mark bought 8 boxes .A week later half of all his boxes were destroyed in a fire there are now only 20 boxes left. With how many did he start with?
SHOW YOU WORK PLEASE

Answer:

D. p - 0.20p

Step-by-step explanation:

(b) By solving the dual problem graphically, we find that the optimal solution occurs at the vertex (0, 2) with a minimum value of W = 10. The shadow price for resource 1 (x1 + x3 ≤ 3) in the primal problem is 10. This means that an additional unit of resource 1 would increase the objective function value by 10. The shadow price for resource 2 (x2 + 2x3 ≤ 5) in the primal problem is 0. This indicates that the optimal solution is not sensitive to changes in resource 2.

(a) To construct the dual problem, we will assign dual variables y1 and y2 to the constraints of the primal problem and convert the objective function to the dual form. The dual problem has two constraints corresponding to the resources in the primal problem. The objective function in the dual problem represents the costs or prices associated with the resources.

(b) To solve the dual problem graphically, we will plot the feasible region and find the optimal solution.

Constraint 1: y1 + y2 ≥ 2

Rearranging the inequality, we get:

y2 ≥ 2 - y1

Constraint 2: y1 + 2y2 ≥ 6

Rearranging the inequality, we get:

y2 ≥ (6 - y1) / 2

The feasible region is the intersection of the two constraint inequalities, taking into account the non-negativity constraints y1 ≥ 0 and y2 ≥ 0.

Now, let's plot the feasible region on a graph:

Starting with the y-axis, plot points (0, 2) and (0, 3) to represent the non-negativity constraint y2 ≥ 0.

Next, draw a line with a slope of -1 passing through the point (0, 2).

Draw another line with a slope of -0.5 passing through the point (0, 3).

The feasible region is the area bounded by these two lines and the y-axis.

To find the optimal solution, we need to evaluate the objective function at the vertices of the feasible region.

Vertices of the feasible region:

(0, 2)

(0, 3)

Now, substitute these vertices into the objective function:

For (0, 2):

W = 3(0) + 5(2) = 10

For (0, 3):

W = 3(0) + 5(3) = 15

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Answer:

\(-21 < 109\)

Step-by-step explanation:

Given

\(Savings = \$109\)

\(Checking = -\$21\)

Required

Represent as an inequality

On a number line -21 comes before 109 (from left to right)

This means that -21 is smaller/lesser than 109.

So, the inequality that compares the two account values is:

\(-21 < 109\)

Answer:

the answer is C

Step-by-step explanation:

this is because it passes the vertical and horizontal line test

Answer:

C

Step-by-step explanation:

Answer:

12 miles

Step-by-step explanation

56.75 - 2.75 = 54

1/2(54/2.25)

The process capability ratio is approximately 0.67 (option A).

To calculate the process capability ratio, we need to use the following formula:

Process Capability Ratio = (Upper Specification Limit - Lower Specification Limit) / (6 * Process Standard Deviation)

Given the following values:

Upper Specification Limit = Diameter + Tolerance = 6.77 cm + 0.01 cm = 6.78 cm

Lower Specification Limit = Diameter - Tolerance = 6.77 cm - 0.01 cm = 6.76 cm

Process Standard Deviation = 0.005 cm

Plugging these values into the formula, we have:

Process Capability Ratio = (6.78 cm - 6.76 cm) / (6 * 0.005 cm)

Process Capability Ratio = 0.02 cm / 0.03 cm

Process Capability Ratio ≈ 0.67

Therefore, the process capability ratio is approximately 0.67. The correct answer is A) 0.67.

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The maximum volume of the largest rectangular box that can be inscribed in the ellipsoid can be calculated by finding the x, y, and z coordinates in the first octant that satisfy the equation (x^2/4) + (y^2/64) + (z^2/49) = 1.

Since the box must have edges parallel to the axes, the coordinates will also be the lengths of the box's edges. From the equation, we get the x coordinate to be 2, the y coordinate to be 8, and the z coordinate to be 7.

The volume of the box is the product of its edges, so the maximum volume of the box is V = 8xyz = 8 * 2 * 8 * 7 = 896.

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EXPLANATION

The division is equal to:

First we need to write the problem in long division format:

8.0 /_ 9.92

Divide 9 by 8 to get 1:

1

8.0 /_ 9.92

Multiply the quotient digit (1) by the divisor 8:

1

8.0 /_ 9.92

8

Subtract 8 from 9:

1

8.0 /_ 9.92

8

1

Add a decimal point to the solution

Bring down the next number of the dividend

1.

8.0 /_ 9.92

8

19

Answer:

1,845.2 M^3

Step-by-step explanation:

The volume of a pyramid with a square base can be calculated using the formula V=(1/) * (Base area) * Height). The base of a square is equal to the square of one side, so the base area of this pyramid is 15.2^2=230.4 m^2. the volume of the pyramid is then (1/3) * 230.4 * 21.3. 1,845.2 M^3

Answer:

\(\frac{10969}{260}\)

Step-by-step explanation:

Answer:

XDdddDddDDDDDDDDDDDDDDDDDDD

The total Number of tomato plants in the array is 100.

In a 10-by-10 array of tomato plants, there are 100 tomato plants arranged. Here, we have to determine the numbers of plants in each row and column, as well as the total number of plants.

In an array, we have rows and columns. If we have a total of 100 tomato plants, we have to divide the number of plants by the number of rows or columns, since the rows and columns are equal.

So, for 10 rows, each row contains 100/10 = 10 plants, and for 10 columns, each column contains 100/10 = 10 plants. In this example, each row and column contains the same number of plants, and the array is a square array.

Since there are ten rows and ten columns, each containing ten plants, the total number of plants is 10 x 10 = 100 plants.

In conclusion, a 10-by-10 array of tomato plants contains 100 tomato plants arranged.

Each row and column contain ten plants, and the array is square.

The total number of tomato plants in the array is 100.

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Answer:

p is 16 and N is 49.

Step-by-step explanation:

Answer:

p = 16

n = 49

Step-by-step explanation:

p + n = 65

p + 3.55n = 189.95

To solve this system of equations, you have to use substitution.  This means that you have to set one equation equal to one of the variables.  You then have to substitute that variable into the second equation.

Rearrange the first equation so that it equals p.

p + n = 65

p = 65 - n

Substitute the p-value into the second equation.

p + 3.55n = 189.95

(65 - n) + 3.55n = 189.95

Solve for n.

65 - n + 3.55n = 189.95

65 + 2.55n = 189.95

(65 + 2.55n) - 65 = 189.95 - 65

2.55n = 124.95

(2.55n)/2.55 = 124.95/2.55

n = 49

Use this n-value to solve for p.  You can pick whichever equation you want to solve for p and get the same answer.  I will use the first answer.

p + n = 65

p + 49 = 65

(p + 49) - 49 = 65 - 49

p = 16

There are 16 pounds of almonds and 49 pounds of cashews.

Given:

A figure of a quadrilateral.

To find:

The measures of angle 1 and angle 2.

Solution:

The given figure has two pairs of congruent adjacent sides. So, the quadrilateral in the figure is a kite.

We know that the diagonals of a kit are perpendicular to each other at the point of intersection.

\(m\angle 1=90^\circ\)

According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees.

\(90^\circ+65^\circ+m\angle 2=180^\circ\)

\(155^\circ+m\angle 2=180^\circ\)

\(m\angle 2=180^\circ-155^\circ\)

\(m\angle 2=25^\circ\)

Therefore, the correct option is C.

The equation that has a value greater than 7,245 is three-halves times 7,245

From the question, we are to determine the value that is greater than the given number

From the given information,

The number is 7,245

to determine the number that it greater than 7,245, we will evaluate each of the given options

one-third times 7,245

That is,

1/3 × 7245 = 2,415

two-thirds times 7,245

That is,

2/3 × 7245 = 4,830

three-thirds times 7,245

That is,

3/3 × 7245 = 7,245

three-halves times 7,245

That is,

3/2 × 7245 = 10,867.5

Hence, the value is three-halves times 7,245

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Answer:

4/18 and 15/18

Step-by-step explanation:

trust me bro

Answer:4/18 and 15/18

Step-by-step explanation:trust the progres kk

Answer:

1/4 in fraction form or in decimal form its 0.25

Step-by-step explanation:

Answer: 4

Explanation: To solve (⁵⁵⁄₅) ÷ (¹¹⁄₄), you must follow PEMDAS. And so, I'd divide what's inside the parentheses. 55 divided by 5 is 11, and 11 divided by 4 is 2.75. Now, our equation should look like this: 11 ÷ 2.75. After dividing, you should get a quotient of 4.

I hope this helped!

Good luck <3

Answer:

yes

Step-by-step explanation:

Both of the figures have the same perimeter (4n + 4) hence equal in perimeter,

We know the perimeter of any 2D figure is the sum of the lengths of all the sides except the circle and the area of a rectangle is the product of its length and width.

We know the perimeter of a rectangle is 2(length + width) and the perimeter of a square is 4×side.

Given, A rectangle with sides of length n+2 and n.

∴ Perimeter = 2((n + 2) + n)

= 2(2n + 2).

= 4n + 4.

Also given, A square with sides of length n + 1.

∴ Perimeter = 4(n + 1).

= 4n + 4.

So, yes the two shapes are equal in the perimeter.

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The best measure of variability is the standard deviation.

Player A is the most consistent, with an IQR of 1.5.

Standard deviation is defined as the square root of the variance is used to calculate the standard deviation, a statistic that expresses how widely distributed a dataset is in relation to its mean.

The table shows the number of goals made by two hockey players.

Player A:

2, 3, 1, 3, 2, 2, 1, 3, 6

Using  a statistics calculator, we have:

Mean = 2.56

S.D. = 1.51

Player B:

1, 4, 5, 1, 2, 4, 5, 5, 11

S.D. = 3.03

The best measure of variability is the standard deviation.

Player A is the most consistent, with an IQR of 1.5.

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If Mr. Jamison bought 8 dozen sketch pencils, 6dozen colored pencils and 3 dozen art gum, with a sales tax of 8 percent, considering each dozen of sketch pencils costed $x, colored pencils costed $y and art gums costed $z, the total bill approximately would be

$[(8x + 6y + 3z) + 0.08(8x + 6y + 3z)].

As per the question statement, Mr. Jamison bought 8 dozen sketch pencils, 6dozen colored pencils and 3 dozen art gum, with a sales tax of 8 Percent, and since no information is provided about the price of the sketch pencils, colored pencils or art gums, let us consider that each dozen of sketch pencils costed $x, colored pencils costed $y and art gums costed $z.

We are required to calculate the total approximate bill, Mr. Jamison would have to pay for the items he picked up.

To solve this question, first we will have to calculate the total price of the items he picked, without any taxes, i.e.,

$[(8 * x) + (6 * y) + (3 * z)] = $(8x + 6y + 3z).

Now an 8% sales tax on the price of the items bought will be

8% of $[(8x + 6y + 3z), i.e.,

[(8/100) * (8x + 6y + 3z)]

= $[0.08(8x + 6y + 3z)]

Therefore, total bill = (Total item costs + tax)

                                = $(8x + 6y + 3z) + $[0.08(8x + 6y + 3z)]

                                = $[(8x + 6y + 3z) + 0.08(8x + 6y + 3z)]

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The theorem states that if T is a translation along a line l, then T is also a translation along any line l' that is parallel to l.

To prove the theorem, let's consider a translation T along a line l. By definition, a translation preserves distances and directions. Now, let's consider a line l' that is parallel to l.

Since l' is parallel to l, any point on l' will have the same distance and direction from the corresponding point on l. In other words, for any point P on l', there exists a corresponding point Q on l such that the distance and direction between P and Q are the same.

Now, when we apply the translation T along l, it will move every point on l by the same distance and in the same direction. Since l' is parallel to l, the corresponding points on l' will also be moved by the same distance and in the same direction. Therefore, T is also a translation along l'.

Hence, we have proved that if T is a translation along a line l, then T is also a translation along any line l' that is parallel to l.

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The data set which has the smallest IQR is "Option C" - Final exams

Mid-term : 73,78,80,81,82,86,87,90,92,95,96

Q1 = 80

Q2 (median) = 86

Q3 = 92

IQR = Q3 - Q1 = 92 - 80 = 12

Midterm = 12

Finals : 75,78,78,78,81,82,83,83,85,85,100

Q1 = 78

Q2 = 82

Q3 = 85

IQR = Q3 - Q1 = 85 - 78 = 7

Finals = 7

12 > 7

Thus,

Midterm > Finals

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Full Question:

Although part of your question is missing, you might be referring to this full question:

The table below shows data for a class's mid-term and final exams:

Mid-Term Final

96 100

95 85

92 85

90 83

87 83

86 82

82 81

81 78

80 78

78 78

73 75

Which data set has the smallest IQR?

A. They have the same IQR

B. Mid-term exams

C. Final exams

D. There is not enough information

By using midpoint theorem of triangles we can get the value of x as 6 and the length of SR is also 6 units.

A line segment constructed by joining the midpoints of two triangle sides will be parallel to the third side and have a length that is half that of the third side, according to the midpoint theorem, also known as the midline theorem.

Therefore from the above property we can write

IK=2SR

or, 3x-6 = 2(2x-6)

or, 3x-6 = 4x - 12

or, -x = -6

or, x = 6

Therefore the length of SR is 6 units and the length of x is also 6 units.

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On solving the provided question, we can say that Considering that the test statistic inside the lower tail the rejection zone, the null hypothesis should be rejected.

A null hypothesis is a kind of statistical hypothesis that asserts that a specific set of observations has no statistical significance. Using sample data, hypotheses are tested to determine their viability. Sometimes known as "zero" and symbolized by H0. Researchers start off with the presumption that there is a link between the variables. In contrast, the null hypothesis claims that there is no such association. Although the null hypothesis may not appear noteworthy, it is a crucial component of research.

\(H0:p=0.25\) (null hypothesis)

\(H0:p \neq 0.25\) (alternative hypothesis)

Do not reject the null because the test statistic\((-1.2) is >\) \(the critical value (-1.7531)\)

Considering that the test statistic is inside the lower tail of the rejection zone, the null hypothesis should be rejected.

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The measure of the angle JKL as per the attached diagram is equal to 97 degrees.

As per in the question,

Diagram is attached.

Angle JKL is linear pair angle with given angle of measure 83 degrees.

Sum of the pair of linear pair is always equal to 180 degrees.

Let 'x' be the measure of angle JKL, we get,

83° + m ∠JKL = 180°

Subtract 83° from both the side of the equation we get,

⇒ 83° - 83° + m ∠JKL = 180° - 83°

⇒ m ∠JKL = 97°

Therefore, the measure of the angle JKL as per the attached diagram is equal to 97 degrees.

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Let be "t" the total amount of money you will receive.

According to the information given in the exercise, you can sell each share of Michaels Flowers at $7.28. Since you sell 175 of them, you get:

You also know that you can sell each share of Nanotech One at $10.80. Therefore, the amount of money you'll receive for these shares of Nanotech One, can be calculated by multiplying the price of one share by the 445 shares you will sell:

Then, you can set up that:

The answer is: $6,080

The Frequency Distribution table is shown below.

The proportion of one event's frequency to all events' frequencies in a statistical experiment.

Divide the frequency by the total number of data values to obtain the relative frequency. Add all of the earlier relative frequencies to the relative frequency for the current row to obtain the cumulative relative frequency.

Given:

The Frequency Distribution table is as follow:

Bin                           Frequency     relative Frequency        Cumulative        

                                                                                                Frequency

0- 5000                        4                    4/25 x 100 = 16%            4

5000 - 10000               7                    7/25 x 100 = 28%           4+7 = 13

10000- 15000               7                    7/25 x 100 = 28%            13+ 7= 20

15000 -20000              4                    4/25 x 100 = 16%            20+4= 24

20000-25000              3                    3/25 x 100 = 12%              24+3= 27

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