To have an average speed of 4mph, you should run the next 0.5 hour at a speed of 7mph.
To find the average speed, you need to use the formula:
average speed = total distance / total time
First, find the total distance you traveled during the 1.5 hours of walking:
distance = speed × time
distance = 4mph × 2 hours
distance = 8 miles
Subtract the distance you traveled during the 1.5 hours of walking from the total distance to find the distance you need to travel during the 0.5 hours of running:
8 miles - 4.5 miles = 3.5 miles
Finally, use the formula for distance to find the speed you need to run:
distance = speed × time
3.5 miles = speed × 0.5 hours
speed = 7mph
Therefore, you need to run at a speed of 7mph for 0.5 hours to have an average speed of 4mph.
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Find the area of the irregular figure. I don’t know this I need help.
Answer:
11 in.²
Step-by-step explanation:
you can divide the shape into 2 rectangles and then you solve for the 2 rectangles and then you add them up.
suppose that the population of all north american domesticated cats have a mean weight of 12 pounds and standard deviation of 2.5 pounds. the frequency distribution of north american domesticated cat weights is approximately normal. about 95% of the mean weights from samples of size 100 cats from this population fall between what two values (note: assume the sampling distribution of sample means is approximately normal)?
Answer. The correct option is (E). 9.5 and 14.5
Explanation for step 1This is because 95% of the mean weights from samples of size 100 cats from this population will fall between 9.5 and 14.5 pounds. The other answers are incorrect because they do not fall within the range of 95% of the mean weights from samples of size 100 cats from this population
About 95% of the mean weights from samples of size 100 cats from this population would fall between approximately 11.51 pounds and 12.49 pounds.
To determine the range within which 95% of the mean weights from samples of size 100 cats would fall, we can use the concept of the confidence interval.
Given:
Population mean weight (μ) = 12 pounds
Population standard deviation (σ) = 2.5 pounds
Sample size (n) = 100 cats
Since the population distribution is assumed to be approximately normal, the sampling distribution of sample means will also be approximately normal. To calculate the range, we can use the formula for the confidence interval:
Confidence Interval = sample mean ± (z * standard error)
The standard error can be calculated using the formula:
Standard Error = σ / √n
Using a 95% confidence level, the corresponding z-value is approximately 1.96 (obtained from standard normal distribution table).
Plugging in the values:
Standard Error = 2.5 / √100 = 0.25
Confidence Interval = 12 ± (1.96 * 0.25)
Calculating the values:
Lower limit = 12 - (1.96 * 0.25) ≈ 11.51 pounds
Upper limit = 12 + (1.96 * 0.25) ≈ 12.49 pounds
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Gustavo ha forrado una pared de 12,5 m cuadrados con 50 paneles cuadrados iguales de madera ¿ Cuantos decímetros cuadrados mide cada papel?
Answer:
25 dm²
Step-by-step explanation:
La superficie de nuestra pared tiene 12.5 m²
Si dividimos la superficie por la cantidad de paneles cuadrados, obtenemos la superficie de cada panel
12.5 m² /50 = 0.25 m²
Sabemos que la superficie de un cuadrado se calcula como l²
Convertimos los 0.25 m² a dm² → 0.25 m² . 100 dm² / 1m² = 25 dm²
Esa es la medida de cada papel.
Si calculamos la medida de cada lado será:
√ (25 dm²) = 5 dm
En conclusión un cuadrado con 5 dm de lado tiene 25dm² de superficie
Si convertimos a m² = 0.25 m²
0.25 m² es la medida que cubre 1 panel de papel
para cubrir 12.5 m² necesitariamos (12.5 . 1) /0.25 = 50 paneles.
ASAPPPPPPPPPPPPPPPPPPPPPPPPP HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
Answer:
s+s+s and 3s
Step-by-step explanation:
imagine S as a number. lets say s is 1. they boyght 3 starts so it has to be 3. Option 1 and 3 has a sum of 3. Option 2 has the tital of 1 because 1³=1 and option 4 is 4.
The real roots for the equation x4 – x3 10x2 – 16x – 96 = 0 are –2 and 3. what are the nonreal solutions? –i, i –2i, 2i –4i, 4i –16i, 16i
The Non-real solutions for the equation \(x^{4} -x^{3}+10x^{2} -16x-96=0\) are (-4i, 4i).
Non-real solution:
An answer to a mathematical equation with the root of a negative number that cannot be determined using solely real numbers—i.e., numbers that can be described along a single axis—is referred to as a non-real solution.
If a quadratic has a negative discriminant, then the quadratic equation has a Non-real solution.
Given,
\(x^{4} -x^{3}+10x^{2} -16x-96=0\)
On factorizing the above equation, we get
\((x-3)(x-2)(x^{2} +16)=0\)
Applying Zero Product Property,
\(x^{2} +16 = 0\) or \(x-3=0\) 0r \(x+2=0\)
Taking \(x^{2} +16 = 0\), we get
\(x^{2} =-16\)
x = ± \(\sqrt{-16}\)
x = ± 4i [∵ i = √-1]
Hence,
The Non-real solutions for the equation \(x^{4} -x^{3}+10x^{2} -16x-96=0\) are (-4i, 4i).
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Answer:
C
Step-by-step explanation:
edge 2026
Write and solve the equation:
a number is less than one fourth the sum of three times the number and four.
Answer:
The number is less than 4.
Explanation:
If we write the inequality out, we get this:
x<14(3x+4)
Now we just need to solve for x. Multiplying both sides by 4 yields:
4x<3x+4
Subtract 3x from both sides:
x<4
So any number less than 4 will work!
Amy and Rob each improved their yards by planting rose bushes and shrubs. They bought their
supplies from the same store. Amy spent $43 on 1 rose bush and 11 shrubs. Rob spent $68 on 5
rose bushes and 6 shrubs. Find the cost of one rose bush and the cost of one shrub.
Answer: a rose bush is 10 dollars while a shrub is 3
Step-by-step explanation:
5x10 is 50
6x3 is 18
__________ +
68
10
11x3=33
________+
43
in the regression line y = a+ bx + e, a is the slope of the regression line.
In the regression line y = a+ bx+ e, a is the slope of the regression line.
The above statement is False.
The correct Statement is :
The linear regression line has an equation of the form Y =a + bX
where, Y is called the dependent variable or response.
X means independent or predictor or explanatory variable.
a is the y-intercept and b is the slope of the line.
Regression Line:
A regression line is a statistical tool that shows the correlation between two variables. Specifically, it is used when the variation of one (the dependent variable) depends on changes in the value of the other (the independent variable).
Simple linear regression has two cases:
The equation is Y on X, and the value of Y changes as the value of X changes. The formula is X over Y, and the change in X varies with the deviation of the Y variable.The formula for the least squares regression line (LSRL) from Y to X is:
Y=a + bX + ɛ
where,
Y is the dependent variable.
a is the Y intersection.
b is the slope of the regression line.
X is the independent variable.
ɛ is the residual (error).
and
b = (N∑XY-(∑X)(∑Y) / (N∑X2– (∑X)2) ;
and
a = (∑Y – b ∑X) / N
where, N is the total number of observations.
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Use the long division method to find the result when 3x³ +19x² + 23x + 15 is
divided by 25.
The result by using long division method for the given polynomial equation is: 25[(1/3x³) +(1/19x²) + (1/23x) + (1/15)]
What is long division method?
In mathematics, the long division method can be performed on the polynomial equations. Basically, in this big equation can be solved by making smaller group of equations to make the calculation simple. It divide the dividend with divisor.
According to the question, the given polynomial equation is 3x³ +19x² + 23x + 15. Using long division method, divide it by 25
Therefore, the expression can be written as:
Required expression: \(\frac{3x^{3} +19x^{2} + 23x + 15 }{25}\)
Dividing it by 25, we get:
(25/3x³) +(25/19x²) + (25/23x) + (25/15)
⇒ 25[(1/3x³) +(1/19x²) + (1/23x) + (1/15)]
Hence, the result by using long division method for the given polynomial equation is: 25[(1/3x³) +(1/19x²) + (1/23x) + (1/15)]
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"Suppose X --> N(20,5)
(a) Find: (i) P(X> 18)
(ii) P(7 < X < 15)
(b) Find the value a such that P(20-a < X < 20+ a) = 0.99
(c) Find the value b such that P(20-b< X < 20+ b) = 0.95
a) i)P(X > 18)= 0.65542
ii)P(7 < X < 15)=0.154
b)The value of a using the standard normal table or a calculator is 12.875
c)the value of b using the standard normal table or a calculator is 9.8
a) Let X be the normal random variable with mean μ = 20 and standard deviation σ = 5. We have to find P(X > 18) and P(7 < X < 15).
(i) P(X > 18)
This can be calculated using the standard normal table or a calculator as follows:
z = (18 - μ)/σ
= (18 - 20)/5
= -0.4
P(X > 18) = P(Z > -0.4)
= 1 - P(Z ≤ -0.4).
Using the standard normal table or a calculator, P(Z ≤ -0.4) = 0.34458
Therefore, P(X > 18) = 1 - 0.34458 = 0.65542
(ii) P(7 < X < 15). This can be calculated using the standard normal table or a calculator as follows:
z₁ = (7 - μ)/σ
(7 - 20)/5 = -2.6z₂
(15 - μ)/σ = (15 - 20)/5
= -1
P(7 < X < 15) = P(-2.6 < Z < -1)
= P(Z < -1) - P(Z < -2.6)
Using the standard normal table or a calculator,
P(Z < -1) = 0.15866P(Z < -2.6) = 0.00466
Therefore, P(7 < X < 15) = 0.15866 - 0.00466 = 0.154
b) We have to find the value of a such that
P(20 - a < X < 20 + a) = 0.99.
This can be calculated as follows:
z₁ = (20 - a - μ)/σ
= (20 - a - 20)/5
= -a/5z₂ = (20 + a - μ)/σ
= (20 + a - 20)/5 = a/5
We need to find a such that
P(z₁ < Z < z₂) = 0.99
Using the standard normal table or a calculator,
P(Z < z₂) - P(Z < z₁) = 0.99P(Z < a/5) - P(Z < -a/5) = 0.99
This can be rewritten as
P(Z < a/5) - [1 - P(Z < a/5)] = 0.99P(Z < a/5) - P(Z < -a/5) = 0.995
From the standard normal table or a calculator,
P(Z < 2.575) = 0.995P(Z < -2.575) = 0.005
Therefore,
2.575 = a/5 or -2.575 = -a/5a = 12.875
Therefore, the value of a is 12.875.
c) We have to find the value of b such that P(20 - b < X < 20 + b) = 0.95.
This can be calculated as follows:
z₁ = (20 - b - μ)/σ
= (20 - b - 20)/5
= -b/5z₂
= (20 + b - μ)/σ
= (20 + b - 20)/5 = b/5
We need to find b such that
P(z₁ < Z < z₂) = 0.95
Using the standard normal table or a calculator,
P(Z < z₂) - P(Z < z₁) = 0.95P(Z < b/5) - P(Z < -b/5) = 0.95
This can be rewritten as
P(Z < b/5) - [1 - P(Z < b/5)] = 0.95P(Z < b/5) - P(Z < -b/5) = 0.975
From the standard normal table or a calculator,
P(Z < 1.96) = 0.975P(Z < -1.96) = 0.025
Therefore,1.96 = b/5 or -1.96 = -b/5b = 9.8
Therefore, the value of b is 9.8.
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A national park reports that it had 2,382,476 visitors last year. What is the value of the digit 8 in 2,382,476?
Answer:
80,000
Step-by-step explanation:
the 8 in 2,382,476 is in the ten thousands place (it's simple math once you understand it)
randomization in an experiment is important because it ensures that
Let f and g be functions defined on R" and c a real number. Consider the following two problems, Problem 1: max f(x) and Problem 2: max f(x) subject to g(x) = c. 1. Any solution of problem 1 is also a solution of problem 2. True or false? 2. If Problem 1 does not have a solution, then Problem 2 does not have a solution. True or false? 3. Problem 2 is equivalent to min - f(x) subject to g(x) = c. True or false? 4. In Problem 2, quasi-convexity of f is a sufficient condition for a point satisfying the first-order conditions to be a global minimum. True or false? 5. Consider the function f(x,y) = 5x - 17y. f is a) quasi-concave b) quasi-convex c) quasi-concave and quasi-convex d) no correct answer
True. Any solution of Problem 1 (max f(x)) is also a solution of Problem 2 (max f(x) subject to g(x) = c).
True. If Problem 1 does not have a solution, then Problem 2 does not have a solution.
True. Problem 2 (max f(x) subject to g(x) = c) is equivalent to min -f(x) subject to g(x) = c.
False. In Problem 2, the quasi-convexity of f is not a sufficient condition for a point satisfying the first-order conditions to be a global minimum.
The function f(x,y) = 5x - 17y is quasi-concave.
Any solution that maximizes f(x) will also satisfy the constraint g(x) = c. Therefore, any solution of Problem 1 is also a solution of Problem 2.
If Problem 1 does not have a solution, it means that there is no maximum value for f(x). In such a case, Problem 2 cannot have a solution since there is no maximum value to subject to the constraint g(x) = c.
Problem 2 can be reformulated as finding the minimum of -f(x) subject to the constraint g(x) = c. This is because maximizing f(x) is equivalent to minimizing -f(x) since the maximum of a function is the same as the minimum of its negative.
False. Quasi-convexity of f is not a sufficient condition for a point satisfying the first-order conditions to be a global minimum in Problem 2. Quasi-convexity guarantees that local minima are also global minima, but it does not ensure that the point satisfying the first-order conditions is a global minimum.
The function f(x,y) = 5x - 17y is quasi-concave. A function is quasi-concave if the upper contour sets, which are defined by f(x,y) ≥ k for some constant k, are convex. In this case, the upper contour sets of f(x,y) = 5x - 17y are convex, satisfying the definition of quasi-concavity.
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a new shopping mall is gaining in popularity. every day since it opened, the number of shoppers is 5% more than the number of shoppers the day before. about how many total shoppers would be expected after 10 days, if there were 100 shoppers on the first day?
After 10 days, the expected number of shoppers at the shopping mall is 163.
It is given that the number of shoppers increases daily by 5% from the number of shoppers the previous day.
As we can see that the increase in the number of shoppers is going to change every day, and the above case is compounded daily.
The formula of compound increase is
Amount = Base X (1 + r/n)ⁿˣ
where,
Base = original amount
r = rate of change
n = no. of times the change occurs in the time period
t = time
Here,
Base = 100
r = 5/100
n = 1, since it changes once every day
x = 10
Therefore we get
100 X (1 + 5/100)¹⁰
= 100 X 1.05¹⁰
162.88
Since the number of people cannot be in decimal,
the expected number of people is 163
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identify the sampling technique used. a researcher for an airline interviews all of the passengers on five randomly selected flights. a) random b) cluster c) stratified d) systematic e) convenience
The sampling technique used in this scenario is a) random sampling. The researcher interviews all passengers on five randomly selected flights.
The sampling technique used in this scenario is random sampling. Random sampling involves selecting individuals from a population in such a way that each individual has an equal chance of being chosen. In this case, the researcher selects five flights at random, and then interviews all passengers on those selected flights.
Random sampling helps ensure that the sample is representative of the population and reduces the potential for bias. By randomly selecting flights, the researcher increases the likelihood of obtaining a diverse range of passengers, capturing a variety of opinions and experiences.
Other sampling techniques have different characteristics. Cluster sampling involves dividing the population into groups or clusters and randomly selecting entire clusters to be included in the sample. Stratified sampling involves dividing the population into subgroups or strata and then randomly selecting individuals from each stratum. Systematic sampling involves selecting every nth individual from a list. Convenience sampling involves selecting individuals based on their availability or accessibility, which may introduce bias into the sample.
In summary, the sampling technique used in this scenario is random sampling, as the researcher randomly selects five flights and interviews all passengers on those selected flights. This approach helps ensure a representative sample and reduces potential bias.
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What value of will make the triangles similar by the similarity theorem?
As similarity theorem, the value of x that will make the triangles similar by SSS similarity theorem is 77.
Similarity theorem:
In math, similarity theorem refers the line segment splits two sides of a triangle into proportional segments if and only if the segment is parallel to the triangle's third side.
Given,
Here we need to find the t value of will make the triangles similar by the similarity theorem.
For example, we are told that the 2 triangles are similar by SSS theorem.
Here we know that, SSS means Side - Side -Side and it is a congruence theorem which states that the 3 corresponding sides of two triangles have same ratio, then we can say that the two triangles are congruent by SSS theorem
Therefore, in the triangles ,applying the SSS postulate gives;
=> x/35 = 44/20
Then by applying the multiplication property of equality, let us multiply both sides by 35 to get;
=> x = (44 * 35)/20
When we simplify this one then we get,
=> x = 77
Therefore, the value of x is 77.
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5x² = 80 in a quadratic equation
Solve for a
6a-15=72
Answer:
a=
Step-by-step explanation:
72+15=87
87/6= 14.5
a= 14.5
Answer: 14.5
Step-by-step explanation:
6a - 15 = 72
add 15 on both sides
6a = 87
divide by 6 on both sides
a = 14.5
a bowl of kashi cereal has 25 grams of total carbohydrates of which 4g is fiber, and 1 gram of fat, how many total calories does it have?
The bowl of Kashi cereal has a total of 93 calories
Each gram of carbohydrates provides 4 calories, and each gram of fat provides 9 calories. To calculate the total calories in the bowl of Kashi cereal, we need to determine the calories from carbohydrates and fat separately and then add them together.
Calories from carbohydrates
Total carbohydrates = 25g
Fiber = 4g
Net carbohydrates = Total carbohydrates - Fiber = 25g - 4g = 21g
Calories from carbohydrates = Net carbohydrates x 4 calories/gram
Calories from carbohydrates = 21g x 4 calories/gram
Calories from carbohydrates = 84 calories
Calories from fat
Fat = 1g
Calories from fat = Fat x 9 calories/gram
Calories from fat = 1g x 9 calories/gram
Calories from fat = 9 calories
Total calories = Calories from carbohydrates + Calories from fat
Total calories = 84 calories + 9 calories
Total calories = 93 calories
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Find the value of ′x'
The value of x, which we get by using an exponent rule is x = 2.80259.
What is an exponent rule?
Exponent is defined as the method of expressing large numbers in terms of powers. That is, exponent refers to how many times a number is multiplied by itself. For example, 6 is multiplied by itself four times, resulting in 6 6 6 6. This can be written as 64. In this case, 4 is the exponent and 6 is the base.
We have,
\(\frac{2}{3} ^{x} . \frac{3}{2} ^{2x} = \frac{81}{16}\)
By applying the exponent rule:
\(\left(-1\cdot \:x+2x\right)\ln \left(\frac{3}{2}\right)=\ln \left(\frac{81}{26}\right)\)
By simplifying the equation:
\(x=\frac{\ln \left(\frac{81}{26}\right)}{\ln \left(\frac{3}{2}\right)}\)
x = 2.80259
Hence, the value of x = 2.80259
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I WILL GIVE 50 POINTS PLEASE HELP IT'S EASY
Now that you have represented your data graphically, it can be more easily analyzed.
a) Describe how the line of best fit and the correlation coefficient can be used to determine the correlation between the two variables on your graph.
b) Describe the type of correlation between the two variables on your graph. How do you know?
c) Does the correlation between the variables imply causation? Explain.
d) How do you calculate the residuals for a scatterplot?
e) Calculate the residuals for your scatterplot in step 2d.
f) Create a residual plot for your data.
g) Does your residual plot show that the linear model from the regression calculator is a good model? Explain your reasoning.
a) Using your equation from step 2d, estimate the GPA of a student who studies for 15 hours a week. Justify your answer.
Answer:
a=The sign of the correlation coefficient is the same as the sign of the slope for the best fit line.
b= When the y variable tends to increase as the x variable increases, we say there is a positive correlation between the variables.
Step-by-step explanation:
Find the value of x.
Answer:
Solution
a+148=180(Angles on a straight line equals180)
▪a=180-148=32
Now,
a+b=90(A right angle is equal to 90)
So,
▪b=90-a=90-32=58
Then,
b=b(base of iscoceles angles of traingle)
Now,
b+b+x=180(sum of angles of triangle equals 180)
or,58+58+x=180
or,x=180-116
▪x=64'
Answer.
describe the difference in appearance between a bar graph and a histogram. check all that apply. a bar graph leaves a space between adjacent bars. in a histogram, adjacent bars touch at the real limits of the intervals. in a bar graph, shading is used to give the bars a three-dimensional appearance. the bars in a bar graph touch at the category boundaries. a histogram leaves a space between adjacent bars.
All the options that apply for the Histograms and Bar graph are :
(b) in a histogram, the adjacent bars touch at real limits of intervals.
(d) the bars in a bar graph touch at the category boundaries.
The Option (a) and (c) are not correct because the bar graph can be drawn with either adjacent bars touching or leaving spaces between them, and shading is not a necessary feature of a bar graph.
The Option (e) is not correct because the histogram typically does not leave space between adjacent bars, but rather has the bars touching at the real limits of the intervals.
Therefore, options (b) and (d) are the correct options which describes difference in appearance between a bar graph and a histogram.
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The given question is incomplete , the complete question is
Describe the difference in appearance between a bar graph and a histogram. Select all that apply.
(a) a bar graph leaves a space between adjacent bars.
(b) in a histogram, adjacent bars touch at the real limits of the intervals.
(c) in a bar graph, shading is used to give the bars a three-dimensional appearance.
(d) the bars in a bar graph touch at the category boundaries.
(e) a histogram leaves a space between adjacent bars.
Find the 49th term.
-15, -10, -5, O, 5, ...
49th term = [?]
1st term + common difference(desired term - 1)
Enter
Answer:
49th term = 225
Step-by-step explanation:
The following sequence: -15, -10, -5, 0, -5... is an example of an arithmetic progression.
An arithmetic progression or AP for short, is a sequence in which the difference between successive terms is constant. This difference is known as the common difference, and can be found by subtracting a term by its preceding term.
The general formula, for the nth term of an arithmetic progression, is thus:
Tn = a + (n - 1)d, where a = first term, and d = common difference.
In the sequence: -15, -10, -5, 0, 5...,
a = -15, and d = -10--15 = 5
T49 = -15 + (49 - 1)5 = 225
∴ 49th term = 225
Somebody please help me
The value of trigonometry function cot θ at θ = 690 degree is,
⇒ - √3
We have to given that,
A trigonometry function is,
⇒ cot θ
Where, θ = 690 degree
Now, We can simplify as;
⇒ cot θ
⇒ cot (690)
⇒ cot (2×360 - 30)
⇒ - cot 30°
⇒ - √3
Therefore, The value of trigonometry function cot θ at θ = 690 degree is,
⇒ - √3
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If a researcher wants to examine if there is a relationship between the number of steps taken and HR in a group of 1000 athletes, what would be the appropriate test to recommend? O Chi-Square O Spearman's Correlation Coefficient O Pearson's Correlation Coefficient Multiple Regression
The appropriate test to examine the relationship between the number of steps taken and HR in a group of 1000 athletes depends on the type of data and the research question.
If the number of steps and HR are both measured on a continuous scale and the research question is to examine the strength and direction of the relationship between the two variables, then the appropriate test would be Pearson's correlation coefficient.
If either the number of steps or HR is measured on a continuous scale and the other variable is measured on an ordinal scale, then the appropriate test would be Spearman's correlation coefficient.
However, if the research question is to predict HR based on the number of steps taken, and there are other variables that may influence the relationship, then multiple regression analysis would be the appropriate test.
Chi-Square test is used to examine the association between two categorical variables. It is not appropriate for examining the relationship between a continuous and categorical variable.
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The surface area of a rectangular prism that has height of 4 inches, width of 9 inches and length of 3 inches
The surface area of a rectangular prism is found as 150 square inches.
What is rectangular prism?A rectangular prism is a polyhedron in geometry that has two parallel and congruent bases. It also goes by the name cuboid. Six faces make up a rectangular prism, and each face has a rectangle shape and twelve edges.
Actually, prisms get their name from the way their faces are shaped. Therefore, a rectangular prism is just a prism with rectangular faces. Although it is a closed, three-dimensional object, two rectangles serve as its foundation.
Calculation for the surface area of rectangular prism-
Height of a rectangular prism => H = 4 inches
Width of a rectangular prism => B = 9 inches
Length of a rectangular prism => L = 3 inches
Surface area of a rectangular prism = 2(LB + BH + HL)
= 2(9×3 + 9×4 + 4×3)
= 150
Therefore, the surface area of a rectangular prism is found as 150 square inches.
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A study of the ages of 100 persons grouped into intervals 20—22, 22—24, 24—26……, revealed the mean agae and standard deviation to be 32. 02 and 13. 18,respectively. While checking, it was discovered that the observation 57 wasmisread as 27. Calculate the correct mean age and standard deviation
the corrected mean age and standard deviation are 32.32 and 13.76, respectively. Therefore, the required correct mean age and standard deviation are 32.32 and 13.76.
We are required to find the correct mean age and standard deviation. Concept Used: When a single observation in a data set is incorrectly recorded, we can make a new data set, substituting the correct value for the incorrect value, and then recalculating the statistics. The mean age is calculated as follows:
\($$\bar{x}=\frac{\sum_{i=1}^{n}x_i}{n}$$\)
where n is the total number of observations. The standard deviation is calculated as follows:
\($$s=\sqrt{\frac{\sum_{i=1}^{n}(x_i-\bar{x})^2}{n-1}}$$\)
We are given the mean age and standard deviation to be 32.02 and 13.18, respectively.
Since one observation was misread as 27 instead of 57, we can substitute 57 for 27 and find the correct mean and standard deviation as follows:
\($$\bar{x}=\frac{\sum_{i=1}^{n}x_i}{n}$$\)
\($$\frac{\sum_{i=1}^{n}x_i}{n}=\frac{(32.02 \times 100)-27+57}{100}$$\)
\($$\bar{x}=32.32$$\)
Now, let's calculate the corrected standard deviation:
\($$s=\sqrt{\frac{\sum_{i=1}^{n}(x_i-\bar{x})^2}{n-1}}$$\)
\($$s=\sqrt{\frac{\sum_{i=1}^{n}(x_i-\bar{x})^2}{99}}$$\)
Substituting the values of x_i and
$\bar{x}$, we have:
\($$s=\sqrt{\frac{(20-32.32)^2+(22-32.32)^2+...+(56-32.32)^2}{99}}$$\)
Substituting 57 for the misread observation of 27, we have:
\($$s=\sqrt{\frac{(20-32.32)^2+(22-32.32)^2+...+(56-32.32)^2+(57-32.32)^2}{99}}$$\)
$$s=13.76$$
Hence, the corrected mean age and standard deviation are 32.32 and 13.76, respectively.
Therefore, the required correct mean age and standard deviation are 32.32 and 13.76.
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Henry showed all the steps he took to solve the equation. 4 (negative one-half x + 7) + 5 x = 15 Step Simplified Expression 1 -Negative 2 x + 28 + 5 x = 15 2 3 x + 28 = 15 3 3 x = 15 4 x = 5 Sammy tried to verify the solution by substituting x = 5 back into the original equation. It did not result in a true statement. Which explains why Henry's solution is incorrect? Step 1 is wrong because the distributive property of equality was used incorrectly. Step 2 is wrong because the addition property of equality was used incorrectly. Step 3 is wrong because the subtraction property of equality was used incorrectly. Step 4 is wrong because the division property was used incorrectly.
Answer:
Step 3 is wrong because the subtraction property of equality was used incorrectly
Step-by-step explanation:
Henry showed all the steps he took to solve the equation.
The steps as show in the question is
4 (negative one-half x + 7) + 5 x = 15 Step 1
-Negative 2 x + 28 + 5 x = 15
Step 2
3 x + 28 = 15
Step 3
3 x = 15
Step 4
x = 5
Verifying the steps
The steps as show in the question is
4 (negative one-half x + 7) + 5 x = 15 Step 1
-Negative 2 x + 28 + 5 x = 15 (Distributive property of equality) This is correct
Step 2
3 x + 28 = 15(Addition property of equality this is correct)
Step 3
3 x = 15 (Subtraction property of equality) This is incorrect
The correct form is
3x +28 - 28 = 15 - 28
3x = -13
Step 4
x = -13/3
x = - 4.3333333333
Henry's solution is incorrect because Step 3 is wrong because the subtraction property of equality was used incorrectly.
x = -4.3
Answer:
c
Step-by-step explanation:
anna has 2 dozen Rollo bars and 1 dozen apples as treats for halloween. in how many ways can anna hand out 1 treat to each of 36 children who come to her door?
There are approximately 3.72 x 10⁴¹ ways that Anna can hand out 1 treat to each of the 36 children who come to her door.
Anna has 2 dozen Rollo bars, which is equivalent to 2 x 12 = 24 Rollo bars.
She also has 1 dozen apples, which is equivalent to 1 x 12 = 12 apples.
So, Anna has a total of 24 + 12 = 36 treats to hand out.
Now, she needs to hand out 1 treat to each of the 36 children who come to her door.
This can be thought of as selecting 1 treat from the total of 36 treats for each child, without replacement, as each child can only receive 1 treat.
The number of ways to do this is given by the concept of permutations, denoted by "nPr", which is calculated as;
nPr = n! / (n - r)!
where n is the total number of items (treats) to choose from, and r is the number of items (treats) to choose.
In this case, n = 36 (total number of treats) and r = 36 (number of children).
Plugging in the values, we get;
36P36 = 36! / (36 - 36)! = 36! / 0! = 36!
Since 0! (0 factorial) is equal to 1, we can simplify further:
36! / 1 = 36!
36! ≈ 3.72 x 10⁴¹
So, there are 3.72 x 10⁴¹ ways that Anna can hand out 1 treat to each of the 36 children who come to her door.
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