explanation:

To solve the given equation \(\sf x - y = 4 \\\), we can perform the following calculations:

a) To find the value of \(\sf 3(x - y) \\\):

\(\sf 3(x - y) = 3 \cdot 4 = 12 \\\)

b) To find the value of \(\sf 6x - 6y \\\):

\(\sf 6x - 6y = 6(x - y) = 6 \cdot 4 = 24 \\\)

c) To find the value of \(\sf y - x \\\):

\(\sf y - x = - (x - y) = -4 \\\)

Therefore:

a) The value of \(\sf 3(x - y) \\\) is 12.

b) The value of \(\sf 6x - 6y \\\) is 24.

c) The value of \(\sf y - x \\\) is -4.

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Answer:

Step-by-step explanation:

Here you go mate

Use PEMDAS

Parenthesis,Exponent,Multiplication,Division,Addition,Subtraction

Step 1

2(x+5)=(x-4)  Equation/Question

Step 2

2(x+5)=(x-4)  Remove parenthesis

2x+10=x-4

Step 3

2x+10=x-4  Subtract 1x from sides

x+10=-4

Step 4

x+10=-4  Subtract 10 from sides

answer

x=-14

Hope this helps

\(\text {Hi There! Let's Solve this Problem!}\)

\(\text {\underline {The First Step is to Simplify}}\)

\(\text {2*x=2x}\\\text {2*5=10}\)

\(\text {Your New Problem Is: 2x+10=x-4}\)

\(\text {\underline {The Next Step is to Subtract x}}\)

\(\text {2x+10-x=x-4-x}\)

\(\text {Your New Problem Is: x+10=-4}\)

\(\text {\underline {The Final Step is to Subtract 10}}\)

\(\text {x+10-10 (Crosses Out)}\\\text {-4-10}\)

\(\text {Your Answer Would Be:}\)

\(\Huge\boxed {x=-14}\)

\(\text {Best of Luck!}\)

To find the equation of the line of intersection of two planes, we need to find the direction vector of the line. This can be done by taking the cross product of the normal vectors of the two planes.

Let the two planes be:
P1: 2x - y + 3z = 5
P2: x + 2y - 4z = -1
The normal vectors of these planes are:
n1 = <2, -1, 3>
n2 = <1, 2, -4>
Taking the cross product of these two vectors, we get:
n1 x n2 = <14, 10, 5>
This is the direction vector of the line of intersection.
To get the vector form of the equation, we need a point on the line. We can choose any point that lies on both planes. To make it easy, we can set z = 0 in both planes and solve for x and y.
From P1:
2x - y = 5
From P2:
x + 2y = -1
Solving these equations, we get:
x = -7/5
y = -3/5
So a point on the line is (-7/5, -3/5, 0).
Using this point and the direction vector, the vector form of the equation of the line of intersection is:
r = <-7/5, -3/5, 0> + t<14, 10, 5>
Here, t represents the parameter.

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Answer:

25 Minutes

Step-by-step explanation:

Because 1000 ÷ 40 = 25

The required angle in radians is approximately 3.33 radians.

Arc is defined as a circular curve drawn, where every point on the curve is equidistant from a fixed point.

Here,

The formula to find the angle in radians given the radius and arc length is,
angle (in radians) = arc length / radius

Substitute the values given,

angle = 30m / 9m = 3.33 radians (rounded to two decimal places)

Therefore, the angle in radians is approximately 3.33 radians.

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The x = 2/5.we need to make use of the circle properties

To solve for x, we need to make use of the circle properties. Let us assume that all segments that appear to be tangent are tangent, which means that the lines are touching the circle at only one point and are perpendicular to the circle's radius. Now, let's consider the given diagram.

[asy]
size(100);
draw(circle((0,0),6));
draw((-6,0)--(6,0));
draw((0,-6)--(0,6));
draw((-3,4)--(3,-4));
draw((3,4)--(-3,-4));
draw((-6,0)--(3,-4));
draw((6,0)--(-3,4));
draw((0,0)--(3,4));
draw((0,0)--(-3,4));
draw((0,0)--(-3,-4));
draw((0,0)--(3,-4));
draw((0,0)--(6,0));
draw((0,0)--(-6,0));
[/asy]

Let P be the point of tangency of AB, AQ be the radius perpendicular to AB and O be the center of the circle. We know that, radius is perpendicular to the tangent at the point of tangency.

Therefore, ∠OQP = 90° and ∠OAQ = 90°

Therefore, ∠OQP + ∠OAQ = 180°

So, ∠OQA = 90°

In △OQA,

OA² = OQ² + AQ²

OA² = (4 + x)² + 4²

OA² = 16 + 8x + x² + 16

OA² = x² + 8x + 32

In △POB,

OB² = OP² + PB²

OB² = (6 - x)² + 2²

OB² = x² - 12x + 40

Since, OB = OA

So, OA² = OB²

x² + 8x + 32 = x² - 12x + 40

20x = 8

x = 2/5

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The coordinates of the image of ABCD after applying the given transformation are, A"(2, 0), B"(0, -4), C"(-4, -6), and D"(-2, -2).

What is transformation of points?

The reflection is the kind of transformation that takes place whenever a shape's points cross a line. When the points are reflected over a line, the image is on the opposite side of the line from the pre-image and is located at the same distance from the line. The image point is reflected from each point (p, q).

Given:

Quadrilateral ABCD has coordinates A(−2, 0), B(0, 4), C(4, 6), and D(2, 2).

First to find the coordinates after applying the transformation  

(x, y) ⟶ (–x, y).

So,

A(-2, 0) ⟶ A'(2, 0)

B(0, 4) ⟶ B'(0, 4)

C(4, 6) ⟶ C'(-4, 6)

D(2, 2) ⟶ D'(-2, 2)

Now applying the transformation (x, y) ⟶ (x, –y)

A'(2, 0) ⟶ A"(2, 0)

B'(0, 4) ⟶ B"(0, -4)

C'(-4, 6) ⟶ C"(-4, -6)

D'(-2, 2) ⟶ D"(-2, -2)

Hence, the coordinates of the image of ABCD after applying the given transformation are, A"(2, 0), B"(0, -4), C"(-4, -6), and D"(-2, -2).

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The radius of the sphere to the nearest meter is 7 meters.

To find the radius of the sphere, we can use the formula for the volume of a sphere:

V = (4/3) * π * r³

Given that the volume of the sphere is approximately 1436.03, we can rearrange the formula and solve for the radius (r):

1436.03 = (4/3) * 3.14 * r³

Dividing both sides by (4/3) * 3.14, we have:

r³ = 1436.03 / ((4/3) * 3.14)

r³ ≈ 343.12

Now, to find the radius (r), we take the cube root of both sides:

r ≈ ∛343.12

Using a calculator, we find that the cube root of 343.12 is approximately 7.03.

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Answer:

About 54.16 percent

Step-by-step explanation:

To turn a fraction into a percentage you must divide the numerator by the denominator.

Ex: 1/2 the percentage is  0.50 percent so its 50%

The ordered pair (1, 2) is a solution to the system of inequalities

x + y > 2 and

3x + 2y ≤ 6.

To find an ordered pair that is a solution to the system of inequalities:

Start with the first inequality:

x + y > 2.

Choose a value for x and y that satisfies this inequality. For example, let's choose

x = 1 and

y = 2.

Substituting these values into the inequality:

1 + 2 > 2, which is true.

Now, let's move to the second inequality:

3x + 2y ≤ 6.

Substitute the same values, x = 1 and

y = 2, into this inequality:

3(1) + 2(2) ≤ 6.

Simplifying, we have:

3 + 4 ≤ 6, which is true.

Therefore, the ordered pair (1, 2) is a solution to the given system of inequalities.

Hence the ordered pair (1, 2) is a solution to the system of inequalities

x + y > 2 and 3x + 2y ≤ 6.

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Answer: b

Step-by-step explanation: b

not completely sure but i think you times the x and y numbers then draw a graph of the units

Answer:

Step-by-step explanation:

25 *88

By filling the frequency table and performing the relevant calculations, we find that approximately 52.06% participants liked neither hamburgers nor burritos. The marginal relative frequency of those who like hamburgers was 34.92%. The category with the lowest joint frequency were those who liked hamburgers but did not like burritos, at 25.71%.

To answer the given problems, we first need to complete the data in the frequency table. From the total given which is 110 for 'Likes hamburgers' and '205' for 'Does not like hamburgers', we can fill the missing frequencies. The number of customers who 'Likes both hamburgers and burritos' is 29 and those who 'Do not like hamburgers but likes burritos' is 41. Therefore, the number of customers who 'Likes hamburgers but not burritos' = Total who likes hamburgers - those who like both = 110 - 29 = 81. Similarly, 'Those who dislike both' = Total disliking hamburgers - those disliking hamburgers but liking burritos = 205 - 41 = 164. The total number of the survey respondents is = 110 + 205 = 315.

Part A: The percentage of the survey respondents who liked neither hamburgers nor burritos is = (Those who dislike both / Total survey respondents) * 100 = (164/315) * 100 = 52.06% approx.

Part B: The marginal relative frequency of all customers who liked hamburgers is = (total who likes hamburgers / total survey respondents) * 100 = (110 / 315) * 100 = 34.92% approx.

Part C: To find the joint relative frequency, we should divide the joint frequency (i.e., the number of customers in each category) by the total number of survey respondents. Hence, the category 'Likes hamburgers but not burritos' has the lowest joint relative frequency = (81/315) * 100 = 25.71% approx.

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z_1 and z_2 are complex number;

i) z₁z₂ = 8(cos(7π/12) + isin(7π/12))

ii) z₁/z₂ = 2(cos(π/12) + isin(π/12))

To calculate z₁z₂ and z₁/z₂, we need to perform the complex number operations on z₁ and z₂. Let's break down the calculations step by step:

i) To find z₁z₂, we multiply the magnitudes and add the angles:

z₁z₂ = 4cos(cos(π/4) + isin(π/4)) * 2cos(2π/3) + isin(2π/3))

= 8cos((cos(π/4) + 2π/3) + isin((π/4) + 2π/3))

= 8cos(7π/12) + isin(7π/12)

ii) To find z₁/z₂, we divide the magnitudes and subtract the angles:

z₁/z₂ = (4cos(cos(π/4) + isin(π/4))) / (2cos(2π/3) + isin(2π/3))

= (4cos((cos(π/4) - 2π/3) + isin((π/4) - 2π/3))) / 2

= 2cos(π/12) + isin(π/12)

i) z₁z₂ = 8(cos(7π/12) + isin(7π/12))

ii) z₁/z₂ = 2(cos(π/12) + isin(π/12))

Please note that the given calculations are based on the provided complex numbers and their angles.

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The net capital gain is $19,500. To calculate the net capital gain(s) for Neil Chen, we need to consider the relevant transactions and deductions. Neil purchased a block of land with a house in 2005, rented it out until June 2018, and then demolished the house and subdivided the land into two blocks.

He constructed two new dwellings and rented them out starting from October 2019. Neil sold one of the dwellings in May 2021 and incurred selling costs. Additionally, he had capital losses from previous years. Based on these details, we can determine the net capital gain(s) by subtracting the total capital losses and selling costs from the capital gain from the sale.

To calculate the net capital gain(s), we need to consider the following components:

1. Calculate the capital gain from the sale: The capital gain is the difference between the sale price and the cost base. In this case, the sale price is $1,050,000, and the cost base includes the original purchase price ($820,000), construction costs ($450,000), and any other relevant costs associated with the property.

2. Deduct selling costs: Selling costs, such as agent commission, should be subtracted from the capital gain. In this case, the selling costs are $12,000.

3. Consider previous capital losses: Neil had capital losses from previous years totaling $31,500.

To calculate the net capital gain(s), subtract the total capital losses ($31,500) and selling costs ($12,000) from the capital gain from the sale. The resulting amount will represent the net capital gain(s) for Neil that is $19,500

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Using Normal distribution,

the minimum required iq is 126.66 for admission into organization.

Normal Probability Problem:

In this problem, we are using the z-score of a normal distribution to calculate the minimum IQ value. The z-score is used to convert a random variable into a standard normal variate with mean zero and unit variance.

we have given that,

Normal Distribution: μ = 105 , σ = 15

Normal curve equation is

Z = (X- u)/sd ~ N( 1 ; 0)

P( Z> x ) = 0.04

the value of z to the cumulative probability 0.04 from normal table is 1.7544

P((X-u)/sd > x - 105/15 ) = 0.04

=> x - 105 / 15 = 1.7544

=> x = 1.7544 × 15 + 105 = 126.66

so, the minimum iq required for admission is 126.66..

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Feasible region - the set of all possible solutions that satisfy all constraints.Binding constraint - a constraint that is met exactly at the optimal solution.Sensitivity analysis - the process of analyzing how changes in the parameters of a linear programming problem affect the optimal solution

1. Feasible region: A set of values for decision variables that satisfy all constraints in an optimization problem.
2. Binding constraint: A constraint that holds as an equality at the optimal solution, affecting the optimal value of the objective function.
3. Sensitivity analysis: A technique used to determine how different values of an independent variable affect a dependent variable under given constraints.
4. Constraint: A condition or limitation imposed on decision variables in an optimization problem.
5. Decision variables: The variables that represent the choices available to the decision-maker in an optimization problem.
6. Objective function: The mathematical expression representing the goal of an optimization problem, which is to be minimized or maximized.
7. Shadow price: The change in the objective function value due to a one-unit increase in the availability of a limited resource, holding other factors constant.

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Answer:

1- the figure doesn't provide enough information from what I'm aware of

2- x= 17.78

3- x=12

4- x=19

Step-by-step explanation:

Step-by-step explanation:

Let the number be \(\overline{abc}=100a+10b+c\).

\(100a+10b+c=34a+34b+34c \\ \\ 66a-24b-33c=0 \\ \\ 22a-8b-11c=0\)

Taking the equation mod \(11\) yields \(-8b \equiv \pmod{11}\), meaning \(b=0\).

So, \(22a-11c=0 \implies c=2a\).

So, the only possibilites are \((a,c)=(1,2), (2,4),(3,6), (4,8)\).

Therefore, there are \(4\) such numbers.

Answer:

45

Step-by-step explanation:

Answer:

Just find the time in and out every day which is every column then add then all out and you should be able to convert the minutes to hours

Step-by-step explanation:

Answer:

(-1, -10) and (-2,0) lmk if I made an error

The correct statement are:

Based on the given information, we can make the following conclusions:

A. The interquartile range for high school students is smaller than college students.

The statement is False

B. The mean for high school students is smaller than college students.

The statement is False because the mean of College is 25.28 and mean for High school is 30.4.

C. The range for high school students is larger than college students.

The statement is True .

D. The college median is equal to the high school median.

The statement is True because the median for both is 24..

E. The mean absolute deviation is larger for college students than high school students.

The statement is False.

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We know that csc(3x) = 1/sin(3x), so our expression becomes:
lim (x->0) (sin(x) * (1/sin(3x)))

Now, we rewrite this as a fraction:
lim (x->0) (sin(x) / (1/3)sin(3x))

We have the 0/0 indeterminate form, so now we can apply L'Hospital's Rule by taking the derivatives of the numerator and denominator with respect to x:
Numerator derivative: d(sin(x))/dx = cos(x)
Denominator derivative: d((1/3)sin(3x))/dx = cos(3x)

Now, we have a new limit to evaluate:
lim (x->0) (cos(x) / cos(3x))
So, the limit of the expression is:
lim (x->0) (sin(x)csc(3x)) = 1/1 = 1
Thus, the limit of the given function as x approaches 0 is 1.

To evaluate Lim Sin SxCsc 3x using L'Hospital's Rules, we need to take the derivative of both the numerator and denominator until we get a non-zero result.

Lim Sin SxCsc 3x
X-DO

Taking the derivative of the numerator:
Lim cos(Sx)Csc 3x (S)

Taking the derivative of the denominator:1

Now we can evaluate the limit:
Lim cos(Sx)Csc 3x
X-DO

As x approaches zero, the value of Sin Sx approaches zero as well. So we can substitute Sin Sx with Sx:
Lim cos(Sx)Csc 3x
X-DO
= Lim cos(Sx)/3x
X-DO

Now we can evaluate the limit using L'Hospital's Rules again:
Taking the derivative of the numerator:
-Lim sin(Sx)/3 (S)

Taking the derivative of the denominator: 3
Now we can evaluate the limit:
= -Lim sin(Sx)/9
X-DO

As x approaches zero, the value of Sin Sx approaches zero as well. So we can substitute Sin Sx with Sx again:
= -Lim sin(Sx)/9
X-DO
= -Lim Sx/9
X-DO
= 0
X-DO

Therefore, Lim Sin SxCsc 3x using L'Hospital's Rules is equal to 0.

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Answer:

999,960

Step-by-step explanation:

let x be a multiple of 120

120x ≤ 999,999

999,999 / 120 = 8333.325

8333 ≤ x ≤ 8334

8333(120) = 999,960

8334(1200) = 1,000,080  this is a 7-digit number

Therefore, the largest 6-digit number that is exactly divisible by 120 is 999,960

The probability that a student scores between 450 and 600 on the SAT math section is approximately 0.4147 or 41.47%.

To find the probability that a student scores between 450 and 600 on the SAT math section, we need to use the properties of the normal distribution. We know that the mean is 511 and the standard deviation is 110.

First, we need to standardize the values of 450 and 600 using the formula:

z = (x - μ) / σ

where x is the value we want to standardize, μ is the mean, and σ is the standard deviation.

For 450:

z = (450 - 511) / 110 = -0.55

For 600:

z = (600 - 511) / 110 = 0.81

Next, we need to find the area under the normal curve between these two standardized values. We can use a table or a calculator to find that the area between z = -0.55 and z = 0.81 is approximately 0.4147.

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Danielle viewed 7 movies on demand, thus you must divide her 35 dollars among them. So the monthly charge for Danielle's cable bill is $5.

Danielle pays a monthly charge of $69 for her cable bill.

She also pays a fee every time she watches a movie on demand.

Last month Danielle watched 7 movies on demand, and her total monthly bill was $104.

We have to find the monthly charge for Danielle's cable bill to choose.

Remove the monthly fee of 69 dollars for cable service from the total of 104 dollars, then check the statement to see that there is still a mystifying 35 dollars on it.

Danielle viewed 7 movies on demand, thus you must divide her 35 dollars among them, giving you the result of $5 per on-demand movie.

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We can clearly conclude from the passage that the correct conclusion is option C (Assumption).

What is assumption and conclusion?

An assumption is an unstated premise that supports the conclusion. Both premise and assumption are unquestionable facts but the assumption, unlike the premise, is not explicitly stated and needs to be deciphered.

A conclusion is the claim, the main point of the argument.

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Answer:

algebra = 21

Step-by-step explanation:

the answer is 21

branbliest, please

The target domain for a Poisson distribution is given the term (0, inf) which can be seen correct in option B.

A Poisson distribution's target domain is (0, inf). This means that the Poisson distribution can only be specified for non-negative integer values of the random variable it is modelling.

The Poisson distribution is a discrete probability function, which indicates that the variable may only take particular values from a finite list of integers. A Poisson distribution estimates how many times an event will occur in "x" amount of time. In other words, it is the probability distribution resulting from the Poisson experiment.

A Poisson experiment is a statistical experiment that categorises the experiment as either successful or unsuccessful. A limiting process of the binomial distribution is the Poisson distribution.

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Complete question:

What is the target domain for a Poisson distribution?

1) (-inf, inf)

2) (0, inf)

3) (-inf, 0]

4) [0, inf)