SOMEBODY PLEASE HELP MY SISTER SHE DOEANT KNOW HOW TO DO THIS AT ALL AND NEITHER DO I THE QUESTION IS IN THE PHOTO THANKS
Answer:
x = 7
Step-by-step explanation:
→ Find perimeter of rectangle
x + x + 4 + x + x + 4 = 4x + 8
→ Find perimeter of triangle
2x - 3 + 3x - 4 + x + 1 = 6x -6
→ Equate 2 expressions together
4x + 8 = 6x - 6
→ Minus 8 from both sides
4x = 6x - 14
→ Minus 6x from both sides
-2x = -14
→ Divide both sides by 2
x = 7
Which one should I choose?
Answer:
∠ 1 = 58°
Step-by-step explanation:
The exterior angle of a triangle is equal to the sum of the 2 opposite interior angles.
117° is an exterior angle of the triangle, then
∠ 1 + 59° = 117° ( subtract 59° from both sides )
∠ 1 = 58°
2. What is the product of -2x3 + x - 5 and x3 - 3x - 4?
(a) Show your work
(b) Is the product of -2x3 + x - 5 and x3 - 3x – 4 equal to the product of x3 - 3x - 4 and
-2x3 + x-5? Explain your answer
The product of \(-2x^{3}\) + x - 5 and \(x^{3}\) - 3x - 4 is \(-2x^{6}\) + \(7x^{4}\) + \(3x^{3}\) + \(12x^{2}\) - 4x + 20. The order of the polynomials does not affect the result; they yield the same product.
a) To find the product of \(-2x^{3}\) + x - 5 and \(x^{3}\) - 3x - 4, we multiply each term in the first expression by each term in the second expression and combine like terms.
\(-2x^{3}\) * \(x^{3}\) = -2\(x^{6}\)
\(-2x^{3}\) * (-3x) = 6\(x^{4}\)
\(-2x^{3}\) * (-4) = 8\(x^{3}\)
x * \(x^{3}\) = \(x^{4}\)
x * (-3x) = -3\(x^{2}\)
x * (-4) = -4x
-5 * \(x^{3}\) = -5\(x^{3}\)
-5 * (-3x) = 15\(x^{2}\)
-5 * (-4) = 20
Combining all the terms, we have:
-2\(x^{6}\) + 6\(x^{4}\) + 8\(x^{3}\) + \(x^{4}\) - 3\(x^{2}\) - 4x - 5\(x^{3}\) + 15\(x^{2}\) + 20
Simplifying further:
-2\(x^{6}\)+ 7\(x^{4}\) + 3\(x^{3}\) + 12\(x^{2}\) - 4x + 20
Therefore, the product of -2\(x^{3}\) + x - 5 and \(x^{3}\) - 3x - 4 is -2\(x^{6}\) + 7\(x^{4}\) + 3\(x^{3}\) + 12\(x^{2}\) - 4x + 20.
(b) The product of two polynomials is commutative, which means that changing the order of the polynomials being multiplied does not affect the result. In other words, the product of \(x^{3}\) - 3x - 4 and -2\(x^{3}\) + x - 5 will be the same as the product obtained in part (a).
Therefore, the product of -2\(x^{3}\) + x - 5 and \(x^{3}\) - 3x - 4 is equal to the product of \(x^{3}\) - 3x - 4 and -2\(x^{3}\) + x - 5. The order of the polynomials being multiplied does not impact the final result, so both expressions yield the same product.
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Please help!!!
If data set A has a larger standard deviation than data set B, data set B is
more spread out thar data set A.
O A. True
O B. False
Answer:
the answer is B.FALSE
Step-by-step explanation:
hope it helps
One size of cardboard can be purchased in sheets that are 3/16 inches thick. The sheets of cardboard are stacked on top of each other in packages. The height of each stack is 2 1/4 inches.
Part A: Use the model of a ruler to determine the number of sheets of cardboard in a stack.
Part B: Explain how you used the model to find your answer.
Part C: Write an expression that can be used to determine the number of sheets of cardboard in a stack.
Part D: Explain how your expression relates to the model.
There are 12 sheets of cardboard in the stack based on the model and the expression.
Part A: To determine the number of sheets of cardboard in a stack, we can use the model of a ruler.
Part B: Using the ruler model, we can compare the height of the stack (2 1/4 inches) to the thickness of each sheet (3/16 inches). We divide the height of the stack by the thickness of each sheet to find the number of sheets in the stack.
Part C: The expression that can be used to determine the number of sheets of cardboard in a stack is:
Number of sheets = Height of the stack / Thickness of each sheet
Part D: The expression relates to the model by dividing the height of the stack (measured in inches) by the thickness of each sheet (also measured in inches). This division represents the number of times the thickness of each sheet fits into the height of the stack, giving us the total number of sheets.
For example, if the height of the stack is 2 1/4 inches and the thickness of each sheet is 3/16 inches, we can calculate:
Number of sheets = (2 1/4) / (3/16) = (9/4) / (3/16) = (9/4) * (16/3) = 12.
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2 A taxi charges $2.50 per mile in addition to a $2
transportation fee. Identify your variables, then
write an equation to represent the total cost to
take a taxi cab.
pls help me
What is the difference in the y values? 62 70 72
When we look for the constant rate of change, we subtract the first two y-values in the first place:
\(216-144=72\)Hence, the difference is 72.Here’s a table that represents the situation. Find the cost of 1 gigabyte
Answer:
.25 dollars or 25 cents
Step-by-step explanation:
128/2=64 32/2=16
64/2=32 16/2=8
32/2=16 8/2=4
16/2=8 4/2=2
8/2=4 2/2=1
4/2=2 1/2=(1/2)
2/2=1 (1/2)/2=(1/4)
1/4 of 1 dollar is 25 cents
What is this- 5(-2xy) simplfied?
Answer:
10xy
Step-by-step explanation:
-5(-2)=10
Answer:
10xy
Step-by-step explanation:
Negative 5 times negative 2 equlas 10
Our answer is 10xy.
I hope it helps!:)
12(x-3)+18= what is the awnser
Answer:
32
Step-by-step explanation:
The answer would be 32:);)
if I have an 84% which is a B but get a 65 which is a D whats my grade now?
Answer: C
Step-by-step explanation:
Three professors at a university did an experiment to determine if economists are more selfish than other people. They dropped 64 stamped, addressed envelopes with $10 cash in different classrooms on the campus. 42% were returned overall. From the economics classes 58% of the envelopes were returned. From the business, psychology, and history classes 32% were returned. • R = money returned • E = economics classes • O = other classes1. ) Write a probability statement for the overall percent of money returned.
2. ) Write a probability statement for the percent of money returned out of the economics classes. 3. ) Write a probability statement for the percent of money returned out of the other classes.
According to the study, economists are not more self-centered than persons in other classes because 51% of the envelopes returned from economics classes and 36% from other classes.
What is meant by probability?Simply put, probability measures how probable something is to occur. We can discuss the probabilities of various outcomes, or how likely they are, whenever we are unsure of how an event will turn out. Statistics is the study of events subject to probability.
At one classroom for economics and another for other topics, they dumped 122 stamped envelopes with addresses and $20 bills inside each.
Let the money returned = R
economics classes = E
other classes = O
a). The following gives the probability statement for the overall percentage of the money returned: 100.P (R)
b). The probability statement that the percentage of money recovered from economics classes is 100.P(R|E)
c). The probability statement that displays the percentage of money returned from the other classes is 100.P(R|O).
d). No, because P(R) is not equal to P(R|E), the money returned is not independent of the classes.
e). According to the study, economists are not more self-centered than persons in other classes because 51% of the envelopes returned from economics classes and 36% from other classes.
The complete question is:
Three professors at George Washington University did an experiment to determine if economists are more selfish than other people. They dropped 122 stamped, addressed envelopes with $20 cash in two different classrooms (one economics, one not) on the George Washington campus. Of these, 42% were returned overall. From the economics class 51% of the envelopes were returned. From the other class 36% were returned.
From
the business, psychology, and history classes 31% were returned.
Let: R = money returned; E = economics classes; O = other classes
a. Write a probability statement for the overall percent of money returned.
b. Write a probability statement for the percent of money returned out of the economics classes.
c. Write a probability statement for the percent of money returned out of the other classes.
d. Is money being returned independent of the class? Justify your answer numerically and explain it.
e. Based upon this study, do you think that economists are more selfish than other people? Explain why or why not. Include numbers to justify your answer.
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what is the domain of the function in the graph?
Answer:
6AJNSDJN
Step-by-step explanation:
Please help! Thank you if you do!
Answer:
8/50
5/50
10/50
38/50
45/50
Step-by-step explanation:
calculate the area of the region bounded by: r=18cos(θ), r=9cos(θ) and the rays θ=0 and θ=π4.
The required area is approximately 39.36 square units.
The given polar curves are r = 18cos(θ) and r = 9cos(θ). We are interested in finding the area of the region that is bounded by these curves and the rays θ = 0 and θ = π/4.
First, we need to find the points of intersection between these two curves.
Setting 18cos(θ) = 9cos(θ), we get cos(θ) = 1/2. Solving for θ, we get θ = π/3 and θ = 5π/3.
The curve r = 18cos(θ) is the outer curve, and r = 9cos(θ) is the inner curve. Therefore, the area of the region bounded by the curves and the rays can be expressed as:
A = (1/2)∫(π/4)^0 [18cos(θ)]^2 dθ - (1/2)∫(π/4)^0 [9cos(θ)]^2 dθ
Simplifying this expression, we get:
A = (1/2)∫(π/4)^0 81cos^2(θ) dθ
Using the trigonometric identity cos^2(θ) = (1/2)(1 + cos(2θ)), we can rewrite this as:
A = (1/2)∫(π/4)^0 [81/2(1 + cos(2θ))] dθ
Evaluating this integral, we get:
A = (81/4) θ + (1/2)sin(2θ)^0
Plugging in the limits of integration and simplifying, we get:
A = (81/4) [(π/4) + (1/2)sin(π/2) - 0]
Therefore, the area of the region bounded by the curves and the rays is:
A = (81/4) [(π/4) + 1]
A = 81π/16 + 81/4
A = 81(π + 4)/16
A ≈ 39.36 square units.
Hence, the required area is approximately 39.36 square units.
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Which linear equation can be used to represent a line perpendicular to Line W passing through point (-3,-2)?
line on graph is x=8 Help please
Answer:
D) y = -2
The equation of the perpendicular line to the given line is y = -2
Step-by-step explanation:
Explanation:-
Given point (-3,-2)
In graph the equation of line x = 8 ( parallel to y- axis )
1 x + o y - 8 =0
The equation of the perpendicular line to the given line
b x - a y + k =0
o x - 1 y + k =0 ...(i)
The equation (i) is Paases through the point ( -3,-2)
0 ( -3) -1(-2) + k =0
2 + k =0
k = -2
∴The equation of the perpendicular line to the given line is
put k = -2 in equation (i)
o x - 1 y + k =0
- y +(-2) =0
- y = 2
y = -2
Final answer:-
∴The equation of the perpendicular line to the given line is y =-2
What value do we need to complete the equation?
Answer:
h/2
Step-by-step explanation:
This figure shows the mer
r = 4 ft.
32 ft.
What is the volume, in cubic feet, of the tank? Round your answer to the nearest tenth.
Answer:
8
Step-by-step explanation:
8•4=32 it's not that bad
A curve c in space is described by the vector-valued function: p(t)=⟨t2−1,2t,2t2 2⟩ find a unit vector with positive x-component that is orthogonal to both p(0) and p′(0):
The unit vector with positive x-component that is orthogonal to both p(0) and p′(0) is \(v_u_n_i_t\) = v / ||v|| = ⟨-1,0,0⟩.
First, we need to find the vector that represents the position of the curve at t=0, which is p(0) = ⟨-1,0,0⟩.
Then we need to find the vector that represents the velocity of the curve at t=0, which is p'(t) = ⟨2t,2,4t⟩, so p'(0) = ⟨0,2,0⟩.
To find a unit vector that is orthogonal to both p(0) and p'(0), we can use the cross product:
v = p(0) x p'(0)
where "x" denotes the cross product. This will give us a vector that is perpendicular to both p(0) and p'(0), but it may not be a unit vector. To make it a unit vector, we need to divide by its magnitude:
\(v_u_n_i_t\) = v / ||v||
where "||v||" denotes the magnitude of v.
So let's calculate v:
v = p(0) x p'(0) = ⟨0,0,2⟩ x ⟨0,2,0⟩ = ⟨-4,0,0⟩
And the magnitude of v is:
||v|| = sqrt((-4)^2 + 0^2 + 0^2) = 4
So the unit vector that is orthogonal to both p(0) and p'(0) and has a positive x-component is:
\(v_u_n_i_t\) = v / ||v|| = ⟨-1,0,0⟩
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Find the volume of the given solid.
Bounded by the coordinate planes and the plane
6x + 7y + z = 42
The volume of the given solid is equal to the triple integral of 1 over the region bounded by the coordinate planes and the plane 6x + 7y + z = 42. This can be written as:
\($\iiint 1\, dV = \iiint 1\, dx\, dy\, dz$\)
The region of integration is bounded by the coordinate planes x = 0, y = 0, and z = 0, and the plane 6x + 7y + z = 42. This is a right triangular prism with vertices (0,0,0), (6,0,0), and (0,6,42). To calculate the volume, we will use the triple integral in cylindrical coordinates, which can be written as:
\($\iiint 1\, dV = \int0^{2\pi}\int0^6\int_0^{42/7} r\, dz\, dr\, d\theta$\)
The volume of the given solid is given by:
\($\frac{504\pi}{7}$\)
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A list of 5 numbers is shown below.
0, 3, 7, -6, -12.3
Which set contains all the numbers in the list?
A integers
B whole numbers
C natural numbers
D rational number
Answer:
D. Rational Number
Step-by-step explanation:
Integers are defined as all whole numbers, positive and negative, including 0. Since in the list there is a number that is not whole, A is not the correct answer choice.Whole numbers are all positive numbers (including 0) without decimals or fractions. Since the list has a number that is not a whole number, along with two that are negative, B is also not correct.Natural numbers are all positive numbers (excluding 0) without decimals or fractions. Since there is a 0 in the list, C is not correct.Rational numbers are all numbers that can be simplified into a ratio with 2 integers (i.e. π and e are not rational). Since every number on the list can be put into this category, answer choice D is correct.Hello, I need some assistance with this homework question please for precalculusHW Q41
A shipment of sugar fills 2(1)/(5) containers. If each container holds 3(3)/(4) tons of sugar, what is the amount of sugar in the entire shipmen Write your answer as a mixed number in simplest form.
The amount of sugar in the entire shipment is 97(1)/(2) tons.
We are given that a shipment of sugar fills 2(1)/(5) containers. If each container holds 3(3)/(4) tons of sugar, we need to find the amount of sugar in the entire shipment.
Step-by-step explanation:
One container of sugar holds 3(3)/(4) tons of sugar. There are 2(1)/(5) containers of sugar in the shipment.
Amount of sugar in one container = 3(3)/(4) tons
Amount of sugar in 2(1)/(5) containers
= 2(1)/(5) × 3(3)/(4) tons
= 13/5 × 15/4 = 195/20
= 97(1)/(2) tons
Therefore, the amount of sugar in the entire shipment is 97(1)/(2) tons.
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Consider the second order differential equation with initial conditions u" - 5u' 6.5u 7 sin(3t), = u(1) = 7.5, u' (1) = 9. Without solving it, rewrite the differential equation as an equivalent set of first order equations. In your answer use the single letter u to represent the function u and the single letter v to represent the "velocity function" u'. Do not use u(t) or v(t) to represent these functions. Expressions like sin(t) that represent other functions are OK. u' = U' = Now write the first order system using matrices: u d •[:]-[ 311: dt V The initial value of the vector valued solution for this system is: u(1) ]-[ = +
The first-order system representing the given second-order differential equation is du/dt = v and dv/dt = 5v - 6.5u - 7sin(3t), with the initial condition [u(1), v(1)] = [7.5, 9].
To rewrite the second-order differential equation u" - 5u' + 6.5u = 7sin(3t) as a set of first-order equations, we introduce a new variable v to represent the u'. Therefore, we have u' = v. Differentiating this equation with respect to t, we obtain u" = v'.
Substituting these expressions back into the original equation, we have v' - 5v + 6.5u = 7sin(3t).
Now, we can express the system of first-order equations in matrix form as [du/dt, dv/dt] = [v, 5v - 6.5u - 7sin(3t)].
The initial value of the vector-valued solution for this system is given as [u(1), v(1)] = [7.5, 9].
In summary, the first-order system representing the given second-order differential equation is du/dt = v and dv/dt = 5v - 6.5u - 7sin(3t), with the initial condition [u(1), v(1)] = [7.5, 9].
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Which system of equations has no solution?
Answer:
4x-5y=3
-3=4x-5y
Step-by-step explanation:
4x-5y = 3
4x-5y = -3
both statements have different answers but has the same problem making the statement x=x and 0=0 making it have no solution
what is the solution to the system of equations ? 3r+2y=45 4r-y=5 1. r=5 y=10 2.r=15 y=10 3.r=5 y=15 4. r=15 y=5
Answer:
The solution to the system of equation is;
\(\begin{gathered} r=5 \\ y=15 \end{gathered}\)Explanation:
Given the system of equations;
\(\begin{gathered} 3r+2y=45\text{ -----------1} \\ 4r-y=5\text{ ----------2} \end{gathered}\)Let us solve by elimination, multiply equation 2 by 2 and add to equation 1 to eliminate y;
\(\begin{gathered} 4r(2)-y(2)=5(2) \\ 8r-2y=10\text{ -----------3} \end{gathered}\)adding to equation 1;
\(\begin{gathered} 3r+8r+2y-2y=45+10 \\ 11r=55 \\ r=\frac{55}{11} \\ r=5 \end{gathered}\)we can now use the value of r to solve for y;
\(\begin{gathered} 3r+2y=45 \\ 3(5)+2y=45 \\ 15+2y=45 \\ 2y=45-15 \\ 2y=30 \\ y=\frac{30}{2} \\ y=15 \end{gathered}\)Therefore, the solution to the system of equation is;
\(\begin{gathered} r=5 \\ y=15 \end{gathered}\)HURRYS!!
You will be creating a short photo essay to answer the question: “What is a Hero”? This should be a synthesis of all that we have studied and discussed throughout the course of this chapter. Your essay will include photos of your choosing which help to define and explain your definition of what a hero is. You will also include short captions to enhance your essay and to further express your understanding of the concept. Follow the guidelines below:
Your photo essay must clearly give an answer to the question: What is a Hero?
The pictures in your photo essay should reflect your personal idea of what a hero is. Images can be public domain pictures, or photos from your personal life.
Your pictures must be supported with captions that further enhance your definition of what a hero is. Focus on word choice, using descriptive adjectives and action verbs.
Your essay should be 60-90 seconds in length.
Include documentation of any sources used in your photo essay. This includes pictures! View the MLA Style Guide.
Complete the self-evaluation below to submit with your photo essay.
Answer:
Honestly YOU have to write what you think a hero means. I know most of yall on here are lazy and just want people to answer questions for you.. but cmon. What do YOU think a hero means?
what is a saddle point? which is more likely, getting stuck in a local minima or in a saddle point? explain why and show proof.
Saddle points are critical point that the function didn't in local maximum points nor in a local minimum position. Saddle pointly mostly happen in the multivariable functions. In simple, saddle point is everything on the function accept the local maxima and minimum maxima. The proof what is the saddle shown in the picture. As you can see, the curve besides local maxima and minimum maxima is create an area like a saddle, thats why its called saddle point.
How to calculate availability of saddle points?Saddle point availability can be calculate by this logic: lets say we have r = f(q, w), then the point (q, w, r) is told to be a saddle point if each derivatives fq(q, w) and fw(q, w) subside,and f is not in any local maximum or local minima value at (x, y).
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I really need to know the answer of this question
Answer:
Amir 20 Rita 45
Step-by-step explanation:
20/4=5
5*9=45
so this satisfices the ration 4:9
Answer:
Amir : 20 sweets and Rita : 45 sweets
Step-by-step explanation:
Rita has 25 more in all answers. to get the answer, this is to see which one : 4:9 ; 20:45.
we multiply 4 and 45 and 9 and 20. if we multiply them, both answers are 180. this means it is equal and that is the answer.
Which graph has a slope of 4/5
-
-5-4-3-2-1₁ 1 2 3 4 5
-2-
-3-
3-4-3-2
1 2 3 4 5
-1₁ 1 2 3 4 5
---
-5-4-3-2-1 1 2 3 4 5 X
The graph that has a slope of 4/5 is the one represented by the equation y = (4/5)x. In this graph, the slope represents the ratio of the vertical change (rise) to the horizontal change (run) between any two points on the line. In this case, for every 5 units of horizontal change (run), there is a vertical change (rise) of 4 units.
The graph can be visualized as a line that goes up 4 units for every 5 units it moves to the right. This means that as x increases by 5 units, y increases by 4 units. Similarly, as x decreases by 5 units, y decreases by 4 units.
By plotting points on the graph, we can see that the line will have a positive slope, moving upward from left to right. The steepness of the line corresponds to the ratio 4/5, indicating that it is relatively steep but not as steep as a line with a slope of 1.
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