how would the gravitational force at the surface of star michael change if star michael contracted to one-sixth of its previous diameter, without losing any of its mass

Explanation:

the PE = Weight x g x Height above ground where g is the gravitational constant (9.8m/s^2)

so tge PE = 100 x 9.8 x 25 = 24500 J

The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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The two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

In the given case, the figure shows an exaggerated view of a rifle that has been sighted in for a 91.4-meter target. Let the muzzle speed of the bullet be v0 = 427 m/s.

Now, we are required to find the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target.

It is known that the horizontal displacement of the bullet from the gun can be given by the equation: x = v0 t cosθ ..........(i)and the vertical displacement of the bullet from the gun can be given by the equation: y = v0 t sinθ - (1/2) g t^2..........(ii).

Here, t is the time of flight of the bullet and g is the acceleration due to gravity.

As the bullet hits the target, its final vertical displacement from the gun is equal to the height of the target, i.e.,y = 91.4m.Now, we can substitute equations (i) and (ii) in place of t and y in equation (ii) to get:x tanθ - (g/2v0^2) x^2 sec^2θ = 91.4 ..........(iii)This is a quadratic equation in tanθ.

On solving this equation using the quadratic formula, we get:tanθ = [-b ± √(b^2 - 4ac)]/2aWhere,a = -gx^2/(2v0^2) = -4.9x^2/v0^2, b = x, and c = -91.4.

Rearranging the terms, we get:2a tanθ^2 + b tanθ - 91.4 = 0On substituting the given values, we get:2(-4.9x^2/v0^2) tanθ^2 + x tanθ - 91.4 = 0θ1 and θ2 are the two possible angles which can be found by solving the above quadratic equation.

Using the trigonometric identity given in the hint, we can write: sin 2θ = 2 sinθ cos θ = 2 tanθ/ (1 + tan^2θ)Now, we can substitute tanθ = (-b ± √(b^2 - 4ac))/2a in the above equation to get: sin 2θ = (-4bx ± 2x√(b^2 - 4ac))/(b^2 + 4a^2)Now, we can substitute the given values to get: sin 2θ1 = -0.999sin 2θ2 = 0.998.

Thus, we get two values of sin 2θ, one is close to -1 and the other is close to 1. As sin 2θ = -1 when 2θ = -π/2 + nπ and sin 2θ = 1 when 2θ = π/2 + nπ, where n is an integer, we get two possible values of θ for each of these two cases.

Hence, the two possible angles θ1 and θ2 between the rifle barrel and the horizontal such that the bullet will hit the target are given by:θ1 = (-1/2) [arctan(2a/(-b - √(b^2 - 4ac))) + π/2 + nπ] andθ2 = (-1/2) [arctan(2a/(-b + √(b^2 - 4ac))) + π/2 + nπ]where n is an integer.

As one of these angles is so large that it is never used in target shooting, we only need to consider the other angle.

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Answer:

1 -a push or a pull acting on a object.

Explanation:

force is a push or pull acting upon an object as a result of its interaction with another object.

The slope of a velocity-time graph gives the acceleration of the object.

A - The part A shows that there is no increase in the velocity of the object. That means the object is at rest.

B - In the part B of the graph, it is shown that the velocity of the object is increasing linearly. That means, the velocity is changing, thus the object has an acceleration in the positive direction.

C - In the part C of the graph, it is shown that there is no change in the velocity of the object, but it is moving with a non-zero velocity. Therefore, we can say that the object is moving with a constant speed.

D - In the part D of the graph, it is shown that the velocity of the object is decreasing linearly. That means the object is having a negative acceleration, but in the positive direction.

E - In the part E of the graph, it is shown that the velocity of the object is again increasing from zero, but in the opposite direction.

F - In the part C of the graph, it is shown that the object is moving with a constant velocity, but in the opposite direction.

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The resistance of the heater is 10.3 ohms.

The power (P) dissipated by the electric space heater is given by the formula P = V²/R, where V is the voltage across the heater and R is the resistance of the heater. In this case, the power is given as 1320 W and the voltage is given as 120 V. So we can rearrange the formula to solve for the resistance: R = V²/P. Substituting the given values, we get R = (120 V)² / 1320 W = 10.3 ohms. Therefore, the resistance of the heater is 10.3 ohm

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Answer:

true

Explanation:

hope this helps

The ball will have a constant velocity of 11 m/s.

Since there is no gravity in space, the ball is not subject to the effects of gravity.

Thus, there is no acceleration acting on the ball in space. So, there is no change in velocity with time.

Therefore, the ball will move with a constant velocity of 11 m/s in space even after travelling 7 meters.

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Answer: they could get a piece of the coral and run tests on it

Explanation:

Explanation:

Opposite side from the 41° angle = 15.24m

We wish to find the adjacent side (horizontal length)

Therefore 15.24m / tan41° = 17.53m.

Answer:

Stars that are more than 40 times more massive than our Sun, cannot expand into a red supergiant. This is because they burn too quickly and lose their outer layers fast. They will reach the blue supergiant stage, or perhaps yellow hypergiant, before returning to become hotter stars.

Explanation:

Answer:

Cause there bigger so they have a more hotter surface.

Answer:

the answer is b.

plsss pa brainliest po ako

Answer:

a. Light bulb - electrical to light

b. Firework - chemical to light / thermal / sound

c. Flute - kinetic to sound

d. Leaf-  solar to chemical

As given, the motorcyclist starts from rest and reaches a speed of 6 m/s

after traveling with uniform acceleration for 3 seconds.

Here, initial velocity u=0

Final velocity v=6 m/s

Time t=3 sec.

Let the acceleration of the motorcycle be a.

On using the equation of motion, v=u+at

6=0+3×a

Or 3a=6

Or a=63

Or a=2 m/s2

→Therefore, the acceleration in a motorcycle is 2 m/s2.←

a. Sidewalk

b. Train

c. Trees or buildings

d. Train

e. Hot air balloon

Answer:

the answer is gas if I'm not mistaken.

Explanation:

Don't come at me if I'm wrong please :')

Answer:

i think try theanswer

Explanation:

proper

Answer:

A

Explanation:

For an object to move with constant speed the forward force is opposed by the effects of forces. There is no resultant force acting or constant speed is a result of no resultant force.

Newton's second law states that an object with no net forces acting on it which is initially at rest will remain at rest. If it is moving, it will continue to move in a straight line with constant velocity. Newton's Second Law states: F = ma. F is the net force acting on an object.

Also if velocity or speed is constant the acceleration will be 0 the F=m×0

F=0.

Gravitational energy depends upon the height, mass and the gravitational strength of the object.

Gravitational energy is the potential energy held via an item due to its high function in comparison to a lower function. In different phrases, it's miles strength associated with gravity or gravitational pressure.

For the gravitational force the method is P.E. = mgh, wherein m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 on the surface of the earth) and h is the height in meters. Note that gravitational capacity electricity has the identical devices as kinetic strength, kg m2 / s2.

Newton's regulation of gravitation: This law states that every factor mass inside the universe draws every different factor mass with a pressure this is immediately proportional to the made from their masses and inversely proportional to the rectangular of the space between them.

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No, the elastic potential energy stored in the pole of a pole vaulter is not the only type of potential energy involved in pole-vaulting.

In pole-vaulting, there are multiple forms of potential energy involved. While the elastic potential energy stored in the pole plays a crucial role, other forms of potential energy include gravitational potential energy and kinetic energy.

1. Elastic Potential Energy: The pole used in pole-vaulting is typically made of flexible materials, such as fiberglass or carbon fiber, which store elastic potential energy when bent or compressed. This stored energy is then released, propelling the vaulter upwards.

2. Gravitational Potential Energy: As the vaulter reaches the highest point of their vault, they have gained gravitational potential energy due to their increased height above the ground. This potential energy is converted into other forms of energy as the vaulter descends.

3. Kinetic Energy: Throughout the vaulting process, the vaulter's body also possesses kinetic energy, which is the energy of motion. The vaulter's initial speed and subsequent acceleration contribute to their kinetic energy, allowing them to gain momentum and clear the bar.

Therefore, while the elastic potential energy stored in the pole is an important component, there are other forms of potential energy involved in pole-vaulting, namely gravitational potential energy and kinetic energy.

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Answer:

2.65m/s

Explanation:

Using the equation of motion:

v² = u²+2a∆S where

v is the final velocity

u is the initial velocity

∆S is the change in distance

a is the acceleration

Given

u = 0m/s

a = 9.8m/s²

∆S = 1.3-0.943

∆S = 0.357m

Substituting the given parameters into the formula

v² = 0²+2(9.8)(0.357)

v² = 0+6.9972

v² = 6.9972

v=√6.9972

v = 2.65m/s

Hence the velocity at which it hit the ground is 2.65m/s

Action-reaction pairs are forces that operate on separate objects in opposing directions and at identical magnitudes. Never do they affect the same thing. We learn that forces are interactions from Newton's third law.

When two bodies contact, they exert an equal and opposite force on one another in accordance with Newton's third rule of motion. Action-reaction forces are made up of these forces.

Think about how a baseball bat and a ball interact, for instance. The bat forces the ball to the right while the baseball forces the bat to the left. The action-reaction force pair is made up of these two forces acting on two separate objects together.

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Your friend must be wrong because the time-dependence of acceleration is given by the derivative of velocity with respect to time, not the time itself. The equation a(t) = yt² + yt does not represent the correct relationship between acceleration and time.

Acceleration is defined as the rate of change of velocity with respect to time. In mathematical terms, it is the derivative of velocity with respect to time, denoted as a(t) = dV/dt. Therefore, the equation a(t) = yt² + yt provided by your friend does not represent the correct relationship between acceleration and time.

To determine the correct relationship, we need to integrate the equation for acceleration to obtain the velocity function. Given that a(t) = yt² + yt, integrating both sides with respect to time gives V(t) = (1/3)yt³ + (1/2)yt² + C, where C is the constant of integration. However, this equation represents the velocity as a function of time, not the acceleration.

Your friend's equation a(t) = yt² + yt for the time-dependence of acceleration is incorrect. Acceleration is the derivative of velocity with respect to time, not a function of time itself. The correct relationship can be obtained by integrating the acceleration equation, yielding the velocity as a function of time.

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Answer:

2.7

Explanation:

V=s÷t

v=13.5÷5.0

V=2.7

The value of (1/T2 - 1/T1) can be calculated by subtracting the reciprocal of the initial temperature (T1) from the reciprocal of the final temperature (T2). The formula can be written as (1/T2) - (1/T1).

For example, if T1 is 20°C and T2 is 30°C, then (1/T2 - 1/T1) = (1/303 - 1/293) = 0.0034.
It is important to note that temperature is typically measured in Celsius (°C), Kelvin (K), or Fahrenheit (°F). The formula remains the same regardless of the unit of temperature used, but the values of T1 and T2 need to be converted accordingly. In summary, the value of (1/T2 - 1/T1) can be calculated by subtracting the reciprocal of the initial temperature from the reciprocal of the final temperature.

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Answer:

yes   1000 j   as I posted on the same Q elsewhere

Explanation:

Answer:

The Coriolus effect causes the spin in a hurricane

The center of a hurricane is called the eye

Hurricanes form over warm ocean water in the tropics

Explanation:

Answer: The Coriolus effect causes the spin in a hurricane

The center of a hurricane is called the eye

Hurricanes form over warm ocean water in the tropics

Explanation:

I got it right on edge! Plz mark brainlist love you all <3

Answer:

In nuclear power plants, energetic neutrons are directed into a sample of the isotope uranium-235. ... A common fission reaction produces barium-141 and krypton-92. In this particular reaction, one uranium nucleus breaks into a barium nucleus, a krypton nucleus, and two neutrons

2)

Explanation

Step 1

Ohm's law states that the strength of a direct current is directly proportional to the potential difference and inversely proportional to the resistance of the circuit.

so

a)

b)

Step 2

2

let

Power is equal to voltage multiplied by current.

so

also, replacing

also

I hope this helps you

Answer: D, Refraction, Reflection, Refraction.

Explanation: Refraction is a rainbow. See image for info.

The magnitude of a vector represents its direction. The phrase also refers to a quantity's mathematical or geometrical representation.

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

If no vector can be written as a linear combination of the others, a set of vectors is said to be linearly independent.

If no vector in a collection of vectors can be written as a linear combination of the ones mentioned before it, the set is said to be linearly independent.

Hence, the magnitude of a vector represents its direction.

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