Measure the height of the tin in mm and write down the real height in mm

The value of M is 4.

The value of M represents the length of the segment that connects the midpoints of the non-parallel sides of trapezoid ABCD. To find the value of M, we can use the fact that the trapezoids are similar.

Now, let's label the points where MN intersects sides BC and FG as P and Q, respectively. We can use the fact that MN is parallel to sides BC and FG to show that triangles BMP and FQN are similar to trapezoids ABCD and EFGH, respectively.

Therefore, we can write:

BM/AB = MP/CD = k

and

FQ/EF = QN/GH = k

Since we know that AB/EF = k, we can substitute this into the first equation to get:

BM/EF = MP/GH

Similarly, we can substitute FQ/EF = k into the second equation to get:

FQ/EF = QN/GH

Now, let's combine these two equations to get:

(BM + FQ)/EF = (MP + QN)/GH

But we know that BM + FQ = EF, and MP + QN = GH. Therefore, we can simplify the equation to get:

EF/EF = GH/GH

Or simply:

1 = 1

This means that our calculations are correct, and that we can use the ratio k to find the value of M. Specifically, since MN is parallel to AB and CD, we know that the length of MN is equal to half the difference between the lengths of AB and CD. Therefore, we can write:

M = (1/2)(AB - CD)/k

When we apply the values on it, then we get,

M = (1/2) (56 - 48) / 1

M = (1/2) x 8 = 4

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You have the coordinates for triangle ABC

A (2,1)

B (6,1)

C (4,4)

To perform a reflection over the x-axis, the x-coordinarte remains the same and you have to invert the sing of the y-coordinate, for example for a point P(x,y):

Preimage → Image

P(x,y) → P'(x,-y)

So to reflect triangle ABC to triangle A'B'C' you have to do as follows:

A (2,1) → A'(2,-1)

B (6,1) → B'(6,-1)

C (4,4) → C'(4,-4)

The domain of the function is defined as 0 ≤  x ≤ 4.

option A is the correct answer.

A domain of a function refers to "all the values" that can go into a function without resulting in undefined values.

So the domain of a function is the set of x values, while the range of a function is the set of y values.

From the given statement, the range of the function is defined as;

y = vt

where;

y = 60 mph x 4 hr

y = 240 miles

From the given statement, the domain of the function is defined as;

0 ≤  x ≤ 4

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Answer:

1. 12 square kilometers

2.18 square inches

Step-by-step explanation:

To find the area of a square you multiply the base and the height. Then you divide it by 2. 8 times 3 divided by 2 is 12. 4 times 9 divided by 2 is 18. Hope this helps!

Answer:

yes the corresponding angles are congruent...

it can be wrong

Answer:

5 and 4

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the gradient and c the y- intercept )

(a)

y = 5x - 3 ← is in slope- intercept form

with gradient m = 5

(b)

3y - 12x + 7 = 0 ( add 12x to both sides )

3y + 7 = 12x ( subtract 7 from both sides )

3y = 12x - 7 ( divide through by 3 )

y = 4x - \(\frac{7}{3}\) ← in slope- intercept form

with gradient m = 4

Four non-coplanar planes define a space.

A line contains at least two points, and a plane contains at least three non-collinear points. Space contains at least four noncoplanar planes (points). The points or lines that lie on the same plane are called coplanar planes and hence the points that do not lie on the same plane are called non-coplanar planes. Any four points lie in at least one space, and any four non-coplanar points lie in exactly one space. If two distinct spaces intersect, then their intersection is a plane. if P is any point of one set and Q is any point in the other set, then the segment P-Q intersects the line. As seen in the figure, the space at least four noncoplanar planes distinguish a space.

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The distance when the mass is 5kg is 15cm.

When two values vary directly, it means that both values move in the same direction. If one of the value increases, the other value increases and if one of the values decreases, the other value decreases.

The equation that is used to represent direct variation is:

d = km

Where:

The first step is to determine the value of k:

12 = 4k

k = 12 / 4

k = 3

d = 3 x 5 = 15cm

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x/2 = -1

=> x = -1 × 2

=> x = -2

Option d. dependent variable. In an experiment, the dependent variable is the factor that is being measured or observed.

It is the variable that is expected to change or be affected as a result of the manipulation of the independent variable. The independent variable is the factor that is being manipulated or controlled in the experiment, while the controlled variable is a factor that is kept constant or consistent throughout the experiment to prevent it from affecting the dependent variable. The dependent variable is often used to draw conclusions about the relationship between the independent variable and the outcome of the experiment.

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The value of x in the triangle is 3.

Different types of shapes—some two dimensional and some three dimensional—appear in mathematics' geometry. Two-dimensional shapes are those that can be specified with the aid of two parameters, while three-dimensional shapes are those that can be defined with three parameters. Shapes that are only two dimensional include squares, rectangles, triangles, etc. Such a two-dimensional object with straight sides is known as a polygon. Three line segments are arranged in a triangle at a specific angle for any two of the three line segments. A triangle has three angles, the total of which is always 180 degrees.

Given,

Triangle given

Sides of the length is x and 14

Sum is 6x -1.

6x - 1 = 14 + x

6x - x = 14 + 1

5x = 15

x = 3

The value of x in the triangle is 3.

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Answer:

6.6

Step-by-step explanation:

Answer:

6.6

Step-by-step explanation:

6 + 8 + 2 + 12 + 5 = 33

33 / 5 = 6.6

plz mark brainliest

A. 299.98 metres, rounded to two decimal places.

The decimal system number is a number system that employs numbers 0 to 9 to express a number with base 10. The number is written in base-10 notation, with each value represented by 0 or the first nine positive integers. Each value in this number system has the power 10 place value.

To determine how much farther the cheetah can travel in 10 seconds than the worm, we must first convert their distances to the same unit.

A cheetah can cover 0.3 kilometres in 10 seconds.

In 10 seconds, the worm crawls 2 millimetres.

We may convert the cheetah's distance travelled to centimetres, which is the same unit as the worm's distance travelled:

0.3 kilometres = 0.3 times 1000 centimetres multiplied by 100 centimetres = 30,000 millimetres

Therefore, in 10 seconds, the cheetah travels 30,000 centimetres.

Now we can deduct the worm's distance from the cheetah's journey to determine how much further the cheetah can travel:

29,998 centimetres = 30,000 centimetres - 2 millimetres

As a result, in 10 seconds, the cheetah can go 29,998 centimetres farther than the worm.

We divide this by 100 to get metres: 29,998 centimetres 100 = 299.98 metres

As a result, the correct answer is A. 299.98 metres, rounded to two decimal points.

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If the budget were to increase to $3000, allowing us to survey many more people from a simple random sample, the test statistic would likely be more accurate and reliable.

As per the given scenario,

if we have a limited budget of $500, we can only survey 50 people from a simple random sample. In order to study the relationship between social class and voting preferences, the budget must be increased to $3000.

On increasing the budget, we can survey more people from a simple random sample, which would lead to a better representation of the population.
Due to the small budget, the test statistic would be less accurate as only a small number of people are being surveyed. However, if the budget increases to $3000, it would allow for a larger sample size and therefore the test statistic would be more accurate.

This would result in a narrower confidence interval and a higher level of confidence in the accuracy of the results.
Moreover, with a larger budget, it would be possible to use more sophisticated sampling techniques such as stratified random sampling, which could further increase the accuracy of the test statistic.

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Answer: The correct answer is B.

Step-by-step explanation: To simplify a square root, you take the factors of the value in the square root and see the greatest factor that is a square. In this case, 49 is the greatest square factor of 98. You take the square root of 49, which is 7. 7 goes outside the radicand. Leave 2 inside the radical because 49 x 2 = 98. Hence, the correct answer is B.

Answer:

Please

Excuse

My

Dear

Aunt

Sally

Step-by-step explanation:

It means to add parenthesis,exclamation points, multiplication, division, addition, & subtraction PEMDAS is a easier way to remember this

Answer:

Hello!

__________________________

PEMDAS: The order of operations

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

Hope this helped you!

Step-by-step explanation: We can remember the order using PEMDAS: Parentheses, Exponents, Multiplication and Division (from left to right), Addition and Subtraction (from left to right).

To find the absolute maximum and absolute minimum values of f on the given interval, f(x) = xe−x2/128, [−2, 16].Here, f(x) = xe−x2/128, [−2, 16]Let's find the absolute maximum and absolute minimum value for the given function by taking the derivative of the function and equating it to zero.

The first derivative of f(x) is: f'(x) = e−x2/128 (1−x2/64)The critical points occur where f'(x) = 0 and where f'(x) is undefined. f'(x) = 0 when e−x2/128 (1−x2/64) = 0 ⇒ 1−x2/64 = 0 or e−x2/128 = 0.Now, 1−x2/64 = 0 when x2 = 64 ⇒ x = ±8.e−x2/128 = 0 when x = ±∞ since e−∞ = 0 and e∞ = ∞.

Therefore, the critical points in the interval [−2, 16] are x = −8 and x = 8. To find the nature of critical points, we take the second derivative. f"(x) = (1/64) (3x2−32)e−x2/128.The second derivative is positive for x < −4 and 4 < x, so x = −8 is a local maximum, and x = 8 is a local minimum.

However, we need to verify whether the critical points are absolute maximum or absolute minimum values. Now, we evaluate the function at the critical points and at the endpoints of the interval to determine the absolute maximum and minimum values. At x = −8, f(−8) = −8e−2 < 0.At x = 8, f(8) = 8e−2 > 0.At x = −2, f(−2) = −2e−1/8 > 0.At x = 16, f(16) = 16e−8/2 < 0.The maximum value of the function occurs at x = 8 and is f(8) = 8e−2.Conversely, the minimum value of the function occurs at x = 16 and is f(16) = 16e−8/2.

Therefore, the absolute maximum value of the function is 8e−2 and the absolute minimum value is 16e−8/2 on the interval [−2, 16].We are given f(x) = xe−x2/128, [−2, 16]. We are to determine the absolute maximum and absolute minimum value of the function on the interval [−2, 16]. The first step to finding the absolute maximum and minimum value of the function is to find the critical points.

To find the critical points, we take the derivative of the function and equate it to zero. We getf'(x) = e−x2/128 (1−x2/64) = 0.The critical points occur where f'(x) = 0 and where f'(x) is undefined. f'(x) = 0 when e−x2/128 (1−x2/64) = 0 ⇒ 1−x2/64 = 0 or e−x2/128 = 0. We find x = ±8. However, we need to verify whether the critical points are absolute maximum or absolute minimum values.

To determine this, we evaluate the function at the critical points and at the endpoints of the interval. Now, we take the second derivative to determine the nature of the critical points.

f"(x) = (1/64) (3x2−32)e−x2/128. The second derivative is positive for x < −4 and 4 < x, so x = −8 is a local maximum, and x = 8 is a local minimum. However, we need to verify whether the critical points are absolute maximum or absolute minimum values.

At x = −8, f(−8) = −8e−2 < 0. At x = 8, f(8) = 8e−2 > 0. At x = −2, f(−2) = −2e−1/8 > 0. At x = 16, f(16) = 16e−8/2 < 0. The maximum value of the function occurs at x = 8 and is f(8) = 8e−2. Conversely, the minimum value of the function occurs at x = 16 and is f(16) = 16e−8/2.

Thus, the absolute maximum value of the function is 8e−2 and the absolute minimum value is 16e−8/2 on the interval [−2, 16]..

Therefore, we can conclude that the absolute maximum value of the function is 8e−2 and the absolute minimum value is 16e−8/2 on the interval [−2, 16].

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The greatest number of passengers the plane can carry on its next flight is 133 passengers (option b). To determine this, we subtract the weight of the cargo from the maximum weight capacity of the plane and then divide the remaining weight by the weight of each passenger with luggage.

Given:

Maximum weight capacity of the plane = 36,600 pounds

Weight of cargo = 7,320 pounds

Weight of each passenger with luggage = 220 pounds

To find the greatest number of passengers the plane can carry, we need to determine how much weight is available for the passengers after accounting for the cargo. We subtract the weight of the cargo from the maximum weight capacity of the plane:

Remaining weight capacity = Maximum weight capacity - Weight of cargo

Remaining weight capacity = 36,600 pounds - 7,320 pounds

Remaining weight capacity = 29,280 pounds

Now, we divide the remaining weight capacity by the weight of each passenger with luggage to find the maximum number of passengers:

Maximum number of passengers = Remaining weight capacity / Weight of each passenger with luggage

Maximum number of passengers = 29,280 pounds / 220 pounds

Maximum number of passengers ≈ 133

Therefore, the greatest number of passengers the plane can carry on its next flight is 133 passengers, as stated in option b.

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In standard nomenclature, a normally distributed dataset is represented as \(N(µ, σ^2)\), where µ is the mean and \(σ^2\)is the variance (square of the standard deviation).

A normally distributed phenomenon using standard nomenclature can be described as follows:

A dataset is said to be normally distributed if it follows a bell-shaped curve, which is symmetrical around the mean (µ) and characterized by its standard deviation (σ). In standard nomenclature, a normally distributed dataset is represented as \(N(µ, σ^2)\), where µ is the mean and \(σ^2\)is the variance (square of the standard deviation).

For example, if we consider the heights of adult males in a large population, we may observe that the distribution is normally distributed with a mean height (µ) of 175 cm and a standard deviation (σ) of 10 cm. In this case, the nomenclature for this normally distributed phenomenon would be N(175, 100), as the variance is \(10^2 = 100\).

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The two-sample z-test statistic for evaluating the null hypothesis that the percentage of students who support capital punishment did not change from 1970 to 2005 is -4.08 (rounded to two decimal places).

To calculate the two-sample z-test statistic, we need to compare the proportions of students who support capital punishment in 1970 and 2005. The null hypothesis states that the percentage of students who support capital punishment did not change.

Let p1 be the proportion of students who support capital punishment in 1970, and p2 be the proportion in 2005. We can calculate the sample proportions as p1 = 590/1000 = 0.59 and p2 = 350/1000 = 0.35.

The formula for the two-sample z-test statistic is given by z = (p1 - p2) / sqrt((p(1 - p)(1/n1 + 1/n2))), where p is the pooled proportion and n1 and n2 are the sample sizes.

To calculate p, we compute the pooled proportion as p = (p1n1 + p2n2) / (n1 + n2) = (0.591000 + 0.351000) / (1000 + 1000) = 0.47.

Substituting the values into the formula, we have z = (0.59 - 0.35) / sqrt((0.47*(1 - 0.47)(1/1000 + 1/1000))) = -4.08.

Therefore, the two-sample z-test statistic for evaluating the null hypothesis is -4.08 (rounded to two decimal places).

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The gallon used by the first car is 35 gallons and the gallon used by the first car is 25 gallons.

The first step is to form a system of linear equation:

35a + 20b = 1725 equation 1

a + b = 60  equation 2

Where:

The elimination method would be used to solve this question.

Multiply equation 2 by 35:

 35a + 35b = 2100  equation 3

Subtract equation 1 from equation 3:

15b = 375

Divide both sides of the equation by 15:

b = 375 / 15

b = 25

Substitute for b in equation 2 :

a + 25 = 60

a = 60 - 25

a = 35

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Answer:

she goes through 29 rooms

Step-by-step explanation:

116/4= 29

Answer:

True.

Step-by-step explanation:

That is exactly what a perimeter is. Hope this helps

As a result, the expression's value in fraction with simplest form is -4/3

Prior to evaluating the expression, the exponents must first be simplified in fraction.

Remember that a negative exponent indicates to take the base raised to the positive exponent's reciprocal.

The numerator and denominator of a fraction are both integers, and this is how fractions are typically expressed. When a fraction is preceded by a negative sign, it is being multiplied by -1. For instance, $-frac4$ signifies "-1 times 4 over 1," which can be written as "-4."

When these values are put into the original equation, we get the following results:

\(-3^(-3)/6^(-2) = (-1/27)/(1/36) = -1/27 * 36 = -4/3\)

As a result, the expression's value is -4/3

In conclusion, we can conduct the necessary procedures to evaluate an equation involving powers of numbers after simplifying the exponents. For the best outcome, it's crucial to follow the PEMDAS order of procedures.

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If  One plane travels 73 km/hr slower than the other. If the two planes are 17,109 kilometers apart after 9 hours, The rate of each plane is 914 km/hr, 987 km/hr.

x + 73 = y  = speed of the  second plane

After 9 hours  they are 17,109 km  apart after travelling in opposite directions

17,109  /9  = 1901 km/hr

(x) + x+93 = 1901

2x = 1901 - 73 = 1828

So,

x =1828/2 = 914 km/hr

y = 914 +73 = 987 km/hr

The speed of the faster plane is 987 km/hr

The speed of the slower plane is 914 km/hr

Check:

9 hours one went =  914 x 9  = 8226 km

Second  went  = 987 x 8 = 8883km

8226 km + 8883 km =  17,109 km

Therefore 914 km/hr, 987 km/hr are the rate of the both plane.

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The diagonal face is the one with the largest area and the area is 67.7 square centimeters.

A right-angled prism is a solid shape made of two right angled triangles and two rectangles.

Analysis:

bottom one is a rectangle, area of rectangle = 12 x 4 = 48 square centimeter

Left one, is a right-angled triangle, area of triangle  = 1/2 x 4 x 4 = 8 square centimeter

Diagonal one, we calculate the diagonal of the right-angled triangle = \(\sqrt{4^{2} + 4^{2} }\) = 5.6cm

Area of diagonal one = 5.6 x 12 = 67.2 square centimeters

In conclusion, the diagonal with an area of 67.2 square centimeters is the one with the largest area

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Answer:

the person above me was close but the correct answer is actually the diagonal one with an area of 68.4, this is because its actually 5.7 x 12 not 5.6 x 12 (you have to round to the nearest tenth which they didn't do)

The lower bound of a 99% confidence interval for the true proportion of fish that are Black Carp in Lake Ontario0. 2357

To determine the lowed bound of the 99% confidence, we have;

Let's find the sample proportion, we get;

Sample proportion (p) = Number of Black Carp / Total number of fish

Substitute the values, we have;

p = 37 / 75

Divide the values

p= 0.4933

The margin of error (E) is expressed as;

E = Z × √((p × (1 - p)) / n)

Substitute the values, we get;

E = 2.576 × √((0.4933× (1 - 0.4933)) / 75)

E = 2.576 × √ 0. 0099

E = 0. 2576

Lower bound = p - E

Lower bound = 0.4933 - 0.2576

Lower bound = 0. 2357

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