We know,
Q=CV
where C is the capacitance Q is the charge and V is the potential difference.
So with increase in potential difference the charge increases while teh capacitance decreases.
So the answers are:
increase the charge
decrease the capacitance
Which of these statements best describes how energy is transferred when an object experiences friction?
A.friction changes mechanical energy to light energy
B.friction changes mechanical energy to heat energy
C. Friction changes mechanical energy to chemical energy
The diagram below shows snapshots of an oscillator at different times . What is the frequency of the oscillation ?
In the diagram tha shows snapshots of an oscillator at different times, the frequency of the oscillation is 0.555 Hz.
How to calculate the periodThe period of the oscillation is the time taken for the for the object to return to its original position. (ie. Displacement = 0). From the above snapshot,
Period of oscillation = 1.80s.
From here, finding the frequency is simple as, Frequency = 1/Period. Hence,
Frequency = 1/1.80
= 0.555 Hz (3 sf).
The frequency of the oscillation is indeed 0.555 Hz. The frequency represents the number of oscillations or cycles per second. In this case, the object completes approximately 0.555 oscillations per second.
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The largest stars we know of have masses of a little over 1035 kilograms, while the lowest mass stars have masses of about 1032 kilograms. How many times more massive are the most massive stars than the lowest mass stars?
Group of answer choices
a thousand times more massive.
a hundred times more massive.
ten times more massive.
ten thousand times more massive
Answer:
the bigger stars tend to be hotter and burn through their fuel more quickly than smaller stars they also tend to ether be turned into a black hole or a huge nebula with a neutron star the smaller stars have a tendency to go through their fuel slower and don't get as hot as big stars until the red giant stage.
Explanation:
helpp tyy
Which of the following is a way to make magnets?
heating
freezing
pressure
heating or pressing but heating is most appropriate, so the answer is heating.
the mass of a density bottle is 18.00g when empty 44.00g when full of water, and 39.84g when full up of a second liquid. calculate the density of the liquid where density of water =1000kgm³
The density of the second liquid is 0.812 g/cm³
To calculate the density of the second liquid, we need to use the principle of displacement. The mass of the liquid can be found by subtracting the mass of the empty density bottle from the mass of the bottle filled with the liquid. Therefore, the mass of the liquid is:
mass of liquid = mass of bottle + liquid - mass of empty bottle
mass of liquid = 39.84g + x - 18.00g
where x is the mass of the liquid.
We can now use the density formula, which is:
density = mass/volume
The volume of the liquid is equal to the volume of the density bottle that is filled with the liquid, which can be calculated by subtracting the volume of the empty bottle from the volume of the bottle filled with the liquid. Therefore, the volume of the liquid is:
volume of liquid = volume of bottle filled with liquid - volume of empty bottle
We can now substitute this expression into the density formula to get:
density of liquid = mass of liquid / (volume of bottle filled with liquid - volume of empty bottle)
We know that the density of water is 1000 kg/m³, which is equal to 1 g/cm³. We can use this to find the volume of the liquid by dividing the mass of water by its density:
volume of water = mass of water / density of water
volume of water = 44.00g / 1 g/cm³
volume of water = 44.00 cm³
Now, we can calculate the volume of the density bottle filled with the second liquid by using the principle of displacement:
volume of bottle filled with liquid = volume of water - volume of liquid
volume of bottle filled with liquid = 44.00 cm³ - (39.84g - 18.00g) / 1 g/cm³
volume of bottle filled with liquid = 44.00 cm³ - 21.84 cm³
volume of bottle filled with liquid = 22.16 cm³
Finally, we can substitute these values into the density formula to get:
density of liquid = x / 22.16 cm³
Solving for x, we get:
x = density of liquid x 22.16 cm³
Substituting x back into the mass equation, we get:
mass of liquid = 39.84g + (density of liquid x 22.16 cm³) - 18.00g
Solving for the density of the liquid, we get:
density of liquid = (mass of liquid - 21.84g) / 22.16 cm³
Substituting the given values, we get:
density of liquid = (39.84g - 21.84g) / 22.16 cm³ = 0.812 g/cm³
In conclusion, the density of the second liquid is 0.812 g/cm³. This value is less than the density of water, which means that the second liquid is less dense than water and will float on top of water.
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A mouse of mass 200 g falls 100 m down a vertical mine shaft and lands at the bottom with a speed of 8.0 m/s. During its fall, how much work is done on the mouse by air resistance?
The work done on the mouse by air resistance is equal to 196 Joules.
Given the following data:
Mass = 200 grams to kg = 0.2 kg.
Distance = 100 meters.
Scientific data:
Acceleration due to gravity = 9.8 \(m/s^2\)
How to calculate work done.In Science, work done is generally calculated by multiplying force and the vertical distance or displacement experienced by an object.
Mathematically, work done is given by the formula:
\(Work\;done = force \times displacement = mgh\)
Substituting the given parameters into the formula, we have;
\(Work\;done = 0.2 \times 9.8 \times 100\)
Work done = 196 Joules.
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HELP PLEASE THIS IS URGENT!!!
The neutron number of an atom X, which undergoes alpha, and beta decay reduces the neutron number by 6.
Alpha decay is the nuclear process in which the parent nucleus emits an alpha or helium particle to form a daughter nucleus. When a particle emits an alpha nucleus, the nucleus loses its two protons and two neutrons. Beta decay is the nuclear process in which the parent nucleus undergoes the emission of electrons to produce a daughter nucleus.
Alpha decay decreases the atomic mass number decreases by 4 and the atomic number decreases by 2. In beta decay, the neutron is converted into a proton and the atomic number decreases by one. The neutron number is affected by alpha decay.
From the given,
X atom undergoes alpha decay. X -----> ₐ₋₂Xᵇ⁻⁴ + He₂⁴. The neutron number decreases by two. ₐ₋₂Xᵇ⁻⁴ -----> ₐ₋₂₋₂Xᵇ⁻⁴⁻⁴ + He₂⁴. The neutron number decreases by two.
When the X atom undergoes beta decay, ₐ₋₄Xᵇ⁻⁸---> ₐ₋₅Xᵇ⁻⁸ + ₋₁e⁰. The neutron number does not get affected. When the atom again undergoes alpha decay, ₐ₋₅Xᵇ⁻⁸ -----> ₐ₋₇Xᵇ⁻¹². Thus, the neutron number decreases by 6 when the atom undergoes three alpha decay.
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Force varies directly with pressure. A force of 22,000 newtons acts on an object, causing 110 N/m² of pressure. The
force decreases to 18,000 newtons. What is the new amount of pressure caused by the force?
○ 45 N/m²
90 N/m²
O 75 N/m²
60 N/m²
The final amount of pressure caused by the force is 90 N/m².
Initial amount of force, F₁ = 22 x 10³ N
Initial amount of pressure produced, P₁ = 110 N/m²
Final amount of force exerted, F₂ = 18 x 10³ N
Pressure is defined as the amount of force acting on an object per unit area of the object.
So, we can say that the force and pressure are directly proportional.
F ∝ P
So, F₁/P₁ = F₂/P₂
Therefore, the final amount of pressure caused by the force is,
P₂ = F₂P₁/F₁
P₂ = 18 x 10³x 110/22 x 10³
P₂ = 18/0.2
P₂ = 90 N/m²
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Ari and Martin are playing with tuning forks. Ari pulls out a tuning fork with an unknown frequency and hits it at the same time that Martin strikes a tuning fork with a frequency of 440 Hz. What are the possible frequencies of Ari's tuning fork? a) 440 Hz or 430 Hz Jay b) 4.4 Hz or 4.3 Hz. c) 443 Hz or 437 Hz d) There is not enough information to determine this answer
ANSWER:
d) There is not enough information to determine this answer
STEP-BY-STEP EXPLANATION:
Given:
Frequency 1 (f1) = 440 Hz
We have the following:
\(beats=∣f_1-f_2|\)We don't know the beats, therefore we can't determine the missing frequency.
This means that the correct answer is d) There is not enough information to determine this answer
HELP!! ASAP!!
The purple and blue characters represent atoms, and the red dots represent electrons. Explain the meaning of the cartoon image below as it relates to electronegativity. Which atom is more electronegative? Why? In addition, also explain where the most electronegative atoms are located on the periodic table.
The most electronegative atoms are located in the seventeenth group of the periodic table.
What is electronegativity?
The term electronegativity refers to the ability of an atom to attract the electrons of a bond towards itself. The more electronegative atom will have the electron pairs closer to itself.
Hence, in this case, the blue atom is more electronegative. The most electronegative atoms are located in the seventeenth group of the periodic table.
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what is the physics behind why electric parallel plates move from positive to negative
The physics behind the movement of electric charges between parallel plates is based on the principles of electrostatics. Electric charges are either positive or negative, and they are affected by electric fields.
Electric fields are created by a difference in electric potential, which is measured in volts. When a voltage is applied to a set of parallel plates, the charges within the plates will be affected by the electric field, and will move in response to it.
What are electric parallel plates?When a voltage is applied to a set of parallel plates, the positive charges in the plate connected to the positive voltage will be attracted to the negative voltage, while the negative charges in the plate connected to the negative voltage will be attracted to the positive voltage.
The movement of charges between the plates is also affected by the presence of any obstacles or resistances in the electric field, such as resistance in the wire. This can slow down the movement of charges and result in a decrease in the current flowing through the circuit.
In all, the movement of charges between electric parallel plates is the result of the electric field created by a difference in electric potential, and the movement of charges is called drift velocity. The movement is also affected by the presence of resistance.
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A ball rolls of buildings that is 100m high calculate the time that it takes for ball to hit the ground
Answer:
2as=v2-u2
2000=v2
V=44
V=u+at
44/10=t
T=4.4seconds
an ideal gas is flowing in a constant diameter pipe at a constant temprature. what is the relation of average velocity to pressure
Answer:
V = mRT / (\(\frac{\pi }{4}\)d²)PM
Therefore, pressure decreases as velocity increases.
This is a hypothetical concept as the friction which causes the velocity to increases also makes the pressure decrease.
Explanation:
Given the data in the question;
we know that an ideal gas equation is;
\(_p\) = PM/RT --------------- let this be equation 1
P is pressure, M is molecular weight, R is universal gas constant and T is the absolute temperature.
The volumetric flow rate from the continuity equation is;
Q = AV
and A = \(\frac{\pi }{4}\)d²
so, Q = (\(\frac{\pi }{4}\)d²)V ---------let this be equation 2
Expression for mass m in flowrate is;
m = Q\(_p\) ------------------let this be equation 3
so, m = (\(\frac{\pi }{4}\)d²)V × PM/RT
solve for V
V = mRT / (\(\frac{\pi }{4}\)d²)PM
Therefore, pressure decreases as velocity increases.
This is a hypothetical concept as the friction which causes the velocity to increases also makes the pressure decrease.
A plastic block of dimensions 2.00 cm x 3.00 cm x 4.00 cm has a mass of 30.0 g. What is its density?
Answer:
1.25 g/cm^3
Explanation:
mass-30.0g
volume- 4cm×2cm×3cm=24cm^3
density?
*to find density
Density=Mass/Volume
=30÷24
=1.25g/cm^3
When you sweat, what is the external stimuli? I need help asap.
Answer:
An External Stimulus is a stimulus that comes from outside an organism. Examples: You feel cold so you put on a jacket. When you sweat, the external stimulus is either you're anxious or hot.
Explanation:
hope it helps! <3
The answer is not B.
Answer:
D
Explanation:
15m/ s
i hope this helps
Cs-124 has a half-life of 30.8 s
A) If we have 7.5 μg initially, how many Cs nuclei are present?
B) How many nuclei are present 2.6 min later?
A) There are 3.70 x 10¹⁶ Cs nuclei present initially and B) There are 2.27 x 10¹⁵ Cs nuclei present 2.6 min later.
A) To solve this problem, we can use the following equation,
\(N = N'2^{\frac{-t}{T_{1/2}}}\)), number of Cs nuclei present is N, initial number of Cs nuclei present is N', elapsed time is t, half-life of Cs-124 is T½. First, we need to convert the initial mass of Cs-124 to the number of nuclei present,
7.5 μg Cs-124(1g/10⁶μg)(6.022x10²³nuclei/1g)
= 4.52 x 10¹⁵ Cs-124 nuclei.
Using the equation above, we can find the number of Cs-124 nuclei present after 0 s,
\(N = 4.52 * 10^{15} * 2^{\frac{-0}{30.8}}}\)
= 4.52 x 10¹⁵ Cs-124 nuclei
Therefore, initially, there are 4.52 x 10¹⁵ Cs-124 nuclei present.
B) After 2.6 min (156 s), we can again use the same radioactivity equation to find the number of Cs-124 nuclei present,
\(N = 4.52 * 10^{15} * 2^{\frac{-156}{30.8}}}\)
N = 1.60 x 10¹⁴ Cs-124 nuclei
Therefore, 2.6 min later, there are 1.60 x 10¹⁴ Cs-124 nuclei present.
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Two identical objects A and B of mass M move on a one-dimensional, horizontal air track. Object B initially moves to the left with speed vo. Object A initially moves to the right with speed 3vo, so that it collides with object B. Friction is negligible. Express your answers to the following in terms of M and vo.
(a) Determine the total momentum of the system of two objects.
(b) A student predicts that collision will be totally inelastic (the objects stick together on collision). Assuming this is true, determine the following for the two objects immediately after the collision. i. the speed ii. the direction of motion.
I 'm having trouble in how to approach the problem, specifically when to use inelastic or elastic.
a) Total momentum before collision is: \(\mathrm{\rho = M \times 3v_0 - M \times v_0 = 2M \times v_0}\)
b) Immediately after the collision, two objects move together with a speed of v₀. The direction of motion is to the right, as A was moving to right before collision.
What is momentum?Momentum may be defined as the product of mass and velocity of any object.
(a) Before the collision, total momentum of the system is :
\(\mathrm{\rho = m_A \times v_A + m_B \times v_B}\)
\(\mathrm{m_A = m_B = M, v_A = 3v_0, \ and \ vB = -v_0}\) (since B is moving to the left).
Therefore, total momentum before the collision is:
\(\mathrm{\rho= M \times 3v_0 - M \times v_0 = 2M \times v_0}\)
(b) Immediately after the collision, the two objects move with the same velocity v. Total momentum of the system is: p' = (mA + mB) × v = 2M × v
As total momentum is conserved: p' = p
\(\mathrm{2M \times v = 2M \times v_0}\)
\(\mathrm{v = v_0}\)
Therefore, immediately after the collision, two objects move together with a speed of v₀. The direction of motion is to the right, since A was moving to the right before collision.
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If the_____of a wave increases, its frequency must decrease.
a. period
b. energy
c. amplitude
d. velocity
Answer:wrong. Jts not velocity. Its period.
Explanation:
Took the test
Sir Dudley the Dextrous is loading cannons on top of the castle's tallest towers in preparation for an expected attack. He slips, and a cannonball of mass 18.0 kg rolls to the edge of the tower, which has a perfectly horizontal surface, and falls to the ground below. It takes the cannonball 1.15 s to fall to the ground, and air resistance is negligible. How much work is done by gravity on the falling cannonball? During the fall, what is the average power transfer to the cannonball due to the force of gravity?
The cannonball experiences a 997.4 W average power transfer from the force of gravity.
How does gravity impact the cannonball's trajectory?The cannonball drops from rest the same distance that it did when it was simply dropped (refer to diagram below). Yet, the projectile's horizontal motion is unaffected by the gravity present.
The cannonball's gravitational potential energy, which is determined by the following formula, is equal to its potential energy when it is at rest on the tower.
PE = mgh
PE = (18.0 kg)(9.81 m/s²)(height of tower)
When the cannonball strikes the ground, it has the following kinetic energy:
KE = (1/2)mv²
The following factors determine the cannonball's kinetic energy at impact:
v = gt
v = (9.81 m/s²)(1.15 s) = 11.27 m/s
Substituting m = 18.0 kg and v = 11.27 m/s, we get:
KE = (1/2)(18.0 kg)(11.27 m/s)² = 1146.56 J
As a result, the typical power transmission is:
P = W/t = 1146.56 J / 1.15 s = 997.4 W
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where is the mask of the vehicle that has 50,000 N and 25 m/s/s
The vehicle has a 2000kg mass.
briefly? Is the formula for F MA in Newtons?Take a mass's acceleration into account. Use the formula F = m a to determine the force's value. Kilogram-meter/second-squared will be used as the unit of force. The short name for this unit, which is made up of the three basic SI units, is newton.
F= ma
m= F/a
m= 50000/25
m= 2000 kg
What is an easy way to define Newton's second law?According to Newton's Second Law of Motion, acceleration (gaining speed) occurs whenever a force acts on a mass (object). This law of motion is best demonstrated by riding a bicycle. The mass is your bicycle. The force that propels you forward on your bicycle comes from your leg muscles.
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Question 2 of 25
Which symbol in the first law of thermodynamics represents the result of a
gas expanding against a constant pressure?
O A. a
B. V
C. U
D. W
Answer: The symbol representing the result of a gas expanding against a constant pressure is W
Explanation:
According to first law of thermodynamics, energy can neither be destroyed nor created but rather transferred to one place to another and converted to and from other energy forms.
The mathematical form of first law of thermodynamics is:
\(\Delta U=q+W\)
where \(\Delta U\) = change in internal energy
q = heat absorbed or released
W = work \((W= P\Delta V)\)
P = pressure
\(\Delta V\) = volume change
Thus the changes in heat or work leads to change in internal energy.
how much force is needed to accelerate a 1000 kg car at a rate of 3 m/s^2
Answer:
3000N
Explanation:
hence, the force needed to accelerate the 1000kg car by 3m/s2 is 3000N
The airport has a new plane that can go from 0 miles per hour to 100 miles per hour in 10 seconds. What is being described about the new plane?
a. acceleration
b. speed
c. velocity
d. magnitude
Answer:
acceleration
Explanation: how fast something can get to a certain speed
Given an average cell is ten times the mass of a bacterium. The mass of a bacterium is 10-15 kg. And a person's mass is 65 kg.
Given the mass of the cell is 1 * 10⁻¹⁴ kg, the number of cells in the 65 kg person is 6.5 * 10¹⁵ cells.
What is the number of cells in a person weighing 65 kg?The number of cells in a human is calculated as follows:
The mass of an average cell is ten times the mass of a bacterium.
The mass of a bacterium = 1 * 10⁻¹⁵ kg
mass of an average cell = 10 * 1 * 10⁻¹⁵ kg = 1 * 10⁻¹⁴ kg
Number of cells = mass of person/mass of cell
Number of cells = 65 kg/1 * 10⁻¹⁴ kg
Number of cells = 6.5 * 10¹⁵ cells.
In conclusion, the number of cells is obtained by dividing the mass of the person by the mass of a average cell.
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Note that the complete question is given below:
Assuming the mass of an average cell is ten times the mass of a bacterium (which is 10⁻¹⁵ kg): Calculate the number of cells in a human assuming the mass of the person is 10² kg.
PLEASE HELP ASAP WILL GIVE BRAINLIEST
Explanation
(m) is measured in kilograms (kg)
(F) is measured in newtons (N)acceleration (a) is measured in metres per second squared (m/s²)Q1) ~mass (m) is measured in kilograms (kg)
Q2)~acceleration (a) is measured in metres per second squared (m/s²)
Q3)~force (F) is measured in newtons (N)
Hope this helped you- have a good day bro cya)
a constant force of magnitude F=45 N and making an angle of 30 to the horizontal is applied on a stationary block placed on the floor over a distance of 8 m. the work done by the force
The work done by the force on the block is approximately 311.2 Joules.
To calculate the work done by the constant force of magnitude F = 45 N over a distance of 8 m at an angle of 30 degrees to the horizontal, we need to find the component of the force that acts parallel to the displacement.
The horizontal component of the force can be calculated using trigonometry:
F_horizontal = F * cos(angle)
= 45 N * cos(30 degrees)
= 45 N * (√3 / 2)
≈ 38.9 N
Now, we can calculate the work done by the force using the equation:
Work = Force * Distance * cos(theta)
where theta is the angle between the force and the displacement.
Work = F_horizontal * Distance * cos(0)
= 38.9 N * 8 m * cos(0)
= 38.9 N * 8 m
= 311.2 Joules
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The pressure of a constant volume gas thermometer is 2100N/M squared at 38c. What will be the temperature of the gas when the pressure is increased by 1/3?
Answer:
Explanation:
In
Curtis, a student in our class, makes the following statement: The puck reached a slightly higher location on the ramp than I predicted. This is because I used the wrong mass for the puck when I did all my calculations. I accidentally used the mass of the smaller puck rather than the mass of the larger puck in my video." Is this a plausible explanation? Would the using the wrong mass for the puck during the calculations mean the puck would reach a greater height? Explain your reasoning.
Answer and Explanation: No, the explanation is not plausible. The puck sliding on the ice is an example of the Principle of Conservation of Energy, which can be enunciated as "total energy of a system is constant. It can be changed or transferred but the total is always the same".
When a player hit the pluck, it starts to move, gaining kinetic energy (K). As it goes up a ramp, kinetic energy decreases and potential energy (P) increases until it reaches its maximum. When potential energy is maximum, kinetic energy is zero and vice-versa.
So, at the beginning of the movement the puck only has kinetic energy. At the end, it gains potential energy until its maximum.
The representation is as followed:
\(K_{i}+P_{i}=K_{f}+P_{f}\)
\(K_{i}+0=0+P_{f}\)
\(\frac{1}{2}mv^{2} = mgh\)
As we noticed, mass of the object can be cancelled from the equation, making height be:
\(h=\frac{v^{2}}{2g}\)
So, the height the puck reaches depends on velocity and acceleration due to gravity, not mass of the puck.
In simple harmonic motion when the speed of the object is maximum,the acceleration is zero.Is this statement true or false
True
Explanation
Simple harmonic motion, in physics, repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side
At the equilibrium position, the velocity is at its maximum and the acceleration (a) has fallen to zero.
so, for example in the graph, at A the velocity is at its maximum, and the acceletion is zero,
therefore, the statement is
True