Imagine that you have two different carbon atoms, one identified as 14C and the other as 13C. These two carbon atoms: (choose all that apply) are two different carbon isotopes. have a different number of neutrons have a different number of protons are the same isotopes of carbon have a different number of electrons have different atomic weights

não se esqueça de mim não sei

3

2

1

4

6

5

not a 100% sure but i think this is it.

The percent by mass of each element in C12H22O11 is 42.1 % for C, 6.4 % for H, and 51.43 % for O respectively.

The mass consistent with cent is defined as the grams of solute consistent with grams of solution, accelerated with the aid of one hundred to get the share. The Mass in keeping with cent components is expressed as fixing for the molar mass and also for the mass of each detail in 1 mole of the compound. Mass percent is one way of representing the attention of an element in a compound or a component in a mixture

Calculation:-

Molar Mass of C12H22O11 = 342

C 12 x 12.01 = 144.12 / 342 × 100

                   = 42.1 %

H 22 x 1.00 = 22/ 342 × 100 = 6.4 %

O 11 x 15.99 = 175.89/ 342 × 100 = 51.43 %

Mass percentage composition is likewise recognized percent via weight. it's miles abbreviated as w/w%. For a solution, mass percent equals the mass of an element in a single mole of the compound divided with the aid of the molar mass of the compound, increased with the aid of 100%.

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If you use 0.600 mol of gas, the gas will have a new volume of 13.2 L.

The amount of space a three-dimensional item takes up is measured by its volume. Usually, it is expressed in terms of liters (L), cubic meters (m3), or cubic feet (ft3).

The volume of the gas is directly proportional to the amount of gas (measured in moles) present, presuming constant temperature and pressure. Avogadro's Law describes this connection.

This law allows us to establish a proportion:

Amount1 / Volume1 = Volume2 / Amount2

If Volume2 is the new volume we wish to find, Volume1 is the initial volume, Amount1 is the initial amount of gas (in moles), and Volume2 is the new volume (in moles).

By entering the specified values, we obtain:

Volume2 / 0.600 mol = 1.1 L / 0.05 mol

For Volume 2, we solve as follows:

Volume2 = 1.1 liters / 0.05 mol / 0.600 mol = 13.2 liters

Therefore, if you use 0.600 mol of gas, the new volume of the gas will be 13.2 L.

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Answer:

big bang → expansion and cooling → atom formation → star and galaxy formation → continuation of expansion and cooling

Explanation:

Answer:

D: big bang → expansion and cooling → atom formation → star and galaxy formation → continuation of expansion and cooling

Explanation:

i just took the quiz and it was right! :)

Answer: The correct answer is 2 moles.

Explanation:

Answer:

PHYSICAL:

An example of a physical change would be clay, for instance, you take out clay you then sculpt it into a spere, this is a physical change.

CHEMICAL

An example of a chemical change is when you take vinegar then put baking soda in it, it has a chemical reaction  

hope this helped <3

Answer:

chemical bonds

Explanation:

The atoms in chemical compounds are held together by attractive electrostatic interactions known as chemical bonds. Ionic compounds contain positively and negatively charged ions in a ratio that results in an overall charge of zero. The ions are held together in a regular spatial arrangement by electrostatic forces.

Answer:

Explanation:

Hope this helps

Mescaline produces a wide range of psychoactive effects when ingested, including altered perception of reality, hallucinations, and euphoria. It is a powerful psychedelic drug that has been used for centuries by Native American tribes in spiritual ceremonies

Mescaline is a hallucinogenic alkaloid that is derived from the Peyote cactus. Mescaline is a complex organic molecule that can be synthesized in the laboratory from 3,4,5-trimethoxybenzyl bromide in two steps.The first step involves nucleophilic substitution using sodium cyanide, and the second step is a reduction using lithium aluminum hydride (LAH).Here's how mescaline can be synthesized from 3,4,5-trimethoxybenzyl bromide:Step 1: Nucleophilic substitution using sodium cyanideThe reaction of 3,4,5-trimethoxybenzyl bromide with sodium cyanide results in the formation of the nitrile derivative. NaCN serves as the nucleophile in this reaction, and it replaces the bromide ion.The mechanism for this reaction involves the following steps: A nucleophilic attack by the cyanide ion on the benzyl bromide. The carbon-bromine bond breaks, and the benzyl cation is formed. A second nucleophilic attack by the cyanide ion occurs on the benzyl cation, resulting in the formation of the nitrile derivative.Here's the reaction equation for this step:Step 2: Reduction using lithium aluminum hydrideThe next step is the reduction of the nitrile derivative using LAH. LAH serves as a strong reducing agent in this reaction and reduces the nitrile derivative to the amine. The mechanism for this reaction involves the following steps: A nucleophilic attack by LAH on the nitrile derivative. This results in the formation of an imine intermediate. The imine intermediate reacts with another LAH molecule, resulting in the formation of the amine.Here's the reaction equation for this step:Mescaline structure: Mescaline is a psychoactive compound that belongs to the phenethylamine class of alkaloids. The structure of mescaline is as follows: The molecule has three methoxy groups attached to the benzene ring, and it has an amine functional group. The molecule is a white crystalline powder that is soluble in water and alcohol.

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After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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The positive value of 571.6 kJwhich is the enthalpy change tells us that it is exothermic

When energy is released into the surrounding area during a chemical reaction, it's considered an exothermic reaction with ΔH < 0. Conversely, endothermic reactions result from heat absorption with ΔH > 0.

The provided equation's positive value of 571.6 kJ reveals that heat is pouring out of the reaction, causing negative changes in enthalpy and firmly placing this chemical event as exothermic in nature.

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Answer:

Particle Symbol Mass

electron e- 0.0005486 amu

proton p+ 1.007276 amu

neutron no 1.008665

Answer:

C

Explanation:

thats my guess but im not completely sure

The total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by Ni2+(ag) is also 2.0 moles of electrons.

This is because in a chemical equation, the number of moles of electrons gained by the reducing agent (in this case Ni2+) is equal to the number of moles of electrons lost by the oxidizing agent (in this case Mg(s)).

In this redox reaction, Mg is being oxidized because it loses electrons and Ni is being reduced because it gains electrons. The oxidation and reduction process are occurring simultaneously, so the number of electrons lost by Mg(s) is equal to the number of electrons gained by Ni2+(ag).

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The electrons that are gained by the \(Ni^{2+}\) ion is 2.0 moles of electrons.

We know that when there is a redox reaction, there would be the loss or gain of electrons in the process. The process is a simultaneous one so the electrons that are lost by one specie must as a matter of necessity be gained by another specie.

In this case, as we look at the reaction equation we can see that there are two electrons that have been lost by the magnesium atom and these two electrons would be gained by the Nickel II ion.

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Answer:

No. of moles \(\approx\) 0.020

Explanation:

To calculate the number of moles of a substance in a solution given its concentration and volume, we use the following formula:

\(\boxed{\mathrm{No. \ of \ moles = Concentration \times Volume}}\),

where concentration is in mol/dm³ (or M) and volume is in L.

In the question, we are told that the volume of the solution is 0.085 L and that its concentration is 0.23 M. Substituting these values into the formula above, we get:

No. of moles = 0.23 × 0.085

                     = 0.01955

                     \(\approx\) 0.020 mol  (3 s.f.)

Therefore, there are 0.020 moles of NH₄NO₃ in the solution.

The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ

First, we shall obtain the limiting reactant. Details below:

3H₂ + N₂ -> 2NH₃

From the balanced equation above,

28 g of N₂ reacted with 6 g of H₂

Therefore,

2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂

We can see that only 0.43 g of H₂ is needed in the reaction.

Thus, the limiting reactant is N₂

Finally, we the amount of heat energy produced. Details below:

3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ

From the balanced equation above,

When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.

Therefore,

When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ

Thus the heat energy produced from the reaction is -6.61 KJ

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The accurate responses are;

1) it has the configuration of of the noble gas in the same period

2) higher, gain, more

The electron configuration shows the arrangement of the atoms in an element. We know that in an element, the nucleus is at the core of the atom. The shells have energies increasing order with the shells that are close to the nucleus having the lowest energy and the energy of the shells tends to increase radially outwards from the nucleus.

Now let us try to look at sodium. We know that the formation of ions leads an element to attain the noble gas configuration. We can see that when sodium loses an electron, it closely resembles the noble gas neon.

The ionization energy is the energy that is required for the removal of one electron from the outermost shell of the atom. The complete statement therefore is; Ionization energies for nonmetals are higher than metals because they would rather gain  electrons than lose electrons, so it takes more energy.

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The correct answer is B. 8 molecules \(SO_3\). Option B

In the given reaction:

S(s) + \(O_2\)(g) → \(SO_3\)(g)

The stoichiometric coefficient in front of the \(SO_3\)molecule is 8, which indicates that 8 molecules of \(SO_3\)are formed as a product. This coefficient represents the ratio of the number of molecules involved in the reaction.

Option A (8 atoms \(SO_3\)) is incorrect because it only mentions the number of atoms, not molecules. The stoichiometric coefficient does not represent the number of atoms, but rather the number of molecules.

Option C (80.07g \(SO_3\)) is incorrect because it mentions a specific mass. The stoichiometric coefficient does not directly represent the mass of the substance, but rather the relative amount of molecules involved in the reaction.

Option D (32 \(SO_3\)) is incorrect because it mentions a specific volume. The stoichiometric coefficient does not directly represent the volume of the substance, but rather the relative amount of molecules involved in the reaction.

Therefore, the correct way to describe the \(SO_3\)component in the reaction is option B: 8 molecules \(SO_3\). This represents the ratio of the number of molecules of \(SO_3\)that are produced in the reaction.

Option B

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Answer: D

Explanation: i found the anwser key

Answer: I believe that the answer is C

Explanation:

Answer:

Answer:

According to Newton's law of gravitation two objects attract each other

Answer: C. Attract each other!

Explanation:

1- FIND MOLES OF magnesium METAL

Moles of Magnesium Metal = 0.6 g/24.31 g/mol = 0.0246 mol

Magnesium is a silvery-white alkaline earth metal that is a very abundant element in the Earth's crust. It is the eighth most abundant element in the universe.

2- FIND CHANGE IN T CALORIMETER

The change in temperature of the calorimeter is not given, so it cannot be calculated.

3- Find q calorimeter

The heat absorbed or released by the calorimeter is qcalorimeter = mCΔT, where m is the mass of the calorimeter, C is the specific heat capacity of the calorimeter, and ΔT is the change in temperature of the calorimeter. Since the mass and change in temperature of the calorimeter are not given, qcalorimeter cannot be calculated.

4- Find q reaction

The heat absorbed or released by the reaction is qreaction = nCΔT, where n is the number of moles of the reactant, C is the specific heat capacity of the reaction, and ΔT is the change in temperature of the reaction. Since the number of moles of the reactant and change in temperature of the reaction are not given, qreaction cannot be calculated.

5- Find the change in heat reaction per mole of Mg consumed

The change in heat per mole of Mg consumed is qMg = qreaction/n, where qreaction is the heat absorbed or released by the reaction and n is the number of moles of Mg. Since qreaction and n are not given, qMg cannot be calculated.

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Answer:

H2 to O2

H2 to H2O

H20 to O2

H2O to H2

O2 to H20

O2 to H2

Explanation:

Answer:

344.5764 torr

Explanation:

Molar mass of naphthalene = 128.2g/mol

Mass of naphthalene = 10.60 g

Carbon disulfide:

Molar mass= 76.14g/mol ;

volume = 155mL ;

density = 1.261 g/mL

Vapour pressure = 355.6 torr

Number of moles = mass / molar mass

CS2:

Mass = density × volume

Number of moles = (density × volume) / molar mass

Number of moles = (1.261 * 155) / 76.14 = (195.455 / 76.14) = 2.567 moles of CS2

Number of moles of C8H10:

Number of moles = 10.60 / 128.2 = 0.083 C8H10

Total number of moles :

2.567 + 0.083 = 2.65 moles

Mole fraction of each compound in solution :

CS2 :

2.567 / 2.65 = 0.969

C8H10:

0.083 / 2.65 = 0.031

According to Raoult's:

Psolution = Xsolvent × Posolvent

CS2 = solvent

Xsolvent = Mole fraction of solvent

Posolvent = Vapour pressure of pure solvent

Psolution = 0.969 × 355.6 torr = 344.5764 torr

The vapor pressure of the solution would be as follows:

\(344.5764\) torr

Given that,

Vapor pressure of Carbon Disulfide \(= 355.6\) torr

\(volume = 155mL ;\)

\(density = 1.261 g/mL\)

Naphthalene's mass \(= 10.60 g\)

Naphthalene's molar mass \(= 128.2g/mol\)

Now,

We know that

Number of moles \(= mass/molar mass\)

Mass \(= density\) × \(volume\)

\(Number of moles =\) \((density\) × \(volume) / molar mass\)

So,

Number of moles of Carbon Disulfide \(= (1.261\) × \(155) / 76.14\)

\(= (195.455 / 76.14)\)

\(= 2.567\) moles of Carbon Disulfide

Number of moles of Naphthalene:

Number of moles \(= 10.60 / 128.2\)

\(= 0.083\)

Now,

Total number of moles :

\(2.567 + 0.083\)

\(= 2.65\) moles

Mole fraction of each compound in solution :

Carbon Disulfide:

2.567 / 2.65

\(= 0.969\)

Naphthalene

0.083 / 2.65

\(= 0.031\)

According to Raoult's:

P\(solution = Xsolvent\) × \(Posolvent\)

Carbon Sulfide = Solvent

\(Xsolvent =\) Mole fraction of solvent

\(Posolvent =\) Vapour  pressure of the pure solvent

\(Psolution\) \(= 0.969\) × \(355.6 torr\)

\(= 344.5764\) torr

Thus, "\(344.5764\) torr" is the correct answer.

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Layer 1 because it is closest to the surface

Answer:

The combustion of hexane (C6H14) is represented in the balanced equation : 2 C6H14 + 19 O --- 12 CO2 + 14 H2O MM hexane 86.18 g/mole, O2 32 g/mole, CO2 44 g/ mole, H2O 18 g/mole A. If 45 g of hexane is reacted and 45 g of water is recovered.

Explanation:

The products of this reaction is 2C₆H₁₄ + 19O₂ = 12CO₂ + 14H₂O is carbon dioxide and water.

Combustion is  the process where a substance burns in the presence of oxygen, giving off heat and light in the process. The hydrocarbons burn in the presence of oxygen giving carbon dioxide and water along with release of energy and thus the process is exothermic.

Combustion is a high-temperature exothermic (heat releasing) redox (oxygen adding) chemical reaction between a fuel and an oxidant, usually atmospheric oxygen, that produces oxidized, often gaseous products, in a mixture termed as smoke.

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Answer:

flo-non metal

germ- metalloid

zinc - metal

phos- non metal

lithium- metal

The total mass of the balloon and its content is 1521.17 g, the number of moles of CO₂ in the balloon is 34.15 mol, and the number of CO₂ molecules in the balloon is 2.06 x 10²⁵ molecules.

a) The molar mass of CO₂ is 44.01 g/mol. To find the total mass of the balloon and its content, we need to add the mass of the balloon (20g) to the mass of the CO₂ inside the balloon.

Mass of CO₂ = number of moles of CO₂ x molar mass of CO₂

Since the balloon is at STP (standard temperature and pressure), we can use the molar volume of a gas at STP (22.4 L/mol) to find the number of moles of CO₂ in the balloon:

Volume of CO₂ = Volume of balloon = 765 L (at STP)

Number of moles of CO₂ = volume of CO₂ / molar volume of a gas at STP

                                          = 765 L / 22.4 L/mol

                                          = 34.15 mol

Mass of CO₂ = 34.15 mol x 44.01 g/mol

                       = 1501.17 g

Total mass of balloon and its content = 20 g + 1501.17 g

                                                               = 1521.17 g

b) Number of moles of CO₂ in the balloon is 34.15 mol

c) To find the number of CO₂ molecules in the balloon, we need to use Avogadro's number (6.02 x 10²³ molecules/mol).

Number of CO₂ molecules = number of moles of CO₂ x Avogadro's number

                                           = 34.15 mol x 6.02 x 10²³ molecules/mol

                                           = 2.06 x 10²⁵ molecules

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