.If n is even, then the lines of symmetry will pass through two
vertices or the
of two opposite sides.

If each shape is one whole, then the fraction greater than 1 that names the parts that are shaded is 3/4.

What is a fraction?

A fraction is a mathematical symbol that represents the ratio between two numbers. The top number is the numerator, and the bottom number is the denominator.

A fraction can represent a part of a whole or a particular amount of a quantity.

What are parts of a whole?

If an object is divided into equal parts, each part is a portion of the whole object. Each portion or piece is called a fraction of the whole object. For instance, if a cake is divided into eight equal parts, each slice is a fraction of the cake.

A unit fraction is a fraction where the numerator is 1, and the denominator is a positive integer. It represents one part of a whole that is divided into many identical parts. In the image, the square is divided into four parts, and three parts are shaded. Therefore, the fraction of the square that is shaded is 3/4.

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By using the roots and the given point, we conclude that the quadratic equation is:

y = 5*(x - 5)*(x - 9).

We know that if a quadratic has a leading coefficient a, and the roots x₁ and x₂, we can write it as:

y = a*(x - x₁)*(x - x₂).

In this case, we know that it passes through the points (5, 0) and (9, 0), then we conclude that the quadratic equation is:

y = a*(x - 5)*(x - 9).

Now, we also know that the equation passes through (7, - 20), then we have that:

-20 = a*(7 - 5)*(7 - 9)

-20 = a*(2)*(-2) = a*-4

-20/-4 = a  = 5

The quadratic equation is:

y = 5*(x - 5)*(x - 9)

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In general, different refrigerants should not be mixed or recovered into the same cylinder.

Different refrigerants have unique chemical compositions and properties that make them incompatible with one another. Mixing different refrigerants can lead to unpredictable reactions, loss of refrigerant performance, and potential safety hazards. Therefore, it is generally recommended to avoid recovering different refrigerants into the same cylinder.

When recovering refrigerants, it is important to use separate recovery cylinders or tanks for each specific refrigerant type. This ensures that the refrigerants can be properly identified, stored, and recycled or disposed of in accordance with regulations and environmental guidelines.

The refrigerant recovery process involves capturing and removing refrigerant from a system, storing it temporarily in dedicated containers, and then transferring it to a proper recovery or recycling facility. Proper identification and segregation of refrigerants during the recovery process help maintain the integrity of each refrigerant type and prevent contamination or cross-contamination.

To maintain the integrity and safety of different refrigerants, it is best practice to recover each refrigerant into separate cylinders. Mixing different refrigerants in the same cylinder can lead to complications and should be avoided. Following proper refrigerant recovery procedures and guidelines helps ensure the efficient and environmentally responsible management of refrigerants.

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The number of different refrigerants that may be recovered into the same cylinder is zero.

When it comes to refrigerants, it is important to understand that different refrigerants should not be mixed together. Each refrigerant has its own unique properties and should be handled and stored separately. mixing refrigerants can lead to chemical reactions and potential safety hazards.

The recovery process involves removing refrigerants from a system and storing them in a cylinder for proper disposal or reuse. During the recovery process, it is crucial to ensure that only one type of refrigerant is being recovered into a cylinder to avoid contamination or mixing.

Therefore, the number of different refrigerants that may be recovered into the same cylinder is zero. It is essential to keep different refrigerants separate to maintain their integrity and prevent any adverse reactions.

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Answer:

5. x = 13

6. x = 11; y = 3

Step-by-step explanation:

5. (9x + 2)° = 119° (alternate interior angles are congruent)

\( 9x + 2 = 119 \)

Subtract 2 from each side

\( 9x + 2 - 2 = 119 - 2 \)

\( 9x = 117 \)

Divide both sides by 9

\( \frac{9x}{9} = \frac{117}{9} \)

\( x = 13 \)

6. (9x + 25)° = (13x - 19)° (corresponding angles are congruent)

\( 9x + 25 = 13x - 19 \)

Collect like terms

\( 9x - 13x = - 25 - 19 \)

\( -4x = -44 \)

Divide both sides by -4

\( \frac{-4x}{-4} = \frac{-44}{-4} \)

\( x = 11 \)

(13x - 19)° + (17y + 5)° = 180° (linear pair)

\( 13x - 19 + 17y + 5 = 180 \)

Plug in the value of x and solve for y

\( 13(11) - 19 + 17y + 5 = 180 \)

\( 143 - 19 + 17y + 5 = 180 \)

Collect like terms

\( 129 + 17y = 180 \)

Subtract 129 from both sides

\( 129 + 17y - 129 = 180 - 129 \)

\( 17y = 51 \)

Divide both sides by 17

\( \frac{17y}{17} = \frac{51}{17} \)

\( y = 3 \)

After addressing the issue at hand, we can state that Hence, the sphere's linear equatiοn vοlume is rοughly 904.32 cm3.

The algebraic equatiοn y = mx + b is knοwn as a linear equatiοn. M serves as the y-intercept, and B serves as the slοpe. The previοus clause has twο variables, y and x, and is sοmetimes referred tο as a "linear equatiοn with twο variables". Bivariate linear equatiοns are thοse with twο independent variables. The fοllοwing are a few examples οf linear equatiοns: 2x - 3 = 0, 2y = 8, m + 1 = 0, x/2 = 3, x + y = 2, and 3x - y + z = 3. When an equatiοn takes the fοrm y = mx + b, with m denοting the slοpe and b denοting the y-intercept, it is referred tο as being linear. The term "linear" refers tο an equatiοn having the fοrm y=mx+b, where m stands fοr the slοpe and b fοr the y-intercept.

The fοllοwing equatiοn determines a sphere's vοlume:

V = (4/3)πR³

where R is the sphere's radius and is a cοnstant that rοughly equates tο 3.14.

R = 5.6 cm and = 3.14 are substituted intο the equatiοns tο yield:

V = (4/3) x 3.14 x (5.6)³

V = 4.19 x (5.6) x (5.6) x (5.6)³

V= 904.32 cm³ (rοunded tο twο decimal places)

Hence, the sphere's vοlume is rοughly 904.32 cm³.

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Answer:

x = 59 degree

Step-by-step explanation:

54 + 67 + x = 180 degrees

x = 180 - 54 - 67

x = 59 degrees

The solution to the question \(-7 \frac{2}{3} + (-5\frac{1}{2} ) + 8\frac{3}{4}\) is \(-4\frac{5}{12}\).

To solve this problem, we need to add up all the given numbers. To make the addition process easier, we can convert all the mixed numbers into improper fractions first.

\(-7\frac{2}{3}\) =\(-(\frac{21+2}{3} )\)= \(-\frac{23}{3}\)

\(-5\frac{1}{2}\) = \(-(\frac{10+1}{2} )\)= \(-\frac{11}{2}\)

\(8\frac{3}{4}\) = \(\frac{32+3}{4}\) = \(\frac{35}{4}\)

Now we can add up the three fractions:

\(-\frac{23}{3}+ -\frac{11}{2}+\frac{35}{4}\)

We must choose a common denominator so that we can sum up these fractions. The smallest common multiple of 3, 2, and 4 is 12.

Therefore,

\(\frac{(-23*4)+(-11*6)+(35*3)}{12}\)

\(\frac{-92-66+105}{12} \\\frac{-53}{12}\)

Therefore, the solution is \(\frac{-53}{12}\). We can also convert this back into a mixed number if required:

\(\frac{-53}{12}\) = \(-\frac{(4*8+5)}{12}\) =\(-4\frac{5}{12}\).

So the final answer is \(-4\frac{5}{12}\).

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Answer:

The image does not have four right angles because translations preserve angle measures.

Answer: so if Zhi earns $16.54 / h. H = Hour

and he works 34 hours per week we can do the math

16.54x34h = 562.36

Rounded to the nearest 5 cents is = 562.35

there's your answer!

There are 30 cubic feet of water in the pipe at time t = 0. 76.570 cubic feet of rainwater flow into the pipe during the 8-hour time interval 0 ≤ t ≤ 8.

\(\int\limits^8_0\)   [R(t) dt = \(\int\limits^8_0\) 20 sin \(\frac{t^2}{35}\) dt = 76.570

What Is Time Interval?

The amount of time between two given times is known as time interval. In other words, it is the amount of time that has passed between the beginning and end of the event. It is also known as elapsed time.

INTERVAL types are divided into two classes: year-month intervals and day-time intervals. A year-month interval can represent a span of years and months, and a day-time interval can represent a span of days, hours, minutes, seconds, and fractions of a second.

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Answer:

First Graph: h(x) = 0.5x^2

Second Graph: f(x) = -2x^2

Third Graph: j(x) = 2x^2

Fourth Graph: g(x) = -x^2

Step-by-step explanation:

First Graph and the Third Graph both open upwards thus we know the coefficient will be positive. Using the point (2,2) as a guide on the first graph, we can see that the best option to fit the first graph would be \(h(x) = 0.5x^2\) as \(h(2) = 0.5 (2)^2 = 0.5(4) = 2\). From process of elimination, we can see that the third graph will be \(j(x) = 2x^2\). Another way to determine this is by looking at the shape of the curves. The first graph opens "wider" thus meaning the coefficient will be smaller.

Second Graph and the Fourth Graph both open downwards thus we know the coefficient will be negative. We only have the options of \(f(x) = -2x^2\) and \(g(x) = -x^2\). We can see that the fourth graph opens "wider" so the coefficient will be smaller thus second graph will be f(x) = -2x^2  and the fourth graph will be g(x) = -x^2. Another way to determine this is by checking a point on a graph. On the fourth graph, there is the point (-2,4). This matches with the equation as \(g(-2) = -x^2 = -(-2)^2 = -4\).

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The value of the expression is A = 6xy

Equations are statements in mathematics that have two algebraic expressions on either side of the equals (=) sign.

It displays the similarity of the connections between the phrases on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are examples of the parts of an equation. When creating an equation, the "=" symbol and terms on both sides are necessary.

Given data ,

Let the expression be represented as A

Now , the value of A is

A = 2 ( x ) ( 3 ) ( y )

On simplifying the equation , we get

A = ( 2 ) (3 ) ( xy )

A = 6xy

Therefore , the value of A is 6xy

Hence , the expression is A = 6xy

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a) The annual demand is 420.

b) The weekly demand forecast is 8.08

c) The EOQ would be approximately 41

d) The reorder point is 45.12

e) The total annual cost is 102439.02

f) The pipeline inventory is 32.32

g) The new reorder point is 48.82

a) To calculate the annual demand, you need to use your student number. For example, if your student number is BBAW190102, the last digit is 2. So, the annual demand would be 400 + 10 x 2 = 420.

b) To calculate the weekly demand forecast for 2021, you need to divide the annual demand by the number of weeks in a year. Assuming there are 52 weeks in a year, the weekly demand forecast would be 420 / 52 = 8.08 (rounded to two decimal places).

c) The economic order quantity (EOQ) can be calculated using the formula EOQ = sqrt((2DS) / H), where D is the annual demand, S is the ordering cost per order, and H is the annual holding cost. In this case, D is the annual demand calculated in part a, S is $1000, and H is $500. Plugging in these values, the EOQ would be sqrt((2 x 420 x 1000) / 500) = sqrt(840000 / 500) = sqrt(1680) ≈ 41 (rounded to the nearest whole number).

d) The reorder point is the level of inventory at which a new order should be placed. It can be calculated using the formula reorder point = demand during lead time + safety stock. The demand during lead time is the average demand per week multiplied by the lead time, which is 8.08 x 4 = 32.32 (rounded to two decimal places). The safety stock is the z-score multiplied by the standard deviation of weekly demand. The z-score for a 90% cycle service level is 1.28 (given in the question) and the standard deviation of weekly demand is 10 (given in the question). So, the safety stock would be 1.28 x 10 = 12.8 (rounded to one decimal place). Therefore, the reorder point would be 32.32 + 12.8 = 45.12 (rounded to two decimal places).

e) The total annual cost of managing the inventory can be calculated using the formula TC = (S x D/Q) + (H x (Q/2 + s)), where S is the ordering cost per order, D is the annual demand, Q is the economic order quantity, H is the annual holding cost, and s is the safety stock. Plugging in the values, the total annual cost would be (1000 x 420/41) + (500 x (41/2 + 12.8)) = 102439.02 (rounded to two decimal places).

f) The pipeline inventory refers to the inventory that is in transit or being processed. In this case, since the lead time is 4 weeks, the pipeline inventory would be the average demand per week multiplied by the lead time. So, the pipeline inventory would be 8.08 x 4 = 32.32 (rounded to two decimal places).

g) To achieve a 95% cycle service level, we need to calculate the new safety stock and reorder point. The z-score for a 95% cycle service level is 1.65 (given in the question). Using the same formula as in part d, the new safety stock would be 1.65 x 10 = 16.5 (rounded to one decimal place). Therefore, the new reorder point would be 32.32 + 16.5 = 48.82 (rounded to two decimal places).

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The required cost of the books is given as $42 and $34.

The equation model has defined as the model of the given situation in the form of an equation using variables and constants.

Here,
Let the cost of the one book be x, y of the other book,
according to the question,
The total cost of the books is $76 so,
x + y = 76 - - - (1)

The difference in the cost of the two books is $8,
x - y = 8 - - - (2)

Adding equations 1 and 2
2x = 84
x = 42

Now, from equation 1
42 + y = 76
y = 34

Thus, the cost of books is $42 and $34.

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Answer:

y=-2/3x-2

Step-by-step explanation:

slope= -2/3

y=-2/3x+b  

enter the given points  

2=4+b  

b=-2  

y=-2/3x-2

hope this helps

Answer:

7+2g

Step-by-step explanation:

7 increased by means 7 +

twice Gali's height =2g

everything now becomes 7+2g

Answer:

Choice C

Step-by-step explanation:

need:

a = 7

b = -5

c = -2

A) 7x^2 - 5x - 1

B)  7x^2 - 5x - 14

C)  7x^2 - 5x - 2

D) 7x^2 - 5x + 2

Answer:1884.35

Step-by-step explanation: it’s just 223% of 845. Might not be what ur looking for but I dk

845 - 223 = 622

622 / 845 = 73.6/100

73.6% are non freshman

please give brainliest

Answer:

No

Step-by-step explanation:

Ratios are the same as percentages or fractions. In this case there are 35 red beads for every 42 green beads on the bracelet. This means the ratio would be \(\frac{35}{42}\) , which when put divided is 0.833 or 83.3%. Kaleb is stating that the ratio is 5:7 which would basically be \(\frac{5}{7}\) which when divided is 0.71 or 71%. Therefore, since these percentages are different we can go ahead and say that Kaleb is not correct.

Answer:4/5

Step-by-step explanation:

False.

Replace x with 0 and solve:

2(0) + 3 = 0+ 3 = 3

3 is not greater than 13 so the answer is false.

Answer:

is equls to 100 Brainliest 6

Answer:

2: 125

4: 55

7: 125

3: 125

Step-by-step explanation:

Since the top and bottom lines are parallel, 2 is equal to 6.

since angles 4+2 sums up to a straight line, its 180 degrees

125+55 is 180

same with 3, 3+4 is 180

7 is same as 3

The dimensions of the vector space Au are 3x3 and the matrix Al with respect to the bases of PA and P2 consisting of powers of t is as follows\(:$$\begin{bmatrix}2&4t+6&5t^2+8t+6\\0&1&4t+1\\0&0&7\end{bmatrix}$$\)

Let Aj be the matrix of the linear transformation L: PA + P2 in  The dimensions of the vector space Au are 3x3. The matrix of the linear transformation L is given as below:\($$L(P) = A \cdot P + P \cdot B$$Where, $A=\begin{bmatrix}2&0&6\\6&1&4\\-1&-3&-2\end{bmatrix}$, $B=\begin{bmatrix}0&4&5\\8&4&4\\10&1&7\\7&-7&5\\3&1&11\\5&1&0\end{bmatrix}$,\)\($P=\begin{bmatrix}x_{11}&x_{12}&x_{13}\\x_{21}&x_{22}&x_{23}\\x_{31}&x_{32}&x_{33}\end{bmatrix}$\)And \($PA$\) is the product of \($A$ and $P$\). Similarly, $PB$ is the product of $P$ and $B$. Now we need to find the matrix of the linear transformation L with respect to the bases of $PA$ and $PB$ consisting of powers of t.To do this, let $p_1 = \(\begin{bmatrix}1&0&0\\0&0&0\\0&0&0\end{bmatrix}$, $p_2 = \begin{bmatrix}0&1&0\\0&0&0\\0&0&0\end{bmatrix}$, $p_3 = \begin{bmatrix}0&0&1\\0&0&0\\0&0&0\end{bmatrix}$, $p_4 = \begin{bmatrix}0&0&0\\1&0&0\\0&0&0\end{bmatrix}$, $p_5 = \begin{bmatrix}0&0&0\\0&1&0\\0&0&0\end{bmatrix}$, and $p_6 = \begin{bmatrix}0&0&0\\0&0&1\\0&0&0\end{bmatrix}$.\)Then we get $PA = a_1p_1 + a_2p_2 + a_3p_3$ and $PB = b_1p_4 + b_2p_5 + b_3p_6$.Finally, we have $L(P) = A \cdot P + P \cdot B$ in which A and B are already given.

Hence, we need to find the $6 \times 6$ matrix of the linear transformation L with respect to the bases $PA$ and $PB$ consisting of powers of t and it is as follows:\($$L_{B_{(PA, PB)}}=\begin{bmatrix}2&4t+6&5t^2+8t+6&6&4t-1&10t-2\\0&1&4t+1&0&7t+5&3t-3\\0&0&7&0&1&5t+1\\0&0&0&-2&-7t+3&4t+11\\0&0&0&0&4&1\\0&0&0&0&0&7\end{bmatrix}$$\)Hence, the dimensions of the vector space Au are 3x3 and the matrix Al with respect to the bases of PA and P2 consisting of powers of t is as follows:\($$\begin{bmatrix}2&4t+6&5t^2+8t+6\\0&1&4t+1\\0&0&7\end{bmatrix}$$.\)

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Answer:

C. Use a compass to draw one arc with point M at the center and intersecting point N.

Step-by-step explanation:

I took the test and got it right.

Your welcome :)

Using a compass, draw one arc with point M at the center and point N intersecting it as the first step in the typical construction of the perpendicular bisector of MN. Option C is correct.

Lines that cut through the middle of each side of a triangle and are perpendicular to the specified side are known as the perpendicular bisectors of the triangle.

The standard construction of the perpendicular bisector of MN will be,

Step 1: Sketch a line segment with any appropriate length, XY.

Step 2: Using a compass, draw arcs above and below the line segment, with X serving as the center and XY's width greater than 50%.

Step 3: Carry out Step 2 but use Y as the center. Step 4: Write "P" and "Q" next to the junction points.

Thus, using a compass, draw one arc with point M at the center and point N intersecting it as the first step in the typical construction of the perpendicular bisector of MN. Option C is correct.

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The conditional expectation E(X | Y = y) for all y is:

E(X | Y = y) = (y + 1) / 2.

To find the conditional expectation E(X | Y = y), we need to calculate the expected value of X given that the sum of the two dice is y.

Let's consider all possible values of y from 2 to 12 (the possible sums of rolling two dice):

For y = 2:

The only possible combination is (1, 1). In this case, X can only take the value 1. Therefore, E(X | Y = 2) = 1.

For y = 3:

The possible combinations are (1, 2) and (2, 1). In both cases, the value of X is 1. Therefore, E(X | Y = 3) = 1.

For y = 4:

The possible combinations are (1, 3), (2, 2), and (3, 1). In these cases, the value of X can be 1, 2, or 3. Taking the average, we have E(X | Y = 4) = (1 + 2 + 3) / 3 = 2.

Similarly, we can calculate the conditional expectations for y = 5, 6, 7, 8, 9, 10, 11, and 12:

For y = 5: E(X | Y = 5) = (1 + 2 + 3 + 4) / 4 = 2.5

For y = 6: E(X | Y = 6) = (1 + 2 + 3 + 4 + 5) / 5 = 3

For y = 7: E(X | Y = 7) = (1 + 2 + 3 + 4 + 5 + 6) / 6 = 3.5

For y = 8: E(X | Y = 8) = (2 + 3 + 4 + 5 + 6) / 5 = 4

For y = 9: E(X | Y = 9) = (3 + 4 + 5 + 6) / 4 = 4.5

For y = 10: E(X | Y = 10) = (4 + 5 + 6) / 3 = 5

For y = 11: E(X | Y = 11) = (5 + 6) / 2 = 5.5

For y = 12: E(X | Y = 12) = 6

In summary, the conditional expectation E(X | Y = y) for all y is given by:

E(X | Y = 2) = 1

E(X | Y = 3) = 1

E(X | Y = 4) = 2

E(X | Y = 5) = 2.5

E(X | Y = 6) = 3

E(X | Y = 7) = 3.5

E(X | Y = 8) = 4

E(X | Y = 9) = 4.5

E(X | Y = 10) = 5

E(X | Y = 11) = 5.5

E(X | Y = 12) = 6

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Equation BEST represents Javier’s data is y=3.25x

An equation typically contains one or more variables, which are quantities that can take different values, and it represents a relationship between these variables.

An equation expression is usually written in the form of an expression on one side of an equals sign, and another expression on the other side. For example, the equation 2x + 3 = 7 represents the relationship between the variable x and the constant value 2, where the left-hand side of the equation is equal to the right-hand side when x is equal to 2.

Equations can be classified into several types, such as:

Linear equations: equations that involve only first-degree variables, such as ax + b = c.

Quadratic equations: equations that involve second-degree variables, such as ax^2 + bx + c = 0.

Polynomial equations: equations that involve higher degree variables, such as ax^3 + bx^2 + cx + d = 0.

Rational equations: equations that involve fractions, such as (x+1)/(x-1) = 2.

Equations are commonly used in various fields, such as physics, engineering, and finance, to model and solve problems. They provide a powerful tool for representing and analyzing relationships between variables and for making predictions based on mathematical models.

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If multiplying 2 negative integers then it's a positive

If multiplying 2 positive integers it's positive

Answer: I hope this is helpful

Step-by-step explanation:

The proceeding pattern is summarized in the following rule for multiplying integers. Rule for Multiplying Two Integers: TO MULTIPLY INTEGERS WITH THE SAME SIGN, multiply the absolute value of the factors. The product is positive.

Jeff's golf score was 1 stroke under par.

Let's first find out what was Mike's golf score.

We know that Mike's score was 2 strokes more than Sam's score, so if Sam's score was 2 over par, then Mike's score must have been:

2 + 2 = 4 over par

We also know that Jeff's score was 5 strokes less than Mike's score. Therefore, Jeff's score relative to par would be:

4 + (-5) = -1 over par

So Jeff's golf score was 1 stroke under par.

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Answer:

Look at image

Step-by-step explanation:

Look at image

Look at image