how many molecules are in 0.89 of silver

Answer:

17.1 Liters

Explanation:

It's a gas law question (more specifically a Charles's Law question). Formula is V1/T1 = V2/T2. You're given V1 and T1 and T2. However, in order to use the equation, temperature needs to be in Kelvins (by subtracting the degrees C from 273) for the numbers to work (among other reasons, the 0 degrees C will always give you an answer of zero or undefined). Placing all temps in kelvins makes the answers come out right. So 20L/273K = xL/233K gives you the answer when you cross-multiply.

Considering the Charles's law, a weather balloon calibrated at 0.00 °C to have a volume of 20.0 L has  17.07 L at -40.0 °C, assuming pressure is held constant.

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

Charles's law is one of the gas laws. It relates the volume and the temperature of a certain quantity of ideal gas, kept at a constant pressure.

This law states that, at constant pressure, the volume of a gas is directly  proportional to its temperature. In other words, for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Mathematically, Charles's law says that the quotient that exists between the volume and the temperature will always have the same value:

\(\frac{V}{T}=k\)

Being an initial state 1 and a final state 2, it is true:

\(\frac{V1}{T1}=\frac{V2}{T2}\)

In this case, you know:

Replacing:

\(\frac{20 L}{273 K}=\frac{V2}{233 K}\)

Solving:

\(V2=233 K x\frac{20 L}{273 K}\)

V2=17.07 L

Finally, a weather balloon calibrated at 0.00 °C to have a volume of 20.0 L has  17.07 L at -40.0 °C, assuming pressure is held constant.

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The density of the substance that has a mass of 4.2 grams and a volume of 6 milliliters is 0.7g/mL.

The density of a substance is a measure of the mass of matter contained by a unit volume.

The density of a substance can be calculated by dividing the mass of the substance by its volume.

According to this question, a sample of a substance has a mass of 4.2 grams and a volume of 6 milliliters. The density can be calculated thus;

Density = 4.2g ÷ 6mL

Density = 0.7g/mL

Therefore, the density of the substance that has a mass of 4.2 grams and a volume of 6 milliliters is 0.7g/mL.

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To clean powder fouling, corrosion, and dirt from outside parts of the lower receiver and extension assembly, one should use the best quality cleaning materials and methods.

Powder fouling, corrosion, and dirt can accumulate on the outside parts of the lower receiver and extension assembly, making it hard to maintain the rifle. It is essential to clean the weapon regularly to maintain its efficiency and longevity.

The following cleaning materials are required for the cleaning process:

Cleaning solvent

Cleaning brush

Microfiber cloth

Lubricant

The best solvent to use when cleaning the rifle is a powder solvent. This is because it is specifically designed to remove fouling from firearms. It is also essential to use a cleaning brush made of brass, nylon, or synthetic material to avoid damaging the parts of the lower receiver and extension assembly.

Brass brushes are best for removing fouling, while nylon and synthetic brushes are gentle on the metal parts and help prevent corrosion. Avoid using a steel brush when cleaning the rifle since it may scratch or damage the surface of the metal.Lubricant is also essential in maintaining the rifle. It helps keep the moving parts smooth and minimizes friction between metal parts.

A high-quality lubricant should be used, and the excess should be wiped off with a microfiber cloth. To clean the weapon, apply the cleaning solvent onto the brush and scrub the outside parts of the lower receiver and extension assembly, then wipe it off with a microfiber cloth. Ensure the surface of the metal parts is dry before applying lubricant. Apply lubricant to moving parts of the weapon.

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To determine the work required to exclude one atmosphere from one cubic centimeter, we can use the concept of pressure and work.

Given:

Height of mercury column (h) = 760 mm

Density of mercury (ρ) = 13.6 g/cm³

We know that pressure (P) is defined as the force (F) exerted per unit area (A), and can be expressed as P = F/A.

In this case, the pressure of one atmosphere is balanced by the height of the mercury column. Since the density of mercury is known, we can calculate the force exerted by the column of mercury using the formula F = ρgh, where g is the acceleration due to gravity (approximately 9.8 m/s²).

First, let's convert the height from millimeters to centimeters:

Height of mercury column (h) = 760 mm = 76 cm

Next, we can calculate the force exerted by the column of mercury:

Force (F) = ρgh

= (13.6 g/cm³) × (76 cm) × (9.8 m/s²) [Note: cm³ and cm cancel out]

= 10116.8 g·cm²/s²

To convert the force to joules (J), we need to multiply by the conversion factor 1 J = 10^7 ergs:

Force (F) = 10116.8 g·cm²/s² × (1 J / 10^7 erg)

= 1011.68 erg

Finally, to convert ergs to joules:

Work = Force × distance

= 1011.68 erg × (1 J / 10^7 erg)

= 0.101168 J

Therefore, the work required to exclude one atmosphere from one cubic centimeter is approximately 0.101168 joules.

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7647 grams (or 7.647 kg) of steam are required to release 3.76 × 10⁵ kJ of heat energy on condensation.

Change of the state of matter from gas phase to the liquid phase is known as condensation.

The heat of condensation of steam is the amount of heat energy released when one unit of mass of steam is condensed to liquid water at constant pressure and temperature. Heat of condensation of steam at standard conditions (1 atm pressure, 100°C temperature) is approximately 40.7 kJ/mol, or 40.7 kJ per 18.02 grams of water (the molar mass of water).

As (heat energy released) / (heat of condensation per unit mass) = (mass of steam)

(3.76 × 10⁵  kJ) / (40.7 kJ/18.02 g) = (mass of steam)

mass of steam = (3.76 × 10⁵  kJ) / (40.7 kJ/18.02 g) ≈ 7647 g

Therefore, approximately 7647 grams (or 7.647 kg) of steam are required to release 3.76 × 10⁵  kJ of heat energy on condensation.

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The rounded roughened area on each lateral edge of the mandible that is just posterior to the most distal molar is known as the mandibular tuberosity.

This area serves as an attachment site for muscles and ligaments involved in chewing and jaw movement. The maxillary tuberosity is a rounded eminence at the lower portion of the infratemporal surface of the maxilla. It became particularly noticeable after the growth of the wisdom tooth and is rough on its lateral side for articulation with the pyramidal process of the palatine bone and, in some cases, the lateral pterygoid plate of the sphenoid. A handful of the medial pterygoid muscle's fibers have their origin there.

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Allosteric site and active site are the two sites on an enzyme.

Allosteric enzymes are those that have two sites. They are the active site and the allosteric site. A unique effector or modulator can be linked to an allosteric site on an enzyme. This fastening can be reversed. Similar to how active sites relate to substrates, this site has a special connection with modulators. An enzyme's allosteric site is a location where activator or inhibitor molecules can attach to the enzyme to either activate or inhibit enzyme activity.

The areas on the surface of enzymes known as active sites are often designed by nature during the course of evolution to either catalyze a process or bind substrates. Consequently, the active site can be split into two components: the catalytic site and the substrate binding site.

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Using an excess of a reactant in a chemical reaction ensures complete reaction, increases yield, compensates for side reactions or losses, and facilitates reaction monitoring.

It's is a common practice for several reasons:

Ensuring Complete Reaction: By providing an excess of one reactant, it ensures that the other reactant is entirely consumed in the reaction. This is particularly important when the stoichiometry of the reaction requires a specific ratio between the reactants.

Having an excess ensures that the limiting reactant is not exhausted prematurely, allowing the reaction to proceed to completion.

Increasing Reaction Yield: In some cases, having an excess of a reactant can increase the overall yield of the desired product. This is especially true when the excess reactant is less expensive or easier to handle than the other reactant.

By ensuring a surplus of the cheaper or more accessible reactant, the reaction can maximize the production of the desired product.

Compensation for Side Reactions or Losses: In complex reactions, side reactions or losses can occur, leading to a decrease in the yield of the desired product.

Having an excess of one reactant can help compensate for these losses by providing an ample supply to continue the main reaction pathway.

Facilitating Reaction Monitoring: In some cases, the excess reactant can act as a reference or marker, making it easier to monitor the progress of the reaction.

By tracking the consumption of the excess reactant, it becomes simpler to determine the extent of the reaction and the reaction rate.

It's important to note that the decision to use an excess of a reactant depends on the specific reaction and its requirements. Factors such as cost, reactant availability, and desired product yield need to be carefully considered when determining the appropriate stoichiometry for a reaction.

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A chemical reaction is a process where reactants are transformed into new products.

Reactants are the initial chemicals, and products are the new chemicals that are generated. There are times when the amount of reactants utilized in a reaction is more than the amount theoretically needed. This is known as an excess of reactants. The excess of reactants can be added for various reasons.

The reasons are as follows:

1.Incomplete reaction:

When a reaction is incomplete due to a lack of sufficient amounts of reactants, the reaction does not proceed to completion.

Therefore, to guarantee that the reaction goes to completion, it is critical to use an excess of reactants.

2. Reaction Yield:

Using excess reactants increases the yield of the desired product. This means that more products are generated.

3. Catalyst:

In certain reactions, the excess of reactants serves as a solvent or diluent that keeps the catalyst in an optimal concentration, hence allowing the reaction to continue at a faster pace.

For instance, in a reaction that employs sulfuric acid as a catalyst, excess sulfuric acid will keep the reaction going at a rapid pace.

4. Error margin:

When conducting experiments, it is important to have a good margin of error. Adding an excess of reactants ensures that there are enough reactants to get the desired product. The correct amount of reactants can be determined by calculating the percentage yield.

For example, if the theoretical yield is 100 g but the actual yield is only 150 g, the percentage yield will be (150 / 100) x 100 = 150 percent.

The given terms used in the answer are:

1. 1502. Excess3. Chemical

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The magnitude of the force is approximately 5.76 × 10^-16 N.

To find the magnitude of the force exerted on the electron, we can use the formula for the magnetic force on a moving charged particle:

F = q * v * B

where F is the magnetic force, q is the charge of the electron, v is the velocity of the electron, and B is the magnetic field.

For an electron, the charge q = -1.6 × 10^-19 C. Given that the magnetic field B = 4.0 × 10^-4 T and the velocity v = 9.0 × 10^6 m/s, we can calculate the force:

F = (-1.6 × 10^-19 C) * (9.0 × 10^6 m/s) * (4.0 × 10^-4 T)

F ≈ -5.76 × 10^-16 N

Therefore, the magnitude of the force exerted on the electron is 5.76 × 10^-16 N.

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The gravity force on an object from the Earth is the same regardless of whether the object is surrounded by air .

the Earth has an average gravitational force. Different locations on Earth have gravitational forces that are larger or smaller than average. This is because each location has more or less mass than the average

Answer:

1.096g

Explanation:

You must know the atomic mass of Hydrogen, Fluorine, and Sodium before you can start:

Hydrogen: 1.008g/mol

Fluorine: 18.99g/mol

Sodium: 22.98g/mol

Next, find the composition percentage of NaF

22.98 + 18.99 = 41.97

Fluorine is 18.99/41.97 =45.25%

Sodium is 100-45.25 = 54.75%

Ultimately we want to know about HF so find how much F is in 2.3g: 2.3 * 0.4525 = 1.041g

Find comp. percentage of HF

18.99+1.008 = 19.998; H/total F/total

Hydrogen 5.041%

Fluorine 94.959%

Laws of conservation of say we have 1.041g of fluorine in our HF. We know 1.041 is 94.959% of the mass of HF so do some simple math to find the remaining: 1.041/0.94959 = 1.096g

Explanation:

According to the problem 0.2916 g of water were produced, so we have to find the number of moles of H in that sample of water. First we will convert those grams into moles using the molar mass of water.

molar mass of H = 1.01 g/mol

molar mass of O = 16.00 g/mol

molar mass of H₂O = 2 * 1.01 g/mol + 1 * 16.00 g/mol

molar mass of H₂O = 18.02 g/mol

moles of H₂O = 0.2916 g * 1 mol/(18.02 g)

moles of H₂O = 0.01618 moles

One molecule of H₂O contains two atoms of H. So 1 mol of H₂O molecules will contain 2 moles of H atoms. We can use that relationship to find the answer to our problem.

1 mol of H₂O = 2 moles of H

moles of H = 0.01618 moles of H₂O* 2 moles of H/(1 mol of H₂O)

moles of H = 0.03236 mol

Answer: 0.03236 mol of H atoms are present in the water produced.

The apparent activation energy for the light-producing chemical reaction in a firefly is 50 kJ mol-1. if you knock out the surroundings from 300 K to 270 K then the firefly will blink 9.3 slower.

Activation energy is the minimum energy required to react when molecules collide. The function of the activation energy is to break the bonds in the reactants so that new bonds will form in the reaction products. The formula equation becomes:

                          ln (k2/k1) = (Ea/R) x ((1/T1) - (1/T2))

information:

k1 = initial reaction rate constant

k2 = rate constant of the variation reaction

Ea = activation energy

R = gas constant (8.314 J/mol.K)

T1 = initial temperature

T2 = temperature variation

Given in question.

Ea = 50 Kj = 50 x 103 h

T1 = 270 K

T2 = 300 K

So:

ln (k2/k1) = (Ea/R) x ((1/T1) - (1/T2))

ln (k2/k1) = 50 x 103/8.314 x (1/270 – 1/300)

ln(k2/k1) = 2.23

   (k2/k1) = 0.11

          k2 = 0.11 k1

          k2 = 1/9.3 k1

Next will be 9.3 times slow.

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Answer: 27 electrons

copper has 29 protons in its nucleus. atoms can only lose or gain electrons. so because copper has 29 protons and will always have 29 protons, and the Cu2+ ion has a positive charge, there are more protons than electrons.

that means there should be 2 less electrons than protons. that leaves us with 29 protons and 27 electrons.

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The smallest angle, measured from the reflecting planes, at which constructive interference of an X-ray beam is observed is approximately 27.2 degrees.

To determine the smallest angle of constructive interference, we can use Bragg's Law, which states that constructive interference occurs when the path difference between two waves is equal to an integer multiple of the wavelength. The formula is given as:

2d sin(θ) = nλ

Where:

d is the distance between the reflecting planes (0.541 nm)

θ is the angle between the incident X-ray beam and the planes (the desired angle)

n is the order of the interference (we are considering the first-order, so n = 1)

λ is the wavelength of the X-ray beam (0.0649 nm)

Rearranging the formula, we get:

sin(θ) = (nλ) / (2d)

θ = arcsin((nλ) / (2d))

Plugging in the values, we have:

θ = arcsin((1 * 0.0649 nm) / (2 * 0.541 nm))

θ ≈ 27.2 degrees

Therefore, the smallest angle at which constructive interference is observed is approximately 27.2 degrees.

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The relationship between a and b in order for there to be a unique solution is that 4a - 6b should not be equal to 0.

Given linear system of equations:ax + y + z = 4-bx + y = 62y + 4z = 8 We have to find what has to be true about the relationship between a and b in order for there to be a unique solution.

Let's write the given system in matrix form. ax + y + z = 4 bx + y = 6 2y + 4z = 8  We can write the system in matrix form as follows: [a 1 1 b 1 0 0 2 4 ] [x y z] = [4 6 8]  

Let's define the coefficient matrix A and the constant matrix B as follows. A = [a 1 1 b 1 0 0 2 4 ]  B = [4 6 8]  Now, we need to check for the existence of a unique solution of the system.

For that, the determinant of the coefficient matrix should be non-zero.  det(A) ≠ 0    Therefore, we need to calculate the determinant of the matrix A. det(A) = a(1(4)-1(0)) - b(1(6)-1(0)) + 0(1(2)-4(1)) = 4a - 6b

From the above calculations, we can observe that the determinant of the coefficient matrix A will be non-zero only when 4a - 6b ≠ 0  

Hence, the relation between a and b such that there exists a unique solution is given by 4a - 6b ≠ 0.

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Answer: c

Explanation: I took it

Answer:

IT WILL HOVER IN THE MIDDLE

Explanation:

Answer:

Ytterbium is a chemical element with the symbol Yb and atomic number 70. It is the fourteenth and penultimate element in the lanthanide

If a solid sample of copper is an excellent conductor of electric current, it is likely due to the presence of metallic bonds in the sample.

Good conductors are the materials which offer very low resistance to the flow of electric current.

Solid copper is a metal, and metals have metallic bonds. Metallic bonds are a type of chemical bond that occur between atoms of metallic elements. In a metallic bond, valence electrons of the metal atoms are delocalized and shared among all the atoms in metallic solid, creating "sea" of electrons that are free to move throughout the structure.

This gives metals their unique properties such as high electrical conductivity and ductility. So, if solid sample of copper is an excellent conductor of electric current, it is likely due to the presence of metallic bonds in sample.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: A solid sample of copper is an excellent conductor of electric current . Which type of chemical bonds are in the sample?

To calculate the pH of a buffer solution containing HF and NaF, we can use the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]). The pH of the buffer solution is approximately 2.69. Therefore, the correct answer is option B.

In this case, [A-] represents the concentration of the conjugate base (NaF), and [HA] represents the concentration of the weak acid (HF). The pKa of HF is given as 6.8 × \(10^{-4}\).

First, we need to calculate the ratio of [A-]/[HA]. In this buffer, [A-] corresponds to the concentration of NaF, which is 0.2 M, and [HA] corresponds to the concentration of HF, which is 0.6 M. Therefore, [A-]/[HA] = 0.2/0.6 = 1/3.

Next, we can substitute the values into the Henderson-Hasselbalch equation: pH = pKa + log([A-]/[HA]). The pKa of HF is given as 6.8 × \(10^{-4}\).

pH = -log(6.8 × \(10^{-4}\)) + log(1/3)

= -(-3.17) + log(1/3)

= 3.17 + (-0.4771)

= 2.6929

Rounding to the correct number of significant figures, the pH of the buffer solution is approximately 2.69. Therefore, the correct answer is option B.

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Answer:

Listed below

Explanation:

COMPOUND

1. It is a pure substance.

2. It can not be separated by a physical method.

3. Element loses their properties in a compound.

4. Its composition is fixed throughout its mass.

5. It has a fixed melting point.

6.In nature they are homogeneous.

MIXTURE

1. It is an impure substance.

2. It can be separated by a physical method.

3. Substances forming mixture retain their properties.

4. It has no fixed composition.

5. It has no sharp melting point.

6. They can be homogeneous as well as heterogeneous in nature.

Answer:

hydrochloric acid

Explanation:

its hydrochloric acid

Answer:

make reclamation compulsory after bauxite has been removed

Explanation:

Available options:

choose other infertile and uninhabited locations for bauxite mining

allow agriculture and mining to take place simultaneously in the location

ask farmers in the location to help in mining bauxite

make reclamation compulsory after bauxite has been removed

The correct option and the best plan to solve the problem of permanent dislocation of farmers would be to make reclamation compulsory after the bauxite has been removed.

Reclamation would involve restoring the agricultural land back to its original status prior to the commencement of bauxite mining. By doing this, the farmers can return to their farmland after being temporarily displaced due to the mining activities.

answer is b

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Answer:

increase the rate of reaction

Answer:

decomposition

Explanation:

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Answer:

The log will float on the water because its density is lower than the liquid, so it will stay at the top due to Archimedes' principle.

Answer:

B: It will float.

Explanation:

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Approximately 280.72 grams of CO2 are emitted into the atmosphere during the grilling of the pork roast.

The energy absorbed by the roast and the energy efficiency of the barbecue.

Given:

Energy absorbed by the pork roast = 1700 kJ

Energy efficiency of the barbecue = 12% = 0.12

Since only 12% of the heat produced by the barbecue is absorbed by the roast, we can calculate the total heat produced by the barbecue using the equation:

Total heat produced = Energy absorbed / Energy efficiency

Total heat produced = 1700 kJ / 0.12

Total heat produced ≈ 14166.67 kJ

The combustion of propane, which is commonly used in barbecues, produces approximately 56 g of CO2 per mole of propane burned.

To calculate the mass of CO2 emitted, we need to convert the total heat produced to moles of propane and then determine the corresponding mass of CO2.

Calculate the moles of propane burned:

Moles of propane = Total heat produced / Heat of combustion of propane

The heat of combustion of propane is approximately 2220 kJ/mol.

Moles of propane = 14166.67 kJ / 2220 kJ/mol

Moles of propane ≈ 6.38 mol

Calculate the mass of CO2 emitted:

Mass of CO2 = Moles of propane × Molar mass of CO2

The molar mass of CO2 is approximately 44 g/mol.

Mass of CO2 = 6.38 mol × 44 g/mol

Mass of CO2 ≈ 280.72 g

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The opposite of heterotroph is autotroph.

What is heterotroph?

An organism is referred to as a heterotroph if it consumes other plants or animals for food and energy. Its origins are in the Greek words hetero, which means "other," and trophe, which means "nutrition."

Examples - Human, birds, dogs, etc.

What is autotroph?

A primary producer, also known as an autotroph, is an organism that uses energy from light or inorganic chemical reactions to create complex organic chemicals from simple ones, such as carbon dioxide.

Example - plants, algae etc.

The opposite of heterotroph is autotroph.

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The new kinetic energy per molecule at a temperature of 22 °C is approximately 6.56 x 10^-21 J.

Kave = (3/2) kT

To solve this problem, we can first convert the given temperature of 11 °C to Kelvin:

T1 = 11 °C + 273.15 = 284.15 K

Kave1 = (3/2) kT1

Next, we can calculate the new kinetic energy per molecule at a temperature of 22 °C:

T2 = 22 °C + 273.15 = 295.15 K

Kave2 = (3/2) kT2

Kave2 = (3/2) kT2 = (3/2) (1.38 x 10^-23 J/K) (295.15 K) ≈ 6.56 x 10^-21 J

A molecule is the smallest particle of a substance that retains its chemical and physical properties. It is formed by the combination of two or more atoms, which are held together by chemical bonds. Molecules can be made up of atoms of the same element or different elements, and their properties depend on the type and arrangement of atoms within the molecule.

Chemical reactions involve the breaking and forming of chemical bonds between molecules, and the study of molecules is essential in understanding chemical reactions and the behavior of matter. Molecules can be classified based on their shape, size, and chemical properties, and this classification helps in predicting their behavior under different conditions. Molecules are the building blocks of all matter, and their interactions with other molecules determine the properties and behavior of matter at the macroscopic level.

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Complete Question:

At 11 °C, the kinetic energy per molecule in a room is Kave.

A) If the temperature rises to 22 °C, what will the new kinetic energy per molecule be?