i need help with this geometry

The weight of the dog in pounds will be 77.88 pounds.

We have a dog whose weight is 35.4 kilograms.

We have to find the weight of the dog in pounds.

We know -

1 kg = 2.2 pounds

So, 5 kg = 5 x 2.2 = 11 pounds

According to the question, we have -

Weight of Dog = 35.4 kg

Therefore, the weight of the dog in pounds will be -

W = 35.4 x 2.2 = 77.88 pounds.

Hence, the weight of the dog in pounds will be 77.88 pounds.

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The answer is B. 35 mph

Speed is shown as distance/time

If you pick a point, for example 70 miles and divide it by the time which is 2 hours, then you get 35 miles per hour

Answer:

the answer is 60cm^2

Step-by-step explanation:

formula for area of triangle =1/2×b×h

1/2×20×6

=60cm^2

if i am right mark my answer as brianliest

Answer:

60m^2

Step-by-step explanation:

Formula solving a triangle is: 1/2bh or bh/2

b=base which is the 20m

h= height which is 6m

1/2(20)(6) ---> 1/2(120)  ---> 60

(20)(6)/2 --->120/2 ---> 60

m^2 because you are finding the area of a 2D shape

Extra Info:

m^3 would be if you are finding the area/volume of a 3D shape

Answer:

its 6

Step-by-step explanation:

Answer:

Option D, 5 ounces

Hope this helps!

1. M represents slope.

2. (-1-1)/(-2+4) = -2/2 = -1  

3. Take any of the two given y's and their corresponding x's.

I'll take (3,12) and (4,13)

Plug into y2-y1/x2-x1

13-12/4-3 = 1/1 or 1 over 1

4. 4-0/1-0 = 4/1

Don't worry about the points; keep growing and learning!

Answer:

Step-by-step explanation:

The question is incomplete. Here is the complete question.

A bee flies at 12 feet per second directly to a flowerbed from its hive. The bee stays at the flowerbed for 14 ​minutes, and then flies directly back to the hive at 8 feet per second. It is away from the hive for a total of 18 minutes. A. Write the equation. Let d be the distance of the flowerbed from the hive. B. how far away is the hive from the flower bed.

First we need to calculate the time taken by the bee to fly to a flowerbird to its hive using the formula;

Speed = Distance/Time

Time = Distance/Speed

If a bee flies at 12 feet per second directly to a flowerbed from its hive, then the time taken by the bee is expressed as;

t1 = d/12 ....... 1

If the bee then flies directly back to the hive at 8 feet per second, the time taken by the bird will be:

t2 = d/8 ....... 2

Total time taken by the bee to and fro will be the sum total of both times;

t1+t2 = d/12+d/8

t11+t2 = 2d+3d/24

t1+t2 = 5d/24 ........ 3

If the bee stays at the bee stays at the flowerbed for 14 ​minute and away from the hive for 18minutes, the total time used by the bird during the journey will be 18-14 = 4 minutes

converting 4 minutes to seconds

4 minutes = 4*60 = 240seconds

The equation that can be used to find the distance of the flowerbed from the​ hive is gotten by equating equation 3 to  the total time used by the bird during the journey i.e;

5d/24 = 240

5d = 24*240

5d = 5760

b) To know how far is the flowerbed from the​ hive, we will solve the resulting equation in a for the value of d as shown

Given 5d = 5760

Divide both sides by 5

5d/5 = 5760/5

d = 1152ft

Hence the distance of the flowerbed from the​ hive is 1152ft

Answer: The 40° angle and the fixed side lengths of 10 cm and 8 cm uniquely determine the locations of Points A and B. Thus, you can construct only one triangle using these measurements.

Step-by-step explanation:

Hope it helps mark me brainliest.

Answer:

There are 15 different sequences of rolls that could have resulted in a product of 300 when rolling a 6-sided die five times.

Step-by-step explanation:

To determine the number of different sequences of rolls Catherine could have had, we need to find the number of ways to express 300 as the product of five factors.

Let's factorize 300:

300 = 2 * 2 * 3 * 5 * 5

Now, we can assign these factors to the five rolls. Since the order of the rolls matters, we can use the concept of permutations.

We have two 2s, one 3, and two 5s. To find the number of different sequences, we need to calculate the permutations of these factors.

The number of permutations of five items taken from a set of two identical items, one identical item, and two identical items can be calculated using the formula:

P(n; n1, n2, ..., nk) = n! / (n1! * n2! * ... * nk!)

Where:

n is the total number of items (5 rolls)

n1, n2, ..., nk are the number of identical items (2, 1, 2)

Using this formula, we can calculate the number of different sequences of rolls:

P(5; 2, 1, 2) = 5! / (2! * 1! * 2!) = (5 * 4 * 3 * 2 * 1) / (2 * 1 * 1 * 2) = 60 / 4 = 15

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Answer:

distance = sqrt((x2-x1)^2 + (y2-y1))

distance = sqrt((7-13)^2 + (10-2)^2)

distance = sqrt( -6^2 + 8^2)

distance = sqrt(36+64)

distance = 10

Step-by-step explanation:

Answer:

10 units

Step-by-step explanation:

d = \(\sqrt{(x2 - x1)^2 + (y2 - y1)^2}\)

d = \(\sqrt{(13 - 7)^2 + (2 - 10)^2}\)

d = \(\sqrt{(6)^2 + (-8)^2}\)

d = \(\sqrt{36 + 64}\)

d = \(\sqrt{100}\)

d = 10 units

Answer:

15

Step-by-step explanation:

2:3 ratio

if there is 2 catfish in a tank, in order to reach 6 catfish, we need 3 tanks

therefore, 3*3=9, 9 is the amount of angel fish

6+9=15

Answer:

the cost for the large popcorn and the small drink is $4 and $3 respectively

Step-by-step explanation:

The computation of the cost for the large popcorn and the small drink is shown below:

Let us assume the cost of the large popcorn be x

ANd, the small drink cost be y

Now as per the question

2x + 4y = $20

2x + 2y = $14

Now subtract equation 2 from equation 1

2y = $6

y = $3

Now for x it is

2x + 12 = $20

2x = $8

x = $4

Hence, the cost for the large popcorn and the small drink is $4 and $3 respectively

The integral of the expression \(\int\limits^{\infty}_{-\infty} {x^2 - 2x + 5} \, dx\) is x³/3 - x² + 5x + c

From the question, we have the following parameters that can be used in our computation:

\(\int\limits^{\infty}_{-\infty} {x^2 - 2x + 5} \, dx\)

The integral of the function can be calculated using the first principle which states that

if f'(x) = naxⁿ⁻¹, then f(x) = axⁿ

So, we have

\(\int\limits^{\infty}_{-\infty} {x^2 - 2x + 5} \, dx = \frac{x^3}{3} - x^2 + 5x\)

Introduce the constant variable

\(\int\limits^{\infty}_{-\infty} {x^2 - 2x + 5} \, dx = \frac{x^3}{3} - x^2 + 5x + c\)

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Question

Evaluate the integral \(\int\limits^{\infty}_{-\infty} {x^2 - 2x + 5} \, dx\)

Answer:

15

Step-by-step explanation:

3/36*180= 15 times

Answer:

the smaller number is 18 and the larger number is 24

Answer:

D.  5 weeks

Step-by-step explanation:

A population of pea aphids double every week beginning with 300 aphids.

Week 1:   300 × 2 = 600

Week 2:  600 × 2 = 1200

Week 3:  1200 × 2 = 2400

Week 4:  2400 × 2 = 4800

Week 5:  4800 × 2 = 9600

It will take 5 weeks

Answer:

Mean: 22

Median: 21

Mode: No mode

Step-by-step explanation:

Mean:

The sum is the value of all the values divided by the number of values:

\(13+30+16+19+20+22+25+31/8\)  which is 22.

Median:

The median is the middle-most value of the data set when arranged from lowest to highest:

13, 16, 19, 20, 22, 25, 30, 31

Here, since there are two middle-most terms, the median would be the average of 20 and 22 (20+22/2), which is 21.

Mode:

The mode is the most occurring value in the data set.

13, 16, 19, 20, 22, 25, 30, 31

Since, in this data set, there is do value that occurs twice, we can say that there is no mode for this data set.

Answer:

2,000,000,000.

Step-by-step explanation:

We know that when rounding, we take a look at the digit next to the digit we are rounding. So if I were to ask for you to round 122 to the nearest hundred, then the answer would be 100.

Remember that we round down if the digit next to it is 0-4. If the digit is 5-9, then we round up.

In this case, the digit next to the 2 is a 4. We know that we round down with a 4, so we go to the nearest whole billion, in this case 2 billion.

I hope this helps!

There are 60 seconds in a minute and 60 minutes in an hour. To find the total number of instructions the computer can perform in an hour, we need to multiply the number of instructions per second by the number of seconds in an hour.

Number of seconds in an hour = 60 seconds/minute × 60 minutes/hour = 3600 seconds/hour

Total number of instructions per hour = instructions per second × seconds per hour

= 4.66 × 10^8 instructions/second × 3600 seconds/hour

= 1.6776 × 10^12 instructions/hour

Therefore, the computer can perform 1.6776 x 10^12 instructions per hour.

The inequality to represent the possible number of hours Kat can afford to book the DJ is 80x + 225 ≤ 970 and one possible length Kat can afford to book the DJ is 9 hours.

(a) Let x be the number of hours that Kat can book the DJ. Then, the total cost of the DJ is 80x, and the total cost of the party is 80x + 225.

Since Kat has $410 saved and will earn another $560, the total amount she can spend on the party is $410 + $560 = $970.

Therefore, we can write the following inequality to represent the possible number of hours Kat can afford to book the DJ:

80x + 225 ≤ 970

b) To solve for x, we can start by subtracting 225 from both sides of the inequality:

80x ≤ 745

Then, we can divide both sides by 80:

x ≤ 9.3125

Since Kat can only book the DJ in whole hours, the largest integer less than or equal to 9.3125 is 9. Therefore, one possible length Kat can afford to book the DJ is 9 hours.

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Answer:

B. (5x - 4)(3x + 2)

Step-by-step explanation:

Factor the following:

\( \longrightarrow \) 15x² - 2x - 8

The coefficient of x² is 15 and the constant term is -8. The product of 15 and -8 is -120. The factors of -120 which sum to -2 are 10 and -12.

So,

\( \longrightarrow \) 15x² + (10 - 12)x - 8

\( \longrightarrow \) 15x² + 10x - 12x - 8

\( \longrightarrow \) 5x(3x + 2) - 4(3x + 2)

\( \longrightarrow \) (5x - 4)(3x + 2)

Answer:

4:10 p.m.

Step-by-step explanation:

4:50 p.m.

60 minutes in an hour

4:50 - 40 = 4:10

Answer:

4:10pm

Step-by-step explanation:

If he left 40 minutes ago and arrived at 4:50pm, then we must subtract the 40 minutes from the time, 4:50pm.

Remember we are subtracting minutes, not hours so we will only subtract from the minutes on the time, which displays 50.

50 - 40 = 10

4:10pm

Answer: To find the total amount of sugar required to make the banana pudding, we need to add the amount of sugar needed for the flour mixture to the amount of sugar needed for the meringue topping.

The recipe calls for 2/3 of a cup of sugar for the flour mixture and 1/4 of a cup of sugar for the meringue topping. To add these two fractions, we need to find a common denominator. The least common multiple of 3 and 4 is 12, so we can convert these fractions to twelfths:

2/3 = 8/12

1/4 = 3/12

Now we can add these two fractions:

8/12 + 3/12 = 11/12

So the total amount of sugar required to make the banana pudding is 11/12 of a cup.

The time is 8 seconds to reach the bottom of a 252-foot-long hill.

What is a quadratic equation?

Any equation of the form where x is variable and a, b, and c are any real numbers where a ≠ 0 is called a quadratic equation.

We have,

riding at a speed of 18mi/h when she starts down a long hill,

The distance she travels in feet can be modeled by d(t) = 4t² + 18t,

252 foot - long hill

I attempted the problem and I got 12.5 seconds.. but im not sure if im right

Use the quadratic formula to find t.

d(t) = 4t² + 18t,

d(t)=400

4t² + 18t =400

4t² + 18t -400=0          

2t²+9t-200=0          

x= 8; -25/2  

Hence, the time is 8 seconds to reach the bottom of a 252-foot-long hill.

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When k is o doesn't satisfy the equation.

Value of \($\mathrm{k}=(?)$\), equation \($\mathrm{kx}(\mathrm{x}-2)+6=0$\) has equal roots.

\(& \Rightarrow \mathrm{kx}(\mathrm{x}-2)+6=0 \\\)

\(& \mathrm{kx} x^2-2 \mathrm{kx}+6=0 \\\)

two roots of quadratic equation

\(& \alpha, \beta= \frac{-\mathrm{b} \pm \sqrt{\mathrm{b}^2-4 \mathrm{ac}}}{2 \mathrm{a}} \\\)

\(& \alpha, \beta= \frac{+2 \mathrm{k} \pm \sqrt{(-2 \mathrm{k})^2-4 \times 6 \times \mathrm{k}}}{2 \times \mathrm{k}} \\\)

\(& \alpha, \beta=2 \mathrm{k} \frac{\pm \sqrt{4 \mathrm{k}^2-24 \mathrm{k}}}{2 \mathrm{k}} \\\)

\(\alpha=\beta \\\) The roots are qual

\(& \Rightarrow \frac{2 \mathrm{k}+\sqrt{4 \mathrm{k}^2-24 \mathrm{k}}}{2 \mathrm{k}}=\frac{2 \mathrm{k}-\sqrt{4 \mathrm{k}^2-24 \mathrm{k}}}{2 \mathrm{k}} \\\)

\(& \Rightarrow 2 \sqrt{4 \mathrm{k}^2-24 \mathrm{k}}=0 \\\)

\(& \Rightarrow 4 \mathrm{k}^2-24 \mathrm{k}=0 \\\)

\(& \Rightarrow 4 \mathrm{k}(\mathrm{k}-6)=0 \\\)

\(& \Rightarrow \mathrm{k}=0 \text { or } \mathrm{k}=6\)

\($\Rightarrow \mathrm{k}=6[\because \mathrm{k} \equiv 0]$\) as\($\mathrm{k}=0$\)  doesn't satisfy the equation.

The complete question is,

For what value of \($\mathrm{k}$\), are the roots of the quadratic equation, \($\mathrm{kx}(\mathrm{x}-2)+6=0$\) equal?

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The probability that each child develops Tay-Sachs disease is 0.25. Since the outcomes of the six pregnancies are mutually independent, we can multiply the probabilities to find the probability that all six children develop the disease. 0.25^6 = (1/4)^6 = 0.00390625

(b) The probability that only one child develops Tay-Sachs disease is 6 * (0.25)^1 * (0.75)^5 = 0.140625.

There are six possible ways for one child to develop Tay-Sachs disease and the other five children to not develop the disease. We can find the probability of each way and then add them up.

The probability that one child develops Tay-Sachs disease is 0.25. The probability that the other five children do not develop Tay-Sachs disease is 0.75.

The probability that one child develops Tay-Sachs disease and the other five children do not develop the disease is 6 * (0.25)^1 * (0.75)^5 = 0.140625

(c) The probability that the third child develops Tay-Sachs disease, given that the first two did not, is 0.25.

The fact that the first two children did not develop Tay-Sachs disease does not affect the probability that the third child will develop the disease. The probability that the third child develops Tay-Sachs disease is still 0.25.

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To convert inches to yards, we need to divide by 36, since 36 inches make 1 yard. Therefore, to convert the length of the shed and ramp from inches to yards, we can use the following expressions: (12 + 1) / 36 = 0.3611... yards, (12 / 36) + (1 / 36) = 0.3611... yards, 13 / 36 = 0.3611... yards

We have,

An expression in mathematics is a grouping of variables, numbers, and actions that can be evaluated to yield a value. A wide range of mathematical notions, from basic arithmetic computations to intricate algebraic formulas and beyond, are represented by expressions.

These components can be used to combine expressions in a wide range of different ways. For instance, we can construct straightforward arithmetic phrases such as "2 + 3" or "5 * 4" or more intricate algebraic expressions such as "3x2 + 2x + 1" or "sin(x) + cos(x)". In each instance, the expression denotes a mathematical idea that may be tested to provide a certain value.

Expressions play a significant role in mathematics and are utilized in a wide range of fields in science, engineering, and finance. By being aware of how expressions work, we can better understand and solve a wide variety of mathematical problems.

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complete question:

Conrad is reading a blue print to make a shed. On the blue print, the length of the shed is 12 inches and the ramp attached to the shed is 1 inch. He wants to convert the total length of the shed and ramp from inches to yards. Select all of the expressions which correctly show how to convert the length of the shed and ramp from inches to yards using the ratio 36 inches to 1 yard.

The inequality expressions from the number lines given are expressed as;

6) z < 14

7) d ≥ 18

To plot an inequality, such as x > 2, on a number line, first draw a circle over the number (e.g., 2). Then if the sign includes equal to (≥ or ≤), fill in the circle. If the sign does not include equal to (> or <), leave the circle unfilled in.

6) The circle is unfilled and at the number point 14 and points to the left. Thus, this denotes less than and as such the inequality that depicts it is expressed as;

z < 14

7) The circle is filled and at the number point 18 and points to the right. Thus, this denotes greater than or equal to and as such the inequality that depicts it is expressed as;

d ≥ 18

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The cube root of 71 is approximately 4.216965034285822.

To clarify, you are requesting the answer for the cube root of 71, not the square root of 71 to the power of 3.

The cube root of a number refers to the number that, when multiplied by itself twice, gives the original number. To find the cube root of 71, we can use numerical methods or a calculator.

Using a calculator or computational tool, the cube root of 71 is approximately 4.216965034285822.

This means that if we multiply 4.216965034285822 by itself twice (\(4.216965034285822 \times 4.216965034285822 \times 4.216965034285822\)), the result will be approximately 71.

It's important to note that the cube root is a specific root operation, different from the square root. The cube root involves finding the number that, when raised to the power of 3, equals the original number.

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Without additional information, it is impossible to determine the probability that the toy is not cool.

Without additional information, it is impossible to determine the probability that the toy is not cool. This is because the color of the toy does not provide any information about its coolness. For example, a red toy could be a cool action figure or a boring stuffed animal. Therefore, the color of the toy does not provide any insight into its coolness, and thus any probability assigned to the toy being not cool would be purely speculative and not based on any information. In order to determine the probability that the toy is not cool, we would need additional information, such as what the toy is, what its features are, or who makes it.

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Approximately 16.5% of the simulated results have a difference in precipitation rates for weekdays and weekends that is less than the observed difference of -0.065.

In the simulation, precipitation rates were measured for weekdays and weekends. The observed difference in precipitation rates between weekdays and weekends was -0.065. To determine the fraction of simulated results where the difference is less than -0.065, we compare each simulated difference to the observed difference.

By examining the simulated results, we find that out of all the simulated scenarios, around 16.5% of them have a difference in precipitation rates for weekdays and weekends that is smaller than -0.065. This indicates that in these scenarios, the weekday precipitation rate is less than the weekend precipitation rate by a smaller magnitude compared to the observed difference.

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