In terms of drag why do airlines fly at such great heights when it costs morefuel to get up to the higher altitudes?

Answer:

Explanation:

a )

Hoverfly will fall with acceleration equal to g .

Initial velocity of fall of hoverflies u = 0

displacement ( vertical ) h = ?

time t = 0.2 s

acceleration due to gravity g = 9.8 m / s²

h = ut + 1/2 g t²

= 0 + .5 x 9.8 x .2²

= .196 m

= 19.6 cm

b )

Time taken to fall by 50 cm or 0.5 m under free fall from initial position .

.5 = 0 + .5 x 9.8 t²

t² = .1020

t = .319 s = 319 ms .

Answer:

The object in motion is deaccelerating in the negative direction.

Explanation:

Interpret the given position-time graph.

Observing the graph we can determine the slope is negative and is gradually flattening out. Thus, we can conclude the object in motion is deaccelerating in the negative direction.

(a) The work done by the force applied by the tractor is 79,968.47 J.

(b) The work done by the frictional force on the tractor is 55,977.93 J.

(c) The total work done by  all the forces is 23,990.54 J.

The work done by the force applied by the tractor is calculated as follows;

W = Fd cosθ

W = (5000 x 20) x cos(36.9)

W = 79,968.47 J

W = Ffd cosθ

W = (3500 x 20) x cos(36.9)

W = 55,977.93 J

W(net) = work done by applied force  -  work done by friction force

W(net) = 79,968.47 J -  55,977.93 J

W(net) = 23,990.54 J

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Answer:

jjjjjjjjjjjjjjjj

Explanation:

Answer:

Southernpole

Explanation:

Answer:

Venus' rotation and orbit are unusual in several ways. Venus is one of just two planets that rotate from east to west. Only Venus and Uranus have this "backwards" rotation. It completes one rotation in 243 Earth days — the longest day of any planet in our solar system, even longer than a whole year on Venus.

Brainliest would help!

Answer:

3, it's the igneous rock, sedimentary rock, and metamorphic rock i believe

Explanation:

Answer:

igneous, sedimentary, and metamorphic.

Explanation:

Answer:

D. Ted expanded more power.

Explanation:

Given the following data;

For Ted.

Force = 10N

Height = 1.5m

Time = 1 seconds

To find Ted's power;

Power = workdone/time

But workdone = force * distance

Workdone = 10 * 1.5

Workdone = 15 Nm

Power = 15/1

Power = 15 Watts.

For Johnny.

Force = 10N

Height = 1.5m

Time = 2 seconds

To find Ted's power;

Power = workdone/time

But workdone = force * distance

Workdone = 10 * 1.5

Workdone = 15 Nm

Power = 15/2

Power = 7.5 Watts

Therefore, from the calculations we can deduce and conclude that Ted expanded more power.

The open universe theory, states that the mass of the universe is not large enough for its gravity to slow down the expansion caused by the Big Bang, and it will continue expanding indefinitely.

This theory also known as the unbounded or infinite universe theory suggests that the geometry of the universe is flat, meaning that parallel lines will never meet or intersect, and that the total energy of the universe is zero. In an open universe, the expansion will not stop, and galaxies will continue to move away from each other at an increasing rate. This theory is supported by observations of the cosmic microwave background radiation, which provide evidence for the early expansion of the universe.

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Answer:

You have to compare the densities,

Explanation:

To find density:

1. Measure the object's weight

2. Divide the mass by the volume

Answer:

a)  y = 0.98 t², t=1s y= 0.98 m,  

b) he two blocks must move the same distance

c) v = 1.96 m / s,  d)  a = -1.96 m / s², e)  x = 0.98 m

Explanation:

For this exercise we can use Newton's second law

Big Block

Y axis

             N-W = 0

             N = M g

X axis

             T- fr = Ma

the friction force has the expression

             fr = μ N

             fr = μ Mg

small block

             w- T = m a

we write the system of equations

             T - fr = M a

             mg - T = m a

we add and resolved

             mg-  μ Mg = (M + m) a

             a = \(g \ \frac{m - \mu M}{m+M}\)

             a = \(9.8 \ \frac{10- 0.2 \ 20}{ 10 \ +\ 20}\)

             a = 9.8 (6/30)

             a = 1.96 m / s²

a) now we can use the kinematic relations

             y = v₀ t + ½ a t²

the blocks come out of rest so their initial velocity is zero

             y = ½ a t²

             y = ½ 1.96 t²

             y = 0.98 t²

for t = 1s y = 0.98 m

       t = 2s y = 1.96 m

b) Time is a scale that is the same for the entire system, the question should be oriented to how far the big block will move.

As the curda is in tension the two blocks must move the same distance

c) the velocity of the block M

           v = vo + a t

           v = 0 + 1.96 t

for t = 1 s v = 1.96 m / s

       t = 2 s v = 3.92 m / s

d) the deceleration if the chain is cut

when removing the chain the tension becomes zero

           -fr = M a

          - μ M g = M a

          a = - μ g

          a = - 0.2 9.8

          a = -1.96 m / s²

e) the distance to stop the block is

         v² = vo² - 2 a x

        0 = vo² - 2a x

        x = vo² / 2a

        x = 1.96² / 2 1.96

        x = 0.98 m

the time to travel this distance is

        v = vo - a t

        t = vo / a

        t = 1.96 /1.96

        t = 1 s

Answer : The volume of water in graduated cylinder is 15.5 mL.

Explanation :

As we know that for the measurement of the volume of liquid in graduated cylinder are shown by placing the graduated cylinder on the flat surface and then view the height of the liquid in the graduated cylinder with the naked eyes directly level with the liquid.

The liquid will tend to curve downward that means this curve is known as the meniscus.

In the case of colored liquid, we are always read the upper meniscus of the liquid for the measurement.

In the case of colorless liquid, we are always read the lower meniscus of the liquid for the measurement.

In the given image, there are 5 larger and 5 smaller division between the 15 and 20 and the solution is colored. The value of larger division is 1 mL and smaller division is 0.5 mL.

So, we will read the upper meniscus of the liquid for the measurement.

Hence, the volume of water in graduated cylinder is 15.5 mL.

Answer:

C.) Quadratic (power)

Explanation: I did the thingy and it worked

its not A or B

Answer:

C) Quadratic (power)

Explanation:

I took the physics exam

The cost of gas is $1.27 per liter and the gallon of gas costs $4.80. where 1 gallon is equal to 3.78541 liters.

To convert the cost of gas from dollars per liter to dollars per gallon, The conversion factor between liters and gallons.

1 gallon is equal to 3.78541 liters (the exact conversion factor is 3.785411784).

Given the cost of gas is $1.27 per liter, let's calculate the cost per gallon:

Cost per gallon = Cost per liter × Liters per gallon

Cost per gallon = $1.27 × 3.78541

Cost per gallon = $4.80

So, a gallon of gas costs $4.80.

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A force of 43.8 N is required to stretch the spring a distance of 15.5 cm = 0.155 m, so the spring constant k is

43.8 N = k (0.155 m)   ==>   k = (43.8 N) / (0.155 m) ≈ 283 N/m

The total work done on the spring to stretch it to 15.5 cm from equilibrium is

1/2 (283 N/m) (0.155 m)² ≈ 3.39 J

The total work needed to stretch the spring to 15.5 cm + 10.4 cm = 25.9 cm = 0.259 m from equilibrium would be

1/2 (283 N/m) (0.259 m)² ≈ 9.48 J

Then the additional work needed to stretch the spring 10.4 cm further is the difference, about 6.08 J.

Answer:

0.5 lambda(wavelength)

Explanation:

We know that

The first harmonic for both side open ended pipe is

L= 1/2lambda

So L = 0.5*wavelength

Hi there!

A)
Since the ball's velocity is initially only in the HORIZONTAL direction, there is NO vertical component of its velocity. Therefore, we can treat this like a free-fall scenario. (Dropped from rest).

We can rearrange the following kinematic equation to make solving for the time taken for the balls to hit the ground easier.

\(d_y = v_yt + \frac{1}{2}at^2\)

dy = vertical displacement (height of table, 0.85 m)

vy = initial vertical velocity (0 m/s, only horizontal)
a = acceleration (due to gravity in this situation, 9.8 m/s²)

t = time (? sec)
Simplify and rearrange the variables for 't'.

\(d_y = 0(t) + \frac{1}{2}at^2\\\\d_y = \frac{1}{2}at^2\\\\t^2 = \frac{2d_y}{a}\\\\t = \sqrt{\frac{2d_y}{a}}}\)

Plug in the given values.

\(t = \sqrt{\frac{2(0.85)}{9.8}} = \boxed{0.4165 s}\)

B)

Now, remember that the ball's acceleration in the vertical direction due to gravity does NOT impact its horizontal velocity. Its vertical and horizontal velocities are COMPLETELY independent. Thus, we can simply use the time solved for above and each ball's respective velocities in the following kinematic equation:
\(d_x = v_xt\)

dₓ= horizontal displacement (? m)

vₓ = horizontal component of velocity (3.5 and 5.3 m/s for A and B respectively)

t = time (0.4165 s)

Solve for the distance traveled by each ball:
Ball A:
\(d_x = 3.5 * 0.4165 = \boxed{1.458 m}\)

Ball B:
\(d_x = 5.3* 0.4165 = \boxed{2.207 m}\)

Answer:

What is the difference between quantum or nuclear physics?

How can I get the most out of Crunchbase Pro?

"Quantum physics" is an umbrella term for any field which uses the quantum formulation of the universe - I.e the postulate that observables are well defined as the eigenstates of Hermitian Operators, and all state wavefunctions obey the Schrödinger equation.

Basically all modern science uses quantum mechanics to a degree - astronomy needs it to predict the behaviour of white dwarfs, condensed matter for semiconductor behaviour and so on.

Nuclear physics is a field focussing on the internal structure and interactions of the nucleus. It lies well within the range of the quantum domain, and is 100% reliant on quantum physics to make any sensible predictions. Nuclear physics also has significant crossover with "particle physics", such that the two are quite often used interchangeably.

Nuclear Physics on the other hand, concerns itself with the particles of the nucleus called nucleons (protons & neutrons). ... In the nucleus the leading theory is quantum chromodynamics (QCD) which attempts to explain phenomena in terms of quarks which are the particles that are proposed to make up the nucleons.

The kinetic energy of an object with mass 5kg and a constant velocity of 15m/s is 562.5J.

Kinetic energy is the energy possessed by an object because of its motion, equal (nonrelativistically) to one half the mass of the body times the square of its speed.

The kinetic energy of an object can be calculated using the following formula:

K.E = ½ mv²

Kinetic energy = ½ × 5 × 15²

Kinetic energy = 562.5J

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A parallel circuit is an electrical circuit with more than one current path and all circuit components are connected between the same two sets of electrically common points. The current supplied by the source in a parallel circuit is equal to the sum of all branch currents in the circuit.

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Answer:

Explanation:

Neither do we. It's just a disconnected statement devoid of any context.

From English studies, an "an" leading the phrase means the following word starts with a vowel.

If the object is moving with varying speed, then the blank could be filled with

"unbalanced"

or

"accelerating"

If the object is dropping, then the blank could be filled with a frictional air resistance acting

"upward"

If the object is wiggling, try

"alternating"

If the object is flying, try

"aerodynamic"

I'm sure I could think of others , but it seems a waste of time guessing.

The type of evidence that was collected based on the information is a forensic evidence.

From the information, it was stated that Detective Lauren arrives at a crime scene of a drive by shooting. Crime Scene Investigator Molly collected bullet casings. The evidence was collected from the curb of the sidewalk using gloves and placed into baggies.

Therefore, the location where evidence was found is a crime scene.

The person who collected the evidence is Crime Scene Investigator Molly collected bullet casings.

The evidence was collected from the curb of the sidewalk using gloves and placed into baggies.

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Answer:

No, they should not trust the "scientific study" because the average headache last about 4 hours. After the 24 hours itself, the head ache would be gone, that's why 99% always say the headache "disappeared" The only way to prove the special water could do anything is if they did a study of the people who claim to have a headache to drink one bottle of the water and see what happens in the next 2-3 hours.

Explanation:

Answer:

This is obvious pseudoscience because the people could be lieing about there headache, because it's a very bonkers product, and there is no actually factual proof supporting there theory.

brainliest???

Answer:

This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.

The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.

The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).

The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:

R(n) = √(X² + Y²)

Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.

However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:

<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2

<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2

Because <X²> = <Y²>, we can write:

<R²> = <X²> + <Y²> = n A²

So, the root mean square distance (the square root of the mean square displacement) after n steps is:

R(n) = √(<R²>) = √(n) * A

Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.

The sentence that best describes the motion is "the motion is a circular motion and has completed one revolution".

Question: "If a car moved one full circular track of 15 Km, which sentence describes its motion?​"

An object moves in a circle at a constant speed in a motion known as uniform circular motion. Any point on a propeller, for instance, that is spinning continuously, is moving uniformly in circles.

There are two types of circular motion: uniform and non-uniform.

Circular motion can be seen in the orbit of a satellite, ice skaters moving at a constant speed in a circle, and vehicles traveling in a circle.

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Answer:

1)     R₁ > R₃ > R₂ correct B , 2) the wire that dissipates the most is wire 2

Explanation:

1) The resistance of a wire is given by the expression

          R = \(\rho \ \frac{l}{A}\)

where ρ is the resistivity of the material, l the length of the wire and A the area of ​​the wire

The area is given by

          A = π r² = π d² / 4

we substitute

         R = (ρ 4 /π)  \(\frac{l}{d^2}\)

the amount in parentheses is constant for this case

let's analyze the situation presented, to find the resistance of each wire

* indicate l₁ = l₂ and d₂ = 2 d₁

the resistance of wire 1 is

          R₁ = (ρ 4 /π)  \(\frac{l_1}{d_1^2}\)  

the resistance of wire 2 is

          R₂ = (ρ 4 /π) \frac{l_2}{d_2^2}

          R₂ = (ρ 4 /π)   \(\frac{l_1}{ (2 d_1)^2}\)

          R₂ = (ρ 4 /π ) \(\frac{l_1}{d_1^2}\)   ¼

          R₂ = ¼ R₁

* indicate that d₂ = d₃    and  l₃ = 2 l₂

           R2 = (ρ 4 /π)  \(\frac{l_2}{d_2^2}\)

the resistance of wire 3 is substituting the indicated condition

           R3 = (ρ 4 /π 2)  \frac{l_3}{d_3^2}

            R3 = (ρ 4 /π)   \(\frac{2 \ l_2}{d_2}\)

            R3 = 2 R₂

let's write the relations obtained

          R₁ = (ρ 4 /π)  \(\frac{I_1}{ d_1^2}\)

          R₂ = ¼ R₁

          R₃ = 2 R₂

let's write everything as a function of R1

           R₁ =(ρ 4 /π)   \(\frac{l_1}{d_1^2}\)

           R₂ = ¼ R₁

           R₃ = ½ R₁

the resistance of the wire in decreasing order is

           R₁ > R₃ > R₂

2) The power dissipated by a wire is

           P = V I

the voltage is

           V = I R

            I = V / R

substituting

          P = V² / R

therefore the power dissipated by each wire is

wire 1

           P₁ = V² / R₁

wire 2

           P₂ = V² / R₂

           P₂ = \(\frac{V^2}{ \frac{1}{4} R_1}\)

           P₂ = 4 P₁

wire 3

           P₃ = V² / R₃

           P₃ = \(\frac{V^2}{ \frac{1}{2} R_1}\)

           P₃ = 2 P₁

Therefore, the wire that dissipates the most is wire 2

Answer:

hpqfie

Explanation:

wdq i love math WOOOOO