No matter the detector, the pattern on the screen is still non-interference.
In the double-slit experiment, how does the detector operate?In the double-double slit experiment, photons are momentum entangled and can share information about each other's which-slit paths if one of them is found near any double slit. If a single slit of a double-slit is blocked, it is possible to determine the which-slit path from the simultaneous photon detection.
What impact does observation have on the double-slit test?In quantum physics, the double-slit experiment serves as a prominent illustration of the observer effect. The measured outcomes of this experiment can alter if quantum phenomena are observed, according to physicists.
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A bullet is fired upward with an initial velocity of 100 m/s. What will be it’s velocity when it hit the ground?
A bullet is fired upward with an initial velocity of 100 m/s. What will be it’s velocity when it hit the ground?
Zero. It is sitting on the ground. This would almost always “assume” a friction-less environment where the only force acting on the bullet is gravity. In this case, it would be 100 m/s immediately before hitting the ground. (zero once it comes to rest)
I NEED HELP PLEASE, THANKS! :)
A 20.0 cm tall object is placed 50.0 cm in front of a convex mirror with a radius of curvature of 34.0 cm. Where will the image be located, and how tall will it be? Please show all work.
Answer:
i = -12.7 cm; h = 5.07 cm
Explanation:
1. Find the focal length
The focal length of a concave spherical mirror is half of its radius of curvature.
f = ½r = ½ × 34.0 cm = 17.0 cm
2. Find the image distance
A convex mirror produces a virtual image behind the mirror, so the image distance is negative.
\(\begin{array}{rcl}\dfrac{1}{o} + \dfrac{1 }{i} & = & \dfrac{1}{f}\\\\\dfrac{1}{50.0} + \dfrac{1 }{i} & = & \dfrac{1}{-17.0}\\\\\dfrac{1}{i} & = & \dfrac{1}{-17.0} - \dfrac{1}{50.0}\\\\& = & \dfrac{50.0 - (-17.0)}{500\times(-17.0)}\\\\& = & \dfrac{67.0}{-850}\\\\i & = & \dfrac{-850}{67.0}\\\\& = & \textbf{-12.7 cm}\\\end{array}\)
3. Find the image size
\(\begin{array}{rcl}\\\\\dfrac{h_{\text{i}}}{ h_{\text{o}}} & = & -\dfrac{i}{o} \\\\\dfrac{h_{\text{i}}}{ 20.0} & = & -\dfrac{-12.7}{50.0} \\\\h_{\text{i}} & = & 20.0 \times \dfrac{12.7}{50.0}\\\\& = & \textbf{5.07 cm}\\\end{array}\)
4. A car accelerates at 2.5 m/s^2, covers 4 km in 0.8 min. How fast was it moving at the beginning
of the time interval? *
Answer:
Initial velocity, u = 23.33 m/s
Explanation:
Given the following data;
Acceleration = 2.5 m/s²
Distance = 4 km to meters = 4000 meters
Time = 0.8 mins to seconds = 0.8 * 60 = 48 seconds.
To find the initial velocity, we would use the second equation of motion;
\( S = ut + \frac {1}{2}at^{2}\)
Where;
S represents the displacement or height measured in meters.
u represents the initial velocity measured in meters per seconds.
t represents the time measured in seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
4000 = u*48 + ½*2.5*48²
4000 = 48u + 1.25*2304
4000 = 48u + 2880
48u = 4000 - 2880
48u = 1120
Initial velocity, u = 1120/48
Initial velocity, u = 23.33 m/s
A 1.5 kg baseball is pitched at 38 m/s and is hit by the batter. It heads directly back at the pitcher at 27 m/s.
a) Find the impulse applied to the ball.
b) If the bat is in contact with the bat for 0.45 sec, how much force was applied.
Show all your work.
Answer:
The initial velocity of the ball is +38.0 m/s. The final velocity is -27.0 m/s.
momentum = mass x velocity
(mass x final velocity) – (mass x initial velocity)
(1.5)(-27) – (1.5)(38) = -97.5
The impulse applied to the ball is -97.5 kg m/s
impulse = force x time interval
force = impulse/time interval
-97.5/0.45 s = - 216.6
The force applied was 216.6 N.
Putting the ball back into play by the offense is called a ____ ____
Answer:
Hand ball ?
Explanation:
The minute hand of a clock completes one revolution in one hour. There are 3,600 seconds in one hour. Calculate the frequency of the minute hand
The frequency of the minute hand is 1/60 Hz. Given that the minute hand of a clock completes one revolution in one hour and there are 3,600 seconds in one hour.
To calculate the frequency of the minute hand: Frequency of the minute hand = No. of revolutions per secondFirstly, let us calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 secondsIn one hour, the minute hand completes 1 revolution. So, in 1 second, the minute hand completes 1/3600 of the revolution.Now, we can calculate the frequency of the minute hand.
Frequency of the minute hand = No. of revolutions per second Frequency of the minute hand = 1/3600 HzTo calculate the frequency of the minute hand, we can use the following steps: Step 1: Calculate the number of revolutions of the minute hand in one second.1 hour = 60 × 60 = 3600 seconds In one hour, the minute hand completes 1 revolution.
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You have managed to get a vacation on the Moon where the gravitational field strength is 1.6 N/kg. Gleefully, you kick a ball of mass 1.25 kg with an initial velocity of < 12, 12, 0> m/s. There is a goal post you can use as an origin marker where you kicked the ball. What is the initial momentum of the ball?
The initial momentum of the ball is 15 Kgms-1.
What is momentum?In Physics, the term momentum is the product of mass and velocity. Momentum is a vector quantity. This implies that momentum possess both magnitude and direction.
Hence, we often write; p = mv
Where:
p = momentum
m = mass
v = velocity
The initial momentum therefore is;
p = 1.25 kg × 12 m/s = 15 Kgms-1
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What are all the terms that could be used to describe the wave that is produced when a person speaks?
Answer:
Sound
Amplitude Wave
Pitch
Strenght
Explanation:
24 How long does it take for the Earth to orbit the Sun?
A one day
B one week
C one month
D one year
Answer:
365 days
So The Final Answer is a Year
D is the answer
Explanation:
Answer:
C one month
Explanation:
fill in the blank. * a within subjects experiment is used to the the effect of light colour on mood. The experiment has a single light bulb with three different ambient colour schemes. The experiment features three rooms each with a different light bulb, there are ___ factors in this experiment.
1
Two factors. The independent variable is the light colour and the dependent variable is the mood. The ambient colour is not a factor as it is being controlled in each room.
A within-subjects experiment is used to assess the effect of light colour on mood. The experiment has a single light bulb with three different ambient colour schemes. The experiment features three rooms each with a different light bulb, there are factors in this experiment.
In this within-subjects experiment designed to assess the effect of light colour on mood, there is 1 factor being manipulated, which is the ambient colour of the light bulb.
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The mass of Venus is 81.5% that of the earth, and its radius is 94.9% that of the earth. Compute the acceleration due to gravity on the surface of Venus from these data.
To compute the acceleration due to gravity on the surface of Venus, we can use the formula for gravitational acceleration:
acceleration due to gravity = (G * mass of planet) / (radius of planet^2)
Given that the mass of Venus is 81.5% that of the Earth, we can calculate the mass of Venus as follows:
mass of Venus = (81.5/100) * mass of Earth. Similarly, the radius of Venus is 94.9% that of the Earth, so we can calculate the radius of Venus as follows:
radius of Venus = (94.9/100) * radius of Earth
Now, substitute these values into the formula for gravitational acceleration:
acceleration due to gravity on Venus = (G * mass of Venus) / (radius of Venus^2)
Finally, calculate the acceleration due to gravity on Venus using the given values and the formula.
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A skydiver jumps from a plane and falls for 5 seconds before reaching his terminal velocity. During this 5 seconds interval, describe his acceleration before reaching terminal velocity?
Answer:
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m
Explanation:
The terminal velocity is the maximum steady velocity attained by a body falling freely with increasing velocity from rest in a fluid, such as air or water
The net force, F acting on the body falling through the fluid is given as follows;
F = Weight force, W, from gravity - Drag force, D, from the fluid
F = W - D
Given that F = Mass, m × Acceleration, a, we have;
F = m × a
The acceleration, a = F/m = (W - D)/m
His acceleration during the first five seconds before reaching terminal velocity = (W - D)/m.
An airplane travels 640 miles from topeka to houston in 3. 2 hours, going against the wind. The return trip is with the wind, and takes only 2 hours. Find the rate of the airplane with no wind. Find the rate of the wind.
When an airplane travels 640 miles from Topeka to Houston in 3. 2 hours, going against the wind. The return trip is with the wind and takes only 2 hours. Then the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr
Let Va is the velocity of the airplane
Va is the velocity of the wind
When flying against the wind then
(Va+Vw)*(3.2 hours) = 640
3.2Va + 3.2Vw = 640
3.2Vw = 640 - 3.2Va
Vw = 200 - Va----------------(1)
When flying with the wind:
(Va-V)*(2 hours) = 640km
2Va - 2Vw = 640
Va - Vw = 320 ----------------(2)
Putting the value of VW in equation (2) we get
Va - (200-Va) = 320
2Va = 320 +200
2Va = 520
Va = 260
Putting this value in equation (2)
Vw =Va - 360
Vw = 100
Therefore the rate of the airplane with no wind is 260 miles/hr, and the rate of the wind is 100 miles/hr
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A 60 kilogram person jumps off a platform, landing while moving at 2. 0 meters per second. Determine the force exerted on the persons feet when he lands if he stops in 0. 25 seconds
The force exerted on the person's feet when he lands if he stops in 0. 25 seconds is found to be 480 N.
What is Force?Force may be characterized as a type of circumstance that significantly deals with the pushing or pulling of an object resulting from the object's interaction with another object. Whenever there is an interaction between two objects, there is a force upon each of the objects.
According to the context of this question,
The mass of a person, m = 60 Kg.
The velocity of a person, v = 2.0 meters/sec.
The time is taken, t = 025 seconds.
The formula for calculating force is as follows:
F = mv/t.= 60 × 2 ÷ 0.25 = 480 N.
Therefore, the force exerted on the person's feet when he lands if he stops in 0. 25 seconds is found to be 480 N.
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Q.7. For a system with a transfer function of G(s)=- co² s² +2a+w² if the natural frequency is 0.5 and the damping ratio is 1.3, which of the following statements is correct regarding the unit step response of the system?
O A) Damped
O B) Undamped
O C) Underdamped
O D) Crittically Damped
O E) Overdamped
The system described by the transfer function G(s) = -co² s² + 2a + w², with a damping ratio of 1.3 and a natural frequency of 0.5, has an overdamped unit step response. So, the correct option is (E)
The transfer function of the system is given as G(s) = -co² s² + 2a + w², where co represents the damping ratio, a represents an arbitrary constant, and w represents the natural frequency of the system. We are given that the natural frequency is 0.5 and the damping ratio is 1.3.
To determine the type of unit step response, we need to analyze the damping ratio (co) in relation to the critical damping value (co_critical).
The critical damping ratio (co_critical) is defined as the value where the system is on the threshold between being overdamped and underdamped. It is given by the formula co_critical = 2 * sqrt(a * w²).
In our case, the natural frequency (w) is 0.5, so we can calculate co_critical as follows: co_critical = 2 * sqrt(a * 0.5²).
Since the damping ratio (co) is given as 1.3, we can compare it with co_critical to determine the type of unit step response.
If co > co_critical, the system is considered overdamped (Option E).
If co = co_critical, the system is considered critically damped (Option D).
If co < co_critical, the system is considered underdamped (Option C).
Based on the given values, we can determine that the system is overdamped (Option E) because the damping ratio (1.3) is greater than the critical damping ratio.
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A small dog is 10 kg on the surface of the Earth. What is the
dog's weight, in N, on the moon?
Answer:
4 kg
Explanation:
because when you go the moon you lose 6 times your weight because of the gravitational pull
Answer:
16.3333333 newtons
Explanation:
on earth it would 98 newtons
what is atomic weight
Answer:
Its also know as atomic mass its the mass of isotopes.
Explanation:
relative atomic masses of sources in the local environment of the Earth's crust and atmosphere as determined by the atomic weight.
what is the phase defig. 1 resistor circuit1) find vr(t) and ir(t)2) what is the phase difference between vr(t) and ir(t)?
The phase defig in an resistor electrical circuit refers to the phase difference between the voltage and the current.
In a resistor circuit, the voltage (vr) and the current (ir) are related by Ohm's law: vr = irR, where R is the resistance of the resistor. To find vr(t) and ir(t), we need to know the time-dependent behavior of the voltage and the current.
Assuming that the circuit is driven by a sinusoidal voltage source with a frequency of ω, we can express the voltage and the current as vr(t) = Vrms*cos(ωt + φv) and ir(t) = Irms*cos(ωt + φi), where Vrms and Irms are the root-mean-square values of the voltage and the current, and φv and φi are the phase angles of the voltage and the current, respectively.
To find vr(t) and ir(t), we need to determine Vrms, Irms, φv, φi, and R. Once we have these values, we can use the above equations to calculate vr(t) and ir(t).
To determine the phase difference between vr(t) and ir(t), we need to calculate the phase angle φ = φv - φi. The phase angle represents the difference in time between the peaks of the voltage and the current waveforms.
In summary, the phase defig in an electrical circuit refers to the phase difference between the voltage and the current.
To find vr(t) and ir(t), we need to know the time-dependent behavior of the voltage and the current, which can be expressed in terms of Vrms, Irms, φv, φi, and R. The phase difference between vr(t) and ir(t) can be calculated as φ = φv - φi.
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An approximate value for the density of nuclear matter is 2.30 ✕ 1017 kg/m3. Determine the mass of a sphere (in kg) with a radius of 3.49 cm (about the size of a baseball) that has this same density.
Therefore, the mass of the sphere with a radius of 3.49 cm and the same density as nuclear matter is 4.65 ✕ 10^12 kg.
The density of nuclear matter is given as;
ρ = 2.30 ✕ 10^17 kg/m³
The formula for the volume of a sphere is;
V = (4/3)πr³ Where
r is the radius of the sphere.
Let's first convert the radius of the sphere to meters;
r = 3.49 cm = 0.0349 m
The volume of the sphere can be calculated as;
V = (4/3)π(0.0349 m)³ = 2.02 ✕ 10^-5 m³
The formula for the mass of an object is;
m = ρV
Substitute the given values;
m = (2.30 ✕ 10^17 kg/m³)(2.02 ✕ 10^-5 m³)
= 4.65 ✕ 10^12 kg
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A rocket weighing 560,000 N is taking off from Earth with a total thrust of
700,000 N at an angle of 20 degrees, as shown in the image below. What is
the approximate vertical component of the net force that is moving the rocket
away from Earth?
A. 76,000 N
B. 112,000 N
C. 132,000 N
D. 98,000 N
Answer:
D
Explanation:
LA FUERZA NETA ES LA FUERZA TOTAL DE EMPUJE MENOS EL PESO DEL
COHETE.
\(F_{y}\) = 700000 N(sen 90° - 20°) - 560000 N = 97785 N
The approximate vertical component of the net force that is propelling the rocket away from Earth is 112,000 N. Option B is correct.
The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. The thrust force is pointing upwards at an angle of 20 degrees, and the weight of the rocket is pointing downwards. The thrust force is the force that is generated by the rocket engine. It is the force that propels the rocket upwards.
The weight of the rocket is the force of gravity acting on the rocket. It is the force that pulls the rocket downwards. The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. If the net force is positive, the rocket will accelerate upwards. If the net force is negative, the rocket will accelerate downwards. If the net force is zero, the rocket will remain at rest.
net force = thrust force + weight
vertical component of net force = thrust force * cos(angle)
vertical component of net force = 700,000 N * cos(20 degrees) = 112,000 N. Option B is correct.
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The geocentric model could not explain which of the following observations made by early astronomers? Select the two correct answers
Mars and Jupiter appeared to move backwards for some period of time
The planets had epicycles
The stars appeared to move
Mercury and Venus changed in appearance throughout the year
s
Owing to the fact that planets orbits the sun at different speeds, Mars and Jupiter does appear to move backwards for some period of time. The geocentric model fails to explain this.
The geocentric model of the solar system is the approach that held the earth rather than the sun as the center of the solar system. The geocentric model was favored by most of the early astronomers.
However, as popular as the geocentric model of the solar system was, it failed to explain the phenomenon of retrograde motion which includes the apparent backward movement of Mars and Jupiter for some period of time.
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Answer:
My guess is
Explanation:
C or Mars and Jupiter appeared to move backwards for some period of time
B or The stars appeared to move
Sorry if i'm wrong
Physics
I’ll give brainiest! :)
the number of neutrons may b 21
Help me with this please anyone
Answer:
The 1st reaction is synthesis and the 2nd reaction is a double displacement.
The phenomenon of echo of sound waves is due to:
a. Reflection
b. Interference
c. Diffraction
d. All of the above
The phenomenon of echo of sound waves is due to reflection. The correct answer is Option A.
Echo is the reflection of sound waves off a surface. When sound waves hit a surface, they bounce back or reflect off that surface, creating an echo. This is similar to how light reflects off a mirror.
The reflected sound waves can be heard as an echo if the distance between the source of the sound and the reflecting surface is large enough for the reflected sound to be heard after the original sound. The reflection of sound waves is also what allows us to hear our own voices when we speak in a room with hard surfaces, such as a bathroom or an empty room.
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How many ammonium ions are present when one mole of ammonium is mixed with 5 moles of ammonium sulfate?
When one mole of ammonium is mixed with 5 moles of ammonium sulfate, there are 10 ammonium ions present.
When one mole of ammonium is mixed with 5 moles of ammonium sulfate, we need to determine how many ammonium ions are present.
First, let's determine the chemical formula of ammonium sulfate. Ammonium has a chemical formula of NH4+, and sulfate has a chemical formula of SO4^2-. To balance the charges, we need two ammonium ions for every sulfate ion. Therefore, the chemical formula of ammonium sulfate is (NH4)2SO4.
Next, we need to determine the number of moles of ammonium sulfate present when one mole of ammonium is mixed with 5 moles of ammonium sulfate. Since the molar ratio between ammonium and ammonium sulfate is 1:5, we can multiply the number of moles of ammonium by the ratio.
So, 1 mole of ammonium * 5 moles of ammonium sulfate/1 mole of ammonium = 5 moles of ammonium sulfate.
Finally, we need to determine the number of ammonium ions present in 5 moles of ammonium sulfate. Since there are 2 ammonium ions per mole of ammonium sulfate, we can multiply the number of moles of ammonium sulfate by 2.
So, 5 moles of ammonium sulfate * 2 ammonium ions/mole of ammonium sulfate = 10 ammonium ions.
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Which term describes the slope of the graph of song 2 beween minute 6 and minute 7?
The slope of song 2's graph between minute 6 and 7 is positive.
The slope of a graph represents the rate of change between two points on the graph. In this case, we are looking at the slope of the graph of song 2 between minute 6 and minute 7.
Based on the shape of the graph, we can see that the line is trending upwards from minute 6 to minute 7.
Therefore, the slope is positive. This means that as time increases by one minute, the value on the y-axis (likely representing the volume or intensity of the song) is also increasing.
In other words, the song is getting louder or more intense over the course of this minute.
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a motorcycle is being driven on a road moving north at 40 miles per hour. a car is driving on the same road moving south at 40 miles per hour. which of the following is true? a the motorcycle and car are moving at the same velocity and the same speed. b the motorcycle and the car are moving in opposite directions, so their velocities are different. c the motorcycle and the car are moving in opposite directions, so their speeds are different. d the motorcycle and car are moving at the same velocity but different speeds.
The motorcycle and the car are moving in opposite directions, so their velocities are different.
What is speed?Speed is the rate in which anyone travel.
In everyday use and in the kinematics, the speed of to every objects is the magnitude of the change of its own positions over the time or the magnitude of the change of its position per unit of the time; thus a scalar quantity.
A motorcycle is being driven by to the north on a road moving in the north at 40m per 1 hour. A car is driving on the same height the road moving at the south at 40m her 1 hour.
The motorcycle and a car are moving in to the opposite directions, so the velocities are different from each other.
As north and south both are opposite directions.
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How to convert 200ml to m(3)?
which planet is known as evening star
Answer:
Mercury is a metal that is used in
Mercury can be seen as an evening "star" near the sun's setting point or as a morning "star" near the sun's rising point. The evening star was given the name Hermes, and the morning star was given the name Apollo, since the ancient Greeks thought they were two separate things. Mercury, the Roman god's messenger, is the planet's name.
Three concentric conducting spherical shells have inner and outer radii of 0.1, 0.2, 0.3, 0.4, 0.5, 0.6 meters. The inner shell has a net charge of -1C, the middle shell has a net charge of -2C, and the outer shell has a net charge of -3C. There are no other charges in the system and all charges remain at rest. What is the surface charge density on the inner surface of the largest shell
The surface charge density on the inner surface of the largest shell is +0.95 C/m2. Therefore option B is correct.
All charges will reside on the outer surface of all shells because shells are conducting.
Given that the inner shell has a net charge of -1C, the middle shell has a net charge of -2C, and the outer shell has a net charge of -3C, the total charge enclosed by the largest shell is (-1C) + (-2C) + (-3C) = -6C.
The total charge on the inner surface of the largest shell will be +3C (due to induction of charge)
Therefore,
Charge density (σi) = +\({3C/4\pi (0.5)^2\)
= \(0.955\ c/m^2\)
Therefore, the surface charge density on the inner surface of the largest shell +\(0.955\ c/m^2\) is correct.
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