Answer:
N-Natural
R-Real
Z-integer
Q-rational
In the equation P = 1,000T/V, find the value of P when T = 32 and V = 800.
(And please explain it! Don't just answer.)
Answer:
Step-by-step explanation:
1. Substitute t and v
p=1000(32)/800
2. solve
p=32000/800
3.simplify
p=40
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10x-5y=20 solve for x
Answer:
x=2
Step-by-step explanation:
Answer:
x=2
Step-by-step explanation:
20/10
Question 3 of 25 What is g(x)?
Answer:
" Its graph is v-shaped and opens up.
If the graph is turned upside down (so that it opens down), then g(x) = -|x|."
Step-by-step explanation:
Hope this helped :)
Step-by-step explanation:
This is an absolute value function with negative coefficient.
we have
g(x) = - Ixl
Convert 114five 1 to base ten.
1. Which of the following lines is parallel to the line y = -3/2x +1 and contains the point (4,2)?
Answer:
The answer should be y = -\(\frac{3}{2}\)\(x\) + 8, but its not one of the answers, so check the question again.
Step-by-step explanation:
If the second line is parallel, then the gradient will be the same:
y = -\(\frac{3}{2}\)\(x\) + c
Find what c is (y-intercept) by inputting the given point into the equation (4,2):
2 = (-\(\frac{3}{2}\) x 4) + c
2 = -6 + c
c = 8
4.66 let x represent the number that occurs when a green die is tossed and y the number that occurs when a red die is tossed. find the variance of the random variable (a) 2x − y ; (b) x 3y − 5.
The variance of each random variable is given as follows:
a) Var(2x - y) = 10.4165.
b) Var(x + 3y - 5) = 20.833.
What is the variance of random variable?The number that occurs when each dice is thrown is represented by an uniform variable, with bounds a = 1 and b = 6, hence the variance of each variable is calculated as follows:
Var(x) = Var(y) = (6 - 1)²/12 = 2.0833.
When two variables are added, the variance is calculated as follows:
Var(aX + bY) = a²Var(X) + b²Var(Y)
Hence, for item a, the variance is calculated as follows:
Var(2x - y) = 2²Var(x) + (-1)²Var(y) = 4Var(x) + Var(y)
The variances were calculated before, which are both of 2.0833, hence:
4Var(x) + Var(y) = 4 x 2.0833 + 2.0833 = 10.4165.
For item b, the variance is calculated as follows:
Var(x + 3y - 5) = Var(x) + 3²Var(y) + (-1)²Var(-5).
The variance of a constant is of zero, hence Var(-5) = 0, and then:
Var(x + 3y - 5) = Var(x) + 3²Var(y) + (-1)²Var(-5) = 2.0833 + 9(2.0833) = 20.833.
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Please help me I need it soon
helppp, determine the indicated lengths
Answer:
phuk u uagsgshwgwgdgwgwyegwgwgwhehehehe
7. Find the slope of a line that is parallel to the line containing the points (3, 4) and (2,6).
SOMEONE ANSWER FAST ITS THE LAST QUESTION
The slope of a line that is parallel to the line containing the points (3, 4) and (2, 6) is -2.
What is the slope of a line that is parallel to the line containing the points (3, 4) and (2,6)?To find the slope of a line that is parallel to the line containing the points (3, 4) and (2, 6), we first need to find the slope of the line containing these points. We can use the slope formula:
m = (y2 - y1) / (x2 - x1)
Where:
m = slope
(x1, y1) = coordinates of the first point (3, 4)
(x2, y2) = coordinates of the second point (2, 6)
Substituting the given values, we get:
m = (6 - 4) / (2 - 3)
m = -2
The slope of the line containing the points (3, 4) and (2, 6) is -2.
Since we are looking for a line that is parallel to this line, the slope of the parallel line will also be -2.
Therefore, the slope of the parallel line is -2.
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The table shows the number of photocopies made during one day at each of the 25 schools in a school district.
Answer: there is no picture for this question
Step-by-step explanation:
Find the two solutions to this equation:
(5x – 1)(x – 2) =0
Give each of your answers as an integer or a fraction in its simplest form.
Step-by-step explanation:
\((5x - 1)(x - 2) = 0 \\ 5x - 1 + x - 2 = 0 \\ 5x + x = 0 + 2 + 1 \\ 6x = 3 \\ 6x = 3 \\ 6 \: \: \: \: \: \: \: \: \: \: \: \: 6 \\ x = \frac{1}{2} \)
Tell whether the figure has line symmetry. If so how many lines of symmetry are there?
Rectangle ABCD has a perimeter of 22 units. The coordinates of the rectangle's vertices are A(-4,5), B(3,x), and D(-4,x). Which could be the value of x
Through the given information in the question, the value of x could be 12.
What is the perimeter of a rectangle?The perimeter of a rectangle is the total distance around the outside of the rectangle. It is calculated by adding together the length of all four sides of the rectangle. If the length of the rectangle is denoted by 'l' and the width is denoted by 'w', then the formula for the perimeter (P) of the rectangle is:
P = 2l + 2w
Alternatively, the formula can also be written as:
P = 2(l + w)
The perimeter of a rectangle is given by the sum of the lengths of all four sides. Therefore, we can write:
AB + BC + CD + DA = 22
We know that AB = CD = 9 since they are opposite sides of the rectangle. We also know that DA = BC = x - 5, since they are the other two sides of the rectangle.
Substituting these values into the perimeter equation, we get:
9 + x - 5 + 9 + x - 5 = 22
Simplifying the equation, we get:
2x - 2 = 22
2x = 24
x = 12
Therefore, the value of x could be 12.
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Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below. Lengths (mm) Frequency 120 - 1211 122 - 12316 124 - 12571 126 - 127108 128 - 12983 130 - 13118 132 - 1333 What is the lower class limit for the second class
The lower class limit for the second class is 122 mm.
The lower class limit is the smallest value within a class interval. Looking at the given frequency distribution table, the second class interval is 122 - 123. The lower class limit for this interval is the smallest value, which is 122 mm.
The class intervals in the table represent ranges of fish lengths, and the lower class limit defines the starting point of each interval. In this case, the second class interval starts at 122 mm, indicating that fish lengths between 122 and 123 mm are included in this interval.
By understanding the concept of class limits and observing the specific values provided in the frequency distribution table, we can determine that the lower class limit for the second class is 122 mm.
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You purchased 7 3/4 lb of candy for your party. You're expecting to have 10 guests attend your party. How much candy will each guests get?
Answer: .775 lbs
Step-by-step explanation:
7 3/4 _> 7.75
7.75 / 10 = .775
ill mark brainliest for correct answer
Answer:
Solution given:
\(\frac{1}{5}(6+3+1)²\)
\(\frac{1}{5}(10)²\)
\(\frac{1}{5}100\)
=20 is a required answer.
What is the distance to the earth’s horizon from point P?
Enter your answer as a decimal in the box. Round only your final answer to the nearest tenth.
(15 points)
From P to the horizon must be tangent to the curvature of the earth...So P to the center of the earth is the hypotenuse. From the Pythagorean Theorem.
Thus, h^2=x^2+y^2.
(3959+15.6)^2=x^2+3959^2
x^2=(3974.6)^2-(3959)^2
x^2=123764.16
x=√123764.16 mi
x≈351.80 mi.
Thus, From P to the horizon must be tangent to the curvature of the earth...So P to the center of the earth is the hypotenuse. From the Pythagorean Theorem.
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HELP
WHICH IS NOT A PROPIETY OF PARALLELOGRAM
According to the given information Congruent diagonals is not a property of parallelogram.
Why not? A kite is not a parallelogram.A kite's opposing forces aren't always parallel, just like not every kite is just a parallelogram. Trapezoids are quadrilaterals having a single pair of parallel sides. The parallel sides make up the bases. If somehow the foundation angles are equal, the trapezoid is said to be an isosceles trapezoid.
Do parallelograms count as diamonds?Since a diamond has four slanted, equal-length sides, it is an example of a rhombus. They are also both parallelograms since a parallelogram is indeed a rhombus and a diamond is one as well.
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Select the correct answer from each drop-down menu.
Sam’s teacher wrote two Boolean expressions on the whiteboard. Identify the names of the laws of these expressions.
Expression 1: X (Y + Z) = X.Y + X.Z
Expression 2: X(Y.Z) = (X.Y)Z = X.Y.Z
The first expression is known as the
law. The second expression is known as the
law.
The first expression X (Y + Z) = X.Y + X.Z is distributive property of multiplication and the second expression X(Y.Z) = (X.Y)Z = X.Y.Z is associative property of multiplication.
According to the question,
We have the following two expressions:
X (Y + Z) = X.Y + X.Z
X(Y.Z) = (X.Y)Z = X.Y.Z
Now, the distributive property of multiplication states that the number outside the bracket is multiplied into each number within the bracket and the sign remains the same.
For example, 2(5+7) is 2*5+2*7.
The associative property of multiplication states that the result of the multiplication of numbers is same even when the bracket is changed from one number to another.
Hence, the first expression X (Y + Z) = X.Y + X.Z is distributive property of multiplication and the second expression X(Y.Z) = (X.Y)Z = X.Y.Z is associative property of multiplication.
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According to the Boolean algebra, the first expression X (Y + Z) = X.Y + X.Z uses distributive property of multiplication and
The second expression X(Y.Z) = (X.Y)Z = X.Y.Z uses the associative property of multiplication.
Boolean Algebra:
Basically, Boolean algebra is a branch of mathematics that deals with operations on logical values with binary variables.
And there are three properties in Boolean algebra.
They are, Commutative, associative, and distributive properties.
Given,
Sam’s teacher wrote two Boolean expressions on the whiteboard. Identify the names of the laws of these expressions.
Expression 1: X (Y + Z) = X.Y + X.Z
Expression 2: X(Y.Z) = (X.Y)Z = X.Y.Z
Here we need to find the name of the property used by the teacher on those two expression.
While we looking into the question,
We have the give the two expressions:
They are
=> X (Y + Z) = X.Y + X.Z
=> X(Y.Z) = (X.Y)Z = X.Y.Z
When we take the first expression,
X (Y + Z) = X.Y + X.Z
That states that the distributive property of multiplication is used here and the process of the distribution property is the number outside the bracket is multiplied into each number within the bracket and the sign remains the same.
Similarly, when we take the second expression
X(Y.Z) = (X.Y)Z = X.Y.Z
That uses the associative property of multiplication which is the result of the multiplication of numbers is same even when the bracket is changed from one number to another.
Therefore, the first expression X (Y + Z) = X.Y + X.Z uses the distributive property of multiplication and the second expression X(Y.Z) = (X.Y)Z = X.Y.Z uses the associative property of multiplication.
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If a = –2.6, what is the value of –a?
2.6
2
–2
–2.6
Answer:
2.6
Step-by-step explanation:
If a = -2.6 then -a = -(-2.6) = 2.6
Find the value of y for the given value of x. y=x2+9;x=−12
Answer:
0
Step-by-step explanation:
0 is what i got
2. Which is equivalent to the calculator output 8.954 E - 15?
8.954 x 10-15
0.895400-000-00-00
8,954,000,000,000,000
-15 108.954
Answer: 8.954 x 10^-15
Step-by-step explanation:
i took a test with this question and this was the answer
To finish an order on time, a company has to produce 40 items each day. But the company manages to complete 20 more items each day than it needs to, and finishes the order 3 days ahead of time. In how many days was the company supposed to finish the order?.
The company was supposed to finish the order in 9 days.
What is a linear equation?
A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables."
Here, we have
The company must have produced 60 items daily if it produced 20 more than the daily average of 40 items.
The company had 120 products to make, which should have taken three days (120 items, 40 items/day), but it finished in just two days (120 items, 60 items/day). They completed this order one day earlier than expected.
However, the issue is that they completed 3 days ahead of schedule. Thus, our estimate is 360 items or three times 120 items.
According to this, they should have completed their order in 9 days (360 things, at a rate of 40 items per day), but they did so in 6, at a rate of 60 items per day. Since 6 is three fewer than 9, our assumption of 360 items was accurate.
We've demonstrated that the business should have completed the order in 9 days.
Let the desired number of days be x.
Then, the company finished its order in x - 3 days.
Since the number of items produced is the number of days times items per day, and it doesn't change:
number of items = 40 items/day * x days
= 60 items/day * (x - 3) days
40x = 60(x - 3) = 60x - 180
180 = 20x
x = 9
Hence, the company was supposed to finish the order in 9 days.
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Which is equivalent toStartRoot 10 EndRoot Superscript three-fourths x ?
Answer:
I THINK its the last one (8 root 10 to the power of 3x)
Step-by-step explanation:
A square root is the same thing as raising something to the 1/2. So the expression we have is (10^1/2)^3/4x.
Due to exponent rules we can multiply to get
10^3/8x which is the same thing as 10^3x/8
The 8 goes to the root and the 3x becomes the exponent
In this exercise we have to have knowledge about the properties of powers, so we have to:
Letter D
Recalling some properties of power, we find that:
Multiplication of powers with the same base.Division of powers with the same base.Power of potency.Potency of a product.Quotient power.Are returning to the exercise and using the properties informed, we find that:
\((10^{1/2})^{3/4x}\\10^{3/8x} = 10^{3x/8}\)
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Find the total derivative Z with respect to t. z=tx+ln(3x+y), where x=e ^−2t y=3t^2 −t
The total derivative of Z with respect to t is given by
\(Z' = (-2e^{-2t})(t + 3/(3e^{-2t} + 3t^2 - t)).\)
We have,
To find the total derivative of Z with respect to t, we can apply the chain rule and the product rule.
Let's calculate it step by step:
Given:
z = tx + ln(3x + y)
\(x = e^{-2t}y = 3t^2 - t\)
We'll start by finding the derivative of z with respect to x, and then multiply it by the derivative of x with respect to t:
dz/dx = t + 1/(3x + y) * (3)
= t + 3/(3x + y)
Next, we'll find the derivative of x with respect to t:
\(dx/dt = d/dt(e^{-2t})\\= -2e^{-2t}\)
Now, applying the chain rule, we can find the derivative of z with respect to t:
dz/dt = dz/dx * dx/dt
\(= (t + 3/(3x + y)) * (-2e^{-2t})\)
Substituting the expressions for x and y, we have:
\(dz/dt = (t + 3/(3e^{-2t} + 3t^2 - t)) * (-2e^{-2t})\)
Simplifying further, we can rewrite it as the total derivative of Z with respect to t:
\(Z' = (-2e^{-2t})(t + 3/(3e^{-2t} + 3t^2 - t))\)
Thus,
The total derivative of Z with respect to t is given by
\(Z' = (-2e^{-2t})(t + 3/(3e^{-2t} + 3t^2 - t)).\)
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show all your working please
Answer:
45 cm²
Step-by-step explanation:
area = ½×11×13×sin 39°
= 71.5 × 0.6294
= 45 cm²
pls help me ???????????????????
Answer:
Hi♀️
Step-by-step explanation:
ΔMAN≅ΔNED
ΔRED≅ΔRGD
ΔLAN≅ΔLEI
ΔRKI≅ΔIYC
Hope it helps you!
Solve:
47 = -2 - 7x
I need help
47 = -2 - 7x
7x = -2 - 47
7x = -49
x = -7
Consider the following function. Function Factors f(x) = 10x3 – 7x2 – 139x + 28 (2x + 7), (5x - 1) (a) Verify the given factors of the function f. (b) Find the remaining factor(s) of f. (c) Use your results to write the complete factorization of f. (d) List all real zeros of f. (smallest value) X = X = X= (largest value)
The real zeros of f(x) are x = -2, x = 1/5, and x = 7/5.
The smallest real zero is x = -2, and the largest real zero is x = 7/5.
Given function is :\(f(x) = 10x3- 7x2 - 139x + 28\).
Now we have to Verify the given factors of the function f which is \((2x + 7), (5x - 1)\).
The Remainder Theorem states that when a polynomial f(x) is divided by a divisor x - c, the remainder is equal to f(c).
Now we will divide f(x) by 2x+7 using polynomial long division.
\(\[\begin{align}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 5x^2&-8x+4 \\2x+7|10x^3-7x^2-139x+28& \\ \ \ \ \ \ \ \ \ \ \ \ \ -\underline{(10x^3+35x^2)}& \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -42x^2-139x& \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \underline{(\ \ 42x^2+147x\ )}& \\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -8x+28& \end{align}\]\)
Now the remaining factor of f(x) is (2x + 7) (5x - 1) (2x - 2), which is further simplified to f(x) = 10(x + 2)(5x - 1)(x - 7/5).
Hence the factorization of the given function is f(x) = 10(x + 2)(5x - 1)(x - 7/5).
The real zeros of f(x) can be found by setting f(x) = 0.
\(\[\begin{align}f(x)&=0 \\10(x+2)(5x-1)(x-\frac{7}{5})&=0 \\x+2&=0\ \ \ \ \ \ \ \ \ \ \ 5x-1=0\ \ \ \ \ \ \ \ \ \ \ x-\frac{7}{5}=0\\x&=-2\ \ \ \ \ \ \ \ \ \ \ x=\frac{1}{5}\ \ \ \ \ \ \ \ \ \ \ x=\frac{7}{5}\end{align}\]\)
Thus, the real zeros of f(x) are x = -2, x = 1/5, and x = 7/5.
The smallest real zero is x = -2, and the largest real zero is x = 7/5.
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how to find the reference angle of a negative angle
To find the reference angle of a negative angle, follow these steps:
Determine the positive equivalent: Add 360 degrees (or 2π radians) to the negative angle to find its positive equivalent. This step is necessary because reference angles are always positive.
Subtract from 180 degrees (or π radians): Once you have the positive equivalent, subtract it from 180 degrees (or π radians). This step helps us find the angle that is closest to the x-axis (or the positive x-axis) while still maintaining the same trigonometric ratios.
For example, let's say we have a negative angle of -120 degrees. To find its reference angle:
Positive equivalent: -120 + 360 = 240 degrees
Subtract from 180: 180 - 240 = -60 degrees
Therefore, the reference angle of -120 degrees is 60 degrees.
In summary, to find the reference angle of a negative angle, first, determine the positive equivalent by adding 360 degrees (or 2π radians). Then, subtract the positive equivalent from 180 degrees (or π radians) to obtain the reference angle.
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